1,992 registered voters were ask "Based on what you know, do you believe the United States is winning or losing the War in Afghanistan?" 23% responded we are winning. 38% responded we are losing. 39% responded Don’t Know/No Opinion. The reported margin of error was +/-2%.

What is the lower bound for the 95% confidence interval for the percentage of voters that believe that the United States is losing the War?

Enter your answer as a percentage rounded to the nearest tenth of a percent.

Answer:

The statements that can be used to compare the characteristics of the functions are:

1. g(x) has the greatest maximum value.

2. All three functions share the same domain.

Explanation:

- The table shows the values of three functions - f(x), g(x), and h(x) - evaluated at different values of x.

- We cannot determine the domain of f(x) or h(x) from the given table but we can see that g(x) has a domain of all real numbers.

- We can see that g(x) has the highest maximum value among the three functions, which is 8.

- We cannot determine the range of f(x) or g(x) from the given table but we can see that h(x) has a range of all negative numbers.

- We cannot say anything about the domain or range of f(x) based on the given table.

- Therefore, the two statements that can be used to compare the characteristics of the functions are: g(x) has the greatest maximum value and all three functions share the same domain.

The english phrase "Seven less than four times a number" as an algebraic expression is 4x - 7

From the question, we have the following parameters that can be used in our computation:

seven less than four times a number

Represent the number with x

So:

four times a number means 4x

So, we have

seven less than 4x

seven less than means - 7

So, we have

4x - 7

Hence, the english phrase as an algebraic expression is 4x - 7

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Complete question

write the english phrase as an algebraic expression. Let x represent the number

Seven less than four times a number

The width RQ of the river is approximately 61.98 ft.

To find the width RQ of the river, we can use the properties of perpendicular lines and collinearity.

Given that Karl starts at point R and walks perpendicular along the edge of the river 42 ft to point S, we can draw a line segment RS of length 42 ft.

From point S, Karl walks 28 ft further to point T. We can draw another line segment ST of length 28 ft.

Now, Karl turns 90° from point T and walks until his location (point U), point S, and point Q are collinear. Let's denote the length of this line segment as UQ.

From the given information, we know that TU = 68 ft.

Since U, S, and Q are collinear, we can form a right triangle by connecting UQ and US.

The length of UQ can be found using the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

In this case, we have:

UQ² = TU² - US²

UQ² = 68² - 28²

UQ² = 4624 - 784

UQ² = 3840

Taking the square root of both sides, we have:

UQ = √3840

UQ ≈ 61.98 ft

Therefore, the width RQ of the river is approximately 61.98 ft.

Note: It's important to keep in mind that this solution assumes the river is a straight line and that Karl's path is perpendicular to the river's edge. In reality, the river's edge may not be perfectly straight, and the path Karl walks may not be exactly perpendicular.

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The number of weeks that Vanessa ran for the number of miles given would be = 24 weeks

The amount of distance that Vanessa covers for a week = 4 miles

The amount of weeks it will take for her to cover 96 moles would be = ?

That is;

1 week = 4 miles

X weeks = 96 miles

Make X the subject of formula;

X = 96× 1/4

= 24 weeks

Therefore Vanessa will be able to cover 96 miles in only 24 weeks.

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Graph #1:

Degree = 2

x-intercept = (0, 0)

y-intercept = (0, 0)

Graph #2:

Degree = 3

x-intercept = (3, 0) and (7, 0)

y-intercept = (0, -6)

Graph #3:

Degree = 3

x-intercept = (0, 0) and (3, 0)

y-intercept = (0, 0)

Graph #4:

Degree = 2

x-intercept = (1, 0)

y-intercept = (0, 1)

The coordinates in a graph indicate the location of a point with respect to the x-axis and y-axis.

The coordinates in a graph show the relationship between the information plotted on the given x-axis and y-axis.

We have,

The degree of the function on the graph is given by (n + 1).

Where n is the number of turning points.

Turning points are the points where the graph goes up to down or down to up.

And,

The x-intercept is the point where the graph touches the x-axis when y = 0.

The y-intercept is the point where the graph touches the y-axis when x = 0.

Now,

Using the above concept,

Graph #1:

Degree = 2

i.e,

n = 1 so,

n + 1 = 1 + 1 = 2

x-intercept = (0, 0)

y-intercept = (0, 0)

Graph #2:

Degree = 3

i.e,

n = 2 so,

2 + 1 = 2 + 1 = 3

x-intercept = (3, 0) and (7, 0)

y-intercept = (0, -6)

Graph #3:

Degree = 3

i.e,

n = 1 so,

n + 1 = 2 + 1 = 3

x-intercept = (0, 0) and (3, 0)

y-intercept = (0, 0)

Graph #4:

Degree = 2

i.e,

n = 1 so,

n + 1 = 1 + 1 = 2

x-intercept = (1, 0)

y-intercept = (0, 1)

Thus,

The degree, x-intercept, and y-intercept of graph #1 are 2, (0, 0), and (0, 0).

The degree, x-intercept, and y-intercept of graph #2 are 3, (3, 0), and (7, 0), and (0, -6).

The degree, x-intercept, and y-intercept of graph #3 are 3, (0, 0), and (3, 0), and (0, 0).

The degree, x-intercept, and y-intercept of graph #4 are 2, (1, 0), and (0, 1).

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keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

\(3x+y=5\implies y=\stackrel{\stackrel{m}{\downarrow }}{-3}x+5\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\)

so we're really looking for the equation of a line that has a slope oif -3 and it passes through (2 , -4)

\((\stackrel{x_1}{2}~,~\stackrel{y_1}{-4})\hspace{10em} \stackrel{slope}{m} ~=~ - 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{- 3}(x-\stackrel{x_1}{2}) \implies y +4 = - 3 ( x -2) \\\\\\ y+4=-3x+6\implies {\Large \begin{array}{llll} y=-3x+2 \end{array}}\)

now, keeping in mind that perpendicular lines have negative reciprocal slopes

\(\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{ -3 \implies \cfrac{-3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{-3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{-3} \implies \cfrac{1}{ 3 }}}\)

so for this one, we're looking for the equation of a line whose slope is 1/3 and it passes through (2 , -4)

\((\stackrel{x_1}{2}~,~\stackrel{y_1}{-4})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{ \cfrac{1}{3}}(x-\stackrel{x_1}{2}) \implies y +4 = \cfrac{1}{3} ( x -2) \\\\\\ y+4=\cfrac{1}{3}x-\cfrac{2}{3}\implies y=\cfrac{1}{3}x-\cfrac{2}{3}-4\implies {\Large \begin{array}{llll} y=\cfrac{1}{3}x-\cfrac{14}{3} \end{array}}\)

Here we have a dilation of scale factor 2.

We can see that bot figures we have the same slope, so we just have a dilation of scale factor K to go from figure A to figure B.

To find the value of K, notice that for some side length L in figure A, the correspondent length L' in figure B must be:

L' = K*L

Here if we use the left sides, we will get:

for figure A; L= 2

for figure B: L = 4

4 = K*2

4/2 = K

2 = K

So this is a dilation of scale factor k = 2.

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Answer:

(fog)(x) = \( x \)

Step-by-step explanation:

Given:

\( f(x) = \frac{x - 1}{3} \)

\( g(x) = 3x + 1 \)

Required:

(fog)(x)

SOLUTION:

(fog)(x) = f(g(x))

Substitute 3x + 1 into \( f(x) = \frac{x - 1}{3} \)

f(g(x)) = \( \frac{(3x + 1)- 1}{3} \)

\( = \frac{3x + 1 - 1}{3} \)

\( = \frac{3x}{3} \)

\( = \frac{x}{1} \)

(fog)(x) = \( x \)

Answer:

is it A and C ):

Step-by-step explanation:

The value of h is 8 units.

"Two triangles are similar when their corresponding sides are in proportion and all corresponding angles are equal."

For given question,

ΔBAD and ΔCBD are similar triangle.

So, their sides are in proportion.

\(\Rightarrow \frac{BA}{CB}= \frac{AD}{BD}= \frac{BD}{CD}\)                    ..................(i)

For given figure,

BD = h, CD = 4 units

Now, we find the length of the side AD.

⇒ AD = AC - CD

⇒ AD = 20 - 4

⇒ AD = 16 units

From (i),

\(\Rightarrow \frac{AD}{BD}= \frac{BD}{CD} \\\\\Rightarrow \frac{16}{h} =\frac{h}{4}\\\\ \Rightarrow 16\times 4=h\times h\\\\\Rightarrow h^2=64\\\\\Rightarrow h=8\)

Therefore, the value of h is 8 units.

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Answer:

Use Tiger Algebra it helps with all answers i just didn't feel like typing it

Step-by-step explanation:

Answer:

x = - 5 , x = 7

Step-by-step explanation:

to find the zeros, let y = 0 , that is

x² - 2x - 35 = 0

consider the factors of the constant term (- 35) which sum to give the coefficient of the x- term (- 2)

the factors are - 7 and + 5 , since

- 7 × + 5 = - 35 and - 7 + 5 = - 2 , then

x² - 2x - 35 = (x - 7)(x + 5) = 0

equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

x - 7 = 0 ⇒ x = 7

The length of the rectangle is twice its width. If its perimeter is 7 1/3 cm, its length will be 22/9 cm, and the width is 11/9 cm.

Let's assume the width of the rectangle is "b" cm.

According to the given information, the length of the rectangle is twice its width, so the length would be "2b" cm.

The formula for the perimeter of a rectangle is given by:

Perimeter = 2 * (length + width)

Substituting the given perimeter value, we have:

7 1/3 cm = 2 * (2b + b)

To simplify the calculation, let's convert 7 1/3 to an improper fraction:

7 1/3 = (3*7 + 1)/3 = 22/3

Rewriting the equation:

22/3 = 2 * (3b)

Simplifying further:

22/3 = 6b

To solve for "b," we can divide both sides by 6:

b = (22/3) / 6 = 22/18 = 11/9 cm

Therefore, the width of the rectangle is 11/9 cm.

To find the length, we can substitute the width back into the equation:

Length = 2b = 2 * (11/9) = 22/9 cm

So, the length of the rectangle is 22/9 cm, and the width is 11/9 cm.

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i don't now all of them but

3.is "A"

4.is "C"

* By definition, the sum of the interior angles of a triangle is 180 degrees.  

* Keeping this in mind, you have:

As you can see, the sum of the other two angles must be 108 degrees, then, let's add the angles given in each option:

A) 9°+9°=18

B) 26°+46°=72°

C)53°+55°=108°

D)72°+108°=180°

*Therefore, the answer is option C.  

5.is "B"

A triangle is called a right triangle when one of it's angles measures 90°.

We have been given the second angle as 14°.

The angles in a triangle add up to 180°.

∴ letting the third angle to be X;

X + 14° + 90° = 180°

X + 104° = 180°

X = 180° - 104°

= 76°

7. the answer is "B"

A = 41 * 14 / 2

A = 574 / 2

A = 287 cm²

So, the area of the trapezoid is 287 cm².

9. is "B"

Area = base x height

Or 356.25=14.25 x Height

Dividing both sides by 14.25

Height =25inches

.Height of the parallelogram is 25 inches. the answer is "B"

10.is "B"

the sum of any 2 sides of a triangle must be greater than the third side

Answer:

\(6x^4y^8\sqrt{5x}\)

Step-by-step explanation:

\(\textsf{When $x > 0$ and $y > 0$, we want to find the expression that is equivalent to}\) \(\sqrt{180x^9y^{16}}.\)

\(\textsf{First, apply the radical rule:} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}\)

\(\sqrt{180}\sqrt{x^9}\sqrt{y^{16}}\)

\(\textsf{Rewrite $x^9$ as $x^{8+1}$:}\)

\(\sqrt{180}\sqrt{x^{(8+1)}}\sqrt{y^{16}}\)

\(\textsf{Apply the exponent rule:} \quad a^{b+c}=a^b \cdot a^c\)

\(\sqrt{180}\sqrt{x^{8}\cdot x^1}\sqrt{y^{16}}\)

\(\sqrt{180}\sqrt{x^{8}}\sqrt{x}\sqrt{y^{16}}\)

\(\textsf{Apply\:the\:radical\:rule:\:}\sqrt[n]{a^m}=a^{\frac{m}{n}},\:\quad a\geq 0\)

\(\sqrt{180}\;x^{\frac{8}{2}}\sqrt{x}\;y^{\frac{16}{2}}\)

\(\sqrt{180}\;x^4\sqrt{x}\;y^8\)

\(\sqrt{180}\sqrt{x}\;x^4\;y^8\)

\(\textsf{Rewrite $180$ as $(6^2 \cdot 5)$:}\)

\(\sqrt{6^2 \cdot 5}\sqrt{x}\;x^4\;y^8\)

\(\textsf{Apply the radical rule:} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}\)

\(\sqrt{6^2} \sqrt{5}\sqrt{x}\;x^4\;y^8\)

\(\textsf{Apply the radical rule:} \quad \sqrt{a^2}=a, \quad a \geq 0\)

\(6 \sqrt{5}\sqrt{x}\;x^4\;y^8\)

\(\textsf{Apply the radical rule:} \quad \sqrt{a}\sqrt{b}=\sqrt{ab}\)

\(6 \sqrt{5x}\;x^4\;y^8\)

\(\textsf{Rearrange:}\)

\(6x^4y^8\sqrt{5x}\)

\(\textsf{Therefore, when $x > 0$ and $y > 0$, the expression that is equivalent to}\)

\(\sqrt{180x^9y^{16}}\;\textsf{is}\;\;\boxed{6x^4y^8\sqrt{5x}}\:.\)

The options given are correct formulas and should use the distributive law √5(√7-√2) for simplicity.

(√5+√2)(-√7)

distribution characteristics

Given integers A, B, and C. According to the distributive law,

A(B + C) = AB + AC

From the formula we can see that A is distributed over B and C.

Therefore, the sum of the coefficients and terms must be in the parentheses of the distribution properties. Based on the options given, the correct formulas that should use the distribution characteristics for simplicity are √5(√7-√2) and

(√5+√2)(-√7)

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Answer:

139 degrees

Step-by-step explanation:

Sum of all three angles of a triangle is 180 degrees

also the sum of 2 angles on a flat plane like this is 180 degrees

so the 2 angles we know added together will equal x

58+81

139 degrees

hopes this helps

Answer: 2

Step-by-step explanation:

5+3=8

8/4=2

‍♂️ I’m not the best at explaining

We know that

Solving for x,

x is aproximately 33.56

Answer:

The Probability would be 2.78%

Step-by-step explanation: Hope this helps :)

Answer:

14.4 kN

Step-by-step explanation:

cantilever balcony 2m wide 0.2m deep and 1.5m length.

= 2 x 0.2 x 1.5

= 0.6 m³

weight of the balcony

= 0.6 x 24

= 14.4 kN.

therefore the max shear 14.4 kN and is acting at support.

Differential formula that estimates the change in the surface area S=6x2 of a cube when the edge lengths change from \(x_{0}\) to \(x_{0}\) + dx is \($$d S=\left(12 x_0\right) d x$$\)

As per the given data:

The surface area is given by

\($$S = 6 x^2$$\)

Differentiate both sides with respect to  f(x)

\($$S^{\prime}(x)=\frac{d}{d x}\left(6 x^2\right)\\\\=6(2) x^{2-1}$$\)

= 12 x

The estimated change in surface area is given by

\($$d S=S^{\prime}(x) d x= > d S\\\\$$\)

= (12 x) dx

The change in surface area at \($x=x_{0} $\) is

\($$d S=\left(12 x_0\right) d x$$\)

Therefore the answer is \($$d S=\left(12 x_0\right) d x$$\)

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Write a differential formula that estimates the change in the surface area S=6x2 of a cube when the edge lengths change from \(x_{0}\) to \(x_{0}\) + dx

Answer: short line: 30 miles, ling leg: 224 miles

Step-by-step explanation:

Intro:
We will be using Pythagoras theorm, which states, if we have a 90 degree triangle which has 3 side as H, B and P defined as Hypotenuse, Base and Perpendicular, then H² = B² + P²
In your case, we know that hypotenuse is 226.

We also know that (A + B)² = A² + B² + 2AB

Given:
H = 226

B - P = 194

Solution:
B = 194 + P
So
(226)² = (194 + P)² + P²

51076 = (194)² + P² + (2 x 194 x P) + P²

51076 = 37636 + 2P² + 388P

51076 - 37636 = 2P² + 388P
13440 = 2P² + 388P

6720 = P² + 194P

P² + 194P - 6720 = 0
P² - 30P + 224P - 6720 = 0
P(P - 30) + 224(P - 30) = 0
(P - 30) x (P + 224) = 0
P = 30 or -224
As miles cannot be negative, we will choose answer as 30 miles.

Now we have H = 226 and P = 30
Using Pythagoras theorm:
(226)² = (30)² + B²
51076 = 900 + B²
50176 = B²

B = 224 miles.

So the missing miles are 224 miles and 30 miles

Answer: the answer is $63.14.

Step-by-step explanation:

I took the test and got it correct.

Answer:

$63.14

Explanation:

I got it right on the test

Answer:

2hrs 30 mins

Step-by-step explanation:

if the buoy Is 12 up and 16 right than you can use Pythagorean theorem

a²+b²=c²

144+256=c²

400=c²

√400=√c²

20=c

20/8=2.5

2 hrs 30 mins

The sum of the eigenvalues of A is equal to the trace of A, and we have proved the desired result.

Let A be an n x n square matrix with eigenvalues λ1, λ2, ..., λn.

The trace of A is defined as the sum of the diagonal elements of A, i.e.,

tr(A) = a11 + a22 + ... + ann

where aij is the element of A in the ith row and jth column.

Now, consider the characteristic equation of A, which is given by

det(A - λI) = 0

where I is the n x n identity matrix.

Expanding the determinant, we get

(-1)^n λ^n + (-1)^(n-1) tr(A) λ^(n-1) + ... + det(A) = 0

By Vieta's formulas, the sum of the roots of this polynomial equation is equal to the negative of the coefficient of the (n-1)th power of λ divided by the coefficient of the nth power of λ.

Thus, the sum of the eigenvalues of A is given by

λ1 + λ2 + ... + λn = -(-1)^(n-1) tr(A)/(-1)^n

= tr(A)

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Answer:

12 feet

Step-by-step explanation:

1 inch= 8 feet

1/2 inch= 4 feet

1/4 inch= 2 feet

(2x2)/2= 2  (one triangle)

2x4=8 (rectangle)

2+2=4 +8=12

^2 was added 2 times cause there are 2 triangles

(you did not need a 3rd measurement cause the triangle measurements were equal)

The function represents a reflection of f(x) = 5(0.8)x across the x-axis is f(x) = -5(0.8)^x

Images that are reflected are mirror images of each other. When a point is reflected across the line y = x, the x-coordinates and y-coordinates change their position. In a similar manner, when a point is reflected across the line y = -x, the coordinates changes position but are negated.

Given the exponential function below

f(x) = 5(0.8)^x

If the function f(x) is reflected over the x-axis, the resulting function will be

-f(x)

This means that we are going to negate the function f(x) as shown;

f(x) = -5(0.8)^x

Hence the function represents a reflection of f(x) = 5(0.8)x across the x-axis is f(x) = -5(0.8)^x

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Answer:

Correct.

Step-by-step explanation:

It looks good to me.

Good job!

Answer:

To translate triangle ABC 3 units up, we need to add 3 to the y-coordinate of each vertex:

A' = (-3, 3 + 3) = (-3, 6)

B' = (0, 7 + 3) = (0, 10)

C' = (-3, 0 + 3) = (-3, 3)

Therefore, the coordinates of the vertices for the image triangle A'B'C' are A'(-3, 6), B'(0, 10), and C'(-3, 3).

So the correct answer is: A′(−3, 6), B′(0, 10), C′(−3, 3).