(1- j9)x + (2 + j10)y = 4 + j3 (2 - j2)x + (7 - j6)y = -5 + j17 what is the magnitude of x?

Answer: Is made up of protons, neutrons and electrons

Make up the matter in the universe

Smallest unit of matter that keep its chemical properties

Answer:

Both balls will reach the ground at the same time

Explanation:

That is because the acceleration due to gravity of both balls are same.

Answer:

B. 15 m/s

Explanation:

p = m × v

480 = 32 × v

32v = 480

v = 480/32

v = 15 m/s

Answer:

B. 15 m/s

Explanation:

P=MV

480=32×v

v=15m/s

David's investment strategy should reflect his financial goals, time horizon, and risk tolerance.

David is a 60-year-old individual with moderate financial health, meaning he has a stable financial situation but may have some debt or other financial obligations. He has a short time horizon, which suggests he may need his funds in the near future for retirement or other expenses.

He has a low risk tolerance, indicating that he is unwilling to take significant risks with his investments and may prefer safer, more conservative options. Based on these factors, David may want to consider investments that prioritize capital preservation, such as bonds or fixed-income securities. He may also want to work with a financial advisor to create a diversified portfolio that balances his need for stability with potential returns.

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Answer:

The automobile tire rotates 91 revolutions

Explanation:

Given;

angular acceleration of the automobile, α = 2.13 rad/s²

time interval, t = 23.2-s

To calculate the number of revolutions, we apply the first kinematic equation;

\(\theta = \omega_i \ + \frac{1}{2} \alpha t^2\)

the initial angular velocity is zero,

\(\theta =0\ + \frac{1}{2} (2.13) (23.2)^2\\\\\theta = 573.2256 \ Rad\)

Find how many revolutions that are in 573.2256 Rad

\(N = \frac{\theta}{2 \pi} = \frac{573.2256}{2\pi} \\\\N = 91 \ revolutions\)

Therefore, the automobile tire rotates 91 revolutions

The formula we use here is v=u+at, with the given data the answer is 5m/s², for the second part f=ma, 5000N is the answer.

Whenever an unbalanced force acts on an object acceleration occurs. The greater the net force acting on an object, the greater its acceleration, but the object's mass also affects acceleration. The smaller the mass, the greater the acceleration for a given force. Newton's second law of motion summarizes these relationships. According to this law, the acceleration of an object is equal to the net force acting on the object divided by its mass.

In first part V=U+AT, final velocity is equal to initial velocity plus acceleration multiplied time

A=(V-U)÷T

=(25-0)/5

=5m/s²

for the second part

Force is mass multiplied with acceleration

F=MxA

=1000x5

=5000N

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The solutions are i) The speed of the boy is 2 m/s. ii) The velocity of the boy is 0 m/s. iii) The velocity is zero and the speed of the boy is 10 m/s. iv) In the case of rectilinear motion the distance and displacements are equal.

i) To find the speed of the boy we can directly use the speed, distance, and time formula that is:

Speed= distance/time

Here we can see that the boy covers a distance of 100 m back and forth so the total distance he covered is 100 m + 100 m = 200 m.

The time he took for the journey is 50 s each side so the total distance is 50 s + 50 s = 100s

Now substituting the values in the formula, we get:

Speed = 200 m / 100 s

Speed = 2 m/s

Therefore the speed of the boy is 2 m/s.

ii)  The velocity is the vector quantity which means it indicates the speed of the boy in a particular direction. The velocity can be found by the formula:

Velocity = Displacement/Time

Now we can see that the initial and the final position of the boy are the same so there is no displacement, so displacement is 0.

Substituting the values into the formula we get

Velocity = 0 m/100 s

Velocity = 0m/s

Therefore the velocity of the boy is zero.

iii) According to the question the boy is just sitting on the merry-go-round and not changing his position with respect to the merry-go-round, his velocity is zero as there is no displacement. However, the merry-go-round is moving at a constant speed of 10 m/s, so the boy has a speed of  10 m/s with respect to the ground.

iv) When an object moves in a straight line. the distance moved and the magnitude of displacement are equal. So, in the case of rectilinear motion, the distance covered and the magnitude of the displacement are equal.

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Answer:

like 23 or something

Explanation:

Given that a horizontal force of at least 200 N is required to start moving an 800 N crate initially at rest on a horizontal floor. We are to find the coefficient of a static friction.To find the coefficient of static friction, we need to make use of the following formula.

When the crate is at rest, the force of static friction acting on the crate is maximum and is given by: f_s = μ_s × NwhereN is the normal force and is equal in magnitude to the weight of the crate.N = mgwhere m is the mass of the crate and g is the acceleration due to gravity.Substituting the value of N in the equation for the force of static friction, we get:f_s = μ_s × mg.

Given that a horizontal force of at least 200 N is required to start moving the crate, the force of static friction acting on the crate is equal to 200 N. Thus, we have:f_s = 200 N = μ_s × mgSubstituting the values of f_s, m, and g, we get:200 N = μ_s × 800 N × 9.81 m/s² Simplifying.

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Answer:

3 meters

Explanation:

add up dum boi

An appropriate value for the resistance in parallel with the smoothing capacitor would be 1.59 kΩ.

To ensure good tracking of the AM envelope, the resistance in parallel with the smoothing capacitor should be low enough to discharge the capacitor quickly during the troughs of the modulated signal, but high enough to avoid discharging it too quickly during the peaks of the signal.

The time constant (τ) of the RC circuit formed by the smoothing capacitor and the parallel resistance is given by the formula:

τ = RC

where R is the resistance and C is the capacitance.

To determine an appropriate value for the resistance, we need to calculate the time constant and compare it to the period of the modulated signal.

The period of a 500 kHz signal is T = 1/f = 2 μs. The modulating signal has a bandwidth of 5 kHz, which means its period is 200 μs.

Assuming a small signal approximation, we can use the formula for the time constant to calculate an appropriate value for the resistance:

τ = 20 nF × R = T/2π = 31.8 ns

Solving for R, we get:

R = τ/C = 31.8 ns / 20 nF = 1.59 kΩ

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Complete question is:

The input signal into an envelope detector is an am signal of carrier frequency 500 khz. the envelope detector employs a smoothing capacitor of 20 nf. the modulating signal has a bandwidth of 5 khz. specify an appropriate value for the resistance in parallel with the smoothing capacitor for a good tracking of the am envelope.

To find the refractive index of medium 'Z' with respect to medium 'X' (n(Z/X)), we can use the formula:

n(Z/X) = n(Z/Y) * n(Y/X)

Given:

n(X/Y) = 2/3

n(Y/Z) = 4/3

Plugging these values into the formula, we get:

n(Z/X) = (4/3) * (2/3)

To simplify the expression, we multiply the numerators and denominators:

n(Z/X) = (4 * 2) / (3 * 3)

= 8 / 9

Therefore, the refractive index of medium 'Z' with respect to medium 'X' is 8/9.

According to Boyle's law, which states that the pressure of a gas is inversely proportional to its volume at a constant temperature, if the volume of a fixed amount of gas is doubled, the pressure exerted by the gas will halve. option(1)

This means that the gas molecules will have more space to move around and will collide less frequently with the walls of the container, resulting in a decrease in pressure.

This relationship between pressure and volume is important in understanding the behavior of gases and is used in many applications, including the compression and expansion of gases in engines and refrigeration systems.

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Full Question : For a fixed amount of gas at a fixed temperature, what will happen if the volume is doubled?

30 kg of mass are raised 2.4 meters above the ground by a motor using 1300 J of energy. 1.841154 is the height.

Utilizing the formula Output Input, efficiency can be represented as a ratio. The total amount of productive work finished, excluding any waste and spoilage, is referred to as output or work output. By multiplying the ratio by 100, efficiency can also be expressed as a percentage.By dividing the energy obtained (useful energy or energy output) by the initial energy, energy efficiency is calculated (energy input).

Potential energy is a form of energy that is stored but is dependent on the relative positions of different system components. Stretching or compressing a spring increases its potential energy. Potential energy is stored energy. A stretched spring, a battery, and raising an object are a few examples. There are two main categories of energy: potential and kinetic.

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30 kg of mass are raised 2.4 meters above the ground by a motor using 1300 J of energy. 1.841154 is the height.

Utilizing the formula Output Input, efficiency can be represented as a ratio. The total amount of productive work finished, excluding any waste and spoilage, is referred to as output or work output. By multiplying the ratio by 100, efficiency can also be expressed as a percentage.By dividing the energy obtained (useful energy or energy output) by the initial energy, energy efficiency is calculated (energy input).

Potential energy is a form of energy that is stored but is dependent on the relative positions of different system components. Stretching or compressing a spring increases its potential energy. Potential energy is stored energy. A stretched spring, a battery, and raising an object are a few examples. There are two main categories of energy: potential and kinetic.

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Answer:

To calculate the force (in N) a piano tuner applies to stretch a steel piano wire 8.00 mm, if the wire is originally 0.850 mm in diameter and 1.35 m long, and the Young's modulus for steel is 210 × 109 N/m2, the answer is;2.015 N.

Explanation:

The cross-sectional area of the piano wire can be calculated as;

A=πr² where r is the radius of the wire.

From the diameter of the wire, we can calculate the radius as;r = 0.850 mm / 2 = 0.425 mm

A = π(0.425 × 10-3 m)²= 1.13 × 10-7 m²

The stress σ applied to the wire is given by the following equation;

σ = F / A where F is the force applied.

The Young's modulus E is the slope of the stress-strain curve, so we can calculate the strain from the change in length ΔL and the original length L as;

strain ε = ΔL / L = 8.00 mm / 1.35 m = 0.00593

σ = E ε = (210 × 109 N/m²) × (0.00593)= 1.25 × 106 N/m²

The force F required to produce this stress can be calculated from the equation above;

F = σA = (1.25 × 106 N/m²) × 1.13 × 10-7 m²= 2.015 N (2.02 N to two significant figures)

Hence, the force (in N) a piano tuner applies to stretch a steel piano wire 8.00 mm, if the wire is originally 0.850 mm in diameter and 1.35 m long, and the Young's modulus for steel is 210 × 109 N/m² is 2.015 N.

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The air speed of the helicopter has the ground speed of 250 km/h is 233 km/h  

The ground speed of the helicopter = 250 km/h

The wind speed of the helicopter = 17 km/h

The air speed of the helicopter can be found using the formula,

            G = W + A
where G is the ground speed of the helicopter

           W is the wind speed of the helicopter

           A is the air speed of the helicopter

Let us rearrange the equation in order to get the airspeed,

          A = G - W

Let us substitute the known values in the above equation, we get

          A = 250 - 17

              = 233 km/h  

Therefore, the air speed of the air speed is 233 km/h

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Answer:

3149.181 N

Explanation:

the force exerted by the atmosphere can be calculated as

F = PA

Where P is the atmospheric pressure and A is the area of the sheet of paper.

The atmospheric pressure is P = 101325 Pa

And the area is equal to

A = Length x Width

A = 0.148 m x 0.210 m

A = 0.03108 m²

Because 14.8 cm = 0.148 m and 21.0 cm = 0.210 m

Now, we can calculate the force as

F = (101325 Pa)(0.03108 m²)

F = 3149.181 N

So, the force exerted is 3149.181 N

In the thermal equilibrium, the change in temperature is said to be zero in between the bodies. Thermal equilibrium is reached when both objects have the same temperature.

Thermal equilibrium is easily explained by the zeroth law of thermodynamics. If any two-body is at thermal equilibrium there is no change in the temperature of the body.

According to zeroth law if body A is in thermal equilibrium with body B and body B is in thermal equilibrium with C . So body A and C are also in thermal equilibrium.

In the thermal equilibrium, the net heat transfer is said to be zero in between the bodies.

Hence option A IS RIGHT. Thermal equilibrium is reached when both objects have the same temperature

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Distance can be defined as the amount of ground covered (traveled) by a physical object over a specific period of time and speed, regardless of its direction, starting point or ending point.

Mathematically, the distance traveled by a physical object can be calculated by using this formula:

Distance = speed × time

Dimitri's total distance is the sum of the distance he covered by moving from point A to B and then from B to C. Thus, his total distance is given by:

Total distance = AB + BC

Total distance = 18.1 + 13.3

Total distance = 31.4 feet.

The magnitude of Dimitri's displacement would be calculated by finding the difference in the position of the two point-to-point distances as follows:

Displacement = AB - BC

Displacement = 18.1 - 13.3

Displacement = 4.8 feet.

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The total heat loss under the given condition is 599.21 W. The heat loss is higher under free convection surrounding conditions as compared to forced convection surrounding conditions. Forced convection should be preferred for this problem as it helps to minimize heat loss.

Given: Length of the pipe, L = 3 m

Thermal conductivity, k = 43 W/m°C

Convective coefficient, h1 = 4000 W/m²°C

Convective coefficient of free convection, h2 = 6.5 W/m²°C

Convective coefficient of forced convection, h3 = 30 W/m²°C

The outlet temperature of a chemical product, T1 = 120°C

External temperature, T2 = 30°C

Under steady-state conditions, the rate of heat loss through the insulated pipe under free convection can be expressed as:

Q = (T1 - T2)/{[1/(h1 . D)] + [(ln(ro/ri))/(2π k L)] + [1/(h2 . D)]}

Here, D is the diameter of the pipe, ro, and ri are the outer and inner radius of the pipe, respectively.

The outer radius of the insulated pipe is given as:

ro = ri + 2 × insulation thickness

= 1.25 + 2 × 0.05= 1.35 mri

= 1.25 m

D = 2.5/1000 = 0.0025 m

Substitute the given values to find the heat loss:

Q1 = (120 - 30)/{[1/(4000 × 0.0025)] + [(ln(1.35/1.25))/(2π × 43 × 3)] + [1/(6.5 × 0.0025)]}

= 1.1204 WK

Under forced convection, the rate of heat loss through the insulated pipe can be expressed as:

Q = (T1 - T2)/{[1/(h1 . D)] + [(ln(ro/ri))/(2π k L)] + [1/(h3 . D)]}

Substitute the given values to find the heat loss:

Q2 = (120 - 30)/{[1/(4000 × 0.0025)] + [(ln(1.35/1.25))/(2π × 43 × 3)] + [1/(30 × 0.0025)]}= 0.5212 WK

So, the total heat loss under forced convection is lower than the free convection, and hence, it should be preferred.

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Answer:

If you change the number of neutrons in an atom, you get an isotope of the same element. The addition of a neutron can make an atom radioactive. When you change the number of protons in an atom, you will change the atom from one element to a different element.

Explanation:

The characteristics of the atomic nucleus allow to find the answer for the effect of the change of neutrons in an atoms is

A chemical element is made up of protons, neutrons and electrons; the first two are in the atomic nucleus and the electrons are in orbits around them.

The number of protons corresponds to the atomic number and its change changes the type of element.

The neutrons that are neutral charge together with protons form the mass of the atom, as neutrons are neutral if the number does not affect the type of atom, but if its atomic mass changes.

Elements with the same atomic number, but different atomic mass, different number of neutrons are called isotopes; in general all elements have isotopes, for example hydrogen has an isotope called deuterium that has a neutral and another radioactive isotope called tritium that has two neutrons.

In conclusion using the characteristics of the atomic nucleus we find the answer for the effect of the change of neutrons in an atoms is

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Pregunta completa :

Un zapato de golf tiene 10 tacos cada uno con un área de 0.01 pulgadas en contacto con el piso suponga que al caminar hay un instante en que los tacos soportan el peso completo de una persona de 180 libras ¿cuál es la presión ejercida por los tacos sobre el suelo?

Responder:

12230825.435 pascal

Explicación:

Dado que:

Peso (W) = 180 libras

Número de tacos = 10

Área por montante = 0.01 in²

Área total (10 * 0.01) = 0.1 pulg²

Usando la calculadora de conversión:

180 libras = 81.647 kg

0.1 pulg² = 6.452 × 10 ^ -5 m²

Recordar :

Presión = Fuerza (Newton) / Área (m²)

Fuerza = masa * aceleración debida a la gravedad

Aceleración por gravedad = 9,8 m / s²

Presión = (81.647 * 9.8) / (6.452 * 10 ^ -5)

Presión = 800.1406 / 6.452 * 10 ^ -5

Presión = 12230825.435 pascal

The velocity of the boat when it reaches distance d is mv₀²/(m + 2kd)

Drag force of water is a resistive force that act opposite to the flow off water.

Here,

The initial velocity of the boat having mass m is v₀.

The force exerted by the water on the boat is proportional to square of its velocity.

   F ∝ v²

   F = -kv²   where k is the proportionality constant and the - sign        indicates the force is opposing the flow.    

ma = -kv²

therefore, a = -kv²/m

where v is the velocity of the boat and a is the acceleration.

Considering the equation of motion,

v² = u² + 2as

Applying the values of u, a and s

v² = v₀² - 2 (kv²/m)d

v² + 2(kv²/m)d = v₀²

v² (1 + 2kd/m) = v₀²

v² (m + 2kd)/m = v₀²

Therefore, v² = mv₀²/(m + 2kd)

                  v = √mv₀²/(m + 2kd)

Hence, the velocity of the boat at distance d, v = √mv₀²/(m-2kd).

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The amount of work exerted during the lifting process is approximately 8,344.51 Joules, representing the gravitational potential energy gained as the bucket and water system is raised from the 29.3 m deep well.

To determine the amount of work performed during the lifting process, we need to calculate the gravitational potential energy gained by the bucket and water system as it is raised from the well.

The work done is equal to the change in gravitational potential energy, which can be calculated using the formula:

Work = mgh

where:

m = mass (combined mass of the water and bucket)

g = acceleration due to gravity (approximately 9.8 m/s²)

h = height (depth of the well)

Given information:

Mass of water and bucket (m) = 12.1 kg

Height of the well (h) = 29.3 m

First, let's calculate the gravitational potential energy gained by the water and bucket system:

Potential energy = mgh

Potential energy = (12.1 kg + 18.9 kg) × 9.8 m/s² × 29.3 m

Potential energy = 31 kg × 9.8 m/s² × 29.3 m

Potential energy ≈ 8,344.51 Joules

Therefore, the work performed during the lifting process is approximately 8,344.51 Joules.

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The corresponding distance traveled by the orbiter is 1,728.05 feet. Given that the deceleration in feet per second squared during the time that the chute is deployed is −0.0003v2 (speed v in feet per second), the corresponding distance traveled by the orbiter can be found using the equation below;

The equation is:ds=∫v₁ᵛ₂dt Let's put in the values we have;v₁ = 200 mi/hr = 200 * 1.467 = 293.4 ft/s, v₂ = 35 mi/hr = 35 * 1.467 = 51.345 ft/s

∫ds= ∫v₁ᵛ₂ dt = ∫v₁ᵛ₂ (-dv/0.0003v²) = [-1/0.0003 ∫(1/v²)dv] from v₁ to v₂= [-1/0.0003 (-1/v)] from v₁ to v₂ = [1/0.0003 (1/v₁ - 1/v₂)]

The distance covered by the shuttle during the time that the chute is deployed is given by 1/0.0003 (1/v₁ - 1/v₂).∴ d = 1/0.0003 (1/293.4 - 1/51.345) = 1,728.05 feet. Therefore, the corresponding distance traveled by the orbiter is 1,728.05 feet.

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In 1912 Wertheimer discovered the phi phenomenon, an optical illusion in which stationary objects shown in rapid succession, transcending the threshold at which they can be perceived separately, appear to move.

When two neighbouring optical stimuli are presented in alternation with a relatively high frequency, an apparent motion is seen that is known as the phi phenomenon. At higher frequencies, beta movement is visible, but the stimuli themselves don't seem to move.

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The average emf induced in the coil is 0. 533 V. The average emf induced in the coil can be calculated using Faraday's law of electromagnetic induction. The formula for the average emf induced in a coil is given by:

E = N * (ΔΦ / Δt)

where E is the average emf, N is the number of turns in the coil, ΔΦ is the change in magnetic flux, and Δt is the time interval.

In this case, the number of turns is 80, and the time interval is 0.0600 s. The change in magnetic flux can be calculated by finding the initial and final flux values.

The initial flux is given by Φ1 = B * A * cos(θ1), where B is the magnetic field, A is the area of the coil, and θ1 is the angle between the coil and the magnetic field.

The final flux is given by Φ2 = B * A * cos(θ2), where θ2 is 90 degrees since the coil is perpendicular to the field.

Substituting the values into the formula, we have:

\(E = 80 * (Φ2 - Φ1) / Δt\)

Calculating the values, we find:

\(Φ1 = (1.10 T) * (0.25 m) * (0.40 m) * cos(37.0°) = 0.536 WbΦ2 = (1.10 T) * (0.25 m) * (0.40 m) * cos(90°) = 0.110 WbΔΦ = Φ2 - Φ1 = 0.110 Wb - 0.536 Wb = -0.426 Wb\)

Substituting the values into the formula, we get:

E = 80 * (-0.426 Wb) / 0.0600 s = -0.568 V

Taking the absolute value, the average emf induced in the coil is 0.568 V or approximately 0.533 V.

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In order for the International Space Station (ISS) to regain the orbit it had exactly one year earlier, it fires rockets that thrust parallel to its current velocity. The station's gravitational potential energy is not affected by the rocket's thrust.

The station's kinetic energy is, however, influenced by the rocket's thrust. The rocket's thrust is proportional to the mass of the propellant and the velocity of the exhaust gases in the opposite direction. Thrust is also influenced by the rate of propellant consumption. Since the station is already in a state of motion, the rocket's thrust serves to change the magnitude of the station's velocity, which affects its kinetic energy. When the station is in orbit, its kinetic energy is balanced by the gravitational potential energy of the earth. The ISS has a higher gravitational potential energy when it is in a higher orbit. When the station's velocity increases as a result of the rocket's thrust, its kinetic energy rises, and the station's potential energy is converted to kinetic energy. The higher kinetic energy causes the ISS to ascend to a higher orbit. When the velocity decreases, the station's kinetic energy decreases, and its potential energy increases. The station descends to a lower orbit as a result of this.

As a result, when the ISS is moving faster, its gravitational potential energy decreases, and when it is moving slower, its potential energy increases.

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The de Broglie wavelength of a proton moving with a speed of 1.3 x 10^6 m/s is roughly 3.046 x 10^-13 metres.

The equation for a particle's de Broglie wavelength is:

λ = h / p

where λ  is the wavelength, h is Planck's constant, and p is the particle's momentum.

We may use the following equation to calculate the proton's momentum:

p = mv

where m denotes the proton's mass and v its velocity.

We may calculate the mass of a proton to be around 1.67 x 10^-27 kg.

We may compute the momentum with the provided velocity of 1.3 x 10^6 m/s :

p = (1.67 x 10^-27 kg) x (1.3 x 10^6 m/s) = 2.171 x 10^-21 kg m/s

We can now use this momentum to get the de Broglie wavelength:

λ = h / p

where h denotes Planck's constant, which has an estimated value of 6.626 x 10^-34 J s.

λ = (6.626 x 10^-34 J s) / (2.171 x 10^-21 kg m/s)

λ = 3.046 x 10^-13 m

As a result, the de Broglie wavelength of a proton travelling at 1.3 × 10^-6 m/s is roughly 3.046 x 10^-13 metres.

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