Answers
Given:
n = 1.4
radius of the front = 1.3 m
radius of the rear = -0.9 m
Let's find the refractive power of the lens.
To find the refractive power of the lens, apply the formula:
\(\frac{1}{f}=(n-1)(\frac{1}{R_1}-\frac{1}{R_2})\)Thus, we have:
\(\begin{gathered} \frac{1}{f}=(1.4-1)(\frac{1}{1.3}-(-\frac{1}{0.9})) \\ \\ \frac{1}{f}=(0.4)(\frac{1}{1.3}+\frac{1}{0.9}) \\ \\ \frac{1}{f}=(0.4)(\frac{0.9+1.3}{1.17}) \\ \\ \frac{1}{f}=(0.4)(\frac{2.2}{1.17}) \\ \\ \frac{1}{f}=0.75 \end{gathered}\)Therefore, the refractive power of the lens is 0.75 diopters
• ANSWER
1. 0.75 diopters
Related Questions
An object with mass of total tags sitting on a ledge, 15 M above the ground starts to fall. What was the potential energy of the object before it fell?
Answers
The potential energy of the object before it fell is determined as 147 (kg). J.
What is potential energy?
The potential energy of an object is the energy possessed by an object due to its position above the ground level.
The potential energy of an object depends on the mass and height of the object above the ground.
P.E = mgh
where;
m is mass of the object in kgh is height of the objectg is acceleration due to gravitySubstitute the given parameters and solve for the potential energy of the object as shown below.
P.E = (m , kg)(15 m)(9.8 m/s²)
P.E = 147 (kg). J
Thus, the potential energy of the object before it fell is determined as 147 (kg). J.
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How much work is required to move a 1 nC charge from an electric potential of 0 V to a potential of 18V?
a) 56 µJ
b) No work is required by an external force because this is the natural movement of the charge.
c) 18 J
d) 56 MJ
e) 18GJ
f) 18 nJ
Answers
The work required to move a 1 nC charge from an electric potential of 0 V to a potential of 18 V is 18 nJ (Option f).
When moving a charge in an electric field, the work done can be calculated using the formula W = qΔV, where W is the work done, q is the charge, and ΔV is the change in electric potential.
In this case, the charge is\(0.36V * 1600 kg/m^3 = 0.36 * 0.088 m^3 * 1600 kg/m^3 = 88 kg.\)) and the change in potential is 18 V. Plugging these values into the formula, we get\(W = (1 × 10^-9 C)(18 V) = 18 × 10^-9 J = 18 nJ.\)
Therefore, the correct answer is option f. No other options accurately represent the work required to move the charge in this scenario.
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A well-coated structure is defined as A) 95% or better B) 90% or better C) 99% or better D) 93% or better
Answers
Answer and Explanation:
A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.
However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.
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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.
However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.
Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body
A 1.8-kg object is attached to a spring and placed on frictionless, horizontal surface. A force of 40 N stretches a spring 20 cm from its equilibrium position (the origin of the x axis). The object is now released from rest from this stretched position, and it subsequently undergoes simple harmonic oscillations. a) Find the force constant of the spring. b) Find the total energy of the oscillating system. c) Where will the object be from the equilibrium position when its velocity is -2.0 m/s (negative 2 m/s)
Answers
Answer:
a) k = 200 N/m
b) E = 4 J
c) Δx = 6.3 cm
Explanation:
a)
In order to find force constant of the spring, k, we can use the the Hooke's Law, which reads as follows:\(F = - k * \Delta x (1)\)
where F = 40 N and Δx =- 0.2 m (since the force opposes to the displacement from the equilibrium position, we say that it's a restoring force).Solving for k:\(k =- \frac{F}{\Delta x} =-\frac{40 N}{-0.2m} = 200 N/m (2)\)
b)
Assuming no friction present, total mechanical energy mus keep constant.When the spring is stretched, all the energy is elastic potential, and can be expressed as follows:\(U = \frac{1}{2}* k* (\Delta x)^{2} (3)\)
Replacing k and Δx by their values, we get:\(U = \frac{1}{2}* k* (\Delta x)^{2} = \frac{1}{2}* 200 N/m* (0.2m)^{2} = 4 J (4)\)
c)
When the object is oscillating, at any time, its energy will be part elastic potential, and part kinetic energy.We know that due to the conservation of energy, this sum will be equal to the total energy that we found in b).So, we can write the following expression:\(\frac{1}{2}* k* \Delta x_{1} ^{2} + \frac{1}{2} * m* v^{2} = \frac{1}{2}*k*\Delta x^{2} (5)\)
Replacing the right side of (5) with (4), k, m, and v by the givens, and simplifying, we can solve for Δx₁, as follows:\(\frac{1}{2}* 200N/m* \Delta x_{1} ^{2} + \frac{1}{2} * 1.8kg* (-2.0m/s)^{2} = 4J (6)\)
⇒ \(\frac{1}{2}* 200N/m* \Delta x_{1} ^{2} = 4J - 3.6 J = 0.4 J (7)\)
⇒ \(\Delta x_{1} = \sqrt{\frac{0.8J}{200N/m} } = 6.3 cm (8)\)
identify two factors that determine the amount of electricity that can be generated by an indi-vidual hydroelectric power plant. (2 points)
Answers
Two factors that determine the amount of electricity that can be generated by an individual hydroelectric power plants - It depends on the vertical distance through which the water falls and the flow rate, or amount of water that flows past a certain point per unit time, The greater the distance that the water falls, the more potential energy it had and the more electricity is generated the more kinetic energy it has and the more .
Impoundment, diversion, and pumped storage facilities are the three different types of hydroelectric facilities. Hydropower plants vary in their utilisation of dams. Despite the fact that not all dams were constructed for hydropower, they have been successful in supplying vast amounts of renewable energy to the grid. As of 2020, fewer than 2,300 of the more than 90,000 dams in the United States were producing electricity. The other dams are utilised for water supply, irrigation, flood control, stock/farm ponds, and recreation. Hydropower facilities come in a variety of sizes, from modest initiatives providing electricity for a single house or community to massive undertakings.
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Look at the diagram showing the different wavelengths in sunlight.
A diagram showing the human eye and visible light. Visible light is broken down by color with wavelength in nanometers. Red is 700, orange is 600, yellow is 580, green is 550, blue is 475, indigo is 450, violet is 400.
Which has a wavelength of 350 nanometers?
red light
violet light
infrared light
ultraviolet light
Answers
Answer:
ultraviolet light
plz mark me as brainliest.
Answer:
Ultra violet
Explanation:
In a home stereo system, low sound frequencies are handled by large "woofer" speakers, and high frequencies by smaller "tweeter" speakers. For the best sound reproduction, low-frequency currents from the amplifier should not reach the tweeter. One way to do this is to place a capacitor in series with the 9.0 Ω resistance of the tweeter; one then has an RLC circuit with no inductor L (that is, an RLC circuit with L = 0).
What value of C should be chosen so that the current through the tweeter at 200 Hz is half its value at very high frequencies? Express your answer with the appropriate units.
Answers
Answer:
C = 2.9 10⁻⁵ F = 29 μF
Explanation:
In this exercise we must use that the voltage is
V = i X
i = V/X
where X is the impedance of the system
in this case they ask us to treat the system as an RLC circuit in this case therefore the impedance is
X = \(\sqrt{R^2 + ( wL - \frac{1}{wC})^2 }\)
tells us to take inductance L = 0.
The angular velocity is
w = 2π f
the current is required to be half the current at high frequency.
Let's analyze the situation at high frequency (high angular velocity) the capacitive impedance is very small
\(\frac{1}{wC}\) →0 when w → ∞
therefore in this frequency regime
X₀ = \(\sqrt{R^2 + ( \frac{1}{2\pi 2 10^4 C} )^2 } = R \sqrt{ 1+ \frac{8 \ 10^{-10} }{RC} }\)
the very small fraction for which we can despise it
X₀ = R
to halve the current at f = 200 H, from equation 1 we obtain
X = 2X₀
let's write the two equations of inductance
X₀ = R w → ∞
X= 2X₀ = \(\sqrt{R^2 +( \frac{1}{wC} )^2 }\) w = 2π 200
we solve the system
2R = \sqrt{R^2 +( \frac{1}{wC} )^2 }
4 R² = R² + 1 / (wC) ²
1 / (wC) ² = 3 R²
w C = \(\frac{1}{\sqrt{3} } \ \frac{1}{R}\)
C = \(\frac{1}{\sqrt{3} } \ \frac{1}{wR}\)
let's calculate
C = \(\frac{1}{\sqrt{3} } \ \frac{1}{2\pi \ 200 \ 9}\)
C = 2.9 10⁻⁵ F
C = 29 μF
Two 60.00 resistors are connected in parallel and this parallel arrangement is then connected in series with a 30.00 resistor. The combination is placed across a 120 V potential difference. What is the equivalent resistance for the entire circuit? a RT = 900 b RT12002 C RT = 30N 30Ω d RT = 60Ω
Answers
The equivalent resistance for the entire circuit is equal to 1830 Ω.
What is the resistance of resistors in series?In a series combination of resistors, the resistors are connected end-to-end. Assume two resistors, R₁ and R₂ which are connected with each other in a series then their effective resistance:
Total Resistance, R = R₁ + R₂
In a parallel combination of resistors, the resistors are connected parallel to each other.
\(\displaystyle \frac{1}{R} =\frac{1}{R_1} +\frac{1}{R_2}\)
The resistance in parallel, R₁ = 60 Ω , R₂ = 60 Ω , R₃ = 30 Ω
The equivalent resistance for the entire circuit will be given by:
\(R_{eq} =R' + R_3\)
\(\displaystyle R_{eq} = \frac{R_1R_2}{R_1+R_2} + R_3\)
\(\displaystyle R_{eq} = \frac{60\times 60}{1+1} + 30\)
R = 3600/2 +30
R = 1800 +30
R = 1830 Ω
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You have two identical looking spools (same mass, same shape, same size). However, one is hollow, made from iron, the other is solid, made from aluminum. A string is wound around each spool. If you pull on both strings with equal forces, which spool is going to have the larger angular acceleration
Answers
Answer:
The one made from AL will have a smaller moment of inertia and thus a greater acceleration:
α = I ω
I = M R^2 for the iron (all the mass at a distance R)
Replacing any of the Fe with Al (and putting at a smaller radius) is going to reduce the total moment of inertia,
Which statement correctly compares sound and light waves?Both light and sound waves need matter to carry energy from one place to another.Neither light nor sound waves need matter to carry energy from one place to another.Light waves carry energy parallel to the motion of the wave, while sound waves carry energy perpendicular to it.Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.
Answers
Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.
What is energy parallel?Energy parallel is a type of energy efficiency strategy that seeks to reduce the amount of energy used in a building or facility by utilizing multiple energy sources instead of relying solely on one. This type of energy efficiency strategy works by drawing energy from multiple sources, such as solar, geothermal, wind, and water energy, and combining them to power a single building or facility. By utilizing multiple energy sources, energy parallel helps to reduce the overall amount of energy used in a building or facility, thus improving its overall energy efficiency. Additionally, this type of energy efficiency strategy helps to reduce the amount of energy that is wasted or lost by utilizing energy sources that are renewable and more sustainable.
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The highness or lowness of a sound is perceived as
a.
compression.
c.
ultrasound.
b.
wavelength.
d.
pitch.
Answers
Answer:
i think its D
Explanation:
Answer:
The highness or lowness of a sound is perceived as pitch. Pitch is a perceptual property of sound that allows us to distinguish between sounds that have the same loudness and duration, but differ in their frequency content. The pitch of a sound is determined by the frequency of the sound wave, with higher frequencies producing higher pitches and lower frequencies producing lower pitches. The pitch is what makes a sound distinguishable and is important in music, language, and communication.
how much pressure is exterted by the water at the bottom of well if the depth of the wall is 6m.
Answers
Hydrostatic pressure = q g h
Density of water (q) = 1000kgm^-3 , gravity (g)= ms^2
q = 10^3 kg/m^3
1g= 10ms^-2
h= 6m
Pressure = 10^3kg/m3 x 10m/s^2 x 6
P = 60000pa
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
Answers
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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how much metal is needed to cast a cubical metal box
Answers
If metal is required to cast the cubical metal box, it would require 784cm3 of solid static electricity iron.
What exactly is static electricity?Unbalanced electric charge on such a material's surface is known as static electricity. In contrast for dynamic (moving) electricity, which takes the shape of electric currents, static electricity is defined as being fixed or immovable. A typical atom is neutral, meaning it has an equal number of protons and electrons.
What effects does static electricity have on the body?Although static electricity does not directly endanger human life, it can nonetheless shock us and, if we were on an elevated surface, might inflict serious injuries.
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i love u whoosever seeing my question
Answers
consider a car at rest, parked on level ground. the force of friction between a car tire and the ground .
Answers
The force of friction between car tire and ground is : umg.
Friction is defined as the resistance offered by the surfaces that are in contact when they move past each other.Friction is caused due to the irregularities on the two surfaces in contact. So, when one object moves over the other, these irregularities on the surface get entangled, giving rise to friction. The more the roughness, the more irregularities and more significant will be the friction.It is impossible to have zero friction because every surface will have minor irregularities no matter how lubricated.Static friction is a variable resistive force which is equal and opposite to the external force until it surpasses the threshold of motion when the slipping starts. Hence, static friction is a self-adjusting force.Since the car is at rest , static friction will come into action. So the force of friction between car tire and ground is : umg , where
u = coefficient of friction ,
m = mass of car and
g = acceleration due to gravity
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Two cubes are exactly the same size. The cube that is made of the material
with the largest density will have the
OA. largest mass
OB. smallest volume
O C. smallest mass
OD. largest volume
Answers
Answer:
A
mass is the density and volume is the size
you made $100,000 this year. you have $0 in adjustments, $11,500 in deductions and $7,300 in exemptions. What is your taxable increase?
Answers
The tax rate you will pay is displayed in tax brackets for each category of taxable income.
Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.
Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.
As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.
Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.
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PLEASE HELP QUICKLY THANKS
Answers
Answer: the answer is d
Explanation:
What is the main form of energy present in the initial state? (Initial state is when the rubber band is stretched , just before it is released)
O gravitational potential
O kinetic
O thermal
O elastic potential
Answers
The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answers
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
How has Physics improved
or affected our society?
Answers
By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life
From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.
The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.
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A train has a final velocity of 110 km/h. It accelerated for 36 s at 0.50 m/s2 . What was its initial velocity
Answers
The initial velocity of the train is 12.56 m/s.
Initial velocity
The initial velocity of the train can be determined by using the first kinematic equation as shown below;
v = u + at
u = v - at
where;
v is the final velocity = 110 km/h = 30.56 m/su is the initial velocityu = 30.56 - (36 x 0.5)
u = 12.56 m/s
Thus, the initial velocity of the train is 12.56 m/s.
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A rock is thrown straight down from a cliff with an initial velocity of 10.0 m/s. Its final velocity when it strikes the water below is 115 m/s. How long is the rock in flight?
Answers
The time of the rock in flight is 10.71 s.
What is time of flight?This is the total time taken for an object or a projectile to return back to the same plane at which it was projected.
To calculate the time of the rock in flight, we use the formula below.
Formula:
v = u+gt............. Equation 1Where:
v = Final final velocityu = Initial velocityt = time of the rock in flight. g = acceleration due to gravitymake t the subject of the equation
t = (v-u)/g.................... Equation 2
From the question,
Given:
u = 10 m/sv = 115 m/sg = 9.8 m/s².Substitute these values into equation 2
t = (115-10)/9.8t = 105/9.8t = 10.71 sHence, the time of the rock in flight is 10.71 s.
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The rock was in the flight for 11.7 s
Time of flightThis is defined as the total time spent by an object in air.
Determination of the height of the cliffFrom the question given above, the following data were obtained:
Initial velocity (u) = 10 m/sFinal velocity (v) = 115 m/sAcceleration due to gravity (g) = 9.8 m/s²Height of cliff (h) =?v² = u² + 2gh
115² = 10² + (2 × 9.8 × h)
13225 = 100 + 19.6h
Collect like terms
13225 – 100 = 19.6h
13125 = 19.6h
Divide both side by 19.6
h = 13125 / 19.6
h = 669.64 m
How to determine the time of flight Acceleration due to gravity (g) = 9.8 m/s²Height of cliff (h) = 669.64 mTime of flight (t) =?h = ½gt²
669.64 = ½ × 9.8 × t²
669.64 = 4.9 × t²
Divide both side by 4.9
t² = 669.64 / 4.9
Take the square root of both side
t = √(669.64 / 4.9)
t = 11.7 s
Thus, the rock was in the flight for 11.7 s
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The speed of revolution of particle going around a circlr is doubled and its angular speed is havled. What happen to the centripetal acceleration?
a) unchanged
b) doubles
c) halves
d) becomes four times
Answers
Answer: The correct answer is C
Explanation:
if you lift an apple from the ground to some point above the ground, the gravitational potential energy in the system increases
Answers
Imagine a baseball pitcher and a batter. The baseball has a mass of 0.14 kg. The ball is
pitched to the right with a velocity of 41.26 m/s.
Answers
The momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s.
What is the momentum of the baseball?The momentum of the baseball is calculated by applying the following formula as shown below;
P = mv
where;
m is the mass of the baseballv is the speed of the baseballThe momentum of the baseball is calculated as follows;
mass of the baseball = 0.14 kg
velocity of the baseball = 41.26 m/s
momentum, P = mv
P = 0.14 kg x 41.26 m/s
P = 5.78 kgm/s.
Thus, the momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s by applying the formula for linear momentum.
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The complete question is below:
Imagine a baseball pitcher and a batter. The baseball has a mass of 0.14 kg. The ball is pitched to the right with a velocity of 41.26 m/s. What is the momentum of the baseball?
A box puts a pressure of 50 N/m2 on an area of 0.25 m2. Find the force of the box on the floor.
Answers
A box puts a pressure of 50 N/\(m^{2}\) on an area of 0.25 \(m^{2}\). The force of the box on the floor is 12.5 Newton (N)
What is pressure and types?Pressure is defined as the physical force exerted on an object. The force applied is perpendicular to the surface of objects per unit area. The basic formula for pressure is \(\frac{F}{A}\) (Force per unit area). Unit of pressure is Pascals (Pa). Types of Pressures are Absolute, Atmospheric, Differential, and Gauge Pressure.
Using the formula Force = Pressure × Area
given Pressure = 50 N/\(m^{2}\)
area = 0.25 \(m^{2}\)
Substituting the values ,
Force = 12.5 Newton
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Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)
Answers
The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.
First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.
Next, we calculate the effective thermal conductivity of the air layer as:
k_eff = (k_air * L_air) / (L_air + k_glass)
Substituting the given values, we have:
k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air
Now, we can calculate the heat flow per second through the air layer using the formula:
Q = (k_eff * A * ΔT) / L_air
Substituting the given values, we get:
Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s
Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
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What is the average velocity of a car that travels 120 km in 3.5 hours?
Answers
Answer:
34.29 km/hr
Explanation:
Looking for km/hr
so plug in the values given 120 km / 3.5 hr = 34 .29 km / hr
( 34 2/7 km/hr)