14. Sometimes, gas particles are similar to
billiard balls on a pool table. Explain how their
behavior is similar.

2.1 Given that channel A's carrier frequency (100 kHz) and the IF frequency are different, the lowest local oscillator frequency that might be utilised to demodulate the signal on that channel is 50 kHz (50 kHz).

2.2 The difference between the IF frequency and the channel B carrier frequency (150 kHz) determines the lowest local oscillator frequency that could be used to demodulate the signal on channel B. This frequency is 100 kHz (50 kHz).

2.3 The difference between the carrier frequency of channel A and the local oscillator frequency is zero if the local oscillator is set to 100 kHz. Thus, the envelope of the modulated signal in channel A will be represented by a DC voltage (zero frequency) at the mixer's output. The channel B transmission won't be demodulated.

2.4 The difference between the carrier frequencies of channel A and channel B, assuming the local oscillator is set to 125 kHz, is 25 kHz, while the difference between channel B's carrier frequency and the local oscillator frequency is -25 kHz. Hence, the demodulated signal from channel A (1 kHz sinusoid) and the modulated signal will both be present in the mixer's output.

2.5 The difference between the carrier frequency of channel B and the local oscillator frequency is zero if the local oscillator is set to 150 kHz. Thus, the envelope of the modulated signal in channel B will be represented by a DC voltage (zero frequency) at the mixer's output. The channel A transmission won't be demodulated.

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Answer:

       y =\(\frac{1.22L}{D}\) \(\sqrt{\frac{h^2 m}{2eV} }\)

Explanation:

Let's solve this exercise in parts. Let's start by finding the wavelength of the electrons accelerated to v = 10 103 V, let's use the DeBroglie relation

             λ= \(\frac{h}{p} = \frac{h}{mv}\)

Let's use conservation of energy for speed

starting point

             Em₀ = U = e V

final point

             Em_f = K = ½ m v²

             Em₀ = Em_f

             eV = ½ m v²

             v =\(\sqrt{\frac{2eV}{m} }\)

we substitute

             λ=  \(\sqrt{ \frac{h^2 m}{2eV}}\)

the diffraction phenomenon determines the minimum resolution, for this we find the first zero of the spectrum

            a sin θ = m λ

first zero occurs at m = 1, also these experiments are performed at very small angles

            sin θ = θ

            θ = λ / a

This expression is valid for linear slits, in the microscope the slits are circular, when solving the polar coordinates we obtain

           θ = 1.22 λ / D

where D is the diameter of the opening

we substitute

          θ = \(\frac{1.22}{D}\)   \sqrt{ \frac{h^2 m}{2eV}}  

this is the minimum angle that can be seen, if the distance is desired suppose that the distance of the microscope is L, as the angles are measured in radians

            θ = y / L

when substituting

where y is the minimum distance that can be resolved for this acceleration voltage

            y =\(\frac{1.22L}{D}\) \(\sqrt{\frac{h^2 m}{2eV} }\)

what are the options???????????

The force on an electron would be upwards. To achieve this force, the velocity of the proton should be oriented parallel to the magnetic field, as shown below:

A magnetic field with north and south poles, similar to a bar magnet, is created as current flows through the coil. The magnetic field inside the solenoid has a parallel, linear pattern. A solenoid's magnetic field moves from its north pole to its south pole in one direction only.

a) To find the magnitude of the force on the proton, we use the formula:

F = qvBsinθ

where F is the force, q is the charge of the proton, v is its velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field. Plugging in the values given, we get:

\(F = (1.602 * 10^-^1^9 C) * (3.60 m/s) * (0.750 T) * sin(55) = 2.06 * 10^-^1^7 N\)

To find the direction of the force, we use the right-hand rule, which states that if you point your thumb in the direction of the velocity, and your fingers in the direction of the magnetic field, then the force on a positive charge will be perpendicular to both your thumb and your fingers, in a direction given by the palm of your hand. In this case, the force will be pointing downwards, as shown below:

b) The maximum force will be achieved when the velocity of the proton is perpendicular to the magnetic field, since sin(90°) = 1, and the force is proportional to sinθ. In this case, the force will be:

\(F_m_a_x = (1.602 * 10^-^1^9 C) * (3.60 m/s) * (0.750 T) x sin(90) = 3.22 * 10^-^1^7 N\)

To achieve this force, the velocity of the proton should be oriented at a right angle to the magnetic field, as shown below:

The minimum force will be achieved when the velocity of the proton is parallel to the magnetic field, since sin(0°) = 0, and the force is proportional to sinθ. In this case, the force will be zero:

\(F_m_i_n = (1.602 * 10^-^1^9 C) * (3.60 m/s) x (0.750 T) * sin(0) = 0 N\)

To achieve this force, the velocity of the proton should be oriented parallel to the magnetic field, as shown below:

c) For an electron traveling in the same way as the proton, the magnitude of the force would be the same as in part (a), since the only difference between a proton and an electron is their charge (protons are positive, while electrons are negative). However, the direction of the force would be opposite, since electrons have a negative charge. Therefore, the force on an electron would be upwards.

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The direction of the third force, such that the object continues to

move with a constant velocity is  94.5N at 0.19° south of east.

The force that one thing exerts on another. A barrel being pushed by a human is an illustration of applied force. When the individual pushes the barrel, the barrel experiences an applied force. Newton's second law of motion defines the force formula as follows: A force is equal to an object's mass times its acceleration, or F = m a. You must use SI units when applying this formula: kilograms for mass, meters per second squared for acceleration, and newtons for force. a push or pull that an object has experienced. Here, an object is given a force by a person or any other thing. A chair being pushed to the opposite side of the room, for instance.

For the object to move with constant velocity the total acceleration must be zero.

So,

Total  F = \(F_{1} +F_{2} +F_{3}\)

  ma = 0

\(F_{1}\) = 84.4N

\(F_{2}\) = 42.7 N

\(F_{3} = -F_{1} - F_{2}\)

= 94.58 N

TanФ = 0.19°

Hence \(F_{3}\) = 94.5N at 0.19° south of east.

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Answer:

Gravity

gravity pulled the gasses together over long period of time

Answer:

C.

Explanation:

Visual constancy is a key mechanism that allows the perception to remain.the same even as images change

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Visual constancy is  important because it allows perceptions to remain the same even as images change.

Constancy phenomenon describes how people and animals tend to perceive familiar objects as having a constant shape, size, colour, or location regardless of adjustments to distance, illumination, or perspective. Instead of responding to the real stimulus, the impression has a tendency to adapt to the object as it is or is imagined to be.

The ability to recognise things in a variety of situations, which appear to be "taken into account" throughout a process of mental rebuilding of the known image, is a result of perceptual constancy. For instance, snow appears white in both the dim moonlight and the 800,000-fold brighter day. Reduced contextual cues that help with object identification and limited experience with the object both affect perceptual constancy.

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A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.

A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.

Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience

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Considering the Coulomb's Law, the force between the two ballons is 9.216×10⁻⁸ N.

Charged bodies experience a force of attraction or repulsion on approach.

From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.

From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that two balloons have a negative charge of 1.6×10⁻¹⁰ C and the balloons are 0.05 m apart.

Replacing in the Coulomb's Law, you get:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{(-1.6x10^{-10} C)x(-1.6x10^{-10} C)}{(0.05 m)^{2} }\)

Solving:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{2.56x10^{-20} C^{2} }{(0.05 m)^{2} }\)

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } 1.024x10^{-17}\frac{ C^{2} }{m^{2} }\)

F= 9.216×10⁻⁸ N

Finally, the force between the two ballons is 9.216×10⁻⁸ N.

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Answer:

F=2496 N

Explanation:

Given that,

Mass of SUV, m = 1600 kg

Initial speed, u = 0

Final speed, v = 25 m/s

Distance, d = 200 m

We need to find the net force. Firstly, let's find acceleration using equation of motion.

\(v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(25)^2-(0)^2}{2\times 200}\\\\a=1.56\ m/s^2\)

Net force, F = ma

\(F=1600\times 1.56\\\\F=2496\ N\)

So, the net force is 2496 N.

The amount of net force that will be required to accelerate a 1600kg SUV from rest to a speed of 25 m/s in a distance of 200m is 2500N

HOW TO CALCULATE NET FORCE:

Where:

Since a = 1.563m/s²

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The potential and kinetic energy of the system at the following time instances is zero and maximum.

From the given,

The displacement of the system is, x = A cos(3πt/T)

1) At t =0, the displacement of the system is given by, x = cos(3π×0/T)= cos(0) = 1. The displacement is maximum at t=0. Hence, the potential energy is maximum and kinetic energy is zero.

2) At t=T, the displacement, x = cos(3πT/T)= cos(3π) = -1. The displacement is minimum and hence, the potential energy is minimum and kinetic energy is maximum.

3) At t = T/6, the displacement x = cos(3πT/6T)=cos(π/2)=0, the displacement is zero, and hence, both the potential and kinetic energy is zero.

4) At t=T/3, the displacement, x= cos(3πt/T)=cos(3πT/3)= -1. The displacement is minimum and hence, the potential energy is minimum and kinetic energy is maximum.

5) At t=T/2, the displacemetn x = cos(3πt/T) = cos(3πT/2T) = cos (3π/2)=0. Hence, both the potential and kinetic energy is zero.

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The total weight in Newtown is 21.56 N.

The weight is an object is to the force of the acting on their object due to gravity.

Weight is a force described by the   physics which is due  to the gravitation pull of  earth mercury is the

It's magnitude can be the  calculated by multiplying the mass with the by the  acceleration due to gravity but to the

And direction is always to the the centre of earth has

the weight of an object is to the  force acting on their object by the  due to gravity. Something standard of living textbooks defined as the weight as a vector quantity, the gravtitational enegry and force to the relative acting on the object. Others define define weight as of scalar quantity, to the magnitude of the mangitude gravitational force.

Here earth acceleration due to gravity is g= 9.8 ms^-2

And mass is 2+0.2 = 2.2  kg

So weight is 2.2(9.8)

= 21.56 N

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Explanation

Step 1

Diagram:

Step 2

the work done by an object is defined as:

the product of the displacement of an object and the component of the applied force which is in the direction of the object's displacement:

so,let

therefore,l to reduce the amount of force needed , we need to affect the distnace or the angle

Step 3

let's check every option

A)Make the ramp higher.

as the distnace becomes greater the force must increase too, so this is not the rigth option,in other words , a higher distnace will neeed a stronger force

B)making the ramp longer will make the angle becomes smaller, and this makes the distance becomes greater,

C) when yuo make the ramp shorter ,you will need the same force because the displacementis vertical

when the angle becomes smaller, the work will be the same, but the distnace and force, change, cos

when the angle goes to 0° degrees the required force becomes smaller, so

the answer is

b. Make the ramp longer.

D)finally, if yuo lift the object witouth the ramp ( vertically) , the distnace becomes smaller, ( only 3 m),but the force is the total weigth of the object ( 300 N)

I hope this helps you

Answer:

D

Explanation:

In a series circuit there is only one path for the current to complete the path....so D

Answer:

Explanation: Acceleration due to gravity is the acceleration acquired by an object due to the gravitational force. It is a vector quantity, denoted by g and its SI unit is m ... The mass of the earth is about 6E24 kg and the earth radius (Re) is 6371 km which gives G= 9.8m/s/s as the acceleration constant at earth's surface.  I hope this is helpful :)

Acceleration on a body that approached the earth and comes within 6 earth radii of the earth’s surface is 0.2046 m/s²

Acceleration is rate of change of velocity with respect to time.

i.e. a = dv/dt

if an object changes its velocity in short time, we can say that it has grater acceleration.

a= dv/dt =Δv/Δt =  \(\frac{v_{2}- v_{1} }{t_{2}- t_{1}}\)

where    v₂= initial velocity

             v₁= final velocity

             t₂= initial time

             t₁ = final time  

Acceleration due to gravity is nothing but acceleration produced in the body due to gravitational force. According to second newton's second law, F=ma, force is responsible for the acceleration of the body. it is denoted by g and which is equal to 9.8 m/s². Acceleration due to gravity is affected by the height at which a body is from the surface of the earth.

Acceleration due to gravity at height h is given by,

g(h) = GM ÷ (R+h)²

where

g(h) = acceleration due to gravity at height h.

G = universal gravitational constant.

M = mass of the planet(earth)

R= radius of the planet(earth)

h = height of the object from surface.

Given,

G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²

M = 5.97 × 10²⁴ kg

R = 6.3 × 10⁶ m

h=  6R

g(h) = (6.67 × 10⁻¹¹)×(5.97 × 10²⁴) ÷(R+6R)²

g(h) = 3.98×10¹⁴ ÷ (7×6.3 × 10⁶)²

g(h) = 0.2046 m/s²

Hence acceleration due to gravity of body is 0.2046 m/s²

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Answer:

D

Explanation:

the other students are making fun of her most likely because they are jealous that she is successing in school. hope this helps :)

Answer:

D

Explanation:

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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One of the things that are NOT a typical consequence that is associated with open pit mines is the release of high concentrations of ozone into the local environment, causing long-term respiratory harm to individuals and the environment.

The open-pit mine is a surface mining technique used to extract rocks or minerals from the earth using an open-air pit. This technique is used when ore or rock deposits are found near the surface, which makes digging a tunnel unnecessary.

The main consequence of open-pit mine that concerns most people is that it generates a large amount of dust that contains heavy metals to the environment, as well as creating deposits of toxic waste ponds. Ozone is not considered a heavy metal.

Attached below is an image of the Sunrise Dam Gold Mine open pit mine in Australia.

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Answer:

Explanation:

\(y(t) = 5t-5t^2\)

When y(t) = 0, the ball is on the hand.

\(0=5t-5t^2\\0=5t(1-t)\\t=0,1\)

It takes 1 second.

There are several different possibilities.

==>  If the 5.0 means 5 miles per hour, that's 2.24 meters per second, up.

The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (2.24/9.8) = 0.229 second.  Then, after is starts to fall, it takes the same amount of time to the person's hand.

Total time = 0.457 second.

==>  If the 5.0 means 5 meters per second, up . . .

The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (5.0/9.8) = 0.51 second.  Then, after is starts to fall, it takes the same amount of time to the person's hand.

Total time = 1.02 second.

==>  If the 5.0 means 5 km/minute, that's about 83.33 meters per second, up.

The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (83.33/9.8) = 8.503 seconds.  Then, after is starts to fall, it takes the same amount of time to the person's hand.

Total time = 17.01 seconds.

==>  If the 5.0 means 5 furlongs per fortnight, that's about 0.00083 meters per second, up.

The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (0.00083/9.8) = 0.000085 second.  Then, after is starts to fall, it takes the same amount of time to the person's hand.

Total time = 0.00017 second.

This is why all of your numbers always need their units.

Machine Power =? The basketball has a mechanical energy of 46.8 J. Mechanical energy, also known as kinetic energy and potential energy, is the energy that an object possesses when it is in motion .

The gravitational potential energy of an object is transformed into kinetic energy as it falls from rest. Calculating the velocity immediately before it impacts the surface is made possible using the instrument of energy conservation. Naturally, K.E. = J equals the initial potential energy.

An object has mechanical energy when it is moving or when it is in a position different than the position with zero electric potential.  Mechanical energy is produced by a moving vehicle (kinetic energy).Mechanical energy is calculated as follows: Kinetic energy = 30.8 J + Potential energy = 16.0 J = 46.8 J

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Answer:

61.33 Kg

Explanation:

From the question given above, the following data were obtained:

Distance = 1×10² m

Time = 9.5 s

Kinetic energy (KE) = 3.40×10³ J

Mass (m) =?

Next, we shall determine the velocity Leroy Burrell. This can be obtained as follow:

Distance = 1×10² m

Time = 9.5 s

Velocity =?

Velocity = Distance / time

Velocity = 1×10² / 9.5

Velocity = 10.53 m/s

Finally, we shall determine the mass of Leroy Burrell. This can be obtained as follow:

Kinetic energy (KE) = 3.40×10³ J

Velocity (v) = 10.53 m/s

Mass (m) =?

KE = ½mv²

3.40×10³ = ½ × m × 10.53²

3.40×10³ = ½ × m × 110.8809

3.40×10³ = m × 55.44045

Divide both side by 55.44045

m = 3.40×10³ / 55.44045

m = 61.33 Kg

Thus, the mass of Leroy Burrell is 61.33 Kg

Answer:

The initial momentum of the ball is 8 kg-m/s.

Explanation:

Given that,

Mass of the ball is 4 kg

Initial speed of the ball is 2 m/s

Force applied to the ball is 5 N for 3 seconds

It is required to find the initial momentum of the ball. Initial momentum means that the product of mass and initial velocity of the ball. It is given as :

\(p_i=mu\\\\p_i=4\ kg\times 2\ m/s\\\\p_i=8\ kg-m/s\)

So, the initial momentum of the ball is 8 kg-m/s.

Answer:

did you get the answer??

Sustained processes of nuclear fusion occur only in stars. This statement describes one way that nuclear fusion differs from nuclear fission. Hence option C is correct.

When two lighter nuclei are fused together to form heavier nuclei which is called as fusion reaction. It generally involves hydrogen nuclei, In Fusion process two hydrogen nuclei are fused together and helium nucleus is formed, In this process and enormous amount of energy is released. Fusion reaction occurs only in the star like sun. In sun, hydrogen is a fuel which converts into helium that is why we can see that sun is burning.

It is almost impossible to get fusion reaction on the earth, that is why uranium is used in nuclear power plant. In nuclear power plant uranium is converted into two lighter nuclei which is called as fission.

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Answer: The acceleration of the train is 0.1667 m/s^2.

Explanation:

We can use the following kinematic equation to solve this problem:

v = u + at

where:

v is the final velocity (0 m/s, since the train comes to a complete stop)

u is the initial velocity (15.0 m/s)

a is the acceleration of the train (what we're trying to find)

t is the time it takes for the train to come to a stop (90 seconds)

We can rearrange this equation to solve for a:

a = (v - u) / t

Substituting the known values:

a = (0 m/s - 15.0 m/s) / 90 s

a = -0.1667 m/s^2

The negative sign indicates that the train is decelerating (slowing down), which makes sense given the problem statement. Therefore, the acceleration of the train is 0.1667 m/s^2.

Answer:

B. 1200 J

Explanation:

Hello.

In this case, given the powers, we compute the energy transferred as shown below:

\(E=P*t\\\\E_1=60J/s*30s=1800J\\\\E_2=100J/s*30s=3000J\\\\Difference=3000J-1800J\\\\Difference=1200J\)

Therefore, answer is B. 1200 J .

Best regards.

Wundt studies consciousness using introspection because his subjects examined and shared their own feelings and thoughts. Wundt was the first psychologist.

Introspection refers to the examination of one's own mental and/or emotional mechanisms and processes.

Wilhelm Wundt was a distinguished psychologist who demonstrated that introspection is a highly practiced mechanism of self-examination.

W. Wundt developed the theory of conscious thought by indicating that conscious mental states can be scientifically (empirically) studied by using introspection.

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Answer: B His subjects examined and shared their own feelings and thoughts.

Explanation: Just took the test

Answer:

10m

Explanation:

if it was at the 2.0 line it would be 10 m

If a typical atom has a diameter of about 1.0×10⁻¹⁰ m, then there are approximately atoms are there along a 2.0-centimeter line.

In positional notation, significant figures refer to the digits in a number that is trustworthy and required to denote the amount of something, also known as the significant digits, precision, or resolution.

As given in the problem If a typical atom has a diameter of about 1.0×10⁻¹⁰ m, then we have to find out approximately how many atoms are there along a 2.0-centimeter line,

diameter of the one atom =  1.0×10⁻¹⁰

approximate number of atoms in 2 cm line = 2 ×10⁻² /( 1.0×10⁻¹⁰ )

                                                                         =2 ×10⁸ atoms

Thus, there are approximately 2 ×10⁸ atoms are there along a 2.0-centimeter line.

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The magnitude of the charge of the given moveable beads is 9.33 nC.

The tension in the string is calculated as follows;

Tcos45 = mg

where;

F = Tsin45

\(\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }\)

\(q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC\)

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