The balanced equation for the reaction between hydrochloric acid and sodium carbonate is;`2HCl + Na2CO3 → 2NaCl + H2O + CO2`From the equation, 2 moles of NaCl is produced for every 1 mole of CO2.
If 179.2 liters of CO2 is collected at STP, then n = PV/RT = (1.00 atm × 179.2 L)/(0.08206 L atm mol^-1 K^-1 × 273 K) = 7.28 moles of CO2`Since 2 moles of NaCl is produced for every 1 mole of CO2, then 2 moles of NaCl = 1 mole of CO2``1 mole of NaCl = 1/2 mole of CO2.
Therefore, the number of moles of NaCl produced is 7.28 × (1/2) = 3.64 moles of NaCl. Rounding off to the appropriate number of significant figures gives 3.6 moles of NaCl. Option 2 (12.5 moles) is incorrect.Option 3 (32.0 moles) is incorrect.Option 4 (4.0 moles) is incorrect. Option 5 (8.0 moles) is incorrect.
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A penny having a mass of 2.5340 g was dissolved in 20 mL of 8 M HNO3. The resulting solution was transferred to a 100.00-mL volumetric flask and diluted to the mark with water. Then, a sample solution was prepared by transferring 10.00 mL of this solution to a 25.00-mL volumetric flask, adding 2.00 mL of 15 M NH3, and diluting to the mark with water. The concentration of [Cu(NH3)4]2 in the sample solution (determined using a SpectroVis spectrophotometer) is 0.00426 M. a) What is the concentration (in M) of [Cu(NH3)4]2 in the original dissolved penny solution? What is the concentration (in M) Cu2+ in the original dissolved penny solution? b) What is the mass of Cut in the original solution? (Note that this value is also the mass of Cu2+ in the penny since the solution contains all of the dissolved penny) c) What is the percentage by mass of copper in the penny?
(a)The concentration of [Cu(NH₃)₄]²⁻ in the original dissolved penny solution is 0.01065 M. (b)The mass of Cu in the original solution is approximately 0.0169 g. (c)The percentage by mass of copper in the penny is approximately 0.67%.
To solve this problem, we will use the principles of stoichiometry and dilution calculations.
a) First, let's determine the concentration of [Cu(NH₃)₄]² in the original dissolved penny solution.
From the given information, we know that 10.00 mL of the original solution was transferred to a 25.00 mL volumetric flask, and this solution has a concentration of 0.00426 M [Cu(NH₃)₄]²⁻.
Using the dilution equation:
C1V1 = C2V2
Where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume.
C1 = (C2V2) / V1
= (0.00426 M × 25.00 mL) / 10.00 mL
= 0.01065 M
Therefore, the concentration of [[Cu(NH₃)₄]² in the original dissolved penny solution is 0.01065 M.
To find the concentration of Cu²⁺ in the original solution, we need to consider the stoichiometry of the reaction:
[Cu(NH₃)₄]² + 4H₂O ⇄ Cu²⁺ + 4NH₃ + 4OH⁻
The complex [Cu(NH₃)₄]² dissociates in water to form Cu²⁺ ions. Since the complex has a 1:1 stoichiometry with Cu²⁺, the concentration of Cu²⁺ will be the same as the concentration of [Cu(NH₃)₄]²⁻, which is 0.01065 M.
b) To calculate the mass of Cu in the original solution, we need to know the molar mass of Cu.
The molar mass of Cu is approximately 63.55 g/mol.
The number of moles of Cu can be calculated using the formula:
moles of Cu = concentration of Cu × volume of solution
moles of Cu = 0.01065 M × 0.02500 L
= 2.6625 × 10⁻⁴ mol
Finally, we can calculate the mass of Cu:
mass of Cu = moles of Cu × molar mass of Cu
= 2.6625 × 10⁻⁴ mol × 63.55 g/mol
= 0.0169 g
Therefore, the mass of Cu in the original solution is approximately 0.0169 g.
c) To find the mass percentage of copper in the penny, we need to compare the mass of Cu in the penny to the mass of the penny.
Given that the mass of the penny is 2.5340 g:
Percentage by mass of copper = (mass of Cu / mass of penny) × 100
= (0.0169 g / 2.5340 g) × 100
= 0.67%
Therefore, the percentage by mass of copper in the penny is approximately 0.67%.
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Calculate the calories needed from fat each day for a triathlete who requires 4500 calories a day. A) 550-700. B) 750-875. C) 900-1575. D) 1580-1650.
The triathlete needs approximately 1580-1650 calories from fat each day. This calculation is based on a total daily calorie requirement of 4500 calories and a fat intake of 25% of total calories. Option D is Correct.
To calculate the calories needed from fat, we first need to determine the percentage of calories that should come from fat. The American Dietetic Association suggests that athletes' diets should consist of 20-35% fat.
Let's assume a moderate fat intake of 25% for our calculation.
Step 1: Calculate the total calories from fat:
Total Calories = 4500 calories/day
Percentage of Calories from Fat = 25%
Calories from Fat = Total Calories x Percentage of Calories from Fat
Calories from Fat = 4500 calories/day x 0.25
Calories from Fat = 1125 calories/day
Step 2: Convert calories to grams of fat:
Since 1 gram of fat contains 9 calories, we can calculate the grams of fat needed by dividing the calories from fat by 9:
Grams of Fat = Calories from Fat / 9
Grams of Fat = 1125 calories / 9
Grams of Fat ≈ 125 grams
The triathlete needs approximately 1580-1650 calories from fat each day. Remember that individual nutritional needs may vary, and it's always recommended to consult a healthcare professional or registered dietitian for personalized advice. Option D is Correct.
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True or False:
11. The water cycle has no start or end.
12. When water turns into a gas this is called evaporation.
13. The amount of water on the Earth grows by 0% each year.
14. Evaporation can only occur in salt water.
15. More evaporation occurs during the day.
A. True
A. True
A. True
A. True
A. True
B. False
B. False
B. False
B. False
B. False
Answer:
11) True
12) True
13) False
14)False
15) True
Explanation:
Hope this helps!
Have a nice day! :D
Please write the equilibrium constant expression for the following reaction: 3 P(s) + 4 O2 (g) = P₃O₈ (s). Please use brackets, superscripts, and subscripts where appropriate. You may indicate the denominator of the equilibrium expression by using the division symbol, I. Watch out for the phase of each reagent!
The equilibrium constant expression for the reaction 3P(s) + 4O2(g) ⇌ P₃O₈(s) is as follows:
K = [P₃O₈(s)] / ([P(s)]³ [O2(g)]⁴)
The numerator of the expression, [P₃O₈(s)], represents the concentration of P₃O₈ in the solid phase at equilibrium. The denominator consists of the concentrations of P raised to the power of 3 ([P(s)]³) and O2 raised to the power of 4 ([O2(g)]⁴). These exponents reflect the stoichiometric coefficients of the reactants in the balanced equation, indicating their respective contributions to the equilibrium constant.
The equilibrium constant expression provides a quantitative measure of the extent to which the reaction favors the formation of products or reactants at equilibrium.
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Question 2 Multiple Choice Worth 2 points)
(01.01 LC)
Which of the following is a characteristic of science?
O Reproducible by other scientists
The personal opinion of the scientist
Using vanable conditions for each test
O Including only the data that supports a hypothesis
Question 3 Multiple Choice Worth 2 points)
Answer:
Reproducible by other scientists
The personal opinion of the scientist
Using vanable conditions for each test
Explanation:
What does the period number tell about the energy levels occupied by electrons in an atom?
Answer:
Number of energy levels that the element has.
Explanation:
The period number (n) is the outer energy level that is occupied by electrons. The period number that an element is in, is the number of energy levels that the element has.
How many moles of KCIO3 must be reacted according to the following balanced chemical reaction to transfer -34.2kJ of heat? kclo₃(s) → kcl(s) o₂(g) ∆h =-89.4 kJ ________ ________- x ( ________ ) = _______- _______-STARTING AMOUNT
To calculate the amount of \(KCIO_{3}\) that must be reacted to transfer -34.2 kJ of heat, we can use the balanced chemical equation and the given ∆H value: 0.764 moles of \(KCIO_{3}\) must be reacted to transfer -34.2 kJ of heat.
2 \(KCIO_{3}\)(s) → 2 KCl(s) + 3 O2(g) ∆H = -89.4 kJ
We can see from the balanced equation that for every 2 moles of \(KCIO_{3}\) reacted, -89.4 kJ of heat is transferred. To determine the amount of \(KCIO_{3}\) needed to transfer -34.2 kJ of heat, we can set up a proportion:
2 moles \(KCIO_{3}\) / -89.4 kJ = x moles \(KCIO_{3}\) / -34.2 kJ
Solving for x, we get:
x = (2 moles \(KCIO_{3}\) / -89.4 kJ) x (-34.2 kJ) = 0.764 moles \(KCIO_{3}\)
Therefore, 0.764 moles of \(KCIO_{3}\) must be reacted to transfer -34.2 kJ of heat.
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How many electrons are in an Fe2+ ion?
Which of the following reactions is an example of combustion?
CH4 + 2O2 → CO2 + 2H2O
CH4 + CO2 → O2 + 2H2O
CH4 + O2 → CO2 + 2H2
CH4 + 2O2 → CO2 + 2H2O
The reaction A) CH4 + 2O2 → CO2 + 2H2O is an example of combustion.
Combustion is a chemical reaction that occurs between a fuel and an oxidizer, typically oxygen, resulting in the release of energy in the form of heat and light. In this reaction, methane (CH4) combines with oxygen (O2) to form carbon dioxide (CO2) and water (H2O).
The presence of oxygen as an oxidizer and the production of carbon dioxide and water as products are characteristic of combustion reactions.
The reaction releases energy in the form of heat and may also produce a flame. The other given reactions do not involve the complete combustion of methane or the formation of carbon dioxide and water, which are key indicators of a combustion reaction. So A is correct option.
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Compared with a complex atom like neon, a simple atom such as hydrogen has.
Compared with a complex atom like neon, a simple atom such as hydrogen has fewer electrons and a smaller number of protons, neutrons, and electrons. The number of protons, neutrons, and electrons determines an atom's physical properties, including its size, charge, and behavior.
In comparison to complex atoms like neon, simple atoms like hydrogen have fewer electrons and a smaller number of protons, neutrons, and electrons. The electrons revolve around the nucleus of the atom in a shell, which is determined by the number of protons, neutrons, and electrons. Hydrogen, on the other hand, only has one electron, one proton, and no neutrons, while neon has ten electrons, ten protons, and ten neutrons. As a result, hydrogen is much less massive than neon and has a much smaller size, while neon is much heavier and larger. Atoms are the basic building blocks of all matter, and they are made up of protons, neutrons, and electrons. The number of protons, neutrons, and electrons determines an atom's physical properties, including its size, charge, and behavior. A simple atom like hydrogen has fewer electrons and a smaller number of protons, neutrons, and electrons compared to a complex atom like neon.
Hydrogen, for example, has one electron, one proton, and no neutrons, while neon has ten electrons, ten protons, and ten neutrons. Hydrogen is much less massive than neon and has a much smaller size as a result. Hydrogen has only one electron in its outer shell, while neon has eight electrons in its outer shell. As a result, neon is chemically inactive and does not engage in chemical reactions, while hydrogen is highly reactive and engages in chemical reactions with a variety of substances. In comparison to complex atoms like neon, simple atoms like hydrogen have fewer electrons and a smaller number of protons, neutrons, and electrons. As a result, they are less massive and have smaller sizes. Hydrogen is the most abundant element in the universe, and it is commonly found in molecules like water and methane. It is also used in the synthesis of various chemicals and is a vital element in the production of ammonia.
In conclusion, we can state that hydrogen is a much simpler atom than neon, with a significantly smaller number of protons, neutrons, and electrons, as well as fewer electrons in the outer shell. Neon, on the other hand, is a complex atom with a considerably larger number of protons, neutrons, and electrons, as well as a greater number of electrons in the outer shell.
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given the hypothetical reaction: 2 a(g) x b(g) 3 c(g), kp = kc at 250ºc. what is the value of the coefficient x? a) 1 b) 2 c) 3 d) 4 e) not enough information given.
We cannot determine the value of the coefficient because not enough information given.
So, the answer is E
The given reaction is 2 a(g) x b(g) 3 c(g), and it is stated that kp = kc at 250ºC. This means that the equilibrium constant in terms of pressure (kp) is equal to the equilibrium constant in terms of concentration (kc) at the given temperature.
Using the formula for the equilibrium constant, we can write:
Kp = (PC)³ / (PA)² * (PB)²
where PA, PB, and PC are the partial pressures of a, b, and c, respectively. As the value of x is not given, we cannot determine the values of PA, PB, and PC.
Hence, we do not have enough information to calculate the value of the coefficient x.
Therefore, the answer is (E) not enough information given.
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Please help!
A chemical _________________ represents what happens in a chemical
reaction.
A.) Conservation
B.) Product
C.) Equal
D.) Reactant
E.) Equation
F.) Rearranged
Answer:
it is D. Reactant
Explanation:
Answer:
D
Explanation:
A chemical reaction is a process in which one or more substances, also called reactants.
plsss helpp ASAP
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Answer:
Specific heat is defined by the amount of heat needed to raise the temperature of 1 gram of a substance 1 degree Celsius (°C). Water has a high specific heat capacity which we'll refer to as simply "heat capacity", meaning it takes more energy to increase the temperature of water compared to other substances.
Explanation:
Which type of monomer combines and forms nucleic acids?
A. Nucleotide
B. Nitrogenous base
C. Amino acid
D. Monosaccharide
Answer:
A. Nucleotide
Explanation:
Nucleotides are the monomers that make up nucleic acids, such as DNA and RNA.
A cube of iron at 20C is placed in contact with a cube of copper at 60C. Which statement describes the initial flow of heat between the cubes?
Answer:
the iron is more condensed then the copper more electricity
A 26.5 g sample of nitrogen, N2 , has a volume of 50.0 L and a pressure of 640. mmHg . express answer in three sig figsWhat is the temperature of the gas in kelvins?What is the temperature of the gas in degrees Celsius?
To answer this question we have to usethe ideal gas law:
\(PV=nRT\)Where P is the pressure, V is the volume, n is the number of moles, R is the constant of ideal gases (0.082atmL/molK) and T is the temperature (in Kelvin degrees).
The first step is to convert the given mass of N2 to moles using its molecular mass:
\(26.5gN_2\cdot\frac{molN_2}{28gN_2}=0.95molN_2\)And convert the pressure from mmHg to atm (1atm=760mmHg):
\(640mmHg\cdot\frac{1atm}{760mmHg}=0.84atm\)Finally, solve the initial equation for T and replace for the given values:
\(\begin{gathered} T=\frac{PV}{nR} \\ T=\frac{0.84atm\cdot50.0L}{0.95mol\cdot0.082atmL/molK} \\ T=539.15K \end{gathered}\)The temperature of the gas is 539.15K.
Convert this temperature to Celsius by substracting 273.15 to the temperature in Kelvins:
\(T=539.15-273.15=226\)The temperature of the gas is 226°C.
(a) The student made two mistakes in setting up the apparatus.
Identify the two mistakes.
Describe the problem each mistake would cause.
The first mistake that the student made is drawing the start line with ink. So it will run/dissolve in the solvent / split up
The second mistake that the student made is placing the solvent above the spots or start line instead of under them. So they will mix with solvent or wash off paper or color the solvent or dissolve in the solvent.
In the first mistake, there is no clear, visible starting line for the experiment as the ink flows or dissolves in the solvent. This error can lead to confusion and inaccuracy in results as students cannot accurately measure or compare the progress of their experiments.
The second mistake, it mixes or washes away the solvent with the dirt and starts the line, making it difficult or impossible to observe or measure the progress of the experiment. This error can also lead to inaccuracies in results, as students may not be able to accurately measure or compare the progress of their experiments.
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Your friend says, “chemical changes are caused by an input in energy. In physical changes, there is no transfer of energy” is your friend correct? Why or why not?
Answer: Your friend is incorrect.
Explanation: If we have an object or something that isn’t moving, (let’s say a notebook on a desk). If there is change, and the notebook moves, there is acceleration. Force = Mass times acceleration, f = m*a. There has to be a force, first of all. If you touched the notebook and moved it, some of your energy is transferred and now the notebook has kinetic energy. If our system is you and the notebook, the total energy doesn’t change. the energy is transferred, but doesn’t change. Your friend is not correct. Please give brainliest hope this helped!
What is the enthalpy of reaction for the decomposition of calcium carbonate?
CaCO3(s) Right arrow. CaO(s) + CO2(g)
A 2-column table with 6 rows. Column 1 is labeled Compound with entries upper C a upper O solid, Upper C a upper C upper O subscript 3 solid, Upper C subscript 6 upper H subscript 6 gas, Upper C upper O subscript 2 gas, Upper H subscript 2 upper O gas, Upper N upper O subscript 2 gas. Column 2 is labeled Delta H subscript f in kilojoules per molecule with entries negative 157.3, negative 1,207.1, 82.90, negative 393.5, negative 241.82, 33.84.
Answer:
First Blank: 656.3 kJ
Second Blank: Endothermic
Explanation:
Edge 21'
Answer:
1. 656.3
2. endothermic
Explanation:
Water is a polar molecule. What does that mean?
A. It is a molecule with too many protons
B. it is a molecule with identical charges on opposite ends
C. it is a molecule with no charge
D. it is a molecule with opposite charges on opposite ends
Ordered sodium amytal 0.1 gm IM stat Available sodium amytal 200mg/3ml How many mls would you give IM?
To get a dose of 0.1 gm (100 mg), 1.5 ml of sodium amytal solution must be injected intramuscularly (IM).
What is sodium amytal ?We can use the available concentration and the desired dose.
Given
Available sodium amytal concentration: 200 mg/3 mlDesired dose: 0.1 g (which is equivalent to 100 mg)First, we need to convert the desired dose from grams to milligrams:
0.1 g = 100 mg
Now, we can set up a proportion to find the volume of solution needed:
(100 mg) / (200 mg) = (x ml) / (3 ml)
Cross-multiplying and solving for x:
100 mg * 3 ml = 200 mg * x ml
300 mlmg = 200 mlmg
x ml = (300 ml*mg) / (200 ml)
x ml = 1.5 ml
So, To get a dose of 0.1 gm (100 mg), 1.5 ml of sodium amytal solution must be injected intramuscularly (IM).
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What is hydrochloride acid plus water plus salt and water
1.00 l of a gas at standard temperature and pressure is compressed to 473 ml. what is the new pressure of the gas? 2) in a thermonuclear device, the pressure of 0.050 liters of gas within the bomb casing reaches 4.0 x 10 6 atm. when the bomb casing is destroyed by the explosion, the gas is released into the atmosphere where it reaches a pressure of 1.00 atm. what is the volume of the gas after the explosion? 3) synthetic diamonds can be manufactured at pressures of 6.00 x 10 4 atm. if we took 2.00 liters of gas at 1.00 atm and compressed it to a pressure of 6.00 x 10 4 atm, what would the volume of that gas be? 4) the highest pressure ever produced in a laboratory setting was about 2.0 x 10 6 atm. if we have a 1.0 x 10 -5 liter sample of a gas at that pressure, then release the pressure until it is equal to 0.275 atm, what would the new volume of that gas be? 5) atmospheric pressure on the peak of mt. everest can be as low as 150 mm hg, which is why climbers need to bring oxygen tanks for the last part of the climb. if the climbers carry 10.0 liter tanks with an internal gas pressure of 3.04 x 10 4 mm hg, what will be the volume of the gas when it is released from the tanks?
Let's solve each question step by step:
To find the new pressure of the gas after compression, we can use Boyle's Law, which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume:
P1V1 = P2V2
Given:
P1 = 1 atm (standard pressure)
V1 = 1.00 L (initial volume)
V2 = 473 mL = 0.473 L (final volume)
Using the formula, we can rearrange it to solve for P2:
P2 = (P1V1) / V2
P2 = (1 atm * 1.00 L) / 0.473 L
P2 ≈ 2.11 atm
Therefore, the new pressure of the gas after compression is approximately 2.11 atm.
To find the volume of the gas after the explosion, we can use the Combined Gas Law, which relates the initial pressure, volume, and temperature to the final pressure, volume, and temperature:
P1V1 / T1 = P2V2 / T2
Given:
P1 = 4.0 x 10^6 atm (initial pressure)
V1 = 0.050 L (initial volume)
P2 = 1.00 atm (final pressure)
T1 and T2 are not provided, so we assume the temperature remains constant.
Using the formula and rearranging it to solve for V2:
V2 = (P1V1 * T2) / (P2 * T1)
V2 = (4.0 x 10^6 atm * 0.050 L) / (1.00 atm * T1)
Since the temperature remains constant, T2 = T1, and we can simplify the equation:
V2 = (4.0 x 10^6 atm * 0.050 L) / (1.00 atm)
V2 = 2.0 x 10^5 L
Therefore, the volume of the gas after the explosion is 2.0 x 10^5 liters.
To find the volume of the gas when compressed to a pressure of 6.00 x 10^4 atm, we can again use Boyle's Law:
P1V1 = P2V2
Given:
P1 = 1 atm (initial pressure)
V1 = 2.00 L (initial volume)
P2 = 6.00 x 10^4 atm (final pressure)
Rearranging the formula to solve for V2:
V2 = (P1V1) / P2
V2 = (1 atm * 2.00 L) / (6.00 x 10^4 atm)
V2 ≈ 3.33 x 10^-5 L
Therefore, the volume of the gas when compressed to a pressure of 6.00 x 10^4 atm is approximately 3.33 x 10^-5 liters.
To find the new volume of the gas when the pressure is released from 2.0 x 10^6 atm to 0.275 atm, we can again use Boyle's Law:
P1V1 = P2V2
Given:
P1 = 2.0 x 10^6 atm (initial pressure)
P2 = 0.275 atm (final pressure)
V1 = 1.0 x 10^-5 L (initial volume)
Rearranging the formula to solve for V2:
V2 = (P1V1) / P2
V2 = (2.0 x 10^6 atm * 1.
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Which of the following elements has the highest electronegativity?
A.
Boron (B)
B.
Carbon (C)
C.
Oxygen (O)
D.
Nitrogen (N)
Answer:
C. Oxygen
Explanation:
By looking at the periodic table.
As you look from left to right of the periods the electronegativity increases.
As well as from the bottom to the top of the groups it increases.
what is the bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals?
The bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals is 1.5
Bond order is defined as the number of electrons in bonding molecular orbitals minus the number of electrons in antibonding molecular orbitals divided by two. As a result, we may determine the bond order of this diatomic particle by the formula: Bond order = (number of bonding electrons - number of antibonding electrons) / 2
Bond order = (8 - 5) / 2
Bond order = 1.5.
This diatomic molecule, according to the bond order, is a stable molecule since the bond order is greater than 1, indicating that it is a double bond. The molecule has an overall bond strength that is greater than a single bond, but not as strong as a triple bond. So therefore he bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals is 1.5
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Why is baking soda a necessary ingredient in some cake recipes?
A. It adds heat to the cake.
B. It causes cakes to stay flat and even.
C. It neutralizes acids.
D. It acts slowly to release acids.
Answer:
c
Explanation:
took it
how many atoms are present at each of these types of positions in a body-centered cubic unit cell?
The main answer to your question is that in a body-centered cubic (BCC) unit cell, there are two atoms present.
In a BCC unit cell, there is one atom at each corner and one atom in the center of the cell.
There are a total of eight corners in a cubic unit cell.
However, each corner atom is shared by eight adjacent unit cells.
Therefore, only 1/8th of each corner atom belongs to the unit cell in question.
So, for the eight corner atoms, we have a total of 1 atom (8 x 1/8 = 1). Additionally, there is one atom in the center of the cell that is not shared with any other unit cells.
Summary:
In a body-centered cubic unit cell, there are two atoms present: one from the contributions of the corner atoms and one from the center atom.
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how many moles of oxygen gas will be produced if 1.64 moles of sodium chloride was produced
of water can be electrolytically broken down to yield 5 moles or oxygen gas. 1.64x1023 = 1677.72 if 1.64 moles or sodium chloride were produced.
What does a gas mole weigh?A mole (6.021023 typical particles) of the any gas takes up 22.4L at STP (figure below). A comparison of various gases' molar volumes is shown in the image below. At STP, there exist samples containing helium (He), nitrous (N2), or methane (CH4). Each has a mole content of 1 or 6.02 1023 particles.
1.64x1023 = 1677.72
if 1.64 moles or sodium chloride were produced
How is a mole calculated?One mole of the a material is equivalent to 6,022 x 1023 molecules of that substance. The Avogadro number, also referred to as the Avogadro constant, is 6.022 x 1023. The definition of a mole can be used to the conversion between mass and particle count.
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Calculate the number of ions of the following compound :16g of H2CO3
Answer:
1) a) 1.81 × 10²³ molecules (b) 1.93 × 10²³ molecules (c) 0.66× 10²³ molecules
2) a) 0.45× 10²³ions (b) 0.84× 10²³ions (c) 3.6 × 10²³ions
Explanation:
1) Number of molecules:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
a) 16g of H₂CO₃
Number of moles = mass/ molar mass
Number of moles = 16 g/ 62.03 g/mol
Number of moles = 0.3 mol
1 mol = 6.022 × 10²³ molecules
0.3 mol × 6.022 × 10²³ molecules /1 mol
1.81 × 10²³ molecules
b) 20g of HNO₃
Number of moles = mass/ molar mass
Number of moles = 20 g/ 63.01 g/mol
Number of moles = 0.32 mol
1 mol = 6.022 × 10²³ molecules
0.32 mol × 6.022 × 10²³ molecules /1 mol
1.93 × 10²³ molecules
c) 30g of C₆H₁₂O₆
Number of moles = mass/ molar mass
Number of moles = 20 g/ 180.156 g/mol
Number of moles = 0.11 mol
1 mol = 6.022 × 10²³ molecules
0.11 mol × 6.022 × 10²³ molecules /1 mol
0.66× 10²³ molecules
2. Calculate the number of ions in the following compounds:
a) 10g of AlCl₃
Number of moles = mass/ molar mass
Number of moles = 10g/ 133.34 g/mol
Number of moles = 0.075 mol
1 mol = 6.022 × 10²³ ions
0.075 mol × 6.022 × 10²³ ions/1 mol
0.45× 10²³ions
b) 30g of BaCl₂
Number of moles = mass/ molar mass
Number of moles = 30g/ 208.23 g/mol
Number of moles = 0.14 mol
1 mol = 6.022 × 10²³ ions
0.14 mol × 6.022 × 10²³ ions/1 mol
0.84× 10²³ions
c) 58 g of H2SO4
Number of moles = mass/ molar mass
Number of moles = 58g/ 98.079 g/mol
Number of moles = 0.59 mol
1 mol = 6.022 × 10²³ ions
0.59 mol × 6.022 × 10²³ ions/1 mol
3.6 × 10²³ions
Explanation:
what is hydrophytes?