100 ml. of a 0.2 m kcl solution is added to 500 ml. of water. what is the concentration of the resulting solution?
Answers
A 100 mL of 0.2 M KCl solution is added to 500 mL of water, and the concentration of the resulting solution is 0.04 M KCl. We must calculate the concentration of the resulting solution that contains a 100 mL of 0.2 M KCl and 500 mL of water.
We may start by calculating the number of moles of KCl in 100 mL of 0.2 M KCl solution:$$\text{No. of moles of KCl}=\text{Molarity}\times\text{Volume (in L)}$$Molarity = 0.2 MVolume (in L) = 100/1000 L (1 L = 1000 mL)No. of moles of KCl = 0.2 x 100/1000 = 0.02 molesWe now have to calculate the number of moles of KCl in the final solution.
As a result, we'll use the formula:$$\text{Molarity}=\frac{\text{No. of moles of solute}}{\text{Volume of solution}}$$No. of moles of solute = 0.02 molVolume of solution = 500 + 100 = 600 mL= 0.6 L$\text{Molarity}=\frac{\text{No. of moles of solute}}{\text{Volume of solution}}$$\text{Molarity}=\frac{0.02 \text{mol}}{0.6 \text{L}}=0.04 \text{M}$$Therefore, the concentration of the resulting solution is 0.04 M KCl.
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The concentration of the resulting solution is 0.0333 M.
Explanation:To find the concentration of the resulting solution, we can use the formula:
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
In this case, the initial concentration is 0.2 M, the initial volume is 100 ml, and the final volume is the sum of the initial volume and the volume of water, which is 100 ml + 500 ml = 600 ml.
Now we can plug in the values into the formula and solve for C2:
C1V1 = C2V2
(0.2 M)(100 ml) = C2(600 ml)
20 = C2(600)
C2 = 20/600
C2 = 0.0333 M
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Related Questions
Compare the compressibility of solids and liquids. Support your answer by describing the arrangement of particles in solids and liquids.(Does,t need to be very long or detailed)
Answers
Liquids are more compressible than solids.
In liquids there is space between the molecules, not a lot, but there is enough space to offer some compressibility. Solids are arranged in regular patterns and their molecules are almost fixed close together.
what is the coordination number around the central metal atom in ammonium diaquabis(oxalato)nickelate(ii) ((nh₄)₂[ni(c₂o₄)₂(h₂o)₂])?
Answers
The coordination number around the central metal atom in ammonium diaquabis(oxalato)nickelate(II) is 6.
In the given compound, ammonium diaquabis(oxalato)nickelate(II), the nickel (Ni) ion is the central metal atom. The coordination number refers to the number of ligands (atoms or molecules) that are directly bonded to the central metal atom. In this case, there are two oxalate ligands (C₂O₄²⁻) and two water ligands (H₂O) bonded to the nickel ion, resulting in a coordination number of 6.
Each oxalate ligand contributes two oxygen atoms, and each water ligand contributes one oxygen atom, giving a total of six ligands surrounding the central nickel atom.
Therefore, in the compound ammonium diaquabis(oxalato)nickelate(II), the central metal atom has a coordination number of 6.
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Fossils can be body parts of ancient organisms, or they can be traces. Give five examples of traces. Help this is due today!!!!!7 grade
Answers
Burrows, tracks, coprolites, nests and footprints are examples of traces that can be found in a fossil.
Four scientist collected data on the blood pressure of 30 people. Which scientist most likely had a problem with the experimental design?
Answers
Answer:
Scientist 3
Explanation:
Which of the following is NOT an assumption of kinetic molecular theory?
A. The size of gaseous particles is negligible compared to the average distance between them.
B. Gas particles collide with one another and with the walls of their container in an elastic manner.
C. The motion of gas particles is characterized by random, spiraling movements along an arbitrary axis.
D. There is a negligible amount of intermolecular force of attraction existing between the particles of the gas.
Answers
Examine a centers for disease control (cdc) advertising campaign that promotes the influenza (flu) vaccination.
Answers
The disease control (CDC) advertising campaign promoting influenza (flu) vaccination aims to increase the uptake of the seasonal influenza vaccination in risk groups.
CDC typically promotes influenza (flu) vaccination through various means such as television and radio advertisements, social media campaigns, brochures, and posters. These campaigns often stress on the importance of getting vaccinated to protect oneself and others from the flu, the effectiveness and safety of the flu vaccine, and the availability of the vaccine at various locations such as doctors' offices, clinics, and pharmacies.
Some campaigns also target specific groups such as children, pregnant women, and older adults who are at higher risk of complications from the flu.
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10. Write the word equation of the following skeleton equation.
CuCl(aq) + NaOH(aq) → Cu(OH),(s) + NaCl(aq)
Indicate the state of each substance in your word equation.
Someone help me out please
Answers
Answer:
See below.
Explanation:
Aqueous copper chloride reacts with sodium hydroxide aqueous solution to give a precipitate (solid) of copper hydroxide and aqueous sodium chloride.
how many unpaired electrons are there in the following complex?[cr(h2o)6]2 (high spin)group of answer choices541230
Answers
The electrons are first placed in the higher energy level orbitals before pairing up. The chromium ion (Cr2+) has a d4 configuration with six water (H2O) ligands.
Since there are four unpaired electrons in the t2g orbitals, the complex has a magnetic moment of 4.9 BM (Bohr magnetons) which indicates that it is paramagnetic. Therefore, the main answer is 4 unpaired electrons.
1. Determine the oxidation state of Cr in the complex.
2. Determine the electron configuration of Cr in that oxidation state.
3. Count the number of unpaired electrons.
Step 1: Oxidation state of Cr
[Cr(H2O)6]2+ has a charge of +2, so the oxidation state of Cr is +2.
Step 2: Electron configuration of Cr
Cr has an atomic number of 24, so its electron configuration is [Ar]3d5 4s1. In the +2 oxidation state, it loses two electrons, leaving [Ar]3d4.
Step 3: Count unpaired electrons
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3) Which element is the 2s orbital closest to the nucleus?
A) Te
B) Se
C) O
D) Po
E)S
Answers
The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.
C6H12O6(aq) + 6 O2(g) → 6 CO2(g) + 6 H2O(l)
Calculate the volume of dry CO2 produced at body temperature (37°C) and 0.960 atm when 24.5 g of glucose is consumed in this reaction.
Answers
Answer:
\(\large \boxed{\text{21.6 L}}\)
Explanation:
We must do the conversions
mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 180.16
C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O
m/g: 24.5
(a) Moles of C₆H₁₂O₆
\(\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}\)
(b) Moles of CO₂
\(\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}\)
(c) Volume of CO₂
We can use the Ideal Gas Law.
pV = nRT
Data:
p = 0.960 atm
n = 0.8159 mol
T = 37 °C
(i) Convert the temperature to kelvins
T = (37 + 273.15) K= 310.15 K
(ii) Calculate the volume
\(\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}\)
When magnesium metal (Mg) reacts with hydrochloric acid (HCI), magnesium chloride (MgCl2) and hydrogen gas (H2) are produced according to the following chemical equation.
2 HCI (aq) + Mg (s) → MgCl2 (aq) + H2 (8)
If 1.44 moles of HCI is consumed in the chemical reaction above, how many grams of HCI are consumed? Molar mass of HCI is 36.46 g/mol.
For your answer, only type in the numerical value with three significant figures. Do NOT include the unit or the chemical (numbers only).
Answers
Mass of HCI consumed in the reaction 52.6 g.
Given information: Molar mass of HCI = 36.46 g/mol
No of moles of HCI consumed in the reaction = 1.44 moles
We can use the formula for the relationship between moles and mass to calculate the mass of HCI consumed in the reaction.
Mass = No of moles × Molar mass
Thus,Mass of HCI consumed in the reaction = 1.44 mol × 36.46 g/mol= 52.6064 g ≈ 52.6 g
Hence, 52.6 is the required answer in grams consumed of HCI
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from a full-strength hydrogen peroxide solution, how would you prepare 240 ml of two-thirds strength hydrogen peroxide solution for a wound irrigation using normal saline as the diluent?
Answers
To prepare 240 mL of two-thirds strength hydrogen peroxide solution for a wound irrigation using normal saline as the diluent, you need to mix 160 mL of full-strength hydrogen peroxide with 80 mL of normal saline.
This creates a total volume of 240 mL, with two-thirds of it being hydrogen peroxide and one-third being normal saline.
When using a hydrogen peroxide solution for wound irrigation, it is important to ensure that the concentration of the solution is appropriate for the type of wound being treated. Generally, hydrogen peroxide solutions of 2-3% concentration are used for wound irrigation. Higher concentrations can cause tissue damage and skin irritation.
Additionally, it is important to ensure that the diluent used is appropriate for the type of wound being treated. For example, normal saline is most commonly used for wound irrigation, but other diluents such as sterile water may be used for different types of wounds.
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a fish hatchery requires more than 4.5 mg/l of dissolved oxygen. if the river flows at 3.2 km/day, where in the river should you avoid siting the fish hatchery? express your answer as a range in km downstream from the wwtp discharge point. (this problem is asking you to calculate where along the river the do is less than 4.5 mg/l. you can estimate the answer from your plot if you plot enough data points.)
Answers
The range in km downstream from the WWTP discharge point would be the area to avoid for siting the fish hatchery. Based on the information provided, the fish hatchery requires more than 4.5 mg/l of dissolved oxygen. To determine where in the river to avoid siting the fish hatchery, we need to find the point where the dissolved oxygen level falls below 4.5 mg/l.
The river flows at a rate of 3.2 km/day. We can estimate the location by plotting data points. By calculating the distance downstream from the wastewater treatment plant (WWTP) discharge point, we can determine the range to avoid.
Please note that without specific data or a plot, I cannot provide an exact answer. However, you can estimate the distance by analyzing the dissolved oxygen levels at various points along the river and identifying where it drops below 4.5 mg/l. The range in km downstream from the WWTP discharge point would be the area to avoid for siting the fish hatchery.
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what is the word equation of photodecomposition?
Answers
Answer:
I have for Decompostion
Explanation:
A decomposition reaction occurs when one reactant breaks down into two or more products. It can be represented by the general equation: AB → A + B. In this equation, AB represents the reactant that begins the reaction, and A and B represent the products of the reaction
4.
How would the electrons in a calcium atom (atomic number=12) arrange
themselves into different energy levels?
Answers
Answer:
Viewed simply, electrons are arranged in shells around an atom's nucleus. Electrons closest to the nucleus will have the lowest energy. Electrons further away from the nucleus will have higher energy. ... In a more realistic model, electrons move in atomic orbitals, or subshells.
Explanation:
Viewed simply, electrons are arranged in shells around an atom's nucleus. Electrons closest to the nucleus will have the lowest energy. Electrons further away from the nucleus will have higher energy. ... In a more realistic model, electrons move in atomic orbitals, or subshells.
When thermal energy transfers from water vapor to a substance the water molecules in the air gain or lose energy'
GAIN OR LOSE
Answers
Answer:
Explanation:
Thermal energy is the energy related to the temperature of an object or system. It is a type of kinetic energy, that is, the energy associated with movement. Thermal energy is caused by the movement of atoms and molecules that make up an object or system. Thermal energy can be transferred between objects or systems by conduction, convection, or radiation.
When two objects or systems of different temperatures come into contact, thermal energy flows from the hotter object or system to the colder one until thermal equilibrium is reached, i.e. they are at the same temperature. When thermal energy is transferred from water vapor to a substance, the water molecules in the air lose energy. This is because thermal energy is being transferred from a hotter substance to a cooler substance. When water molecules in the air transfer their thermal energy to a cooler substance, their kinetic energy decreases, resulting in energy loss.
Thus, the thermal energy carried by the water vapor loses energy in contact with the air.
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please solve this question
Answers
Answer:
b) it gets accumulated in the respiratory system which then halts or slows down the supply of oxygen to the brain hence leading to death
Uranium-232 has a half-life of 68.8 years. After 344.0 years, how much uranium-232 will remain from a 375.0-g sample?
Answers
Uranium-232 will remain 11.72 g
Further explanationThe atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually radioactive elements have an unstable atomic nucleus.
The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles
General formulas used in decay:
\(\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{T/t\frac{1}{2} }}}\)
T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t 1/2 = half-life = 68.8 years
T = duration of decay = 344 years
No= initial sample = 375 g
Uranium-232 remain :
\(\tt Nt=375.\dfrac{1}{2}^{344/68.8}\\\\Nt=375.\dfrac{1}{2}^5\\\\Nt=11.72~g\)
7) a student claims that if they used a higher concentration of the titrant (naoh) than you did, their calculated concentration of citric acid in the iced tea would have differed dramatically. do you agree or disagree with this student? why?
Answers
According to the student, if he or she used a higher concentration of the titrant (NaOH) than the individual, the calculated concentration of citric acid in the iced tea would have differed significantly.
Why is it necessary to know about the acidity of the citric acid?
It is necessary to know that the acidity of the citric acid in the iced tea plays an important role in the titration process. Citric acid is a tricrotic acid with three dissociation stages. In an acidic solution, each stage dissociates completely. Therefore, to determine the concentration of citric acid in iced tea, a titration technique is employed.
Titration is a technique for determining the concentration of an acid solution using a base solution of known concentration. The titrant is used to neutralize the acid solution in this process.
During the titration process, the volume of the titrant needed to neutralize the acidic solution is measured to calculate the concentration of citric acid in iced tea.
As a result, the student's statement is correct.
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What is the pOH of water?
Answers
Answer:
A. 7
(assuming the water is neutral)
A 25.0 g sample of metal is
warmed by 6.1 °C using 259 ] of
energy.
What is the specific heat of the
metal?
Spec. Heat (J/g °C)
PH
![A 25.0 g sample of metal iswarmed by 6.1 C using 259 ] ofenergy.What is the specific heat of themetal?Spec.](https://i5t5.c14.e2-1.dev/h-images-qa/contents/attachments/ZdKTyAesAqYJ8hKaQbxp79SVxlMuGlf0.png)
Answers
A 25.0 g sample of metal is warmed at 6.1 °C using 259 of energy. The specific heat of the metal is 1.07 J/g°C.
Given:
m = 25.0 g
ΔT = 6.1 °C
q = 259 J
The specific heat of the metal is given by the formula:
q = mcΔT
where q is the amount of heat energy absorbed by the metal, m is the mass of the metal, c is the specific heat of the metal, and ΔT is the change in temperature.
Rearranging the formula:
c = q / (m ΔT)
Substituting the given values:
c = 259 J / (25.0 g × 6.1 °C)
c = 1.07 J/g°C
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Answer:
The correct answer is 1.69
Acellus
Explanation:
as the temperature of a gas decreases is volume
Answers
Answer:
it's volume also decrease
If the volume of a gas is decreased by changing the shape of the container, the number of collisions per area between the molecules and the container walls will increase. This corresponds to an increase in the gas pressure, which is the force exerted per area. What gas law is kinetic molecular theory of gases (KMT) explaining in this case
Answers
Answer:
If the volume of a gas is decreased by changing the shape of the container, the number of collisions per area between the molecules and the container walls will increase. This corresponds to an increase in the gas pressure, which is the force exerted per area.
what is a salient factor?
Answers
Answer:
technology is a silent factor
Explanation:
learned about it in computer class.
the valency of metal 'm' 1+. give the formula of its oxide
Answers
Answer:
\(M_{2}O\)
Explanation:
Anything oxide is a compound with oxygen, and since oxygen is -2, it requires two of the metal's +1 to make it zero
In other words:
2(+1) + (-1) = 0
What is the difference between a pure solvent and a solution? Do they have the same physical properties?
Answers
Answer:
The physical properties of a solution are different from those of the pure solvent. ... Colligative properties are those physical properties of solutions of nonvolatile solutes that depend only on the number of particles present in a given amount of solution, not on the nature of those particles.
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What is empirical evidence
A retest of experimental results to make them reliable
Knowledge gained by observation or measurement
A prediction of test results before an experiment
A conclusion derived from evidence and logical reasoning
Answers
two step strategy for percent composition from experimental data
Answers
Two step strategy to determine percent composition from experimental data are to calculate the moles of each element and Calculate the percent composition.
To determine the percent composition from experimental data, we have to follow this two-step strategy:
1. Calculate the moles of each element: Divide the mass of each element obtained from the experimental data by its respective atomic weight (found on the periodic table). This will give you the moles of each element in the sample.
2. Calculate the percent composition: Divide the moles of each element by the total moles of all elements in the sample, then multiply the result by 100 to obtain the percentage. This will give you the percent composition of each element in the compound.
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1. Atomic mass of 12 and 6 neutrons what is the atomic number?
Answers
Answer:
The atomic number would be 12.
Explanation:
A neutral atom of Carbon-12 contains six protons, six neutrons, and six electrons.
As the distance between the particles
decreases during a phase change, the
potential energy
remains the same
decreases
inceraeses