(02.01 LC)

What is true of neutrons?

They have no charge and are located inside the nucleus.
They have no charge and are located outside the nucleus.
They are negatively charged and are located inside the nucleus.
They are negatively charged and are located outside the nucleus.

Answer:

starts form from a accumulation of gas and dust ,which collapses due to gravity and starts to form stars

Answer:

Stars are the most widely recognized astronomical objects, and represent the most fundamental building blocks of galaxies. The age, distribution, and composition of the stars in a galaxy trace the history, dynamics, and evolution of that galaxy. Moreover, stars are responsible for the manufacture and distribution of heavy elements such as carbon, nitrogen, and oxygen, and their characteristics are intimately tied to the characteristics of the planetary systems that may coalesce about them. Consequently, the study of the birth, life, and death of stars is central to the field of astronomy.

Answer:

I,lll

Explanation:

Because the human can result from PBDEs in great lakes by water? I think?

Answer:

Its is D. 1,2 and 3

Explanation:

i took the exam already

The relative abundance of each isotope in the mixture and the isotopic mass of each isotope determines the average atomic mass of an element.

The average masses of the atoms of beryllium and fluorine are found in the attachment.

The average atomic mass of lithium is 6.9418 amu.

The average atomic mass of lithium is obtained from the isotopic mass and relative abundance of the two isotopes of lithium.

Isotopic mass of lithium-6 = 6.015 amu

Isotopic mass of lithium-7 = 7.016 amu

To calculate the average atomic mass, we use the formula:

average atomic mass = [(isotopic mass of isotope 1 x number of atoms of isotope 1) + ( isotopic mass of isotope 2 x number of atoms of isotope 2)] / total number of atoms

Substituting the values:

average atomic mass of lithium = [(6.015 amu x 3) + (7.016 amu x 2)] / 5

average atomic mass = 6.9418 amu

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Complete question:

1. What are the factors that affect the average atomic mass of a mixture of isotopes?

2. Beryllium (Be) and Fluorine (F) have only one stable isotope. Use the periodic table to complete the following table of the average atomic mass of one atom, two atoms, and three atoms of the isotopes

4. Lithium has only two stable isotopes. Use the sim to determine the following:

a. Atomic mass of lithium-6 = amu

b. Atomic mass of lithium-7= amu

c. Average atomic mass of a sample containing three lithium-6 atoms and two lithium-7 atoms = amu

Solid lead nitrate is heated and forms solid lead oxide, gaseous nitrogen dioxide, and oxygen then it form of decomposition reaction

Lead nitrate is a white color inorganic powder with the chemical formula Pb ( NO₃)₂ when Lead nitrate decomposes it produces Lead oxide a yellow colored oxide of  brown colored Nitrogen dioxide gas, and colorless Oxygen gas and also it gives yellow colors

When lead nitrate is heated it decomposes to form lead oxide, nitrogen dioxide and oxygen from the reaction, we can see that lead nitrate decomposes on heating and forms lead oxide, nitrogen dioxide and oxygen thus, lead nitrate on decomposition gives lead oxide, nitrogen dioxide and oxygen and the lead nitrate and when solid lead nitrate heated it decomposes to produce light yellow solid lead monoxide, reddish-brown nitrogen dioxide gas and colourless oxygen gas

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To find the number of moles of sucrose in 250ml of 0.150m solution, multiply the concentration (0.150m) by the volume in liters (0.25L) to get 0.0375 moles.

To calculate the number of moles of sucrose dissolved in 250ml of solution with a concentration of 0.150m, you can use the formula:  moles = concentration x volume
First, convert the volume of the solution from milliliters to liters by dividing by 1000:

250ml / 1000ml/L = 0.25L
Next, plug in the values for concentration and volume:
moles = 0.150m x 0.25L
moles = 0.0375 moles
Therefore, there are 0.0375 moles of sucrose dissolved in 250ml of solution with a concentration of 0.150m.

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Answer: In the given experiment, iodine molecules from the beaker enter the dialysis tube and turned the starch solution black. On the other hand, the large starch molecules were not allowed to diffuse across the dialysis tube and there was no change in the color of the iodine solution present in the beaker.

Explanation: The cell membrane is mainly composed of the lipid bilayer and embedded proteins. The hydrophobic core of the cell membrane does not allow the polar, charged, and large substances to move through it freely. However, the non-polar and small substances can diffuse through the membrane. Therefore, cell membranes are semipermeable and regulate the entry and exit of substances from cells.

The dialysis tube served as a semipermeable membrane and allowed only selected molecules to pass through it.

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How many grams of oxygen are required for the complete combustion of 47.2 g of butane, C4H10?

2C4H10 + 13O2 = 8CO2 + 10H2O​

Explanation:

Pigments that are absorbed strongly tend to move more slowly than those that are absorbed weakly. This is because strong absorption means that the pigment is more tightly bound to the surface it is on, which results in less movement.

Additionally, the size and shape of the pigment molecule also affect its movement. Larger and more complex molecules tend to move more slowly than smaller and simpler ones. This is because larger molecules experience more friction as they move through a medium, which slows them down.
It's important to note that the movement of pigments is also influenced by external factors such as temperature, pressure, and the nature of the medium they are in. In general, a higher temperature and lower pressure will increase the movement of pigments, while a more viscous medium will slow them down.
In summary, pigments that are absorbed strongly tend to move more slowly, but their movement can also be affected by factors such as size, shape, temperature, pressure, and the nature of the medium they are in.

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The diameter of a ground-state hydrogen atom using the power of 10, in meters, is 1.058 x 10^{-10} using the value of Bohr radius of Hydrogen atom.

Throughout the development of particle physics, under modern science, scientists have created different models to understand the atom. When we talk about the diameter of an atom, we refer to the Bohr radius, which is the radius from the nucleus to the orbiting shell electron.

In the case of a hydrogen atom, it has one electron, and the Bohr radius in the ground state is 5.29 x 10^{-11} meters.

To find the diameter, we would have to multiply the Bohr radius by 2. as diameter is the double of radius.

Diameter of hydrogen in ground-state = 2 x 5.29 x 10^{-11}  meters

                                                                = 10.58 x 10^{-11} meters

Thus, the diameter of a hydrogen atom in ground-state, using the value of Bohr radius of hydrogen is 1.058 x 10^{-10} meters using power of 10.

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The elements X and Y are in the same column on the periodic table, which means they have the same number of valence electrons.

Ionization energy refers to the amount of energy required to remove an electron from an atom. As we move down a group in the periodic table, ionization energy generally decreases because the valence electrons are farther from the nucleus and experience less attraction.

In this case, element Y has a higher atomic number, which means it has more protons in its nucleus than X. This means that there is a stronger attraction between the valence electrons and the nucleus in Y compared to X. Therefore, it would require more energy to remove an electron from Y, making it have a higher ionization energy than X. So, the correct option is "y because it contains more protons so there is a stronger attraction between the valence electrons and the nucleus."

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The oxygen atom forms a double bond with the carbon atom, which involves sharing two pairs of electrons. However, since the carbon atom is also bonded to two other atoms.

To further explain, a double bond involves sharing four electrons between two atoms, with two of the electrons coming from each atom's valence shell. In the case of the propanal molecule, the oxygen atom has six valence electrons and needs two more to complete its octet, while the carbon atom has four valence electrons and needs four more to complete its octet.

In propanal (also known as propionaldehyde), the oxygen atom forms a double bond with the carbon atom. A double bond consists of two pairs of shared electrons. Therefore, the total number of pairs of electrons shared between these atoms is 2.

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The  two pairs of electrons shared between the oxygen atom and the carbon atom in a propanal molecule.

We can look at the structure of propanal. Propanal has the chemical formula C3H6O, with a carbonyl group (C=O) located on the second carbon atom. In this carbonyl group, the oxygen atom is double-bonded to the carbon atom. Double bonds involve the sharing of two pairs of electrons between atoms. Therefore, in a propanal molecule, the oxygen and carbon atoms share two pairs of electrons.
There are two pairs of electrons shared between the oxygen and carbon atoms in a propanal molecule, due to the double bond in the carbonyl group.

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Answer is chemical change

Answer:

warby hair rising over land allows cooler air from the ocean to blow below.

The option that does not represent a characteristic of a pure substance is:

C) It is made up of different types of particles.

A pure substance is a material that consists of only one type of particle, either atoms of an element or molecules of a compound. It does not contain different types of particles. This is what distinguishes a pure substance from a mixture, which is composed of two or more different substances mixed together.

Option A states that a pure substance has a uniform texture throughout, which means it is homogeneous. This is true because pure substances have a consistent composition and properties throughout.

Option B states that a pure substance has a fixed boiling point or melting point. This is also true because pure substances have well-defined temperature ranges at which they transition between solid, liquid, and gas phases.

Option D states that a pure substance can be an element or a compound. This is true as well because pure substances can exist as either single elements or compounds consisting of two or more elements chemically bonded together.

In summary, the correct option is C, as a pure substance does not consist of different types of particles.

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A covalent bond is the exact number of bonded pairs of electrons in a compound

One electron is added by each atom to a pair of shared electrons in a single bond. While double bonds share only one pair of electrons, triple bonds share three pairs. Bonds with multiple covalent bonds exchange several electron pairs

Covalent bonding happens when atoms share electron pairs. Atoms join together through covalent bonds to form a full electron shell, which boosts stability. By sharing their outermost (valence) electrons, atoms can fill out their outer electron shell and become stable. Nonmetals will swiftly create covalent bonds with other nonmetals in order to achieve stability.

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Answer:

A. 257600g (i.e 257.6 Kg) of CaO were produced.

B. 202400g (i.e 202.4 Kg) of CO2 were produced.

Explanation:

We'll begin by calculating the mass of CaCO3 present in 5×10² Kg of lime stone. This is illustrated below:

From the question given, the lime stone contains 92% of CaCO3.

Mass of CaCO3 = 92% x 5×10² Kg

Mass of CaCO3 = 92/100 x 5×10² Kg

Mass of CaCO3 = 460 Kg

Therefore, 460 kg of CaCO3 is present in the lime stone.

Next, we shall determine the mass of CaCO3 that was heated and the masses of CaO and CO2 produced from the balanced equation. This is illustrated below:

CaCO3(s) —> CaO(s) + CO2(g)

Molar mass of CaCO3 = 40 + 12 + (16x3) = 100g/mol

Mass of CaCO3 from the balanced equation = 1 x 100 = 100g

Molar mass of CaO = 40 + 16 = 56g

Mass of CaO from the balanced equation = 1 x 56 = 56g

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of CO2 from the balanced equation = 1 x 44 = 44g

Summary:

From the balanced equation above,

100g of CaCO3 were heated to produce 56g of CaO and 44g of CO2.

A. Determination of the mass of quick lime, CaO produced by heating 5×10² Kg of lime stone.

5×10² Kg of lime stone contains 460 Kg (i.e 460×10³ g) of CaCO3.

From the balanced equation above,

100g of CaCO3 were heated to produce 56g of CaO.

Therefore, 460×10³g of CaCO3 will be heated to produce = (460×10³ x 56)/100 = 257600g of CaO.

Therefore, 257600g (i.e 257.6 Kg) of CaO were produced.

B. Determination of mass of carbon dioxide, CO2 produced by heating 5×10² Kg of lime stone.

5×10² Kg of lime stone contains 460 Kg (i.e 460×10³ g) of CaCO3.

From the balanced equation above,

100g of CaCO3 were heated to produce 44g of CO2.

Therefore, Therefore, 460×10³g of CaCO3 will be heated to produce = (460×10³ x 44)/100 = 202400g of CO2.

Therefore, 202400g (i.e 202.4 Kg) of CO2 produced.

Answer:

Al and Hcl

Explanation:

Reactants are the elements, compounds etc before the arrow

Ethane, because the electron clouds of its molecules are more polarizable than those of propanol.

Ethane is a paraffin series hydrocarbon with the chemical formula C2H6, which is a colourless, odourless, gaseous hydrocarbon. The only hydrocarbon with just one carbon-carbon link structurally is ethane. Ethane is primarily used to create ethylene, a feedstock for plastic production. The primary product of ethylene is ethylene, which is subsequently utilised by the petrochemical industry to create a variety of intermediate products, the majority of which are transformed into plastics. * When breathed in, ethane can have an impact on you. Headache, nauseousness, vomiting, lightheadedness, and other symptoms of exposure are possible. Suffocation from a lack of oxygen can occur at extremely high levels.

based on the structural formulas, which of the following identifies the compound that is more soluble in water and best helps to explain why?

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Answer:

4.2 × 10¹⁷ atoms of Se

Explanation:

Step 1: Convert the mass to grams

We will use the conversion factor 1 g = 10⁶ μg.

55 μg × 1 g/10⁶ μg = 5.5 × 10⁻⁵ g

Step 2: Calculate the moles corresponding to 5.5 × 10⁻⁵ g of Se

The molar mass of Se is 78.96 g/mol.

5.5 × 10⁻⁵ g × 1 mol/78.96 g = 7.0 × 10⁻⁷ mol

Step 3: Calculate the atoms in 7.0 × 10⁻⁷ moles of Se

We will use Avogadro's number: there are 6.02 × 10²³ atoms of Se in 1 mole of Se.

7.0 × 10⁻⁷ mol × 6.02 × 10²³ atom/1 mol = 4.2 × 10¹⁷ atom

Answer:

True

Explanation:

There is such thing called tectonic plated

Answer:

True

Explanation:

The crust is made of plates called tectonic plates that move as fast as your finger nails grow, the amount of movement can create both tall and deep earth wonders. Such as the Mariana Trench and Mount Everest. And it causes earthquakes when they slide together.

Pls mark brainliest

Have a nice day!

Answer:

2AlPO4(aq) + 3Mg(s) -------> Mg3(PO4)2(aq) + 2Al(s)

Explanation:

The principle of writing balanced chemical reaction equations states that; the number of atoms of each element on the right hand side of the reaction equation must be equal to the number of atoms of the same element on the left hand side of the reaction equation.

The reaction is between aqueous aluminum phosphate reacts and solid magnesium to produce solid aluminum and aqueous magnesium phosphate. The equation is represented as follows;

2AlPO4(aq) + 3Mg(s) -------> Mg3(PO4)2(aq) + 2Al(s)

The molarity of the diprotic acid that requires 18.73 mL KOH is 1.405 M.

The chemical reaction between a diprotic acid and KOH is

H₂A + 2 KOH → K₂A + 2 H₂O

In stoichiometry, we learn the chemical reaction and the laws that work in it. According to Avogadro's law, the coefficient of a substance in a chemical reaction expresses the ratio of the number of moles of each substance.

\(M \:=\: \frac{n}{V}\)

n = MV

KOH

The number of moles for a diprotic acid

n KOH : n H₂A = 2 : 1
n H₂A = n KOH ÷ 2
n H₂A = 5.619 ÷ 2
n H₂A = 2.8095 mmol

The molarity of a diprotic acid

\(M \:=\: \frac{n}{V}\)
\(M \:=\: \frac{2.8095}{25.00}\)
M = 1.405 M

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The equilibrium constant for the reaction Cu2+(aq)+Zn(s)→Cu(s)+Zn2+(aq) at 25 °C is 4.96 × 10^15.

The standard electrode potentials for Cu2+/Cu and Zn2+/Zn half cells are +0.34 V and -0.76 V, respectively. Using these standard electrode potentials, let us calculate ΔG∘ and use its value to estimate the equilibrium constant for the following reaction:Cu2+(aq)+Zn(s)→Cu(s)+Zn2+(aq)The standard electrode potential for Cu2+/Cu half cell is +0.34 VThe standard electrode potential for Zn2+/Zn half cell is -0.76 V.

The value of ΔG∘ can be calculated as follows:ΔG∘= -n FE ∘cell Where, n is the number of electrons exchanged, F is the Faraday constant and E∘ cell is the standard cell potential. Substituting the values, we getΔG∘= -2 × 96485 × (1.1) = -212118.7 J/mol = -212.12 kJ/mol The equilibrium constant Kc can be obtained from the relationshipΔG∘= -RT ln Kc where, R is the gas constant and T is the temperature in Kelvin.

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The separation technique that would be used to separate copper (II) sulfate from carbon is filtration, followed by the evaporation of the solvent.

Filtration is the best method to use since it separates solids from liquids. The mixture can be poured onto a filter paper, and the copper (II) sulfate will dissolve in the water and pass through the filter paper while the carbon remains behind.

Once the copper (II) sulfate is separated from the carbon, it can be retrieved by evaporating the solvent leaving the solid copper (II) sulfate behind. This method works because copper (II) sulfate is a water-soluble compound while carbon is not.

By using filtration and evaporation, we can separate both components of the mixture.

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Answer:

The mass of KF in the mixture is 2.77 gms.

Explanation:

Given;

Total weight of mixture (LiF+KF)=5.32gms

Let, mass of KF in the mixture = x gms

⟹ mass of LiF in mixture =(5.32-x)gms.

We know that :

Atomic weight of F=19gms.

Atomic weight of Li =7gms.

Atomic weight of K = 39 gms.

moles=mass/(molecular weight)

Thus, moles of KF=x/58

and moles of LiF = (5.97-x)/26LiF=(5.97−x)/26

Thus,

moles of F in KF=moles of KF=x/58 ---(1)

moles of F in LiF =moles of LiF= (5.32-x)/26---(2)

From (1) & (2),

Total moles of Fluorine

=(x/58)+((5.32-x)/26)

Hence,

total weight of Fluorine in sample = moles*Atomic weight

=((x/58)+((5.32-x)/26))*19gms.

=3.12 gms.---(given)

Now, solving the equation for x,

26x +(5.32*58)-58x

=3.12*58*26/19

22x=308.56-247.62

x=60.94/22

=2.77 gms. (Answer)

Thus, the mass of KF in the mixture is 2.77 gms.

The product composition at equilibrium of cracking pure n-butane to produce olefins is determined by the equilibrium constants.

At equilibrium, the product composition of cracking pure n-butane to produce olefins is determined by the equilibrium constants, K1 and KII.

Using these constants, we can calculate the mole fractions of the products.

The mole fraction of \(C_2H_4\) is calculated by using the formula, (1 + K1/\(KII)^{(-1/2)\), which gives a value of 0.526.

The mole fraction of \(C_2H_6\) is calculated by using the formula, K1/(1 + K1/KII), which gives a value of 0.297.

The mole fraction of \(C_3H_6\) is calculated by using the formula, KII/(1 + K1/KII), which gives a value of 0.146.

The mole fraction of \(CH_4\) is calculated by using the formula, (1 + K1/\(KII)^{(-1/2),\) which gives a value of 0.031.

Therefore, at equilibrium, the product composition is 52.6% \(C_2H_4\), 29.7% \(C_2H_6\), 14.6% \(C_3H_6\), and 3.1% \(CH_4\).

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At equilibrium, the product composition will be 50.1% C2H4, 49.9% C3H6, and negligible amounts of C2H6 and CH4. This is due to the high equilibrium constant for reaction II.

The equilibrium constant expression for each reaction is given by K1 = [C2H4][C2H6] and KII = [C3H6][CH4]/[C4H10]. Assuming x is the extent of reaction for both reactions, the equilibrium concentrations are [C4H10] = P - x, [C2H4] = [C2H6] = x/2, and [C3H6] = [CH4] = xII. Substituting these into the equilibrium constant expressions and solving for x and xII gives x = 0.459 and xII = 0.000171. Therefore, the product composition is 50.1% C2H4, 49.9% C3H6, and negligible amounts of C2H6 and CH4. This is because the equilibrium constant for reaction II is much higher than that for reaction I, meaning that more C3H6 and CH4 are formed than C2H6, making C3H6 the dominant product.

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The total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.

To calculate the total charge that flows while the battery is being charged, we can use the relationship between electrical energy, potential difference, and charge.

The electrical energy (E) stored in the battery is given as 64 mega Jules (64 MJ). The potential difference (V) provided by the battery is 330 volts. We know that the energy (E) is equal to the product of the potential difference (V) and the charge (Q):

E = V * Q

Since the charging process is 100% efficient, all the electrical energy supplied is stored in the battery. Therefore, we can rearrange the equation to solve for the charge (Q):

Q = E / V

Substituting the given values, we have:

Q = 64 MJ / 330 V

To perform the calculation, we need to convert mega Jules (MJ) to joules (J) since the SI unit of energy is joules. One mega Joule is equal to 1 million joules:

Q = (64 * 10^6 J) / 330 V

Calculating the division:

Q ≈ 193,939.39 Coulombs

Therefore, the total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.

This value represents the quantity of electric charge transferred during the charging process, and it indicates the amount of electricity that enters the battery.

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Heterogeneous and homogeneous mixes are the two types of mixtures. While homogeneous mixes seem consistent throughout, heterogeneous mixtures have clearly discernible components. A solution, which can be a solid, liquid, or gas, is the most typical kind of homogeneous combination.

A homogenous mixture is one whose composition is constant across the whole mixture. The dissolved salt is uniformly dispersed across the whole salt water sample, making the salt water in the example above homogenous.

A combination is said to be heterogeneous if its composition is not constant throughout. for example, vegetable soup is a complex concoction. Each mouthful of soup will have differing percentages of the various veggies and other ingredients.

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Answer:

I think its 639/80

Explanation: