1)A balloon becomes negatively charged with an excess of 210 electrons what is the charge in Coulombs of the Balloon?

2) The same balloon is then rubbed against a sweater its new charge is -5.664 x 10-17. How many excess electrons does the balloon now have?

3) Did the balloon gain or lose electrons? HOW DO YOU KNOW?​

When a beam of 11 keV X-rays illuminates a sample, the angles that will produce diffraction maxima of the first, second, and third order can be calculated using Bragg's law, which states that nλ = 2d sin(θ), where n is the order of diffraction, λ is the wavelength of the X-rays, d is the spacing between crystal lattice planes, and θ is the angle of incidence.

Bragg's law can be used to calculate the angles for diffraction maxima. For the first-order maximum (n = 1), we have λ = 2d sin(θ₁). Rearranging the equation, we get sin(θ₁) = λ / (2d). Substituting the values, with λ representing the wavelength of 11 keV X-rays (which can be converted to the corresponding wavelength), and the known spacing between lattice planes, we can solve for θ₁.

For the second-order maximum (n = 2), the equation becomes λ = 2d sin(θ₂). Solving for sin(θ₂) and substituting the values, we can find θ₂.

Similarly, for the third-order maximum (n = 3), we use λ = 2d sin(θ₃) to determine sin(θ₃) and find θ₃ by substituting the values.

By calculating these angles using Bragg's law, we can determine the angles that will produce diffraction maxima of the first, second, and third order for the given beam of 11 keV X-rays illuminating the sample.

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Answer:

32.32857

Explanation:

Searched on the web

Answer:

large membrane enclosed structure

The answer is true. Yes the galvanized wire rope is approximately 10% higher in strength than bright wire rope.

True. Galvanized wire rope is known for its increased strength compared to bright wire rope, with approximately a 10% higher breaking strength. This is due to the galvanizing process that adds a protective zinc coating to the wire, increasing its durability and resistance to corrosion. The zinc coating can also increase the strength of the wire rope by up to 10%, compared to bright wire rope, which is untreated and has no coating. Therefore, galvanized wire rope is generally stronger than bright wire rope and can be used in more demanding applications.

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The resistance of the copper wire is 0.161 Ω. The resistance of a material depends on various factors, including its length, cross-sectional area, and temperature.

What is Resistance?

Resistance is a measure of how much a material opposes the flow of electric current. It is defined as the ratio of the voltage applied to a conductor to the current flowing through it, and is measured in ohms (Ω). Materials with high resistance are poor conductors of electricity, while materials with low resistance are good conductors.

We can use the formula for resistance of a wire:

R = (ρ * L) / A

where R is resistance, ρ is resistivity, L is length of the wire, and A is its cross-sectional area.

We know that the wires are identical, so they have the same length and cross-sectional area. Therefore, their resistances are proportional to their resistivities:

R_aluminum / R_copper = ρ_aluminum / ρ_copper

We can rearrange this to solve for the resistance of the copper wire:

R_copper = R_aluminum * ρ_copper / ρ_aluminum

Plugging in the given values, we get:

R_copper = 0.263 Ω * (1.72 x 10^-8 Ω·m) / (2.82 x 10^-8 Ω·m) = 0.161 Ω

Therefore, the resistance of the copper wire is 0.161 Ω.

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If you are at latitude 59° north of the earth's equator, the angular distance from the northern horizon up to the north celestial pole will be 59 degrees.

The celestial pole is a star located at the Earth's poles. If you stand at any of Earth's poles, you will observe the North Stars directly overhead. The star is fixed in the sky's position; it neither rises nor sets. However, as you travel from the equator toward the pole, the angular distance between the star and the northern horizon increases.The angular distance from the northern horizon up to the north celestial pole is the observer's latitude. That means, for an observer located at a point of latitude 59 degrees N, the north celestial pole is 59 degrees above the horizon (the observer is in the Northern hemisphere).

Therefore, the angular distance from the northern horizon up to the north celestial pole is 59 degrees. This means that, if you stand at a point of latitude 59 degrees N, you will observe the north celestial pole 59 degrees above the northern horizon. This phenomenon happens because the Earth rotates on its axis, which makes the stars appear to rotate around the celestial pole.

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So, the frequency of that light approximately \( \sf{\bold{3.53 \times 10^{14} \: Hz}} \)

Hi ! I will help you to explain the relationship between velocity of electromagnetic waves in a vacuum with frequency and wavelength. We all know that all of the type of electromagnetic wave, will have the same velocity as the speed of light (because the value is a constant), which is 300,000 km/s or \( \sf{3 \times 10^8} \) m/s. As a result of this constant property, the shorter the wavelength, the greater the value of the electromagnetic wave frequency. This relationship can also be expressed in this equation:

\( \boxed{\sf{\bold{c = \lambda \times f}}} \)

With the following condition :

We know that :

What was asked :

Step by step :

\( \sf{c = \lambda \times f} \)

\( \sf{3 \times 10^8 = 8.5 \times 10^{-7} \times f} \)

\( \sf{f = \frac{3 \times 10^8}{8.5 \times 10^{-7}}} \)

\( \sf{f \approx 0.353 \times 10^{8 -(-7)}}} \)

\( \sf{f \approx 3.53 \times 10^{-1} \times 10^{15}} \)

\( \boxed{\sf{f \approx 3.53 \times 10^{14} \: Hz}} \)

So, the frequency of that light approximately \( \sf{\bold{3.53 \times 10^{14} \: Hz}} \)

Answer:

Explanation:you knoe i know

Answer:

Sustainable energy is essential to meet uncontrolled rising demand for energy, reduce pollution and shift to resources that can be used again and again.

Explanation:

Considering the Sustainable Goals floated by United Nation, it is essential for all countries to improve their score in all the SD goals.

One of the SD goal is to shift to sustainable energy.

Sustainable energy is essential from following three points

- Reuse of energy source again and again to outcome the fear of resource depletion

- Sustainable energy source shall ensure cleaner environment

- Sustainable energy sources are also essential to meet the rising consumption of energy with time all across the globe.

Some common examples are - Solar energy, Wind Energy, Energy from nuclear fuels etc.

Some people may give up their rights out of fear or trepidation. However, you must recognize that using your rights is a kind of self-defense, not a challenge to the police.

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Answer:

all of the above conditions are necessary for electric current to flow

Explanation:

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Answer:

=2 000 000 Litres

Explanation:

Density=mass/volume

1000kg/m^3=0.50×Volume

Volume=2000m^3

apparently I searched it up and

1m^3=1000 litres.

Part A: The value of force is 6.4 × 10⁻¹² N.

Part B: The direction of the magnetic force is pointing out of the page.

Part A: The magnitude of the magnetic force on the electron can be calculated using the formula F = qvB, where q is the charge of the electron, v is its velocity, and B is the magnetic field strength. Plugging in the given values, we get F = (1.6 × 10⁻¹⁹ C) × (5.0 × 10⁷ m/s) × (0.80 T) = 6.4 × 10⁻¹² N.

Part B: The direction of the magnetic force can be determined using the right-hand rule. Pointing the thumb in the direction of the electron's velocity (to the right in the figure), and the fingers in the direction of the magnetic field (upward in the figure), the palm of the hand will point out of the page.

Therefore, the magnetic force on the electron is perpendicular to both its velocity and the magnetic field, and is pointing out of the page (towards the reader in the figure).

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The trip takes a total of 1.5 hours and has an average speed of 40 mph.

To calculate the time taken for each leg of the trip, we can use the formula time = distance/speed.

For the first leg of the trip, the car travels 15 miles at a speed of 45 mph. Using the formula, we find that the time taken for this leg is 15/45 = 0.33 hours.

For the second leg of the trip, the car travels another 15 miles but at a speed of 30 mph. Using the formula, we find that the time taken for this leg is 15/30 = 0.5 hours.

To find the total time for the trip, we add the times for each leg: 0.33 hours + 0.5 hours = 0.83 hours.

To calculate the average speed for the entire trip, we use the formula average speed = total distance/total time. The total distance traveled is 15 miles + 15 miles = 30 miles. The total time taken is 0.83 hours. Plugging these values into the formula, we find that the average speed for the trip is 30/0.83 = 36.14 mph.

Therefore, the trip takes a total of 1.5 hours and has an average speed of 40 mph.

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The person must have a velocity of -2.5 kg m/s ÷ 35 kg = -0.0714 m/s.

Velocity is a vector quantity that describes the rate and direction of an object's motion. It is the magnitude of the speed of an object, measured in meters per second (m/s). Velocity can also be used to describe the rate of change of an object's position over time. It is an important concept in physics and engineering, as it is used to measure the acceleration and deceleration of objects.

Since the person has a mass of 35 kg and the snowball has a mass of 0.5 kg, and they both have the same velocity of 5 m/s,
the total momentum of the system must remain constant.
Therefore, since the snowball has a momentum of 0.5 kg * 5 m/s
= 2.5 kg m/s, the person must have a momentum of -2.5 kg m/s.
This means that the person must have a velocity of -2.5 kg m/s ÷ 35 kg = -0.0714 m/s.

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Answer:

There are many forces involved in the game of football. These are: Force of Gravity, Normal Force, Force of Friction, and Applied Force. Force of Gravity applies to football when the football is thrown or kicked, when a player jumps in the air to avoid a tackle or catch a ball, and is constantly being applied.

Explanation:

How physics is used in football?

When you throw a football across the yard to your friend, you are using physics. You make adjustments for all the factors, such as distance, wind and the weight of the ball. The farther away your friend is, the harder you have to throw the ball, or the steeper the angle of your throw.

Answer:

!

Explanation:

Sedimentary rocks originate when particles settle out of water/air, or by precipitation of minerals from water. They accumulate in layers. The most important processes that lead to the creation of sedimentary rocks are erosion, weathering, dissolution, precipitation, and lithification.

Metamorphic rocks result when other rocks are changed by heat, pressure, or reactive fluids, such as hot, mineral-laden water, and sometimes a combination of all these factors. These conditions are found deep within the Earth or where tectonic plates meet.

A sedimentary rock is a rock formed through weathered and compacted sediments. These kinds of rocks undergo five major stages: erosion, deposition, weathering, compaction, and cementation. Through the breaking down and combining of scattered sediments, sedimentary rocks are formed.

A metamorphic rock is typically thought of as a rock that undergoes intense heat and pressure in the mantle of Earth. This kind of rock can be formed from any kind of process, as long as it goes through a phase of extreme exposures to heat. Metamorphic rocks are common underground. These rocks eventually rise to Earth's surface, and they cool and crystallize to become igneous rocks.

a)

We know that the angular acceleration is related to the linear acceleration by:

where alpha is the angular acceleation and r is the radius, then, in this case we have:

Therefore the linear acceleration is 0.6545 meters per second per second.

b)

The linear velocity is related to the angular velocity by:

where omega is the angular velocity, plugging the values we have and solving for the angular velocity we have:

Therefore the angular velocity is 27.013 radians per second.

c)

To determine the time it takes for the cyclist to reach that velocity we use the equation:

since he started at rest this means that the initial velocity is zero; plugging the values we know and solving for t we have:

Hence it takes 15.89 seconds to reach this velocity. To determine how many radians the wheels turned we use the fact that:

then we have:

Therefore the wheels turned 214.618 radians.

d)

To determine how far the bycicle traveled in this time we use:

then we have:

Therefore the bicycle traveled 82.628 meters.

In a series circuit or parallel circuit, the total power consumed by the circuit is times IT.

In general, power means a large effort that can be calculated in units of time or speed. Even so, true power and effort have a slight difference.

If power is the rate of energy, then work is the amount of energy itself. In addition, the difference between the two can also be seen from the units.

Power has units of Watts or Joules/second (J/S), while business has units of Joules (K) only. Work measures distance, while power measures time.

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Answer:

A

Explanation:

Answer:

  1/8

Explanation:

17,100 years is 3 times the half-life of 5,700 years. After each half-life, half remains, so the amount remaining after 3 half-lives is ...

  (1/2)(1/2)(1/2) = 1/8

1/8 of the sample remains after 17,100 years.

Answer:

1/8

Explanation:

The partial pressure of oxygen would be approximately 1.9573 atmospheres when you are 100 m underwater and have inflated your lungs using air from Earth's atmosphere

To calculate the partial pressure of oxygen when you are 100 m underwater and have inflated your lungs using air from Earth's atmosphere, we need to consider the increase in pressure with depth and the composition of air.

First, let's convert the depth of 100 m to the number of additional atmospheres of pressure. You mentioned that for every 12 m, there is approximately 1 atm of additional pressure. Therefore, for 100 m, the additional pressure would be:

100 m / 12 m = 8.33 additional atmospheres (approximately)

Since the pressure inside the lungs should be approximately the same as the pressure outside, we need to consider the total pressure at that depth, which includes the atmospheric pressure at sea level.

The atmospheric pressure at sea level is approximately 1 atmosphere (atm). Therefore, the total pressure at 100 m underwater would be:

1 atm (at sea level) + 8.33 atm (additional pressure) = 9.33 atmospheres

Now, let's consider the composition of air. You mentioned that air in Earth's atmosphere is approximately 78% nitrogen and 21% oxygen (as mol fractions). This means that out of 100 mol of air, 78 mol is nitrogen, and 21 mol is oxygen.

To calculate the partial pressure of oxygen at 9.33 atmospheres, we'll use Dalton's law of partial pressures. According to Dalton's law, the total pressure exerted by a mixture of ideal gases is equal to the sum of the partial pressures of each gas in the mixture.

The partial pressure of oxygen (P_O2) can be calculated as follows:

P_O2 = Total pressure * Mol fraction of oxygen

P_O2 = 9.33 atm * (21 / 100) = 1.9573 atm

Therefore, the partial pressure of oxygen would be approximately 1.9573 atmospheres when you are 100 m underwater and have inflated your lungs using air from Earth's atmosphere.

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The partial pressure of oxygen would be approximately 1.9573 atmospheres when you are 100 m underwater and have inflated your lungs using air from Earth's atmosphere

To calculate the partial pressure of oxygen when you are 100 m underwater and have inflated your lungs using air from Earth's atmosphere, we need to consider the increase in pressure with depth and the composition of air.

First, let's convert the depth of 100 m to the number of additional atmospheres of pressure. You mentioned that for every 12 m, there is approximately 1 atm of additional pressure. Therefore, for 100 m, the additional pressure would be:

100 m / 12 m = 8.33 additional atmospheres (approximately)

Since the pressure inside the lungs should be approximately the same as the pressure outside, we need to consider the total pressure at that depth, which includes the atmospheric pressure at sea level.

The atmospheric pressure at sea level is approximately 1 atmosphere (atm). Therefore, the total pressure at 100 m underwater would be:

1 atm (at sea level) + 8.33 atm (additional pressure) = 9.33 atmospheres

Now, let's consider the composition of air. You mentioned that air in Earth's atmosphere is approximately 78% nitrogen and 21% oxygen (as mol fractions). This means that out of 100 mol of air, 78 mol is nitrogen, and 21 mol is oxygen.

To calculate the partial pressure of oxygen at 9.33 atmospheres, we'll use Dalton's law of partial pressures. According to Dalton's law, the total pressure exerted by a mixture of ideal gases is equal to the sum of the partial pressures of each gas in the mixture.

The partial pressure of oxygen (P_O2) can be calculated as follows:

P_O2 = Total pressure * Mol fraction of oxygen

P_O2 = 9.33 atm * (21 / 100) = 1.9573 atm

Therefore, the partial pressure of oxygen would be approximately 1.9573 atmospheres when you are 100 m underwater and have inflated your lungs using air from Earth's atmosphere.

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Answer:

7 hectometers is 7000 decimeters

Option C) decreasing Hernando’s pushing force will most likely decrease Tom’s acceleration on the swing.

The definition of acceleration is a change in the rate of motion, speed, or motion. An instance of acceleration is increasing your using pace from forty-five to 55 to merge with site visitors.

Accelerations are vector portions. The orientation of an object's acceleration is given with the aid of the orientation of the net force acting on that item. Acceleration is a vector quantity this is defined as the rate at which an object modifications its speed. An item is accelerating if it's far converting its velocity.

Speed ​​and acceleration are basic terms of motion. speed is the distance protected with the aid of an object in unit time, whilst acceleration is the charge of change of speed.

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Answer:

At the point of dropping the object, by Newton's first law due to gravitational force \(F_g\) = m × g, accelerates

By Newton's Second law the object reaches impacts on the air with the gravitational force resulting in changing momentum of m×(Final Velocity - Initial Velocity)

As the velocity increases, the rate of change of momentum becomes equivalent to the gravitational force and by Newton's third law, the action action and reaction are equal and opposite hence they cancel each other out

The body then moves at a constant uniform motion down according to Newton's first law

Explanation:

At the point the object of mass, m, is dropped from the height of the tower, the only force acting on the object is the gravitational force such that the object has an acceleration which is the acceleration due to gravity, g, and the gravitational force is therefore = m × g

As the speed of the object increases while the object is falling with the gravitational acceleration the rate at which the object cuts through layers of air which (by Newton's first law of motion, are at rest ) has some buoyancy effect also increases therefore, the object is constantly increasingly changing the momentum of the air which by Newton's second law results, at an high enough velocity, and by Newton's third law, in a force equal to the applied gravitational force

Therefore, the force of the air drag becomes equal to the gravitational force, cancelling each other out and the object then moves according to Newton;s first law, in uniform motion of a constant speed while still falling down.

First find Acceleration

\(\boxed{\sf Acceleration=\dfrac{v-u}{t}}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{42-0}{2}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{42}{2}\)

\(\\ \sf\longmapsto Acceleration=21m/s^2\)

Using second equation of kinematics

\(\boxed{\sf s=ut+\dfrac{1}{2}at^2}\)

\(\\ \sf\longmapsto s=0(2)+\dfrac{1}{2}(21)(2)^2\)

\(\\ \sf\longmapsto s=21(2)\)

\(\\ \sf\longmapsto s=42m\)

a = v-u/t

2 = v - 0 / 5

2 = v/5

v = 10 m /s

According to the given statement The ships average acceleration is 2790 km/hr².

Rate of change in both speed and direction of motion over time. A point or object going straight forward is accelerated when it accelerates or decelerates. Even though the speed is constant, motion on a circle accelerates because of direction is always shifting

We know that from newton's equation,

v² + u² = 2as

S = ut + 0.5 at²

Where, v = final speed

           u = initial speed

           a = acceleration

           S = distance covered

            t = time taken

Given, u = 0

So the equations becomes:

v² = 2as

S = 0.5 at²

Using these equations we get:

v² = 2a(0.5)at²

v² = a²t²

v = at

v/t = a

Given,  v = 93 km/hr

          t = 2 min = 2/60 hr

Putting these values in above equation we get, a = 2790 km/hr²

So, the ships average acceleration is 2790 km/hr²

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