16. What will be the output of the following Code?
1.
#include
2.
3.
4.
5.
6.
7.
int main()
{
int i = 2;
int i = i++ + i;
printf("%d\n", i);
)
a. = operator is not a sequence point
b. ++operator may return value with or without side effects
c. it can be evaluated as (i++) or (+4)
d. = operator is a sequence point

Answer:

you want me help u with this one?

2. The different amount of shades of color

3. The artist had given every marvel or DC or villian the color that fit them and the texture is also very nice in the picture.

4. The artist maybe could make the pic a little bit more high quality cause in the image is sort of blurry and you cant really see the further people that well.

The term that applies to a relay with two isolated circuits and two contact positions per pole is "double-pole double-throw" (DPDT) relay. This type of relay has two sets of contacts that can switch between two separate circuits, allowing for more complex switching configurations than a single-pole relay. The two contact positions per pole refer to the two different positions the contacts can take when the relay is energized or de-energized.

Answer:

UDP is the answer

Explanation:

UDP enables best-effort connectionless transfer to individual block of information, while TCP enables reliable transfer of a stream of bytes. That's two modes of services available through the circuit interface, connection-oriented and connection-less.

The image is a DR-type security tag, used to prevent theft of objects through concealment in a store. This device activates store alarms by detecting metal inside this label.

The image shows the back of a DR-type security label. The main feature of this label is that it is adhesive and is attached to different products in order to prevent theft.

This label has metal sheets inside that cause the security device (metal detector alarm) to activate once the thief hides the product and tries to leave the store. This product is usually glued in a hidden place on the product so that the thief does not know that the alarm is going to sound.

According to the above, the DR tag allows store owners to have their items protected from thieves who try to hide them and remove them from the store.

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A Java Script program that simulates a coin flipping, so that each time the program runs, it should print either “Heads” or “Tails” along with the other details given is stated below.

var NUM_FLIPS = 10;

var RANDOM = Randomizer.nextBoolean();

var HEADS = "Heads";

var TAILS = "Tails";

function start(){

var flips = flipCoins();

printArray(flips);

countHeadsAndTails(flips);

}

// This function should flip a coin NUM_FLIPS

// times, and add the result to an array. We

// return the result to the caller.

function flipCoins(){

var flips = [];

for(var i = 0; i < NUM_FLIPS; i++){

if(Randomizer.nextBoolean()){

flips.push(HEADS);

}else{

flips.push(TAILS);

}

}

return flips;

}

function printArray(arr){

for(var i = 0; i < arr.length; i++){

println("Flip Number " + (i+1) + ": " + arr[i]);

}

}

function countHeadsAndTails(flips){

   var countOne = 0;

   var countTwo = 0;

   for(var i = 0; i < flips.length; i++){

       if(flips[i] == HEADS){

           countOne+=1;

       }

       else {

           countTwo+=1;

       }

   }

   println("Number of Heads: " + countOne);

   println("Number of Tails: " + countTwo);

}

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Answer:

Electronic device

Explanation:

If the electronic device can pick up the signal and be able to use it, then it would work.

Answer:yes there WAS a parrapa level but it was scrapped from the game I think you can find it in beta versions of the game but

Answer:

You can use regular expressions to match patterns in the names and split them accordingly. One way to do this is to use the re.split() function, which allows you to split a string based on a regular expression.

For example, you can use the regular expression (?<=[A-Z])\s(?=[A-Z]) to match a space between two capital letters, indicating a first and last name. Then use the re.split() function to split the names based on this regular expression.

Here is an example of how you can use this approach to split the names in your list:

(Picture attached)

This will give you the output ['Jack', 'Tomas', 'Ponce', 'Ana', 'Mike', 'Jenny', 'Jack Hansen']. As you can see, the name "Jack Hansen" is not split, as it matches the pattern of first and last name.

It's worth noting that this approach assumes that all first and last names will have the first letter capitalized and the last names capitalized too. If this is not the case in your data, you may need to adjust the regular expression accordingly.

Answer:

To scroll up and down on any page without using the vertical scroll bar on the right hand side of a document or webpage.

Explanation:

Took the tech class for this

#!/bin/bash

INPUT_FILE=$1

count=1

while IFS= read -r line; do

echo $count - $line

count=$(($count + 1))

done < $INPUT_FILE

Answer:

D is the correct answer of this question

Answer:

If this is Amplify, the answer is C which is Air parcel 1 will lose energy to the surrounding air, which will cause more water vapor to fall as rain.

Explanation:

If this is amplifying, then the correct response is C, meaning that Air parcel 1 will lose energy to the surrounding air, increasing the amount of water vapor that rains.

A sign's power can be increased using an electronic device known as an amplifier, electronic amplifier, or amp.

Named after French physicist André-Marie Ampère, the term "ampère" first appeared in 1881 to describe "the current that one volt can transmit through a resistance of one ohm" (1775-1836). adopted in 1881 at the Electric Congress in Paris. reduced form. amplifier (n.)

The triode vacuum tube, developed by Lee De Forest in 1906, was the first widely used device that could amplify, and it led to the creation of the first amplifier in 1912. Up until the 1960s and 1970s, practically all amplifiers employed vacuum tubes until being replaced by transistors.

The technique of increasing the amplitude of an electromagnetic light wave is known as light amplification. The three main categories of this procedure are laser, parametric, and scattering.

In order to reduce the risk of electrocution, the amplifier ground is the ground wire that safely offers the least possible electrical resistance to earth ground or chassis ground. Usually, power mains outlet connections, power supply, or the car chassis are used to ground amps.

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Using knowledge in computational language in JAVA it is possible to write a code that install java and set java home to point to the java installation directory.

Writting the code:

For Maven I tried :

1. open cmd

2. type mvn -version

3. Error appeared :

C:\Users\Admin>mvn -version

ERROR: JAVA_HOME is set to an invalid directory.

JAVA_HOME = "C:\Program Files\Java\jre7\bin"

Please set the JAVA_HOME variable in your environment to match the

location of your Java installation

For ANT I tried and worked :

1. open cmd

2. type mvn -version

3. Apache Ant(TM) version 1.9.1 compiled on May 15 2013

There are multiple ways to copy elements from one array in Java, like you can manually copy elements by using a loop, create a clone of the array, use Arrays. copyOf() method or System. arrayCopy() to start copying elements from one array to another in Java.

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The feature that allows a person to key on new lines without tapping the return or enter key is called word wrap

When the current line is full with text, word wrap automatically shifts the pointer to a new line, removing the need to manually press the return or enter key.

In apps like word processors, text editors, and messaging services, it makes sure that text flows naturally within the available space.

This function allows for continued typing without the interruption of line breaks, which is very helpful when writing large paragraphs or dealing with a little amount of screen space.

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answer:

A statement that I always think about to understand the size of an atom. If you squish a person down to the size of an atom. It will make a black hole. and if you squish the whole Earth. down to the size of a jelly bean it will also make a black hole. This is just a approximation.

-----------------------

I use the scale to understand how small that is I am open to hear more principles if you were talking about math wise that would be glad to help.

if you have anymore questions I will try to answer your questions to what I know.

.

Answer:

Written in Python:

evens = 0

odds = 0

oddtotal = 0

eventotal = 0

total = 0

mylst = []

tryag = "Y"

while tryag == "Y" or tryag == "y":

     num = int(input("Input: "))

     mylst.append(num)

     tryag = input("Another Input (Y/y): ")

mylst.sort()

print("Minimum: "+str(mylst[0]))

print("Maximum: "+str(mylst[-1]))

for i in mylst:

     total = total + i

     if i%2 == 0:

           evens = evens + 1

           eventotal = eventotal + i

     else:

           odds = odds + 1

           oddtotal = oddtotal + i

print("Evens: "+str(evens))

print("Odds: "+str(odds))

print("Even Average: "+str(eventotal/evens))

print("Odd Average: "+str(oddtotal/odds))

print("Total Average: "+str(total/(evens+odds)))

Explanation:

The following lines initializes useful variables to 0

evens = 0

odds = 0

oddtotal = 0

eventotal = 0

total = 0

This declares an empty list

mylst = []

tryag = "Y"

This is repeated until user stops the loop by entering strings other than y or Y

while tryag == "Y" or tryag == "y":

This prompts user for input

     num = int(input("Input: "))

User input is appended to the list

     mylst.append(num)

This prompts user to try again the loop

     tryag = input("Another Input (Y/y): ")

This sorts the list from small to large

mylst.sort()

This prints 1. The minimum

print("Minimum: "+str(mylst[0]))

This prints 2. The maximum

print("Maximum: "+str(mylst[-1]))

The following iterates through the list

for i in mylst:

This calculates the total

     total = total + i

This checks for even entry

     if i%2 == 0:

This counts the number of even entries

           evens = evens + 1

This sums the even entries

           eventotal = eventotal + i

     else:

This counts the number of odd entries

           odds = odds + 1

This sums the odd entries

           oddtotal = oddtotal + i

This prints 3. Sum of Even entries

print("Evens: "+str(evens))

This prints 4. Sum of Odd entries

print("Odds: "+str(odds))

This prints 5. Average of Even entries

print("Even Average: "+str(eventotal/evens))

This prints 6. Average of Odd entries

print("Odd Average: "+str(oddtotal/odds))

This prints 7. Total Average

print("Total Average: "+str(total/(evens+odds)))

The if-else statement to describe an integer is given below.

The if-else statement to describe an integer will be:

#include <stdio.h>

#include <stdbool.h>

int main(void) {

int userNum;

bool isPositive;

bool isEven;

scanf("%d", &userNum);

isPositive = (userNum > 0);

isEven = ((userNum % 2) == 0);

if(isPositive && isEven){

  printf("Positive even number");

}

else if(isPositive && !isEven){

  printf("Positive number");

}

else{

  printf("Not a positive number");

}

printf("\n");

return 0;

}

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The output provided appears to be from the "ping" utility.

Ping is a network diagnostic   tool used to test the connectivity between two network devices,typically using the Internet Control Message Protocol (ICMP).

In this case, the output shows   the successful replies received from the IP address 64.78.193.84,along with the response time and time-to-live (TTL) value.

Ping is commonly used to troubleshoot   network connectivity issues and measureround-trip times to a specific destination.

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Answer: we need the awnser key

Explanation:

a) Lowest address: 0, Highest address: (2^20) - 1. b) Lowest address: 0, Highest address: ((2^20) / 2) - 1. c) Lowest address: 0, Highest address: ((2^20) / 4) - 1.

a) If memory is byte-addressable, the lowest address would be 0 and the highest address would be (2^20) - 1.

This is because each byte in the memory requires a unique address, and since there are 2^20 bytes in total, the highest address would be one less than the total number of bytes.

b) If memory is word-addressable with a 16-bit word, each word would consist of 2 bytes.

Therefore, the lowest address would be 0 (representing the first word), and the highest address would be ((2^20) / 2) - 1.

This is because the total number of words is equal to the total number of bytes divided by 2.

Subtracting 1 gives us the highest address, as the addresses are zero-based.

c) If memory is word-addressable with a 32-bit word, each word would consist of 4 bytes.

In this case, the lowest address would still be 0 (representing the first word), and the highest address would be ((2^20) / 4) - 1.

Similar to the previous case, the total number of words is equal to the total number of bytes divided by 4.

Subtracting 1 gives us the highest address.

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Answer:

I'm going to add a python program for this example, step by step:

We declare 4 variables for our zoo, zoo quantity, and the average.

We make the operation for the average where sum the zoo and divide with the quantity

In the last step, we print the variable avg_owls.

num_owls_zoo1 = 1

num_owls_zoo2 = 2

num_owls_zoo3 = 3

num_owls_zoo4 = 4

zoos = 4

avg_owls = 0.0

avg_owls=(num_owls_zoo1+num_owls_zoo2+num_owls_zoo3+num_owls_zoo4)/zoos

print('Average owls per zoo:', int(avg_owls))

Explanation:

The coding of the print avg_owls as an integer is written above.

We connect with computers through coding, often known as computer programming. Coding is similar to writing a set of instructions because it instructs a machine on what to do. You can instruct computers what to do or how to behave much more quickly by learning to write code.

We make the operation for the average, where sum the zoo and divide by the quantity.

In the last step, we print the variable avg_owls.

num_owls_zoo1 = 1

num_owls_zoo2 = 2

num_owls_zoo3 = 3

num_owls_zoo4 = 4

zoos = 4

avg_owls = 0.0

avg_owls=(num_owls_zoo1+num_owls_zoo2+num_owls_zoo3+num_owls_zoo4)/zoos

print('Average owls per zoo:', int(avg_owls))

Therefore, the coding is written above.

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Answer:

while(is_sunny=="n")

Explanation:

The loop keeps repeating itself until a certain condition is met.

Here while loop keeps executing until value of is_sunny is not equal to 'n'

When the value of is_sunny is not equal to n then the loop stops.

So lets explain this logic with a chunk of code:

#include <iostream> //to use input output functions

using namespace std; //to identify objects like cin cout

int main() {  //start of main function

  string is_sunny = "n"; //value of is_sunny is set to n

  cout<<"Enter value of is_sunny: "; // prompts user to enter value of is_sunny

  cin>>is_sunny; // reads value of is_sunny from user

  while(is_sunny=="n") // keeps iterating until value of is_sunny is not equal to n

  {   cout<<"keep executing until is_sunny is not equal to n"<<endl;//display this message with each iteration

      cout<<"Enter value of is_sunny: "; //keeps prompting to enter is_sunny

      cin>>is_sunny;   } } //keeps reading value of is_sunny from user

Now if the user keeps entering "n" as value of is_sunny then the loop keeps repeating. When the user enters any string other than n then the loop breaks. The output of the program is attached.

In the case above it is vital to meet with a professional in the field of digital forensics for a comprehensive analysis in the areas of:

First steps that need to be done at the beginning. One need to make sure the image file is safe by checking its code and confirming that nobody has changed it. Write down who has had control of the evidence to show that it is trustworthy and genuine.

Also, Investigate the picture file without changing anything using special investigation tools. Find out what type of system is used on the hard drive. Typical ways to store files are NTFS, FAT32 and exFAT.

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The following column names, data types, and constraints:

CREATE TABLE Student (

ID INTEGER (65000) AUTO _ I NCREMENT PRIMARY KEY,

FirstName VA RCHAR (20) NOT NULL,

LastName VARCH AR(30) NOT NULL,

Street VARCH AR(50) NOT NULL,

City VA RC HAR(20) NOT NULL,

State CHAR (2) NOT NULL DEFAULT 'TX',

Zip INTEGER (16000000) NOT NULL,

Phone  CHAR (10) NOT NULL,

Email VAR C HAR(30) UNIQUE NOT NULL

);

VARCHAR, which stands for Variable Character, is a data type used in data bases and programming languages to store character strings of variable length. This type of data is often used for storing text-based information, such as names, addresses, descriptions, and other data that does not require numerical calculations to be performed.

VARCHAR data is stored as a string of characters, and can be used to store up to a predetermined maximum length of characters. This maximum length is typically specified when the database or program is set up and is usually determined by the user or programmer.

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Advntage:

provides CPU scheduling, memory management, file management, and other operating system functions through system calls. The other one is that it is a single large process running entirely in a single address space.

Disadvantage: if anyone service fails it leads to an entire system failure

Answer:

software developer- microsoft certified solutions developer

help desk technician- CompTIAA+
network design architect- Cisco certified internetwork expert

Explanation

edmentum

In this exercise we have to use the knowledge in computational language in python to write the following code:

We have the code can be found in the attached image.

So in an easier way we have that the code is:

function v = myfib(n,v)

if nargin==1

   v = myfib(n-1,[0,1]);

elseif n>1

   v = myfib(n-1,[v,v(end-1)+v(end)]);

end

end

function v = myfib(n,v)

if nargin==1

   v = myfib(n-1,[0,1]);

elseif n>1

   v = myfib(n-1,[v,v(end-1)+v(end)]);

elseif n<1

   v = 0;

end

function [n] = abcd(x)

if (x == 1 || x==0)

   n = x;

   return

else

   n = abcd(x-1) + abcd(x-2);

end

end

fibonacci = [0 1];

for i = 1:n-2

   fibonacci = [fibonacci fibonacci(end)+fibonacci(end-1)];

end

>> myfib(8)

ans =

   0    1    1    2    3    5    8   13

>> myfib(10)

ans =

   0    1    1    2    3    5    8   13   21   34

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Answer:

CC BY-NC-SA

Explanation:

BY ==> credit has to be given to original author

NC ==> non-commercial

SA  ==>Share alike ; modified work should be reused under the original license