The pH of the solution after 20.0 ml of 0.200 M NaOH is added to a 50.0 ml sample of 0.150 M HCl is 13.03.
To calculate the pH after 20.0 ml of 0.200 M NaOH is added to a 50.0 ml sample of 0.150 M HCl, we need to use the equation for the reaction between the acid and base:
HCl + NaOH → NaCl + H2O
We can start by calculating the amount of moles of HCl in the initial solution:
n(HCl) = M(HCl) x V(HCl)
n(HCl) = 0.150 mol/L x 0.050 L
n(HCl) = 0.0075 mol
Since the reaction is a 1:1 stoichiometry, the amount of moles of NaOH added to the solution will be equal to the amount of moles of HCl originally present:
n(NaOH) = n(HCl)
n(NaOH) = 0.0075 mol
We can use the amount of moles of NaOH and the volume of NaOH added (20.0 ml) to calculate the new concentration of NaOH:
M(NaOH) = n(NaOH) / V(NaOH)
M(NaOH) = 0.0075 mol / 0.020 L
M(NaOH) = 0.375 M
Now, we can calculate the amount of moles of HCl remaining in the solution after the addition of NaOH:
n(HCl) = n(HCl)initial - n(NaOH)
n(HCl) = 0.0075 mol - 0.0075 mol
n(HCl) = 0.000 mol
This means that all the HCl has reacted with the NaOH, and we are left with only NaCl and water in the solution. To calculate the pH, we need to calculate the concentration of NaCl:
n(NaCl) = n(NaOH)
n(NaCl) = 0.0075 mol
M(NaCl) = n(NaCl) / V(solution)
M(NaCl) = 0.0075 mol / 0.070 L
M(NaCl) = 0.107 M
We can use the concentration of NaCl to calculate the concentration of H+ ions (which is the same as the concentration of OH- ions since the solution is neutral):
[H+] = [OH-] = Kw / [NaCl]
[H+] = [OH-] = 1.0 x 10^-14 / 0.107 M
[H+] = [OH-] = 9.35 x 10^-14 M
Finally, we can use the pH equation to calculate the pH:
pH = -log[H+]
pH = -log(9.35 x 10^-14)
pH = 13.03
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To calculate the pH after 20.0 mL of 0.200 M NaOH have been added to a 50.0 mL sample of 0.150 M HCl, follow these steps:
1. Determine the moles of HCl and NaOH:
moles of HCl = (volume of HCl) x (concentration of HCl) = (50.0 mL) x (0.150 M) = 7.5 mmol
moles of NaOH = (volume of NaOH) x (concentration of NaOH) = (20.0 mL) x (0.200 M) = 4.0 mmol
2. Calculate the moles of remaining HCl after the reaction:
Since HCl and NaOH react in a 1:1 ratio, subtract the moles of NaOH from the moles of HCl: 7.5 mmol - 4.0 mmol = 3.5 mmol of HCl remaining.
3. Calculate the concentration of remaining HCl:
Since the total volume of the solution has increased, new concentration = (moles of HCl) / (total volume in L) = (3.5 mmol) / (50.0 mL + 20.0 mL) x (1 L/1000 mL) = 0.050 M
4. Calculate the pH of the solution:
Since the remaining solution contains only HCl, the pH is determined by the concentration of H+ ions. For HCl, [H+] = [HCl], so pH = -log[H+] = -log(0.050) ≈ 1.30
In conclusion, after 20.0 mL of 0.200 M NaOH have been added to a 50.0 mL sample of 0.150 M HCl, the pH of the solution is approximately 1.30.
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true or false. a hot plate is the only heat source available in the lab room to heat the hydrate in a crucible at least 2 times for 10-15 minutes at medium-high setting.
The given statement "A hot plate is the only heat source available in the lab room to heat the hydrate in a crucible at least 2 times for 10-15 minutes at medium-high setting" is true because the water in hydrate can be removed by heating.
The crucible is the type of the laboratory glassware that is designed to melt or to burn the solid chemicals over the burner. Crucible is made from the heat resistant ceramic or the metal. The hot plates are the laboratory tools that is used for the uniformly heat the samples. The hot plates are available with Varity of the number of the different heating top styles.
Thus, the hot plate is the heating tool to heat the hydrate in the crucible.
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A 50. 0 ml sample of 0. 468 m nh4no3 is diluted with water to a total volume of 290. 0 ml. What is the ammonium nitrate concentration in the resulting solution?.
The ammonium nitrate concentration in the resulting solution is 0.08 M.
The molarity and volume are related to each other by the formula -
\( M_{1}\) \( V_{1}\) = \( M_{2}\) \( V_{2}\), where values at Left Hand Side are initial concentration and volume and values are Right Hand Side are final concentration.
Keep the values in formula to find final concentration.
0.467 × 50 = \( M_{2}\) × 290
Performing multiplication in the equation
\( M_{2}\) = 23.35 ÷ 290
Performing division on Right and Side of the equation
\( M_{2}\) = 0.08 M
Thus, the final molarity is 0.08 M.
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what does Combustion do? (ez) (just for points)
Combustion is a chemical process in which a substance reacts rapidly with oxygen and gives off heat. The original substance is called the fuel, and the source of oxygen is called the oxidizer. The fuel can be a solid, liquid, or gas, although for airplane propulsion the fuel is usually a liquid. HoPe iT doSe WhaT EvEr U nEed IT foR hUmAn
Consider this reaction. What volume of oxygen gas, in milliliters, is required to react with 0.640 g of SO2 gas at S TP? 11.2 mL 22.4 mL 112 mL 224 mL
Answer:
112mL
Explanation:
We'll begin by calculating the number of mole in 0.640g of SO2.
This is illustrated below:
Molar mass of SO2 = 32 + (16x2) = 64g/mol
Mass of SO2 = 0.640g
Number of mole of SO2 =.?
Mole = mass /molar mass
Number of mole of SO2 = 0.640/64
Number of mole of SO2 = 0.01 mole
Next, we shall determine the number of mole of O2 required for the reaction. This is illustrated below:
2SO2(g) + O2(g) —> 2SO3(g)
From the balanced equation above,
2 moles of SO2 reacted with 1 mole of O2.
Therefore, 0.01 mole of SO2 will react with = (0.01 x 1)/2 = 0.005 mole of O2.
Therefore, 0.005 mole of O2 is required for the reaction.
Finally, we shall determine the volume of O2 required for the reaction as follow:
Note: 1 mole of a gas occupy 22.4L (22400mL) at stp.
1 mole of O2 occupy 22400mL at stp.
Therefore, 0.005 mole of O2 will occupy = 0.005 x 22400 = 112mL
Therefore, 112mL of O2 is required for the reaction.
Answer:
the answer is C
Explanation:
i did the test on edg and got it right
Ordered sodium amytal 0.1 gm IM stat Available sodium amytal 200mg/3ml How many mls would you give IM?
To get a dose of 0.1 gm (100 mg), 1.5 ml of sodium amytal solution must be injected intramuscularly (IM).
What is sodium amytal ?We can use the available concentration and the desired dose.
Given
Available sodium amytal concentration: 200 mg/3 mlDesired dose: 0.1 g (which is equivalent to 100 mg)First, we need to convert the desired dose from grams to milligrams:
0.1 g = 100 mg
Now, we can set up a proportion to find the volume of solution needed:
(100 mg) / (200 mg) = (x ml) / (3 ml)
Cross-multiplying and solving for x:
100 mg * 3 ml = 200 mg * x ml
300 mlmg = 200 mlmg
x ml = (300 ml*mg) / (200 ml)
x ml = 1.5 ml
So, To get a dose of 0.1 gm (100 mg), 1.5 ml of sodium amytal solution must be injected intramuscularly (IM).
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In the reaction 2H2 + O2 → __H2O, what coefficient should be placed in front of H2O to balance the reaction?
1
2
3
4
Answer:
Below
Explanation:
2 H2 + O2 ====> H20 you have 4 H's on L...need 4 on right so:
2H2 + O2 =====> 2 H2 O Now H's are 'balanced' and a check of the O's shows they are balanced too (two O's on each side)
What is the mass shown?
(Sorry u cant really see!)
A cylinder container with a diameter of 23.0 cm and a height of 140 cm contains N2O at a pressure of 108 kpa and temperature of 294 K. How many grams of N2O gas are in the cylinder?
Answer:
113.17 g
Explanation:
This can be solved using the Ideal Gas Equation:
PV=nRT
First step is to calculate the volume of the cylinder in L:
V=πr²h
V= π (11.5)² (140)
V= π (132.25) (140)
V = π (18.515)
V = 58,166.588 cm³ = 58.2 L
Then, convert kpa into atm:
1 kpa = 0.00987 atm
108 kpa = 1.06588 atm
Then, plug all of your values into the Ideal Gas Equation to solve for moles:
(1.06588)(58.2)=n(0.082057)(294)
62.034=n(24.125)
2.571357513=n
Finally, convert the moles into grams
2N = 28.0134 amu
O = 15.999 amu
_______________
44.0124 amu
(2.571357513moles)(44.0124 amu) = 113.17 g
a molecule of an element is called what?
Answer:
a molecule of an element is called atomicity
Relative Strengths of oxyacids and Amines < 9 of 11 > Bases act as hydrogen ion acceptors because of the unshared electron pairs in their structure. Any group present in a base that withdraws electrons makes these electron pairs less available to accept a hydrogen ion. In contrast, any group that can act as an electron donating group such as hydrocarbon groups (usually represented as R) can increase the base strength. Thus, the addition of electronegative atoms or groups of atoms to the structure of a base decreases the base strength and electron donating groups increase base strength. Many common weak bases are derivatives of ammonia, in which H atom(s) of NH3 are replaced with other groups. Part B Arrange the following amines in order of decreasing base strength. Rank from strongest to weakest base. To rank items as equivalent, overlap them. View Available Hint(s) Reset Help NH3 (CH3)2NH CH3NH, NH,Br Strongest base Weakest base The correct ranking cannot be determined. Submit Previous Answers Request Answer
To rank the following amines in order of decreasing base strength: NH₃ > (CH₃)₂NH > CH₃NH₂ > NH₂Br.
The order of base strength is determined by the availability of the lone pair of electrons on the nitrogen atom, which can be donated to form a bond with a proton (H⁺).
NH3 has the highest base strength because it has the most electron-donating groups (three hydrogens) attached to the nitrogen atom, making the lone pair of electrons more available.
(CH₃)₂NH is the next strongest base because it also has two electron-donating methyl groups attached to the nitrogen atom.
CH₃NH₂ has only one electron-donating methyl group, so it is weaker than (CH₃)₂NH.
NH₂Br is the weakest base because the electronegative bromine atom withdraws electron density from the nitrogen atom, making the lone pair of electrons less available.
Therefore, the correct ranking from strongest to weakest base is:
NH₃ > (CH₃)₂NH > CH₃NH₂ > NH₂Br.
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For a phase change, AH = 31 kJ/mol and Sº= 0.093 kJ/(K-mol). What are
AG and the spontaneity of the phase change at 300 K?
OA. AG 3.1 kJ; nonspontaneous
OB. AG=59 KJ; spontaneous
OC. AG= 3.1 kJ; spontaneous
O D. AG= 59 KJ; nonspontaneous
Based on the calculations, the Gibbs's free energy and spontaneity of the phase change are equal to: C. ΔG° = 3.1 kJ; spontaneous.
Given the following data:
Enthalpy of reaction (ΔH°) = 31 kJ/mol.Temperature = 300 K.Entropy of reaction (ΔS°) = 0.093 kJ/mol.How to calculate Gibbs's free energy?Mathematically, the Gibbs's free energy for this chemical reaction can be calculated by using this formula:
ΔG° = ΔH° - ΔS°
Substituting the given parameters into the formula, we have;
ΔG° = 31 × 10³ - (300 × 0.093)
ΔG° = 31 × 10³ - 27.9 × 10³
ΔG° = 3.1 kJ.
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A gas has a temperature of 14 °C, and a volume of 4.5 liters. If the temperature is raised to 29
°C and the pressure is not changed, what is the new volume of the gas
The new volume of the gas wii be 4.7 liters.
How many quarts of 5% solution can be made from 4.73 grams of
drug?
The number of quarts of 5% solution that can be made from 4.73 grams of the drug is 100 quarts.
To calculate the number of quarts of 5% solution that can be made from 4.73 grams of the drug, we need to use the formula that relates the amount of drug to the concentration and volume of the solution. Let's first convert the drug quantity to grams. Since 1 gram is equivalent to 1000 milligrams, then:
4.73 grams = 4730 milligrams
Now, let's plug in the values into the formula and solve for the volume of the solution.
Amount of drug (in grams) = Concentration (as a decimal) × Volume of solution (in milliliters)
To convert milliliters to quarts, we will divide the volume by 946.35 (1 quart = 946.35 milliliters). So we have:
4730 mg = 0.05 × Volume of solution (in milliliters)
Volume of solution = 4730 ÷ 0.05 = 94,600 milliliters (ml)
Number of quarts of solution = 946.35 = 100 quarts (rounded to the nearest whole number).
Therefore, 100 quarts of 5% solution can be made from 4.73 grams of the drug.
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PLEASE URGENT HELP!! 30 POINTS!!!!!!
Answer:
CH³–C=CH——CH³–CH=CH²
Explanation:
THIS IS PROPYNE TO PROPENE
Section 1: Parts of Chemical Reaction and Conservation of mass
1) Identify the reactants cand products of the following
Chemical equation:
(The equation in image)
Answer:
The reactants are on the left of the arrow, the products are on the right.
Explanation:
Reactants are the substances that exist before the chemical reaction takes place. When writing a chemical reaction or equation, they are found on the left of the arrow. They react to form new substances, which are known as the products. The products are found to the right of the arrow in the reaction.
write the equation for the acid hydrolysis of glyceryl trioleate (triolein).
The glyceryl trioleate (triolein) acid hydrolysis equation calls for the interaction of the triglyceride with an acid, often a powerful acid like hydrochloric acid (HCl).
The triglyceride is converted into its component fatty acids and glycerol during this process. For triolein, a particular triglyceride made up of three oleic acid molecules esterified to a glycerol molecule, the equation is as follows:
C₅₇H₁₀₄O₆ + 3H₂O + 3HCl → 3C₁₇H₃₃COOH + C₃H₈O₃
In this equation:
C₅₇H₁₀₄O₆ represents the glyceryl trioleate (triolein) molecule.
3H₂O represents three water molecules, which are needed for the hydrolysis reaction.
3HCl represents three molecules of hydrochloric acid, which serve as the catalyst for the reaction.
3C₁₇H₃₃COOH represents the three oleic acid molecules released from triolein.
C₃H₈O₃ represents the glycerol molecule released from triolein.
Triolein undergoes acid hydrolysis when it reacts with hydrochloric acid, rupturing the ester bonds between the fatty acids and the glycerol molecule to produce the appropriate fatty acids and glycerol.
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The gas formed when coal is heated in the absence of air_____________
How many centimeters are in 5 miles? Hint: 1 miles = 5280 feet
the central atom in the icl4- ion has nonbonded electron pair(s) and bonded electron pair(s) in its valence shell. question 9 options: a) 6, 0 b) 0, 4 c) 2, 4 d) 2, 2 e) 4, 2
The central atom in the icl4- ion has nonbonded electron pair(s) and bonded electron pair(s) in its valence shell is 2 and 4 respectively.
The central atom is generally the atom with the lowest subscript within the molecular system and the atom that may shape the maximum bonds. If all the atoms commonly shape an equally wide variety of bonds, the least electronegative atom is usually the critical atom.
A bonding electron is an electron concerned with chemical bonding. this could confer with: Chemical bond, a lasting appeal between atoms, ions, or molecules. A covalent bond or molecular bond is a sharing of electron pairs between atoms. A bonding molecular orbital is an attraction among the atomic orbitals of atoms in a molecule.
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what are the three parts of nucleotide
Answer:
The three parts of the nucleotide building block of DNA are the sugar, the base and the phosphate.
Explanation:
Hope that helps!
Answer:
three parts of the nucleotide building block of DNA are the sugar, the base and the phosphate.
How many moles of the product can be made when 5 moles of B2 and 6 moles of AB2?
Answer:
Explanation:yo what is you talkin about
2. Briefly list and describe radiocarbon and radiopotassium
dating methods. What chemical process forms the basis of the
method? How, in general, does each work? Time frame? (10-15
sentences explanati
Radiocarbon dating, also known as carbon-14 dating, is a method used to determine the age of organic materials. It is based on the radioactive decay of the isotope carbon-14 (14C).
Living organisms constantly absorb carbon, including a small amount of carbon-14, from the atmosphere. When an organism dies, it no longer takes in carbon-14, and the existing carbon-14 begins to decay at a known rate. By measuring the ratio of carbon-14 to stable carbon isotopes (carbon-12 and carbon-13) in a sample, scientists can estimate the time that has elapsed since the organism's death. Radiocarbon dating is effective for dating materials up to about 50,000 years old.
Therefore, both radiocarbon dating and radiopotassium dating rely on the principles of radioactive decay. The decay rates of the isotopes used in these methods are well-established and constant, allowing for accurate age determinations.
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a diagram of the electromagnetic spectrum is shown. which wavelength is the longest safest wavelengths for humans? Helppp pleaseee
Answer:
radio waves
Explanation:
the answer is simple, radio waves. it is radio waves because when you look at the diagram the waves below Radio are very long. if you look at the waves under gamma ray, they are very short. radio is the longest wave while gamma is the shortest. if you are still confused it also says longer wavelength and low frequency( meaning it is safe) right under the wavelength.
the structure of the nacl crystal forms reflecting planes 0.541 nm apart. what is the smallest angle, measured from these planes, at which constructive interference of an x-ray beam reflecting off the two planes is observed? assume x-rays of wavelength 0.0649 nm are used? give your answer in degrees.
The smallest angle, measured from the reflecting planes, at which constructive interference of an X-ray beam is observed is approximately 27.2 degrees.
To determine the smallest angle of constructive interference, we can use Bragg's Law, which states that constructive interference occurs when the path difference between two waves is equal to an integer multiple of the wavelength. The formula is given as:
2d sin(θ) = nλ
Where:
d is the distance between the reflecting planes (0.541 nm)
θ is the angle between the incident X-ray beam and the planes (the desired angle)
n is the order of the interference (we are considering the first-order, so n = 1)
λ is the wavelength of the X-ray beam (0.0649 nm)
Rearranging the formula, we get:
sin(θ) = (nλ) / (2d)
θ = arcsin((nλ) / (2d))
Plugging in the values, we have:
θ = arcsin((1 * 0.0649 nm) / (2 * 0.541 nm))
θ ≈ 27.2 degrees
Therefore, the smallest angle at which constructive interference is observed is approximately 27.2 degrees.
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what is the volume of 15.0 g of ice
A. 7.5
B. 13.8
C. 15.0
D. 16.3
When we convert 15 g of ice to volume in milliliters (mL), the result obtained is 15 mL (option C)
Conversion scale1 g = 1 mL
How to convert 15 g to mL1 g is equivalent to 1 mL.
Therefore,
15 g will also be equivalent to 15 mL
Thus,
15 g = 15 mL
The correct answer to the question is 15 (Option C)
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PLS HELP!!
Which of these processes are catabolic reactions? Check all that apply.
conversion of glycogen to glucose
conversion of glucose to stored lipid
bone growth
reduction reactions
breakdown of ATP to form ADP
Answer:
It's A) and E)
Explanation:
Did the assignment
Answer:
A. conversion of glycogen to glucose and
E. breakdown of ATP to form ADP
Explanation: I also did the assignment.
How can you determine an atom's atomic mass?
Answer: I think you're supposed to add the protons and neutrons and then that's your answer. Sorry if I'm wrong :/
Explanation:
a sample of unknown material weighs 500 n in air and 200 n when immesersed in alcholol with a specfic gravity of 0.7 what is the mass density
Answer: The mass density is 1166.36 \(kg/m^{3}\).
Explanation:
Given: Weight of sample in air \((F_{air})\) = 500 N
Weight of sample in alcohol \((F_{alc})\) = 200 N
Specific gravity = 0.7 = \(0.7 \times 1000 = 700 kg/m^{3}\)
Formula used to calculate Buoyant force is as follows.
\(F_{B} = F_{air} - F_{alc}\\= 500 - 200 \\= 300 N\)
Hence, volume of the material is calculated as follows.
\(V = \frac{F_{B}}{\rho \times g}\)
where,
\(F_{B}\) = Buoyant force
\(\rho\) = specific gravity
g = acceleration due to gravity = 9.81
Substitute the values into above formula.
\(V = \frac{F_{B}}{\rho \times g}\\= \frac{300}{700 \times 9.81}\\= \frac{300}{6867}\\= 0.0437 m^{3}\)
Now, mass of the material is calculated as follows.
\(mass = \frac{F_{air}}{g}\\= \frac{500 N}{9.81}\\= 50.97 kg\)
Therefore, density of the material or mass density is as follows.
\(Density = \frac{mass}{volume}\\= \frac{50.97 kg}{0.0437 m^{3}}\\= 1166.36 kg/m^{3}\)
Thus, we can conclude that the mass density is 1166.36 \(kg/m^{3}\).
why does the hydrogen gas need to flow continuously for a while before starting the heating process?
In the laboratory, hydrogen gas is used as fuel for various purposes, including heating. In order to start the heating process, it is necessary to allow the hydrogen gas to flow continuously for a while. This is because there may be air or other gases present in the hydrogen gas pipeline that can affect the heating process.
When the hydrogen gas is allowed to flow continuously for a while, the air or other gases are purged from the pipeline, which improves the quality of the hydrogen gas. This ensures that there is no interference with the heating process, which could otherwise lead to inaccurate results.The continuous flow of hydrogen gas is essential because if it is not allowed to flow for a while, air or other gases can cause damage to the burner or other equipment used for heating. The air or other gases can cause an explosion, which can result in severe injury or death.In conclusion, the hydrogen gas needs to flow continuously for a while before starting the heating process to remove any air or other gases from the pipeline. This improves the quality of the hydrogen gas, ensures accurate results, and prevents damage to the equipment. It is important to follow safety protocols when using hydrogen gas to prevent any accidents.For such more question on heating process
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SERE
Which of the following is an input for cellular respiration?
а.
CO2
b. H2O
C. sunlight
d. O2
Please select the best answer from the choices provided
A
B
оооо
С
Answer:
d. oxygen (O2) is the answer