Answer: x=4
Step-by-step explanation:
Answer:
Step-by-step explanation:
x = 4
(URGENT)An engineer has a 40:1 scale drawing of a bridge. The dimensions of the scaled bridge deck are 24 inches by four and four fifths inches. What is the area of the actual bridge deck in square feet?
460 square feet
640 square feet
960 square feet
1,280 square feet
The area οf the actual bridge deck in square feet is 1,280 square feet.
What is Area?Area refers tο the measurement οf the size οf a twο-dimensiοnal surface, usually measured in square units such as square inches, square feet, οr square meters. It represents the amοunt οf space that is inside the bοundary οf a flat οbject οr shape.
The scale οf the drawing is 40:1, which means that the dimensiοns οf the scaled bridge deck are 40 times smaller than the actual bridge deck. Tο find the area οf the actual bridge deck in square feet, we need tο cοnvert the dimensiοns οf the scaled bridge deck frοm inches tο feet and then multiply by the square οf the scale factοr (40² = 1600).
The dimensiοns οf the scaled bridge deck in feet are:
24 inches = 2 feet
4 and 4/5 inches = 0.4 feet
Sο, the area οf the scaled bridge deck in square feet is:
2 feet x 0.4 feet = 0.8 square feet
Tο find the area οf the actual bridge deck in square feet, we need tο multiply the area οf the scaled bridge deck by the square οf the scale factοr:
Area οf actual bridge deck = 0.8 square feet x (40²) = 1280 square feet
Therefοre, the area οf the actual bridge deck in square feet is 1,280 square feet.
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Answer:
Step-by-step explanation:
The scale factor indicates the actual bridge is 40 times larger than the drawing.
Increase the scale dimensions by the factor of 40.
24 times 40 = 960"
4.8 times 40 = 192" (I changed 4 4/5 to 4.8)
Area = length times width
960 times 192 = 184320 sq inches actual bridge deck in square inches
Divide 183320 by 144 (sq inches in a square foot) = 1280 sq feet
4272/6 use partial qutiants to divide
Answer:
712
Step-by-step explanation:
\(4272/6= 4200/6+72/6\\4272/6= 700 +12\\4272/6=712\)
Hope this helps :D
Consider this equation
1/x-1 = | x-2 |
Using three iterations of successive approximation, what is the approximate solution to the equation? Use the graph as a starting point.
A. x ≈ 43/16
B. x ≈ 21/8
C. x ≈ 41/16
D. x ≈ 19/8
The approximate solution to the equation 1/x-1 = |x-2| after three iterations of successive approximation is x ≈ 5/2 or x ≈ 2.5.
To solve the equation 1/x-1 = |x-2| using three iterations of successive approximation, we will start with an initial guess and refine it using an iterative process.
Given that the equation involves absolute value, we will consider two cases:
Case 1: x - 2 ≥ 0
In this case, |x-2| simplifies to x-2, and the equation becomes 1/(x-1) = x-2.
Case 2: x - 2 < 0
In this case, |x-2| simplifies to -(x-2), and the equation becomes 1/(x-1) = -(x-2).
Now, let's perform the successive approximation:
Iteration 1:
Let's start with an initial guess, x = 2.
Case 1: When x - 2 ≥ 0,
1/(2-1) = 2-2,
1/1 = 0,
which is not true.
Case 2: When x - 2 < 0,
1/(2-1) = -(2-2),
1/1 = 0,
which is not true.
Since our initial guess did not satisfy the equation in either case, we need to choose a different initial guess.
Iteration 2:
Let's try x = 3.
Case 1: When x - 2 ≥ 0,
1/(3-1) = 3-2,
1/2 = 1,
which is not true.
Case 2: When x - 2 < 0,
1/(3-1) = -(3-2),
1/2 = -1,
which is not true.
Again, our guess did not satisfy the equation in either case.
Iteration 3:
Let's try x = 2.5.
Case 1: When x - 2 ≥ 0,
1/(2.5-1) = 2.5-2,
1/1.5 = 0.5,
which is true.
Case 2: When x - 2 < 0,
1/(2.5-1) = -(2.5-2),
1/1.5 = -0.5,
which is not true.
Our guess of x = 2.5 satisfies the equation in Case 1.
Therefore, the approximate solution to the equation 1/x-1 = |x-2| after three iterations of successive approximation is x ≈ 5/2 or x ≈ 2.5.
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What is the surface area of this cylinder? Use ≈ 3.14 and round your answer to the nearest hundredth. 9.4 yd 18.6 yd square yards
The surface area of the cylinder has a radius of 9.4cm and a height of 18.6 cm is 1098.56 square centimeters.
What is the surface area of this cylinder?The surface area of this cylinder is defined as the product of the radius of the base and the height of the cylinder.
The surface area of this cylinder = (2π x r)h
We have given a radius of the base is 9.4 cm and the height of the cylinder is 18.6 cm.
The surface area of this cylinder = (2π x r)h
= (2π x 9.4)18.6
= (59.06)18.6
= 1098.56
Thus, The surface area of the cylinder has a radius of 9.4cm and a height of 18.6 cm is 1098.56 square centimeters.
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Which composition of two rigid motions maps ️ABC to ️A'B'C'
Answer:
C. Translation \((x,y) \longrightarrow (x-7, y+0)\), Reflection in the \(y\)-axis
O EQUATIONS AND INEQUALITIESSolving a compound linear inequality: Interval notation
Explanation
For the given compound inequality
\(\begin{gathered} 3x+6\ge24 \\ or \\ 2x-6>0 \end{gathered}\)We will solve the inequalities independently so that
\(\begin{gathered} 3x+6\ge24 \\ 3x\ge24-6 \\ 3x\ge18 \\ \\ x\ge\frac{18}{3} \\ \\ x\ge6 \end{gathered}\)Also
\(\begin{gathered} 2x-6>0 \\ 2x>6 \\ \\ x>\frac{6}{2} \\ \\ x>3 \end{gathered}\)So, we have
\(x\ge6\text{ or x}>3\)Combining the two rs
Thus, the answer will be
\(\begin{bmatrix}\mathrm{Solution:}\:&\:x>3\:\\ \:\mathrm{Interval\:Notation:}&\:\left(3,\:\infty \:\right)\end{bmatrix}\)A study is done by a community group in two neighboring colleges to determine which college graduates students with more math classes. College A samples 11 graduates. Their average is 4 math classes with a standard deviation of 1.5 math classes. College B samples 9 graduates. Their average is 3.5 math classes with a standard deviation of 1 math class. The community group believes that a student who graduates from college A has taken more math classes, on the average. Test at a 1% significance level.
A. Is this a test of two means or two proportions? Are the populations dependent or independent?
B. Are the populations' standard deviations known or not?
C. Which distribution is to be used?
D. What is random variable?
E. Hypothesis
F. Test is two tailed or one tail
G. Test value=_____.
H. Use P-value method) to reach to the conclusion.
Answer:
A) It is a test of two proportions and the populations are independent of each other
B) The population standard deviations are known : For college A the standard deviation is = 1.5 while for College B population the standard deviation is 1
C) The distribution to be used is 1 distribution
D) The Random variable is the size of the community group
E) Hypothesis : H0 : u1 = u2 . Ha : u1 > u2
F) Test is one tailed
G) Test Value > significance level
F) when; P value > significance level ( 0.01 ) we do accept Null hypothesis
when ; P value < significance level ( 0.01 ) we reject Null hypothesis
Step-by-step explanation:
College A :
sample size = 11
x ( mean ) value = 4
std = 1.5
College B :
sample size = 9
x ( mean value ) = 3.5
std = 1
A) It is a test of two proportions and the populations are independent of each other
B) The population standard deviations are known : For college A the standard deviation is = 1.5 while for College B population the standard deviation is 1
C) The distribution to be used is 1 distribution
D) The Random variable is the size of the community group
E) Hypothesis : H0 : u1 = u2 . Ha : u1 > u2
F) Test is one tailed
G) Test Value > significance level
F) when; P value > significance level ( 0.01 ) we do accept Null hypothesis
when ; P value < significance level ( 0.01 ) we reject Null hypothesis
A logarithmic function, h, is plotted on the graph. What is the approximate rate of change of this function on the interval [-2,2]?
Answer:
C: - 9/8
Step-by-step explanation:
interval: -2 ≤ x ≤ 2
Find 2 coordinate points on the graph where x = -2 and x = 2:
(-2, 2) and (2, -2.5)
Let \((x_1,y_1)\) = (-2, 2) and \((x_2,y_2)\) = (2, -2.5)
rate of change = \(\frac{y_2-y_1}{x_2-x_1}=\frac{-2.5-2}{2+2} =\frac{-4.5}{4}=-\frac{9}{8}\)
Answer:
C. -\(\frac{9}{8}\)
Explanation:
Plato-
About how many times greater is the area ofthe Pacific Ocean than the Atlantic Ocean?Ocean Area (square kilometers)Pacific161.8 × 106Atlantic85,133,000
Given:
Area of Pacific ocean = 161.8 12 x 10⁶ square kilometers
Area of Atlantic ocean = 85133000 square kilometers
Let's find how many times greater is the area of the pacific ocean than the Atlantic ocean.
To find how many times greater, divide the area of the Pacific ocean by the area of the Atlantic ocean.
Thus, we have:
\(\begin{gathered} \frac{161.8\times10^6}{85133000} \\ \\ =\frac{161.8\times10^6}{85.133\times10^6} \\ \\ =1.9 \end{gathered}\)Therefore, the area of the Pacific ocean is 1.9 times greater than the area of the Atlantic ocean.
ANSWER:
1.9 times
Please help me!! I need help asap
Could someone help me out?
The equation of the line is y = -11x + 232
How to determine the equation?The given parameters are:
Slope (m)= -11
Point (x1, y1) = (31, -109)
The linear equation is then calculated as:
y = m(x - x1) + y1
This gives
y = -11(x - 31) - 109
Evaluate the product
y = -11x + 341 - 109
Evaluate the like terms
y = -11x + 232
Hence, the equation of the line is y = -11x + 232
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Given m∠ABC=37°m∠ABC=37°and m∠CBD=165°m∠CBD=165°. According to the Angle Addition Postulate, what is the measure of ∠ABD∠ABD, that contains −−→BCBC→?
According to the Angle Addition Postulate, the measure of m∠ABD = 202°.
What is an angle addition postulate?According to the Angle Addition Postulate, an angle's measure is equal to the sum of the measures of any two adjacent angles. The Angle Addition Postulate can be used to determine the measurement of a missing angle or to determine the angle produced by two or more other angles.
Given:
The angle measures:
m∠ABC=37°,
and m∠CBD= 165°.
So, according to the angle addition postulate;
m∠ABD = m∠ABC + m∠CBD
Substituting the values,
m∠ABD = 37° + 165°
m∠ABD = 202°
Therefore, the angle measure of m∠ABD = 202°.
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Kelly uses cruise control to drive at a constant speed. She travels first 192 miles in 3 hours. At the rate, how long will it take Kelly to drive a total of 448 miles?
Answer:
Step-by-step explanation:
rate = d / t
rate = 192 / 3
rate = 64 miles / hour
Now you want to know how long it can take to get 448 miles
d = r * t
t = d / r
t = 448/64
t = 7 hours.
You could actually do it using proportions.
192/3 = 448/x Cross multiply
192*x = 448*3
192*x = 1344 Divide by 192
x = 1344/192
x = 7
Do this the way you feel is the best way.
The table represents a linear relationship
X—2 0 4
Y-4 3 1
Which equation represents the table
Y=1/2x+5
y=-1/2x+3
Y=2x-3
Y=-4x+2
The linear relationship illustrated in the provided table can be effectively described by the equation Y = -4x + 2. Option D.
To determine the equation that represents the given table with the values of x and y, we can observe the pattern and find the equation of the line that fits these points.
Given the table:
X: 2 0 4
Y: -4 3 1
We can plot these points on a graph and see that they form a straight line.
Plotting the points (2, -4), (0, 3), and (4, 1), we can see that they lie on a line that has a negative slope.
Based on the given options, we can now evaluate each equation to see which one represents the line:
Y = 1/2x + 5
When we substitute the x-values from the table into this equation, we get the following corresponding y-values: -3, 5, and 6. These values do not match the given table, so this equation does not represent the table.
Y = -1/2x + 3
When we substitute the x-values from the table into this equation, we get the corresponding y-values: 4, 3, and 2. These values also do not match the given table, so this equation does not represent the table.
Y = 2x - 3
When we substitute the x-values from the table into this equation, we get the corresponding y-values: -4, -3, and 5. These values do not match the given table, so this equation does not represent the table.
Y = -4x + 2
When we substitute the x-values from the table into this equation, we get the corresponding y-values: -6, 2, and -14. Interestingly, these values match the y-values in the given table. Therefore, the equation Y = -4x + 2 represents the table.
In conclusion, the equation Y = -4x + 2 represents the linear relationship described by the given table. So Option D is correct.
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Given the graphed function below, which of the following ordered pairs are found on the inverse function? A. (8, -2), (5, -1), (2, 0), (-4, 2) B. (-8,1), (-5, 1), (-2, 0), (1, -1), (4, -2) C. (-2, -8), (-1, -5), (0, -2), (1, 1), (2, 4) D. (-8, 2), (-5, 1), (-2, 0), (1, 1), (4, 2)
The ordered pairs that can be found on the inverse functions are: (8,-2), (5,-1), (2,0), (-1,1), (-4,2)
How to determine the inverse function?The attached image represents the missing information in the question
From the graph, we have the following ordered pairs:
(x,y) = (-2, 8), (-1, 5), (0,2), (1,-1) and (2,-4)
Next, we swap the coordinates:
(y,x) = (8,-2), (5,-1), (2,0), (-1,1), (-4,2)
Hence, the ordered pairs that can be found on the inverse functions are: (8,-2), (5,-1), (2,0), (-1,1), (-4,2)
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Its factorial math pleaseHelp.
\(\dfrac{7!4!}{5!3!}=6\cdot7\cdot4=168\)
Two statistics teachers both believe that each has the smarter class. To put this to the test, they give the same final exam to their students. A summary of the class sizes, class means, and standard deviations is given below:n1 = 47, x-bar1 = 84.4, s1 = 18n2 = 50, x-bar2 = 82.9, s2 = 17Is there evidence, at an ?=0.04 level of significance, to conclude that there is a difference in the two classes? Carry out an appropriate hypothesis test, filling in the information requested.How do I find the standardized test statistic and the p-value?Your decision for the hypothesis test: A. Do Not Reject H0. B. Do Not Reject Ha. C. Reject H0. D. Reject Ha.
Answer:
We conclude that there is no difference between the two classes.
Step-by-step explanation:
We are given that two statistics teachers both believe that each has a smarter class.
A summary of the class sizes, class means, and standard deviations is given below:n1 = 47, x-bar1 = 84.4, s1 = 18n2 = 50, x-bar2 = 82.9, s2 = 17
Let \(\mu_1\) = mean age of student cars.
\(\mu_2\) = mean age of faculty cars.
So, Null Hypothesis, \(H_0\) : \(\mu_1=\mu_2\) {means that there is no difference in the two classes}
Alternate Hypothesis, \(H_A\) : \(\mu_1\neq \mu_2\) {means that there is a difference in the two classes}
The test statistics that will be used here is Two-sample t-test statistics because we don't know about the population standard deviations;
T.S. = \(\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }\) ~ \(t_n_1_+_n_2_-_2\)
where, \(\bar X_1\) = sample mean age of student cars = 8 years
\(\bar X_2\) = sample mean age of faculty cars = 5.3 years
\(s_1\) = sample standard deviation of student cars = 3.6 years
\(s_2\) = sample standard deviation of student cars = 3.7 years
\(n_1\) = sample of student cars = 110
\(n_2\) = sample of faculty cars = 75
Also, \(s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }\) = \(\sqrt{\frac{(47-1)\times 18^{2}+(50-1)\times 17^{2} }{47+50-2} }\) = 17.491
So, the test statistics = \(\frac{(84.4-82.9)-(0)}{17.491 \times \sqrt{\frac{1}{47}+\frac{1}{50} } }\) ~ \(t_9_5\)
= 0.422
The value of t-test statistics is 0.422.
Now, the P-value of the test statistics is given by;
P-value = P(\(t_9_5\) > 0.422) = From the t table it is clear that the P-value will lie somewhere between 40% and 30%.
Since the P-value of our test statistics is way more than the level of significance of 0.04, so we have insufficient evidence to reject our null hypothesis as our test statistics will not fall in the rejection region.
Therefore, we conclude that there is no difference between the two classes.
Please help quickly I’m not completely sure on this one
The two inequalities have all the solutions larger than 4 in common.
Which solutions are common for both inequalities?To check this, we just need to solve both inequalities:
The first one is:
-2(c - 4) ≤ -4
-2c + 4 ≤ -4
4 + 4 ≤ 2c
8/2 ≤ c
4 ≤ c
The second one gives:
(1/2)d - 6 > -4
Solving it for d:
(1/2)d > -4 + 6
d > 2*2
d > 4
Then the solutions are:
c ≥ 4
d > 4
The inequalities have almost all the solutions in common, except for c = 4 which is a solution for the first one but not for the second one.
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This diagram shows the blue prints a contractor drew for a ramp. In order for the ramp to meet safety regulations, the angle created by the bottom of the ramp and the ground should be no more than 18°.
How many degrees should the contractor lower the ramp by in order to meet safety regulations?
Enter your answer, rounded to the nearest tenth, in the box.
The contractor should lower the ramp by approximately 4.62° to meet safety regulations.
We have,
To determine the angle created by the bottom of the ramp and the ground, we can use the trigonometric function of sine.
In the given triangle, the height is 6 ft and the base is 16 ft.
The angle we want to find is opposite the height (let's call it θ).
The sine of an angle is defined as the ratio of the opposite side to the hypotenuse.
sin(θ) = opposite/hypotenuse
sin(θ) = 6/16
sin(θ) = 0.375
To find the angle θ, we can take the inverse sine (also known as arcsine) of 0.375:
θ = arcsin(0.375)
θ ≈ 22.62°
To meet safety regulations, the angle should be no more than 18°. Therefore, the contractor needs to lower the ramp by:
22.62° - 18° ≈ 4.62°
Thus,
The contractor should lower the ramp by approximately 4.62° to meet safety regulations.
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Let p represent "He is able" and let q represent "He will win." Translate Translate p- into a verbal sentence.
Answer:
He will is able win
Step-by-step explanation:
Answer:
he is able to win
Step-by-step explanation:
The red-tailed tropic bird, Phaethon rubricauda, is an extremely rare sea bird that nests on several islands of the Queensland coast of Australia. As part of a conservation e ort to manage these endangered birds, every nesting pair was measured and weighed. Below are the body weights of these birds (in kg).
Female 2.45 2.57 2.81 2.37 2.01 2.50 2.32
Male 2.86 2.65 2.75 2.60 2.30 2.49 2.84
Required:
a. Determine the following descriptive characteristics for the weights of the females: mean, variance, and standard deviation. Is this a sample or population? Again, pay attention to number of decimal places and appropriate units.
b. Determine the mean, variance, and standard deviation for the male weights.
Answer:
This is a population
a) Female
Mean : 2.432857143kg
Variance: 0.05162040817kg
Standard deviation: 0.2272012504kg
b) Male
Mean : 2.641428571kg
Variance : 0.03432653062kg
Standard deviation: 0.1852742039kg
Step-by-step explanation:
a. Determine the following descriptive characteristics for the weights of the females: mean, variance, and standard deviation. Is this a sample or population? Again, pay attention to number of decimal places and appropriate units.
a) Female: 2.45 2.57 2.81 2.37 2.01 2.50 2.32
Mean
The formula = Sum of term/ Number of terms
Mean = 2.45 + 2.57 + 2.81 + 2.37 + 2.01 + 2.50 + 2.32/7
17.03/7
= 2.432857143kg
Variance
This is a population
Hence: The formula for Population variance =
= (X - Mean)²/N
Where N = Number of terms = 7
= (2.45 - 2.432857143)² + (2.57 -2.432857143)² + (2.81 -2.432857143)² + (2.37- 2.432857143)²+ (2.01 - 2.432857143)²+ (2.50 - 2.432857143)² + (2.32 - 2.432857143)² /7
= 0.0002938775509 + 0.01880816325 + 0.1422367347 + 0.003951020409 + 0.1788081633 + 0.004508163265 + 0.0127367347/7
= 0.3613428572/7
= 0.05162040817kg
Standard Deviation
Formula = √Variance
= √0.05162040817
= 0.2272012504kg
b. Determine the mean, variance, and standard deviation for the male weights
Male 2.86 2.65 2.75 2.60 2.30 2.49 2.84
Mean
The formula = Sum of term/ Number of terms
= 2.86 + 2.65 + 2.75 + 2.60 + 2.30 + 2.49 + 2.84/7
= 18.49/7
= 2.641428571 kg
Variance
= ( 2.86 -2.641428571)² + (2.65 - 2.641428571)² + (2.75 -2.641428571)² + (2.60 +2.641428571)² + (2.30 - 2.641428571)² + (2.49+2.641428571)² (2.84 + 2.641428571)²/7
= 0.0477734694 + 0.00007346938775 + 0.01178775511 + 0.001716326531 + 0.1165734694 + 0.02293061224 +! 0.03943061226/7
= 0.2402857143/7
= 0.03432653062kg
Standard Deviation
= √Variance
= √0.03432653062
= 0.1852742039kg
19. You priced buy a car for $26,635, including taxes and license fees. You will pay $7,000 for down payment and will finance the balance of the loan at 6.41% for three years. Compute a) your monthly payment; and b) total interest for the loan.
a) The Monthly Payment will be $598.5
b) The total interest for the loan will be $1,911.
What is the interest rate?
The amount of interest due each period expressed as a percentage of the amount lent, deposited, or borrowed is known as an interest rate. The total interest on a loaned or borrowed sum is determined by the principal amount, the interest rate, the frequency of compounding, and the period of time the loan, deposit, or borrowing took place.
Here, we have
Given: You priced to buy a car for $26,635, including taxes and license fees. You will pay $7,000 as the down payment and will finance the balance of the loan at 6.41% for three years.
a) Loan Amount (P) = $19,635 [$26,635 - $7,000]
Monthly Interest Rate (n) = 0.511% per month [6.14% / 12 Months]
Number of months (n) = 36 Months [3 Years x 12 months]
Monthly Loan Payment = [P x {r (1+r)ⁿ} ] / [( 1+r)ⁿ – 1]
= [$19,635 x {0.00511 x (1 + 0.00511)³⁶}] / [(1 + 0.00511)³⁶ – 1]
= [$19,635 x {0.00511 x 1.2014048}] /[1.2014048 -1]
= [$19,635 x 0.0061391]/0.2014048
= 598.5 per month.
Hence, the Monthly Payment will be $598.5
b) Total Interest for the Loan
Total Interest for the Loan = Total Payment – Loan Amount
= [$598.5 per month x 36 Months] - $19,635
= $21,546- $19,635
= $1,911
Hence, the total interest for the loan will be $1,911.
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A road map is drawn to the scale of 1 inch equals 20 miles. How far apart in miles are two towns which are 2 1/2 inches apart on the map?
50
Step-by-step explanation:
You set this up with a ratio, 1:20 or 1 equals 20 miles. So i'm multiplying by 20 regardless. Now I have 2 and a half inches or you can say 2.5. Multiply 2.5 (on paper..) and 20 and there you go. 20 times 2 equals 40 and 20 times a half is 10, 40 + 10= 50.
Use the graph below to find the following:
A) what is the slope of the line?
B) what is the y intercept of the line?
C) what is the equation of the line in slope intercept form?
On average, teens spend 4 hours a week using the Internet and 4 hours doing chores. They spend 10 hours listening to the radio. What percent of the total time teens spend using the Internet and doing chores is the time they spend listening to the radio?
The percent of the total time teens spend using the Internet and doing chores is the time they spend listening to the radio is 55.56%.
How the percentage is calculatedTime spent using the internet = 4 hours
Time spent doing chores = 4 hours
The time spent listening to the radio = 10 hours
The total time spent during the week is 4 + 4 + 10 = 18 hours
The percentage of this total time that is spent listening to the radio is:
(10 hours / 18 hours) x 100% =55.56%
This is basic arithmetic operations and is used in calculation of numbers.
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Darren says that more students hands are 4 2/4 inches longer than 4 and 5 1/4 inches combined. is he right?Explain you're answer
In a case whereby Darren says that more students hands are 4 2/4 inches longer than 4 and 5 1/4 inches combined, he is wrong
What is the justification?
\(4\frac{2}{4}\) that was given in the question can be seen as mixed fraction, we can expressed this as improper fraction so that it will be easier to handle.
\(4\frac{2}{4} = \frac{16+4}{2}\)
=\(\frac{18}{4}\)
Then \(4 + 5\frac{1}{4} = \frac{16}{4} +\frac{20+1}{4} \\\\=\frac{37}{4}\)
Then after expressing the given fractions as improper fraction we can now compare them so that e will know may be Darren is right or wrong, then here we can see that \(\frac{18}{4}\) is less than \(\frac{37}{4}\) Hence, Darren is wrong.
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Calculate the monthly loan payment
Loan amount: 60000
Down payment: 4000
Interest rate: 13%
Term: 60 months (5 years)
The monthly loan payment for a $60,000 loan with a $4,000 down payment, 13% interest rate, and a term of 60 months is approximately $1,289.49.
To calculate the monthly loan payment, we need to use the loan amount, down payment, interest rate, and term.
Loan amount: $60,000
Down payment: $4,000
Principal amount: Loan amount - Down payment = $60,000 - $4,000 = $56,000
Interest rate: 13% per annum (or 0.13 as a decimal)
Monthly interest rate: 13% / 12 = 0.0133 (approx.)
Term: 60 months (5 years)
Now, let's calculate the monthly loan payment using the formula for a fixed-rate loan:
Monthly payment = P * (r * (1 + r)^n) / ((1 + r)^n - 1)
Where:
P = Principal amount
r = Monthly interest rate
n = Total number of payments
Substituting the values into the formula:
Monthly payment = $56,000 * (0.0133 * (1 + 0.0133)^60) / ((1 + 0.0133)^60 - 1)
Using a calculator, the approximate monthly loan payment comes out to be $1,289.49.
Therefore, the monthly loan payment for a $60,000 loan with a $4,000 down payment, 13% interest rate, and a term of 60 months is approximately $1,289.49.
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The graph of the relationships ( dogs,cost) is a line that contains the points(0,0) (3,12) and (6,24). What is the constant of proportionality?
4 is the constant of proportionality of given graph.
What is Graph?Graph is a mathematical representation of a network and it describes the relationship between lines and points.
Given,
The graph of the relationships ( dogs,cost) is a line that contains the points(0,0) (3,12) and (6,24).
We need to find the constant of proportionality
The constant of proportionality is the ratio that relates two given values in what is known as a proportional relationship.
To find the constant of proportionality, we have to divide the value of y by x.
12/3=4
24/6=4
Hence, 4 is the constant of proportionality of given graph.
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correct to 3 significant figures , the value of 18.75-(2.11)²
Answer:3.657 hope this helps
Step-by-step explanation:
1. 4 points Last season Steven made 74% of the free throws in his basketball games. In the first two games this season he got to shoot 16 free throws. If his free throw percentage holds from last season, about how many free throws did Steven make during these two games? A 8 B 9 C 10 D 12
Given:
Percentage of free throws last season = 74%
This season he got to shoot 16 free throws in the first two games this season.
Since his free throw percentage holds from last season, this means that the percentage this season will also be 74%.
To find how many free throws Steven made during these two games, we have:
\(\frac{74}{100}\ast16\text{ = }11.84\text{ }\)Therefore, Steven made about 12 free throws during these two games.
ANSWER:
D. 12