1. Take the speed at which the body moves as 10 m/s 2. Calculate the distance travelled by the body every second 3. Take the time on the x-axis and distance travelled on the y-axis 4. Plot the distance vs time graph on a centimeter graph sheet taking 1cm= 1 s 5. Repeat the steps 2-4 for a speed of 50 m/s on the same graph sheet 6. Observe the graphs obtained for different speeds a) Find the nature of the graph obtained b) What kind of motion is obtained- uniform/non-uniform?

Answers

Answer 1

Answer:

a)this graph is also a line     b) in both cases we have a uniform movement

Explanation:

In this exercise we have a uniform movement

     v = d / t

     d = v t

in the table we give some values ​​to make the graph

       t (s)    d (m)

        1         10

        2        20

        3         30

In the attached we can see the graph that is a straight line

we have another vehicle at v = 50 me / S

t (s)     d (m)

1         50

2        100

3         150

this graph is also a line

b) in both cases we have a uniform movement

1. Take The Speed At Which The Body Moves As 10 M/s 2. Calculate The Distance Travelled By The Body Every

Related Questions

What is the net force required to give an automobile with a mass of 2,100 kg an acceleration of 5.4 m/s^2?

Answers

Answer:

Net force = 11340 N

Explanation:

Given that,

Mass of an automobile, m = 2100 kg

Acceleration of the automobile, a = 5.4 m/s²

We need to find the net force required for the automobile. The net force is the product of mass and acceleration. It can be given by the formula as follows :

\(F=ma\\\\F=2100\ kg\times 5.4\ m/s^2\\\\F=11340\ N\)

So, the net force is 11340 N.

An appeal of a state appellate court ruling can next be made to:
• A. a state trial court.
• B. the state supreme court.
• C. the U.S. Supreme Court.
• D. a U.S. Court of Appeals.

An appeal of a state appellate court ruling can next be made to: A. a state trial court. B. the state

Answers

The decision of the country's highest court may then be appealing to that Supreme Court of both the U. S., but only in cases where the issue involves federal law.

Why is Supreme renowned?

In particular, followers of hip-hop, surfing, and post - punk culture will find their clothing appealing. Every person who appreciates streetwear will discover the ideal item thanks to Supreme's wide range of clothing.

Why is Supreme so expensive?

Rebellious and distinctive brand image! Despite giving a venture - capital group a 50% ownership in the company, Supreme has been able to keep its skater roots and fan base. To top it all off, the Supremes' emblem is distinctive, outstanding, and simple to recognize.

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A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.​

Answers

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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4. Work and Energy is measured in
a. Newtons (N)
b. Newton-meters (Nm)
C. Joules (J)
d. Either Newton-meters (Nm) or Joules (J)

Answers

Answer:

D

Explanation:

A Newton-meter is the same thing as a Joule.

Answer:

c

Explanation:

feel kolang na yan yung answer HAHAHAHA

In a football game, one team kicks off to the other. At the moment the receiver catches the ball, he is 40 meters from the nearest tackler. The receiver runs left to right at a speed of 10 meters per second (10 m/s). The tackler runs right to left at a speed of 6 meters per second.

How long does it take before they collide? ___________

How far does the receiver go? _____________________

Answers

Take left to be the negative direction, and right to be positive.

The receiver's position at time t, taking his starting position to be the origin, is

(10 m/s) t

while the tackler's position is

40 m + (-6 m/s) t

The two collide when their positions are equal:

(10 m/s) t = 40 m - (6 m/s) t

(16 m/s) t = 40 m

t = (40 m) / (16 m/s)

t = 2.5 s

In this time, the receiver covers a distance of

(10 m/s) (2.5 s) = 25 m

Unpolarized light of intensity 0.0288 W/m2 is incident on a single polarizing sheet. What is the rms value of the electric field component transmitted

Answers

Answer:

the rms value of the electric field component transmitted is 3.295 V/m

Explanation:

Given;

intensity of the unpolarized light, I = 0.0288 W/m²

For unpolarized light, the relationship between the amplitude electric field and intensity is given as;

\(E_{max} = \sqrt{2\mu_0cI} \\\\E_{max} = \sqrt{2(4\pi \times 10^{-7})(3\times 10^8)(0.0288)} \\\\E_{max} = 4.66 \ V/m\)

The relationship between the rms value of the electric field and the amplitude electric field is given as;

\(E_{rms} = \frac{E_0}{\sqrt{2} } =\frac{E_{max}}{\sqrt{2} } \\\\E_{rms} = \frac{4.66}{\sqrt{2} }\\\\E_{rms} = 3.295 \ V/m\)

Therefore, the rms value of the electric field component transmitted is 3.295 V/m

Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.

Answers

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

What is the  magnitude of the initial acceleration?

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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Select all the correct statements that are always true about conductors. a. A conductor in an electric field becomes polarized. b. In electrostatic equilibrium, the electric field inside a conductor should be zero. c. In electrostatic equilibrium, the electric field inside a conductor should be infinite. d. In electrostatic equilibrium, the electric field must point outward from the surface of the conductor. e. In electrostatic equilibrium, the electric field must point inward from the surface of the conductor.

Answers

Answer:

true b

Explanation:

They ask us to evaluate if the expressions are true

a) False. The concept of polarization refers to the direction of the oscillating electric field in a traveling wave, in this case the shocks cause the wave to disperse

b) True .. Yes, since no work is done inside the conductor, so all the load is on the surface

c) False. In electrostatic equilibrium the voltage must be the same everywhere

d) False. If the charges are positive point out

              If the charges are negative point inwards

e) False. If the charge is positive, the pattern is outward

               if negative largares points gavia inside.

6. The concept of Horsepower was first defined by James Watt so he could compare steam engines to horses.
Watt defined horsepower by determining that the average horse could do about 45,000 J of work in one
minute. This is equivalent to a horse pulling 150 kg of coal a distance of 30 m in one minute. The unit HP
stuck and today it is used to describe everything from chain saws to racecars. The average car produces
about 150 HP, or 112,000 W. If 1 HP=745 W, determine how much horsepower you produced when doing
pushups. SHOW YOUR WORK!

Answers

The power produced for doing one push-up if  45,000 J of work in one minute. This is equivalent to a horse pulling 150 kg of coal at a distance of 30 m in one minute is 0.466 horsepower.

What is Power?

A low-powered motor can carry out the same amount of work slowly, whereas a high-powered motor can finish it rapidly.

Given:

The average power of a horse = 45000 J/min,

The force you applied times the distance you applied equals the labor needed to complete the activity. The work you produced is equal to the work for one repeat multiplied by the number of repetitions you completed. The amount of work you accomplished divided by the total time required is your power output.

Let the mass of a man doing push-ups is 70 kg and take 2 seconds to complete, then,

The Force exerted by the man while doing one push-up = 70 * 9.8 N = 686 N.

Now calculate the work done if body displacement is 1 meter during push-ups,

Work done = \(F\times displacement\),

Work done = 686 × 1,

Work done = 686 J,

So the \(Power = \frac{workdone}{Time}\)

Substitute the values

Power = 686 ÷2

Power = 343 Watt

1 watt = 0.00135962 horsepower

Hence, 343 Watt  = 343 × 0.00135962

Power = 0.466 horsepower

Therefore, the power produced by doing one push-up is 0.466 horsepower.

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Forces that are equal in size but opposite in direction are what a, balanced forces, b frictional forces, c, inertial forces or d, net forces.

Answers

Answer:

b) frictional forces

Explanation:

These forces tend to oppose sudden movement of an object.

The slope of a velocity time graph will give

Answers

Acceleration of a moving object

A person pushes a box across a horizontal surface at a constant speed of 0.5 meter per second The box has
a mass of 40 kilograms, and the coefficient of sliding friction is 0.25. The power supplied to the box by the
person is
a. 0.2 W
c. 50 W
b. 5W
d. 100 W

Answers

Answer:

The correct option

(C) 50W

-

Hope it help's u :))!

Using the given data table, calculate the acceleration of the skateboarder. You can use either form of the
equation:

Using the given data table, calculate the acceleration of the skateboarder. You can use either form of

Answers

The acceleration of skateboard on road A will be 7.74 \(m/s^{2}\)

The acceleration of skateboard on road B will be 3.87 \(m/s^{2}\)

The acceleration of skateboard on road C will be 9.68 \(m/s^{2}\)

force = mass * acceleration

mass1 = 62 kg

force1 = 480 N

acceleration1 = force / mass

                     = 480 / 62 = 7.74 \(m/s^{2}\)

mass2 = 62 kg

force2  = 240 N

acceleration 2  = 240 / 62 = 3.87  \(m/s^{2}\)

mass 3 = 62 kg

force 3  = 600 N

acceleration 3  = 600 / 62  = 9.68  \(m/s^{2}\)

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Find the depth in a lake at which the pressure is 173.693 lb/in2.

Answers

The depth in the lake of pressure 173.693 lb/in² is 122.45 m.

What is depth?

Depth is the distance down either from the top of something to the bottom, or to a distance below the top surface of something.

To calculate the depth in the lake, we use the formula below.

Formula:

h = P/gD........................ Equation 1

Where:

h = Depth in the lakeP = Pressure D = Density of waterg = Acceleration due to gravity

From the question,

Given:

P = 173.693 lb/in² = 1.2×10⁶ N/m²g = 9.8 m/s²D = 1000 kg/m³

Substitute these values in to equation 1

h = (1.2×10⁶)/(9.8×1000)h = 122.45 m

Hence, the depth in the lake is 122.45 m.

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How is it possible for man made things to move?

Answers

Explanation:

Natural things are all the elements present in the world. Whatever is there because of nature, like petrolium and coal which is developed over thousands and millions of year process. There are many more, like even living things do come inside the circle of natural things, because man can not make life we can alter it examples can be found on your dining table, fruits and vegetables. Over the period of time humans have altered the genes of fruits and vegetables to grow the way they want example seedless grapes, seedless banana etc.

Which of the following works of art is from the Amarna Period? How to: Items can be selected or deselected by clicking anywhere on the box. Selected items are highlighted in blue. 1 2 3 4

Answers

Work of art from the Amarna Period that is abstract or descriptive in nature.

What modifications did the Amarna Period bring to the arts?

That momentarily altered during the Amarna Period. The neck, arms, and hands were among the longer characteristics on the body. The traditional Egyptian painting form was briefly replaced by this strange new art form, which resulted in portraits of people that were virtually caricatures.

What is renowned about the Amarna Period?

Religious iconoclasts are associated with the Amarna Period. Because he only worshiped the Aten, the pharaoh Amenhotep IV changed his name to Akhenaten. At Tell el-Amarna in Middle Egypt, he constructed a brand-new capital and cemetery.

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how much rope is needed for 1 with the 1 fixed, 1 moveable pulley system

A.10 meters

B. 20 meters

C. 30 meters

D 40 meters

Answers

Answer:

c

Explanation:

The answer is c i think

How do you find the period of a sound wave?

Answers

Answer:

Period refers to the time for something to happen and is measured in seconds/cycle. In this case, there are 11 seconds per 33 vibrational cycles. Thus the period is (11 s) / (33 cycles) = 0.33 seconds. We now know that the period is 3.2 seconds and that the frequency is 0.31 Hz.

Hendry throws an object vertically upwards at a velocity of 26,5 m⋅s-1 from the
edge of a cliff of height 120m. After some time, the projectile lands on the
ground below the cliff After 1 second, Cathy fires a second object upwards FROM THE
GROUND BELOW with a velocity of 45 m⋅s-1. Calculate the time and
distance will the two objects meet.

Answers

Hendry and Cathy will each throw an object, and the time and location at which they will collide can be determined using the laws of motion. Hendry's item had an initial velocity of 26.5 m/s, whereas Cathy's object had an initial velocity of 45 m/s. Hendry's object's equation of motion is given by: s = u*t + 0.5*a*t*2, where s is the displacement, u*t* is the starting velocity, t* is the time, and a*t* is the acceleration brought on by gravity.

The acceleration caused by gravity is negative since the item is being flung upward. The item that Cathy threw has the following equation of motion: s = u * t - 0.5 * a * t2.where s is the distance travelled, u is the starting speed, t is the passage of time, and an is the acceleration brought on by gravity. The acceleration caused by gravity is negative since the item is being flung upward.

These equations allow us to determine the location and timing of the two items' collision. By figuring out the two equations for t, one may determine the moment when the objects will collide. By changing the value of t in either equation, one may determine the distance at which the objects will collide. Therefore, using the equations of motion, it is possible to determine the moment and distance at which the two objects will collide.

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A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?

3.13 m/s2

4.22 m/s2

5.31 m/s2

6.67 m/s2

none of the above

Answers

First convert 90km/hr to m/s.

Initiate velocity = 0m/s (car was at rest)

Final velocity is 25m/s (90km/hr converted)

25m/s - 0m/s / 8s = 3.125 m/s^s

Therefore the answer is option A (3.13m/s^2)

2. A girl and her bicycle have a total mass of 40 kg. At the top of the hill her speed is 5.0 m/s.
The hill is 10 m high and 100 m long.
If the magnitude of the force of friction as she rides down the hill is 20 N, what is her speed
at the bottom of the hill? (Take g=9.8 m/s?)
(a) 5.0 m/s
(b) 10 m/s
(c) 11 m/s
(d) 18 m/s
(e) She stops before she reaches the bottom.

Answers

Answer:

Explanation:

1. First draw a free body diagram of the scenerio (a block sliding down a a slant surface).
2. Then we analyze the forces and write equations that satisfy Fnet = ma. This will give us the acceleration as the block slides down the surface.

3. Last, we can use the kinematic equation (vf^2 = vi^2 + 2as) and to solve the final speed of the block.

2. A girl and her bicycle have a total mass of 40 kg. At the top of the hill her speed is 5.0 m/s.The

Particles q₁ +8.0 μC, q₂ +3.5 μC, and
93 -2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right

Particles q +8.0 C, q +3.5 C, and93 -2.5 C are in a line. Particles q and q2 areseparated by 0.10 m and

Answers

The net electric force on particle 2 is -21.7 N.

What is the net force on particle q₂?

The net force on particle q₂ is determined by applying Coulomb's law of electrostatic force.

F = kq₁q₂ / r²

where;

k is coulomb's constantq is the magnitude of the charger is the distance between the charge

The force  between particle 2 and particle 1 is calculated as;

F = -( 9 x 10⁹ x 8 x 10⁻⁶ x 3.5 x 10⁻⁶ ) / (0.1)²

F = - 25.2 N

The force  between particle 2 and particle 3 is calculated as;

F = ( 9 x 10⁹ x 2.5 x 10⁻⁶ x 3.5 x 10⁻⁶ ) / (0.15)²

F = 3.5 N

The net force on particle 2 = 3.5 N - 25.2 N = -21.7 N

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1. The wave speed of a wave through a medium is equal to the frequency times the wavelength. When the frequency changes, the wavelength must change to compensate. Why can't the velocity of the wave change?
a. The velocity must remain constant to keep the ratio of frequency and wavelength in check
b. The velocity of a mechanical wave is dependent on the medium
c. The wavelength is separate from the velocity, so it can change while the wavelength cannot
d. The velocity of the wave cannot change because it is set by the force that starts the oscillation

2. If a water wave has a velocity of 4.5 m/s and has a frequency of 25 Hz, what is the wavelength of the wave?
a. 0.80 m
b. 5.6 m
c. 0.35 m
d. 0.18 m

Answers

a. The velocity must remain constant to keep the ratio of frequency and wavelength in check. The wave speed is determined by the properties of the medium through which the wave travels, and is independent of the frequency and wavelength of the wave.

c. 0.35 m. The wavelength can be calculated using the formula: wavelength = wave speed / frequency. Plugging in the given values, we get wavelength = 4.5 m/s / 25 Hz = 0.18 m/Hz = 0.35 m (rounded to two decimal places).


A car accelerates from 10m/s to 50m/s over a distance of som. What is the
acceleration of the car?

Answers

Answer:

40m/s

Explanation:

50m/s - 10m/s = 40m/s

derive an expression for torque experiend by an electric dipole placed in a uniform electric field​

Answers

Answer:

The torque τ on an electric dipole with dipole moment p in a uniform electric field E is given by τ = p × E where the "X" refers to the vector cross product. Ref: Wikipedia article on electric dipole moment.

Explanation:

Figure 13-27 gives the gravitational acceleration ag for four planets as a function of the radial distance r from the center of the planet, starting al the surface of the planet (at radius R1,R2,R,or R4). Plots 1 and 2 coincide for r greater than equal to R2; plots3 and 4 coincide for r greater than equal toR4. Rank the four planets according lo(a) mass and (h) mass per unit volume. greatest first.

Answers

1 > 2 > 3 > 4 will be the order of the planets As per mass per unit volume and stats are given. As the density of the planet is directly proportional to its mass of the planet.

The force of attraction of two bodies is directly proportional to the products of their masses whereas it is inversely proportional to that of the distance between them here we use the constant Newton's gravitational Universal Constant.

So the more the mass more the attraction and more the distance the less attraction will be or vice-versa.

And shown in the Image attached how density is decreasing from planet 1 to planet 4 so the order of masses will also be the same.

And for bodies that have the same density would be evaluated on the basis of the distance between them.

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Figure 13-27 gives the gravitational acceleration ag for four planets as a function of the radial distance

15. [-/10 Points) DETAILS SERPSE10 1.A.0P.031.MI. A high fountain of water is located at the center of a circular pool as shown in thi pool and measures its circumference to be 23.8 m. Next, the student stands at th to gauge the angle of elevation of the top of the fountain to be g - 54.0°. How hi mA high fountain of water is located at the center of a circular pool as shown in the figure below. A student walks around the pool and measures its circumference to be 23.8 m. Next, the student stands at the edge of the pool and uses a protractor to gauge the angle of elevation of the top of the fountain to be p = 54.0°. How high is the fountain?

Answers

The fountain is 5.213m high.

Any shape's perimeter, or route around it, may be described by its circumference. In other words, the perimeter is another name for the circumference, which makes it easier to determine how long a shape's boundary is. The measurement of the circle's boundaries is known as the circumference or perimeter of the circle.circumference of pool = 23.8m2πr = 23.8mr = 3.788mThe angle formed between the horizontal line and the line of sight of a certain observer is known as the angle of elevation. The angle of elevation, as implied by its name, refers to the angle created when an item is viewed from below by the observer and their line of sight.angle of elevation of fountain = 54°let height of fountain be "h"Tan(54°) = h/rh = Tan(54°)*rh = 1.37638192 * 3.788h = 5.213m

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Part D
The quantity represented by v is a function of time (i.e., is not constant).

True or false

Part E a particle moves with constant acceleration a. The expression VI +80 represents the particles velocity at what instant in time.

A. At a time T=zero

B. At the initial time

C. When a time tea has passed since the beginning of the particles motion, when its velocity was the vi

Answers

The amount indicated by is not fixed and changes over time. In situations where the linear acceleration is not zero, the velocity is always changing.

The first case is true

Since it depends on time, is not constant?

The amount indicated by is not fixed and changes over time. In situations where the linear acceleration is not zero, the velocity is always changing.

The dimension of the quantity albo will be ufa au av u t when calculating a particle's velocity as a function of time t using the formula v = a(1 - eb), where a and b are constants. (1 - e-b) Greutate, urb'a 221 Aich, a zat a2b3c faut Eleft.

The amount indicated by is not fixed and changes over time. When linear acceleration is absent  .

   

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The quantity represented by v is a function of time (i.e., is not constant).

True or false

A  particle moves with constant acceleration a. The expression VI +80 represents the particles velocity at what instant in time.

A. At a time T=zero

B. At the initial time

A particle starts from the origin at time t = 0 and moves along the positive x - axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time t = 5s?

URGENT HELP IT IS DUE BY TONIGHT PLEASE HELP

URGENT HELP IT IS DUE BY TONIGHT PLEASE HELP

Answers

Answer:

45.8

Explanation:

becuse 9.8+36=45.8 simple


What is the resistance at 20°C of a 2.0-meter length of tungsten wire with a cross-sectional area of 7.9 10^-7
meter^2

Answers

Answer:

1.4 * 10 ^-1 Ω

Explanation:

Hi,

For this question, we gotta use the formula

R = pL/A

p = The resistivity of your material at 20°C

L = length of the wire

A = cross-sectional area

The resistivity of tungsten is 5.60 * 10^-8 at 20°C

By plugging the values, we get:

R = (5.60 * 10^-8)(2.0)/(7.9*10^-7) = 1.4 * 10 ^-1 Ω

Other Questions
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