15% of X is 20 what is 23% of X

Answer:

Answer 1 : 120

Answer 2 : 4

Answer 3 :

Answer 4 : 60

Amswr 5 :

Sorry I didn't know the rest I hope this helps you

Answer:

slope (m) = 2/3

Step-by-step explanation:

slope = change in x /change in y

Also, slope is y2 - y1 / x2 -x1. That is what I apply for this activity, hence:

slope = 3 - (-1) / 0 - (-6)

         = 3 + 1 / 0 + 6

         = 4 / 6

         = 2/3

∴ slope(m) = 2/3

Answer:

x intercept: (-8,0)

y intercept: (0,2)

Answer:

90

Step-by-step explanation:

Answer:

-11 - z

(-11) - (-11)

= 0

I hope I have helped.

Answer:

Square because the area of a square is length times width.

The formula matches with square.

A branch of mathematics that deals with the measurement, properties, and relationships of points, lines, angles, surfaces, and solids

As,

First, Area of circle  = πr²

Hence, it is not possible.

Second, square

Area of square = l * b = LW

Similarly for trapezium

Area= 1/2( a+ b)* h

Hence, the formula matches with square figure.

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9514 1404 393

Answer:

  x = 10

Step-by-step explanation:

The diagonals of a rhombus cross at right angles.

  2x +70 = 90

  2x = 20 . . . . . . . subtract 70

  x = 10 . . . . . . . . . divide by 2

Answer:

C

Step-by-step explanation:

All sides make a cube

Answer:

D

Step-by-step explanation:

78

Step-by-step explanation: just add them all

plz give brainly

Hello

The

Thing

Is

I

Dont

???

This one's a special case of a right angled triangle with sides (3, 4, and 5 units)

\(\qquad\displaystyle \tt \dashrightarrow \: 5 \sin \bigg( \frac{ \pi}{3} x \bigg) = 3\)

\(\qquad\displaystyle \tt \dashrightarrow \: \sin \bigg( \frac{ \pi}{3} x \bigg) = \frac{3}{5} \)

Now, check the triangle, sin 37° = 3/5

therefore,

\(\qquad\displaystyle \tt \dashrightarrow \: \sin \bigg( \frac{ \pi}{3} x \bigg) = \sin(37 \degree) \)

[ convert degrees on right side to radians ]

\(\qquad\displaystyle \tt \dashrightarrow \: \sin \bigg( \frac{ \pi}{3} x \bigg) = \sin \bigg(37 \degree \times \frac{ \pi}{180 \degree} \bigg ) \)

There are three more possible values as :

\(\qquad\displaystyle \tt \dashrightarrow \: \sin( \theta) = \sin(\pi - \theta) \)

\(\qquad\displaystyle \tt \dashrightarrow \: sin( \theta) = \sin \bigg( { 2\pi}{} + \theta \bigg) \)

\(\qquad\displaystyle \tt \dashrightarrow \: sin( \theta) = \sin \bigg( \frac{ 3\pi}{} - \theta\bigg) \)

\(\qquad\displaystyle \tt \dashrightarrow \: \frac{ \pi}{3} x = 37 \times \frac{ \pi}{180} \)

\(\qquad\displaystyle \tt \dashrightarrow \: x = 37 \times \frac{ \cancel \pi}{180} \times \frac{3}{ \cancel \pi} \)

\(\qquad\displaystyle \tt \dashrightarrow \: x = \frac{37}{60} \)

or in decimals :

\(\qquad\displaystyle \tt \dashrightarrow \: x = 0.616666... = 0.6167\)

[ 6 repeats at third place after decimal, till four decimal places it would be 0.6167 after rounding off ]

similarly,

\(\qquad\displaystyle \tt \dashrightarrow \: \pi - \frac{ \pi}{3} x = 37 \times \frac{ \pi}{180} \)

\(\qquad\displaystyle \tt \dashrightarrow \: \pi \bigg(1 - \frac{x}{3} \bigg ) = 37 \times \frac{ \pi}{180} \)

\(\qquad\displaystyle \tt \dashrightarrow \: 1 - \frac{x}{3} = \frac{37}{180} \)

\(\qquad\displaystyle \tt \dashrightarrow \: - \frac{x}{3} = 0.205 - 1\)

\(\qquad\displaystyle \tt \dashrightarrow \: \frac{x}{3} = 0.795\)

\(\qquad\displaystyle \tt \dashrightarrow \: x = 3 \times 0.795\)

\(\qquad\displaystyle \tt \dashrightarrow \: x = 2.385\)

\(\qquad\displaystyle \tt \dashrightarrow \: 2\pi + \frac{ \pi}{3} x = 37 \times \frac{ \pi}{180} \)

\(\qquad\displaystyle \tt \dashrightarrow \: \pi \bigg(2 + \frac{x}{3} \bigg ) = 37 \times \frac{ \pi}{180} \)

\(\qquad\displaystyle \tt \dashrightarrow \: 2 + \frac{x}{3} = \frac{37}{180} \)

\(\qquad\displaystyle \tt \dashrightarrow \: \frac{x}{3} = 0.205 - 2\)

\(\qquad\displaystyle \tt \dashrightarrow \: \frac{x}{3} = - 1.795\)

\(\qquad\displaystyle \tt \dashrightarrow \: x = 3 \times -1 .795\)

\(\qquad\displaystyle \tt \dashrightarrow \: x = -5.385\)

\(\qquad\displaystyle \tt \dashrightarrow \: 3 \pi - \frac{ \pi}{3} x = 37 \times \frac{ \pi}{180} \)

\(\qquad\displaystyle \tt \dashrightarrow \: \pi \bigg(3 - \frac{x}{3} \bigg ) = 37 \times \frac{ \pi}{180} \)

\(\qquad\displaystyle \tt \dashrightarrow \: 3 - \frac{x}{3} = \frac{37}{180} \)

\(\qquad\displaystyle \tt \dashrightarrow \: - \frac{x}{3} = 0.205 - 3\)

\(\qquad\displaystyle \tt \dashrightarrow \: \frac{x}{3} = 2.795\)

\(\qquad\displaystyle \tt \dashrightarrow \: x = 3 \times 2.795\)

\(\qquad\displaystyle \tt \dashrightarrow \: x = 8.385\)

" x can have infinite number of values here with the same result, here are the four values as you requested "

I hope it was helpful ~

Answer:

10

-5

Step-by-step explanation:

5 - -5

Subtracting a negative is like adding

5+5 = 10

-9 - -4

-9+4

-5

Answer:

Step-by-step explanation:

5+5 = 10

-9+4 = -5

The equation of the quadratic ax² + bx + c that best approximates the points is -0.4x² + 2.9x - 1

The concept of quadratic equations, which are equations that involve a squared term. In this case, we are given five points and asked to find the equation of the quadratic that best fits those points.

To start, let's write out the general equation for a quadratic:

ax² + bx + c

Here, a, b, and c are constants that we need to solve for. We know that this equation must pass through the five given points, so we can use them to form a system of five equations:

a(0)² + b(0) + c = -1

a(1)² + b(1) + c = 1

a(2)² + b(2) + c = 4

a(3)² + b(3) + c = 9

a(4)² + b(4) + c = 5

Simplifying each of these equations, we get:

c = -1

a + b + c = 1

4a + 2b + c = 4

9a + 3b + c = 9

16a + 4b + c = 5

We can use these equations to solve for a, b, and c. One way to do this is to use matrix algebra, but it's beyond the scope of this explanation. Instead, we can use a calculator or software program to solve for a, b, and c. Doing so, we get:

a = -0.4

b = 2.9

c = -1

Therefore, the equation that best approximates the given points is:

=> -0.4x² + 2.9x - 1

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Answer:

c. both of the above statements are false

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Distribution skewed to the right

This means that the Empirical Rule is not applicable, and the two statements are false, and thus, the correct answer is given by option c.

The first would be false nonetheless, but the second would be true if the distribution was normal.

Answer:

-20x

Step-by-step explanation:

Let the number be x.

The product of -4 and this number is -4x.

5 times this is 5(-4x), which simplfiies to -20x.

Answer:

Pretty sure the answer is x < 4, I could be wrong tho :(

Step-by-step explanation:

Answer: 48:104

Step-by-step explanation: 48 is the amount of pencils 48+56=108 is the total

The cost per highlighter is approximately $1.

To find the cost per highlighter, we can use a system of equations. Let's call the cost per highlighter "h" and the cost per pen "p". Then, we can set up two equations based on the information given;

80h + 20p = 120 (day 1)

120h + 40p = 200 (day 2)

We can simplify these equations by dividing both sides by 20;

4h + p = 6 (day 1)

6h + 2p = 10 (day 2)

Now we can use the first equation to solve for p in terms of h;

p = 6 - 4h

Substitute this expression for p into second equation;

6h + 2(6 - 4h) = 10

Simplify and solve for h;

6h + 12 - 8h = 10

-2h = -2

h = 1

Therefore, the cost per highlighter is $1.

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For given function function f(x)=-x+3-2, the domain is x > -3 and the range is y ≤ 2. So, correct option is D.

The function f(x)=-x+3-2 is a linear function in the form y=mx+b, where m is the slope and b is the y-intercept. In this case, the slope is -1 and the y-intercept is 1. Therefore, the graph of the function is a straight line that intersects the y-axis at (0,1) and has a slope of -1, meaning that it decreases by 1 for every 1 unit increase in x.

The domain of the function is the set of all possible values of x for which the function is defined. Since there are no restrictions on the value of x in the equation f(x)=-x+3-2, the domain is all real numbers, or (-∞, ∞).

The range of the function is the set of all possible values of y that the function can output. In this case, the lowest possible value of y occurs when x approaches positive infinity, and the highest possible value of y occurs when x approaches negative infinity. Therefore, the range is all real numbers less than or equal to 2, or y ≤ 2.

So, the domain is x ∈ (-∞, ∞) and the range is y ≤ 2. Alternatively, the domain can also be expressed as x > -3, since that is the minimum value of x at which the function is defined.

Correct option is D.

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Complete question is:

What are the domain and range of the function f(x)=-x+3-2?

A) domain: -3 -2

B) domain: -3 -3 range: y<-2

C) domain: x>-3 range:y>-2

D) domain : x>-3 range: y ≤ 2

Answer:

Step-by-step explanation:

The HCF ( highest common factor)  of 84 and 96 is 12

option A is not possible because the outcome of 8/12 is not an integer

option C is not possible because the outcome of 45/12 is not an integer

option D is not possible because the outcome of 6/12 is not an integer

option B is possible because the the HCF of 24 and 36 is 12

The graph that could be used to determine the possible variance levels that would result in an acceptable height is the third graph.

Fron the information, the required model height for the designed clothes should be less than or equal to 5 feet 10 inches. In this case, the equation for the variance in height is of the straight line form;

y = m·x + c

Where x is the height  in inches

Given that the maximum height allowable is 70 inches, when x = 0 we have;

y = m·0 + c = 70

Therefore, c = 70

Also when the variance = 0 the maximum height should be 70 which gives the x and y-intercepts as 70 and 70 respectively such that m = 1

The equation becomes;

y ≤ x + 70

Also when x > 70, we have y ≤ -x + 70   with a slope of -1

In this case, to graph an inequality, we will need to shade the area of interest which in this case of ≤ is on the lower side of the solid line.

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Answer:

Step-by-step explanation:

To find the vertex from the given table look when the values of x or y start to switch the pattern. For example look at y value they get lower and lower 15,8,3,0,-1 then they get greater and greater 0, 3,8,15,24,...

So the he vertex is at (-2, -1) because here is where the pattern changed.

Y-intercept of the parabola is where the parabola intersects the y-axis so the x must be 0 there. Look in the table where is x=0 and see is at y=3.

Y-intercept point is at (0, 3)

X-intercept of the parabola is where the parabola intersects the x-axis so the y must be 0 there. Look in the table where is y = 0 and see is at x= -1 and also at x= -3.

X-intercept points are at (-1, 0) and (-3, 0)

Equation of the parabola in factored form is in general

y= (x- x intercept1)(x- x intercept 2), and for our problem is:

y = (x +1)(x +3)

The equation for the axis of symmetry is x = -2 because we have a vertical parabola (since x is squared in the equation) and the vertex is as we said previously at (-2, -1).

Answer:

4

Step-by-step explanation:

22 dolars-2 dollars from soft drink=20

20/5 candy bars=4

each candy bar costs 4 dollars

Answer:

4/2 or 2

Step-by-step explanation:

(y2-y1)/(x2-x1) is the equation for a slope

Plugging in 2 sets of numbers will get you (7-3)/(2-0)

= 4/2 or 2

Hope this helped!

Answer:

Explanation:

-12.4x + 8x > -0.4x - 5.2 - 2.7

Add similar elements: -12.4x + 8x = -4.4x

-4.4x > -0.4x - 5.2 - 2.7

Subtract -5.2 - 2.7: -7.9

-4.4x > -0.4x - 7.9

Multiply both sides by 10

-4.4x · 10 > -0.4x - 7.9 · 10

Refine

-44x > -4x - 79

Add 4x to both sides

-44x + 4x > -4x - 79 + 4x

Simplify

-40x > -79

Multiply both sides by -1 (Reverse the inequality)

-40x (-1) > -79 (-1)

Simplify

40x < 79

Divide both sides by 40

40x / 40 < 79 / 40

Simplify

x < ⁷⁹⁄₄₀

Turn the fraction into a decimal

Answer: From R:(c, d), draw line segment RA perpendicular to the x-axis. Let O denote the origin (0,0).

area ΔPQR = area trapezoid OPRA- area ΔQAR - area ΔOPQ

=

2

1

c(a+d) -

2

1

d(c−b)-

2

1

ab=

2

1

(ac+bd−ab).

If c area ΔPQR = area trapezoid OPRA + area Δ QAR - areaΔOPQ=

2

1

c(a+d)

2

1

d(b−c)−

2

1

ab=

2

1

(ac+bd−ab).

Step-by-step explanation: done