Matter is the substance which have some mass and can occupy space is well.
What does it mean that matter has mass and occupies space?Matter is any substance which has mass and occupy some space by having the volume. All physical things are made up of matter and an easily observed property of matter is its state or phase. There are three states of matter Solid, Liquid and Gas. These three matter are responsible for the production of things. The matter can occupy the space but the same matter can not occupy the same space.
Which two types of forces are responsible for state of matter?The state of a substance directly depends on the balance between kinetic energy of the individual particles and the intermolecular forces between them. If forces are strong, state of matter changes into solid and liquid.
So we can conclude that matter is the substance which have some mass and can occupy space is well.
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A metal block of density 900kgm^-3 weighs 60N in air, find its weight when it is immersed in paraffin wax of density 800kgm^-3
Mrs. Tate travels in her car. She goes from mile marker 15 to 125 in 2.75 hours. What is her average speed?
Answer:
Explanation:
Step 1: Subtract 15 from 125
\(125-15=110\)
She traveled 110 miles in 2.75. We need to find her avg. speed.
Step 2: Divide 110 by 2.75
\(110/2.75=40\)
The answer is: Her average speed is 40 miles per hour.
Hope this helped!
A man attempts to move a truck by pushing it, but he can't move it. Describe the work done by the man.
If a man tried to move a truck by pushing it, but he is not able to move it, then the work done by the man will be equal to zero.
What is Work?In physics, the word "work" involves measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied with in the direction of the displacement. The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.
As per the given question,
The man tries to move the truck, but he is not able to move. It means that the total displacement is zero, which means according to the formula of work done the work is also zero.
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In terms of electric pressure, describe a charged capacitor.
Answer: The capacitor is fully charged when the voltage of the power supply is equal to that at the capacitor terminals. This is called capacitor charging; and the charging phase is over when current stops flowing through the electrical circuit.
You are reading a book and decide to estimate the magnitude of the electric and magnetic fields of the light that is incident on the book from your desk lamp. You can treat the lamp as a point source that emits sinusoidal EM waves uniformly in all directions. The book is at 1 m from the 100 Watt light bulb. Assume that all the electric energy is transformed into visible light.
(Part a) Calculate I, the intensity of the light incident on your book?
(Part b) Find Eo and Bo, the amplitude of the electric and the magnetic fields of the EM waves emitted by the lamp.
Answer:
a. 7.96 W/m² b. i. 0.205 V/m ii. 0.68 nT
Explanation:
(Part a) Calculate I, the intensity of the light incident on your book?
Intensity, I = Power, P/Area,A
I = P/A where P = 100 W and A = 4πr² where r = distance of source from book = 1 m.
So, I = P/A
= 100 W/4π(1 m)²
= 25/π W/m²
= 7.96 W/m²
(Part b) Find Eo and Bo, the amplitude of the electric and the magnetic fields of the EM waves emitted by the lamp.
i. Eo the amplitude of the electric field
Intensity, I = E²/cμ₀ where E = r.m.s value of electric field, c = speed of light = 3 × 10⁸ m/s and μ₀ = permeability of free space = 4π × 10⁻⁷ H/m
Thus, E = √(I/cμ₀)
substituting the values of the variables into the equation, we have
E = √(I/cμ₀)
E = √(7.96 W/m²/[3 × 10⁸ m/s × 4π × 10⁻⁷ H/m])
E = √(7.96 W/m²/120π H/s)
E = √(0.0211 Ws/Hm²)
E = 0.145 V/m
Now E = E₀/√2 where E₀ = maximum value of electric field
So, E₀ = √2E
= √2 × 0.145 V/m
= 0.205 V/m
ii. Bo the amplitude of the magnetic field
Since c = E₀/B₀ where c = speed of light = 3 × 10⁸ m/s
B₀ = E₀/c
= 0.205 V/m ÷ 3 × 10⁸ m/s
= 0.068 × 10⁻⁸ T
= 0.68 × 10⁻⁹ T
= 0.68 nT
PLS ANSWER I NEED HELP
How is an electromagnetic wave (such as a radio wave) different from an ocean wave?
A) An electromagnetic wave cannot travel through empty space, but an ocean wave can.
B) An electromagnetic wave does not require a physical medium to travel through.
C) An electromagnetic wave is a longitudinal wave and an ocean wave is an oblong wave.
D) An electromagnetic wave travels more slowly than an ocean wave.
Answer:
mmmm im going to say B but i’m not sure
Explanation:
Electromagnetic waves can travel through air and unlike ocean waves or sound waves they do not need physical molecules for like a medium to travel
A 240 N force is pulling a 85.0 kg refrigerator across a horizontal surface. The force acts at an angle of 20 above the surface. The coefficient of kinetic friction is 0.200, and the refrigerator moves a distance of 8.00 m. Calculate the work done by the kinetic friction force.
Answer:
Approximately \((-1.2\times 10^{3})\; {\rm J}\) (assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\) and that the refrigerator moved along a straight line.)
Explanation:
It is given that the fridge is on a level surface. The following forces would act on the fridge in the vertical direction:
Weight of the fridge (downwards.)Normal force from the ground (upwards.)Vertical component of the force pulling on the fridge (upwards.)Weight of the refrigerator:
\((\text{weight}) = m\, g = (85.0\; {\rm kg})\, (9.81\; {\rm N \cdot kg^{-1}}) = 833.85\; {\rm N}\).
Let \(F\) denote the force pulling on the fridge. Let \(\theta\) denote the angle of elevation of this force. It is given that \(\theta = 20^{\circ}\). The vertical component of this force will be:
\(\begin{aligned}F\, \sin(\theta) &= (240\; {\rm N})\, \sin(20^{\circ}) \approx 82.085\; {\rm N}\end{aligned}\).
Since the fridge isn't moving in the vertical direction, the resultant force on the fridge in that direction should be \(0\; {\rm N}\). Thus:
\(\begin{aligned} & (- (\text{weight})) + (\text{normal force}) + F\, \sin(\theta) = 0\; {\rm N} \end{aligned}\).
Rearrange this equation to find \((\text{normal force})\).
\(\begin{aligned} (\text{normal force}) &= (\text{weight}) - (\text{normal}) \\ &\approx (833.85\; {\rm N}) - (82.805\; {\rm N}) \\ &\approx 751.77\; {\rm N}\end{aligned}\).
The kinetic friction on this fridge would be:
\(\begin{aligned}& (\text{kinetic friction}) \\ =\; & (\text{coefficient of kinetic friction}) \, (\text{normal force}) \\ \approx\; & (0.200)\, (751.77\; {\rm N}) \\ \approx\; & 150.35\; {\rm N}\end{aligned}\).
Note that the displacement of the refrigerator is opposite to the direction to the direction of the kinetic friction. Thus, \((\text{displacement}) = (-8.00\; {\rm m})\).
Multiply kinetic friction by displacement to find the work done:
\(\begin{aligned}(\text{work done}) &= (\text{force})\, (\text{displacement}) \\ &\approx (150.35\; {\rm N})\, (-8.00\; {\rm m}) \\ &\approx 1.2 \times 10^{3}\; {\rm J}\end{aligned}\).
The figure shows the cross-section of a hollow cylinder of inner radius a = 5.0 cm and
outer radius b = 7.0 cm. A uniform current density of 1.0 A/cm2 flows through the
cylinder parallel to its axis. Calculate the magnitude of the magnetic field at a distance
of d = 10 cm from the axis of the cylinder. (µ0 = 4π × 10−7 T.m/A)
The magnetic field of a hollow cylinder can be calculated by the Biot-Savart law which can be represented as:`\(d\vec{B} = \frac{\mu_0}{4\pi} \frac{Id\vec{l} \times \vec{r}}{r^2}\)
Where:• I is the current through the wire• dℓ is an infinitesimal segment of the wire• r is the distance from the wire to the point of interest• μ₀ is the permeability of free space Biot-Savart's law can be used to determine the magnetic field produced by any current distribution.
Furthermore, this law is a consequence of the equation describing how a magnetic field induces an electric field and vice versa.
In this case, the cylinder's magnetic field at a distance of d = 10 cm from the axis of the cylinder can be calculated as follows:Given; Inner radius a = 5.0 cm
Radius of cylinder b = 10 cmµ
0 = 4π × 10−7 T.m/A
Formula to be used;`
B= (µ0 * I * a^2)/2 * (d^2 + a^2)^(3/2)`
Here, a = 5 cm
and d = 10 cm.
Substituting the values;
`B = (4 * π * 10^−7 * I * (5*10^−2)^2)/(2 * (10*10^−2^2 + (5*10^−2)^2)^(3/2))`
On solving the above equation, we get;`B = 1.33 × 10^-9 * I T`
Therefore, the magnitude of the magnetic field at a distance of d = 10 cm from the axis of the cylinder is `1.33 × 10^-9 * I T`.
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An airplane has a speed of 120 m/s and an angle of flight of 30º above the horizontal. What is the upward component of the airplane’s velocity?
Answer:
2.26 seconds
97m/s
Explanation:
Fall time
Why do the waves have different speeds in different layers of Earth's surface?
A Earth's different layers contain materials with different energy-transfer properties.
B Earth's different layers already move at different speeds because of Earth's rotation
O c Waves increase in speed as they move away from their source, so they move faster in deeper layers.
D. Waves gain heat energy by traveling through each layer, and the heat is transformed to kinetic energy.
Answer:
Material's density
Explanation:
Seismic waves travel at different rates of speed based on a material's density. Hopefully, you understand that the Earth has three main layers: the crust, mantle, and core. Earthquake waves move faster through solids.
Mention & Instrument used to measure
the mass of the body.
Answer:
a scale is used to measure the mass of the body
Scott travels north 2 miles and then goes west 5 miles before coming straight back south 7 miles what is his displacement
Answer:
Displacement is 5√2 miles
Explanation:
From south, Scott travelled 2 miles north and then 5 miles west then he came back south by 7 miles.
I've attached a diagram to indicate Scott's path travelled
Now, displacement is a vector quantity that tells us the overall change in position by Scott i.e distance from his initial position to his current final position while distance is a scalar quantity and tells us how much ground Scott covered in his motion over the entire trip.
Now, from the attached image, the displacement is denoted by "d".
d can be found from pythagoras theorem.
Thus;
d² = 5² + 5²
d = √50
d = 5√2 miles
two parallel wires carrying equal currents of 10A attract each other with a force of 1mN. If both currents are doubled, what will be the force of attraction?
Answer:
F (force) can be written F/L = K I1 I2 where K is some constant
F1 = 4 F1 if I1 and I2 are each doubled
If both currents are doubled, the new force of attraction between the wires will be 0.4 mN.
The force of attraction between two parallel wires carrying equal currents is given by Ampere's law, which states that the force is directly proportional to the product of the currents and inversely proportional to the square of the distance between the wires. Given that the current in each wire is 10A and the force of attraction is 1mN, we can use this information to calculate the distance between the wires.
Let's assume the distance between the wires is "d".
Using the formula for the force of attraction between the wires:
F = (μ₀ * I₁ * I₂) / (2πd)
where F is the force, μ₀ is the permeability of free space, I₁ and I₂ are the currents, and d is the distance between the wires.
Rearranging the formula, we can solve for d: d = (μ₀ * I₁ * I₂) / (2πF)
We know that F = 1mN, I₁ = I₂ = 10A, and μ₀ = 4π x 10^(-7) N/A².
Substituting these values into the formula, we can find the distance between the wires:
d = (4π x 10^(-7) N/A² * 10A * 10A) / (2π * 1mN)
Simplifying the expression, we find: d = (4 x 10^(-6) N/A² * 100 A²) / (2 x 10^(-3) N)
d = 200 x 10^(-6) m
d = 0.2 mm
Now, if both currents are doubled to 20A, we can calculate the new force of attraction between the wires using the same formula:
F' = (μ₀ * I₁' * I₂') / (2πd)
where F' is the new force, I₁' and I₂' are the new currents, and d is the distance between the wires.
Substituting the values, we get: F' = (4π x 10^(-7) N/A² * 20A * 20A) / (2π * 0.2mm)
Simplifying the expression, we find: F' = (4 x 10^(-6) N/A² * 400 A²) / (4 x 10^(-4) N)
F' = 400 x 10^(-6) N
F' = 0.4 mN
Therefore, the new force of attraction between the wires will be 0.4 mN, if both currents are doubled.
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Since the bullets also have zero velocity, a more exact description of the bullet's state would be _____.
Answer:
Static equilibrium.
Explanation:
a student spins a cup that is in contact with a platform in a horizontal circular path at a constant speed, as shown in figure 1. the platform is connected to two strings that are held by the student as the platform-cup system experiences uniform circular motion. a free-body diagram of the cup is shown in figure 2. which statement of reasoning best supports and correctly identifies the magnitude of the force the cup exerts on the platform?
√F1²+F2², because this force reflects the overall force the cup has applied to the platform.
What factors contribute to circular motion?The change in direction and centripetal force. A centripetal force is applied to any item travelling in a circle (or along a spherical route). Towards other words, the item is being physically pushed or pulled in the direction of the circle's center. This is the necessary centripetal force.
What exactly is the force pulling on a particle traveling in a circle?Centripetal force is the name of the force exerted on a particle that is rotating in a circle. It is this centripetal force that is focused inward that prevents the particle from deviating from or losing its circular course.
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If the instantaneous voltage at a given moment in the circuit RL is V=VmaxSIN(150), then the instantaneous current at the...... same instant I=Imaxsin
The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.
1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).
2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.
3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.
4. However, the given equation does not explicitly mention resistance.
5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).
6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.
7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).
8. Therefore, V = VR + VL.
9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.
10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.
The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.
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Find the current flowing out of the battery.
Answer:
5A
Explanation:
wavelength = 5.4 cm and frequency = 9.4 Hz
What is the speed
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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The image shows a diagram explaining a concept.
Which concept does the diagram show?
A. tempature
B. Altitude
C. air density
D. air pressure
Answer:
D.
Explanation
Air pressure.
Answer:air pressure
Explanation:
Emmy kicks a soccer ball up at an angle of 45° over a level field. She watches the ball's trajectory and notices that it lands, two seconds after being kicked, about 20 m away to the north. Assume that air resistance is negligible, and plot the horizontal and vertical components of the ball's velocity as a function of time. Consider only the time that the ball is in the air, after being kicked but before landing. Take "north" and "up" as the positive x ‑ and y ‑directions, respectively, and use g≈10 m/s2 for the downward acceleration due to gravity.
Answer:
v_y = 10 - 10t
v_x = 10 m/s
Explanation:
This is a projectile launch where the x axis and y axis will be treated independently.
Now, towards the north on the x-axis, there will be no acceleration and so the speed is constant
So, vₓ = v₀ₓ
Whereas, on the vertical y - axis, the acceleration due to gravity with be negative since it's in a downward direction.
Thus, the equation is;
v_y = v_oy - gt
Now, the initial velocity component will be;
cos 45 = v₀ₓ/v₀
And sin 45 = v_₀y/v₀
Thus, we have;
v₀ₓ = v₀(cos 45)
Also, v_oy = v₀(sin 45)
Now, the initial velocity would be gotten from the equation of range which is;
R = (v₀² × sin 2θ)/g
Making v₀ the subject, we have;
v₀ = √(Rg/sin 2θ)
We are given;
R = 20 m
g = 10 m/s²
θ = 45°
Thus;
v₀ = √[20 × 10/(sin (2 × 45))]
v₀ = √200
v₀ = 14.14 m/s
Thus;
v₀ₓ = 14.14(cos 45) = 10 m/s
v_oy = 14.14(sin 45) = 10 m/s
Earlier we saw that;
v_y = v_oy - gt
Thus;
v_y = 10 - 10t
Also,we saw that;
vₓ = v₀ₓ
Thus;
v_x = 10 m/s
For the graph, we will use times of t = 0, 0.2, 0.4, 0.6, 0.8, 1.0, 1.2
Thus, for each of those values of t, we will have the following values of v_oy
t (s) v_oy (m / s)
0 10
0.2 8
0.4 6
0.6 4
0.8 2
1.0 0
1.2 -2
Graph is attached
Magnetic resonance imaging needs a magnetic field strength of 1.5 T. The solenoid is 1.8 m long and 75 cm in diameter. It is tightly wound with a single layer of 1.50-mm-diameter superconducting wire.
What current is needed?
Answer:
The current needed is 1790.26 A
Explanation:
Given;
magnitude of magnetic field, B = 1.5 T
length of the solenoid, L = 1.8 m
diameter of the solenoid, d = 75 cm = 0.75 m
The magnetic field is given by;
\(B = \frac{\mu_o NI }{L}\)
Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A
I is current in the solenoid
N is the number of turns, calculated as;
\(N = \frac{Length \ of\ solenoid}{diameter \ of \ wire} \\\\N = \frac{1.8}{1.5*10^{-3}} =1200 \ turns\)
The current needed is calculated as;
\(I = \frac{BL}{\mu_o N} \\\\I = \frac{1.5 *1.8}{4\pi *10^{-7} *1200} \\\\I = 1790.26 \ A\)
Therefore, the current needed is 1790.26 A.
Answer:
I = 1790.5 A
Explanation:
The magnetic field due to a solenoid is given by the following formula:
B = μ₀NI/L
where,
B = Magnetic Field Required = 1.5 T
μ₀ = 4π x 10⁻⁷ T/A.m
L = length of Solenoid = 1.8 m
I = Current needed = ?
N = No. of turns = L/diameter of wire = 1.8 m/1.5 x 10⁻³ m = 1200
Therefore,
1.5 T = (4π x 10⁻⁷ T/A.m)(1200)(I)/1.8 m
I = (1.5 T)(1.8 m)/(1200)(4π x 10⁻⁷ T/A.m)
I = 1790.5 A
A candle is placed in front of a concave mirror as it is shown . State the image characteristics (SALT)
As a result, the picture behind the mirror is virtual, upright, and enlarged.
What does SALT in concave mirrors stand for?You will find that the properties of an image (SALT) created in a concave mirror depend on the object's position. A) if the item is larger than C. Size, attitude, and location are all important considerations.
The image will be true, but reversed and much reduced. To obtain a crisp flame image, move the burning candle towards the mirror while moving the screen away from it. The size of the inverted picture grows.
Concave mirrors may create both physical and virtual images. A virtual and enlarged picture is produced when the item gets closer to the mirror. When the item is placed further away from the mirror,.
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What is the moment of inertia of a 4.2-kg uniform cylindrical grinding wheel of radius 32 cm?
The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².
What is the moment of inertia?
This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².
From the question:
Mass,M =4.2kg
Radius, R=32Cm
The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:
moment of inertia, I =1/2MR²
I =\(\frac{1}{2}\) * 4.2 * 32²
=2,150.4 kgm²
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In which circuit would ammeter A shows the greatest current?
In the circuit with two 10Ω resistors in parallel, ammeter A would show the greatest current. This is because, in a parallel circuit, the total resistance is lower than in a series circuit, which means that the current can flow more easily.
In this case, the two 10Ω resistors in parallel create a total resistance of 5Ω (1/Rtotal = 1/10 + 1/10 = 2/10, Rtotal = 10/2 = 5), while in the series circuit,https://brainly.com/question/11409042?referrer=searchResults the total resistance would be 20Ω (10 + 10). Ohm's law states that the current is directly proportional to the voltage and inversely proportional to the resistance, so the circuit with lower resistance will allow for greater current flow.
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--The complete Question is, In which circuit would ammeter A show the greatest current: a circuit with one 6V battery and two 10Ω resistors in parallel or a circuit with one 6V battery and two 10Ω resistors in series? --
Please help me with my homework
The correct equation for the x-axis of object A is F-T = mga, where F is the force acting on object A, T is the tension in the rope, m is the mass of object A, g is the acceleration due to gravity, and a is the acceleration of object A.
From NA - WA = 0, we know that the normal force acting on object A is equal to its weight, NA = WA = mg = 75 kg * 9.81 m/\(s^2\) = 735.75 N.
From Ng - WB = 0, we know that the weight of object B is equal to the weight of the hanging mass, WB = mg = 75 kg * 9.81 m/\(s^2\) = 735.75 N.
The tension in the rope is equal to the weight of the hanging mass, T = WB = 735.75 N.
From F - T = mga, we can solve for the acceleration of object A, a = (F - T) / m = (mA * g - T) / mA = (mA * g - 735.75 N) / mA.
Substituting the given values of mA = 50 kg and g = 9.81 m/\(s^2\), we get a = (50 kg * 9.81 m/\(s^2\) - 735.75 N) / 50 kg = 4.549 m/\(s^2\).
Therefore, the correct equation for the x-axis of object A is F-T = mga = 50 kg * 4.549 m\(s^2\) = 227.45 N.
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Two cars collide head-on and stick together.
Car A, with a mass of 2000 kg, was initially
moving at a velocity of 10 m/s to the east. Car
B, with an unknown mass, was initially at rest.
After the collision, both cars move together at
a velocity of 5 m/s to the west. What is the
mass of Car B?
OF
The mass of Car B is -6000 kg.
To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.
Therefore, we can write the equation for the conservation of momentum as:
(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision
Let's substitute the given values into the equation:
(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)
Simplifying the equation:
20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)
Dividing both sides by -5 m/s:
-4000 kg = 2000 kg + mass of Car B
Subtracting 2000 kg from both sides:
mass of Car B = -4000 kg - 2000 kg
mass of Car B = -6000 kg
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Which two characteristics are needed to describe a force?
A. Speed
B. Resistance
C. Direction
D. Size
Answer:
Direction and Size both are required .
Answer:
C and D I think.
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HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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Give an example of how a bicycle rider would accelerate? Explain the three different ways a bicyclist could
accelerate.
A cyclist can increase the speed of their bike in various ways such as, changing gears, positioning themselves properly, increase the pedalling rate
Ways in which a cyclist can increase the speed of a bicycle
Bicycle riders could accelerate/ increase their speed in various ways
By Changing the gears and by doing so increasing the speedBy Positioning themselves in a streamlined manner, this is so that they become aerodynamic hence they cut across airflow.By increase the rate at which they are pedalling the bicycle.Learn more about increasing bicycle speed here:
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