Answer:
Step-by-step explanation:
The surface area of a cube = 6a2 where a is the length of the side of each edge of the cube. Put another way, since all sides of a cube are equal, a is just the lenght of one side of a cube. We have 96 = 6a2 → a2 = 16, so that's the area of one face of the cube.
6x + 8 greater than or equal to 1
Answer:
\(x\leq-\frac{7}{6}\)
Step-by-step explanation:
\(6x+8\geq1\\6x\geq-7\\x\leq-\frac{7}{6}\)
The answer is:
x ≥ -7/6
Work/explanation:
The symbol for greater than or equal to is ≥.
The inequality is:
6x + 8 ≥ 1
Subtract 8 on each side
6x > -7
Divide each side by 6.
x > -7/6
Hence, the answer is x > -7/6.
What is the largest whole number value of n that your calculator will display in standard notation? a. 3^n b. pi^n c. 12^n d. 237^n. What is the smallest value of n that your calculator will display in scientific notation? a. 10^n b. 100^n c. 1000n^n
The largest whole number value of n that your calculator will display in standard notation is d. 237^n.The smallest value of n that your calculator will display in scientific notation is b. 100^n. A calculator can display numbers in either standard or scientific notation.
Standard notation is the usual way of representing numbers, while scientific notation is used to represent very large or very small numbers. In standard notation, a number is written as an integer or a decimal. In scientific notation, a number is written in the form of a x 10^n, where a is a number between 1 and 10 and n is an integer. For example, the number 123,000,000 can be written in scientific notation as 1.23 x 10^8.
The largest whole number value of n that your calculator will display in standard notation is d. 237^n. This means that the calculator can display any number that is less than or equal to 237^n in standard notation. For example, if n is equal to 3, then the calculator can display any number that is less than or equal to 237^3 = 12,441,093. In contrast, the smallest value of n that your calculator will display in scientific notation is b. 100^n. This means that the calculator can display any number that is greater than or equal to 100^n in scientific notation. For example, if n is equal to 2, then the calculator can display any number that is greater than or equal to 100^2 = 10,000.
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A family is calculating the cost for one semester of college next year. Each hour of class will cost $155. A
scholarship gift of $64 can be deducted from costs. If h is the number of hours taken, and c is the total cost,
which equation can be used to calculate the total tuition costs for a semester?
Answer:
h x c
Step-by-step explanation:
PLS HELP WILL GIVE BRAINLIEST ALMOST DUE
Which equation could represent the line of best fit for the temperatures based on the altitudes?
Answer:
\(y = - \frac{7}{5} x + 59\)
what is x ÷ t/4 = -6/13
Answer:
look at explanation
Step-by-step explanation:
first you need to find what -6/13 is and once you do that you fill everything in pretty much
Can someone help me with this
Answer:
I can't see the sign between 2 and (1/3)^3 in the last question, it's a bit blurry. You should send it again.
Step-by-step explanation:
please mark BRAINLIEST
sara is researching phones and decides to create a weighted average to determine the 'best.' she uses the following weights: 50% battery life, 30% cost, and 20% camera. she finds the following ratings out of 10 for each category on the internet. brand battery cost camera rating iphone 4 8 4 samsung 10 8 8 motorola 9 5 8 compute the overall rating for each of the phones in the table. express your answers rounded to the nearest tenth. based on the ratings that you computed, which phone is the 'best' ?
The overall rating for the iPhone 4 is 6.2, the Samsung is 8.2, and the Motorola is 7.8. Based on the ratings, the Samsung is the best phone since it has the highest overall rating.
To calculate the overall rating for each phone, Sara first determined the weights of each category. Battery life was given a weight of 50%, cost was given a weight of 30%, and camera was given a weight of 20%. She then used the ratings for each phone to calculate the weighted average of the ratings. The weighted average of the iPhone 4 was 6.2, the Samsung was 8.2, and the Motorola was 7.8.
To calculate the weighted average, Sara first multiplied the ratings of each phone in each category by the weight associated with that category. For the iPhone 4, this meant that 8*0.5 was multiplied by 4*0.3 and 4*0.2 for the cost and camera categories respectively. The sum of these values was 6.2.
Similarly, for the Samsung, 10*0.5 was multiplied by 8*0.3 and 8*0.2 for the cost and camera categories respectively to get 8.2. Lastly, for the Motorola, 9*0.5 was multiplied by 5*0.3 and 8*0.2 to get 7.8. Thus, based on the ratings, the Samsung is the best phone since it has the highest overall rating.
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help meeeeeeeeeeeee.
Answer:
4:1, 20:5
Step-by-step explanation:
You can determine if a ratio is equivalent by dividing each term with the respective term in the other ratio. If you come out with 1, the ratios are equivalent.
Answer:
4:1 & 20:5
Step-by-step explanation:
These two ratios are equal and true to 12:3!
Hopefully this helps have a great day! :D
Learning Task 1: Show the following decimals using grids. Write your answer in your notebook. 1) 0.9 2) 0.1 3) 0.24 4) 0.21 50.11 6) 0.15
Answer:
I hope this helps you:)
Step-by-step explanation:
The organizers of a conference needs to prepare at least 200 notepads for the event
and have a budget of $160 for the notepads. A store sells notepads in packages of 24
and packages of 6.
24x + 6y > 200
This system of inequalities represent these constraints:
(16x + 5.40y = 160
The system of inequalities represent these constraints is 24x + 6y > 200 and 16x + 5.40y ≤ 160
Inequalities shows the non equal comparison of numbers or expressions.
Let x represent the number of packages of 24 notepads and y represent the number of packages of 6 notepads
Since the organizers need to do at least 200 notepads, hence:
24x + 6y > 200
Also, they have a budget of $160. Let us assume that each 24 package cost $16 and each 6 package cost $5.40, hence:
16x + 5.40y ≤ 160
The system of inequalities represent these constraints is 24x + 6y > 200 and 16x + 5.40y ≤ 160
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help quick pleaseeee
IXL, Factoring Polynomials
Answer:
\(\left(h-2\right)\left(h-11\right)\)
Step-by-step explanation:
Pic below...
hope this helped!
brainliest please!
Given that P = x + y . Find P when: x = 20 and y = − 24 P = ?
Answer:
P = -4
Step-by-step explanation:
Assuming that x = 20 and y = 24, you have to plug in these numbers for x and y to get to this equation P = 20 - 24. You should get -4 when you subtract 24 from 20 giving you a negative answer.
1. if it takes five elves five minutes to wrap five presents, how long would it take fifty elves to wrap fifty presents?
If it takes five elves five minutes to wrap five presents, then the time it will take fifty elves to wrap fifty presents is 5 minutes.
If it takes five elves five minutes to wrap five presents, then each elf wraps one present in five minutes.
So, to wrap fifty presents, we would need 50 elves.
Since each elf wrap one present in 5 minutes,
So, the fifty elves can wrap fifty presents in the same amount of time it takes one elf to wrap one present.
So, the time it would take fifty elves to wrap fifty presents is also five minutes.
Therefore, It would take fifty elves 5 minutes to wrap fifty presents.
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ou are setting up a zip line in your yard. You map out your yard in a coordinate plane. An equation of the line representing the zip line is y=-8/3+8
. There is a tree in your yard at the point (3,16) . Each unit in the coordinate plane represents 1 foot. Approximately how far away is the tree from the zip line? Round your answer to the nearest tenth.
9514 1404 393
Answer:
5.6 feet
Step-by-step explanation:
Assuming your zip line equation is supposed to be ...
y = -8/3x +8
we can rewrite it to general form:
8/3x +y -8 = 0
8x +3y -24 = 0 . . . . multiply by 3
Now, we can use the formula for the distance from a point to a line:
d = |ax +by +c|/√(a²+b²) . . . . . distance from (x, y) to ax+by+c=0
Filling in the values we know, we have ...
d = |8(3) +3(16) -24|/√(8² +3²) = 48/√73 ≈ 5.6
The distance from the tree to the zip line is about 5.6 feet.
Use pumping Lemma to prove that the following languages are not regular [ 5 pts each]. 1. L
1
={0
n
1
n
2
n
∣n≥0,Σ={0,1,2}} 2. L
2
={ωωω∣ω∈{a,b}
∗
}
In all cases, we can find a pumped string \(xy^kz\) that does not belong to L₂, which contradicts the assumption that L₂ is regular. Therefore, L₂ is not regular.
To prove that the given languages L₁ and L₂ are not regular using the pumping lemma, we need to show that for any hypothetical regular language L.
There exists a pumping length p such that for any string s in L of length at least p, we can pump s in a way that the pumped string is not in L.
1. L₁ = {\(0^n1^n2^n\) | n ≥ 0, Σ = {0, 1, 2}}
Assume L₁ is regular and let p be the pumping length. Consider the string s = \(0^p1^p2^p\). This string is in L₁ because it has the form \(0^n1^n2^n\), where n = p.
By the pumping lemma, we can decompose s into three parts: s = xyz, such that:
1. |y| > 0
2. |xy| ≤ p
3. For all k ≥ 0, \(xy^kz\) is in L₁.
Let's consider different cases for the possible placement of y in s.
y contains only 0s (\(y = 0^m\), where 1 ≤ m ≤ p).
In this case, when we pump y (k > 1), the number of 0s will exceed the number of 1s and 2s, and hence the pumped string \(xy^kz\) will not be in L₁.
y contains both 0s and 1s (\(y = 0^m1^k\), where 1 ≤ m + k ≤ p).
In this case, when we pump y (k > 1), the number of 0s and 1s will not be balanced with the number of 2s, and hence the pumped string \(xy^kz\) will not be in L₁.
y contains only 1s (\(y = 1^k\), where 1 ≤ k ≤ p).
In this case, when we pump y (k > 1), the number of 1s will exceed the number of 0s and 2s, and hence the pumped string \(xy^kz\) will not be in L₁.
y contains both 1s and 2s (\(y = 1^m2^k\), where 1 ≤ m + k ≤ p).
In this case, when we pump y (k > 1), the number of 1s and 2s will not be balanced with the number of 0s, and hence the pumped string \(xy^kz\) will not be in L₁.
Thus, in all cases, we can find a pumped string \(xy^kz\) that does not belong to L₁, which contradicts the assumption that L₁ is regular. Therefore, L₁ is not regular.
2. L₂ = {ωωω | ω ∈ {a, b}*}
Assume L₂ is regular and let p be the pumping length. Consider the string \(s = a^pb^pa^pb^pa^pb\). This string is in L₂ because it has the form ωωω, where ω = \(a^pb^p\).
By the pumping lemma, we can decompose s into three parts: s = xyz, such that:
1. |y| > 0
2. |xy| ≤ p
3. For all k ≥ 0, \(xy^kz\) is in L₂.
Let's consider different cases for the possible placement of y in s.
y contains only a's (\(y = a^m\), where 1 ≤ m ≤ p).
In this case, when we pump
y (k > 1), the number of a's will exceed the number of b's in the first or second occurrence of ω, and hence the pumped string \(xy^kz\) will not be in L₂.
y contains only b's (\(y = b^m\), where 1 ≤ m ≤ p).
In this case, when we pump y (k > 1), the number of b's will exceed the number of a's in the second or third occurrence of ω, and hence the pumped string \(xy^kz\) will not be in L₂.
y contains both a's and b's (\(y = a^mb^n\), where 1 ≤ m + n ≤ p).
In this case, when we pump y (k > 1), the number of a's or b's will exceed the number of the corresponding symbol in the corresponding occurrence of ω, and hence the pumped string \(xy^kz\) will not be in L₂.
Thus, in all cases, we can find a pumped string \(xy^kz\) that does not belong to L₂, which contradicts the assumption that L₂ is regular. Therefore, L₂ is not regular.
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Complete Question
Use the pumping lemma to prove that the following languages are not regular:
L1 = {0^n 1^n 2^n | n ≥ 0, Σ = {0, 1, 2}}
L2 = {ωωω | ω ∈ {a, b}*}
For each language, apply the pumping lemma to show that there exists a pumping length (p) such that no matter how the string is divided into segments, it is not possible to pump the segments to generate all the strings in the language. This demonstrates that the languages are not regular.
V3 and but outside r, r2 = 2 sin (20) then set up integral(s) for area of the following: (12 pts) Sketch the graph of 1 a) Inside r. b) Inside r, but outside r; c) Inside both ri and r
To find the areas of the given regions, we need to set up integrals. The regions are described.
a) To find the area inside r, we need to set up the integral based on the given equation r1 = 2 sin(20). We can sketch the graph of r1 as a circle with radius 2 sin(20) centered at the origin. The integral for the area can be set up as ∫∫ \(r1^2\) dA, where dA represents the area element.
b) To find the area inside r2 but outside r1, we need to set up the integral based on the given equation r2 = 3. We can sketch the graph of r2 as a circle with radius 3 centered at the origin. The region between r1 and r2 can be visualized as the area between the two circles. The integral for the area can be set up as ∫∫ (\(r2^2\) - \(r1^2\)) dA.
c) To find the area inside both r1 and r2, we need to find the overlapping region between the two circles. This can be visualized as the region common to both circles. The integral for the area can be set up as ∫∫ \(r1^2\)dA, considering the area within the smaller circle.
These integrals can be evaluated to find the actual area values for each region.
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Let x be an integer. Prove that if x is not divisible by 3, then
(x + 1)(x + 2) is divisible by 3
Answer:
(x + 1)(x + 2) is divisible by 3.
Step-by-step explanation:
Assume that x is not divisible by 3. This means that x can be expressed as x = 3k + r, where k is an integer and r is the remainder when x is divided by 3. Since x is not divisible by 3, the remainder r must be either 1 or 2.
Case 1: r = 1
If r = 1, then x = 3k + 1. Now let's consider (x + 1)(x + 2):
(x + 1)(x + 2) = (3k + 1 + 1)(3k + 1 + 2)
= (3k + 2)(3k + 3)
= 3(3k^2 + 5k + 2)
We can see that (x + 1)(x + 2) is divisible by 3.
Case 2: r = 2
If r = 2, then x = 3k + 2. Now let's consider (x + 1)(x + 2):
(x + 1)(x + 2) = (3k + 2 + 1)(3k + 2 + 2)
= (3k + 3)(3k + 4)
= 3(3k^2 + 7k + 4)
We can see that (x + 1)(x + 2) is divisible by 3.
Hence, the statement is proven.
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simple random sample of 25 observations is derived from a normally distributed population with a known standard deviation of 8.2. Use Table 1. a. Is the condition that formula76.mml is normally distributed satisfied? Yes No b. Compute the margin of error with 80% confidence. (Round intermediate calculations to 4 decimal places, "z-value" and final answer to 2 decimal places.) Margin of error 2.0992 c. Compute the margin of error with 90% confidence.(Round intermediate calculations to 4 decimal places, "z-value" and final answer to 2 decimal places.) Margin of error d. Which of the two margins of error will lead to a wider interval? The margin of error with 90% confidence. The margin of error with 80% confidence.
The margin of error with the 80% confidence intervals are 2.099.
80% confidence interval, margin of error can be calculate as follows:
margin of Error :
The margin of Error is a statistic that indicates how much random sampling error is included in the survey results. The greater the margin of error, the lower the confidence that the survey results accurately reflect the census results.
so,n=25, σ=8.2
For 80% confidence intervals, the critical value for z is 1.28. So the required error bound is
ME= Zc. σ =1.28 X 8.2 =2.0992
√n √25
Therefore, the error bar at 80% confidence is 2.099.
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how to calculate sum of squared residuals from sst and sse
The SSR can be calculated as:
SSR = SST - SSE
How to determine the SSR?The linear regression analysis i.e., sum of squared residuals (SSR) can be calculated as the difference between the total sum of squares (SST) and the explained sum of squares (SSE).
SST represents the total variation in the data and is calculated as the sum of the squared differences between each data point and the mean of the data:
SST = ∑(\(yi\) - ȳ)²
where \(yi\) is the \(i-th\) data point and ȳ is the mean of the data.
SSE represents the variation in the data that is explained by the model and is calculated as the sum of the squared differences between each predicted value and the actual value:
SSE = ∑(yi - ŷi)²
where yi is the i-th actual data point and ŷi is the i-th predicted value from the model.
Then, the SSR can be calculated as:
SSR = SST - SSE
This represents the unexplained variation in the data that is not accounted for by the model.
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Maddy works for base pay: $37,555 and commission: 5.5%
H.E.L.P M.E
The 5.5 percent commission on $37555 will give Mandy a value of $2065.525
How to calculate the commission?It's important to note that commission is the amount that's given based on the sales made.
In this case, we want to calculate the commission based on the percentage. This will be:
= 5.5% × $37,555
= 0.055 × $37,555
= $2065.525
This shows the commission.
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Maddy works for base pay: $37,555 and commission: 5.5%. What is the. commission?
Maddy's total pay would be = $39,620.525
What is commission value?Commission values are the sum of money that is gotten from the total amount and the given commission rate.
The base pay received by Maddy at work = $37,555
The commission rate at work = 5.5%
His total pay after receiving after receiving his commission;
= ( 5.5/100 × 37, 555) + 37, 555.
= ( 206,552.5/100) + 37,555
= 2,065.525 + 37,555
= $39,620.525.
The amount of money that Maddy would receive at the end of work = $ 39,620.525.
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( 2x + 5 ) + ( 3x - 7
Answer:
5x-2
Step-by-step explanation:
2x+3x=5x
5-7=-2
Answer:
5x+-2
Step-by-step explanation:
(2x+5) + (3x-7)
2x+3x=5x
5-7=-2
5x-2
Last year, 85% of students participated in the school fundraiser. Using this data, what would be the BEST prediction of how many of the 320 students will participate in the fundraiser this year?
Answer:
C. 272
Step-by-step explanation:
Since we know 85% of the students participated last year we can assume the same amount will participate this year so to find the answer you simply do the total number of students (320) multiplied by 85% or .85 to get the best guess of how many students will participate this year.
Arianys wants to ride her bicycle 55.5 miles this week. She has already ridden 19 miles. If she rides for 5 more days, which equation could be used to determine, m, the average number of miles she would have to ride to meet her goal? A. 19m = 55.5 - 5 B. 5m = 19 - 55.5 C. m = 55.5-19/5 D. 55.5 = 19m + 5
The equation that could be used to determine, m, the average number of miles she would have to ride to meet her goal is; m = (55.5 - 19)/5
How to Solve Algebra Word Problems?
Distance that she wants to ride this week = 55.5 miles
Distance she has already ridden so far = 19 miles
Now, we are told that she will ride 5 more days.
If m is the average number of miles she has to ride to meet her goal, then we can say that;
5m + 19 = 55.5
Making m the subject by, we have;
m = (55.5 - 19)/5
Thus, the equation that could be used to determine, m, the average number of miles she would have to ride to meet her goal is;
m = (55.5 - 19)/5
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Sketch the graphs. -3x+4y=-4
Answer:
(0,-1)
Step-by-step explanation:
Graph the line using the slope and the y intercept
y=mx+b form: y=3/4x-1
Answer:
(0,-1) (1.333, 0)
Step-by-step explanation:
Suppose that the function f is given by f(z, 3) = 4 – 8 – +1. Find the critical points of f. For each critical point of f. determine whether it is a local minimum, local maximum, or a saddle point.
The critical point of f at z = 1 is a local minimum.
To find the critical points of the function f(z, 3) = 4z^2 - 8z + 1, we need to find the values of z where the first partial derivatives with respect to z are equal to zero. Let's solve it step by step.
Take the partial derivative of f with respect to z:
∂f/∂z = 8z - 8
Set the derivative equal to zero and solve for z:
8z - 8 = 0
8z = 8
z = 1
The critical point of f occurs when z = 1.
To determine whether the critical point is a local minimum, local maximum, or a saddle point, we can use the second partial derivative test. We need to calculate the second partial derivative ∂²f/∂z² and evaluate it at the critical point (z = 1).
Taking the second partial derivative of f with respect to z:
∂²f/∂z² = 8
Evaluate the second derivative at the critical point:
∂²f/∂z² at z = 1 is 8.
Analyzing the second derivative:
Since the second derivative ∂²f/∂z² = 8 is positive, the critical point (z = 1) corresponds to a local minimum.
Therefore, the critical point of f at z = 1 is a local minimum.
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The word "and" in probability implies that we use the ____ rule.
A. Subtraction
B. Division
C. Addition
D. Multiplication
The word "and" in probability implies that we use the Multiplication rule.
The correct option is Option D.
What is the Multiplication Rule of Probability?The likelihood of both events A and B occurring, in accordance with the probability multiplication rule, is equal to the product of the probability of B occurring and the conditional probability of event A occurring given that event B occurs.
The relationship between two events is explained by the probability multiplication rule.
Set A∩B represents the events in which both events A and B have occurred for two events A and B related to a sample space S. Consequently, (A∩B) indicates that occurrences A and B happened at the same time. You can write the event A∩B as AB. Using the characteristics of conditional probability, the likelihood of event AB is calculated.
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How many intersections are there of the graphs of the equations below? one-halfx 5y = 6 3x 30y = 36
The number of intersections of the graphs of the given equations is 0.
To determine the number of intersections of the graphs of the equations:
1. One-halfx + 5y = 6
2. 3x - 30y = 36
We can convert the equations to slope-intercept form (y = mx + b) by isolating y:
1. \(\frac12\\\)x + 5y = 6
5y = -\(\frac12\\\)x + 6
y = (-1/10)x + 6/5
2. 3x - 30y = 36
-30y = -3x + 36
y = (1/10)x - 36/30
y = (1/10)x - 6/5
Now, we can observe that both equations have the same slope, which is 1/10, but they have different y-intercepts (6/5 and -6/5).
Since the slopes are the same but the y-intercepts are different, the two lines are parallel.
Parallel lines do not intersect,
so the graphs of these equations have no intersection points.
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Answer:
A or none
Step-by-step explanation:
edge
Find the value of x.A.55B.25C.35D.10
Answer:
D hope that help c: yhisj
Simplify the expression below by rationalizing the denominator. When typing your answer be sure to be careful and include the correct signs. Keep in mind that the variables a,b,c,d, e and f can represent a product of a number and a variable. \frac{\sqrt[]{8}}{1-\sqrt[]{3z}} simplifies to \frac{a\sqrt[]{b}+c\sqrt[]{d}}{e- \sqrt[]{f}} Our value for a is AnswerOur value for b is AnswerOur value for c is AnswerOur value for d is AnswerOur value for e is AnswerOur value for f is Answer
Given:
\(\frac{\sqrt[]{8}}{1-\sqrt[]{3z}}\)Simplife:
\(\begin{gathered} =\frac{\sqrt[]{8}}{1-\sqrt[]{3z}} \\ =\frac{\sqrt[]{8}}{1-\sqrt[]{3z}}\times\frac{1+\sqrt[]{3z}}{1+\sqrt[]{3z}} \\ =\frac{\sqrt[]{8}+\sqrt[]{24z}}{1-\sqrt[]{9z^2}} \\ =\frac{2\sqrt[]{2}+2\sqrt[]{6z}}{1-\sqrt[]{9z^2}} \end{gathered}\)The given simplifies equation is:
\(\frac{a\sqrt[]{b}+c\sqrt[]{d}}{e-\sqrt[]{f}}\)After the compare the both inequality:
a=2
b=2
c=2
d=6
e=1
f=9