Let , side lawn is a.
Area of boundary is :
\(A=4\times5\times a\\\\A=20a\ m^2\)
Now, total cost is given by :
\(T=20a\times 36.25\\\\90625=725a\\\\a=125\ m\)
Area left is :
\(A'=a^2-20a\\\\A'=125^2-20\times 125\ m^2\\\\A'=13125\ m^2\)
Price to empty space with turfs is :
\(P=A'\times 20\\\\P=13125\times 20\\\\P=262500\)
Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.
Hence, this is the required solution.
GIVING BRAINLIST PLEASE HELP!!!
The probability that a randomly selected point within the circle would fall in the red- shaded area is 45. 833 %
How to find the probability ?The arc that is covered by the red - shaded area in the circle has a degree measure of 165 degrees. This is out of the total circle angle measure of 360 degrees.
This therefore means that the probability that a randomly selected point within the circle would fall in the red- shaded area can be found to be :
= Angle measure of red - shaped area / Total area x 100 %
= 165 / 360 x 100 %
=0. 45833 x 100 %
= 45. 833 %
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Evaluate the expression: 8 ⋅ (1/2)^2
Answer:
8 × (1/2)²
8 × 0.25
2 Answer!
Hope this helps, thank you :) !!
Answer:
Step-by-step explanation:
The answer is : 2
Simplify
I added image with explation! Hope this helps!
the dice was thrown 35 times and following numbers were obtained prepare frequency table51423266142545361526254132141626333
This table shows the frequency of each number obtained after throwing the die 35 times
How to prepare frequency tableTo prepare a frequency table based on the numbers obtained from throwing a die 35 times, we can list the numbers from 1 to 6 and count the frequency of each number.
Numbers: 1, 2, 3, 4, 5, 6
Frequency: 5, 14, 6, 4, 5, 1
Based on the given numbers, the frequency table would look like this:
Number | Frequency
1 5
2 14
3 6
4 4
5 5
6 1
This table shows the frequency of each number obtained after throwing the die 35 times.
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Complete the sequence of numbers in the set. Explain the pattern.The completed sequence of numbers is 8.5, 7.15, 5.8,
blank and
blank. fill it in
Answer:
\(8.5,7.15,5.8,4.45,3.1,...\)
Step-by-step explanation:
The first step to solve this question is to analyze the given sequence.
We can notice that the difference between 8.5 and 7.15 is
\(8.5-7.15=1.35\)
And again the difference between the second and the third term is :
\(7.15-5.8=1.35\)
One way to describe all the numbers in the sequence is by using a formula.
We can write :
Given the sequence \(a_{0},a_{1},a_{2},a_{3},...\)
\(a_{n}=8.5-(1.35)n\) with \(n\) ∈ I\(N_{0}\)
For example :
\(a_{2}=8.5-(1.35).2=5.8\) which verifies our original sequence.
We can obtain any term we want of the sequence.
Some of the terms that complete the sequence are :
\(8.5,7.15,5.8,4.45,3.1,...\)
A population of values has a normal distribution with μ=25.9 and σ=74.2. You intend to draw a random sample of size n=99.Find the probability that a sample of size n=99 is randomly selected with a mean between 28.1 and 35.6. P(28.1 < M < 35.6) =
Answer: 0.0397
Explanation
Given
• Normal distribution
,• μ = 25.9
• σ = 74.2
,• n = 99
,• Mean between 28.1 and 35.6
Procedure
As we have a normal distribution, we can get Z-score to approximate the probability using the following formula for both values:
\(Z=\frac{x-\mu}{\sigma}\)• Lower value
\(Z_1=\frac{28.1-25.9}{74.2}=0.030\)• Upper value
\(Z_2=\frac{35.6-25.9}{74.2}=0.131\)\(P\left(28.1Using the Standard Normal Table we can conclude that:\(P(28.1\lt M\lt35.6)=P(0.030\lt Z\lt0.131)=0.0397\)which shows the product of 23 and 39
Answer:
897
Step-by-step explanation:
"Product" in math refers to multiplication, so you would just multiply the two to get 897.
Answer:
897
Step-by-step explanation
multilpy
In the state of Pennsylvania 12% of students submit box tops for education to their school. A large school district in western Pennsylvania runs a contest to see if they can increase participation. The superintendent takes a random sample of 210 students from the district and finds that 35 have submitted box tops this year. Do these data provide convincing evidence that the contest has increased participation in the box tops for education programs
Answer:
Step-by-step explanation:
All it's saying is that the 12% of the people are 35 and the 82% of people who did not submitted data is 175 people
The calculated test statistic (2.08) is greater than the critical value (1.96), we reject the null hypothesis and conclude that there is evidence to suggest that the contest has increased participation in the box tops for education program.
How to calculate the null hypothesis?To determine if the contest has increased participation in the box tops for the education program, we need to conduct a hypothesis test.
We will use a significance level of 0.05, which means we are willing to accept a 5% chance of making a Type I error (rejecting the null hypothesis when it is actually true).
Null Hypothesis: The proportion of students submitting box tops for education is still 12% (or has decreased) after the contest.
Alternative Hypothesis: The proportion of students submitting box tops for education has increased after the contest.
To test this hypothesis, we will use a one-sample proportion test. We will use the sample proportion, p' = 35/210 = 0.1667, as an estimate of the population proportion, p. The test statistic is calculated as:
z = (p' - p) / √(p x (1-p)/n)
where n is the sample size.
Under the null hypothesis, the expected value of the test statistic is 0, and the standard deviation of the test statistic is sqrt(p*(1-p)/n).
Using p = 0.12 and n = 210, we have:
z = (0.1667 - 0.12) / √(0.12 x 0.88/210) ≈ 2.08
The critical value for a significance level of 0.05 and a two-tailed test is ±1.96.
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PLEASE HELP ME with an explanation. Thanks in advance
Answer:
Option 3.
Step-by-step explanation:
Let T=Total, B=Brother and S=Sister. By using given diagram, we get
\(n(B)=28+68=96\)
\(n(S)=82+68=150\)
\(n(T)=28+68+82+52=230\)
\(n(B\cap S)=68\)
Using this information, we get
\(P(B)=\dfrac{n(B)}{n(T)}=\dfrac{96}{230}\approx 0.42\)
\(P(S)=\dfrac{n(S)}{n(T)}=\dfrac{150}{230}\approx 0.65\)
\(P(S|B)=\dfrac{P(B\cap S)}{P(B)}=\dfrac{n(B\cap S)}{n(B)}=\dfrac{68}{96}\approx 0.71\)
\(P(B|S)=\dfrac{P(B\cap S)}{P(S)}=\dfrac{n(B\cap S)}{n(S)}=\dfrac{68}{150}\approx 0.45\)
The probability P(S|B) has the largest value.
Therefore, the correct option is 3.
I have a test and I need all the answers
Answer:
ok what is it
Step-by-step explanation:
Answer:
ok...ask the questions
Step-by-step explanation:
What’s the correct answer for this?
Answer
D.
Explanation
mIH = 44
mIJ = 46
mJK = 77
ADDING THEM ALL TO FIND THE MEASURE OF m<HOK
<HOK = 44+46+77
<HOK = 167°
I have to solve each problem and round to the nearest tenth.
Answer:
x=10
Step-by-step explanation:
Solve for x leave your answer in simplest radical form
Answer:
X=11 trust me on my mom
Pls help I will give brainiest answer.
Answer:
1) D
2) A
Step-by-step explanation:
Brian set his compass equal to the radius of circle C and drew two circles centered at points A and B on circle C. He labeled the points of intersection of the two circles as shown.
Two circles are drawn by having another circle in the center. The center circle has points A, M, N, B, P, Q, and C. At C the two circles intersect, and at P the center circle and the top circle intersect.
To complete his construction, Brian only needs to use his straightedge to draw some chords of circle C.
Which figures could Brian be constructing?
equilateral triangle MNQ inscribed in circle C
equilateral triangle ANP inscribed in circle C
regular hexagon AMNBPQ inscribed in circle C
square MNPQ inscribed in circle C
square ANBQ inscribed in circle C
The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:
Equilateral triangle MNQ inscribed in circle C
Regular hexagon AMNBPQ inscribed in circle C
Brian is constructing figures inscribed in circle C.
Equilateral triangle MNQ inscribed in circle C:
This option is possible since the points M, N, and Q are labeled and they lie on circle C.
Equilateral triangle ANP inscribed in circle C:
This option is not possible. The points A and P are labeled, but the third vertex of the equilateral triangle is not specified.
Regular hexagon AMNBPQ inscribed in circle C:
This option is possible since the points A, M, N, B, P, and Q are labeled and they lie on circle C.
Square MNPQ inscribed in circle C:
This option is not possible based on the given information. The label points do not form a square.
Square ANBQ inscribed in circle C:
This option is not possible . The points A, N, B, and Q are labeled, but they do not form a square.
The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:
Equilateral triangle MNQ inscribed in circle C
Regular hexagon AMNBPQ inscribed in circle C
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what is 1/4 compared to 25%
Answer:
i dunno if this will help any but i think 1/4 and 25% is the same since 100/4=25
Step-by-step explanation:
if it doesn't i'm sorry for waisting ur time-
Half as many as 7 more than a number
Answer:
less than twice the number
Step-by-step explanation:
The variable y varies directly with the variable x.
A 2-column table with 3 rows. Column 1 is labeled x with entries 2, 10, 14. Column 2 is labeled y with entries 3, 15, blank, where y is
If the value of x is 14, what is the value of y?
Now that we know k is 3/2, we can use the formula to find the value of y when x is 14:
y = (3/2)(14) = 21
Therefore, when x = 14, y = 21.
What is a variable defined as?A variable is a number in mathematics that can change depending on the issue. Several statements and equations in mathematics use the generic letters x, y, and z. Or to put it another way, a variable is a symbol that denotes an unknowable numerical value. Assume that x + 5 = 10. The term "x" is used here.
Since y varies directly with x, we know that the ratio of y to x is constant. Let's call this constant k. Then we can write:
y = kx
To find k, we can use the first two rows of the table:
When x = 2, y = 3, so:
3 = k(2)
k = 3/2
When x = 10, y = 15, so:
15 = k(10)
k = 3/2 (which matches the previous calculation)
Now we can use k to find y when x = 14:
y = (3/2)(14) = 21
Therefore, when x = 14, y = 21.
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The monthly water bill is a function of the number of gallons used. The cost is $19 60 for 20.000 gal or less Over 20.000 gal the cost is $19 60 plus $1 for each 1000 gal over 20,000 with any fraction of 1000 gal charged at a fraction of $1 On what interval is the cost constant? On what interval is the cost increasing? On what interval is the cost constant?
Let's define the monthly water bill as a function, where:
• c ,is the number of gallons consumed that month
,• B(c), is cost of the monthly water bill
Therefore, for a consumption of 20.000 gallons or less, the monthly water bill would be:
\(\begin{gathered} B(c)=19.60 \\ c\le20000 \end{gathered}\)For a consumption of more than 20.000 gallons,
\(\begin{gathered} B(c)=19.60+\frac{c-20000}{1000} \\ c>20000 \end{gathered}\)Therefore:
• The cost is constant ($19.60) when the number of gallons consumed is less than or equal to 20,000 gallons
,• The cost increases if the number of gallons consumed is greater than 20,000 gallons
You spent 9.5 hours playing Among Us
this week. This is 2.75 hours more than the
number of hours h you played last week.
Which equation can be used to find h?
A. 9.5=2.75-h B. 9.5= h+ 2.75 C. 2.75= h-9.5 D. 2.75= h+9.5
Answer:
c
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Joseph is exactly 13 meters from Holly (2, 2), and he is located in the 4th quadrant on the grid. Where is Joseph?
which grows at the fastest rate for increasing values of x
\(f(x)=4*2^x\\h(x)=9x^2+25\\\\g(x)=15x+6\)
The function that grows at the fastest rate for increasing values of x is f(x) = 4×2ˣ.
We can see this by comparing the growth rates of the three functions for larger and larger values of x.
As x gets larger, the exponential function f(x) grows much faster than the other two functions, which are both polynomial functions.
if we plug in x = 10, we get:
f(10) = 4×2¹⁰ = 4×1024 = 4096
h(10) = 9×10² + 25 = 925
g(10) = 15×10 + 6 = 156
As we can see, f(10) is much larger than h(10) and g(10), indicating that f(x) grows at a much faster rate than the other two functions.
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The US Fish and Wildlife Service reported that the mean length of a 6 year old trout in the Arolik River in Alaska is 480 and standard deviation of 40 mm. Assume length of trout is normally distributed,
a) Find the 58th percentile of the lengths
The 58th percentile of the lengths is 489.4 mm.
What is the 58th percentile of the lengths?The 58th percentile of the lengths is calculated from normal distribution curve as shown below.
The mean of the distribution is at the 50th percentile.
The 58th percentile is between the mean and 1 standard deviation above the mean.
Mean (50%) = 480 mm
58% = ?
1 standard deviation above the mean (84%)= M + S.D = 480 mm + 40 mm = 520 mm
We are going to interpolate, to find the approximate value of the length.
50 ----- 480 mm
58 ----- ?
84 ------- 520 mm
(58 - 50)/(84 - 50) = (x - 480)/(520 - 480)
0.235(40) = x - 480
9.4 = x - 480
x = 489.4 mm
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If 1,200 students participated in the survey, how many rated the cafeteria food “poor”?
200 students
300 students
400 students
600 students
Answer:
The answer is 300
Answer:
300 students
Step-by-step explanation:
hope this helps!
Which one of the them please?
Answer:
Dog.
Step-by-step explanation:
Because:-
Tomato is much lighter.
Pineapple is not convincing
Dog is reliable.
Pencil is not correct.
6x8 = nx 16
What is the value of the unknown number?
state whether the standardized test statistic t indicates that you should reject the null hypothesis. explain.
No, the standardized test statistic t does not indicate that you should reject the null hypothesis.
The value of the test statistic t only tells you how much of an effect the independent variable has on the dependent variable. To determine whether to reject the null hypothesis, you must compare the value of t to a critical value based on the sample size, the level of significance, and the degrees of freedom.
The standardized test statistic t does not indicate whether you should reject the null hypothesis. To determine this, you must compare the value of t to a critical value based on the sample size, level of significance, and degrees of freedom.
No, the standardized test statistic t does not indicate that you should reject the null hypothesis.
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Fifteen percent of 168
Answer:
25.2
Step-by-step explanation:
168 x .15 = 25.2
\(\large\text{Hey there!}\)
\(\rm{15\%\ of\ 168}\\\\\rm{= 15\% \times 168} \\\\\rm{= \dfrac{15}{100}\times 168}\\\\\rm{= \dfrac{15}{100}\times \dfrac{168}{1}}\\\\\rm{=\dfrac{15\times168}{100\times1}}\\\\\rm{= \dfrac{2,520}{100}}\\\\\rm{= 25.2}\)
\(\huge\text{Therefore, your answer should be: }\)
\(\huge\boxed{\frak{25.2}}\huge\checkmark\)
\(\huge\text{Good luck on your assignment \& enjoy your day!}\)
~\(\frak{Amphitrite1040:)}\)
Complete the following sentence (select all that apply). The expected count of females who are not pierced is what we would expect to see in the sample if ___________________________. Group of answer choices gender and piercing were significantly related. gender and piercing are independent. the null hypothesis is true. the null hypothesis is not true.
The statement that completes the blank is (c) the null hypothesis is true.
In sampling techniques, the expected count of a variable is dependent on the null hypothesis.
This means that, if the null hypothesis is true, then the expected count is what is expected to be seen in the sample.
This in other words, means that the complete statement is:
The expected count of females who are not pierced is what we would expect to see in the sample if the null hypothesis is true.
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What is the surface area of this cylinder?
Use ≈ 3.14 and round your answer to the nearest hundredth.
The radius is 10mm and the height is 5mm
Answer:
942 square millimeters.
Step-by-step explanation:
The formula for the surface area of a cylinder is:
S = 2πr^2 + 2πrh
where S is the surface area, r is the radius, and h is the height.
Substituting the given values, we get:
S = 2 x 3.14 x 10^2 + 2 x 3.14 x 10 x 5
S = 628 + 314
S = 942
Therefore, the surface area of the cylinder is 942 square millimeters.
Which of the following would be proportional to 3/5? 3/10 12/15 12/20. 18/20
Answer:
15/20
Step-by-step explanation:
It is the only one that can be simplified into 3/5
Answer:
12/20
Step-by-step explanation: