2. Fill in the blanks. (3 pts for each blank, total 24 pts) (1) ____ [ is used to store the user's basic information (including: user's login name, user's home directory, user's password, shell program used by the user, such as bash, or CSH) (2) Using command ____ to display the current login user. (3) After some programs or services are started, their PID will be placed in the directory: ____ Some temporary archives generated during the operation of the application Result will be stored in the directory: ____ (4) who can use the command groupdel? ____ (5) Files permissions, r express ____], w express [ ____],x express ____
Answers
(1) The / etc / passwd file is used to store the user's basic information (including: user's login name, user's home directory, user's password, shell program used by the user, such as bash, or CSH).
(2) Using command whoami to display the current login user.
(3) After some programs or services are started, their PID will be placed in the directory: /var / run. Some temporary archives generated during the operation of the application will be stored in the directory: /tmp.
(4) Who can use the command groupdel? The root user.
(5) Files permissions, r express [read], w express [write], x express [execute].
The /etc/ passwd file is a system file that stores basic information about user accounts on a Unix-like operating system. It contains entries for each user, including their login name, encrypted password (or a reference to the password file), user ID, group ID, home directory, and default shell. This file is used by the system for user authentication and to retrieve user information when needed.
The whoami command is used to display the login name of the current user. When executed, it retrieves the username associated with the current session and prints it on the terminal. It is a simple way to identify the currently logged-in user without the need for additional arguments or options.
In Unix-like systems, when programs or services are started, their unique process IDs (PIDs) are stored in the /var/run directory. This directory is used to keep track of running processes and allows other programs to query information about them. Additionally, temporary files generated during the operation of an application may be stored in the /tmp directory, providing a location for temporary storage that is cleared periodically.
The groupdel command is used by the root user in Unix-like systems to delete a group. The root user has administrative privileges and can manage user accounts, groups, and permissions on the system. By executing groupdel followed by the group name, the root user can delete a group from the system, removing its associated permissions and settings.
File permissions in Unix-like systems are represented by the letters r (read), w (write), and x (execute). These permissions determine the access rights for files and directories. The read permission allows a file to be viewed or read, the write permission allows modifications to the file, and the execute permission allows the file to be executed as a program or script.
Each permission can be granted or denied for three different categories of users: the owner of the file, the group associated with the file, and other users. The permissions are represented as a series of characters in the order of owner, group, and other users.
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Related Questions
9. The highest voltage typically encountered on the job by a residential electrician is
volts.
A. 120
B. 600
C. 240
D. 480
Answers
Answer:
240
Explanation:
The highest voltage typically encountered on the job by a residential electrician is C. 240 volts.
What is voltage?Voltage is the measure of the difference in electrical power between two points in a circuit.
It is like the force that pushes electric charges in a circuit and is measured in volts (V) and affects how strong the electric current flows in a wire.
In many countries, the United States included, residential electrical systems often use a split-phase setup with a voltage of 120/240 volts.
This voltage is widely used for things like household appliances, lights, and other electrical needs in homes.
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An adiabatic pump is to be used to compress saturated liquid water at 10 kPa to a pressure of 15 MPa in a reversible manner. 15 MPa P Pump Determine the work input using entropy data from the compressed liquid table. Use steam tables. (You must provide an answer before moving on to the next part.) The work input is kJ/kg. Determine the work input using inlet specific volume and pressure values. (You must provide an answer before moving on to the next part.) The work input is kJ/kg Determine the work input using average specific volume and pressure values. answer before moving on to the next part.) The work input is kJ/kg. Calculate the errors involved in parts b and c. The error involved in part b is 1% The error involved in part cis 1%.
Answers
To determine the work input using entropy data from the compressed liquid table, we need to find the specific entropy of water at 10 kPa and 15 MPa, then calculate the change in entropy during the compression process.
From the compressed liquid table, we can find that the specific entropy of saturated liquid water at 10 kPa is 0.2888 kJ/kg-K. At 15 MPa, the specific entropy of saturated liquid water is 1.2960 kJ/kg-K.
The change in entropy during the compression process is ΔS = S2 - S1 = 1.2960 - 0.2888 = 1.0072 kJ/kg-K.
Using the definition of adiabatic work as dW = -TdS, where T is the temperature and dS is the change in entropy, we can calculate the work input per unit mass as:
dW = -TΔS
To find the temperature at each state, we can use the saturated liquid table again. At 10 kPa, the saturation temperature is 10.01°C, and at 15 MPa, the saturation temperature is 198.4°C.
Using these temperatures and the change in entropy calculated above, we get:
dW = - (198.4 + 273.15) * 1.0072 = -478.5 kJ/kg
Therefore, the work input using entropy data from the compressed liquid table is -478.5 kJ/kg.
To determine the work input using inlet specific volume and pressure values, we can use the equation for reversible adiabatic work:
dW = v(P2 - P1)
where v is the specific volume and P1 and P2 are the initial and final pressures, respectively.
Using the saturated liquid table, we find the specific volume of saturated liquid water at 10 kPa is 0.001043 m³/kg. At 15 MPa, we can use the compressed liquid table to find that the specific volume of saturated liquid water is approximately 0.001066 m³/kg.
Using these values in the equation above, we get:
dW = 0.001043 * (15 - 0.01) * 10⁶ = 154.7 kJ/kg
Therefore, the work input using inlet specific volume and pressure values is 154.7 kJ/kg.
To determine the work input using average specific volume and pressure values, we can use the average pressure and specific volume during the compression process:
Pavg = (P1 + P2) / 2 = (0.01 + 15) / 2 = 7.505 MPa
vavg = (v1 + v2) / 2 = (0.001043 + 0.001066) / 2 = 0.001055 m³/kg
Using these values, we can calculate the work input as:
dW = vavg * (P2 - P1)
dW = 0.001055 * (15 - 0.01) * 10⁶ = 155.7 kJ/kg
Therefore, the work input using average specific volume and pressure values is 155.7 kJ/kg.
To calculate the errors involved in parts b and c, we can use the formula:
error = |(actual value - approximate value) / actual value| * 100%
For part b, the actual value is -478.5 kJ/kg and the approximate value is 154.7 kJ/kg. Plugging in these values, we get:
error = |(-478.5 - 154.7) / -478.5| * 100% = 132.6%
Therefore, the error involved in part b is 132.6%.
For part c, the actual value is -478.5 kJ/kg and the approximate value is 155.7 kJ/kg. Plugging in these values, we get:
error = |(-478.5 - 155.7) / -478.5| * 100% = 132.5%
Therefore, the error involved in part c is 132.5%.
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The most appropriate layout for an automobile assembly line
process is a
Group of answer choices
Fixed position layout
Cellular layout
Product layout
None of these answers is correct
Process layout
Answers
The most appropriate layout for an automobile assembly line process is a Product layout.
What layout is best suited for automobile assembly lines?In automobile manufacturing, a product layout is the most appropriate assembly line process. This layout involves arranging workstations and equipment in a sequential order that matches the production steps required to assemble the vehicles. Each workstation is dedicated to a specific task, such as installing a particular component or system, and the vehicles move along the line as the assembly progresses.
The product layout offers several advantages in terms of efficiency and productivity. It allows for a smooth, uninterrupted flow of work, minimizing unnecessary movement and reducing production time. Specialized tools and equipment can be stationed at each workstation, ensuring that workers have everything they need at hand. Additionally, this layout enables standardized processes and quality control measures to be implemented effectively, leading to consistent product quality.
The product layout in automobile assembly lines optimizes efficiency, productivity, and quality by arranging workstations and equipment in a sequential order. This layout streamlines the assembly process, reducing unnecessary movement and ensuring a smooth flow of work. Specialized tools and equipment are stationed at each workstation, enabling workers to perform their tasks efficiently.
Standardized processes and quality control measures can be implemented effectively, resulting in consistent product quality. The product layout is widely used in the automotive industry to maximize production efficiency and meet customer demands.
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If you can choose among three lanes on your side of the road,
a. pick the right lane for the smoothest driving
b. use the middle lane to drive slowly, enter, or turn off the road
c. use the left lane to go faster, pass, or turn left
h
Answers
Please explain the term ‘causal link’. What is the importance of the causal link
in work accidents? What kind of situations breaks the causal link? Explain all
situations with examples.
Answers
Answer:
:)
Explanation:
The correlation between a factor and an outcome could be a coincidence, or it could be caused by a completely different factor. For example, as ice cream sales increase, sales of meat for barbecues also increase.
Technician a says that all vehicles from the same manufacturer use the exact same power steering fluid. technician b says that some fluids may be incompatible with system seals. which technician is correct
Answers
The technicians have it right .The power steering system in a car uses the power of the engine to make it easier to turn the front wheels.
Power sterilizing fluid: what is it?It is a technology that helps the driver control and steer the vehicle better.
There are options for either electric or hydraulic power steering systems. Fluid is used to deliver hydraulic pressure to a hydraulic system in order to assist in turning a car's wheels. Using an electric motor and a variety of sensors, an electric system determines how much assistance the system needs to provide based on the force applied by the driver to the steering wheel.
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Estimate properties and pipe diameter Determine the diameter of a steel pipe that is to carry 2000 gal/min of gasoline with a pressure drop of 5 psi per 100 ft of horizontal pipe. Pressure drop is a function of flow rate, length, diameter, and roughness. Either iterative methods OR equation solvers are necessary to solve implicit problems. Total head is the sum of the pressure, velocity, and elevation. What is the density of gasoline
Answers
Answer:
Diameter of pipe is 0.535 ft
Explanation:
see attachment, its works out 1st half
Rod of steel, 200 mm length reduces its diameter (50 mm) by turning by 2 mm with feed speed 25 mm/min. You are required to calculate the metal removal rate (MRR)
Answers
Answer:
Explanation:
The material rate of removal is the total amount of material removed per unit time during any operation. The material rate of removal is usually given by the formula
Material Rate of Removal = Radial Depth of Cut * Axial Depth of Cut * Feed Rate, where
Radial Depth of Cut, RDOC = 25 mm
Axial depth of cut, ADOC = 200 mm
Feed rate, FR = 25 mm/min
On multiplying all together, we will then have our Material Rate of Removal, which is
MRR = 25 mm * 200 mm * 25 mm/min
MRR = 125000 mm³/min
Or we convert it to cm³/min and have
MRR = 125000 mm³/min ÷ 1000
MRR = 125 cm³/min
Liquid benzene and liquid n-hexane are blended to form a stream flowing at a rate of 1700 lbm/h. An on-line densitometer (an instrument used to determine density) indicates that the stream has a density of 0.810 g/mL. Using specific tractors from Table B.1, estimate the mass and volumetric feed rates of the two hydrocarbons to the mixing vessel (in U.S. customary units). State at least two assumptions required to obtain the estimate from the recommended date.
Answers
I want to draw a monster should i do it on my free time and if you want to give me ideas.
Answers
Answer:
yes
Explanation:
an idea could be a jack o lantern monster since it Halloween tomorrow
1. Use the charges to create an electric dipole with a horizontal axis by placing a positive and a negative charge (equal in magnitude but opposite in sign) 4 meters away from each other. (Axis of a dipole is a line passing through both charges.) Place positive charge on the left and negative on the right.
2. Describe the field at the following locations, and explain these results using the superposition principle:
on the horizontal axis to the right of the dipole;
on the horizontal axis between charges;
on the horizontal axis to the left of the charges;
on the vertical line bisecting the line segment connecting the charges, above the dipole;
on the vertical line bisecting the line segment connecting the charges, below the dipole;
is there a location where the electric field is exactly zero?
Remove the negative charge and replace it with equal in magnitude positive charge.
3. Observe the change in electric field, and again describe the field at the following locations, explaining these results using the superposition principle:
on the horizontal axis to the right of the charges;
on the horizontal axis between charges;
on the horizontal axis to the left of the charges;
on the vertical line bisecting the line segment connecting the charges, above the charges;
on the vertical line bisecting the line segment connecting the charges, below the charges;
is there a location where the electric field is exactly zero?
Answers
Answer:
2)
a) to the right of the dipole E_total = kq [1 / (r + a)² - 1 / r²]
b)To the left of the dipole E_total = - k q [1 / r² - 1 / (r + a)²]
c) at a point between the dipole, that is -a <x <a
E_total = kq [1 / x² + 1 / (2a-x)²]
d) on the vertical line at the midpoint of the dipole (x = 0)
E_toal = 2 kq 1 / (a + y)² cos θ
Explanation:
2) they ask us for the electric field in different positions between the dipole and a point of interest. Using the principle of superposition.
This principle states that we can analyze the field created by each charge separately and add its value and this will be the field at that point
Let's analyze each point separately.
The test charge is a positive charge and in the reference frame it is at the midpoint between the two charges.
a) to the right of the dipole
The electric charge creates an outgoing field, to the right, but as it is further away the field is of less intensity
E₊ = k q / (r + a)²
where 2a is the distance between the charges of the dipole and the field is to the right
the negative charge creates an incoming field of magnitude
E₋ = -k q / r²
The field is to the left
therefore the total field is the sum of these two fields
E_total = E₊ + E₋
E_total = kq [1 / (r + a)² - 1 / r²]
we can see that the field to the right of the dipole is incoming and of magnitude more similar to the field of the negative charge as the distance increases.
b) To the left of the dipole
The result is similar to the previous one by the opposite sign, since the closest charge is the positive one
E₊ is to the left and E₋ is to the right
E_total = - k q [1 / r² - 1 / (r + a)²]
We see that this field is also directed to the left
c) at a point between the dipole, that is -a <x <a
In this case the E₊ field points to the right and the E₋ field points to the right
E₊ = k q 1 / x²
E₋ = k q 1 / (2a-x)²
E_total = kq [1 / x² + 1 / (2a-x)²]
in this case the field points to the right
d) on the vertical line at the midpoint of the dipole (x = 0)
In this case the E₊ field points in the direction of the positive charge and the test charge
in E₋ field the ni is between the test charge and the negative charge,
the resultant of a horizontal field in zirconium on the x axis (where the negative charge is)
E₊ = kq 1 / (a + y) 2
E₋ = kp 1 / (a + y) 2
E_total = E₊ₓ + E_{-x}
E_toal = 2 kq 1 / (a + y)² cos θ
e) same as the previous part, but on the negative side
E_toal = 2 kq 1 / (a + y)² cos θ
When analyzing the previous answer there is no point where the field is zero
The different configurations are outlined in the attached
3) We are asked to repeat part 2 changing the negative charge for a positive one, so in this case the two charges are positive
a) to the right
in this case the two field goes to the right
E_total = kq [1 / (r + a)² + 1 / r²]
b) to the left
E_total = - kq [1 / (r + a)² + 1 / r²]
c) between the two charges
E₊ goes to the right
E₋ goes to the left
E_total = kq [1 / x² - 1 / (2a-x)²]
d) between vertical line at x = 0
E₊ salient between test charge and positive charge
E_total = 2 kq 1 / (a + y)² sin θ
In this configuration at the point between the two charges the field is zero
How does concurrent engineering speed up product development?
A. The product and process are designed using computer-aided design.
B. The product and process are designed in series.
C. The product and process are designed in separate spaces.
D. The product and process are designed simultaneously.
Answers
Answer:
The product and process are designed simultaneously
Explanation:
PENN
a river reach has flow of 350 ft3 /sec in trapezoidal channel with a bottom width of 14 ft and side slopes of 7:2 (h:v). the channel reach is 1300 ft long. channel bottom elevations at upstream and downstream of the reach are 146 ft and 141 ft, respectively. estimate the channel depth. the channel roughness is equivalent to earth, uniform section, graveled soil.
Answers
The estimated channel depth (\(\(y\)\)) is approximately 0.714 ft or 8.57 inches.
Understanding Channel DepthTo estimate the channel depth in the given trapezoidal channel, we can use the concept of energy equation for flow in open channels. The energy equation for this case is as follows:
\(\[E_1 + \frac{V_1^2}{2g} + z_1 = E_2 + \frac{V_2^2}{2g} + z_2 + h_L\]\)
Where:
\(\(E_1\)\) and \(\(E_2\)\) are the specific energies at upstream and downstream locations, respectively.
\(\(V_1\)\) and \(\(V_2\)\) are the velocities at upstream and downstream locations, respectively.
\(\(g\)\) is the acceleration due to gravity (approximately 32.2 ft/s²).
\(\(z_1\)\) and \(\(z_2\)\) are the elevations at upstream and downstream locations, respectively.
\(\(h_L\)\) is the head loss due to friction between the two locations.
The trapezoidal channel flow area \((\(A\))\) can be expressed as:
\(\[A = (b + 2zy) y\]\)
Where:
\(\(b\)\) = bottom width of the channel (14 ft)
\(\(z\)\) = side slope (7:2, h:v) = 7
\(\(y\)\) = channel depth (unknown)
The channel velocity \((\(V\))\) can be calculated as:
\(\[V = \frac{Q}{A}\]\)
Where:
\(\(Q\)\) = flow rate (350 ft³/s)
We can assume that the channel is running full, which means the depth of flow (\(\(y\)\)) is equal to the flow depth (\(\(d\)\)).
Now, let's solve for the channel depth (\(\(y\)\)):
Step 1: Calculate the cross-sectional area (A) of the channel:
\(\[A = (14 + 2 \cdot 7 \cdot y) \cdot y = (14 + 14y) \cdot y = 14y + 14y^2\]\)
Step 2: Calculate the flow velocity (V) using the flow rate (Q) and cross-sectional area (A):
\(\[V = \frac{Q}{A} = \frac{350}{14y + 14y^2}\]\)
Step 3: Calculate the specific energy (E) at the upstream and downstream locations:
\(\[E_1 = \frac{V^2}{2g} + z_1 = \frac{\left(\frac{350}{14y + 14y^2}\right)^2}{2 \cdot 32.2} + 146\]\)
\(\[E_2 = \frac{V^2}{2g} + z_2 = \frac{\left(\frac{350}{14y + 14y^2}\right)^2}{2 \cdot 32.2} + 141\]\)
Step 4: Write the energy equation between the upstream and downstream locations:
\(\[\frac{\left(\frac{350}{14y + 14y^2}\right)^2}{2 \cdot 32.2} + 146 = \frac{\left(\frac{350}{14y + 14y^2}\right)^2}{2 \cdot 32.2} + 141 + h_L\]\)
Step 5: Cancel out the terms and solve for \(\(h_L\)\):
\(\[h_L = z_1 - z_2 = 146 - 141 = 5\]\)
Step 6: Calculate the flow depth (\(\(y\)\)) using the head loss (\(\(h_L\)\)):
\(\[y = \frac{h_L}{z} = \frac{5}{7} = 0.714\]\)
Therefore, the estimated channel depth (\(\(y\)\)) is approximately 0.714 ft or 8.57 inches.
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Water is pumped from a lake to a storage tank 18 m above at a rate of 70 L/s while consuming 20.4 kW of electric power. Disregard any frictional losses in the pipes and any changes in kinetic energy, determine (a) the overall efficiency of the pump-motor unit (5-point), and (b) the pressure difference between the inlet and the exit of the pump (5-point).
Answers
Part A
For each method,a function to model the expected number of plants for each year
Part B
Use the Functions to Find the expected number of plants in 10 years for each method.
Part C
Suppose you have a coworker who is a high Mach in your workplace. What could you do to counter the behavior of that individual? Put the high Mach individual in charge of a project by himself, and don’t let others work with him. Set up work projects for teams, rather than working one on one with the high Mach person. Work with the high Mach individual one on one, rather than in a team setting. Explain to the high Mach individual what is expected of him and ask him to agree to your terms.
Answers
Answer:
To counter the behavior of a high Mach individual in my workplace, I could put the individual in charge of a project by himself, and don't let others work with him.
Explanation:
A high Mach individual is one who exhibits a manipulative and self-centered behavior. The personality trait is characterized by the use of manipulation and persuasion to achieve power and results. But, such individuals are hard to be persuaded. They do not function well in team settings and asking them to agree to terms is very difficult. "The presence of Machiavellianism in an organisation has been positively correlated with counterproductive workplace behaviour and workplace deviance," according to wikipedia.com.
Mach is an abbreviation for Machiavellianism. Machiavellianism is referred to in psychology as a personality trait which sees a person so focused on their own interests that they will manipulate, deceive, and exploit others to achieve their selfish goals. It is one of the Dark Triad traits. The others are narcissism and psychopathy, which are very dangerous behaviors.
Find the engine volume and compression ratio from the paper. Use those numbers to calculate the following and list any assumptions you make about the cycle in your document. Assume that air has γ-1.4 and R-287 J/kgK. and the engine is running an air-standard ideal Otto cycle.
a) Indicated work produced each cycle (in Joules)
b) Heat addition each cycle (in Joules) - assume the engine runs off gasoline with a lower heating value of 42 MJ/kg and air-to-fuel ratio of 14.7 (stoichiometric for gasoline). The lower heating value is the amount of heat generated from the combustion of a liquid fuel per unit mass.
c) Indicated thermal efficiency of the engine.
Answers
Answer:
A) 411.66 Kj/kg
B) 672.23 kj/kg
C) 55.8%
Explanation:
Assumptions:
y = 1.4
R = 287 j/kg/k
lower heating value = 42 mj/kg
air-to-fuel ratio = 14.7
attached below is the detailed solution
What part moves in the brake caliper to push the brake pads against the brake rotor?
Answers
The component that moves in the brake caliper to push the brake pads up against the brake rotor is called the brake piston.
What is Brake Pistons?The ability of the brake pads to make contact with the braking rotor and stop a vehicle is provided by the pistons. The master cylinder releases braking fluid into the brake caliper when the brake pedal is depressed, and the pistons can be found in both floating and fixed brake calipers.
On the inboard side of the braking rotor, a floating caliper typically has one or two large diameter pistons. The piston(s) pull both pads toward the brake disc when they are engaged. Behind the brake pads, pistons are forced outward.
The brake pedal and master cylinder of the car generate hydraulic pressure in the braking fluid that engages the caliper. In this assembly, friction is produced by pressing the brake pads up against the disc rotor surface.
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A gas has an initial volume o.25m^3, and absolute pressure 100kPa. Its initial temperature is 290k. The gas is compressed into a volume of o.O5m^3 during which its temperature rises to 405k. Calculate its final pressure using the formula . P1V1/T1=p2V2/t2
Answers
Answer:
698.3KpaExplanation:
Step one:
given data
V1=0.25m^3
T1=290k
P1=100kPa
V2=0.5m^2
T2=405k
P2=? final pressure
Step two:
The combined gas equation is given as
P1V1/T1=P2V2/T2
Substituting we have
(100*0.25)/290=P2*0.05/405
25/290=0.5P2/405
0.086=0.05P2/405
cross multiply
0.086*405=0.05P2
34.9=0.05P2
divide both sides by 0.05
P2=34.9/0.05
P2=698.3Kpa
Therefore the new pressure is 698.3Kpa when the gas is compressed
Come up with a topic that can be put on research project/topic
proposal concerning applications of hydrographic surveying. include
research and review of related literature.
Answers
The research project/topic proposal focuses on the applications of hydrographic surveying. It involves conducting research and reviewing related literature to explore the various uses and advancements in hydrographic surveying techniques and technologies.
Hydrographic surveying plays a crucial role in various fields such as marine navigation, coastal engineering, offshore resource exploration, and environmental monitoring. This research project aims to investigate the applications of hydrographic surveying and analyze its impact on these industries.
The proposal will begin with a comprehensive literature review to gather existing knowledge and understanding of hydrographic surveying techniques, equipment, and methodologies. This review will encompass both academic research papers and industry reports to gain insights into the current state of the field and identify any gaps or areas that require further investigation.
The research project will then delve into specific applications of hydrographic surveying, such as the use of multibeam sonar for seafloor mapping, the application of LiDAR technology for coastal zone management, the role of hydrographic surveys in the installation and maintenance of underwater infrastructure, and the use of remote sensing techniques for monitoring and assessing coastal erosion and sediment transport.
By conducting thorough research and reviewing relevant literature, this project aims to contribute to the understanding of the applications of hydrographic surveying and highlight its importance in various industries. It will also identify potential areas for further research and advancements in hydrographic surveying technologies and methodologies.
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Which of the following tasks might a civil engineer perform during a project’s construction phase in a design-build approach? (Select all that apply.)
Work with construction management to solve specific problems as they arise.
Draw up the contracts for construction management.
Ensure compliance with safety standards.
Provide information on design changes.
Answers
Answer:
Draw up the contract for construction management.
Answer:
Work with construction management to solve specific problems as they arise.
Ensure compliance with safety standards.
Explanation:
2. (a) (6%) Given 8 numbers stored in an array A = [1, 2, 3, 4, 5, 6, 7, 8], illustrate how the Build Heap procedure rearranges the numbers so that they form a (max-)heap. In particular, show the final heap structure. (b) (4%) Consider the heap you created implements a priority queue. Explain the steps carried out in inserting the number 9 into the structure. In particular, show the final heap structure after the insertion is completed.
Answers
(a) The Build Heap procedure rearranges the numbers so that they form a (max-)heap, here is how to get the final heap structure: Starting from index n/2 down to 0, we can perform the heapify procedure by examining each node and making sure that it is greater than its children.
The nodes that do not satisfy this property will have their values swapped with their larger child and recursively heapify the affected child of the swapped node, to restore the max-heap property. In the array A = [1, 2, 3, 4, 5, 6, 7, 8], the heap will look like this: Heap Image(b) The steps carried out in inserting the number 9 into the structure are as follows:
Inserting 9 into the heap means appending it to the end of the heap and then checking if this insertion will preserve the heap property. 9 may be greater than its parent, so we swap it with its parent until it is no longer greater than its parent. In this case, inserting 9 into the heap gives us the heap shown below. Heap the Image after inserting 9
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What is an example of an innovation in logistics?
Group of answer choices
using drones to deliver retail packages
designing a robot that performs surgery
hiring engineers to teach high school classes
eye-scanning locking devices in everyday homes
Answers
Answer:
geolocation technologies, drones, automated transportation vehicles
Explanation:
Supplemental Question: Conductivities Match each of the conductivity values/ranges with its associated class of materials. 1020 to 10-10 (2-m)1 107 (a-m)1 10-6 to 104 (2-m)1 Semiconductors Metals Insulator
Answers
Semiconductors - 10-6 to 104 (2-m)1, Metals - 107 (a-m)1, Insulator - 1020 to 10-10 (2-m)1.
Conductivity is the measure of a material's ability to conduct electricity.
Different classes of materials have different conductivity ranges. Semiconductors have a range of 10-6 to 104 (2-m)1, metals have a range of 107 (a-m)1, and insulators have a range of 1020 to 10-10 (2-m)1.
Semiconductors, such as silicon, have intermediate conductivity and can be used in electronic devices like transistors. Metals, such as copper, have high conductivity and are used in electrical wiring.
Insulators, such as rubber, have low conductivity and are used to insulate electrical wires and prevent electric shock. Understanding the conductivity of materials is important for designing and manufacturing electronic devices and electrical systems.
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Conductivity values/ranges can be associated with different classes of materials as follows:
1020 to 10-10 (2-m)1: Insulators
Insulators have very low conductivity and high resistivity. They are poor conductors of electricity.
107 (a-m)1: Metals
Metals have high conductivity and low resistivity. They are excellent conductors of electricity.
10-6 to 104 (2-m)1: Semiconductors
Semiconductors have intermediate conductivity between insulators and metals. They can be controlled to exhibit both conducting and non-conducting behavior, making them useful for electronic devices.
Therefore, the correct match is:
1020 to 10-10 (2-m)1: Insulators
107 (a-m)1: Metals
10-6 to 104 (2-m)1: Semiconductors
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The influent BOD5 to a primary settling tank is 345 mg/L. The average flow rate is 0.050 m3/s. If the BOD5 removal efficiency is 30%, how many kilograms of BOD5 are removed in the primary settling tank each day?
Answers
The kilograms of BOD5 that are removed in the primary settling tank each day is 447.12 kg.
How to calculate the value?The BOD5 removed in the primary settling tank each day will be:
= efficiency * influent * average flow rate*24*60*60
The average flow rate is 0.050 m3/s and the BOD5 removal efficiency is 30%,
Influent = 0.345 g/L = 0.000345 kg/L
BOD5 removed in the primary settling tank each day will be:
= 0.3*50*0.000345*24*60*60
= 447.12 kg
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describe an engineering advance that has led to greater knowledge about the solar system
Answers
Answer:
Space Rovers
Explanation:
The engineering advancement of the invention space rovers has changed space exploration tremendously. The first space rover ever to go out onto another planet was made by NASA and put on mars to learn more about the red planet and see if there where any plausible signs of past or maybe even present life. This mission was incredibly successful and for the first time in space exploration history, there was a spacecraft that you could move around that could with do the conditions of the planet for weeks, months, sometimes years at a time, moving around taking pictures and constantly collecting data. This was revolutionary for scientists, this way they could get copious amounts of information just on rover and not having to send multiple crafts only to die in the first few hours but sending back a relative amount of information. With rovers you can have them collect samples and bring the back to earth, not something that could’ve been done without a human, until rovers. They have completely changed and improved collecting data from other planets and have been one of the most revolutionary inventions when it comes to space exploration.
This is what I put for the answer, hope it helps in some way.
Which of following are coding languages used in controlling a robot? *
A. Scratch
B. B/B--
C. C/C++
D. Robot Z
Answers
Answer:
C/C++
Explanation:
C/C++
Which of the following ion is the largest in size?a K+ b Ca2+ c Cl- d S2-
Answers
The ionic radius of Ca²⁺ is 100 pm, K⁺ is 138 pm, Cl⁻ is 181 pm, and S²⁻ is 184 pm, therefore option d is the right choice.
The influence of an ion's nucleus on its electron cloud extends outward to a distance called the ionic radius.
When an atom loses or gains an electron, an ion is created. A cation is formed when an atom loses an electron, and an anion is formed when an atom gains an electron. The ionic radius is the furthest point away from the ion's nucleus that its outermost shell can extend.
A cation's atomic size will be lower than that of its parent atom. Compared to its parent atom, an anion is comparatively large. That's because the net effective nuclear charge gets drowned out by the repulsion between electrons caused by an atom gaining electrons.
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What is the primary tool material used for CNC turning?
Answers
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Consider the function with three inputs given in figure below. Draw a circuit for using a 4×1 multiplexer and one NOT gate.
A B C | F
0 0 0 1
0 0 1 1
0 1 0 0
0 1 1 1
1 0 0 0
1 0 1 0
1 1 0 1
1 1 1 0
Answers
A circuit using a 4×1 multiplexer and one NOT gate can be designed to implement the given function with three inputs.
How can a 4×1 multiplexer and a NOT gate be used to implement the given function?To implement the given function using a 4×1 multiplexer and a NOT gate, we can use the three inputs A, B, and C as the select lines of the multiplexer and connect the function's output F to one of the inputs of the multiplexer. The remaining input of the multiplexer is connected to the output of the NOT gate, which takes the complement of the output F.
The select lines A, B, and C control which input of the multiplexer is connected to its output. By setting the select lines according to the truth table of the given function, we can route the correct input to the output of the multiplexer.
The output of the multiplexer is then fed into the NOT gate, which complements the output to produce the desired result.
multiplexers and logic gates to understand how they can be used to implement various logic functions.
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Consider the flow of mercury (a liquid metal) in a tube. How will the hydrodynamic and thermal entry lengths compare if the flow is laminar
Answers
Answer:
Explanation:
Considering the flow of mercury in a tube:
When it comes to laminar flow of mercury, the thermal entry length is quite smaller than the hydrodynamic entry length.
Also, the hydrodynamic and thermal entry lengths which is given as DLhRe05.0= for the case of laminar flow. It should be noted however, that Pr << 1 for liquid metals, and thus making the thermal entry length is smaller than the hydrodynamic entry length in laminar flow, like I'd stated in the previous paragraph