2. A manager has 75 employees. He pays each employee $693 per week. After
paying his workers for one week, he has $2,999 left in his account. How
much money was in the account before he paid the workers?

Step-by-step explanation:

1)

imagine the trapezoid standing upright (90°) turned.

then the top and bottom lines are parallel, and the 15 side is with its double right angles the height of the trapezoid.

in general, the area of such a trapezoid is

(top + bottom)/2 × height

in our case that is

(3 + 4)/2 × 15 = 7/2 × 15 = 3.5 × 15 = 52.5 units²

2)

this is basically the sum of the lower rectangle and the upper trapezoid.

the area of the lower rectangle is

58×15 = 870 mm²

the area of the upper trapezoid is (the same formula as before)

(47 + 58)/2 × (21 - 15) = 105/2 × 6 = 52.5 × 6 = 315 mm²

so, the total area is

870 + 315 = 1,185 mm² = 1,185.0 mm²

Step-by-step explanation:

domain =x is an element of real numbers

y>or =-8

Answer:

8 did not get an A

Step-by-step explanation:

75%  obtained an A , then

25% did not obtain an A

25% of 32

= \(\frac{25}{100}\) × 32

= 0.25 × 32

= 8

When examining group differences with a specified direction, a one-tailed test is used i.e., option b is correct.

In statistical hypothesis testing, researchers often have a specific direction in mind when comparing two groups.

For example, they may hypothesize that Group A performs better than Group B or that Group A has a higher mean than Group B. In such cases, a one-tailed test is appropriate.

A one-tailed test is designed to detect differences in a specific direction. It focuses on evaluating whether the observed data significantly deviates from the null hypothesis in the specified direction.

The null hypothesis assumes no difference or no relationship between the groups being compared.

In a one-tailed test, the critical region is defined on only one side of the distribution, corresponding to the specified direction of the difference.

The critical value, which determines whether the observed difference is statistically significant, is chosen based on the desired level of significance (e.g., alpha = 0.05).

On the other hand, a two-tailed test is used when the direction of the difference is not specified, and the researchers are interested in determining whether there is a significant difference between the groups in either direction.

In this case, the critical region is divided equally between the two tails of the distribution.

A directional hypothesis (option C) is a statement that specifies the expected direction of the difference, but it is not the statistical test itself. The critical value (option D) is the value used to determine the cutoff for rejecting or accepting the null hypothesis.

Therefore, when examining group differences with a specified direction, a one-tailed test is used to assess the statistical significance of the observed difference in that particular direction.

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Answer:

Slant height = 7.07 ft to nearest hundredth.

Step-by-step explanation:

The slant height = height of one of the triangular sides

Using Pythagoras:

S^2 =  1/2 * 10^2 + 10^2 = 50 ft.

S = √50 = 7.071

Answer:

Candy canes are a classic Christmas treat, traditionally white with red stripes and flavored with peppermint. They have been popular since the 1600s and are thought to have originated in Germany. Today, 90 percent of all candy canes are sold between Thanksgiving and Christmas.

In a bag of Christmas treats, there are 3 red candy canes for every 5 gingerbread men. If there total is 40 treats, then the number of candy canes will be 24. This can be calculated by taking 40 divided by 8 (5+3) which equals 5, and then multiplying this by 3 which equals 15. Therefore, 24 candy canes are included in the bag of 40 Christmas treats.

Step-by-step explanation:

Answer:

-14x+4x+11y-13y=-10x-2y

-2(5x+y)

Thank give branlist please

Answer:

–10x – 2y

in factorise form

–2(5x + y)

Step-by-step explanation:

–14x + 11y + 4x –13y

= –14x + 4x + 11y –13y

= –10x –2y

i hope this helps

We have determined whether Ta and Tb are linear transformations or not. Ta is not a linear transformation, while Tb is a linear transformation.

Ta(x1,x2) = (-3x2)Tb(x1,x2) = (x2 - 1,x1)Let us check if Ta and Tb satisfy the following two conditions for any vectors x and y and a scalar c.

Additivity: T(x + y) = T(x) + T(y)

Homogeneity: T(cx) = cT(x)

Check whether Ta(x + y) = Ta(x) + Ta(y) for any vectors x and y.Ta(x + y) = -3(x2 + y2)Ta(x) + Ta(y) = -3x2 - 3y2= -3x2 - 3y2Therefore, Ta does not satisfy additivity.

Hence it is not a linear transformation.

Ta is not a linear transformation. Tb is a linear transformation.

Summary: We have determined whether Ta and Tb are linear transformations or not. Ta is not a linear transformation, while Tb is a linear transformation.

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The graph of a parabola is not a function of x.

Thus option 2 is correct.

Function is the process or state of instruction that text inputs performance is specific tax and produce an output functional key components of programming language allowing the quarters to create complex commands with simple instruction for example a function can be used to add two numbers round together or to generate a random function can also be combined to create more complex sequence of instruction.

number

Parabolas are usually graphed as a quadratic equation, which is not a function since it is not one-to-one. A function of x is a relation between two variables that can be expressed in the form y = f(x), where f is a mathematical expression. A parabola is a curve in the form of a U-shape, which is not one-to-one, and therefore not a function of x.

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Complete question:

Which of the following is not the graph of a function of x?

Answer:

Choice 4^th

Step-by-step explanation:

Given:

1/2+3/4+7/16 = __

To Solve:

Addition equation by finding a common multiple.

Solution:

Let the blank _ be x.

Then,

1/2+3/4+7/16 = x

Flip this equation:

Now solve for x.

Hence,

1/2+3/4+7/16 = 27/16

4^th Choice is accurate.

Answer: Multiply the centimeters number by 10.

Step-by-step explanation: There are 10 millimeters in every centimeter.

The distance from the center of the circle to the outer edge is called radius of the circle.

Circle is a segment of line connected to it itself. It is a 2 dimensional structure measuring 360°. The outer edge of the circle is called circumference. Now, an interesting fact about the circle is that circumference is equi distant from the radius.

Therefore, be it any point on the circumference, it will be at the same distance from radius. If the radius is further extended to meet the opposite side of circumference, it will become a diameter. The total length of diameter however decreases as we move from center to top of the circle.

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each toss results in 2 possible outcomes, head or tail so the number of possible outcomes for 7 would be

Answer:

2^7

2x2x2x2x2x2x2 = 2^7

Answer:

I'm pretty sure 2 and 5

Step-by-step explanation:

Hope this helps :)

The statement "P(A) + P(A') = 1" is not true if a successful event is defined as drawing a heart from a standard deck of 52 cards, where A' represents the set of all black cards and diamonds.

The probability of an event and its complement sum up to 1, but in this case, the given value of P(A') as 4/3 is incorrect. P(A') represents the probability of not drawing a heart, which consists of the black cards (clubs and spades) and diamonds (excluding hearts). There are a total of 26 cards in this set (13 black cards and 13 diamonds).

To calculate P(A') correctly, we need to determine the number of cards in the set A' and divide it by the total number of cards in the deck:

n(A') = 26

P(A') = n(A') / Total number of cards = 26 / 52 = 1/2

Therefore, the correct value of P(A') is 1/2, not 4/3. As a result, the statement "P(A) + P(A') = 1" does not hold true in this scenario.

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a) there are approximately 467.32 cancer cases per 100,000 people in Australia. b) there are approximately 352.63 cancer cases per 100,000 people in the USA. c) Australia has a higher number of cancer cases per capita than the USA.

To calculate the number of cancer cases per 100,000 people in Australia, we can use the following formula:

Number of cancer cases per 100,000 people = (Number of cancer cases / Population) * 100,000

a. Number of cancer cases in Australia per 100,000 people:

Number of cancer cases = 115,128

Population of Australia = 24.6 million = 24,600,000

Number of cancer cases per 100,000 people = (115,128 / 24,600,000) * 100,000

Calculating this expression:

Number of cancer cases per 100,000 people = 467.32

b. Number of cancer cases in the USA per 100,000 people:

Number of cancer cases = 1,147,115

Population of the USA = 325.7 million = 325,700,000

Number of cancer cases per 100,000 people = (1,147,115 / 325,700,000) * 100,000

Calculating this expression:

Number of cancer cases per 100,000 people = 352.63

c. Comparing the number of cancer cases per capita, we can see that Australia has a higher number of cancer cases per 100,000 people (467.32) compared to the USA (352.63).

In conclusion, based on the given data, Australia has more cancer cases per capita than the USA.

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Answer:

We conclude that the 12x is the required expression that is equivalent to 7x + 4x + x and has only one term.

Step-by-step explanation:

Given the expression

\(7x+4x+x\)

The current expression has three terms such as 7x, 4x, and x.

The current expression can be further simplified such as

\(7x+4x+x\)

Add similar elements:  \(7x+4x+x=12x\)

\(=12x\)

Thus, the given expression \(7x+4x+x\) can be expressed as the only one term such as \(12x\).

i.e. \(7x+4x+x=12x\)

Therefore, we conclude that the 12x is the required expression that is equivalent to 7x + 4x + x and has only one term.

The least amount of cards Hadas can have is 30 cards.

To find the least number of cards Hadas can have, we need to determine the least common multiple (LCM) of 6 and 15.

The LCM is the smallest multiple that both 6 and 15 divide evenly into.

The prime factorization of 6 is 2 × 3.

The prime factorization of 15 is 3 × 5.

To find the LCM, we take the highest power of each prime factor that appears in either number:

LCM = 2 × 3 × 5 = 30

Therefore, the least amount of cards Hadas can have is 30 cards.

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The present ages of Raj and his daughter are respectively: 42 years and 12 years.

Present Age of Raj =y years

Present Age of daughter =x years

According to Question :

7 Years ago,

y − 7 = 7(x − 7)

⇒ 7x − y − 42 = 0.............(1)

And 3 Years from now

y + 3 = 3(x + 3)

⇒ 3x − y + 6 = 0............(2)

From eq (1) and eq (2)

Subtract eq 2 from eq 1 to get:

7x − 3x − y + y − 42 − 6 = 0

⇒ 4x = 48

⇒ x = 12

Putting x = 12 in Equation (2). we get,

(3 × 12) − y + 6 = 0

⇒ y = 42

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Let the original cost of the jacket be x.

Now, saying that one-third of the original cost of the jacket is $34, is mathematically equivalent to:

Now we have to solve the resulting equation in order to obtain the value of x

This is done as follows:

Therefore, the original cost of the jacket is $102

Answer:

0 ≤ x ≤ 18

Step-by-step explanation:

Let 'x' be the number of youth tickets purchased at the zoo and 'y' be the number of adult tickets purchased at the zoo.

At a zoo, youth tickets cost $5 and adult tickets cost $9. A group spent a total of $90 on tickets. We can write as

5x + 9y = 90

to find x we divide both side by 5

x = (90-9y)/5 =>  90/5 - 9y/5

x = 18 - 9y/5

The domain of the relationship is the possible set of values of x and y that satisfies the equation. The domain of this relationship is

0 ≤ x ≤ 18

At x = 0, it means only adult tickets were purchased.

At x = 18, it means only youth tickets were purchased.

Answer:

0 ≤ x ≤ 18

Step-by-step explanation:

got it correct on pluto

Answer:

my answer is A

Step-by-step explanation:

if you work out the equation where you know that at the x intercept y=0 you will find A to be true

The recommended approach when choosing between one-tailed and two-tailed tests is to use a two-tailed test only.

The choice between a one-tailed or two-tailed test should be based on the research hypothesis and the specific question being investigated.

If you have a convincing reason for not predicting a direction, and use the one that is most likely to produce significant results.

If the research hypothesis or question does not make a clear directional prediction, then a two-tailed test would be appropriate.

This is because a two-tailed test will consider the possibility of significant results in both directions of the distribution.

And is more conservative in its estimation of significance.

If the research hypothesis or question does make a clear directional prediction, then a one-tailed test would be appropriate.

This is because a one-tailed test will only consider the possibility of significant results in one direction of the distribution.

And is more powerful in detecting significant results in that specific direction.

Therefore, the answer is to use a two-tailed test only if you have a convincing reason for not predicting a direction, and use the one that is most likely to produce significant results.

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Strange Times Inc. would recognize interest revenue of approximately $1,800 for Year 1.

To determine the interest revenue recognized for Year 1, we need to calculate the implied interest on the zero-interest bearing note. The implied interest rate is given as 6%.

The formula to calculate interest revenue is:

Interest Revenue = Principal Amount × Interest Rate.

In this case, the principal amount is $60,000. Multiplying it by the interest rate of 6% gives us $3,600, which represents the total interest for the two-year period. Since we are interested in the interest revenue for Year 1, we need to apportion this total amount accordingly.

To determine the interest revenue for Year 1, we divide the total interest by the number of years, which is 2, and round the result to the nearest dollar. So, $3,600 divided by 2 is $1,800. Therefore, Strange Times Inc. would recognize approximately $1,800 as interest revenue for Year 1.

It's important to note that the interest revenue recognized represents the amount of revenue related to the time period of Year 1 only. As the note is zero-interest bearing, the entire interest revenue is recognized upfront based on the implied interest rate.

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Answer:

(5a3b)(2ab)

Expand

That's

15ab( 2ab )

we have the answer as

5y(-y² + 7y - 2)

Expand

That's

Hope this helps you

1. The solution to the given differential equation \(V = V ln|sin(e)| - V^3 ln|cot(e) + cosec(e)| + C\) where C is an arbitrary constant.

2. The particular solution to the differential equation is \(s(t) = 0.5t^2 - 8\)

To solve the given differential equation: \(dV/de = V cot(e) + V^3 cosec(e)\), we can use separation of variables.

Starting with the differential equation:

\(dV/de = V cot(e) + V^3 cosec(e)\)

We can rearrange it as:

\(dV/(V cot(e) + V^3 cosec(e)) = de\)

Next, we separate the variables by multiplying both sides by (V cot(e) + V^3 cosec(e)):

\(dV = (V cot(e) + V^3 cosec(e)) de\)

Now, integrate both sides with respect to respective variables:

∫\(dV\) = ∫\((V cot(e) + V^3 cosec(e)) de\)

The integral of dV is simply V, and for the right side, we can apply integration rules to evaluate each term separately:

\(V = \int\limits(V cot(e)) de + \int\limits(V^3 cosec(e)) de\)

Integrating each term:

\(V = V ln|sin(e)| - V^3 ln|cot(e) + cosec(e)| + C\)

where C is the constant of integration.

2.To find particular solution of differential equation \(64 + 8s = 4e^2t\), using the method of undetermined coefficients, assume a particular solution of the form:\(s(t) = At^2 + Bt + C\), where A, B, and C are that constants which have to be determined.

Taking the derivatives of s(t), we have:

\(s'(t) = 2At + B\\s''(t) = 2A\)

Substituting derivatives into the differential equation, we get:

\(64 + 8(At^2 + Bt + C) = 4e^2t\)

Simplifying the equation, we have:

\(8At^2 + 8Bt + 8C + 64 = 4e^2t\)

Comparing coefficients of like terms on both sides, get:

8A = 4  -->  A = 0.5

8B = 0   -->  B = 0

8C + 64 = 0  -->  C = -8

Therefore, the particular solution to differential equation: \(s(t) = 0.5t^2 - 8\).

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