2) Find the 10th term of the Harmonic progression,

1/2,1/4,1/6............. 10th term
​

Answer:

1000000

Step-by-step explanation:

(10^5)/(10^-1) = 10^ 5-(-1) = 10^6 = 1000000

Answer:

Clarice is right because you can flip the triangle and it makes a different shape every single time.

Step-by-step explanation:

Hope i helped.

A brainliest is always apprciated.

A. The acceleration due to gravity is represented by a negative number because it acts in the opposite direction of the upward motion of the projectile. It pulls the object downward, causing it to decelerate and eventually fall back to the ground.

B. The formula to represent the height of a projectile at any given time t is: h = (0.5 * a * t^2) + (v * t) + h0, where h is the height, a is the acceleration (-32 ft/s^2), t is the time, v is the initial velocity, and h0 is the initial height.

C. To find the time when the projectile is at a height of 320 feet, we can set h = 320 in the formula and solve for t. 320 = (0.5 * -32 * t^2) + (192 * t) + 0. Solve the quadratic equation to find the value of t.

D. To find the time it takes for the object to reach its maximum height, we need to find the time when the velocity becomes zero. Set v = 0 in the formula and solve for t. Then substitute the value of t into the formula to find the maximum height.

E. To find the time when the projectile lands on the ground, we need to find the time when the height becomes zero. Set h = 0 in the formula and solve for t.

F. If the initial velocity stays the same but the height the projectile is launched from changes, the amount of time it takes for the projectile to reach its maximum height will remain the same. However, the maximum height will change based on the initial height.

G. To increase the amount of time it takes for the projectile to return to the ground by one second, we need to find the height that corresponds to that additional time. Set the time to (t + 1) in the formula and solve for h. Subtract the initial height from the result to find the height above the ground from which the projectile needs to be launched.

Comment if you need more help!

~~~Harsha~~~

Answer:

1/5=0 more

.02=0 more

3/8= 1/2 less

2/3= 1/2 more

4/5= 1 less

0.9= 1 less

4/3= 1 more

Step-by-step explanation:

The angle x in the diagram is 98 degrees.

When parallel lines are cut by a transversal line, angle relationships are formed such as corresponding angles, alternate interior angle, alternate exterior angles, vertically opposite angles, same side interior angles etc.

Therefore, let's find the angle of x using the angle relationships as follows:

The size of the angle x can be found as follows:

82 + x = 180(same side interior angles)

Same side interior angles are supplementary.

Hence,

82 + x = 180

x = 180 - 82

x = 98 degrees

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Answer:

1/17 0r 6%

Step-by-step explanation:

the answer is rounded up for you

Answer:

10

Step-by-step explanation:

46 - [(9 + 15 ÷ 5) × 3]

~We can simplify everythingusing PEMDAS

46 - [(9 + 3) × 3]

46 - [(12) × 3]

46 - 36

10

Best of Luck!

Answer:

46−[(9+15÷5)×3] = 10

Step-by-step explanation:

46-[(9+3)×3]

46-[12×3]

46-36

10

The study conducted by the researcher suffers from several limitations, including the absence of a control group, small sample size, participant bias, and experimenter bias. Furthermore, the sample selection is inadequate, as all the participants are students of one course in a single university.

Moreover, the study fails to account for extraneous variables that might affect the results. Therefore,  that textbooks are not necessary or helpful for learning is premature and cannot be generalized to other courses or universities. T he study is flawed, and more research is needed to assess the effect of textbooks on learning.

The study conducted by the researcher suffers from several limitations. First, there is no control group, which makes it difficult to determine whether the results are due to the absence or presence of the textbook. Second, the sample size is small, which reduces the generalizability of the findings.

Third, there is participant bias, as some students might have bought the textbook even though it was optional, while others might not have bought it even though it was required. Fourth, there is experimenter bias, as the professor who scored the essays knew which section had the textbook and which did not.

Fifth, the sample selection is inadequate, as all the participants are students of one course in a single university. Moreover, the study fails to account for extraneous variables that might affect the results, such as the students' prior knowledge, motivation, and study habits.

Therefore, the  textbooks are not necessary or helpful for learning is premature and cannot be generalized to other courses or universities. The study is flawed, and more research is needed to assess the effect of textbooks on learning.

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Using the  EV/EBITDA multiple method the value of the perpetual method is = $593,555. Option C is correct.

The formula for the terminal value is given as EV/EBITDA multiple * EBITDAn

Then we would have Terminal Value = 8.5*69,830

This would then give us Terminal Value = $593,555

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The length of arc EG is approximately 7.35 units.

To find the length of arc EG, we need to use the formula:

length of arc = (central angle/360°) × 2πr

where r is the radius of the circle and the central angle is in degrees.

We are given that m∠EFG = 58°, and EF = 6 units. Since EF is a chord of the circle, we can use the chord-chord angle theorem to find that m∠EGF = ½(180° - 58°) = 61°.

Now, we can use the Law of Cosines to find the length of GE:

GE² = EF² + FG² - 2(EF)(FG)cos(∠EGF)

GE² = 6² + FG² - 2(6)(FG)cos(61°)

Since FG = 2r (because it is the diameter of the circle),

GE² = 36 + (2r)² - 12r cos(61°)

We can simplify this to:

GE² = 4r² - 12r cos(61°) + 36

GE² = 4(r² - 3r cos(61°) + 9)

Now, we can use the formula for the length of the arc:

length of arc EG = (m∠EGF/360°) × 2πr

length of arc EG = (61/360) × 2πr

length of arc EG = (61/180) × πr

Substituting the expression for GE² in terms of r, we get:

length of arc EG = (61/180) × π √[4(r² - 3r cos(61°) + 9)]

We can now use a calculator to find the approximate value of the length of arc EG.

Rounded to the nearest hundredth, the length of arc EG is approximately 7.35 units.

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The value of the triple integral is 72π.

To evaluate this triple integral in cylindrical coordinates, we first need to express the region E using cylindrical coordinates.

The cylinder x² + y² = 16 can be expressed in cylindrical coordinates as r² = 16, or r = 4. The planes z = -5 and z = 4 define a region of height 9.

So, the region E can be expressed in cylindrical coordinates as:

4 ≤ r ≤ 4

-5 ≤ z ≤ 4

0 ≤ θ ≤ 2π

The integrand √(x² + y²) can be expressed in cylindrical coordinates as r, so the integral becomes:

∭E√x²+y²dV = ∫0²π ∫4⁴ ∫-5⁴ r dz dr dθ

Note that the limits of integration for r are from 0 to 4, which means we are only integrating over the positive x-axis. Since the integrand is an even function of x and y, we can multiply the result by 2 to get the total volume.

The integral with respect to z is easy to evaluate:

∫₋₅⁴ r dz = r(4 - (-5))

= 9r

So the triple integral becomes:

∭E√x²+y²dV = 2 ∫0^2π ∫4⁴ 9r dr dθ

= 2(9) ∫0^²π 4 dθ

= 72π

Therefore, the value of the triple integral is 72π.

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Answer:

1

Step-by-step explanation:

5x=5

1x=1

x=1

Answer:

A, B, D

Step-by-step explanation:

A: factors of 9= 1, 3, 9/factors of 15= 1, 3, 5, 15. Their largest common one is 3

B: factors of 9= 1, 3, 9/factors of 21= 1, 3, 7, 21. Their largest common factor is 3

C: factors of 12= 1, 2, 3, 4, 6, 12/ factors of 18= 1, 2, 3, 6, 9, 18. Their largest common factor is 6, not 3

D: factors of 15= 1, 3, 5, 15/ factors of 27= 1, 3, 9, 27. Their biggest common factor is 3.

E: factors of 30= 1, 2, 3, 5, 10, 15, 30/ factors of 45= 1, 3, 5, 9, 15, 45. Their largest common factor is 15, not 3.

Answer:

lines that will never touch

Step-by-step explanation:

these are lines that you could keep drawing and they will never cross or touch

Answer:

ABCD has congruent diagonals.

ABCD is a rhombus.

ABCD has four congruent angles

Step-by-step explanation:

The following statements would be considered true

1. The quadrilateral ABCD could have the congruent diagonals as the diagonals are perpendicular

2. ABCD would be treated as the rhombus as it is a  regular quadrilateral

3. ANd, It Have the four congruent angles that means the four angles be 90 degrees

The other statements would be false.

Answer:

A,B,E

Step-by-step explanation:

Edge 2021

The isosceles triangle has three acute angles, meaning that the angles are less than 90°. The sum of three angles of an isosceles triangle is always 180°.

What is the measure of the angle of an isosceles?

Properties of an Isosceles Triangle

The isosceles triangle has three acute angles, meaning that the angles are less than 90°. The sum of three angles of an isosceles triangle is always 180°.

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Using Algebra operation,

the total revenue from ticket sales on that day is $ 3444..

We have given the following information,

timing of museum for entry is 9:00 am to 5:55pm. i.e 8 hours 55 minutes .

price of ticket for a regular admission= $10

price of ticket for a student admission = $6

30 people's admission in every 5 minutes so,

inclusive there are 9×12=108 five-minute intervals, total of tickets were sold = 108× 30

= 3240

let x student and 3x regular tickets were sold on that day.

then, x+3x= 108× 30 –> x= 3240/4 = 810

put x= 7560 in above formula, for regular admission, 3x=3× 81 = 243

So, the total revenue from ticket sales that day was 243×$10 + 810×$6 = $2430 + $4860

= $7290

Hence, total revenue from tickect sales is $7290.

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Step-by-step explanation:

\( \frac{7}{27} \)

it helps you ☺️☺️

Thank you ☺️☺️

Answer:

1. 640   2. $39

Step-by-step explanation:

1. 50 percent = half of the number so $320 is the sale price we just multiply it by 2 = 320 x 2 = 640

2. first, we find 35% of 60 = 21 then we subract it by 60 = 60 - 21 = $39

Have a wonderful day

The molar solubility of Co(OH)2 in a solution buffered at pH = 4.50 is negligible, while in a solution buffered at pH = 11.25, it is approximately 5.41 x 10^-6 M.

To calculate the molar solubility of Co(OH)2 in a buffered solution, we need to consider the effect of pH on the solubility.

(a) Buffered Solution at pH = 4.50:

At pH = 4.50, the solution is acidic. In an acidic solution, Co(OH)2 will undergo hydrolysis and form Co2+ ions according to the following reaction:

Co(OH)2 (s) ⇌ Co2+ (aq) + 2 OH- (aq)

Since the hydroxide ion concentration is determined by the pH of the solution, we can use the following equation to calculate the molar solubility (S) of Co(OH)2:

Ksp = [Co2+][OH-]^2

To determine the molar solubility, we need to find the concentration of OH- ions. Since the solution is buffered at pH = 4.50, we can assume the concentration of OH- ions to be negligible. Therefore, the molar solubility of Co(OH)2 in this buffered solution is considered very low or negligible.

(b) Buffered Solution at pH = 11.25:

At pH = 11.25, the solution is alkaline/basic. In an alkaline solution, the concentration of OH- ions is relatively high. We can assume that the OH- concentration is in excess and will not significantly affect the solubility equilibrium.

Using the same Ksp expression:

Ksp = [Co2+][OH-]^2

Since the concentration of OH- ions is in excess, we can consider it to be constant. Therefore, we can directly calculate the molar solubility of Co(OH)2 using the Ksp value.

Let's denote the molar solubility of Co(OH)2 as x. Then, we have:

Ksp = [Co2+][OH-]^2 = x * (2x)²= 4x³

Given that Ksp = 2.5 x 10^-16, we can solve for x:

4x³ = \(2.5 * 10^{-16\)

x³ = (\(2.5 * 10^{-16\)) / 4

x = \(((2.5 x 10^-16)^{(1/3) }/ 2^{(1/3))}^{(1/3)} / 2^{(1/3)\)

Using a calculator, we find that the molar solubility of Co(OH)2 in this buffered solution at pH = 11.25 is approximately 5.41 x\(10^{-6\) M.

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(a) The equation 1 + x + x² + x³ + ... is an infinite geometric series with a common ratio of x. To find the sum of the series, we can use the formula for the sum of an infinite geometric series: S = a / (1 - r), where a is the first term and r is the common ratio.

In this case, a = 1 and r = x. Plugging these values into the formula, we get S = 1 / (1 - x). Now, we need to find the value of x when the sum of the series equals 4x. Setting the equation 1 / (1 - x) = 4x, we can solve for x. The solution is x = 1/5.

(b) The equation x - (x^(3)/3!) + (x^(5)/5!) - ... represents an alternating series that converges to 0.9x. To find the value of x, we need to solve the equation x - (x^(3)/3!) + (x^(5)/5!) - ... = 0.9x. Since this is a convergent alternating series, we can use the formula for the sum of an infinite alternating series: S = a / (1 + r), where a is the first term and r is the common ratio. In this case, a = x and r = -x^(2)/2!. Plugging these values into the formula, we get S = x / (1 - x^(2)/2!). By setting S equal to 0.9x, we can solve for x. The solution is x = 0.9486.

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If you had $150, but you are spending $2 each day, then the algebraic expression model of this situation is 150-2x

Given,

The total amount you had = $150

The amount you spend in each day = $2

Consider the number of days = x

Then the algebraic expression for this situation is 150-2x

Hence, If you had $150, but you are spending $2 each day, then the algebraic expression model of this situation is 150-2x

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The point on the surface z = 2 + x² + y² at which the tangent plane is parallel to the plane z = 6 is (0,0,2), and parallel to the plane z = 6 + 4x − 12y is (2,-6,42).

Tangent plane is a plane that touches a surface at a point.

Normal vector to a plane is a vector that is perpendicular to the plane.

The normal vector to the tangent plane at any point on the surface is given by the gradient at that point.

To find the point at which the tangent plane of z = 2 + x² + y² is parallel to the given planes, we need to find the gradient of the surface at that point. The gradient of the surface is given by the partial derivatives of the function with respect to x and y.

dz/dx = 2x

dz/dy = 2y

Therefore, the normal vector to the tangent plane at the point (x,y,z) is (2x, 2y, -1).

(a) For the tangent plane to be parallel to the plane z = 6, the normal vectors of the two planes must be parallel.

The normal vector of the plane z = 6 is (0,0,1).

Therefore, we need to find the point (x,y,z) on the surface such that (2x, 2y, -1) is parallel to (0,0,1).

This is only possible if x = y = 0.

Then we plug these values into the equation:

z = 2 + x² + y²

  = 2 + 0 +0

  = 2

Therefore, the point on the surface at which the tangent plane is parallel to the plane z = 6 is (0,0,2).

(b) For the tangent plane to be parallel to the plane z = 6 + 4x − 12y, the normal vectors of the two planes must be parallel.

The normal vector of the plane z = 6 + 4x − 12y is (4,-12,1).

Therefore, we need to find the point (x,y,z) on the surface such that (2x, 2y, -1) is parallel to (4,-12,1).

This is only possible if x = 2 and y = -6.

Then we plug these values into the equation:

z = 2 + x² + y²

  = 2 + 2² + (-6)²

  = 42

Therefore, the point on the surface at which the tangent plane is parallel to the plane z = 6 + 4x − 12y is (2,-6,42).

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The probability that you will not be assigned weekends is 4/49

For given question,

A supervisor assigns you 5 evenings out of 7 possibilities.

so, you will not be assigned 2 evenings out of  7 possibilities.

Let event A:  you will not be assigned on Saturday

event B:  you will not be assigned on Sunday

Using probability formula,

The probability that you will not be assigned on Saturday = 2/7

⇒ P(A) = 2/7

Similarly using probability formula,

the probability that you will not be assigned on Sunday = 2/7

⇒ P(B) = 2/7

We need to find the probability that you will not be assigned weekends.

P(A∩B) will represent the probability that  you will not be assigned on both days (weekends)

P(A ∩ B) = P(A) × P(B)

Substituting values,

⇒ P(A ∩ B) = 2/7 × 2/7

⇒ P(A ∩ B) = 4/49

Therefore, the probability that you will not be assigned weekends is 4/49

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The appropriate simulation applet to calculate an approximate p-value is 0.0077.

The strong evidence that a short delay hinders the memorization process is strong data suggests that a brief delay impairs memorization.

Delay or no delay, answer: the number of words remembered

The mean distance between words remembered with and without delay over time is null, or zero.

Alt: The mean distance in words remembered over the long term (with no delay minus with delay) is higher than 0.

Yes, the majority of the lines do skew to the right. The mean for no delay is 10.55 whereas that for with delay is 8.7.

The mean distance in words remembered is 1.85.

1)0.0077 as the p-value

2)Strong data suggests that a brief delay impairs memorization.

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Answer:

Step-by-step explanation:

In my opinion the three consecutive numbers should be 25 26 and 27

25 + 26 + 27 = 78

Answer:

Step-by-step explanation:

x, x+1, x+2

add the three expressions above to get 3x+3

3x+3=78

3x=75

x=25

25 is the smallest number out of the three

Answer: 1/2

Step-by-step explanation:

There are 8 movies in total.

4 of those movies are romance movies.

The probability of picking a romance movie is the proportion of romance movies to the total number of movies.

= Number of romance movies / Number of total movies

= 4 / 8

= 1 / 2

Answer:

1/2

Step-by-step explanation:

Answer:

0.8969

Step-by-step explanation:

This can be solved using the binomial probability relation :

P(x = x) = nCx * p^x * q^(n-x)

p = 0.9031

Number of trials, n = 12

q = 1 - p =0.0969

x ≥ 10

P(x ≥ 10) = P(x= 10) + p(x = 11) + p(x = 12)

P(x = 10) = 12C10*0.9031^10 * 0.0969^2 = 0.2236

P(x = 11) = 12C11 * 0.9031^11 * 0.0969^1 = 0.3790

P(x = 12) = 12C12*0.9031^12 * 0.0969^0 = 0.2943

P(x ≥ 10) = (0.2236 + 0.3790 + 0.2943)

P(x ≥ 10) = 0.8969

Answer:

what is the particular question?