The particular solution can be expressed as y_p(x) = (-2wx + C₁)x + 19x² + C₂, where w, C₁, and C₂ are constants.
To find a particular solution, we can use the method of variation of parameters. Since x, x², and are solutions to the homogeneous equation, we can assume the particular solution to have the form y_p(x) = u(x)x + v(x)x² + w(x).
Substituting this into the differential equation, we have:
x³y_p'' + x²y_p' - 2xy_p' + 2y_p = 38x
Differentiating y_p(x) with respect to x, we get:
y_p' = u'x + u + 2vx + 2xv' + wx + 2xw'
Taking the second derivative, we have:
y_p'' = u''x + 2u' + 2v'x + 2v + 2w'x + w
Now, substituting these expressions into the differential equation and equating coefficients, we get:
x³(u''x + 2u' + 2v'x + 2v + 2w'x + w) + x²(u'x + u + 2vx + 2xv' + wx + 2xw') - 2x(u + vx + x²v' + wx) + 2(u + vx + x²v' + wx) = 38x
Expanding and simplifying the equation, we get:
x³u'' + 3x²u' + 3xu + 2x³v' + 4x²v + 2x³w' + 4x²w + x²u' + xu + 2x²v' + 2xv + x²w + 2xw - 2u - 2vx - 2x²v' - 2wx + 2u + 2vx + 2x²v' + 2wx = 38x
Simplifying further, we have:
4x³w' + 4x²w + 2x²u' + 2xv = 38x
Equating coefficients, we get the following system of equations:
4w' = 0
4w + 2u' = 0
2v = 38
From the first equation, we find that w' = 0, which implies w is a constant. From the second equation, we have u' = -2w. Integrating both sides, we get u = -2wx + C₁, where C₁ is a constant. Finally, from the third equation, we find that v = 19.
Therefore, the particular solution is given by:
y_p(x) = (-2wx + C₁)x + 19x² + C₂, where C₁ and C₂ are constants.
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Develop a full regression model based on all the predictor variables indicated. Choose the right model equation below
A. Assessed Value = 246.42+43.94*(Size) + 15.69*(Fireplace Coded)+8.25*(Bedrooms) B. Asking Price = 246.42+43.94*(Size) + 15.69*(Fireplace Coded)+8.25*(Bedrooms)
C. Assessed Value = 246.42+43.94*(Size) + 15.69*(Fireplace Coded)+0.9677*(Bathrooms) D. Assessed Value = 244.4325 + 43.5532*(Size)+ 8.1910*(Bedrooms)+ 0.9677*(Bathrooms)
Q2. A review of the t-test on the significance of individual independent variable suggests that, based on the p-values
A. Only one of the independent variable possibly needs to be retained B. Two of the independent variables possibly needs to be retained C. None of the independent variables could be retained D. Three of the independent variables could be retained
Q3:
Choose the right option below. Based on the full regression model involving all of the independent variables
A. VIF for Size = 2.336, VIF for Fireplace = 1.121, VIF for bedrooms = 1.979
B. VIF for Size = 5.3352, VIF for Fireplace = 10.1873, VIF for bedrooms = 2.7885
C. VIF for Fireplace = 1.1873, VIF for bedrooms = 1.9885
D. None of the above
Q4: Based on VIF values, there is concern for collinearity in this dataset
A. True B. False
Q5:
Based on the normal probability plot, the normality assumption seems to be met
A. True
B. False
Q:7: Based on conducting residual analysis the model seems
Group of answer choices
Adequate
Inadequate
Violates Independence Assumption
Not enough information to assess the LINE assumptions
Q.2: A review of the t-test on the significance of individual independent variable suggests that, based on the p-values. None of the independent variables could be retained. This is because if the p-value is high, it means the significance is low.
Q3: Choose the right option below. Based on the full regression model involving all of the independent variables. VIF for Size = 5.3352, VIF for Fireplace = 10.1873, VIF for bedrooms = 2.7885.
Q.4: Based on VIF values, there is concern for collinearity in this dataset. True
Q5: Based on the normal probability plot, the normality assumption seems to be met. True
Q7: Based on conducting residual analysis the model seems. Adequate.
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A company purchased two vehicles for its sales force to use. The following functions give the respective values of the vehicles after x years
The polynomial function V that gives the combined value of both cars after x years is V(x) = (-5,393 + F)x + 55,273.
The combined value of the two cars after 3 years is $(39,094 + 3F)
To find the combined value of both cars after x years, we simply add the values of each car at that time.
So, we can write:
V(x) = 7x - 2,500x + 23,425 + F(x) - 2,900x + 31,848
Simplifying this expression, we can combine like terms:
V(x) = (7 - 2,500 + F - 2,900)x + (23,425 + 31,848)
V(x) = (-5,393 + F)x + 55,273
So the polynomial function V that gives the combined value of both cars after x years is,
V(x) = (-5,393 + F)x + 55,273
Now, to find the combined value of the two cars after 3 years,
We simply plug in x=3 into the function V(x),
V(3) = (-5,393 + F)(3) + 55,273
We don't have a value for F,
So we can't solve for V(3) exactly.
However, we can still simplify this expression by distributing the 3,
V(3) = (-16,179 + 3F) + 55,273
V(3) = 39,094 + 3F
So the combined value of the two cars after 3 years is 39,094 + 3F.
We don't know the value of F, so we can't give a specific number for this answer.
However, we can say that as long as we know the value of F,
We can plug it in to find the exact combined value of the two cars after 3 years.
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The complete question is:
Craig just purchased a new car. He financed $45000 and must pay it back over 5 years with 11% interest.
How much will he have paid for his car, including interest, after 5 years?
Answer:
$49950
Step-by-step explanation:
you do 45000(.11) which equals 4950. and then you add 4,950 to 45000, and then you get your answer
Find the amount of periodic payment necessary for the deposit to a sinking fund. (Round your answer to the nearest cent.)
$ X
Amount Needed Frequency Rate Time
A n r t
————————————————————————
$85,000 quaterly 1,4 % 5 yr
The amount of the periodic payment necessary for the deposit to a sinking fund is approximately $18,065.19.
To find the amount of the periodic payment necessary for the deposit to a sinking fund, we can use the formula for the future value of an ordinary annuity. The formula is:
X = A * (1 + r)^nt / [(1 + r)^nt - 1]
Where:
X is the amount needed
A is the periodic payment
r is the interest rate per period
n is the number of compounding periods per year
t is the total number of years
Given the information:
Amount Needed (X) = $85,000
Frequency: Quarterly
Rate (r) = 1.4% (or 0.014 as a decimal)
Time (t) = 5 years
Since the frequency is quarterly, the number of compounding periods per year (n) is 4.
Substituting the values into the formula:
$85,000 = A * (1 + 0.014)^(4*5) / [(1 + 0.014)^(4*5) - 1]
Simplifying the equation:
$85,000 = A * (1.014)^20 / [(1.014)^20 - 1]
To find the value of A, we can rearrange the equation:
A = $85,000 * [(1.014)^20 - 1] / (1.014)^20
Using a calculator or spreadsheet, we can calculate the value of A.
A ≈ $85,000 * 0.298 / 1.350
A ≈ $18,065.19
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For a lower tail test, the p-value is the probability of obtaining a value for the test statistic at least as.
The answer will be, at least as small as that provided by the sample using p-value.
What is the p-value?
Under the premise that the null hypothesis is true, the p-value in null-hypothesis significance testing represents the likelihood of receiving test findings that are at least as extreme as the result actually observed. A severe observed outcome would be highly improbable under the null hypothesis, according to a very small p-value. In academic papers of many quantitative fields, reporting the p-values of statistical tests is standard practice. Misuse of p-value is common and has been a big concern in metascience due to its difficult-to-understand precise meaning.
The probability that a population parameter in a particular statistical model will be less than a given value when the null hypothesis is true is known as the p-value,
And that is also known as a probability value or a measure of significance.
Hence the probability is, at least as small as that provided by the sample using p-value.
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A summer camp cookout is planned for the campers and their families. There is room for 200 people. Each adult costs 4, and each camper costs4,and each camper costs3. There is a maximum budget of $750. Write the system of inequalities to represent this real-world scenario, where x is the number of adults and y is the number of campers.
A. \begin{gathered}x + y \leqslant 200 \\ 4x + 3y \leqslant 750\end{gathered}x+y⩽2004x+3y⩽750
B. \begin{gathered}x + y \leqslant 750 \\ 4x + 3y \leqslant 200\end{gathered}x+y⩽7504x+3y⩽200
C. \begin{gathered}x + y \leqslant 200 \\ 3x + 4y \leqslant 750\end{gathered}x+y⩽2003x+4y⩽750
D. \begin{gathered} x + y \leqslant 750 \\ 3x + 4y \leqslant 200\end{gathered}x+y⩽7503x+4y⩽200
Answer:
Option A
The system of inequalities
x + y ≤ 200
4x + 3y ≤ 750
Step-by-step explanation:
Let the
Number of Adults = x
Number of campers = y
A summer camp cookout is planned for the campers and their families.
There is room for 200 people.
x + y ≤ 200
Each adult costs $4, and and each camper costs $3. There is a maximum budget of $750.
Maximum means the total cost is equal to or less than $750
$4 × x + $3 × y ≤ $750
4x + 3y ≤ 750
The system of inequalities
x + y ≤ 200
4x + 3y ≤ 750
Option A is correct
For the following set of data, find the percentage of data within 2 population standard deviations of the mean, to the nearest percent
chart is in the photo
Percentage of data within 2 population standard deviations of the mean is 68%.
To calculate the percentage of data within two population standard deviations of the mean, we need to first find the mean and standard deviation of the data set.
The mean can be found by summing all the values and dividing by the total number of values:
Mean = (20*2 + 22*8 + 28*9 + 34*13 + 38*16 + 39*11 + 41*7 + 48*0)/(2+8+9+13+16+11+7) = 32.68
To calculate standard deviation, we need to calculate the variance first. Variance is the average of the squared differences from the mean.
Variance = [(20-32.68)^2*2 + (22-32.68)^2*8 + (28-32.68)^2*9 + (34-32.68)^2*13 + (38-32.68)^2*16 + (39-32.68)^2*11 + (41-32.68)^2*7]/(2+8+9+13+16+11+7-1) = 139.98
Standard Deviation = sqrt(139.98) = 11.83
Now we can calculate the range within two population standard deviations of the mean. Two population standard deviations of the mean can be found by multiplying the standard deviation by 2.
Range = 2*11.83 = 23.66
The minimum value within two population standard deviations of the mean can be found by subtracting the range from the mean and the maximum value can be found by adding the range to the mean:
Minimum Value = 32.68 - 23.66 = 9.02 Maximum Value = 32.68 + 23.66 = 56.34
Now we can count the number of data points within this range, which are 45 out of 66 data points. To find the percentage, we divide 45 by 66 and multiply by 100:
Percentage of data within 2 population standard deviations of the mean = (45/66)*100 = 68% (rounded to the nearest percent).
Therefore, approximately 68% of the data falls within two population standard deviations of the mean.
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The record low temperature in Wyoming is -63° F. How many degrees below 0 is this?
Answer:
Step-by-step explanation:
It's 63 degrees F below zero.
Temperature is measured on a number line. You can get confused by the freezing point of water which is +32.
0 represents the coldest temperature that those who used Fahrenheit thought the temperature would go. Tell that to the people who lived through - 63.
So the answer if - when the temperature goes below 0.
3x + 2y = -10
5x + y = 9
Answer:
x=4, y=-11. (4, -11).
Step-by-step explanation:
3x+2y=-10
5x+y=9
--------------
3x+2y=-10
-2(5x+y)=-2(9)
--------------------
3x+2y=-10
-10x-2y=-18
-----------------
-7x=-28
7x=28
x=28/7=4
5(4)+y=9
20+y=9
y=9-20=-11
A running club's coach recorded the ages of the teens that participated in a 5k.
the teens' ages are: {16, 18, 15, 14, 17, 16, 17, 15, 17}
what is the interquartile range (iqr) of the teens' ages?
a.1
b.2
c.3
d.4
If the teen's ages that participated in a run are {16, 18, 15, 14, 17, 16, 17, 15, 17} , then the Interquartile Range of the teen's ages is 2 .
The Interquartile range(IQR) is defined as the difference between third quartile (Q₃) and first quartile (Q₁) .
A running club's coach recorded ages of the teen's that participated in a 5k run ,
the teen's ages are ⇒ {16, 18, 15, 14, 17, 16, 17, 15, 17}
we first arrange the data of teen's ages in the increasing order .
we get , {14 , 15 , 15 , 16 , 16 , 17 , 17 , 17 , 18 } .
So , the lower half will be = {14 , 15 , 15 , 16}
the first quartile (Q₁) = (15+15)/2 = 30/2 = 15 ,
the upper half of the data is = {17 , 17 , 17 , 18}
the third quartile (Q₃) = (17 + 17)/2 = 34/2 = 17 .
So , the inter quartile range is = Q₃ - Q₁
= 17 - 15
= 2 .
Therefore , the Interquartile range is = 2 .
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Suppose the function f(t) = 95 cosine (startfraction pi over 10 endfraction t) 120 models the height of a seat on a ferris wheel after t minutes. based on this information, what is the diameter of the ferris wheel? 95 ft 120 ft 190 ft 215 ft
The diameter of the Ferris wheel is equal to 95 ft.
What is a expression? What is a mathematical equation? What is Equation Modelling?A mathematical expression is made up of terms (constants and variables) separated by mathematical operators. A mathematical equation is used to equate two expressions. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.
We have a function that models the height of a seat on a Ferris wheel after [t] minutes.
We have the following function -
f(t) = 95 cos(π/10)t
The diameter of the Ferris wheel would be the maximum height reached by the wheel. We have -
f(t) = 95 cos[(π/10)t]
df/dt = 95 x - sin[(π/10)t] x (π/10)
df/dt = -(95π/10) sin[(π/10)t]
For maximum height -
df/dt = 0
- (95π/10) sin[(π/10)t] = 0
sin[(π/10)t] = 0
sin[(π/10)t] = sin (0)
(π/10)t = 0
t = 0
Put t = 0, in f(t) = 95 cos[(π/10)t], we get -
f(max) = 95 cos(0) = 95 ft
Therefore, the diameter of the Ferris wheel is equal to 95 ft.
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Answer: Option C (190 ft)
Step-by-step explanation:
Statistics can add credibility to speech clims when used sparingly. true or false
Answer:
True
Step-by-step explanation:
Statistics can add credibility to speech clims when used sparingly.
name me brainiest please.
True, statistics can add credibility to speech claims when used sparingly. By incorporating accurate and relevant statistics in a speech, you can support your arguments and demonstrate your knowledge on the subject. However, it is essential to use them sparingly to avoid overwhelming the audience and maintain their interest in your message.
Statistics, when used appropriately and sparingly, can add credibility to speech claims. By incorporating relevant and reliable statistical data, speakers can support their claims with objective evidence. Statistics have the potential to provide context, demonstrate trends, or highlight the magnitude of a particular issue, thereby strengthening the credibility and persuasiveness of the speaker's arguments.
However, it is important to use statistics accurately, ensuring they are from reliable sources, properly interpreted, and presented in a clear and understandable manner. Overusing statistics or relying solely on statistical evidence without considering other forms of supporting evidence may weaken the overall impact of the speech.
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Sean is drinking a slushy as fast as he can.
The amount of slushy left in the cup (in milliliters) as a function of time in seconds) is graphed.
How much slushy did sean drink every 5 seconds
Answer:
40 millimetres
Answer:
40
Step-by-step explanation:
anita created a batch of green paint by mixing 2 ounces of blue paint with 3 ounces of yellow paint. she must mix a second batch using the same ratio of blue and yellow paint as the first batch. if she uses 5 ounces of blue paint for the second batch, how much yellow paint should anita use? a) exactly 5 ounces b) 3 ounces more than the amount of yellow paint used in the first batch c) 1.5 times the amount of yellow paint used in the first batch d) 1.5times the amount of blue paint used in the second batch
Anita created a batch of green paint by mixing 2 ounces of blue paint with 3 ounces of yellow paint. she must mix a second batch using the same ratio of blue and yellow paint as the first batch. C: Anita should use 4.5 ounces of yellow paint for the second batch.
The first batch of green paint was created by mixing 2 ounces of blue paint with 3 ounces of yellow paint, which means that the ratio of blue to yellow paint was 2:3. Anita needs to use the same ratio of blue to yellow paint for the second batch, but she is using 5 ounces of blue paint this time. To determine how much yellow paint she needs, we can use the same ratio:
2:3 = 5:x
We can cross-multiply to solve for x:
2x = 15
x = 7.5
Therefore, Anita needs to use 7.5 ounces of yellow paint for the second batch. However, the answer choices do not include this exact amount, so we need to look for the closest option. Option C states that she should use 1.5 times the amount of yellow paint used in the first batch, which would be:
1.5 x 3 = 4.5
Therefore, Anita should use 4.5 ounces of yellow paint for the second batch, which is the closest option to the exact amount calculated.
Anita should use 4.5 ounces of yellow paint for the second batch, based on the same ratio of blue to yellow paint used in the first batch. Option C is the correct answer.
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PLS ANSWER THE QUESTION
The maximum value of the data in the box-and-whisker plot is 75.
What is a box-and-whisker plot?A box-and-whisker plot is a standardized representation of statistical data on a plot using a rectangle drawn to represent the distribution of data under five summaries: “minimum”, first quartile [Q1], median, third quartile [Q3], and “maximum.”
The inside vertical line indicates the median value while the lower and upper quartiles are horizontal lines on either side of the rectangle.
Minimum value = 10
Median = 35
Maximum value = 75
Thus, the maximum value, which shows the end of the line, of the data distribution of this box-and-whisker plot is 75.
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A fifteen passenger van is rented for a family vacation. The van rental is $75.00 per day, plus a $160.00 insurance fee. How many days can the van be rented if they want to spend less than $760.00 on the van rental? Write and solve the inequality.
The answer is three
Step-by-step explanation:
75 plus 160 is 235 and 235+235+235= 705
The sum of the bases of a trapezoid is 17 feet. determine the area of the trapezoid, if the perpendicular distance between the bases is 15 feet.
Area of the trapezoid is 127.5 feet².
What is trapezoid?A trapezoid, also called a trapezium, is a four-sided polygon or quadrilateral. There is a set of parallel faces and a set of non-parallel faces. The parallel sides of the trapezoid are called the base and the non-parallel sides are called the legs of the trapezoid.
Given,
Sum of bases of trapezoid
a + b = 17 feet
Height of the trapezoid h = 15 feet
Area of the trapezoid
= h(a + b)/2
= 15 × 17/2
= 255/2
= 127.5 feet²
Hence, 127.5 feet² is the area of the trapezoid.
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Camp cool algebra question number 1.
How many children will be in the camp in 3 years?
Answer:8750
Step-by-step explanation:
I did 5000 times .25(1/4 as a decimal) which equals 1250. Then 1250 times 3(year) equals 3750. 5000 plus 3750 is 8750
find the area of the region bounded by the given curves. y = 6x2 ln(x), y = 24 ln(x)
The area of the region bounded by the given curves. y = 6x2 ln(x), y = 24 ln(x) is 2.85 sq.units.
In this question we need to find the area of the region bounded by the given curves. y = 6x^2 ln(x), y = 24 ln(x)
Equating both the equations of the curve,
6x^2 ln(x) = 24 ln(x)
24 ln(x) - 6x^2 ln(x) = 0
x = 1, 2
This means, the curves intersect at x = 1 and x = 2.
So, the required area would be,
A = ∫[1 to 2] [24 ln(x) - 6x^2 ln(x)] dx
First we find the indefinite integral ∫[24 ln(x) - 6x^2 ln(x)] dx
= -6 ∫[-4 ln(x) + x^2 ln(x)] dx
= -6 ∫ln(x) (x^2 - 4) dx
= -6 ln(x) (1/3 x^3 - 4x) + 2/3 x^3 - 24x
So, ∫[1 to 2] [24 ln(x) - 6x^2 ln(x)] dx
= [-6 ln(x) (1/3 x^3 - 4x) + 2/3 x^3 - 24x] _(x = 1 to x = 2)
= 32 ln(2) - 58/3
= 22.18 - 19.33
= 2.85 sq.units.
Therefore, the area of the region is 2.85 sq.units.
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Solve for P by isolating the variable. 2p + 193.99 = 284.97
Answer:
p=45.49
Step-by-step explanation:
i hope this helps :)
Please help me I need help
If the diameter of a circle is doubled, the circumference of the new circle is..
A. 1/4 of the circumference of the original circle
B. 1/2 of the circumference of the original circle
C. The same as the circumference as the original circle
D. 2 times the circumference of the original circle
E. 4 times the circumference of the original circle
Answer:
D
Step-by-step explanation:
Let's call the original diameter x. Then, the circumference would be xπ. If the diameter is 2x, the circumference is 2xπ. 2xπ / xπ = 2 so the answer is D.
Answer:
D. 2 times the circumference of the original circle
Step-by-step explanation:
The circumference of a circle is represented by the formula C = 2(r)pi (where is r is the radius), which can also be written as C = (d)pi, where d is the diameter, (since 2r is equivalent to d). If the diameter is doubled, the original equation can be rewritten as C = 2(d)pi. Therefore, the circumference of the new circle is double the original circle.
You can plug in a sample number to further prove this point. Pretend r = 3 so d = 6. C = 6pi. Now when the diameter is doubled, d = 12 and C = 12pi which is double 6pi.
So the answer is D. 2 times the circumference of the original circle
was your student's transformation successful, yes or no, or are the data inconclusive? if it was clearly successful or unsuccessful, explain how you know. if the data are inconclusive, explain how the data indicate this. given that your student's data do not match the 'expected' data for a completely successful transformation, provide a possible explanation for what could have happened that led to this result. (2 pts)
The success of a student's transformation can be determined by analyzing their performance data, but there may be external factors that could affect the outcome, and further analysis may be necessary.
If the student's data show a clear improvement in their performance, skills, or knowledge after undergoing a specific transformation, then we can say that the transformation was successful. On the other hand, if there is no discernible improvement or even a decline in the student's performance, we can infer that the transformation was unsuccessful.
However, in some cases, the data might not be entirely conclusive, and there could be other factors affecting the outcome. For example, a student may have made some progress, but not enough to meet the expected outcomes fully. In such cases, we might need to analyze the data more thoroughly to determine the extent of the transformation's success.
There could be several reasons why a student's data might not match the expected outcome of a successful transformation. For instance, the student might not have fully embraced the transformation or might have faced challenges or obstacles that hindered their progress. Additionally, external factors such as socioeconomic background, family support, and access to resources could also impact the results.
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The lower limit of one of the objective function coefficients is 19. If this coefficient is
changed to 18.99 (the coefficient was originally 24)
If the lower limit of one of the objective function coefficients is 19 and it is changed to 18.99 (while the coefficient was originally 24), it means that the coefficient is being decreased.
This change in the coefficient value may affect the optimal solution of the linear programming problem. The new coefficient of 18.99 would make the corresponding variable less valuable or less desirable in the objective function compared to its original value of 24. This can potentially lead to a different optimal solution or a change in the objective function value.
The impact of this change on the overall solution depends on the specific problem and its constraints. It would be necessary to re-evaluate the linear programming problem with the updated coefficient value to determine its effects on the optimal solution and the objective function value.
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Factor the polynomial: x(6x - 1) – 3(6x - 1)
O A. -3x(6x - 1)
O B. 3x(6x - 1)
O C. (6x - 1)(x - 3)
O D. (6x - 1)(x + 3)
Answer:
C.
Step-by-step explanation:
x(6x - 1) – 3(6x - 1) = (6x - 1)(x - 3)
The factor of the polynomial x(6x - 1) – 3(6x - 1) is (6x -1) (x - 3).
The correct option is C.
To factor the polynomial x(6x - 1) - 3(6x - 1), we can observe that both terms have a common factor of (6x - 1). We can factor out this common factor using the distributive property.
The given expression can be rewritten as:
x(6x - 1) - 3(6x - 1)
Now, we can factor out the common factor (6x - 1):
(6x - 1)(x) - (6x - 1)(3)
Notice that we have (6x - 1) as a common factor in both terms. We can combine the two terms using this common factor:
(6x - 1)(x - 3)
Therefore, the factored form of the polynomial x(6x - 1) - 3(6x - 1) is (6x - 1)(x - 3).
Option C: (6x - 1)(x - 3) is the correct answer.
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In the diagram below, DE is parallel to X. What is the value of y?
•
**
122
A. 78
B. 112
C. 58
O D. 122
They start you off with the angle 122 d (degrees) and a straight lime is 180 d so you should do 180 d - 122 d to get 58
find the greatest commom factor gcf for each pair of numbers
9 and 33
Answer:
3
Step-by-step explanation:
Find the prime factorization of 9
9 = 3 × 3
Find the prime factorization of 33
33 = 3 × 11
To find the GCF, multiply all the prime factors common to both numbers:
Therefore, GCF = 3
Jose paid 47.00 for 4 movie tickets. Each ticket costs the same amount.what was the cost of each movie ticket in dollars and cents
Answer:
$11.75
Step-by-step explanation:
In order to solve this problem, you divide $47.00/4. When you do that, you get $11.75
If a study introduces parallel forms of the same measurement instrument to the same person, the researcher is assessing_____
Multiple Choice
O item Interpretability
O item economy
O item equivalence
O item stability
O item convenience
The researcher is assessing item equivalence, If a study is in parallel forms of the measurement instrument to the same person. The correct option is C).
When a study introduces parallel forms, the researcher is assessing item equivalence. Item equivalence refers to the extent to which the different forms of the measurement instrument produce similar results for the same individual.
This assessment is crucial in research because it allows researchers to evaluate the consistency and reliability of the measurement instrument across different versions. By administering parallel forms to the same person, any differences in responses can be attributed to individual factors rather than variations in the instrument.
This helps ensure that the instrument is measuring the intended construct consistently and accurately. The correct option is C).
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7 miles in 10 minutes = 3.5 miles in 5 minutes
True
False
The two values of speed are the same. The statement is correct.
What is speed?The speed is the fraction of the distance traveled and the time taken by the object to cover that distance. The speed is measured in meters per second as a unit.
It is given that one object travels 7 miles distance in a time of 10 minutes. So this is equal to the distance he traveled 3.5 miles in the time of 5 minutes.
The two speeds can be calculated as:-
Speed one = 7 / 10 = 0.7 miles/s
Speed second = 3. 5/ 5 = 0.7 miles/s
Therefore, the two speeds are the same.
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Find FH
A. 13.5
B. 6.0
C. 8.1
D. 6.7
Step-by-step explanation:
the FH seems to be option b.6.0
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