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yes you the best
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Find the acceleration due to gravity on planet Fergie which has a mass of 6.23 * 10^23 kg and a radius of 5.79* 10^7 m
Answer:
The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
Explanation:
We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.
Now, the acceleration due to gravity is defined through the following equation:
\(mg = GMm/R^2\)
where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.
Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get
g = 0.0123 m/s^2.
Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
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A negative test charge experiences a force to the right as a result of an electric field. Which is the best conclusion to draw based on this description?
The most logical conclusion to make in light of the facts available is that the electric field is directed to the left. This conclusion may be drawn from the fact that a negative test charge, which is attracted to positive charges and repels other negative test charges, feels a force to the right.
The force applied to the negative test charge suggests the presence of positive charges in the electric field, indicating that the field lines begin with positive charges and end on negative charges since opposing charges attract.
The assumption that electric field lines originate from positive charges and end on negative charges is supported by this deduction. As a result, in this situation, the electric field is directed leftward.
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A 25 kg lamp is hanging from a rope. What is the tension force being supplied by the rope?
The tension force being supplied by the rope is 245 N.
What is tension force?Tension force is the force exerted on a rope or cord due to the weight of an object suspended from it.The tension force on the given rope due to the weight of the lamp hanging from the rope is calculated by applying Newton's second law of motion as shown below;
T = mg
where;
m is the mass = 25 kgg is acceleration due to gravity = 9.8 m/s²T = 25 x 9.8
T = 245 N
Thus, the tension force being supplied by the rope is 245 N.
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A pair of glasses is dropped from the top of a 32.0m stadium. A pen is dropped 2.Os later. How high above the ground is the pen when the spectacles hit the ground? Neglect the air resistance.
Answer:
\(h_p = 30.46\ m\)
Explanation:
Free Fall Motion
A free-falling object refers to an object that is falling under the sole influence of gravity. If the object is dropped from a certain height h, it moves downwards until it reaches ground level.
The speed vf of the object when a time t has passed is given by:
\(v_f=g\cdot t\)
Where \(g = 9.8 m/s^2\)
Similarly, the distance y the object has traveled is calculated as follows:
\(\displaystyle y=\frac{g\cdot t^2}{2}\)
If we know the height h from which the object was dropped, we can solve the above equation for t:
\(\displaystyle t=\sqrt{\frac{2\cdot y}{g}}\)
The stadium is h=32 m high. A pair of glasses is dropped from the top and reaches the ground at a time:
\(\displaystyle t_1=\sqrt{\frac{2\cdot 32}{9.8}}=2.56\ sec\)
The pen is dropped 2 seconds after the glasses. When the glasses hit the ground, the pen has been falling for:
\(t_2=2.56 - 2 = 0.56\ sec\)
Therefore, it has traveled down a distance:
\(\displaystyle y=\frac{9.8\cdot 0.56^2}{2} = 1.54\ m\)
Thus, the height of the pen is:
\(h_p = 32 - 1.54\Rightarrow h_p=30.46\ m\)
The pen is 30.52 m above the ground.
Given that the height of the stadium is h = 32m
The initial velocity of the glasses will be 0.
\(h=\frac{1}{2}gt^{2} \\t=\sqrt{\frac{2h}{g} } \\t=\sqrt{\frac{2*32}{9.8} }\\t=2.55s\)is the time taken for the glasses to hit the ground.
Now the pen is released 2 seconds later. So by the time the glasses hit the ground the pen has spent:
\(t^{'}=2.55-2\\t^{'}=0.55s\)in the air
distance traveled by the pen:
\(d=\frac{1}{2}gt^{2}\\\\d=\frac{1}{2}*9.8*0.55*0.55\\\\d=1.48m\)
So the pen is \(h-d=32-1.48=30.52m\) above the ground.
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An electron initially at rest accelerates through a potential difference of 1 V, gaining kinetic energy KEe, whereas a proton, also initially at rest, accelerates through a potential difference of - 1 V, gaining kinetic energy KEp. Which of the following relationships holds?
The electron gains more kinetic energy than the proton when accelerated through a potential difference of 1 V.
The relationship between the kinetic energies of the electron and proton can be determined using the formula for the kinetic energy of a particle:
\(KE = (1/2)mv^2\)
\(V = (q/m)d\)
where V is the potential difference, q is the charge, m is its mass, and d is the distance .
For the electron, \(V = 1 V\)and\(q/m = -1.6 x 10^-19 C/kg\), so its final velocity is:
\(v_e = sqrt((2qV)/m) = sqrt((2*(-1.6 x 10^-19)*1)/9.11 x 10^-31) = 5.93 x 10^6 m/s\)
For the proton, \(V = -1 V and q/m = 1.6 x 10^-19 C/kg,\) so its final velocity is:
\(v_p = sqrt((2qV)/m) = sqrt((2*(1.6 x 10^-19)*(-1))/1.67 x 10^-27) = 7.16 x 10^5 m/s\)
Substituting these values into the formula for kinetic energy, we get:
\(KE_e = (1/2)9.11 x 10^-31(5.93 x 10^6)^2 = 1.63 x 10^-17 J\)\(KE_p = (1/2)1.67 x 10^-27(7.16 x 10^5)^2 = 0.84 x 10^-17 J\)
Therefore, we have:
\(KE_e > KE_p\) , This is because the electron has a much smaller mass than the proton, so it experiences a much larger acceleration and gains more velocity and kinetic energy.
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A car starts from rest at a stop sign. It accelerates at 2.0 m/s2 for 6.2 seconds, coasts for 2.5 s , and then slows down at a rate of 1.5m/s2 for the next stop sign. How far apart are the stop signs
Answer:
the distance between the stop signs is 120.7 m.
Explanation:
The car moved in three stages;
(1) It accelerates from rest at 2.0 m/s² for 6.2 seconds
(2) it moved at a constant speed for 2.5 s
(3) it finally decelerate at the rate of 1.5m/s²
(1) The distance moved by the car during the first stage;
s₁ = ut + ¹/₂at²
s₁ = 0 + ¹/₂ (2)(6.2)²
s₁ = 38.44 m
(2) The distance moved by the car during the second stage;
calculate the constant speed of the car,
v = u + at
v = 0 + 2 x 6.2
v = 12.4 m/s
The distance moved by the car as it coasts for 2.5s: s₂ = vt
s₂ = 12.4 x 2.5
s₂ = 31 m
(3) The distance moved by the car during the third stage;
When the car stops, the final velocity is zero.
v² = u² + 2as₃
a = -1.5 m/s², since the car slowed down or decelerated.
0 = 12.4² + (2 x - 1.5)s₃
0 = 153.76 - 3s₃
3s₃ = 153.76
s₃ = 153.76 / 3
s₃ = 51.253 m
The total distance moved by the car from the start to stop = s₁ + s₂ + s₃
d = 38.44 m + 31 m + 51.253 m
d = 120.7 m
Therefore, the distance between the stop signs is 120.7 m.
Callisto is a moon of Jupiter
(mass= 1.90 x 1027 kg), which orbits
the planet with a period of 16.9 days.
What is the radius of its orbit?
[?] x 10¹ m
Coefficient (green)
Exponent (yellow)
Enter
8.27 x 1013 meres is the orbital radius.
Additional details:-Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution
The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.
6.67 x 10⁻¹¹ N/m²kg
2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7
What distinguishes Callisto, a huge moon orbiting Jupiter, from all other large moons in the solar system?The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.
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Parallel field lines evenly spaced and all pointing left labeled B. There is a point with a vector down labeled v. There is a circle next to the point labeled F. Use the right-hand rule for magnetic force to determine the charge on the moving particle. This is a charge.
By using the right-hand rule for magnetic force to determine the charge on the moving particle, it's a negative charge.
What is magnetic force?It should be noted that the magnetic force simply means the attraction or repulsion that arises between electrically charged particles.
The right-hand rule for magnetic force states that to determine the direction of the magnetic force, one should point the right thumb in the direction of the velocity.
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Answer:
Particle q1 has a charge of 2.7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5.75 × 10–3 N, what is the strength of the magnetic field?
✔ 2.8
T
In the same magnetic field, particle q2 has a charge of 42.0 μC and a velocity of 1.21 × 103 m/s. What is the magnitude of the magnetic force exerted on particle 2?
✔ 0.12
N
Explanation:
Hope this helps
Notice one domain, Eukarya, contains four kingdoms while the other two domains contain one kingdom each. One characteristic do scientists use to place organisms in the Domain Eukarya?
A. These kingdoms contain organisms that are consumers.
B. They are composed on one or more eukaryotic cells.They are composed on one or more eukaryotic cells.
C. They contain cells without major organelles.They contain cells without major organelles.
D. They are multicellular.
The characteristic that scientists use to place organisms in the Domain Eukarya is that they are composed of one or more eukaryotic cells. Therefore, the answer is B
What characteristic do scientists use to place organisms in the Domain Eukarya?
To understand why eukaryotic cells are such an important characteristic of the Domain Eukarya, it's helpful to know a bit about the other two domains of life: Bacteria and Archaea.
Bacteria and Archaea are both composed of prokaryotic cells, which are cells that lack a nucleus and other membrane-bound organelles. In prokaryotic cells, the genetic material is typically found in a single circular chromosome that floats freely in the cytoplasm. Prokaryotes also lack other specialized structures like mitochondria and chloroplasts, which are found in eukaryotic cells.
This means that organisms in this domain have a true nucleus and other membrane-bound organelles within their cells. The four kingdoms within Eukarya are Animalia, Plantae, Fungi, and Protista, which are all composed of eukaryotic cells.
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An elevator suspended by a vertical cable is moving downward at a constant speed. The tension in the cable must be A) greater than the weight of the elevator. B) less than the weight of the elevator. C) equal to the weight of the elevator.
Answer:
(C) because the elevator is not accelerating
Note F = M a = M g (the resultant force on the elevator is due to gravity)
or Fup = Fc the force exerted on the elevator by the cable
and Fdown = Fe the force exerted on the elevator by gravity
F = M a = Fup - Fdown = zero resultant force on elevator
study 60cm ady the water the diagram Pressure at A, B and C. C B 30cm A ram and calculate the liquid pressure
To calculate the liquid pressure at points A, B, and C in the given diagram, we need to consider the height and density of the liquid.
Let's assume that the liquid in the container is water, which has a density of approximately 1000 kg/m³.
Given:
- Height of column AB = 60 cm = 0.6 m
- Height of column BC = 30 cm = 0.3 m
To calculate the pressure at each point, we can use the formula:
Pressure = density * gravity * height
where:
- Density = 1000 kg/m³ (density of water)
- Gravity = 9.8 m/s² (acceleration due to gravity)
Calculating the pressures:
At point A:
Pressure_A = density * gravity * height_AB
= 1000 kg/m³ * 9.8 m/s² * 0.6 m
= 5880 Pascal (Pa)
At point B:
Pressure_B = density * gravity * (height_AB + height_BC)
= 1000 kg/m³ * 9.8 m/s² * (0.6 m + 0.3 m)
= 8820 Pascal (Pa)
At point C:
Pressure_C = density * gravity * height_BC
= 1000 kg/m³ * 9.8 m/s² * 0.3 m
= 2940 Pascal (Pa)
Therefore, the liquid pressures at points A, B, and C are as follows:
- Pressure at point A = 5880 Pa
- Pressure at point B = 8820 Pa
- Pressure at point C = 2940 Pa
differences between static friction and dynamic friction
Answer:
Static friction acts on stationary objects while kinetic friction acts on those in motion. Static friction is always greater or equal to kinetic friction. This can explain why objects often take more force to get in motion than it takes to continue their motion.
A kangaroo is capable of jumping to a height of 2. 62 m.
George burnt his fingertips so badly that he can't feel anything with them anymore.
Which part of his skin must have been damaged?
O papillary layer
Hypodermis
hyperdemis
subcutaneous layer
George burnt his fingertips so badly that he can't feel anything with them anymore, then the papillary layer part of his skin must have been damaged, therefore the correct answer is option A.
What is thermal energy?It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.
As given in the problem George burnt his fingertips so badly that he can't feel anything with them anymore.
Option A is the appropriate response since George must have injured the papillary layer of his skin if his fingertips were burned so badly that he can no longer feel anything with them.
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consider a man of mass 80kg standing 10m from a woman with a mass of 65 kg the attractive gravitational force between them would be ?
please I need a fast verified answer
3.17 x 10^-8 Newtons is the required gravitational force between them.
Determining the gravitational force between objectsThe gravitational force between two objects is given by the formula:
F = G * (m1 * m2) / r^2
where F is the gravitational force, G is the gravitational constant (6.6743 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between the centers of mass of the two objects.
In this case, the masses of the man and the woman are:
m1 = 80 kg
m2 = 65 kg
The distance between them is:
r = 10 m
Plugging these values into the formula, we get:
F = 6.6743 x 10^-11 * (80 kg * 65 kg) / (10 m)^2
F = 3.17 x 10^-8 Newtons
Therefore, the attractive gravitational force between the man and the woman is approximately 3.17 x 10^-8 Newtons.
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The moral quality of the will that voted the nation dry had its origin in a moral and social source. It
was an honest desire to protect human life. This wish made concrete and appealing through the lives
of women and children…As the race has evolved, womanhood and childhood have come to occupy
more commanding positions. Today in the United States the moral sense of the people puts them
first. What is good for them should become a law. So the voters were led to believe and so they
acted. Men and women merely said, The liquor business is a menace to our women and children.
Let us get rid of it...".…Salvation Army leaders, social workers, district nurses, Prohibition officers,
child welfare organizations, and others who are in close observance of social conditions have
repeatedly declared that no other law has worked so great a revolution in social welfare as has
Prohibition... Nearly one hundred million dollars of funds once spent to cure the harm done by the
saloon is now expended in fresh air work, free dental clinics, prematurity care, district nursing.
hospitalization, and other forms of work.…
Summarize the main idea
A moral and social wellspring was the source of the moral quality of the vote that dried up the country.Protecting human life was a sincere desire.The lives of women and children gave this wish a tangible and compelling form.
What lessons can be learned from Prohibition?A moral and social wellspring was the source of the moral quality of the vote that dried up the country.Protecting human life was a sincere desire.The lives of women and children gave this wish a tangible and compelling form.Six Things About Prohibition We Can Learn.Prohibition Depends on Interest Groups.People who would not otherwise commit crimes are made criminals by prohibition.As a result of prohibition, criminals have access to markets.Prohibition diverts resources from law enforcement and raises the risks of already dangerous activities.For the purpose of preventing the "scourge of intoxication," Prohibition was put into place.However, it had unforeseen effects, such as an increase in organized crime linked to the illicit manufacturing and sale of alcohol, a rise in smuggling, and a decrease in tax revenue.To learn more about Prohibition refer
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What is the main difference between the gravitational potential energy is elasctic potential energy
Answer:
• Gravitational potential energy is always negative while the elastic potential energy is always positive.
• Gravitational potential energy depends on the mass of the object, but elastic potential energy does not depend on the mass.
g Vector has a magnitude of 10.9 units and points due west. Vector points due north. (a) What is the magnitude of if + has a magnitude of 15.7 units? (b) What is the direction of + relative to due west? (c) what is the magnitude of if - has a magnitude of 15.7 units? (d) What is the direction of - relative to due west?
Answer:
a. 11.3 units
b. 46.031°
c. 11.3 units
d. 46.03°
Explanation:
a. magnitude
B = \(\sqrt{R^{2}-A^{2} }\)
= √15.7² - 10.9²
= √127.68
= 11.3 units
b. direction
θ = cos⁻¹(10.9units/15.7 units)
= 46.031⁰ north of west
c. thge magnitude at 15.7 units is the same as solution a above
15.7² = 10.9² + B²
B = 11.3 units.
d. the direction is same as answer b.
θ = 46.031°
but the vector faces south of west
Write the differences between rest and motion
Answer:
Depends on position
Explanation:
Rest:
A body is said to be at rest, if it does not change its position with respect to its surroundings.
Motion:
A body is said to be in motion, if it changes its position with respect to its surroundings.
The state of rest and motion is relative
What does the double arrow in the diagram below label?
( click photo)
B. The wavelength of the wave
The speeds of a 600-kg roller coaster car at the top of three consecutive hills are shown below. The radii of the hills are shown. Determine the acceleration, net force, and normal force experienced by the car at the top of each hill.
Answer:
they will fly
Explanation:
yes flying is fun
The acceleration, net force, and normal force by the car at the top of hill A are 4.5 meter/second² , 3180 N and 3180 N.
The acceleration, net force, and normal force by the car at the top of hill B are 4.17 meter/second² , 3379N and 3379 N.
The acceleration, net force, and normal force by the car at the top of hill C are 4.0 meter/second² , 3480 N and 3480 N.
What is centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.
On hill A;
The centripetal acceleration = v²/r = 6²/8 meter/second² = 4.5 meter/second² .
The net force = m(g -a) = 600 (9.8 - 4.5) N = 3180 N.
The normal force = 3180 N
On hill B;
The centripetal acceleration = v²/r = 5²/6 meter/second² = 4.17 meter/second² .
The net force = m(g -a) = 600 (9.8 - 4.17) N = 3379 N.
The normal force = 3379 N.
On hill A;
The centripetal acceleration = v²/r = 4²/4 meter/second² = 4.0 meter/second² .
The net force = m(g -a) = 600 (9.8 - 4.0) N = 3480 N.
The normal force = 3480 N.
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An upright spring with a 96g mass on it is compressed 2 cm. When
released it travels 60 cm upwards. A) Calculate the spring constant. B)
Calculate its beginning speed when it takes off.
Answer:
I only know answer A and it's 2825.28 N/m, with rounding it's 2825.5
Explanation:
Use the m*g*h=1/2*k*x^2 equation
96*9.81*60=1/2*k*2^2
5650.56=2k
5650.56/2=2825.28N/m
6th grade measuring wavelengths!
PLEASE HELP!
Wavelength of the given wave is 8 cm and frequency is 37.5 *\(10^{8}\) Hz.
What is frequency?The number of vibrations counted per second is called frequency. A wave is a group of vibrations that are referred to as energy. The bottom node is known as the crest, and the top node is known as the trough.
The frequency of an alternating current is the number of full cycles per second. The hertz, also known as Hz, is the accepted unit of frequency. The frequency of a current is 1 Hz if one cycle is completed per second; 60 cycles per second equals 60 Hz.
There are 8 waves so assume one wave is 1 cm so wavelength is 8 cm and frequency of wave = speed of light/ wavelength
frequency = \(3*10 ^{8} / .08\)
Frequency = 37.5 *\(10^{8}\) Hz
Wavelength of the given wave is 8 cm and frequency is 37.5 *\(10^{8}\) Hz.
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Which is an SI base unit that makes up part of the unit of energy?
candela
ampere
kelvin
kilogram
The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D
What is a unit of measurement?A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.
The base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole
The unit of energy is Joules which is equivalent in mks unit as Kg m²s⁻²
Thus, The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D
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The table shows columns that Franklin uses to organize his notes on the properties of elements. His notes state that some elements are widely used in semiconductors.
A 3-column table with 2 rows. The first row has entries metals, metalloids, nonmetals. The second row has entries nothing, nothing, nothing.
Where should Franklin place this property in his table?
only in the column for metalloids
only in the column for nonmetals
in the columns for metalloids and for nonmetals
in the columns for metals and for metalloids
Answer:
only in the column for metalloids
Explanation:
Did it on edge!
Franklin should place this property only in the column for metalloids, therefore the correct answer is option A.
What are metalloids?The elements of the periodic tables that behave as metal, as well as the nonmetal in some chemical or physical aspects, are known as metalloids. Some examples of metalloids are Boron, silicon, germanium, arsenic, antimony, tellurium, etc.
Generally, metalloids have an intermediate position in the periodic table which is in between metals and nonmetals.
As given in the problem The table shows columns that Franklin uses to organize his notes on the properties of elements. His notes state that some elements are widely used in semiconductors, A 3-column table with 2 rows. The first row has entries as metals, metalloids, and nonmetals. The second row has entries nothing, nothing, nothing.
As metalloids are widely used as semiconductors across several electronic and electrical applications.
Thus, Franklin should only list this characteristic under metalloids, therefore the correct answer is option A.
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An independent-measures t hypothesis test is appropriate when ____.
a. the mean for a treated group of subjects is compared to a known population mean
b. one sample is used to test a hypothesis about one population
c. the value for s is known
d. there are two separate samples containing different subjects
An independent-measures t hypothesis test is appropriate when - d. there are two separate samples containing different subjects.
When you wish to compare the means of just two groups—no more, no less—use an independent samples t test! This test is typically used to detect whether two population means differ. This process employs samples to infer information about populations, making it an inferential statistical hypothesis test. The two sample t test is another name for the independent samples t test. You can reject the null hypothesis if the p-value is less than your threshold for significance (for example, 0.05). The two means difference is statistically significant. The data from your sample is convincing enough to support the conclusion that the two-population means are not equal.
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plzzzzzzzzzzzzzzzzzzzzzzzzzz help 20 points
Answer:
1.23
Explanation:
\({\underline{\pink{\textsf{\textbf{ Answer : }}}}}\)
➩ 1.23 feet
\({\underline{\purple{\textsf{\textbf{Explanation : }}}}}\)
Given :
Simon cuts a pipe that was 4.92 feet long Then he cuts it into four equal pieces.To find :
What is the length of the each piece.Solution :
As it is told that it's divided into four equal pieces
Therefore,
We must divide it by 4 to get the length of each piece.
So,
\( \sf \to \: \frac{4.92}{4} \\ \sf \to \: 1.23 \: feet \: ans.\)
A woman stands on a moving sidewalk (conveyor belt) that is moving to the right at a speed of 2 m/s relative to the ground. A dog runs on the belt toward the woman at a speed of 8 m/s relative to the belt. A conveyor belt is moving to the right at the speed v subscript belt, ground equals 2 meters per second. A girl stands stationary on the left end of the belt. A dog runs on the belt to the left toward the girl at the speed v subscript dog, belt equals 8 meters per second. What is the speed of the dog relative to the ground
Answer:
V_{2G} = - 10 m / s
Explanation:
This is an exercise on relative velocities in one dimension, let's use the subscript 1 for the girl, the 2 for the but, the index 3 for the conveyor belt and the index G for the Earth
we will consider the velocity is positive to the right.
They indicate the speed of the belt with respect to the ground = 2 m/s
the dog speed with respect to the belt = - 8 m / s
Dog speed is requested with respect to the Earth
\(V_{2G} = V_{23} - V_{3G}\)
notice that the inner subscripts cancel out.
We calculate
= -8 - 2
V_{2G} = - 10 m / s
the negative sign indicates that the dog moves to the left
Explain how we could test for the accuracy of the period you calculated (and don't mean by using a calculator). How could you experimentally find it?
Answer:
Here are the steps to perform the experiment:
1. Set up a pendulum by suspending a weight from a fixed point using a string or a rod. Ensure that the length of the string or the rod is constant.
2. Displace the weight by a small angle and release it to allow it to oscillate back and forth.
3. Use a stopwatch or a timer to measure the time it takes for the pendulum to complete one full oscillation (i.e., from one extreme position to the other and back to the original position).
4. Repeat the measurement several times to get an average value for the time period.
5. Compare the measured time period to the calculated value using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
If the measured value is close to the calculated value, then the calculated period can be considered accurate. However, if the measured value is significantly different from the calculated value, then the calculated period may need to be revised or further experiments may need to be performed to determine the source of the error.
It is important to note that experimental errors such as human error in measuring the time or the length of the pendulum can affect the accuracy of the measurement. Therefore, it is recommended to repeat the experiment several times to minimize these errors and obtain a more accurate value.
A train travels 8.81 m/s in a -51.0° direction.
The train accelerates for 2.23 s, changing its
velocity to 9.66 m/s in a 37.0° direction.
What is [delta]x?
The displacement of the train after 2.23 seconds is 25.4 m.
Resultant velocity of the trainThe resultant velocity of the train is calculated as follows;
R² = vi² + vf² - 2vivf cos(θ)
where;
θ is the angle between the velocity = (90 - 51) + 37 = 76⁰R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)
R² = 129.75
R = √129.75
R = 11.39 m/s
Displacement of the trainThe displacement of the train is the change in position of the train after a given period of time.
The displacement is calculated as follows;
Δx = vt
Δx = 11.39 m/s x 2.23 s
Δx = 25.4 m
Thus, the displacement of the train after 2.23 seconds is 25.4 m.
Learn more about displacement here: brainly.com/question/2109763
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