The correct answer is B) They are no more alike than siblings from two separate pregnancies.
Since Susan gave birth to fraternal twins (one boy and one girl), they developed from two separate eggs fertilized by two separate sperm cells. Fraternal twins are dizygotic, which means they are no more alike than siblings born from two separate pregnancies. Monozygotic or identical twins, on the other hand, develop from a single fertilized egg that splits into two embryos, resulting in twins with identical DNA. Therefore, option B is the correct answer in this case.
Susan's twins are a boy and a girl, which means they cannot share the same DNA and be monozygotic. Therefore, the correct answer is B) They are no more alike than siblings from two separate pregnancies. These twins are dizygotic, or fraternal twins, as they result from two separate fertilized eggs.
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Susan recently gave birth to twins: a boy and a girl. She delivered about 4 weeks before her due date. The correct answer is B) They are no more alike than siblings from two separate pregnancies.
What are monozygotic twins?
Since Susan gave birth to a boy and a girl, it is impossible for them to be monozygotic (identical twins). Monozygotic twins come from a single fertilized egg that splits into two embryos, and is, therefore, the same sex and has identical DNA. Dizygotic (fraternal) twins, on the other hand, come from two separate eggs fertilized by two separate sperm and are no more genetically similar than siblings from two separate pregnancies.
The fact that Susan delivered 4 weeks before her due date (premature birth) does not provide any information about the type of twins she gave birth to. The gestation period for twins is typically shorter than for single births, with an average of 36-37 weeks for dizygotic twins and 38-39 weeks for monozygotic twins. However, premature birth can occur with any type of twin pregnancy.
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What is Type 4 secretion system?
The Type IV secretion system (T4SS) is a complex molecular machine found in some bacteria that allows them to transfer DNA and proteins to other cells.
This secretion system is important for a wide range of bacterial functions, including the exchange of antibiotic-resistance genes, the delivery of virulence factors into host cells, and the transfer of DNA between bacteria. The Type IV secretion system consists of multiple protein components that assemble into a channel or pore spanning the bacterial cell envelope. The channel is made up of several protein subunits that assemble into a helical structure, forming a channel through which DNA or proteins can pass. The T4SS also includes other components that help to regulate the transfer of DNA or proteins through the channel.
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How do positive and negative feedback loops differ?
a Positive feedback loops increase the amount of positively charged ions, while negative feedback loops increase the amount of negatively charged ions.
b There is no difference; they both have similar functions.
c Positive feedback loops are good for the cells, while negative feedback loops are harmful to cells.
d Positive feedback loops increase the initial signal, while negative feedback loops decrease the original signal.
Answer:
Positive and negative feedback differs in that positive feedback loops increase the initial signal, while negative feedback loops decrease the original signal (option d).
Explanation:
Feedback is a process that, applied to biological systems, allows for the changes needed to maintain homeostasis.
Negative feedback loop occurs when a stimulus is presented, producing a change in the body, so the response is to stop the change that is occurring. It is the most frequent type of feedback and has the greatest impact on homeostasis. An example of negative feedback is a decrease in body temperature through sweating. Positive feedback loop occurs when the stimulus produces a change and promotes a response that reinforces that change. The classic example of positive feedback is the secretion of oxytocin, promoted by uterine contractions, whose effect is to increase those contractions, allowing labor.In summary, positive feedback loop acts by increasing an action or signal in the body, while the negative feedback loop reduces or stops the action or signal that occurs.
Answer:
D is correct
Positive feedback loops increase the initial signal, while negative feedback loops decrease the original signal.
Explanation:
what determines which base is to be added to an rna strand during transcription? base pairing between the dna template strand and the rna nucleotides
The base pairing between the dna template strand and the rna nucleotides determines base is to be added to an rna strand during transcription.
Ribonucleic acid (RNA) is a dna polymerase discovered in all living organisms that is structurally similar to DNA. RNA, unlike DNA, is typically single-stranded. Rather than the ribose found in DNA, the foundation of an RNA molecule is made of interchanging hydroxyl group and the sugar purines. RNA is purely a duplicate of DNA that, with exception of DNA, needs to travel around the cell as well as assistance the nucleus in only certain functions. Since it needs to bond to amino acid residues and send genetic texts, it requires one strand in sequence to be unpredictable enough to bond with the other molecules. RNA has a strand. The backbone of RNA is constituted of phosphorous and ribose sugar.
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during meiosis the centromeres divide as the cell moves into
During meiosis, the centromeres divide as the cell moves into the anaphase stage.
Meiosis is a specialized cell division process that occurs in sexually reproducing organisms. It involves two rounds of division, known as meiosis I and meiosis II, resulting in the formation of four haploid cells.
In meiosis I, the cell goes through prophase I, metaphase I, anaphase I, and telophase I. It is during anaphase I that the centromeres divide. The centromere is a region of the chromosome that holds the sister chromatids together. During anaphase I, the microtubules of the spindle apparatus pull the homologous chromosomes apart, separating them and moving them towards opposite poles of the cell. As the chromosomes separate, the centromeres divide, allowing each sister chromatid to be pulled toward opposite poles.
This division of centromeres ensures that each resulting cell in meiosis I receive one copy of each homologous chromosome. The subsequent meiosis II division then separates the sister chromatids, resulting in the formation of four haploid cells, each with a unique combination of genetic material.
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which of the following foods is likely to contain clostridium botulinum? a. raw or undercooked eggs b. cream-filled pastries c. pasteurized milk d. canned foods e. hot dogs
Clostridium botulinum is a bacterium that produces the botulinum toxin, which can cause a severe form of food poisoning called botulism. Option D is the correct answer.
This bacterium thrives in low-oxygen environments, such as improperly canned or preserved foods. Canned foods, especially those that are not properly processed or stored, can provide an ideal environment for the growth of Clostridium botulinum and the production of its toxin. Consuming contaminated canned foods can lead to botulism if the bacteria and toxin are present. Therefore, canned foods are more likely to contain Clostridium botulinum compared to other food items listed in the options.
Option D is the correct answer.
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What is the purpose of a chronological?.
While a person's biological age is determined by epigenetic changes and DNA methylation, which indicate how capable and functional she is as well as if she has illnesses associated with aging, a person's chronological age relates to the actual period of time they have been alive.
Developmental study searches for variations to time or changes in behavior that are connected to age. It is possible to approximately ensure the equality of elements like physical experience, social contact, learning, and acculturation by using chronological age with time constraint.
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what characteristic to the majority (40 out of 60) of plants with a one to one correspondence between their scientific identity and their local name?
The majority (40 out of 60) of plants with a one-to-one correspondence between their scientific identity and their local name tend to share a characteristic of having distinct and recognizable features.
These features make it easier for people to associate the local name directly with the scientific identity of the plant. This can include the plant's morphology, such as its leaf shape, flower color, or growth habit. In some cases, it can also relate to the plant's ecological role or its ethnobotanical uses.
The one-to-one correspondence ensures that there is a clear link between the local and scientific names, reducing confusion in communication and plant identification. This is particularly important for plants with cultural or economic significance, as accurate identification is crucial for their proper use and conservation.
This correspondence may have arisen due to the contributions of both local and scientific knowledge, leading to a more comprehensive understanding of the plant's characteristics and significance.
In summary, the main characteristic of plants with a one-to-one correspondence between their scientific identity and their local name is their distinct and recognizable features. This connection helps to ensure accurate identification and communication, contributing to the proper use, study, and conservation of these plants.
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what is the process through which organisms create more organisms that can be genetically identical or genetically different.
Answer: sexual reproduction or reproduction
Explanation: an organism combines the genetic information from each of its parents and is genetically unique.
Consider the cell structure that is shown below.
A cell structure is shown. This structure consists of phospholipid bilayer, proteins, and carbohydrates.
Which is a function of the structure that is represented in the image?
Answer:
The correct answer is A
Explanation:
I did it on edu and it was correct!
You're welcome!
Answer:
A, correct on edge ! have a good day!
A zygote is a ________________________
Answer:
a diploid cell resulting from the fusion of two haploid gametes; a fertilized ovum.
Explanation:
Answer:
Diploid cell resulting from the fusion of two haploid gametes
Explanation:
A zygote is a diploid cell resulting from the fusion of two haploid gametes.
What does the notation TT mean to genetics ?
The notation TT denote homozygous tall plant.
The heterozygoty or homozygoty is decided based on the type of allele present in gene. If the gene consist of similar type of allele such as TT or tt .This is regarded as homozygous condition. When gene consist of different type of allele such as Tt. This is called heterozygotic condition. The phenotype of these gene depend on the dominant allele.
When two heterozygous tall plants are crossed, tall and dwarf plants are produced in a 3:1 phenotypic ratio. The F2 generation is referred to as this.
The genotypes will be as:
1 homozygous tall(TT)
2 heterozygous tall(Tt) and
1 homozygous dwarf(tt)
Hence, phenotype of gene is decided based on the dominant allele.
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Using what you've learned so far, is the air quality forecast likely to be
better in urban areas or in rural areas? Explain your answer. *
Answer:
Rural areas have better air quality. Urban areas have more pollution due to higher pollutant emitters
Explanation:
if garlic mustard were to reduce arbuscular mycorrhizal fungi in an apple orchard, what effect would this have on apple crops?
Myccorrhizal colonization ill help in the pathogen incidence with the factors that the apple productivity is no longer harmed in the production. The process is like symbiosis.
What is symbiosis ?It is the effect in which the two organisms are living together for the mutual benefits of each other and the effect thus reduces the dependence on a multi chained mechanism.
When the nutrient deficiency and the various productions are harmed in the mechanism where the multiple factors along with the pathogen invasion and development of the diseased crops are coming in that way they harm the production.
If by the growth of the arbuscular mycorrhizal fungi then the production is harmed and with the garlic mustard it eliminates the negative impacts and this automatically improves the stats for the effect.
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how to count replicated chromosomes in mitosis
PLEASE HELP
Answer:
Once mitosis is complete, the cell has two groups of 46 chromosomes, each enclosed with their own nuclear membrane. The cell then splits in two by a process called cytokinesis, creating two clones of the original cell, each with 46 monovalent chromosomes.
Explanation:
g the predominant mechanism by which cells in different tissues in eukaryotes differ from each other is the difference in gene_____.
The predominant mechanism by which cells in different tissues in eukaryotes differ from each other is the difference in gene expression.
While all cells in an organism contain the same set of genes, not all of these genes are expressed in every cell.
Gene expression refers to the process by which genetic information stored in DNA is used to produce functional gene products, such as proteins or RNA molecules.
The regulation of gene expression is a complex process that involves various mechanisms, including transcriptional, post-transcriptional, translational, and post-translational control.
Through these mechanisms, cells can selectively activate or repress specific genes, allowing them to differentiate into specialized cell types with distinct structures and functions.
Therefore, differences in gene expression patterns can account for the vast diversity of cell types in multicellular organisms, and ultimately, for the complexity of biological systems. Therefore, the correct answer is gene expression.
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What separates the dorsal cavity into two subdivisions.
Answer:
The skull
Explanation:
The skull separates the cranial cavity and the vertebral cavity, which contain the brain and spine respectively.
2
How does Mike's mom compare the cell membrane and the nuclear
membrane?
A
Both the cell membrane and nuclear membrane are coverings.
B Both the cell membrane and the nuclear membrane controls the cell's
activities,
Both the cell membrane and the nuclear membrane let out waste.
D Both the cell membrane and the nuclear membrane allow substances to
enter the cell.
Answer:
A, they are both coverings. The cell membrane for the entire cell and nuclear membrane surrounds the nucleus.
The Moon can be seen on Earth because it produces its own light. True or false
Answer:
false
Explanation:
These different faces are called phases and they are the result of the way the Sun lights the Moon's surface as the Moon orbits Earth. The Moon can only be seen as a result of the Sun's light reflecting off it. It does not produce any light of its own.
Answer:
FALSE
Explanation:
cuz it obtain light produced by sun
Using the sorting results from Part C, complete the modified Punnett square below.First, fill in the frequently of each gamete produced by the F1 by dragging one green label to each green target at the TOP and LEFT of the Punnett square.Then, fill in the frequency of each F2 genotype by dragging one blue label to each blue target inside the Punnett square.Finally, fill in the number of additive alleles in each F2 genotype by dragging one pink label to each pink target.
Answer:
a) 1/16, b) 4/16, c) 1/16, d) 1/16, e) 4/16, f) 4/16, g) 0 + alleles, h) 1/256, i) 1 + alleles, j) 4/256, k) 2 + alleles, l) 16/256, m) 3 + alleles, n) 24/256, o) 4 + alleles), p) 36/256, q) 5 + alleles, r) 24/256, s) 6 + alleles, t) 16/256, u) 7 + alleles, v) 4/256, w) 8 + alleles, x) 1/256.
You will find the uncompleted Punnett square (missing in the problem statement) and the complete modified Punnett square in the attached files
Explanation:
Due to technical problems, you will find the complete explanation in the attached files
Explain several things that can affect the level of the water table.
Answer:
Droughts, seasonal variations in rainfall, and pumping affect the height of the under groundwater levels.
Explanation:
If a well is pumped at a faster rate than the aquifer around it is recharged by precipitation or other underground flow, then water levels in the well can be lowered.
Which animal class has no tissue? A.Sponges B.Cnidarians C.Roundworms D. Flatworms
The organisms that are usually fossilized
by replacement are what?
Answer:
when the original shell or bone dissolves away and is replaced by a different mineral; when this occurs with permineralization, it is called petrification. In compression, the most common form of fossilization of leaves and ferns, a dark imprint of the fossil remains.
Explanation:
Which of the following statements is not part of the cell theory. 1. Cells are the basic unit of structure and function in all living things
2. All cells are produced from other cells
3. Only animal cells are composed of cells
4. All living things are composed of cells
Answer:
your answer is option 3
QUESTION 1 Exercise 11.10. Butterflies. Alice, Bob, and Charlotte are looking for butterflies. They look in three separate parts of a field, so that their probabilities of success do not affect each other. • Alice finds 1 butterfly with probability 17%, and otherwise does not find one • Bob finds 1 butterfly with probability 25%, and otherwise does not find one • Charlotte finds 1 butterfly with probability 45%, and otherwise does not find one Let X be the number of butterflies that they find altogether. Write X as the sum of three indicator random variables, X1, X2, X3 that indicate whether Alice, Bob, Charlotte (respectively) found a butterfly. Then X= X1+X2 +X3. Find the expected value of X by finding the expected value of the sum of the indicator random variables. Your answer will have two decimal places. **This is a straight forward expected value of a sum of random variables, nothing fancy here! QUESTION 2 Exercise 11.16. Flipping coins. Flip a coin until the second head comes up. Let X be the number of flips needed to get the second head. What is the E(X). The first step is to find the expected value of getting the first head. Is this like Example 11.10, sampling without replacement, OR like Example 11.11, sampling with replacement? O A. Example 11.10, sampling without replacement O B. Example 11.11, sampling with replacement QUESTION 3 Exercise 11.16. Flipping coins. Flip a coin until the second head comes up. Let X be the number of flips needed to get the second head. What is the E(X). The first step is to find the expected value of getting the first head. What is the expected value of getting the first head? This will be an integer answer. QUESTION 4 Exercise 11.16. Flipping coins. Flip a coin until the second head comes up. Let X be the number of flips needed to get the second head. What is the E(X). The next step is to find the expected value of getting the second head. Because this is identical to finding the expected number of rolls for the first head (independent events), we just multiply the first head's expected value by 2. This will be an integer answer. QUESTION 5 Exercise 11.17 (a). Waiting for favorite song. Michael puts his iTunes on shuffle mode where songs are not allowed to be replayed. He has 2,781 songs saved on iTunes, and exactly one of these is his favorite. How many songs is he expected to have to listen to until his very favorite song comes up? Is this like Example 11.10, sampling without replacement, OR like Example 11.11, sampling with replacement? A. Example 11.11, sampling with replacement B. Example 11.10, sampling without replacement
In Exercise 11.10, the expected value of the number of butterflies found by Alice, Bob, and Charlotte is obtained by finding the expected value of the sum of three indicator random variables.
In Exercise 11.16, the expected value of the number of flips needed to get the second head in a coin flipping experiment is determined. These exercises involve different scenarios of sampling with and without replacement.
In Exercise 11.10, the expected value of X, the total number of butterflies found, is found by calculating the expected value of each indicator random variable (X1, X2, X3) representing whether Alice, Bob, and Charlotte found a butterfly, respectively.
The expected value of each indicator variable can be obtained by multiplying the probability of success (finding a butterfly) by 1 and the probability of failure (not finding a butterfly) by 0. Then, the expected value of X is calculated as the sum of the expected values of the indicator variables.
In Exercise 11.16, the expected value of X, the number of flips needed to get the second head, is determined. To find this value, we first need to find the expected value of getting the first head. This scenario is similar to Example 11.11, which involves sampling with replacement.
Each coin flip is an independent event, and the probability of getting a head is constant at 0.5.
Therefore, the expected value of getting the first head is 1/p, where p is the probability of success (0.5 in this case).
In Exercise 11.17 (a), the scenario of waiting for a favorite song in Michael's iTunes playlist involves sampling without replacement. Each song played is not replayed, and there is only one favorite song among the total number of songs.
Therefore, this scenario is similar to Example 11.10, sampling without replacement.
To find the expected number of songs Michael needs to listen to until his favorite song comes up, the formula for sampling without replacement is used, which is the reciprocal of the probability of selecting the favorite song at each step.
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5. A mother's diet is very important throughout her pregnancy but especially during the first
trimester. Vitamins and minerals provide essential nutrients during this stage of
development. Vitamins A, D, and Beta Carotene help bones and teeth grow and harden,
Vitamin E is used in the formation of red blood cells and muscles, and Vitamin C helps build
a healthy immune system. Which of the following would most likely result from a poor diet
during the first trimester?
A. Less production of urine
B. Response to outside stimulus
C. A functioning nervous system
D. Abnormal development of the heart and lungs
Poor nutrition during the first trimester of pregnancy can have negative effects on both the mother and the unborn child. A poor diet is more likely to cause improper heart and lung development.
What is the dependence of the bones ?The growth of bones and teeth depends on vitamins A, D, and beta-carotene, whereas the development of red blood cells and muscles depends on vitamin E. A robust immune system may be built using vitamin C.
Without these nutrients, the baby's heart and lungs could not develop normally, which might result in life-threatening medical issues. Because the body is unable to absorb the essential nutrients from meals, poor nutrition can also result in reduced urine output.
Dehydration from this may result, which may further contribute to healthcare issues. Additionally, because the baby's nervous system could not be fully formed, a poor diet during the first trimester can result in a diminished reaction to external input.
Problems with motor and cognitive development may result from this. To sum up, a bad diet throughout the first trimester might result in major medical issues for both the mother and her unborn child. A poor diet is more likely to cause improper heart and lung development.
In addition, a poor diet might cause issues with motor and cognitive development, reduced sensitivity to external stimuli, and decreased urine output. It is therefore essential that pregnant women eat a balanced diet with the necessary vitamins and minerals to ensure the health of both mother and baby.
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5.17. A man aiming at a target receives 10 points if his shot is within 1 inch of the target, 5 points if it is between 1 and 3 inches of the target, and 3 points if it is between 3 and 5 inches of the target. Find the expected number of points scored if the distance from the shot to the target is uniformly distributed between 0 and 10
The expected number of points scored is 2.6.
To find the expected number of points scored, we need to consider the probabilities of each scoring range and multiply them by the respective points. Since the distance is uniformly distributed between 0 and 10 inches, we can calculate the probabilities of each scoring range.
For 10 points (within 1 inch): The range is 0 to 1 inch, so the probability is 1/10 or 0.1.
For 5 points (between 1 and 3 inches): The range is 1 to 3 inches, so the probability is (3-1)/10 or 0.2.
For 3 points (between 3 and 5 inches): The range is 3 to 5 inches, so the probability is (5-3)/10 or 0.2.
The remaining probability (no points) is 0.5, as the shot is between 5 and 10 inches from the target.
Now, we can calculate the expected number of points:
Expected points = (10 points × 0.1) + (5 points × 0.2) + (3 points × 0.2)
Expected points = 1 + 1 + 0.6
Expected points = 2.6
Therefore, the expected number of points scored is 2.6.
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Imagine that you are performing a cross involving seed color in garden pea plants. What traits would you expect to observe in the F1 offspring if you cross true-breeding parents with green seeds and yellow seeds
In pea plants, seed color is one of the traits that show Mendelian inheritance. The green and yellow color of the pea seeds are determined by different alleles.
If true-breeding parents with green seeds and yellow seeds are crossed, the F1 generation would have all yellow seeds. This is because the yellow seed color allele is dominant, and the green seed color allele is recessive. Since the parents are true-breeding, this means that they both have homozygous genotypes.
The green seed parent would have a genotype of gg, while the yellow seed parent would have a genotype of YY. When they are crossed, all the F1 offspring will inherit a Y allele from the yellow seed parent and a g allele from the green seed parent.
This gives them a Yg genotype, which is heterozygous for seed color. Since the Y allele is dominant, all the F1 offspring will have yellow seeds. However, even though all the F1 offspring have yellow seeds, they still carry the recessive green seed color allele.
This can be observed in the F2 generation when the F1 offspring are crossed. When two F1 offspring with Yg genotypes are crossed, they will produce F2 offspring with a ratio of 3:1 yellow to green seed color. This is because of the probability of the Y allele being dominant and the g allele being recessive in a monohybrid cross.
Therefore, if true-breeding parents with green seeds and yellow seeds are crossed, the F1 offspring will have all yellow seeds, but the F2 offspring will have a 3:1 ratio of yellow to green seed color.
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For the cross in Part B, predict the frequencies of each of the phenotypes in the F1 progeny, and determine the genotype(s) present in each phenotypic class.
The genotype(s) present in each phenotypic class.
yellow round: 3/8, RrYY, RrYy (x2)yellow wrinkled: 3/8, rrYY, rrYy(x2)green round: 1/8, Rryygreen wrinkled: 1/8, rryyGenotype AaBbCc can produce 8 types of gametes, i.e., ABC, Abc, ABc, AbC, abc, aBC, aBc and abC.What is the genotypic ratio of the F1 generation?
Since that component is regarded as dominant, generation F1's genotype ratio of 100 percent Ss hybrid resulted in 100 percent smooth pea production. Mendel was producing the Ss X Ss hybrid by self-fertilizing those F1 individuals.What is the genotype of the green pod plant?
Due to the dominance of green (G) over yellow (g), plants with G in their genotypes produce green pods. The only plants with yellow pods are gg-genotype plants.What is the phenotype of F1 progeny?
Given that one dominant and one recessive allele were transmitted from the parents, the F1 generation exhibits a uniform round yellow phenotype, as predicted by the first law.
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What pathological conditions can be best identified when performing an anteroposterior (ap) projection of the lumbar spine?
When injury of joint is suspected.The spinous processes are demonstrated in the middle of the vertebral bodies.
The lumbar spine anteroposterior or posteroanterior view image the lumbar spine in its anantomical position. This is consist of five vertebrae. The lumbar spine anteroposterior or posteroanterior view image the lumbar spine in its anatomical position.
The lumbar spine generally consists of five vertebrae. A radio-graphic study in which the X- rays travel from anterior to posterior.This projection is utilized in many imaging contexts including trauma, postoperatively and for chronic conditions.The DAP reduction of approximately 27% and effective dose reduction of approximately 53% is using the PA instead of AP standard projection in lumbar spine radiography.
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A researcher has devised a technique that allows her to label all the integral membrane proteins with a fluorescent tag. She uses a laser to bleach the fluorescence in a specific area of the cell membrane. After 24 hours, she notices that fluorescence has returned to the bleached area. What can she deduce from this experiment?.
A researcher has devised a technique that allows her to label all the integral membrane proteins with a fluorescent tag. She uses a laser to bleach the fluorescence in a specific area of the cell membrane. After 24 hours, she notices that fluorescence has returned to the bleached area. She can deduce from this experiment that integral membrane proteins are able to move laterally within the cell membrane.
In the field of biology, integral proteins of the cell membrane can be described as the proteins which are embedded in the plasma membrane of a cell. These integral membrane proteins allow the movement of specific molecules into or outside the cell through the method of facilitated diffusion.
Scientific research has shown that the integral proteins of a cell membrane can either move in a rotation or show lateral movements. It is due to the lateral movements that the fluorescence was seen again at bleached places by the researcher above. The fluorescent tag attached to only the integral proteins confirmed that it was the integral proteins showing moving laterally.
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