1) IMPORTANT: For this quiz, you will not explicitly specify any database names. All of your table names will start with your eid which is your linux login, so my "students" table would be named "bsay_students"
2) The deliverable for this quiz is a single .sql file which contains all of the proper MySQL Statements to create the requested tables and run the requested queries in the order specified in the quiz.
3) Create a table eid_students
a) Each student has a name, up to 255 characters
b) Each student has an id, an integer
c) Each student has a gpa, which is a double
4) Run a SHOW CREATE TABLE eid_students query.
5) Insert into the students table 26 students
a) The student's id numbers are 800000001 through 800000026
b) The students names are Aaa through Zzz (capitalized triplets of each letter of the alphabet
i) These correspond to the id numbers in the same order
c) Each student's GPA is random number between 2.00 and 4.00 (inclusive, 2 decimal places)
d) Run a SELECT query to show all of the student data, ordered by id
6) Create a table eid_classes
a) Table has these fields:
i) Department Code (i.e. CT, CS, MATH, etc...). Use an appropriate data type
ii) Course Number (i.e. 310, 312, 220, etc...). Use an appropriate data type
iii) Credits (Numeric, 1-4)
b) Insert into this table the courses in CS and CT that you have taken, up to and including this semester.
c) Print a SHOW CREAT TABLE for the table.
d) Run a SELECT query to show all of the table's contents
7) Change the entry for CT310 as follows:
a) The department code is now CS
b) The course numer is now 312
c) Run a SELECT query to show the entire classes table contents
8) Add a table called eid_enrollments
a) It is a linking table to make a many-to-many relationship between students and courses.
b) Use the appropriate columns to link these tables.
c) Create an extra column called semester
i) It is an ENUM (FA17, SP18, SU18, FA18, SP19, SU19, FA19, SP20)
d) Assign classes to students so that each student has exactly 4 different classes.
i) Make sure CS312 has at least 5 students taking it. Have at least 2 classes that nobody is taking.
e) Print out a count of the number of rows in this table
9) Print out a list of students who are taking CS312 using a query.
10) Print out a list of all classes that have at least one student taking them
a) Only print out the Department Code, Course Number and Credits
11) Print a full enrollment list that lists a row for each student
a) This row includes a column that is a comma separated list of course codes (i.e. "CS220, CS312, CS440")
12) Run a query that only prints one row, one column that has the sum of the total number of enrolled credits.
a) That is, for each student, add their enrolled credits (across all terms) and then sum that number for all students to get one numeric answer.
13) 10 points per top level bullet.
14) All queries must be generic, that is they must not know anything about the specific data in the tables and should work even if the data in the tables is changed.

Given parameters are;Axial load = 3 kNShaft speed = 1440 rpm Coefficient of friction = 0.04 Uniform wear constant = 16 kN/mPower absorbed in friction = 400 kW

Let the radii of the bearing be r1 and r2The expression for power absorbed in friction is: Power absorbed in friction = f . vwhere,f is the force of frictionv is the velocity at the mean radius

Assuming uniform pressure over the surface of contact between the bearing and the shaft, then the expression for the force of friction is:f = μ . Wwhere,μ is the coefficient of frictionW is the axial load on the bearingFrom equilibrium of forces in the y-direction, the following relationship can be derived:W = PFrom the diagram, the following relationships can be obtained:r2 - r1 = d (Equation 1)tan 60°

=  (r2 - r1)/d

⇒ r2 - r1

=  √3 d/3 (Equation 2)

From equilibrium of moments about C:W . r2 = F . Rwhere,F is the force acting on the bearingR is the radius of the mean point of contact. Assuming uniform wear, the relationship between F and W is:

F = C/W = C/P (Equation 3)Where C is the uniform wear constantSubstituting for F in Equation (2),

F = C/P⇒ C = F . P The force of friction can be written as:f = μ . WP = 3 kN (given)C = 16 kN/m (given)F = C/P = 16/3 kN (approx)From Equation (4),f = μ . WF = 16/3 kN (approx)μ = 0.04 (given)v = π . d . N/60 = π . d . 1440/60where N is the shaft speedd is the diameter of the mean point of contactSubstituting the expression for v in

Equation (4):Power absorbed in friction = f . v = 0.04 x 16/3 x π x d x 1440/60

= 307.2 x dwhere d is in meters

When using the uniform pressure theory, the expression for the radius of the mean point of contact is:R = (r1r2) / (r1 + r2)Let

R = r

The expression for the force of friction is:F = 2π rL pWhere L p is the length of the contact arc

Substituting for F in Equation (3):P = C/FSubstituting for F:Power absorbed in friction

= f . v

= 2πrL pC/F x πdN/60

= Cπ2dLpN/30rF

= 3 kNC

= 16 kN/mr

= √3d/3

Using Equation (1),r2 - r1 = d/2∴ r1

= r - d/2r2

= r + d/2L p

= πr/3Substituting the values: r = √3d/3L p

= πr/3

= πd/3

From Equation (5):Power absorbed in friction = Cπ2dLpN/30r

= Cπ2d(πd/3)N/30(√3d/3)

= Cπ2N√3/90 d4

Power absorbed in friction

= 16 x π2 x 1440 x √3 / 90 x 4

= 109.83 kW (approx)

Therefore, the radii of the bearing are r1 = 0.18m and r2 = 0.42m.The power absorbed in friction using the uniform pressure theory is 109.83 kW.

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Answer:

Motorcyclist Fatality and Injury Rates per Vehicle Miles Traveled, 1998-2008. 10. 9. Fatalities in School Transportation Related Crashes,. 1998-2008.

Explanation:

The primary goal of political parties in televised presidential debates is to: D. to explain party platforms to voters.

A political party can be defined as an organized group of individuals (people) who presumably share common political ideologies, aims, goals, vision, and strategies on how a country should be governed.

This ultimately implies that, a political party ​is an organization of people that are sharing similar political ideologies and it provides a platform for a chosen candidate to run as its sole representative in an election category.

In this context, the primary goal of political parties in televised presidential debates is to explain party platforms to the electorates or voters.

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It's D I just took the test

Edge 2023 :)

Answer:

they occur at the same time

Explanation:

What this means is that if let's say on a particular cash record we have two transactions on the same date: For example,

Only the two transactions on the 11th are permissible to sum the dollar amounts without conversion.

Answer:

A tax is a monetary payment without the right to individual consideration, which a public law imposes on all taxable persons - including both natural and legal persons - in order to generate income. This means that taxes are public-law levies that everyone must pay to cover general financial needs who meet the criteria of tax liability, whereby the generation of income should at least be an auxiliary purpose. Taxes are usually the main source of income of a modern state. Due to the financial implications for all citizens and the complex tax legislation, taxes and other charges are an ongoing political and social issue.

I dont know I asked this to

Explanation:

ᴄᴏᴍᴘʟᴇᴛᴇɴᴇꜱꜱ ᴍᴇᴀɴꜱ ᴛʜᴇ ꜱᴛᴀᴛᴇ ᴏꜰ ʙᴇɪɴɢ ᴄᴏᴍᴘʟᴇᴛᴇ ᴀɴᴅ ᴇɴᴛɪʀᴇ; ʜᴀᴠɪɴɢ ᴇᴠᴇʀʏᴛʜɪɴɢ ᴛʜᴀᴛ ɪꜱ ɴᴇᴇᴅᴇᴅ.

ʙᴇᴀᴜᴛʏ ᴍᴇᴀɴꜱ combination of qualities, such as shape, colour, or form, that pleases the aesthetic senses, especially the sight.

(a) The probability of drawing a black fuse from the second toolbox is 4/7.

(b) The probability of drawing a white fuse from the second toolbox is 3/7.

(c) The probability that one fuse is white is 27/49.

To calculate the probabilities, we need to consider the number of white and black fuses in each toolbox.

First, let's determine the total number of fuses in each toolbox:

First Toolbox:

Total fuses = 4 white fuses + 3 black fuses = 7 fuses

Second Toolbox:

Total fuses = 3 white fuses + 5 black fuses = 8 fuses

(a) The probability that the fuse drawn from the second toolbox is black:

The probability of drawing a black fuse from the second toolbox depends on the fuse selected from the first toolbox. There are two scenarios to consider:

Scenario 1: The fuse selected from the first toolbox is black.

In this case, the second toolbox will have 3 black fuses remaining out of the total 7 fuses.

Probability = (Number of black fuses in the second toolbox)/(Total number of fuses in the second toolbox)

Probability = 3/7

Scenario 2: The fuse selected from the first toolbox is white.

In this case, the second toolbox will have 5 black fuses out of the total 7 fuses.

Probability = (Number of black fuses in the second toolbox)/(Total number of fuses in the second toolbox)

Probability = 5/7

To calculate the overall probability, we need to consider the probability of each scenario and weigh it by the probability of selecting a fuse of that color from the first toolbox. Since the fuse from the first toolbox has an equal chance of being white or black, we need to take an average of the probabilities in both scenarios.

Probability of drawing a black fuse from the second toolbox = (Probability of scenario 1 + Probability of scenario 2)/2

Probability of drawing a black fuse from the second toolbox = (3/7 + 5/7)/2

Probability of drawing a black fuse from the second toolbox = 8/14

Probability of drawing a black fuse from the second toolbox = 4/7

Therefore, the probability of drawing a black fuse from the second toolbox is 4/7.

(b) The probability that the fuse drawn from the second toolbox is white:

Similarly, we can calculate the probability of drawing a white fuse from the second toolbox. It will be the complement of the probability of drawing a black fuse.

Probability of drawing a white fuse from the second toolbox = 1 - Probability of drawing a black fuse from the second toolbox

Probability of drawing a white fuse from the second toolbox = 1 - 4/7

Probability of drawing a white fuse from the second toolbox = 3/7

Therefore, the probability of drawing a white fuse from the second toolbox is 3/7.

(c) The probability that one is white:

To calculate the probability that one fuse is white, we need to consider both scenarios: either the fuse drawn from the first toolbox is white and the fuse drawn from the second toolbox is black, or the fuse drawn from the first toolbox is black and the fuse drawn from the second toolbox is white.

Scenario 1: Fuse drawn from the first toolbox is white, and the second toolbox has a black fuse:

Probability = (Probability of drawing a white fuse from the first toolbox) * (Probability of drawing a black fuse from the second toolbox)

Probability = (3/7) * (5/7)

Scenario 2: Fuse drawn from the first toolbox is black, and the second toolbox has a white fuse:

Probability = (Probability of drawing a black fuse from the first toolbox) * (Probability of drawing a white fuse from the second toolbox)

Probability = (4/7) * (3/7)

To calculate the overall probability, we need to sum up the probabilities of both scenarios:

Probability that one fuse is white = Probability

of scenario 1 + Probability of scenario 2

Probability that one fuse is white = (3/7) * (5/7) + (4/7) * (3/7)

Probability that one fuse is white = 15/49 + 12/49

Probability that one fuse is white = 27/49

Therefore, the probability that one fuse is white is 27/49.

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Renewable resources are those energy resources which will never end. Germany aims to be completely dependent on renewable energy resources by 2035.

Renewable resources are those energy resources which will never end. A few examples of such energy resources are Solar Energy, Wind Energy, etc.

Germany is a European country, therefore, it is a cold country and is highly dependent on the natural resources of Russia. As the war is going on between Russia and Ukraine, it is hard for countries like Germany to put sanctions on Russia because of its dependency on its resources.

Thus, Germany wants to be a self-dependent country in terms of electricity and wants to completely stop the use of non-renewable resources for the production of electricity.

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At 1.2mpa pressure and 50c

What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).

a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser

T2 = 46.29C - 5
T2 = 41.29C

Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg

(COP)r = 238/53
(Cop) = 4.490

Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.

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Answer:

do the wam wam

Explanation:

The heat flux is =1038kW/m² , the heat lost per hour is =259.5 kW, the heat lost per hour using a sheet of soda- lime glass.

The thickness of steel( t) = 10mm = 10× 10^-³m

The temperature difference on both sides = 300-100

∆T = 200°C

But the formula for heat flux = q = k∆T/t

Where K = thermal conductivity for steel = 51.9W/mK.

Substitute the variables into the formula for heat flux;

q = 51.9 × 200/10 × 10-³

q = 10380 × 10³/10

q = 10380000/10

q = 1038000 W/m² = 1038kW/m²

To calculate the heat lost per hour if the cross sectional area is = 0.25 m2 use the formula q × A

= 1038kW/m² × 0.25 m2

= 259.5 kW.

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Gross errors produce data that differ unreasonably from data from similar samples and apply to the given category. The correct option is B.

Gross errors, often known as "outliers," are errors that are not systematic or random. They are inherently unpredictable and frequently huge.

Gross errors result from experimenter negligence or device malfunction. These “outliers” are typically ignored when analyzing data because they are far above or below the genuine value.

Therefore, the correct option is B: gross errors produce data that differ unreasonably from data from similar samples.

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The level of measurement for the given data is as follows:

(a) Temperature - Quantitative, interval

(b) Allergies - Qualitative, nominal

(c) Weight - Quantitative, ratio

(d) Pain level - Quantitative, ordinal

Temperature is a quantitative variable that can be measured on an interval scale because the differences between temperature values are meaningful (e.g., the difference between 20 and 30 degrees Celsius is the same as the difference between 30 and 40 degrees Celsius).

Allergies, on the other hand, are a qualitative variable that can be categorized into different groups or levels without any inherent numerical value. It is measured on a nominal scale, which means there is no numerical order or ranking associated with the categories.

Weight is a quantitative variable that can be measured on a ratio scale. It has a meaningful zero point (absence of weight) and the ratios between weight values are meaningful (e.g., 100 pounds is twice as heavy as 50 pounds).

Pain level is also a quantitative variable, but it is measured on an ordinal scale. The scale of 0 to 10 represents different levels of pain intensity, but the differences between the numbers may not be equal or meaningful. It only provides a ranking or order of pain levels.

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Therefore, the correct answer is (o) 2200 -Jbisee 0 wy :987 .6 (rounded to the nearest whole number).

To solve this problem, we need to use the formula for power:

Power = force x velocity
First, we need to find the force that the man is exerting. We know that the total weight of the man and his bicycle is 200 lb. On a S percent grade, this weight will be resolved into two components: one parallel to the surface (the force that propels the man forward) and one perpendicular to the surface (the force of gravity). The parallel component is equal to the weight times the sine of the angle of the grade:

Force parallel = 200 lb x sin(S)
Next, we need to find the velocity of the man. We are given that he is riding at a constant speed of 15 mi/hr. To convert this to feet per second, we can use the conversion factor:

15 mi/hr x (1 hr/60 min) x (1 min/60 sec) x (5280 ft/1 mi) = 22 ft/s

Now we can plug in these values to the formula for power:

Power = Force parallel x velocity
Power = (200 lb x sin(S)) x 22 ft/s

We are not given the value of S in the problem, so we cannot calculate the exact value of power. However, we can see that the answer choices are all in different units of power. To convert our answer to the correct unit, we can use the conversion factor:

1 f-lb/sec = 1.356 J/s

So we need to convert our answer from ft-lb/sec to J/s:

Power = (200 lb x sin(S)) x 22 ft/s
Power = 4400 lb-ft/s x (1.356 J/s)/(1 ft-lb/s)
Power = 5960.8 J/s

Rounding this to the nearest whole number, we get:

Power = 5961 J/s

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A limit switch is a device that limits the angle of the boom at its highest position.

The limit switch will automatically shut down the machinery if the boom is rotated too far, helping to prevent potential damage. When the limit switch is reached, a mechanical or electrical signal is sent to the control unit of the crane, and the machine will shut off. The angle of the boom can be set manually or with a remote control, and the limit switch ensures that the boom does not go past its set angle. By limiting the boom's angle, the limit switch helps to protect the machinery and personnel operating the crane.

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The tool that is specifically designed to grab and lift small objects is a 3-prong holder, also known as a tweezer or forceps.

A 3-prong holder is a handheld tool with two opposing arms that can be squeezed together to grip and hold small objects securely. It typically has a narrow and pointed tip that allows for precise handling of delicate or small items. The prongs of the holder are usually made of metal, such as stainless steel, which provides strength and durability.

The design of the 3-prong holder allows for easy manipulation and control when picking up small objects. The user can squeeze the arms of the holder to create a firm grip on the object, and release the grip by gently separating the arms. This tool is commonly used in various fields such as electronics, jewelry making, laboratory work, and medical procedures.

Unlike the other options provided:

- An IC (Integrated Circuit) extractor is a specialized tool used for safely removing IC chips from sockets or circuit boards. It is not intended for grabbing and lifting small objects in general.

- A multi-meter is an electrical testing tool used for measuring voltage, current, and resistance in circuits. It is not designed for grabbing or lifting objects.

- A cable tester is a tool used for checking the integrity and functionality of cables, such as Ethernet or audio cables. It is not suitable for grabbing or lifting small objects.

Thus, the correct option is "c".

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The tool that is specifically designed to grab and lift small objects is a 3-prong holder, also known as a tweezer or forceps.

A 3-prong holder is a handheld tool with two opposing arms that can be squeezed together to grip and hold small objects securely. It typically has a narrow and pointed tip that allows for precise handling of delicate or small items. The prongs of the holder are usually made of metal, such as stainless steel, which provides strength and durability.

The design of the 3-prong holder allows for easy manipulation and control when picking up small objects. The user can squeeze the arms of the holder to create a firm grip on the object, and release the grip by gently separating the arms. This tool is commonly used in various fields such as electronics, jewelry making, laboratory work, and medical procedures.

Unlike the other options provided:

- An IC (Integrated Circuit) extractor is a specialized tool used for safely removing IC chips from sockets or circuit boards. It is not intended for grabbing and lifting small objects in general.

- A multi-meter is an electrical testing tool used for measuring voltage, current, and resistance in circuits. It is not designed for grabbing or lifting objects.

- A cable tester is a tool used for checking the integrity and functionality of cables, such as Ethernet or audio cables. It is not suitable for grabbing or lifting small objects.

Thus, the correct option is "c".

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When it comes to combining multiple documents, an important word processing skill to know that ensures the final result is organized and easy to use is pagination.

Pagination is a page numbering technique that is done sequentially. These page numbers are usually located at the top or bottom of the web page. In most cases, it is used for main pages and partitions in corporate websites. This kind of design can generally make the user experience simpler on the site. They can also feel more comfortable when it comes to distributing and navigating products within the website.

For example, like this, imagine an e-commerce site that consists of hundreds of product catalogs from various categories. Of course, these products will not be found easily if only placed on one page. As a solution, UI developers and designers can take advantage of pagination to make product placement more structured.

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Answer: outrigger ??

Explanation:

Cranes and derricks installed on floating surfaces must have a stability test.

Stability testing is a method of determining the quality and behavior of a system or software in various environmental parameters such as temperature, voltage, and so on.

Cranes and derricks installed on floating surfaces such as barges or ships must be stable.

This is because the weight and position of the crane or derrick, as well as the load being lifted, can affect the stability of a floating surface.

Without proper stability calculations, the crane or derrick could capsize or become unstable, resulting in accidents or injuries. Understanding and managing your barge's stability is critical to its safety.

Thus, it should have a stability test to installed an floating surfaces.

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The Hypergeometric Distribution gives the probability that exactly k out of the n items tested are substandard. The expression for the Hypergeometric Distribution is:

P(X = k) = (K choose k) * ((N - K) choose (n - k)) / (N choose n)

Where:

P(X = k) is the probability that exactly k out of the n items tested are substandard.

(K choose k) represents the binomial coefficient, which calculates the number of ways to choose k substandard items out of K.

((N - K) choose (n - k)) calculates the number of ways to choose (n - k) non-substandard items out of (N - K).

(N choose n) calculates the total number of ways to choose n items out of N.

This formula takes into account the specific scenario where the items are drawn without replacement from a population of N identical components, with K being the number of substandard components in the population. It allows us to calculate the probability of observing a specific number of substandard items among the n items tested.

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The statement that best describes the first priority of public works during the initial response is: B. Provide an initial assessment of the damages to all community services

Public works are defined as a broad category of infrastructure projects, that are financed and constructed by the government, for recreational, employment, and health and safety uses in the greater community.

They include works (such as schools, highways, docks) constructed for public use or enjoyment especially when financed and owned by the government.

Looking at the given options, the one that best describes the first priority of public works is Option B

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The missing options are:

A. Review reports and other data to provide a preliminary damage assessment

B. Provide an initial assessment of the damages to all community services

C. Restore solid waste management services, repair facilities, and clear streets

D. Assist with life safety activity by providing equipment and technical expertise

Answer:

4. Compromise

Explanation:

A compromise is when the two disagreeing parties give up something to make a conclusion that both are satisfied with. In this case, Anthony wants Angel to have a good time, so he gives up his bowling.

The magnitude of force at pin A is 410 lbs and the force in cable BC is 0 lbs.

To determine the magnitude of force at pin A and in cable BC, we need to use the principle of equilibrium. Since the system is in equilibrium, the sum of all forces acting on it must be zero.

First, let's find the force at pin A. Since there are only two forces acting on point A, the force in the cable AB and the force in the cable AC must be equal and opposite to the force of the load. Thus, the force at pin A is 410 lbs.

Now, to find the force in cable BC, we need to consider the forces acting on point B. There are three forces acting on point B, the force in the cable AB, the force in the cable BC, and the force of tension in the cable CD. Since the system is in equilibrium, the sum of all forces acting on point B must be zero. Thus,

force in AB - force in BC - force of tension in CD = 0

We know that the force in AB is 410 lbs, and the force at pin A is also 410 lbs. Therefore, the force of tension in CD must also be 410 lbs. Thus,

410 lbs - force in BC - 410 lbs = 0

Solving for the force in BC, we get:

force in BC = 410 lbs - 410 lbs = 0 lbs

Therefore, the force in cable BC is zero. This makes sense because cable BC is slack and not under tension.

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The magnitude of force at pin A is 410 lbs and the force in cable BC is 0 lbs.

To determine the magnitude of force at pin A and in cable BC, we need to use the principle of equilibrium. Since the system is in equilibrium, the sum of all forces acting on it must be zero.

First, let's find the force at pin A. Since there are only two forces acting on point A, the force in the cable AB and the force in the cable AC must be equal and opposite to the force of the load. Thus, the force at pin A is 410 lbs.

Now, to find the force in cable BC, we need to consider the forces acting on point B. There are three forces acting on point B, the force in the cable AB, the force in the cable BC, and the force of tension in the cable CD. Since the system is in equilibrium, the sum of all forces acting on point B must be zero. Thus,

force in AB - force in BC - force of tension in CD = 0

We know that the force in AB is 410 lbs, and the force at pin A is also 410 lbs. Therefore, the force of tension in CD must also be 410 lbs. Thus,

410 lbs - force in BC - 410 lbs = 0

Solving for the force in BC, we get:

force in BC = 410 lbs - 410 lbs = 0 lbs

Therefore, the force in cable BC is zero. This makes sense because cable BC is slack and not under tension.

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A Waterways Conservation Officer is responsible for preserving and protecting aquatic life and the environment. They make sure that vessels and operators comply with laws, regulations, and policies related to waterways conservation and management.

In some cases, they may instruct vessel operators to return to the nearest mooring. Some conditions that may lead to such instruction include:1. Inclement Weather:In bad weather conditions, such as heavy storms, winds, or thunderstorms, a Waterways Conservation Officer may instruct a vessel operator to return to the nearest mooring. This is because operating a vessel in such conditions can be risky, dangerous, and potentially life-threatening.

2. Safety Concerns:If a vessel operator is not following the safety rules and regulations, a Waterways Conservation Officer may instruct them to return to the nearest mooring. This may include cases where the vessel is overloaded, not carrying enough life jackets, or the operator is not wearing a personal flotation device.3. Breaking Laws:If the vessel operator is breaking any waterways laws or regulations, the Waterways Conservation Officer may instruct them to return to the nearest mooring.

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Answer:

The equilibrium mole fraction of CO is 0.0515

Explanation:

Solution

Given that:

Temperature T = 2400 K

Pressure P = 100 kPa

The reaction C₅H₁₂ + 8 O₂ →5CO₂ + 6 H₂ O

Now,

We take in K value from logarithm to the base e of the equilibrium constant K at 2400 K

From reaction 2CO₂⇔ 2 CO + O₂

In K = -7.715

P° =0.1 MPa

K = e^⁻7.715

=4.461 * 10^⁻4

Thus,

2CO₂⇔ 2 CO + IO₂

The initial mole CO₂ and shift reaction with 'x'

The  atom balance from the above reaction is given below:

Species: CO₂ CO O₂ H₂O

Initial:  5006

Changes: - 2x 2xx0

Total:5 - 2x 2xx6

The total number of moles n tot = 5-2x+2x+x+6

= 5+x+6

=11+x

Now,

from the equation of the equilibrium constant K

K =Y²co₂Yo₂/Y²co₂ (P/P₀)

Yc₀ =nc₀/n tot

= 2x/11+x

Yco₂ = nc₀/n tot

= 5-2x/11 +x

So,

K =(2x/1+x)² *x/1+x/(5-2x/11 +x)² * (100/100)

4.461 * 10^⁻4 = (2x)²/(11 +x)² x/(11+x) (11+x)/(5-2x) *1

4.461 * 10^⁻4= (2x/5-2x)² x/11+x

Now by trial and error method by keeping  x =0.291 the value satisfies the equation

4.461 * 10^⁻4 =(2 *0.291/5-(2* 0.291))² *(0.291/11 + 0.291)

4.461 * 10^⁻4 =4.47 *10^⁻4

Hence

x =0.291

Thus,

The mole fraction of CO₂ =nco₂/ntot

Yco₂ = 5-2x-/11 +x

Yco₂ = 5-(2 * 0.291)/11+0.291

Yco₂ = 0.39128

So,

Mole fraction of CO =nco/ntot

Yco = 2x/11+x

=2 * 0.291/11+0.291

Yco =0.0515

Then,

Mole fraction of O₂ =no₂/ntot

Yo₂ = x/11 +x

= 0.291/11+0.291

=0.02577

102 sheets of 4' x eight' pieces of plywood will it take to cover a 24' wall.


locating the quantity of sheets of plywood wanted for a ground, wall, ceiling, or cabinet starts with locating the vicinity that wishes to be covered. vicinity may be located with the aid of multiplying the period and width of the gap in toes. find the rectangular pictures of each space and upload together to locate the whole square photos wanted. Divide by way of the entire square footage by the square footage of a sheet of  to discover the range of sheets required to cover the gap. A 4×eight sheet of plywood is 32 ft².
for example, if the place to be blanketed in plywood is 800 ft² then 25 sheets of plywood can be had to cowl it.
800 ÷ 32 = 25 sheets

To know more about plywood click right here
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Answer: A, B, C or D

Explanation: its either those

Answer:

a) x = 5.7791 m ( this a turbulent flow )

b) x = 0.04 m ( this is a Laminar flow )

Explanation:

For Air, take

p = 1.2 kg/m³ and u = 1.8×10⁻⁵ kg/m³

So for A , x = 10 cm

Guess turbulent flow;

(Sturb / x) = (0.16 / (p∪x / u)^1/7)

we substitute

(0.1/x = 0.16) / ( 1.2 × 15 × x / 1.8×10⁻⁵)^1/7

x = 5.7791 m

CHECK

Re = (1.2 × 15 × 5.7791) / 1.8×10⁻⁵ = 5.779×10⁶

Therefore this a turbulent flow

for B, x = 1mm

Guess Laminar flow

(S-laminar / x) = ( 5 / (Reₓ)^1/2)

x = (Stutb)²p∪ / 23u

x = ((0.001)² × 1.2 × 15) / (25 × 1.8×10⁻⁵)

x = 0.04 m

CHECK

Re = (1.2 × 15 × 0.04) / (1.8×10⁻⁵)

= 40000

Therefore  this is a Laminar flow

Answer: B. number = random.randit (1, 50)