17. A moving truck fills up a shipment at an old
address at (-2, 1). It travels 7 blocks south and 6
blocks east to the new address. What is the
location of the new address?

The binary representations are a) 0.11000110, b) 0.10000010 and c) 0.10100000.

Let's convert the given real numbers to binary with 8 binary places after the radix point.

A. 0.11:

To convert 0.11 to binary, we can use the following steps:

Multiply 0.11 by 2:

0.11 × 2 = 0.22

Take the integer part of the result, which is 0, and write it down.

Multiply the decimal part of the result by 2:

0.22 × 2 = 0.44

Again, take the integer part (0) and write it down.

Repeat steps 3 and 4 until you reach the desired precision (8 binary places after the radix point).

0.44 × 2 = 0.88 (integer part: 0)

0.88 × 2 = 1.76 (integer part: 1)

0.76 × 2 = 1.52 (integer part: 1)

0.52 × 2 = 1.04 (integer part: 1)

0.04 × 2 = 0.08 (integer part: 0)

0.08 × 2 = 0.16 (integer part: 0)

0.16 × 2 = 0.32 (integer part: 0)

0.32 × 2 = 0.64 (integer part: 0)

Write down the integer parts obtained in step 4 and 5, in order:

0.11000110

Therefore, the binary representation of 0.11 with 8 binary places after the radix point is 0.11000110.

B. 0.51:

To convert 0.51 to binary, we can use the same steps:

Multiply 0.51 by 2:

0.51 × 2 = 1.02

Take the integer part of the result, which is 1, and write it down.

Multiply the decimal part of the result by 2:

0.02 × 2 = 0.04

Again, take the integer part (0) and write it down.

Repeat steps 3 and 4 until you reach the desired precision (8 binary places after the radix point).

0.04 × 2 = 0.08 (integer part: 0)

0.08 × 2 = 0.16 (integer part: 0)

0.16 × 2 = 0.32 (integer part: 0)

0.32 × 2 = 0.64 (integer part: 0)

0.64 × 2 = 1.28 (integer part: 1)

0.28 × 2 = 0.56 (integer part: 0)

0.56 × 2 = 1.12 (integer part: 1)

0.12 × 2 = 0.24 (integer part: 0)

Write down the integer parts obtained in step 4 and 5, in order:

0.10000010

Therefore, the binary representation of 0.51 with 8 binary places after the radix point is 0.10000010.

C. 0.625:

To convert 0.625 to binary, we can use the same steps:

Multiply 0.625 by 2:

0.625 × 2 = 1.25

Take the integer part of the result, which is 1, and write it down.

Multiply the decimal part of the result by 2:

0.25 × 2 = 0.50

Again, take the integer part (0) and write it down.

Repeat steps 3 and 4 until you reach the desired precision (8 binary places after the radix point).

0.50 × 2 = 1.00 (integer part: 1)

0.00 × 2 = 0.00 (integer part: 0)

0.00 × 2 = 0.00 (integer part: 0)

0.00 × 2 = 0.00 (integer part: 0)

0.00 × 2 = 0.00 (integer part: 0)

0.00 × 2 = 0.00 (integer part: 0)

0.00 × 2 = 0.00 (integer part: 0)

0.00 × 2 = 0.00 (integer part: 0)

Write down the integer parts obtained in step 4 and 5, in order:

0.10100000

Therefore, the binary representation of 0.625 with 8 binary places after the radix point is 0.10100000.

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Answer:

there will only be one 3

Step-by-step explanation:

see cause the first 3 of both numbers are 2 but only the last one of both numbers are 3 .

The THREE true statements regarding the graph of B(w) are;

A) Based on the zeros of the function, the number of boxes of cereal sold is 0 after 0 weeks.

C) Based on the end behavior of the function, the number of boxes of cereal sold will keep falling after reaching the maximum.

E) Based on the asymptote of the function, the number of boxes of cereal sold will never reach 0 after the cereal is introduced in the store.

We are given the graph represented by the quadratic function;

B(w) = 120w/(150 + w²) for w ≥ 0 that models;

the number of boxes, B, in thousands, of the cereal sold after w weeks

From the graph, we can see that at the origin which is the coordinate (0, 0) that it remains so and as such the number of boxes of cereal sold is 0 after 0 weeks. Thus, option A is correct

Secondly, from the given graph, we see that the graph starts rising from zero to a maximum after which it keeps falling. Thus, we can say that option C is correct

Lastly, we see that the graph asymptote approaches 500 thousand boxes but never gets to zero and as such we can say that option E is correct.

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Answer:

23

Step-by-step explanation:

Given in the picture below (BODMAS rule is applied)

I hope my answer helps you

Answer:

Step-by-step explanation:

5 + 2 x 3² =                         (remember PEMDAS)

5 + 2 x 9 =

5 + 18 =

23

The equation of the tangent plane to z = x2 5y3 at (1, 1, 6) is 2(x - 1) - 15(y - 1) - (z - 6) = 0

To find the equation of the tangent plane to the surface z = x^2 - 5y^3 at (1, 1, 6), we need to first find the gradient vector of the surface at the given point.

The gradient vector of the surface z = f(x, y) is given by:

∇f(x, y) = <fx, fy, -1>

where fx and fy are the partial derivatives of f with respect to x and y, respectively.

Taking the partial derivatives of z = x^2 - 5y^3 with respect to x and y, we get:

fx = 2x

fy = -15y^2

Therefore, the gradient vector at (1, 1, 6) is:

∇f(1, 1) = <2, -15, -1>

Now, we can use the point-normal form of the equation of a plane to find the equation of the tangent plane. The point-normal form of the equation of a plane is given by:

n . (r - P) = 0

where n is the normal vector to the plane, P is a point on the plane, and r = <x, y, z> is any point on the plane.

At the point (1, 1, 6), the equation of the tangent plane is:

<2, -15, -1> . (<x, y, z> - <1, 1, 6>) = 0

Simplifying this equation, we get:

2(x - 1) - 15(y - 1) - (z - 6) = 0

Therefore, the equation of the tangent plane to z = x^2 - 5y^3 at (1, 1, 6) is:

2(x - 1) - 15(y - 1) - (z - 6) = 0

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Answer:

Interest earned: $30    Balance: $230

Step-by-step explanation:

The equation that models the balance y after x months is y = 1600 - 145x

Price Zachary purchased the computer = $1600

Remaining balance after 5 months = $875

Amount deducted in 5 months = 1600 - 875 = $725

Remaining balance after 7 months = $585

Amount deducted in 7 months = 1600 - 585 = $1015

So, amount deducted each month = Amount deducted in 5 months/Number of months = 725/5 = $145

Let y be the balance after x months, formulating the equation we get

Balance after x months = Initial amount - Amount deducted each month* Number of months

y = 1600 - 145x

Hence, the equation that models the problem is y = 1600 - 145x

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Step-by-step explanation:

=

38.64=9.2h/2

=

38.64=4.6h

=

h = 38.64/4.6

h = 8.4

thats it

The graph of the function f(x)=x²+6x²-36x is shown below: Graph of the function f(x)=x²+6x²-36xTo find the absolute maximum and minimum values of the function, we need to find its critical points and its value at the endpoints of its domain. To find the critical points, we differentiate the function f with respect to x and set the derivative equal to zero to solve for x: f'(x) = 2x + 12x - 36 = 0

Simplifying the above equation gives:

2x + 12x - 36 = 0

=> 14x - 36 = 0

=> 14x = 36

=> x = 36/14

Therefore, the only critical number of the function is 36/14, which is approximately equal to 2.57.We also need to check the endpoints of the domain of the function, which is the set of all real numbers. Since the domain is infinite, we need to take the limit of the function as x approaches infinity and negative infinity. We have:

f(x) = x²+6x²-36xf(x) = 7x²-36x

As x approaches infinity, f(x) approaches positive infinity, and as x approaches negative infinity, f(x) approaches positive infinity.

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Answer:

y = 1

Step-by-step explanation:

\(\frac{6}{2}=\frac{2(y+2)}{2}\\ \Leftrightarrow 3-2=y=2-2\\\Leftrightarrow y=1\)

The solution to the given equation 6 = 2(y+2) is y = 1, which is determined by distribution and arithmetic operations.

The equation is given as follows:

6 = 2(y+2)

To solve the equation 6 = 2(y + 2) for y, we need to isolate y on one side of the equation.

First, distribute the 2 on the left side by multiplying it with y and 2:

6 = 2y + 4.

Next, move the constant term (4) to the other side of the equation by subtracting it from both sides:

6 - 4 = 2y

2 = 2y

y = 2/2

Apply division operation to get:

y = 1

Therefore, the solution to the given equation is y = 1.

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Stephanie and Brett will be 89.25 miles apart after 9.92 hours of cycling, as they are cycling in opposite directions at different speeds.

Stephanie and Brett are cycling in opposite directions at different speeds. Stephanie's average speed is 9 miles per hour, and Brett's average speed is 8 miles per hour. To determine when they will be 89.25 miles apart, we can use the formula:

Distance = Speed x Time

Since they are moving in opposite directions, their distances are additive. Let's assume t is the time in hours:

Stephanie's distance = 9t

Brett's distance = 8t

The sum of their distances should be equal to 89.25 miles:

9t + 8t = 89.25

Simplifying the equation:

17t = 89.25

Dividing both sides by 17:

t = 89.25 / 17 ≈ 5.25

Therefore, Stephanie and Brett will be 89.25 miles apart after approximately 5.25 hours of cycling.

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Answer:

7

2

-3

-8

Step-by-step explanation:

To do this, you plug in the given x-values:

y = -5(-1) + 2 = 5 + 2 = 7

y = -5(0) + 2 = 0 + 2 = 2

y = -5(1) + 2 = -5 + 2 = -3

y = -5(2) + 2 = -10 + 2 = -8

Answer:

(a) 48/60 = 4/5

(b) 150/60 = 15/6 = 5/2 = 2 1/2

(c) 84/98 = 12/14 = 6/7

(d) 12/52 = 3/13

(e) 7/28 = 1/4

The fractions reduced to their simplest form:

(a) 48/60 simplifies to 4/5.

(b) 150/60 simplifies to 5/2.

(c) 84/98 simplifies to 6/7.

(d) 12/52 simplifies to 3/13.

(e) 7/28 simplifies to 1/4.

Let's discuss each question separately:

(a) To reduce the fraction 48/60 to simplest form, we need to find the greatest common divisor (GCD) of both numbers. The GCD of 48 and 60 is 12. Dividing both the numerator and denominator by 12 gives us the simplified fraction 4/5.

(b) For the fraction 150/60, we find that the GCD of 150 and 60 is 30. Dividing both the numerator and denominator by 30 results in the simplified fraction 5/2.

(c) The fraction 84/98 can be simplified by dividing both the numerator and denominator by their GCD, which is 14. This gives us the simplest form of 6/7.

(d) To simplify the fraction 12/52, we calculate the GCD of 12 and 52, which is 4. Dividing both numbers by 4 yields the simplest form of 3/13.

(e) The fraction 7/28 can be simplified by dividing both the numerator and denominator by their GCD, which is 7. This simplifies the fraction to 1/4.

In summary, the fractions in their simplest forms are:

(a) 4/5

(b) 5/2

(c) 6/7

(d) 3/13

(e) 1/4.

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The elevation of the cave in feet will be negative 72 feet. Then the correct option is D.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

A jumper is at a height of - 18 feet comparative with ocean level. The jumper plunges to an undersea cavern that is 4 times as distant from the surface

The elevation of the cave is given as,

Elevation = - 18 x 4

Elevation = - 72 feet

The elevation of the cave in feet will be negative 72 feet. Then the correct option is D.

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Step-by-step explanation:

PYTHAGORAS THEOREM

\( {c}^{2} - {b}^{2} = {a}^{2} \\ {7}^{2} - {5}^{2} = {x}^{2} \\ 49 - 25 = 24 \\ \sqrt{24} = 4.89897948557\)

9. Yes, since \(8+12>16\), meaning the side lengths satisfy the triangle inequality.

10. No, since \(5+7<20\), meaning the side lengths do not satisfy the triangle inequality.

Therefore , the answer is  the confidence interval is positive, the researcher can conclude there is a greater proportion of men than women who watch television regularly.

A confidence interval in frequentist statistics is a range of estimates for an unobserved parameter. The most common confidence level for computing confidence intervals is 95%, however other levels, including 90% or 99%, are sporadically employed.

Here,

Assuming that the confidence interval's lower and upper bounds are both positive and that it does, then one of the proportions must be larger than the other as the confidence interval's range corresponds to the difference in proportions. Men watch television more frequently than women do (56/70 vs. 47/85, according to a quick calculation of the proportions).

The reply is "D" The researcher can infer that more men than women routinely watch television because the confidence interval is positive.

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Answer:

  A.  6%, $448 million

Step-by-step explanation:

a) The base of the exponential term is 1.06, so the projected annual growth is 1.06 -1 = .06 = 6%

__

b) Filling in 11 for t, we find the projected worth to be ...

  w = 236(1.06^11) ≈ $448 . . . million

The pollster should survey approximately 2,401 U.S. voters to estimate the true proportion of voters who oppose capital punishment with 95% confidence and a margin of error of 2%.

In order to estimate the true proportion of U.S. voters who oppose capital punishment with a 95% confidence level and a margin of error of 2%, the pollster should survey approximately 2,401 voters.



To calculate the sample size needed for this estimation, we can use the formula:

n = (Z² * p * q) / E²

where n is the sample size, Z is the z-score corresponding to the confidence level (in this case, 1.96 for 95% confidence), p is the estimated proportion of voters who oppose capital punishment, q is the estimated proportion of voters who support capital punishment (which is 1-p), and E is the desired margin of error (in this case, 0.02).

Assuming a conservative estimate of p = q = 0.5, we can plug in the values and solve for n:

n = (1.96² * 0.5 * 0.5) / 0.02² ≈ 2,401

Therefore, the pollster should survey approximately 2,401 U.S. voters to estimate the true proportion of voters who oppose capital punishment with 95% confidence and a margin of error of 2%.



In conclusion, to estimate the true proportion of U.S. voters who oppose capital punishment with a 95% confidence level and a margin of error of 2%, the pollster should survey approximately 2,401 voters. This sample size calculation is based on the formula for calculating sample size using the z-score, estimated proportions, and desired margin of error

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Answer:

2x + 3

Step-by-step explanation:

Step 1: Write expression

8x - 6 - (6x - 9)

Step 2: Distribute negative

8x - 6 - 6x + 9

Step 3: Combine like terms (x)

2x - 6 + 9

Step 4: Combine like terms (constants)

2x + 3

The probability value of (m, n) is (1, 2^1005).

Let n be a positive odd integer. We are asked to find the probability that its reciprocal gives a terminating decimal. This is equivalent to saying that the only prime factors of n are 2 and 5 because any other prime factor will yield a repeating decimal.

If n is less than 2010, then its only possible prime factors are 3, 7, 11, ..., 2009, since all primes greater than 2009 are greater than n. We want n to have no prime factors other than 2 and 5. There are 1005 odd integers less than 2010.

We want to count how many of these have no odd prime factors other than 3, 7, 11, ..., 2009. This is equivalent to counting how many subsets there are of {3, 7, 11, ..., 2009}. There are 1004 primes greater than 2 and less than 2010. Each of these primes is either in a subset or not in a subset. Thus, there are 2^1004 subsets of {3, 7, 11, ..., 2009}, including the empty set.

Thus, the probability is:

P = (number of subsets with no odd primes other than 3, 7, 11, ..., 2009) / 2^1004

We can count this number using the inclusion-exclusion principle. Let S be the set of odd integers less than 2010. Let Pi be the set of odd integers in S that are divisible by the prime pi, where pi is a prime greater than 2 and less than 2010. Let Pi,j be the set of odd integers in S that are divisible by both pi and pj, where i < j.

Then, the number of odd integers in S that have no prime factors other than 2 and 5 is:

|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...|

where the union is taken over all sets of primes with at least one element and less than or equal to 1005 elements.

By the inclusion-exclusion principle:

|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...| = ∑ (-1)^k ⋅ (∑ |Pi1,i2,...,ik|)

where the outer summation is from k = 0 to 1005, and the inner summation is taken over all combinations of primes with k elements.

This simplifies to:

(1/2) ⋅ (2^1004 + (-1)^1005)

Thus, the probability is: P = (1/2^1004) ⋅ (1/2) ⋅ (2^1004 + (-1)^1005) = 1/2 + 1/2^1005. Hence, (m, n) = (1, 2^1005).

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Complete question:

If m/n is the probability that the reciprocal of a randomly selected positive odd integer less than 2010 gives a terminating decimal, with m and n being relatively prime positive integers. what is probability value of m and n?

The probability value of (m, n) is (1, 2^1005).This is equivalent to saying that the only prime factors of n are 2 and 5 because any other prime factor will yield a repeating decimal.

Let n be a positive odd integer. We are asked to find the probability that its reciprocal gives a terminating decimal. This is equivalent to saying that the only prime factors of n are 2 and 5 because any other prime factor will yield a repeating decimal.

If n is less than 2010, then its only possible prime factors are 3, 7, 11, ..., 2009, since all primes greater than 2009 are greater than n. We want n to have no prime factors other than 2 and 5. There are 1005 odd integers less than 2010.

We want to count how many of these have no odd prime factors other than 3, 7, 11, ..., 2009. This is equivalent to counting how many subsets there are of {3, 7, 11, ..., 2009}. There are 1004 primes greater than 2 and less than 2010. Each of these primes is either in a subset or not in a subset. Thus, there are 2^1004 subsets of {3, 7, 11, ..., 2009}, including the empty set.

Thus, the probability is:

P = (number of subsets with no odd primes other than 3, 7, 11, ..., 2009) / 2^1004

We can count this number using the inclusion-exclusion principle. Let S be the set of odd integers less than 2010. Let Pi be the set of odd integers in S that are divisible by the prime pi, where pi is a prime greater than 2 and less than 2010. Let Pi,j be the set of odd integers in S that are divisible by both pi and pj, where i < j.

Then, the number of odd integers in S that have no prime factors other than 2 and 5 is:

|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...|

where the union is taken over all sets of primes with at least one element and less than or equal to 1005 elements.

By the inclusion-exclusion principle:

|S - ⋃ Pi + ⋃ Pi,j - ⋃ Pi,j,k + ...| = ∑ (-1)^k ⋅ (∑ |Pi1,i2,...,ik|)

where the outer summation is from k = 0 to 1005, and the inner summation is taken over all combinations of primes with k elements.

This simplifies to:

\((1/2) * (2^{1004} + (-1)^1005)\)

Thus, the probability is: P = \((1/2)^{1004}* (1/2) *(2^{1004} + (-1)^{1005}) = 1/2 + 1/2^{1005}.\)

Hence, (m, n) = (\(1, 2^{1005\)).

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Using line tangent, the approximation for f(2.1) is 3.95

Given,

The point (a, f(a)) is on the line tangent to the graph of y = f(x) at x = a, which has a slope of f'(a).

The equation be like;

y - f(a) / (x - a) = f'(a)

y = f'(a) (x - a) + f(a)

Using the provided data and a = 2, we can determine that the tangent line to the graph of y = f(x) at x = 2 has equation

y = f'(2) (x - 2) + f(2)

y = -1/2 (x - 2) + 4

To compute a "approximation of f(2.1) using the line tangent to the graph of f at x = 2," one must substitute x = 2.1 for f in the equation for the tangent line (2.1). You get 2.1 when you plug this in.

y = -1/2 (x - 2) + 4

y = -1/2 (2.1 - 2) + 4

y = -1/2 x 0.1 + 4

y = 3.95

That is,

The approximation for f(2.1) using line tangent is 3.95

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The force on the longer side of the aquarium based on the information is A. 1000 lb.

The hydrostatic force on a surface is equal to the pressure at the centroid of the surface multiplied by the area of the surface. The pressure at the centroid of the surface is equal to the density of the water multiplied by the depth of the centroid. The area of the surface is equal to the length of the surface multiplied by the width of the surface.

In this case, the density of the water is 62.5 lb/ft³, the depth of the centroid is 2 ft, the length of the surface is 4 ft, and the width of the surface is 2 ft. Therefore, the hydrostatic force on the longer side of the aquarium is:

F = 62.5 lb/ft³ * 2 ft * 4 ft * 2 ft

= 1000 lb

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Answer:

65/100

Step-by-step explanation:

The number 65 stays the same all  you have to do is add the numbers up to get 100

Answer:

C

Step-by-step explanation:

Slope of UV = 0 = Slope of XW

So UV is parallel to XW.

Slope of UX = [6-(-4)]/[-7-(-3)] = -5/2

Slope of VW = [6-(-4)]/(0-4) = -5/2

Slope of UX = Slope of VW i.e. UX is parallel to VW.

It is a parallelogram because opposite sides are parallel.

Answer:

Yes, because opposite sides are parallel.

Step-by-step explanation: I took the test

Answer:

9

Step-by-step explanation:

The diagram showing the three pieces of paper of three digit in which two of the letters were covered can be seen below.

From the diagram; we have;

243 , 1_7 , _26

Assuming the covered digits are _

The sum is 826.

i.e

243 + 1_7 + _26 = 826

The objective is to determine the sum of the two unknown digits

So; we need to think about what number can we add put in 1_7 to determine the covered digit in  _26

From ; 1_7 , we have the choice to pick from 0 - 9

Assuming the covered digit is 0; let's check if we are right

So; 243 + 107  +  _26 = 826

350 +   _26 = 826

_26 = 826 - 350

_26 = 476

So; the covered digit is in the position of 4 , but it doesn't tally together

i.e 426 is not the same as 476, which makes our assumption to be wrong.

Let consider the covered digit to be 5 for example.

So; 243 + 157  +  _26 = 826

400 +   _26 = 826

_26 = 826 - 400

_26 =  426

The covered digit is in the position of 4

SO;

426 = 426

Here , our assumption is right.

As such , the covered digits are 5 and 4

The sum of the two  covered digits are = 5 + 4 = 9

Answer:

-1/2

Step-by-step explanation:

The slope is always the value with the x.

Answer:

Slope = - 1/2x

Step-by-step explanation:

The limit - A. lim 3x = 21, x → 7. The correct choice is A.

The limit of 3x as x approaches 7 can be evaluated by substituting the value 7 into the expression 3x:

lim 3x = 3(7) = 21.

x → 7

Therefore, the correct choice is:

A. lim 3x = 21.

x → 7

To elaborate further, when we evaluate the limit of 3x as x approaches 7, we substitute the value of 7 into the expression 3x. This gives us:

lim (3x) = 3(7) = 21

This means that as x gets arbitrarily close to 7 (but not equal to 7), the value of 3x approaches 21. In other words, as we consider x values approaching 7 from both the left and the right sides, the corresponding values of 3x approach 21.

Therefore, the limit exists and we can determine its value (which is 21), we can conclude that the limit of 3x as x approaches 7 is indeed 21 (Choice A).

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