2. Identify What are three ways a rock can change during metamorphism?

The modulus of elasticity, E, is a measure of a material's stiffness and ability to resist deformation when a force is applied. It is defined as the ratio of stress to strain within the elastic range of the material. In other words, it describes how much a material will stretch or compress under a given force.

The modulus of elasticity is important because it allows engineers to predict how materials will behave under different conditions, such as temperature changes, loading conditions, and other factors. It also helps to determine the maximum load a material can withstand before it starts to deform or break.

In detail, the modulus of elasticity is a fundamental property of a material that describes its ability to resist deformation when subjected to external forces. It is calculated by measuring the stress and strain of the material and using the equation E = σ/ε, where σ is stress and ε is strain.

The modulus of elasticity is important in many areas of engineering, such as structural design, materials science, and mechanics. It helps to ensure that structures and materials are designed and tested to withstand the loads and stresses they will be subjected to, and it provides a basis for comparing different materials and choosing the best one for a particular application.

In summary, the modulus of elasticity, E, is a material property that describes its stiffness and resistance to deformation. It is correctly determined using Hooke's Law and is crucial for predicting the mechanical behavior of materials when subjected to stress.

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When the object is 12.5 cm in front of the converging lens with a power of 4.00 diopters, the image distance is 25.0 cm and the image is inverted. The ray diagram that best represents this scenario is [Insert Ray Diagram 1].

1. Given that the object height is 10.0 cm and the lens has a power of 4.00 diopters, we can use the lens formula to find the image distance. The lens formula is given by 1/f = 1/v - 1/u, where f is the focal length of the lens, v is the image distance, and u is the object distance.

2. Since the power of the lens is 4.00 diopters, which is equal to 1/f in meters, we can calculate the focal length as f = 1/4.00 = 0.25 meters.

3. The object distance is given as 12.5 cm = 0.125 meters.

4. Substituting the values into the lens formula, we have 1/0.25 = 1/v - 1/0.125.

5. Solving the equation, we find that 1/v = 4 - 8 = -4, which means 1/v = -4. Taking the reciprocal of both sides gives v = -1/4 = -0.25 meters.

6. The negative sign indicates that the image is formed on the same side as the object, which means it is a virtual image.

7. The magnification can be calculated using the formula M = -v/u, where M is the magnification, v is the image distance, and u is the object distance. Plugging in the values, we have M = -(-0.25)/0.125 = 2.

8. Since the magnification is positive, the image is upright.

9. Therefore, when the object is 12.5 cm in front of the lens, the image distance is 25.0 cm and the image is inverted.

10. Similarly, we can perform the above calculations for the object distances of 25.0 cm and 50.0 cm to find the corresponding image distances and characteristics.

11. When the object is 25.0 cm in front of the lens, the image distance is 25.0 cm and the image is of the same size as the object. The ray diagram that best represents this scenario is [Insert Ray Diagram 2].

12. When the object is 50.0 cm in front of the lens, the image distance is 50.0 cm and the image is magnified. The ray diagram that best represents this scenario is [Insert Ray Diagram 3].

13. In each case, the magnification can be calculated using the formula M = -v/u, and the characteristics of the image (inverted or upright) can be determined based on the sign of the magnification.

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Answer:

______________________________

use tall safety and position hoist arms

i need the same question

The maximum distance the spring of spring constant k = 1960 N/m is compressed when a block of mass m = 2.0 kg is dropped from height h = 40 cm onto a spring is 6.32 cm.

To find the maximum distance the spring is compressed, we use the conservation of energy principle.Conservation of Energy Principle;The principle of conservation of energy states that energy cannot be created or destroyed; it can only be transformed from one form to another. So, the total energy before the block is dropped is equal to the total energy after the block is dropped.The total energy before the block is dropped is given by:

PE1 + KE1 where PE1 is the potential energy and KE1 is the kinetic energy.The total energy after the block is dropped is given by:PE2 + KE2 + Uwhere PE2 is the potential energy, KE2 is the kinetic energy, and U is the potential energy stored in the spring. The maximum distance the spring is compressed is the distance when the block comes to rest, so KE2 = 0.From the principle of conservation of energy, we have:

PE1 + KE1 = PE2 + U.Since the block is dropped from rest, KE1 = 0, and PE1 is given by: mgh where g is the acceleration due to gravity.Substituting the given values, we have: PE1 = mgh = 2.0 kg × 9.8 m/s² × 0.4 m = 7.84 J.At the maximum compression, the potential energy stored in the spring is equal to the potential energy lost by the block, so:U = PE1 - PE2.

Substituting the values, we have:U = 7.84 J - 0 = 7.84 J.Since the potential energy stored in a spring is given by:U = 1/2 k x²where x is the compression distance of the spring.Substituting the values, we have:7.84 J = 1/2 × 1960 N/m × x²x² = 7.84 J / (1/2 × 1960 N/m)x² = 0.004 m²x = √(0.004 m²) = 0.0632 m = 6.32 cm.Therefore, the maximum distance the spring is compressed is 6.32 cm.

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The time taken for temperature to fall from  45°C to 35°C is 6.21 minutes when a liquid cools from 65°C to 55°C in 5 mins.

We can utilize Newton's Law of Cooling to tackle this issue. It expresses that the pace of progress of temperature of an article is corresponding to the distinction in temperature between the item and its environmental elements.

Utilizing this regulation, we can compose:

(dT/dt) = - k(T - Ts)

where dT/dt is the pace of progress of temperature, k is the cooling steady, T is the temperature of the fluid, and Ts is the temperature of the environmental elements.

To begin with, how about we track down the cooling steady. From the given data, we know that the fluid cools from 65°C to 55°C in 5 mins. Subsequently, we can compose:

-10 = - k(65 - 35)

k = 0.5

Presently, we can utilize this worth of k to make the opportunity taken for temperature to decrease from 45°C to 35°C. We want to tackle:

(dT/dt) = - 0.5(T - 35)

with introductory condition T(0) = 45.

Isolating factors and coordinating the two sides, we get:

ln|T - 35| = - 0.5t + C

Utilizing the underlying condition T(0) = 45, we get:

ln|10| = C

C = 2.303

Subbing this worth of C, we get:

ln|T - 35| = - 0.5t + 2.303

Taking dramatic on the two sides, we get:

|T - 35| = e^(- 0.5t+2.303)

Settling for T = 35°C, we get:

t = 6.21 minutes.

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The complete question is:

A liquid cools from 65°C to 55°C in 5 mins. If the surrounding temperature is 35℃, calculate the time taken for temperature to fall from 45°C to 35°C.

Answer:

chargeing by induction

Explanation:

this is the answer have a great day

The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.

The freezing point is the temperature at which the substance changes its phase from liquid to solid.

The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.

The requried combined length of the trains are 1.8 kilometers.

Velocity is defined as the rate of change in the position of an object with respect to time.

Here,

Let's first convert the speeds from km/h to m/s to make our calculations easier,

The first train travels at 108 km/h = 30 m/s.

The second train travels at 72 km/h = 20 m/s.

Now, we can calculate the relative speed of the trains:

The relative speed between the two trains is 30 m/s - 20 m/s = 10 m/s.

We know that the first train overtakes the second train in 60 seconds. During this time, the first train will cover a distance equal to the combined length of both trains.

Let's denote the length of the first train as L₁ and the length of the second train as L₂. Then, we can write,

Distance covered by the first train in 60 seconds = L₁

Distance covered by the second train in 60 seconds = L₂ + L₁ (because the second train is L₂ behind the first train when it is overtaken)

The speed of the first train is 30 m/s, so its distance covered in 60 seconds is:

Distance covered by the first train in 60 seconds = 30 m/s x 60 s = 1800 m

Similarly, the speed of the second train is 20 m/s, so its distance covered in 60 seconds is,

Distance covered by the second train in 60 seconds = 20 m/s x 60 s = 1200 m

L₁ = 1800 m - 1200 m = 600 m

L₁ + L₂ = 1800 m

So the combined length of both trains is:,
L₁ + L₂ = 1800 m

L₁ + L₂ = 1.8 km

Therefore, the combined length of both trains is 1.8 km.

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Answer:

Explanation: I know that people'strength vary on what they can lift.

Answer:

81.6 m

Explanation:

Answer: 81.6 m.

The time it takes gravity to slow 40 m/s to zero when it teaches maximum height is

-v(initial) / -g = t

-40 m/s / -9.8 m/s^2 = 4.08 s

The height reached is the average velocity times this time 4.08 s, with v(avg) = [v(initial) + v(final)] / 2 with v(final) = 0. v(avg) = v(initial) / 2 = 40 m/s / 2 = 20 m/s.

So the distance d of maximum height is

d = v(avg)•t

d = 20 m/s • 4.08 s = 81.6 m.

Answer:

80m

Explanation:

time taken for stone to reach max-height is t=final velocity - intial velocity / acceleration due to gravity

t=v-u/g

where:

v=0 , u=40m/s ,g=-10m/so

: t=0-40/-10

t=4secs

: max-height reach=ut + 0.5gt²

=(40)(4)+(0.5)(-10)(4)I

=160-5(16)

=160-80

=80m

Answer:

distance and length are the same quantity

(a) the constants in the hall-petch equation for this case is 18.48MPa*mm^(0.5)

(b)347.39 MPa.

Hall-Petch equation provides direct relations between the strength of the material and the grain size:

σ=σ0+k/√d , where d- grain size, σ- strength for the given gran size, σ0 and k are the equation constants.

As in this problem, we don't know the constants of the equation, but we know two properties of the material, we are able to find them from the system of equations:

σ1=σ0+k/√d1

σ2=σ0+k/√d2 , where 1 and 2 represent 150MPa and 250MPa strength of the steel.

Note, that for the given problem, there is no need to convert units to SI, as constants can have any units, which are convenient for us.

From the system of equations calculations, we can find constant: σ0=55.196 MPa, k=18.48 MPa*mm^(0.5)

Now we are able to calculate strength for the grain diameter of 0.004 mm:

σ=55.196+18.48/(√0.004)=347.39 MPa

The strength of the steel with the grais size of 0.004 mm is 347.39 MPa.

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The region of very bright colors embedded within a hook echo on a radar screen indicating damage being produced by a tornado is called a debris ball.

A debris ball is a signature on Doppler radar screens that is produced when a tornado is picking up debris and causing damage. The debris is picked up by the tornado and carried aloft, where it is then detected by the radar and appears as a distinct, bright region within the hook echo. The presence of a debris ball on a radar screen is a strong indication that a tornado is on the ground and causing damage. This information is useful for meteorologists and emergency responders, who can use it to issue warnings and alert the public to take appropriate safety measures.

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Answer:

Push or pull

Explanation:

To calculate the delta-V needed to insert the space object into a captured elliptical orbit, we can use the vis-viva equation:

\(v^2 = GM(2/r - 1/a)\)

where v is the velocity of the space object, G is the gravitational constant, M is the mass of the Earth, r is the distance between the center of the Earth and the object, and a is the semi-major axis of the elliptical orbit.

At the altitude of 37,000 km, the distance from the center of the Earth is r = 37,000 km + the radius of the Earth (6,371 km) = 43,371 km.

The speed of the space object is 8 km/s, so its kinetic energy per unit mass is (1/2) \(* (8 km/s)^2\) = 32 km\(^2/s^2\).

specific energy of the elliptical orbit is given by:

E = -GM/2a

where E is the specific energy, G is the gravitational constant, M is the mass of the Earth, and a is the semi-major axis of the elliptical orbit.

The maximum apogee of the elliptical orbit is given as the mean lunar radius (384,400 km), so the semi-major axis is:

a = (r + apogee)/2 = (43,371 km + 384,400 km)/2 = 213,885.5 km

Using the flight-path angle, we can find the velocity component in the direction of motion (v_parallel) and the velocity component perpendicular to the direction of motion (v_perp):

At perigee, the distance between the center of the Earth and the object is equal to the radius of the Earth (6,371 km). We can find the velocity of the object at perigee by using the law of conservation of energy:

\(v_perigee^2 = v^2 + 2GM(1/r - 1/2a) - 2E\)

where v is the velocity of the object at the sighting altitude, r is the distance from the center of the Earth to the object at perigee (6,371 km), a is the semi-major axis of the elliptical orbit (213,885.5 km), and E is the specific energy of the elliptical orbit.

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A hair dryer provides about 10 ohms of resistance. When plugged into a typical outlet in Georgia, and then turned on, 1440 W is its power. Therefore, the correct option is option D.

The quantity of energy moved or transformed per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power inside the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.

Power is correlated with other factors; for instance, the power required to move a land vehicle is indeed the sum of the traction force just on wheels and aerodynamic drag.

power = voltage²×resistance

           =(120)²× 10

           =1440 W

Therefore, the correct option is option D.

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Answer:

Work done  on the two cart system is 2 N-m

Explanation:

Work done is equal to the product of force and displacement

Work done =4N * (0.17 +0.33)

work done = 4N * 0.5

Work done = 2 N -m

Work done  on the two cart system is 2 N-m

The youngest is Calliope.

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Answer:jeff gordon is a boss

Explanation: i am so cool thats how i know its correct

Answer:

Explanation:

Time taken by jogger to travel the distance to finishing line = 2.1 / 7.3

= .28767 hr

Bird will keep flying for this time period

distance covered by bird = speed x time

= 29.2 x .28767 km

= 8.4 km .

The first two exercises are of the uniform rectilinear movement (MRU) is a type of movement that is characterized by a constant speed and a rectilinear trajectory. In other words, an object moving with MRU always moves at the same speed and in a straight line.

The formula to calculate the speed in the MRU is simple: v = d/t, where:

v is the speed

d is the distance traveled

t is the elapsed time

It is also possible to use the formula s = vt to calculate the distance traveled, where s is the distance and t is the time.

It is important to note that velocity in the MRU is a vector that has a magnitude (the velocity itself) and a direction (the direction of motion). In the MRU, the direction of movement is always constant and coincides with the direction of the trajectory.

First we get the data:

V = Velocity = 25 m/s

T = time = ?

D = distance = 350 m

We already know that the MRU formula is V = d/t. But we must calculate the time, we clear the time, then:

t = d/v

We continue, substitute data and solve for time, then

t = d/v

t = (350 m)/(25 m/s)

t = 14 m

To travel 350 meters, it takes me 14 minutes.

To solve this, we first get the data:

V = speed = ?

D = distance = 50 m

T = time = 15 s

We know that the MRU formula is V = d/t. It is also the same formula for calculating velocity.

How should we calculate speed? It is not necessary to clear the formula, we substitute data and solve, then

V = d/t

V = (50 m)/(15 s)

V = 3.33 m/s

If I ride a bicycle 50 meters in 15 seconds, my speed is 3.33 meters per second (m/s).

As for the third exercise, it is an exercise of a rectilinear motion uniformly accelerated (MRUA), since Lance's speed increases constantly in time. A rectilinear motion uniformly accelerated (MRUA) is a type of motion in which an object moves in a straight line and its velocity changes uniformly in time due to constant acceleration. In this type of movement, the acceleration is constant, which means that the speed increases or decreases at a constant rate in each unit of time.

The MRUA is a fundamental concept in physics and is used to describe many phenomena, from free-falling objects to moving vehicles. Uniformly accelerated rectilinear motion is described mathematically by a series of equations, relating position, velocity, acceleration, and time.

One of the most important equations in the MRUA is the velocity equation, which relates the final velocity (Vf), the initial velocity (Vi), the acceleration (a) and the time (t). The velocity equation can be expressed as:

This equation shows how the final velocity of an object in an MRUA depends on its initial velocity, acceleration, and elapsed time.

Another important equation in the MRUA is the position equation, which relates the final position (x), the initial position (x0), the initial velocity (Vi), the acceleration (a) and the time (t).

The position equation can be expressed as:

This equation shows how the position of an object in an MRUA changes as a function of time, initial velocity, acceleration, and initial position.

First we get the data, this is the first step to start solving:

Vf = Final speed = 12 m/s

Vo = Initial velocity = 2 m/s

t = time = 12 s

a = acceleration = ?

The velocity equation can be expressed as:

Vf = Vi + a * t.

We use this formula to clear the formula to calculate the acceleration,

We continue solving, now we substitute our data and solve:

a = (Vf - Vo)/t

a = (30 m/s - 2 m/s)/(12 s)

a = 2.33 m/s²

Its acceleration is 2.33 meters per second squared (m/s²).

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Answer: Which of these statements is most likely correct about the stars?

Star 2 attracts Star 1 with a greater gravitational force than Star 1 attracts Star 2.

No, because Third Newton Law states that both forces are equal in magnitude.

Earth exerts almost equal gravitation force on both the stars.

No, because the Universal Gravitational Law, estblished by Newton, states the atraction force to two masses is proportional to the product of the masses.

Star 1 attracts Star 2 with a greater gravitational force than Star 2 attracts Star 1.

No (same reason for the first statement)

Earth exerts greater gravitation force on Star 2 than on Star 1.

Right. This is the correct statement. Given the mass of Star 2 is greater than the mass of Star 1, by the Universal Gravitational Law, the earth exerts greater gravitational attraction on Star 2.

Explanation:

:)

Answer:

i. Cv =3R/2

ii. Cp = 5R/2

Explanation:

i. Cv = Molar heat capacity at constant volume

Since the internal energy of the ideal monoatomic gas is U = 3/2RT and Cv = dU/dT

Differentiating U with respect to T, we have

= d(3/2RT)/dT

= 3R/2

ii. Cp - Molar heat capacity at constant pressure

Cp = Cv + R

substituting Cv into the equation, we have

Cp = 3R/2 + R

taking L.C.M

Cp = (3R + 2R)/2

Cp = 5R/2

Answer:

both

Explanation:

because science is not included in both of them

The correct option is 4.

The process by which the isotope 56Fe decays into the isotope 56Co is beta decay.

The correct option is 4.What is beta decay? Beta decay is a type of radioactive decay in which a beta particle, a positron, or an electron is emitted by the nucleus of an atom. Beta decay is a decay process in which the atomic nucleus emits beta particles, which are high-energy, high-speed electrons or positrons.

In beta decay, a neutron in the nucleus transforms into a proton, causing the emission of an electron and a neutrino in the process. The isotope 56Fe decays into the isotope 56Co by the following beta decay process:56Fe26 → 56Co27 + β−where β- is a beta particle, and it is emitted from the nucleus, resulting in an increase in atomic number Z by one, while atomic mass number A remains unchanged. The daughter isotope is 56Co.

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Answer:

9.8 meters per square second

Explanation:

Free Falling Object. the value of g is 9.8 meters per square second on the surface of the earth. The gravitational acceleration g decreases with the square of the distance from the center of the earth. But for many practical problems, we can assume this factor to be a constant.

The grade is also the tangent of the angle above horizontal.

The angle whose tangent is 0.317 is called the "arctangent" of 0.317

It's 17.6 degrees.

Through -212 V potential difference must the electron pass to accomplish this

The difference in electric potential between two points, which is defined as the effort required per unit of charge to move a test charge between the two places, is known as voltage, electric potential difference, electric pressure, or electric tension.

The initial kinetic energy of the electron is,

\({K_i} = \frac{1}{2}mv_i^2\)

Here, m is the mass of the electron and

is the initial velocity of the electron.

\(\begin{array}{c}\\{K_i} = \frac{1}{2}\left( {9.11 \times {{10}^{ - 31}}\;{\rm{kg}}} \right){\left( {2.5 \times {{10}^6}\;{\rm{m/s}}} \right)^2}\\\\ = 2.88 \times {10^{ - 18}}\;{\rm{kg}}\\\end{array}\)

The final kinetic energy of the electron is,

\(\begin{array}{c}\\{K_f} = \frac{1}{2}\left( {9.11 \times {{10}^{ - 31}}\;{\rm{kg}}} \right){\left( {9 \times {{10}^6}\;{\rm{m/s}}} \right)^2}\\\\ = 3.68 \times {10^{ - 17}}\;{\rm{kg}}\\\end{array}\)

\(\begin{array}{c}\\{V_1} - {V_2} = \frac{{3.68 \times {{10}^{ - 17}}\;{\rm{J}} - 2.88 \times {{10}^{ - 18}}\;{\rm{J}}}}{{ - 1.6 \times {{10}^{ - 19}}\;{\rm{C}}}}\\\\ = - 212\;{\rm{V}}\\\end{array}\)

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