2. Dee owns a game system. He checked some stores to find the cheapest place to buy games. • Taylor's Department Store sells games for $15.50 each. • Buyer's Warehouse has an initial $25 membership fee, then each game is $12. a. Write an equation relating the cost c for any number of games g at each store. (Goal 11) Taylor's Department Store: Buyer's Warehouse:

Answer:

9y - 4(4) + y³= 18-16+8=10

The given equation is equivalent to y = -5x/7 - 2

Given that an equation, 5x+7y = -14, we need to find an equivalent equation for thus,

So,

5x+7y = -14

Minus 5x from both the sides

7y = -14 - 5x

Divide the equation by 7,

y = -5x/7 - 2

Hence the given equation is equivalent to y = -5x/7 - 2

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It is important to note that the chi-squared test of independence is applicable for categorical variables, and the assumptions of the test should be met for valid results.

The null hypothesis is a type of hypothesis that explains the population parameter and is used to examine if the provided experimental data are reliable.

To determine if the distribution of a given categorical variable is consistent with a null hypothesis, you can use a statistical test called the chi-squared test of independence.

The chi-squared test of independence is used to assess whether there is a significant association between two categorical variables. It compares the observed frequencies (counts) of each category in the given variable with the expected frequencies that would be observed if the null hypothesis were true. The null hypothesis typically assumes that there is no association or relationship between the variables, and any deviations from expected frequencies are due to random chance.

Here are the steps involved in conducting a chi-squared test of independence:

1. Formulate the null and alternative hypotheses: The null hypothesis assumes no association between the variables, while the alternative hypothesis suggests that there is an association.

2. Create a contingency table: Construct a contingency table that shows the observed frequencies of the categories for each variable.

3. Calculate the expected frequencies: Based on the null hypothesis, calculate the expected frequencies for each category. This is typically done assuming independence between the variables.

4. Calculate the test statistic: Using the observed and expected frequencies, calculate the chi-squared test statistic. This measures the overall discrepancy between the observed and expected frequencies.

5. Determine the p-value: The chi-squared test statistic follows a chi-squared distribution. Calculate the p-value associated with the test statistic, which represents the probability of obtaining results as extreme as the observed data under the null hypothesis.

6. Make a decision: Compare the p-value to a predetermined significance level (e.g., 0.05). If the p-value is smaller than the significance level, you reject the null hypothesis and conclude that there is evidence of an association between the variables. Otherwise, if the p-value is larger than the significance level, you fail to reject the null hypothesis and conclude that there is no evidence of an association.

It is important to note that the chi-squared test of independence is applicable for categorical variables, and the assumptions of the test should be met for valid results. These assumptions include having independent observations and sufficient expected frequencies in each cell of the contingency table.

It is also worth mentioning that there are other statistical tests available for specific scenarios or different types of categorical data analysis, such as Fisher's exact test or McNemar's test. The choice of the appropriate test depends on the research question, study design, and the specific characteristics of the data.

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Answer:

10 shirts have to be purchased.

Step-by-step explanation:

The Cactus Company equation: 15 (base fee) + 7x (7 being the price, x being the number of shirts purchased).

The Flower Company equation: 35 (base fee) + 5x (5 being the price, x being the number of shirts purchased).

Our final equation: 15+7x = 35 + 5x

                                    -5x            -5x

                                15+2x = 35

                                -15         -15

                                2x = 20

                                  /2    /2

                                  x = 10

Answer:

the solution points for the system of equations are (3, 25) and (-7/2, -7).

Step-by-step explanation:

We can solve this system of equations using substitution or elimination. Here, we will use the substitution method:

Substitute y = 2x^2 + 5x - 10 into the second equation:

4x - (2x^2 + 5x - 10) = -11

Simplifying the left side of the equation:

4x - 2x^2 - 5x + 10 = -11

Rearranging the terms:

2x^2 - x + 21 = 0

Using the quadratic formula:

x = (-(-1) ± sqrt((-1)^2 - 4(2)(21))) / 2(2)

x = (1 ± sqrt(169)) / 4

x = (1 ± 13) / 4

Simplifying:

x = 3 or x = -7/2

Now, substitute each value of x back into one of the original equations to find the corresponding value(s) of y:

For x = 3:

y = 2(3)^2 + 5(3) - 10 = 25

So one solution point is (3, 25).

For x = -7/2:

y = 4(-7/2) + 11 = -7

So the other solution point is (-7/2, -7).

Therefore, the solution points for the system of equations are (3, 25) and (-7/2, -7).

The difference in overall gain is $299.30.

For Stock A:

Purchase price: $90 per share

Number of shares: 120

Total purchase cost: 120 * $90 = $10,800

Selling at high price: $105.19

Selling at low price: $103.25

High price sale proceeds: 120 * $105.19 = $12,622.80

Low price sale proceeds: 120 * $103.25 = $12,390

Profit/loss at high price: $12,622.80 - $10,800 = $1,822.80

Profit/loss at low price: $12,390 - $10,800 = $1,590

Difference for Stock A: $1,822.80 - $1,590 = $232.80

For Stock B:

Purchase price: $145 per share

Number of shares: 35

Total purchase cost: 35 * $145 = $5,075

Selling at high price: $145.18

Selling at low price: $143.28

High price sale proceeds: 35 * $145.18 = $5,081.30

Low price sale proceeds: 35 * $143.28 = $5,014.80

Profit/loss at high price: $5,081.30 - $5,075 = $6.30

Profit/loss at low price: $5,014.80 - $5,075 = -$60.20

Difference for Stock B: $6.30 - (-$60.20) = $66.50

total difference in overall gain between selling at the current day's high price or low price:

Difference for Stock A + Difference for Stock B = $232.80 + $66.50 = $299.30

So, the correct statement is:

The difference in overall gain is $299.30.

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Answer:

x = 30

Step-by-step explanation:

x + 2x + 3x = 180 (Add like terms)

6x = 180 (Divide both sides by 6)

x = 30

Therefore;

x = 30

2x = 60

3x = 90

Answer:

answer is A cuz if we put the value 11 instead of g we get 26 so the answer is 11

Answer:

i wrote how to below!

Step-by-step explanation:

okay since the y intercept is 2, put a dot on the point (0, 2)

now for the next one just substitute an easy value like 1 to the equation

y = 3/4(4) + 2

the 4 will cancel out the denominator then...

y = 3 + 2

y = 5

now put a point on (4, 5)

Answer:

answer in explanation

Step-by-step explanation:

(0,2)

(1,2.75)

(2,3.5)

(3,4.25)

(4,5)

9514 1404 393

Answer:

  5x -16y = 2

Step-by-step explanation:

The least common multiple of the fraction denominators is 6. Multiplying by that gives ...

  16y = 5x -2

We can put this in standard form by adding 2-16y to both sides.

  5x -16y = 2

Answer:

4.6620663x10^19 or 46,620,663,000,000,000,000 total configurations

Step-by-step explanation:

Since each couple must get adjacent seats, we can first think of the row as having 17 seats instead of 34 since the people in each pair does not change and we consider instead the position of the pair rather than the two people.

There are 17 places where each couple can sit in the 34 chairs. Therefore the number of ways to order the 17 pairs (regardless of the order of individual people in those pairs) is 17!.

This is because first place could be taken by any of the 17 couples so there are 17 possibilities. After the first place is taken, there are only 16 possible couples to take the second place to we have 17x16. After the first two are taken there are only 15 possible couples to take the third place so we multiply by 15. This continues with each respective place so the total number of configurations is: 17x16x15x14x13x12x11x10x9x8x7x6x5x4x3x2x1 OR 17! which is equal to 3.5568743x10^14, or 355,687,430,000,000 different configurations.

Now we must also consider the order of the individual people in the pairs as one can sit on the left or on the right of the other person (e.g. 1,2 or 2,1). And since each pair can have two possible orders, every possible configuration of the pairs in the 17 places must be multiplied by 2^17 to accommodate for this (2x2x2x2x2x2x2x2x2x2x2x2x2x2x2x2x2 for the 17 couples), which is equal to: 131072

Therefore the total number of ways to seat 17 couples in a row of 34 is 131072x355,687,430,000,000= 4.6620663x10^19 or 46,620,663,000,000,000,000 total configurations.

Hope this helped!

Answer:

2^17 × 17!

Step-by-step explanation:

Seat 1 = 34 possibilities

Seat 2 = 1 possibility

Seat 3 = 32 possibilities

Seat 4 = 1 possibility

And so on

So it is 34 × 32 × 30 × ... × 2

So it is

\( {2}^{17} \times 17factorial\)

I hope this helps you :)

Answer:

its D

Step-by-step explanation:

"For whatever reasons, Ray, call it . . . Fate, Call it Luck, Call it Karma. I believe everything happens for a reason. I believe that we were destined to get thrown out of this dump."-Dr. Peter Venkman (GhostBusters)

Im imposter yay

Answer:

Step-by-step explanation:

This triangle is a 30-60-90 triangle, which you can just find by solving for the unknown angle in the triangle, making it a 30-60-90 triangle.

You'll need to memorize the side lengths for these triangles, but the side opposite from the hypotenuse (x in this case), will be half the length of the hypotenuse.

Meaning that \(2x=8\)

So \(x=4\)

Hope this helps.

頑張って!

Answer:

3.21

Step-by-step explanation:

.........................

a) A recurrence relation for the number of bit strings of length n that contain three consecutive 0s :

a_n = a_(n-1) + a_(n-2) + a_(n-3) + 2^(n-3)   for n ≥ 3

b) The initial conditions are:

a_0 = a_1 = a_2 = 0 and a_3 = 1

c) There are 47 bit strings of length seven contain three consecutive 0s

Let s_n be a string of length n that does not have 3 consecutive 0's, and a_n be the number of strings  that contain three consecutive 0's

Consider a string of length n -1 that does not have 3 consecutive 0's, s_(n-1)

If we add 1 to this string, then we get a string s_n.

Consider a string s_(n-2)

If we add 10 at the end, then we get a string s_n

Now consider a string s_(n-3)

If we add 100 at the end we get a string s_n.

Now we got all possible strings s_n: that end in 1 (i.e. the last 3 digits could be 001, 011, 101 and 111),

Those strings that end in 10 (i.e. the last 3 digits could be 010 and 110)

and those strings  that end in 100. There are no other possibilities without having 3 consecutive zeros.

In the third case, there are a_(n-3) possibilities. And, in the fourth case, there are 2^(n-3) possibilities.

Hence the recurrence relation is

So, a_n = a_(n-1) + a_(n-2) + a_(n-3) + 2^(n-3)   for n ≥ 3

The initial conditions are a_0 = a_1 = a_2 = 0 and a_3 = 1

The recurrence gives the sequence of positive integers 0, 0, 0, 1, 3, 8, 20, 47, 107, 238, 520, 1121, 2391, . . . .

Hence there are a_7 = 47 bit strings of length seven that contain

three consecutive 0's.

Therefore, a) the recurrence relation:

a_n = a_(n-1) + a_(n-2) + a_(n-3) + 2^(n-3)   for n ≥ 3

b) Initial conditions: a_0 = a_1 = a_2 = 0 and a_3 = 1

c) there are 47 bit strings of length seven

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Answer:

x = -3, x = 0 is a extraneous solution

Step-by-step explanation:

Step 1: Cross-multiply

3x² = 4x² + 3x

Step 2: Isolate x's

0 = x² + 3x

Step 3: Factor

0 = x(x + 3)

Step 4: Find roots

x = 0, -3

Step 5: Double check work

Plug in both to see if they both work. Only x = 0 should be extraneous. We now have our answer!

Answer:

x = -3, x = 0 is a extraneous solution

Step-by-step explanation:

the person above is correct

The probability that the time until an accident occurs exceeds the mean time by more than 2 standard deviations is 0.0228 or 2.28%.

Using the standard normal distribution (Z) table.
Step 1: Convert the problem into a Z-score. In this case, the Z-score is 2 because we are looking for the probability of exceeding the mean by more than 2 standard deviations.
Step 2: Look up the Z-score of 2 in the standard normal distribution table. You will find a probability value of 0.9772. This value represents the probability that the time until an accident occurs is within 2 standard deviations from the mean.
Step 3: Since we are looking for the probability that the time exceeds the mean by more than 2 standard deviations, we need to find the probability of the complement. Subtract the probability found in Step 2 from 1.
1 - 0.9772 = 0.0228
So, the probability that the time until an accident occurs exceeds the mean time by more than 2 standard deviations is 0.0228 or 2.28%.

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(A) Circular orbits of stable particles are possible at radii greater than three times the Schwarzschild radius for the non-rotating spherically symmetric mass.

This represents the radius of a black hole's event horizon, within which nothing can escape. The Schwarzschild radius is the event horizon radius of a black hole with mass M.

M can be calculated using the formula: r+ = 2Mwhere r+ is the radius of the event horizon.

(B)  1/2 M -1/2 3M (²) ¹² (1-³) dT = R³ R. This is the required expression.

Tau is the proper time of the particle moving around a circular orbit. Hence, by making use of the formula given above:1/2 M -1/2 3M (²) ¹² (1-³) dT = R³ dt.

(C) Time passes differently in different gravitational fields, and it follows that the period as measured at infinity should be larger than that measured by the particle.

The principle of equivalence can be defined as the connection between gravitational forces and the forces we observe in non-inertial frames of reference. It's basically the idea that an accelerating reference frame feels identical to a gravitational force.

(D) The period of the orbit as measured by an observer at infinity is 16π M^(1/2) and the period of the orbit as measured by the particle is 16π M^(1/2)(1 + 9/64 M²).

The period of orbit as measured by an observer at infinity can be calculated using the formula: T = 2π R³/2/√(M). Substitute the given values in the above formula: T = 2π (8M)³/2/√(M)= 16π M^(1/2).The period of the orbit as measured by the particle can be calculated using the formula: T = 2π R/√(1-3M/R).

Substitute the given values in the above formula: T = 2π (8M)/√(1-3M/(8M))= 16π M^(1/2)(1 + 9/64 M²).

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Answer:

463

Step-by-step explanation:

Division is repeated subtraction

So to get 0, we divide 20835 by 45

=> 20835/45

=> 463

The total amount he puts towards emergency savings is $74

The correct option is C.

His total weekly deposits are as follows: 219+115+40+20+10+40+15 = 459

Now

that we are aware, his weekly deposits total $459 in total.

His total remuneration is $498 due to an error in his addition of the numbers.

The amount he has each week will be determined by deducting his deposits from his paycheck:

498-459 = 39

He contributes two equal payments of $20 and $15 to his emergency fund.

His entire contribution to emergency savings is = 20 + 15 = 35.

Only need to add the additional $39

To determine how much he can set aside each week for emergency savings, multiply his total emergency savings by 35 dollars:

39+35 = 74

the total per week that he can put towards emergency savings = $74

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I understand that the question you are looking for is:

Mr. Thom makes $25,900/year salary as a document processor. He has made the following chart in order to divide his weekly paycheck into his accounts: Expense type Account Weekly deposits Essential (Fixed) 1st Checking account $219 Essential (Variable) 1st Checking account $115 Non-essential 2nd Checking account $40 Other (Unexpected) Emergency savings account $20 Other (Pictable) Education investment fund $10 Other (Pictable) Retirement investment fund $40 Other (Pictable) Emergency savings account $15 Total paycheck $498 Unfortunately, he has made a mistake in adding the numbers and has not allocated all of the paycheck. If he deposits the difference into the two emergency savings accounts, how much total per week can he then put towards emergency savings?

a. $40

b. $60

c. $74

d. $55

Answer: C. $74

Step-by-step explanation:  C. $74.00

Answer:

\(\huge\boxed{\bf\:2\left(3x-1\right)\left(3x+2\right) }\)

Step-by-step explanation:

\(18x^{2} + 6x - 4\\\\Factor \: out \: the \: common \: factor = 2\\\\= 2\left(9x^{2}+3x-2\right) \\\\Split\:the\:quadraric\:equation\:inside\:the\:parentheses \\\:using\:the\:splitting-the-middle-term \:method.\\\\= 2\left(9x^{2}-3x\right)+\left(6x-2\right) \\= 2 (3x\left(3x-1\right)+2\left(3x-1\right) )\\= \boxed{\bf\:2 \left(3x-1\right)\left(3x+2\right) }\)

\(\rule{150pt}{2pt}\)

Answer:

2(3x - 1)(3x + 2)

Step-by-step explanation:

18x² + 6x - 4 ← factor out 2 from each term

= 2(9x² + 3x - 2) ← factor the quadratic

consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 9 × - 2 = - 18 and sum = + 3

the factors are - 3 and + 6

use these factors to split the x- term

9x² - 3x + 6x - 2 ( factor first/second and third/fourth terms )

= 3x(3x - 1) + 2(3x - 1) ← factor out (3x - 1) from each term

= (3x - 1)(3x + 2) ← in factored form

then

18x² + 6x - 4

= 2(3x - 1)(3x + 2)

x=12 hopefully it helps

By understanding some statistics concepts, it can be concluded that these data are Quantitative and Discrete, and the highest level of measurement the data possesses is Interval.

Qualitative data is information that is descriptive and cannot be measured by numbers.

Quantitative data is a collection of information that can be measured, calculated, and compared on a numerical scale.

Discrete data is a type of data that has clear spaces and points between values. It contains distinct or discrete values.

Continuous data is data that falls in a continuous sequence. It includes any value that falls within a range.

Nominal data is data given to objects or categories that do not describe the position of the object, but only labels/codes.

Ordinal data is data whose numbering objects or categories are arranged according to magnitude, from the lowest level to the highest or vice versa, with the distance/range not having to be the same.

Interval data is data where objects/categories can be sorted based on an attribute that provides information about the interval between each object/category the same.

Ratio data is data that is the same distance and has an absolute zero value.

Thus, based on these definitions, data about the IQ scores of students at the local college are Quantitative and Discrete, and the highest level of measurement the data possesses is Interval.

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Answer:

The similarity postulate theorem is;

Similar - AA

Step-by-step explanation:

We are told that angle p is congruent to angle s, angle q is congruent to angle t.

Thus it is an AA similarity theorem because AA similarity theorem states that: If two angles in one triangle are congruent/respectively equal to two angles of another triangle, then the 2 triangles are similar.

For example, if we assume ΔABC and ΔDEF to be two triangles such that ∠A = ∠D and ∠B = ∠E. Then the two triangles are equiangular and thus they are similar by AA.

Answer: similar AA is correct

Step-by-step explanation:

Just took the test:)

The length of the vector x=5e1+3e2+2e3+4e4+2e5−4e6 is √79.

The given vector x can be expressed as a linear combination of the standard basis vectors in R6. We calculate the length (magnitude) of x using the formula ||x|| = √(x₁² + x₂² + x₃² + x₄² + x₅² + x₆²), where x₁, x₂, x₃, x₄, x₅, and x₆ are the coefficients of the standard basis vectors e1, e2, e3, e4, e5, and e6 respectively.

In this case, x = 5e1 + 3e2 + 2e3 + 4e4 + 2e5 - 4e6, so we substitute the coefficients into the formula:

||x|| = √((5)² + (3)² + (2)² + (4)² + (2)² + (-4)²)

      = √(25 + 9 + 4 + 16 + 4 + 16)

      = √(74 + 5)

      = √79

Therefore, the length of vector x, ||x||, is √79.

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Answer:

Area of big diagram = 33.32 m²

Step-by-step explanation:

Given:

Both given diagram is similar

Perimeter of small diagram = 20 m

Area of small diagram = 19.6 m²

Perimeter of big diagram = 34 m

Find:

Area of big diagram

Computation:

Both given diagram is similar So,

Perimeter of small diagram / Area of small diagram = Perimeter of big diagram / Area of big diagram

20 / 19.6 = 34 / Area of big diagram

Area of big diagram = [19.6/20][34]

Area of big diagram = 33.32 m²

Answer:

56.6

Step-by-step explanation:

this equation (34/20)^2 * 19.6 = 56.644

Answer:

The answer is 3

Step by step explination

y/x times 3 Its a little trick I learned at math camp last year!