1. Which statement is true about Mendeleev's periodic table?

A.)It was not useful
B.)it was based on atomic number
C.)It contained 18 families
D.)None of the above

When compared to winds at the surface, winds at 2,000 feet are typically higher due to the absence of friction.

At the surface, winds are affected by friction with the Earth's surface, which slows them down and causes them to move in a more turbulent and erratic fashion. However, as winds move up in altitude, they encounter less and less friction, allowing them to increase in speed and flow in a more uniform and predictable manner.
While friction may still have some influence on winds at 2,000 feet, it is not as significant as at the surface. Therefore, winds at this altitude tend to move more smoothly and follow a more consistent path, often perpendicular to the isobars (lines of equal pressure) on a weather map. This makes them useful for aviation purposes, as pilots can use this information to plan their flight paths and take advantage of favorable tailwinds or avoid dangerous crosswinds.
In contrast, winds at the surface are more affected by local topography, temperature gradients, and other factors that can cause them to vary widely in direction and speed. Overall, winds at 2,000 feet are an important component of the Earth's atmospheric circulation system, and understanding their behavior is essential for predicting weather patterns and ensuring safe air travel.

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Answer:

answer c: a mass and volume

Explanation:

no matter what elements are chosen, they all have a mass and volume measurement I believe

(a) The velocity of the object at time t is given by finding the derivative of y (t):

y(t) = -2t2 + t + 10dy(t)/dt

= -4t + 1

Therefore, the velocity of the object at time t is -4t + 1.

(b) The acceleration of the object at time t is given by finding the derivative of the velocity function:

dy(t)/dt = -4t + 1d2y(t)/dt2

= -4

Therefore, the acceleration of the object at time t is -4 m/s2.

(c) The ball hits the ground when y(t) = 0, so we can solve for t by setting -2t2 + t + 10 = 0 and using the quadratic formula:

t = (-b ±  (b2 - 4ac)) / (2a), where a = -2, b = 1, and c = 10.

Plugging these values into the formula, we get:

t = (-1 ±  (12 - 4(-2)(10))) / (2(-2)) = (1 ±  81) / 4

We take the negative root because the positive root corresponds to the ball reaching its maximum height before falling back down. Thus,

t = (1 - 81) / 4

= -2/4

= -0.5 s

To find the velocity of the ball at this time, we plug t = -0.5 into the velocity function we found in part

(a):v = -4t + 1

= -4(-0.5) + 1

= 3 m/s

Therefore, the velocity of the ball at the time it hits the ground is 3 m/s.

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Answer:

electricity because it has more percentage nd energy

Explanation:

mark me brainliest pl

(a) The S-wave velocity can be calculated using the following formula:

Vs = sqrt(μ/ρ)

where:

Vs is the S-wave velocity in m/s

μ is the shear modulus in Pa

ρ is the density of the rocks in kg/m3

Plugging in the values, we get:

Vs = sqrt(3 x 10^10 Pa / 3000 kg/m3) = 4.0 km/s

Therefore, the S-wave velocity is 4.0 km/s.

The distance to the earthquake can be calculated using the following formula:

d = Vs * t

where:

d is the distance to the earthquake in km

Vs is the S-wave velocity in m/s

t is the time it took for the S-wave to travel from the earthquake to the seismograph in seconds

Plugging in the values, we get:

d = 4.0 km/s * 20 seconds = 80 km

Therefore, the earthquake is 80 km away from the seismograph.

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Answer:

D. muscular strength

Explanation:

Lifting any weight requires force to lift it. This force is the result of the muscular strength of the body. It is the muscular strength that determines the weight that a body can lift without any exhaustion. Muscular strength depends on the size of the muscular fibers and the nerves' ability. They help in activating the strength of the muscle. Lifting the objects and the ability to lift it are the outcome of the strength muscles have.

In the given situation, Dawn is trying to find her muscular strength.

Answer:

d

Explanation:

d

The distance to the bending mark when fabricating a 90°-bend is equal to the stub-up minus the take-up. Therefore, the correct answer is option b.

When bending a conduit or pipe to create a 90° angle, the bending mark represents the point at which the bend starts. The stub-up is the length of the conduit that extends vertically from the bottom of the bend to the end of the conduit. The take-up is a measurement that accounts for the additional length of the conduit that is consumed during the bending process.

To find the distance to the bending mark, you need to subtract the take-up from the desired stub-up length. This will give you the correct position to mark on the conduit before starting the bending process. Following this guideline will help ensure that your 90°-bend will be accurate and meet the required specifications.

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When a block slides at constant speed down a ramp while acted on by the forces.

A. True

B. False

C. False

The magnitude of dynamic friction is directly proportional to the magnitude of the normal force and the roughness between the sliding surfaces. The magnitude of static friction is directly proportional to the magnitude of the normal force and the roughness between the sliding surfaces. The normal force is not necessarily equal to gravity, but the force perpendicular to the surface on which the object is sliding.

In other words, the normal force is the force that pushes two surfaces together, and the stronger the normal force the stronger the frictional force. Another fairly common force is the frictional force. Similar to the normal force, it is caused by direct contact between surfaces. However, normal forces are always perpendicular to the surface while frictional forces are always parallel to the surface.

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In conclusion, discrete numerical modeling of loose soil with spherical particles and interparticle rolling friction involves representing particles as discrete entities and simulating their interactions using mathematical equations. This approach allows us to study the behavior of loose soil and gain insights into its properties and response under different conditions.

Discrete numerical modeling is a technique used to simulate the behavior of loose soil with spherical particles and interparticle rolling friction. In this approach, the soil is represented by discrete particles, and their interactions are modeled using mathematical equations.
To simulate the behavior of loose soil, the following steps are typically involved:
1. Particle representation: Each particle in the soil is represented as a discrete entity with its own properties, such as size, shape, and material properties.
2. Interaction modeling: The interactions between particles are modeled based on physical principles, such as interparticle rolling friction. These interactions affect the movement and behavior of the particles.
3. Numerical simulation: Mathematical equations are used to simulate the motion of particles over time. These equations consider various factors, such as gravitational forces, interparticle friction, and contact forces between particles.
4. Solution calculation: The equations are solved numerically to obtain the positions and velocities of the particles at each time step.
5. Analysis and conclusion: The simulation results are analyzed to gain insights into the behavior of loose soil. This analysis can include studying the particle arrangements, deformation patterns, and other properties of the soil under different conditions.
In conclusion, discrete numerical modeling of loose soil with spherical particles and interparticle rolling friction involves representing particles as discrete entities and simulating their interactions using mathematical equations. This approach allows us to study the behavior of loose soil and gain insights into its properties and response under different conditions.

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I believe a scale is good

Answer:

(B) Cu

Explanation:

An atom can be defined as the smallest unit comprising of matter that forms all chemical elements. Thus, atoms are basically the building blocks of matters and as such determines or defines the structure of a chemical element.

Generally, atoms are typically made up of three distinct particles and these are protons, neutrons and electrons.

Isotopes can be defined as the atom of an element that has the same number of protons but different number of neutrons. This ultimately implies that, the isotopes of an element have the same atomic number (number of protons) but different atomic mass (number of nucleons).

The isotope of an element is denoted by \( X_{Z}^{A} \)

Where; X is the symbol of the element.

A is the atomic mass or number of nucleons.

Z is the atomic number or number of protons.

Hence, an atom with 29 protons and 36 neutrons is an isotope of copper because it has an atomic mass of 65, which corresponds with that of the chemical element known as copper with the symbol, Cu.

The ratio of the mass density of girder a to the mass density of girder b is 1/2.

The quantity of substance a given thing contains is referred to as its mass. Density refers to how closely together atoms are packed in a substance, or how close together they are. The quantity of inertia is measured in mass. In contrast, compactness is measured by density.

Mass and volume are intimately correlated with density. In reality, it explains the precise nature of the connection between the two. By dividing the mass of an item by its volume, we may get its density. The mass is considered to be of low density if it has a high volume but a tiny mass.

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Answer:

All the options (a, b, c, and d) are correct situations for negative value of acceleration due to gravity.

Explanation:

Acceleration due to gravity is always acted towards the center of the earth. It's magnitude is \(9.8\rm{m/s^{2}}\).

As per the sign convention, downward direction is considered as negative.

Now, consider the cases:

1. When an object or ball is thrown upward: While moving upwards, gravity or gravitational acceleration opposes the motion of object. The object speed or displacement will be positive while gravity will be negative.

2. When an object is at the top or highest point of their path: When the object is at the top of its path, the gravity still acts downwards and the velocity becomes zero. So, gravity will be negative at this position.

3. When object is falling downward: While falling downwards, the acceleration and velocity will be negative as they both are directed downwards.

From the above points, the value of gravity will always be negative.

Therefore, in all the given options (a, b, c, and d), the acceleration will be \(-9.8\rm{m/s^{2}}\).

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Two Positive and Negative points involving the usage of nuclear energy are:

Positive Points:

1) Large Source of Clean Power.

2) It creates jobs in various nuclear sectors.

Negative Points:

1) Fuel Usage, Large Area under Construction, and Waste Disposal.

2) Operating Nuclear industries is Costly.

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The correct answer is option (A). The fact that a thermometer "takes its own temperature" illustrates the concept of thermal equilibrium.

Thermal equilibrium refers to a state where two objects or systems are at the same temperature and there is no net transfer of heat between them. In this case, the thermometer, being in thermal contact with its surroundings, eventually reaches a state of equilibrium where it shares the same temperature as its environment. Once thermal equilibrium is reached, the thermometer accurately reflects the temperature of its surroundings, effectively "taking its own temperature."

The concept of thermal equilibrium highlights the idea that heat transfer occurs until a balanced state is achieved. It is a manifestation of energy conservation because, in the process, energy is conserved. Heat refers to the transfer of thermal energy between objects, while internal energy represents the total energy stored within a substance, including both its kinetic and potential energies.

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b. False. When two identical sound levels are combined, the overall level increases by only 3 dB, not 10 dB. This is due to the logarithmic nature of the decibel scale.

Two identical sound level will not increase the overall level by 10 dB. In reality, the increase in the overall sound level is only 3 dB. This is because sound levels are measured on a logarithmic scale. This means that the actual increase in sound pressure is not linear and a doubling of the sound pressure level only produces an increase of 3 dB.This means that the increase in overall sound level is much less than might be expected from a simple additive process, and is usually 3 dB or less.

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The average density of the Sun is most similar to that of Jupiter.

The average density of an object is determined by its mass and volume. Jupiter, being a gas giant, has a relatively low density due to its large volume and comparatively lower mass. Similarly, the Sun, being a massive ball of hot plasma, has a relatively low average density despite its immense size and mass. This is because the Sun's mass is spread out over its large volume, resulting in a lower density. On the other hand, objects like Halley's Comet's nucleus, Earth, Mercury, and the Moon have higher densities as they are smaller and have more compact compositions. Therefore, in terms of average density, the Sun is most similar to Jupiter.

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Answer:

This process is CONDENSATION

Explanation:

Condensation occurs when water vapour loses some of its kinetic energy to a colder body and changes into liquid state.

We are given that an object falls with an acceleration of -6 miles/h/s. To determine the initial velocity we will use the following motion:

Where:

Now, we solve for the initial velocity by subtracting "at" from both sides:

Now, we plug in the values:

Now, we solve the operations:

Therefore, the initial velocity is 50 mi/h.

9) A vector describe as a quantity that has both magnitude and direction. 10) We use vectors to describe in physics in physical quantities, including displacement, velocity, acceleration, force, momentum, and torque.

The vector is typically represented by an arrow, with the length of the arrow representing the magnitude of the vector and the direction of the arrow representing the direction of the vector. In addition to the magnitude and direction, vectors also have a starting point and an end point. Vectors can be added together to obtain a resultant vector that represents the sum of the individual vectors. Vectors can also be subtracted, multiplied by a scalar, or divided by a scalar.

For example, displacement is a vector that describes the distance and direction between two points. Velocity is a vector that describes the speed and direction of motion and acceleration is a vector that describes the rate at which velocity changes. Force is a vector that describes the push or pull on an object and momentum is a vector that describes the motion of an object and its resistance to change. Torque is a vector that describes the rotational motion of an object. So therefore vectors are an important tool for physicists because they allow them to describe physical quantities in a way that is both concise and precise.

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C. If a car has a westward acceleration, the car moving east and slowing down.

Westward acceleration is the acceleration of an object directed towards the west of the object's motion.

The acceleration of an object is defined as the change in the velocity of an object with time.

Mathematically, the acceleration of an object is given as;

a = Δv/Δt

where;

a = (v - u) /t

where;

When the car is slowing down, it implies that the final velocity is smaller compared to the initial velocity.

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According to question, The speed of sound in air is 342.85 m/s.

the speed at which an object's location changes in any direction. The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.Speed tells us how fast something or someone is travelling.

the solution is -

distance d = 2.4 km = 2400 m , time t = 7s

speed of sound = distance/time

speed of sound = 2400/7

speed of sound = 342.85 m/s

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True, financial information that is immaterial in amount or nature need not be reported in accordance with GAAP.

According to Generally Accepted Accounting Principles (GAAP), financial information that is immaterial in amount or nature does not need to be reported. Materiality is a concept used in accounting to determine the significance or importance of financial information.

If an item is considered immaterial, it means that its inclusion or exclusion from financial statements would not have a significant impact on the decision-making of users of those statements. In such cases, GAAP allows for the omission of immaterial information.

However, it is important to note that the determination of materiality is subjective and depends on the specific circumstances and professional judgment of accountants. Additionally, even if an item is deemed immaterial, it is still good practice to provide adequate disclosure and transparency to users of financial statements.

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Harry's weight is 1200 N on earth, then Harry's weight on the planet Dreidel is 355 N.

The force of gravity or the weight of an object on a planet is affected by the gravitational acceleration on that planet.

R\(__e\) = R

R\(__p\) = 2R

ρ\(__p\) = 1/3 ρ\(__e\)

w\(__e\)  = 1200 N

Determine the ratio of the mass of the earth to the mass of the planet through the relationship:

ρ = m/V → m = ρV

So:

\(\frac{me}{mp} = \frac{ p_e V_e}{p_pV_p}\)    (1)

Where is the volume of the planet. If both the earth and the planet are considered a ball, then it has the shape:

V = 4/3πR³

So, if we substitute the form above into the equation, we will get:

\(\frac{me}{mp} = \frac{p_eR_e^3}{p_pR_p^3} \\\\\frac{me}{mp} = \frac{p_eR_e^3}{1/3p_p(2R)^3}\\\\\frac{me}{mp} = \frac{3}{8}\) (2)

The weight of an object is expressed as:

\(w =G\frac{mM}{r^2}\)

If we take the comparison of the object's weight when it is on the earth's surface from the planet's surface it meets the:

\(\frac{w_e}{w_p} = \frac{me}{mp} (\frac{R_p +R}{R_e} )^2\\\\\frac{1200}{w_p} = \frac{3}{8} (\frac{2R +R}{R} )^2\\\\\frac{1200}{w_p} = \frac{3}{8} (\frac{9}{1} )^2\\\\w_p= \frac{1200 (8)}{3 (9)} \\\\w_p= \frac{9600}{27} = 355 N\)

Hence Harry's weight on the new planet is 355 N.

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We should position the metre scale along the item such that the zero mark of the metre scale aligns with one end of the object if we want to measure an object's length using metres. The length of the object will then be revealed by the reading on the scale's opposite end.

A foot or so distant or close enough to read a ruler, stand in front of a mirror. The 0 on a plastic ruler should be positioned in the centre of your pupil when you hold it vertically against the frame. The bottom edge of the lens, not the frame's edge, should be measured from the middle of your pupil. Keep track of each eye's height.

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