15. Which element will donate electrons?
nitrogen
chlorine
aluminum
sulfur

Dispersion refers to the spreading or broadening of optical signals as they propagate through an optical fibre. Dispersion can occur due to chromatic dispersion and waveguide dispersion.

To minimize dispersion effects and improve the transmission characteristics of fibre optic systems, it is desirable to operate at a wavelength where the chromatic and waveguide dispersions cancel each other out, resulting in zero net dispersion. The zero-dispersion point in single-mode fibre was moved to 1,550 nm in order to minimize dispersion. At this wavelength, the chromatic dispersion (which causes different wavelengths of light to travel at different speeds) is zero, meaning that signals can be transmitted over longer distances without losing quality or clarity. This wavelength was chosen because it allows for the highest possible data transmission rates with minimal signal distortion.

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Non-polarized capacitors also referred to as ceramic capacitors or ac capacitors can be used on both ac and dc circuits.

A capacitor is an electronic device that stores electrical energy. It has two terminals and is a passive electrical component. Capacitance refers to the amount of electric energy a capacitor can store. The capacity of a capacitor is measured in Farads (F).

AC and DC circuit is categorized as per the type of current that flows through the circuit. The direction of the current in alternating current alternates between moving forward and moving backwards. When in direct current, it consistently flows in a single direction.

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When two identical waves undergo pure constructive interference, the displacement of one wave adds to the displacement of the other wave, resulting in a wave with twice the amplitude.

Since intensity is proportional to the square of the amplitude, the resultant intensity will be four times that of each individual wave.

Mathematically, if the individual waves have intensity I, the resultant wave will have an intensity of:

I_resultant = 2I + 2(I cos θ)

(where θ is the phase difference between the waves)

Since the waves undergo pure constructive interference, the phase difference θ is zero, so:

I_resultant = 2I + 2(I cos 0)

                  = 4I

Therefore, the resultant intensity will be four times that of each individual wave.

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In 1964 Gell Mann and Zweig introduced a baryonic triplet consisting of three hypothetical particles that are termed as Quarks.

The quark model is able to explain many features of elementary particles and gives a good insight into the structure of baryons and mesons.

Quarks are the fermions as the basic building block if we use fermions then we can get fermions and bosons. These bosons are assumed as antiquark pairs.

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Answer:

the galaxy is moving away from us and the magnitude of the displacement gives the value of the relative velocity

Explanation:

The wavelength and frequency of light is affected by the relative motion of the Source (galaxy) and the observer (us on Earth); when the shift is towards the red it indicates that the bodies are moving away from each other.

Consequently the galaxy is moving away from us and the magnitude of the displacement gives the value of the relative velocity

Answer:

Gravity. An object is moving across a surface, but it does not gain or lose speed.

Explanation:

The basic idea. Physicists see gravity as one of the four fundamental forces that govern the universe, alongside electromagnetism and the strong and weak nuclear forces.

Hope it helps! Brainliest?

Chechnya has a significant impact on the Russian Federation's economy, primarily due to its oil and natural gas industry. The republic has abundant oil and gas reserves, which make up about 25% of Russia's total oil reserves.

These resources are essential for Russia's energy sector and contribute significantly to the country's GDP. Additionally, agriculture and construction industries are growing in Chechnya, providing employment opportunities and contributing to the region's economy. However, due to political instability and ongoing conflict, the development of other industries has been limited. Overall, Chechnya's oil and gas reserves are the key industries for the Russian Federation, playing a significant role in the country's energy and economic strategies.

Another important industry in Chechnya is agriculture, with a focus on crops like wheat, barley, and sunflower seeds, as well as livestock farming, particularly sheep and cattle. This sector contributes to the nation's food security and rural development.

Additionally, Chechnya's manufacturing and construction industries have experienced growth in recent years, particularly in areas like metalworking, machinery production, and the development of infrastructure projects.

These key industries in Chechnya not only boost the regional economy but also strengthen the overall economic stability and development of the Russian Federation.

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Answer:

the magnitude of the electric field  = 27.1058 V/m

≈ 27 V/m

Explanation:

given

R(radius enclosed) = 12 cm = 0.12 m

ρ(charge density) = 5.0 nC/m³ = 5.0 × 10⁻⁹C/m³

r(radius from the axis) = 15 cm = 0.15 m

using Gauss law, which states that the electric flux through any closed surface is directly proportional to the total electric charge enclosed by this surface.

attached is the calculation of the question, using Gauss law of electrostatics

Answer:

D

Explanation:

Study habits include, how you prepare for assignments, what questions you ask your teacher, and How you take tests, all of these come under study habits, therefore the correct answer is option D.

The deliberate evidenced based quest and application of information and comprehension of the natural implications for society is what is known as research.

Science is a methodology of discovering more about the world.

People may contribute to the development of new knowledge through science and utilize it to promote their objectives.

A student's study habits include factors like how they approach tasks, questions they ask their professors, and how they prepare for the exam

Thus, the correct answer is option D.

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Ignore my comment, that information is unnecessary.

Assuming no friction between the skis and the water, the total work performed on the skier is due only to the pulling force (T, for tension). By Newton's second law, the net force exerted on the skier is

∑ F = T = ma

where m = 73.5 kg is the mass of the skier, and a is their acceleration.

Under constant acceleration, the skier is pulled a distance x such that

(12.2 m/s)² - (5.2 m/s)² = 2ax

and solving for x gives

x = (60.9 m²/s²) / a

Then the total work performed on the skier is

W = Tx

W = ma • (60.9 m²/s²) / a

W = (73.5 kg) (60.9 m²/s²)

W ≈ 4480 J

Answer:

We conclude that the mass of a rock with a force of 500 N and an acceleration of 75 m/s² is 6.7 kg.

Hence, option D is correct.

Explanation:

Given

To determine

Mass m = ?

Important Tip:

Using the formula

\(F = ma\)

where

now substituting F = 500, and a = 75 m/s² in the formula

\(F = ma\)

\(500 = m(75)\)

switch sides

\(m\left(75\right)=500\)

Divide both sides by 75

\(\frac{m\cdot \:75}{75}=\frac{500}{75}\)

simplify

\(m=\frac{20}{3}\)

\(m=6.7\) kg

Therefore, we conclude that the mass of a rock with a force of 500 N and an acceleration of 75 m/s² is 6.7 kg.

Hence, option D is correct.

Answer:

Displacement = 20 m

Explanation:

Given that,

Kyle runs 20 m north, 20 m west and then 20 m south.

We need to find Kyles's total displacement.

Total distance = shortest path covered by Kyles.

The net displacement of Kyle is 20 m in east direction. Hence, this is the required solution.

Answer:

By opening the door, Elijah is using the chemical energy, which he obtained from eating food to do work. Thus, he is converting chemical energy to mechanical energy.

Stretching the spring by opening the screen door convert the potential energy which is stored in the spring to kinetic energy.

Overall there is conversion of chemical energy to potential energy.

By letting the door go, Elijah is using chemical energy. By snapping shut, the door is converting potential energy to kinetic energy. The overall energy change is conversion of chemical energy to kinetic energy.

Explanation:

The property of a system that enables it to do something or make something happen, including the capacity to do work is called energy.

Energy is the ability of a system to perform work or bring about change is represented by the fundamental idea of energy in physics. It has magnitude but no direction because it is a scalar quantity.

The principle of energy conservation states that energy can be changed from one form to another and that the overall energy of a closed system stays constant. Energy can, however, be converted or transported across various systems or objects, enabling movement or changes to take place.

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The gravitational potential energy gained while climbing the eight-story building, with a height of 24 m, and a mass of 70 kg, is approximately 16,500 Joules. The correct answer is 16,500 Joules.

Gravitational potential energy is calculated using the formula:

Potential Energy = Mass x Gravity x Height

Given:

Mass = 70 kg

Height = 24 m

Using the standard acceleration due to gravity, which is approximately 9.8 m/s², we can calculate the gravitational potential energy gained:

Potential Energy = 70 kg x 9.8 m/s² x 24 m = 16,464 Joules

Rounded to the nearest whole number, the gravitational potential energy gained is approximately 16,500 Joules.

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The force between two charges is inversely proportional to the square of the distance between them and directly proportional to the product of the charges. Therefore, if the distance between two charges is cut in half, the force between them is quadrupled.

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When the fabric strip was treated with the test identification stain, it underwent a chemical reaction which caused it to change color or produce a visible reaction.

When the fabric strip is treated with the test identification stain, the following steps occur:

1. The fabric strip is exposed to the test identification stain, which is a chemical solution designed to detect specific substances or characteristics on the fabric.
2. The test identification stain reacts with any target substances present on the fabric strip, causing a color change or other visible indication.
3. The results of this reaction can then be observed and recorded to determine the presence or absence of the target substances in the fabric strip.

In summary, treating the fabric strip with the test identification stain allows for the detection of specific substances or characteristics within the fabric, by causing a visible reaction.

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Answer:

1. The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time

2. 36÷4= 9

(formula) Speed = distance ÷ time

3. Meter (M) centimeter (cm) kilometers (km)

4. Seconds , Hour, Minute

5. 65÷13=5 (object A)

125÷ 25= 5 (object B)

their both Equal of the amount of speed, so they are travelling at the same speed

Hope I helped

Answer:

i can

Explanation:

i know what's the answer

The magnitude of the electric field is 1.77 x 10⁶ N/C, under the condition that the  distance is  25.00 cm

The electric field at a distance of 25 cm from the axis of the cylinder can be calculated using Gauss's law. The electric field at a point outside a uniformly charged cylinder is given by

E = (ρ × r) / (2 × ε0),

here

ρ = charge density,

r = distance from the axis of the cylinder

ε0 = permittivity of free space.

Now, we have a non-uniform volume charge density of

ρ = 4 × r²C/m³

r = 25 cm

= 0.25 m

Staging these values in the above equation

E = (ρ × r) / (2 × ε0) = (4 × r³) / (2 × ε0)

= (2 × r³) / ε0

E = (2 × (0.25 m)³) / ε0

= 1.77 x 10⁶ NN/C

Therefore, the magnitude of the electric field at a distance of 25 cm from the axis of the cylinder is 1.77 x 10⁶ N/C.

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The force of gravitational attraction is reduced by a factor of 4 when the separation distance between two objects is doubled (increased by a factor of 2).

The gravitational force, which is what pushes mass-containing objects toward one another. We frequently consider the pull of gravity from the Earth. Your body is kept on the ground by this force. However, all mass-bearing objects are pulled toward one another by gravity.

Greater gravitational forces will be used to attract heavier things since the gravitational force is directly proportional to the mass of both interacting objects. Therefore, the gravitational attraction between two objects grows as their respective masses do as well. The force of gravity between two objects is equal to their respective masses multiplied by two. If one of the items triples in mass, the gravitational pull between them will also triple.

The radius of a circle is the separation between its center and circumference. Always, the diameter is twice the radius. As a result, the formula is created by multiplying the diameter by two.

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A high-frequency sound source produces a high pitch and low amplitude.

Sound is produced by our vocal cords, precisely by the vibration of our vocal cords. When they vibrate they have a particular setup of voice mix like it has low or high frequency and low or high amplitude. The voice in the same frequency is called tone. In this type of voice, there is no voice modulation. A sound which is produced with a high frequency has shrill effect and has high pitch. Since, pitch and amplitude are inversely proportional to each other. If we have a high pitch, then we have a low amplitude automatically. Speed is determined by medium through which it passes. Hence, it is clear that a high-frequency sound source produces a high pitch and low amplitude.

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Answer:

Gravity is a force that acts between the Earth's mass and the mass of other objects that surround it. The force of gravity can act across large distances

Explanation:

The speed of the turtle, Adel is 0.2 feet per minutes.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Distance travelled by the turtle, Adel is = 10 feet

Time taken by the turtle is = 50 minutes.

Now we know that

speed = distance travelled ÷ time interval

Hence, the speed of the turtle is = 10 feet ÷  50 minutes.

= 0.2 feet per minutes.

Hence, the speed of the turtle, Adel is 0.2 feet per minutes.

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Answer:

John applied a force of approximately \(795\; {\rm N}\) (on average, rounded) on Lucy.

John slows down to a stop after approximately another \(5.37\; {\rm s}\).

(Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)

Explanation:

Assuming that the surface is level. The normal force on Johnny will be equal to the weight of Johnny: \(N(\text{John}) = m(\text{John})\, g\). Similarly, the normal force on Lucy will be equal to weight \(N(\text{Lucy}) = m(\text{Lucy})\, g\).

Multiply normal force by the coefficient of kinetic friction to find the friction on each person:

\(f(\text{John}) = \mu_{k}\, N(\text{John}) = \mu_{k}\, m(\text{John})\, g\).

\(f(\text{Lucy}) = \mu_{k}\, N(\text{Lucy}) = \mu_{k}\, m(\text{Lucy})\, g\).

Again, because the surface is level, the net force on each person after the first \(1.0\; {\rm s}\) will be equal to the friction. Divide that the net force on each person by the mass of that person to find acceleration:
\(\displaystyle a(\text{John}) = \frac{\mu_{k}\, m(\text{John})\, g}{m(\text{John})} = \mu_{k}\, g\).

\(\displaystyle a(\text{Lucy}) = \frac{\mu_{k}\, m(\text{Lucy})\, g}{m(\text{Lucy})} = \mu_{k}\, g\).

(Note that the magnitude of acceleration is independent of mass and is the same for both John and Lucy.)

\(a = \mu_{k}\, g= (0.2)\, (9.81\; {\rm m\cdot s^{-2}}) = 1.962\; {\rm m\cdot s^{-2}}\).

In other words, after the first \(1\; {\rm s}\), both John and Lucy will slow down at a rate of \(1.962\; {\rm m\cdot s^{-2}}\).

To find the speed of Lucy immediately after the first \(1.0\: {\rm s}\), multiply this acceleration by the time \(t = 8.0\; {\rm s}\) it took for Lucy to slow down to \(0\; {\rm m\cdot s^{-1}}\):

\(\begin{aligned}& (8.0\; {\rm s})\, (1.962\; {\rm m\cdot s^{-2}}) \\ =\; & (8.0)\, (1.962)\; {\rm m\cdot s^{-1}} \\ =\; & 15.696\; {\rm m\cdot s^{-1}}\end{aligned}\).

Thus, in the first \(1.0\; {\rm s}\), Lucy accelerated (from \(0\; {\rm m\cdot s^{-1}}\)) to \(15.696\; {\rm m\cdot s^{-1}}\).

The average acceleration of Lucy in the first \(1.0\; {\rm s}\) would be \((15.696) / (1) = 15.696\; {\rm m\cdot s^{-2}}\). Multiply this average acceleration by the mass of Lucy to find the average net force on Lucy during that \(1.0\; {\rm s}\):

\(\begin{aligned}F_{\text{net}}(\text{Lucy}) &= m(\text{Lucy})\, a \\ &= (45)\, (15.696)\; {\rm N} \\ &= 706.320\; {\rm N}\end{aligned}\).

This net force on Lucy during that \(1.0\; {\rm s}\) is the combined result of both the push from Johnny and friction:

\(F_{\text{net}}(\text{Lucy}) = F(\text{push}) - f(\text{Lucy})\).

Since \(f(\text{Lucy}) = \mu_{k}\, N(\text{Lucy}) = \mu_{k}\, m(\text{Lucy})\, g\):

\(\begin{aligned}F(\text{push}) &= F_{\text{net}}(\text{Lucy}) + f(\text{Lucy}) \\ &= F_{\text{net}}(\text{Lucy}) + \mu_{k}\, m(\text{Lucy})\, g \\ &= (706.320) \; {\rm N}+ (0.2)\, (45)\, (9.81)\; {\rm N} \\ &= 706.320\; {\rm N} + 88.290\; {\rm N} \\ &=794.610\; {\rm N}\end{aligned}\).

In other words, Johnny would have applied a force of \(794.610\; {\rm N}\) on Lucy.

By Newton's Laws of Motion, when Johnny exerts this force on Lucy in that \(1.0\; {\rm s}\), Lucy would exert a reaction force on Johnny of the same magnitude: \(794.610\; {\rm N}\).

Similar to Lucy, the net force on Johnny during that \(1.0\; {\rm s}\) will be the combined effect of the push \(F(\text{push})\) and friction \(f(\text{John}) = \mu_{k}\, m(\text{John})\, g\):

\(\begin{aligned}F_{\text{net}}(\text{John}) &= F(\text{push}) - f(\text{John}) \\ &= F(\text{push}) - \mu_{k}\, m(\text{John})\, g\\ &= 794.610\; {\rm N} - (0.2)\, (65)\, (9.81)\; {\rm N} \\ &= 667.080\; {\rm N}\end{aligned}\).

Divide net force by mass to find acceleration:

\(\begin{aligned}\frac{667.080\; {\rm N}}{65\; {\rm kg}} \approx 10.2628\; {\rm m\cdot s^{-2}}\end{aligned}\).

In other words, Johnny accelerated at a rate of approximately \(10.5406\; {\rm m\cdot s^{-2}}\) during that \(1.0\; {\rm s}\). Assuming that Johnny was initially not moving, the velocity of Johnny right after that \(1.0\; {\rm s}\!\) would be:

\((0\; {\rm m\cdot s^{-1}}) + (10.2628\; {\rm m\cdot s^{-2}})\, (1.0\; {\rm s}) = 10.2628\; {\rm m\cdot s^{-1}}\).

After the first \(1.0\; {\rm s}\), the acceleration of both John and Lucy (as a result of friction) would both be equal to \(a = \mu_{k}\, g= (0.2)\, (9.81\; {\rm m\cdot s^{-2}}) = 1.962\; {\rm m\cdot s^{-2}}\). Divide initial velocity of Johnny by this acceleration to find the time it took for Johnny to slow down to a stop:

\(\displaystyle \frac{10.2628\; {\rm {m\cdot s^{-1}}}}{1.962\; {\rm m\cdot s^{-2}}} \approx 5.23\; {\rm s}\).

Answer:

John applied a force of approximately \(795\; {\rm N}\) (on average, rounded) on Lucy.

John slows down to a stop after approximately another \(5.37\; {\rm s}\).

(Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)

Explanation:

Assuming that the surface is level. The normal force on Johnny will be equal to the weight of Johnny: \(N(\text{John}) = m(\text{John})\, g\). Similarly, the normal force on Lucy will be equal to weight \(N(\text{Lucy}) = m(\text{Lucy})\, g\).

Multiply normal force by the coefficient of kinetic friction to find the friction on each person:

\(f(\text{John}) = \mu_{k}\, N(\text{John}) = \mu_{k}\, m(\text{John})\, g\).

\(f(\text{Lucy}) = \mu_{k}\, N(\text{Lucy}) = \mu_{k}\, m(\text{Lucy})\, g\).

Again, because the surface is level, the net force on each person after the first \(1.0\; {\rm s}\) will be equal to the friction. Divide that the net force on each person by the mass of that person to find acceleration:
\(\displaystyle a(\text{John}) = \frac{\mu_{k}\, m(\text{John})\, g}{m(\text{John})} = \mu_{k}\, g\).

\(\displaystyle a(\text{Lucy}) = \frac{\mu_{k}\, m(\text{Lucy})\, g}{m(\text{Lucy})} = \mu_{k}\, g\).

(Note that the magnitude of acceleration is independent of mass and is the same for both John and Lucy.)

\(a = \mu_{k}\, g= (0.2)\, (9.81\; {\rm m\cdot s^{-2}}) = 1.962\; {\rm m\cdot s^{-2}}\).

In other words, after the first \(1\; {\rm s}\), both John and Lucy will slow down at a rate of \(1.962\; {\rm m\cdot s^{-2}}\).

To find the speed of Lucy immediately after the first \(1.0\: {\rm s}\), multiply this acceleration by the time \(t = 8.0\; {\rm s}\) it took for Lucy to slow down to \(0\; {\rm m\cdot s^{-1}}\):

\(\begin{aligned}& (8.0\; {\rm s})\, (1.962\; {\rm m\cdot s^{-2}}) \\ =\; & (8.0)\, (1.962)\; {\rm m\cdot s^{-1}} \\ =\; & 15.696\; {\rm m\cdot s^{-1}}\end{aligned}\).

Thus, in the first \(1.0\; {\rm s}\), Lucy accelerated (from \(0\; {\rm m\cdot s^{-1}}\)) to \(15.696\; {\rm m\cdot s^{-1}}\).

The average acceleration of Lucy in the first \(1.0\; {\rm s}\) would be \((15.696) / (1) = 15.696\; {\rm m\cdot s^{-2}}\). Multiply this average acceleration by the mass of Lucy to find the average net force on Lucy during that \(1.0\; {\rm s}\):

\(\begin{aligned}F_{\text{net}}(\text{Lucy}) &= m(\text{Lucy})\, a \\ &= (45)\, (15.696)\; {\rm N} \\ &= 706.320\; {\rm N}\end{aligned}\).

This net force on Lucy during that \(1.0\; {\rm s}\) is the combined result of both the push from Johnny and friction:

\(F_{\text{net}}(\text{Lucy}) = F(\text{push}) - f(\text{Lucy})\).

Since \(f(\text{Lucy}) = \mu_{k}\, N(\text{Lucy}) = \mu_{k}\, m(\text{Lucy})\, g\):

\(\begin{aligned}F(\text{push}) &= F_{\text{net}}(\text{Lucy}) + f(\text{Lucy}) \\ &= F_{\text{net}}(\text{Lucy}) + \mu_{k}\, m(\text{Lucy})\, g \\ &= (706.320) \; {\rm N}+ (0.2)\, (45)\, (9.81)\; {\rm N} \\ &= 706.320\; {\rm N} + 88.290\; {\rm N} \\ &=794.610\; {\rm N}\end{aligned}\).

In other words, Johnny would have applied a force of \(794.610\; {\rm N}\) on Lucy.

By Newton's Laws of Motion, when Johnny exerts this force on Lucy in that \(1.0\; {\rm s}\), Lucy would exert a reaction force on Johnny of the same magnitude: \(794.610\; {\rm N}\).

Similar to Lucy, the net force on Johnny during that \(1.0\; {\rm s}\) will be the combined effect of the push \(F(\text{push})\) and friction \(f(\text{John}) = \mu_{k}\, m(\text{John})\, g\):

\(\begin{aligned}F_{\text{net}}(\text{John}) &= F(\text{push}) - f(\text{John}) \\ &= F(\text{push}) - \mu_{k}\, m(\text{John})\, g\\ &= 794.610\; {\rm N} - (0.2)\, (65)\, (9.81)\; {\rm N} \\ &= 667.080\; {\rm N}\end{aligned}\).

Divide net force by mass to find acceleration:

\(\begin{aligned}\frac{667.080\; {\rm N}}{65\; {\rm kg}} \approx 10.2628\; {\rm m\cdot s^{-2}}\end{aligned}\).

In other words, Johnny accelerated at a rate of approximately \(10.5406\; {\rm m\cdot s^{-2}}\) during that \(1.0\; {\rm s}\). Assuming that Johnny was initially not moving, the velocity of Johnny right after that \(1.0\; {\rm s}\!\) would be:

\((0\; {\rm m\cdot s^{-1}}) + (10.2628\; {\rm m\cdot s^{-2}})\, (1.0\; {\rm s}) = 10.2628\; {\rm m\cdot s^{-1}}\).

After the first \(1.0\; {\rm s}\), the acceleration of both John and Lucy (as a result of friction) would both be equal to \(a = \mu_{k}\, g= (0.2)\, (9.81\; {\rm m\cdot s^{-2}}) = 1.962\; {\rm m\cdot s^{-2}}\). Divide initial velocity of Johnny by this acceleration to find the time it took for Johnny to slow down to a stop:

\(\displaystyle \frac{10.2628\; {\rm {m\cdot s^{-1}}}}{1.962\; {\rm m\cdot s^{-2}}} \approx 5.23\; {\rm s}\).

The empirical formula of the compound can be determined based on the combustion analysis results, which provided the masses of carbon dioxide  and water  \(H2O\) produced from the combustion of 0.150 g of the unknown compound.

To find the empirical formula, we need to determine the mole ratios of carbon, hydrogen, and oxygen in the compound. First, we calculate the number of moles of \(CO2\) and \(H2O\) produced:

Moles of  \(CO2\) = Mass of CO2 / Molar mass of \(CO2\)

Moles of  \(CO2\) = 0.2607 g / 44.01 g/mol = 0.00592 mol

Moles of   \(H2O\)       = Mass of H2O / Molar mass of\(H2O\)

Moles of  \(H2O\)= 0.1418 g / 18.02 g/mol = 0.00787 mol

Next, we determine the mole ratios of carbon, hydrogen, and oxygen in the compound. Since  \(CO2\) contains one carbon atom and  \(H2O\)contains two hydrogen atoms, the mole ratio of carbon to hydrogen is 1:2. By comparing the moles of \(CO2\) and  \(H2O\), we find that the mole ratio of carbon to hydrogen is 0.00592 mol: (0.00787 mol × 2) = 0.00592 mol: 0.01574 mol, which simplifies to approximately 1:2.66.

To find the empirical formula, we divide the subscripts by their greatest common divisor to obtain the simplest whole-number ratio. In this case, dividing by 1 gives the empirical formula of \(CH2O.\)Therefore, the empirical formula of the compound is\(CH2O.\)

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это действие является рективным, формула которой такова: m1×v1 = – m2×v2

m1 - масса игрока

m2 - масса шайбы

v1 - скорость игрока

v2 - скорост шайбы.

отсюда, скорост игрокa: v1 = (m2×v2):m1 = 0.092 m/s

Explanation:

weight = m g

weight = 1 × 10

weight = 10 N