12/15•35/13•10/2•26/36 how to do this problem

Answer:

b.

Step-by-step explanation:

Answer:

200

Step-by-step explanation:

you subtract

Answer:

If the safe dose is .5 to 1 mg/kg/dose, the safe limit depends on the side of the child.  Using the more conservative limit of .5mg/kg, you have 36mg(kg/.5mg)=72kg, which is roughly 160lbs,  Even with the upper limit of 1mg/kg, you still have 36mg(kg/1mg) = 36kg, or 80lbs, which is a larger child.  I would say this dose isn't "safe", but you really need the weight of the child to calculate what is a safe dose.

Step-by-step explanation:

The solutions for the trigonometric equation are given as follows:

a. θ = 30º + 360ºk and θ = 150º + 360ºk, for all degree solutions.

b. θ = 30º and θ = 150º, 0 <= θ <= 360º.

The given trigonometric equation is:

2sin(θ) = 1.

Solving for the sine:

sin(θ) = 1/2.

On the first quadrant, the angle with a sine of 1/2 is of 30º. The sine is also positive on the second quadrant, hence 180 - 30º = 150º also has a sine value of 1/2.

The trigonometric circle has a period of 360º, hence:

Which means that the solution can be written in generic terms for item a, as follows:

θ = 30º + 360ºk and θ = 150º + 360ºk.

As we found above, due to the knowledge of standard angles(30º, 45º and 60º), along with equivalent angles, on the first lap, the solutions are 30º and 150º, hence, for item b:

θ = 30º and θ = 150º, 0 <= θ <= 360º.

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Answer:

j(t) = 0.16t + 1.46

Step-by-step explanation:

The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.

To rewrite the function j(t) = 1.7 + 0.4(t - 0.6) in slope-intercept form, we can isolate the y-intercept and the slope.

First, expand the parenthesis to get j(t) = 1.7 + 0.4t - 0.24.

Next, rearrange the terms to get j(t) = 0.16t + 1.46.

So, in slope-intercept form, j(t) = 0.16t + 1.46, where the slope is 0.16 and the y-intercept is 1.46.

probability of drawing two blue marbles= 5/10

                                                                  = 1/2

Given parameters:

Number of marbles in the bag = 10 marbles

Number of blue marbles  = 5 marbles

Number of red marbles = 4 marbles

Number of yellow marbles  = 1 marble

Unknown:

The probability of drawing two blue marbles.

Probability is the likelihood of an event to occur. It is the number of possible outcomes divided by the sample space.

Probability values ranges from 0 to 1

                1 is a certainty that an event will occur.

                0 shows that the event will not occur.

The probability of drawing the first blue marble = \(\frac{5}{10}\)

Probability of drawing the second marble without replacing the marble = \(\frac{4}{9}\)

  Now,

 The probability of drawing two blue marbles without replacement is;

                 =  \(\frac{5}{10}\)  x \(\frac{4}{9}\)

                 = \(\frac{2}{9}\)

So the probability of picking two marbles without replacement is \(\frac{2}{9}\)

By analyzing the graph and evaluating the objective function at each vertex of the feasible region, we can find the optimal solution, which is the vertex that maximizes the objective function z = 3x + y.

To find the optimal solution of the given problem using the graphical method, we need to plot the feasible region determined by the given constraints and then identify the point within that region that maximizes the objective function.

Let's start by graphing the constraints:

1. Plot the line 2x - y = 5. To do this, find two points on the line by setting x = 0 and solving for y, and setting y = 0 and solving for x. Connect the two points to draw the line.

2. Plot the line -x + 3y = 6 using a similar process.

3. The x-axis and y-axis represent the constraints x ≥ 0 and y ≥ 0, respectively.

Next, identify the feasible region, which is the region where all the constraints are satisfied. This region will be the intersection of the shaded regions determined by each constraint.

Finally, we need to identify the point within the feasible region that maximizes the objective function z = 3x + y. The optimal solution will be the vertex of the feasible region that gives the highest value for the objective function. This can be determined by evaluating the objective function at each vertex and comparing the values.

Note: Without a specific graph or additional information, it is not possible to provide the precise coordinates of the optimal solution in this case.

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Answer:

The exact value of the other leg is 10.

Step-by-step explanation:

Finding the exact value of x given a 45 degree angle and a side length of 10 can be done using trigonometry. In a 45-45-90 right triangle, the two legs are congruent and the hypotenuse is equal to the square root of 2 times the length of the legs.

Therefore, if one leg is 10, the hypotenuse is 10 times the square root of 2. To find the length of the other leg, we can use the Pythagorean theorem:

c^2 = a^2 + b^2, where c is the hypotenuse, a and b are the legs of the right triangle.

Substituting known values, we get:

(10√2)^2 = 10^2 + b^2

200 = 100 + b^2

b^2 = 100

b = 10

Therefore, the exact value of the other leg is 10.

To find the measure of the geometry-big circle, we need to sum up the measures of all the arcs around the circle.

We are given the following measures:

\(\sf\:m\angle AB = 56 \\\)

\(\sf\:m\angle BC = 59 \\\)

\(\sf\:m\angle CD = 63 \\\)

\(\sf\:m\angle DE = 63 \\\)

\(\sf\:m\angle EF = 31 \\\)

To find the measure of the geometry-big circle, we add up these measures:

\(\sf\:m\angle AB + m\angle BC + m\angle CD + m\angle DE + m\angle EF \\\)

Substituting the given values:

\(\sf\:56 + 59 + 63 + 63 + 31 \\\)

Simplifying the expression:

\(\sf\:272 \\\)

Therefore, the measure of the geometry-big circle is 272.

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♥️ \(\large{\textcolor{red}{\underline{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

The value of cos (A+B) in simplest form is -136/305.

The standard formula for the cosine of the sum of two angles is:

cos(A+B) = cos A cos B - sin A sin B

We are given that cos A = 11/61 and sin B = 3/5. We can use this information to find the values of sin A and cos B by using the Pythagorean identity:

sin^2 A +\(cos^2\)A = 1  =>  sin A = \(\sqrt(1 - cos^2\) A)

cos^2 B + \(sin^2\) B = 1 => cos B = \(\sqrt(1 - sin^2 B)\)

Substituting the given values, we get:

sin A =\(\sqrt(1 - (11/61)^2) ~~ 60/61\)

cos B = \(\sqrt(1 - (3/5)^2) = 4/5\)

Now we can use these values to find the cosine of the sum of the angles:

cos(A+B) = cos A cos B - sin A sin B

= (11/61)(4/5) - (60/61)(3/5)

= (44/305) - (36/61)

= (44 - 180)/305

= -136/305

Note that since A and B are positive acute angles, A+B is also an acute angle, which means that its cosine is negative.

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we have

y=-2/3x-2

this is an equation in slope intercept form

y=mx+b

where

m is the slope

b is the y-intercept

so

In this problem

we have

slope m=-2/3 (is negative)

y-intercept is b=-2

see the attached figure to better understand the problem

Answer:

1/2

Step-by-step explanation:

I got this wrong it gave me this step by step equation on khan I hope this helps

1 / 3

What times x gives us y?

2 / 3

If we multiply each x-value by 1 / 2 we get to each corresponding y-value:

y = 1 / 2x

3 / 3

The constant of proportionality (r) in the equation y =rx is 1 / 2

this was the exact same explanation and answer khan academy game me, so it should be right

Answer:

1/2

Step-by-step explanation:

The domain for this relation is {1,3} and the range for this relation is {2}.

According to the question, the given domain and range of the relation is as follows:

The domain for this relation is : {0, 1, 3}

The range for this relation is : {-2, 1, 2}

As per definition, the domain is the set of all possible values which a function take as an input.

Therefore, the domain for this relation is : {1, 3}

And the range for this relation is: {2}

Hence, the domain for this relation is {1,3} and the range for this relation is {2}.

What is domain and range of a function?

The domain is the set of all the possible values which a function can take as an input. And the range is also the set of paired values which represent the output of a function.

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Answer:

1.  -.5

2.  7

3.   -2

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

the graph is completely proportional so the answer would be 1

By definition of real field and algebra properties we conclude that the product of three positive integers is always equal to a positive integer.

First, we state the conjecture: The product of three positive integers equals a positive integer. Second, we prove if the conjecture is true:

Integers are part of the real field, which mean that the product of two integers is also an element of that field. By algebra we know that the product of two positive integers is equal to another positive integer. Thus, the product of three positive integers is always equal to a positive integer.

Here is an example:

2 × 5 × 7

10 × 7

70

In a nutshell, the conjecture has been proved true.

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Answer:

a. mu_d = the true population mean difference in jump height

Step-by-step explanation:

In statistical parlance, observations used for a study could either be randomly chosen points or members of a large group or population, this small chosen observation obtained from a larger group is called the sample, the statistical measures or characteristic of such group is called statistic; while statistical characteristic, computations or measurement of the entire group of observations is called the parameter.

Mean of sample are usually represented with a bar sign on top such as (xbar) ; while mean of a population is represented as μ.

Answer:

a) About 95% of organs will be within 230 and 430 grams.

b) 99.7%

c) 0.3%

d) 83.85%

Step-by-step explanation:

The empirical rule 68-95-99.7 tells us that:

We have a bell shaped distribution (we can assume as approximately normal) with mean of 330 g. and standard deviation of 50 g.

a) This happens for an interval with ±2 standard deviations from the mean.

That is:

\(X_1=\mu+z_1\cdot\sigma=330-2\cdot 50=330-100=230\\\\ X_2=\mu+z_2\cdot\sigma=330+2\cdot 50=330+100=430\)

About 95% of organs will be within 230 and 430 grams.

b) We can calculate the z-scores for each value to know how many standard deviations are from the mean.

\(z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{180-330}{50}=\dfrac{-150}{50}=-3\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{480-330}{50}=\dfrac{150}{50}=3\\\\\\\)

As the values are 3 standard deviations from the mean each, it is expected that 99.7% of the organs weigh between 180 and 480 grams.

c) This is the complementary of the point b.

Then, it is expected that (100-99.7)%=0.3% of the organs weigh less than 180 grams or more than 480 grams.

d) We can calculate the z-scores for each value to know how many standard deviations are from the mean.

\(z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{280-330}{50}=\dfrac{-50}{50}=-1\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{480-330}{50}=\dfrac{150}{50}=3\\\\\\\)

Between 280 and 330 there is 68%/2=34% of the data.

Between 330 and 480 there is 99.7%/2=49.85% of the data.

Then, between 280 grams and 480 grams there is (34+49.85)%=83.85% of the data.

The cost of students ticket is $37.5and the cost of general admission is $187.5.

A finite set of equations for which common solutions are sought is referred to in mathematics as a set of simultaneous equations, also known as a system of equations or an equation system.

Assume s be the students tickets cost and g be the general admission cost.

From the given information,

⇒  s + g = 225             ..(1)

 5s + 7g = 1500         ..(2)

From equation (1),

s = 225 - g

Plug the value of s in equation (2)

5(225 - g) + 7g = 1500

1125 - 5g + 7g = 1500

                  2g = 1500 - 1125

                  2g = 375

                    g = 187.5

Plug g = 125 in equation (1),

s + 187.5= 225

        s = 225 - 187.5

        s = 37.5

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Answer:

Table B was created using the equation y = 4x-1.

Explanation:

The equation y = 4x-1 means that for any given value of x, the corresponding value of y can be found by multiplying x by 4 and then subtracting 1.

Table B shows input values of x and output values of y that are consistent with this equation. For example, when x = 3, y = 11 (4 * 3 - 1), and when x = 4, y = 15 (4 * 4 - 1), and so on.

Therefore, we can conclude that Table B was created using the equation y = 4x-1.

The equation that best describes the relation is y = -x+1 ( optionD)

A linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order (linear) term, where m is the slope and b is the y-intercept.

Taking x(0,1) and y ( 1,0)

therefore the slope of the line

= 0-1/1-0

= -1/1 = -1

the equation a line is given as

y-y1 = m(x-x1)

= y-1 = -1( x - 0)

= y-1 = -x

y = -x +1

therefore the equation that describe relation is y = 1-x or y = -x+1

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Answer:

f(9) = 189

Step-by-step explanation:

Plug 9 into x

f(9) = 2(9)^2 + 3(9)

f(9) = 2(81) + 27

f(9) = 162 + 27

Thus, f(9) = 189

Answer:

189

Step-by-step explanation:

f(x) = 2x^2 + 3x , f(9)

f(9) = 2(9)^2 + 3(9)

= 2(81) + 27

= 162 + 27

= 189

The initial temperature of the soda is 22 degrees Celsius, and its temperature after 20 minutes is approximately 10 degrees Celsius.

To find the initial temperature of the soda, we need to evaluate the temperature function T(x) at x = 0.

T(x) = -5 + 27e^(-0.03x)

T(0) = -5 + 27e^(-0.03(0))

T(0) = -5 + 27e^0

Since any number raised to the power of 0 is 1, we have:

T(0) = -5 + 27(1)

T(0) = -5 + 27

T(0) = 22

Therefore, the initial temperature of the soda is 22 degrees Celsius.

To find the temperature of the soda after 20 minutes, we evaluate the temperature function at x = 20.

T(x) = -5 + 27e^(-0.03x)

T(20) = -5 + 27e^(-0.03(20))

T(20) = -5 + 27e^(-0.6)

Using a calculator, we can compute e^(-0.6) ≈ 0.5488.

T(20) = -5 + 27(0.5488)

T(20) = -5 + 14.8152

T(20) ≈ 9.8152

Therefore, the temperature of the soda after 20 minutes is approximately 10 degrees Celsius (rounded to the nearest degree).

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The area of the rectangular figure with two semicircles on the opposite side is  36.56 sq cm.

The circumference of a circle is the distance around the circle which is 2πr.

The diameter of a circle is the largest chord that passes through the center of a circle it is 2r.

Given, A rectangle with two semicircles on two opposite sides.

The length of the rectangle is 6cm and the width of the rectangle is 4cm.

The two given semicircles have a diameter of 4cm seems obvious.

∴ The area of the total figure is an area of the rectangle added to the area of 2 semicircles which makes up to a circle with a radius 2 cm.

∴ (4×6) + π(2)² sq cm.

= 24 + 4π sq cm.

= 24 + 12.56 sq cm.

= 36.56 sq cm.

The area which is not taken up in the rectangle and two circle questions are

(area of the rectangle - 2 times the area of a circle).

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For the function  f(x) = 2x + 3 the third iterate x₃  is 37

To find the third iterate, x3, of the function f(x) = 2x + 3, given an initial value of x₀ = 2,

we can apply the function repeatedly.

Starting with x₀ = 2:

x₁ = f(x₀)

= 2(2) + 3

= 7

x₂ = f(x₁)

= 2(7) + 3 = 17

x₃ = f(x₂)

= 2(17) + 3

= 37

Therefore, the third iterate x₃  is 37.

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9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The table and graph are attached.

  x: -2, -1, 0, 1

  y: -1, 1, 3, 5

Answer: I can help you with this.

Step-by-step explanation:

So you have to use the equation and plug in the numbers.

Like; in the table we are given x so u have to find y using the equation. Let's do one for -2

Y = 2x + 3

? = 2 (-2) + 3

Y = - 1

Hope you can do the rest. ‍♀️