20 pts for free ig I'd just need an awnser ​

Answer:

y=25,000(0.07)^t

Step-by-step explanation: t= year/month. not specified, but year is most appropriate for these kind of equations.

Regardless of the type of triangle, all triangles have internal angles that sum up to 180°. An isosceles triangle will have two equal-sized angles.

The hypotenuse, or side across from the right angle, has a square whose length is equal to the sum of the squares of the other two sides in a right triangle, according to the Pythagorean theorem. In other words, if the hypotenuse's length is c and the lengths of the other two sides are a and b, then c2 = a2 + b2.

Whatever the type of triangle, all triangles have internal angles which sum to 180°. The two angles of an isosceles triangle will be equal in size. Every angle of an equilateral triangle is 60 degrees. The other two angles in a right-angled triangle will add up to 90° because the triangle has one angle that is 90°.

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Answer:

f(x) = - 2x + 4

Step-by-step explanation:

Since we are only trying to move the graph up 3 units, the slope does not change. So, it would be -2.

We also know that the 1 in f(x)= -2x + 1 is the y-intercept (y=mx+b). But again, we are moving the graph 3 units up, so we have to add 3. That makes it 4 (3+1=4).

So, the new equation would be f(x) = -2x + 4

Step-by-step explanation:

it simply means that g(x) is f(x) just shifted 3 units upwards.

that means nothing else changes, only whatever y result f(x) produces is increased by 3.

so,

g(x) = f(x) + 3 = -2x + 1 + 3 = -2x + 4

therefore, as domain and range were the whole set of real numbers, the addition of 3 does not make any difference in relation to infinity. so, they remain unchanged.

the slope stays the same (g(x) is simply a parallel line to f(x)).

the y-intercept (the y-value when x = 0) also increases by 3, and is 4.

the x-intercept (the x-value when y = 0) changes :

0 = -2x + 4

2x = 4

x = 2

the x-intercept is 2.

Answer:

1/2m+100

Step-by-step explanation:

The solution of the given expression will be 9/16.

Expressions in maths are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.

Given an expression, [-3*(10+(-7))]²÷[(3-(-9)]²

= [-3*(10+(-7))]²÷[(3-(-9)]² = (-9)²/12²

= 9/16

Hence, The solution of the given expression will be 9/16.

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The measure of the arc depends on the outside angle formed by the two

tangents, such that the given equations can be equated to find x.

Response:

The given parameters are;

m∠JKL = 8·x - 6

\(m\widehat{JML}\) = 25·x - 13

We have that the external angle formed by two tangents, ∠JKL , is given

by the far arc, near arc theorem or the secant, tangent outside angle

theorem as follows, as follows;

\(\widehat{JML} - \widehat{JL}\) = 2 × \(\mathbf{\angle {JKL}}\)

\(\widehat{JML} + \widehat{JL}\) = 360°

\(\widehat{JML} - \widehat{JL}\)  + \(\widehat{JML} + \widehat{JL}\)  = 2 × \(\mathbf{\widehat{JML}}\)

\(\widehat{JML} - \widehat{JL}\)  + \(\widehat{JML} + \widehat{JL}\) = 2 × \(\angle {JKL}\) + 360°

Which gives;

2 × \(\angle {JKL}\) + 360° = 2 × \(\widehat{JML}\)

2 × (8·x - 6) + 360° = 2 × (25·x - 13)

2 × (8·x - 6) + 360° - 2 × (25·x - 13) = 0

-34·x + 374° = 0

374° = 34·x

\(x = \dfrac{374}{34} = 11\)

\(m\widehat{JML}\) = 25 × 11 - 13 = 262

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There are a total of 3 forwards on the team.

A fraction represents a part of the whole or group of objects.In a fraction, numerator and denominator are separated by a horizontal bar known as the fractional bar

Given:

2/8 of the players are forwards.

Total number of players on the team = 12

We will determine the total number of forwards on the team by multiplying the total number of players by the fraction representing the forwards.

Fraction representing the forwards:

= 2/8

= 1/4

Total forwards on the team:

= 12 * (1/4)

= 3.

Translated question:

Of the 12 players on the team, 2/8 are forwards. What are the total forward in the team?

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The upper quartile of NFC is three points higher than the upper quartile of AFC.

A box plot or boxplot is a visual representation of the location, dispersion, and skewness groups of quartiles of numerical data. When lines (referred to as whiskers) extend from the box on a box plot to indicate variability outside the upper and lower quartiles, the plot is also known as a box-and-whisker plot or box-and-whisker diagram. Outliers that stand out from the rest of the dataset can be shown as separate points outside the box's whiskers. Box graphs lack parametric data. To analyze the level and distribution of a set of scores, a box plot is utilized. There are 4 groups formed from the scores. Each group is worth 25%.

The third line on the box corresponds to the upper quartile. The upper quartile is represented by 75% of the scores.

Upper quartile for AFC : 26

Upper quartile for NFC : 23

Difference = 26 - 23 = 3

Therefore, Difference in Upper Quartiles = 3

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The reasonable domain to plot the function is 0 < d <= 1.4, the y-intercept of the function is 7 and the average rate of change from d = 4 to d = 11 is 0.64

The function is given as:

f(d) = 7(1.06)^d

The maximum radius is 13.29.

So, we have:

7(1.06)^d = 13.29

Divide both sides by 7

(1.06)^d = 1.90

Take the logarithm of both sides

dlog(1.60) = log(1.90)

Divide both sides by log(1.60)

d = 1.4

Hence, the reasonable domain to plot the function is 0 < d <= 1.4

This is when d = 0.

So, we have:

f(0) = 7(1.06)^0

Evaluate

f(0) = 7

Hence, the y-intercept of the function is 7

From d = 4 to d = 11

Calculate f(4) and f(11)

f(4) = 7(1.06)^4 = 8.84

f(11) = 7(1.06)^11 = 13.29

The average rate of change is

Rate = (13.29 - 8.84)/(11 - 4)

Rate = 0.64

Hence, the average rate of change from d = 4 to d = 11 is 0.64

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Answer:

Monthly loan payment is $400.76 for 60 payments at 7.5%.

Step-by-step explanation:

Answer:

At least 7 since 0 is a whole number the lowest n+7 can be is 0+7= 7 and there is seven numbers in between 0 and seven.

Step-by-step explanation:

Answer:

456

Step-by-step explanation:

Product means an answer derived from multiplication.  Therefore, if the product is 155952, and one value is 342, then the following equation is true:

342x = 155952, or 342 * x = 155952

Divide 155952 by 342 to get: 456.

Check the work in the equation:

342(456) = 155952

155952 = 155952, which is true, so the answer is 456.

If I helped, please make this answer brainliest! ;)

Answer:

\(y=-\frac{4}{3} x-\frac{14}{3}\)

Step-by-step explanation:

Linear equations are typically organized in slope-intercept form:

\(y=mx+b\) where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

1) Determine the slope (m)

Parallel lines will always have the same slope. Therefore, this line will have the same slope as the given line \(y=-\frac{4}{3} x+ \frac{7}{3}\).

Plug in \(-\frac{4}{3}\) as the slope

\(y=-\frac{4}{3} x+b\)

2) Determine the y-intercept (b)

To find the y-intercept, plug the given point (-5,2) into the equation and solve for b.

\(2=-\frac{4}{3}(-5)+b\\2=\frac{20}{3}+b\)

Subtract both sides by \(\frac{20}{3}\)

\(2-\frac{20}{3} = \frac{20}{3}+b-\frac{20}{3}\\\frac{6}{3} -\frac{20}{3}=b\\-\frac{14}{3} = b\)

Therefore, the y-intercept is \(-\frac{14}{3}\).

3) Plug the y-intercept back into our original equation

\(y=-\frac{4}{3} x-\frac{14}{3}\)

I hope this helps!

Answer:

The transformations that have been done are reflected vertically -1/2 and moved to the right by 3 units.

Step-by-step explanation:

To find out what transformations differ from your parent graph, look at the a,h, and k values.

A value means if it is being vertically stretched or reflected

In this case, -1/2 is a vertically reflection(upside down).

We also have -3 as our h value. This tells us how many units right or left our graph moves. If the value is negative, it moves to the right. If the value is positive, it moves to the left.

Now you know how to find transformations that differ from the parent graph

1.

9 (3+2)

We have to distribute number 9 in the parenthesis, multiply each term in the parenthesis by 9:

9(3)+9(2)

27+18

45

2.

11(4-1)

11(4)+11(-1)=44-11=33

3.

12(7+7)

12(7)+12(7)

84+84

168

4.

5 (4+8)

5(4)+5(8)

20+40

60

5.

10(9-5)

90-50

40

Step-by-step explanation:

first we will take comman then

\( \frac{4}{5} - \frac{2 \times 5}{5} \)

then 4 - 10

it will be

\( \frac{6}{5} \)

or

\(1 \frac{1}{5} \)

i hope it will help

Answer:

Solution is \(\frac{-6}{5}\)

Step-by-step explanation:

\(\frac{4}{5} - 2\)

Set common denominators

\(\frac{4}{5} - \frac{10}{5}\)

Subtract

\(\frac{4}{5} - \frac{10}{5} = \frac{-6}{5}\)

Answer:

Stohr sequence

Step-by-step explanation:

Let a_1=1 and define a_(n+1) to be the least integer greater than a_n which cannot be written as the sum of at most h>=2 addends among the terms a_1, a_2, ..., a_n. This defines the h-Stöhr sequence

Answer:

B. i and iii

Step-by-step explanation:

There are mistakes in your question. But I solve this problem using the average mean of 15 because that is what is contained in the solution

Hypothesis

H0: u <= 15

H1: u > 15

Mean of x = 16.6

S = 2.22

Test statistic used is t test

16.6 - 15 / 2.22/√24

= 3.531

We find the critical value

Degree of freedom = 24-1 = 23

This is a one tailed test

Critical value = 1.714

We find p value using Ms excel T distribution function

= 0.000894

To make the decision

3.531 > 1.714 so we conclude that

I.) Reject null hypothesis

Iii) conclude an average if more than 15 hours is volunteered per month. So no need to institute the program.

The answer option Is B

We have a formula to find the interior angles sum of a regular polygons, we just need the number of sides

where n is the number of sides

We can modify the formula to know the measure of the angles, since they all measure the same, we will divide into the number of angles

So:

now

Octagon

nonagon

12-gon

Answer:

\(x=29^{\circ}\)

Step-by-step explanation:

Please refer to the picture attached as I labeled the angles.

Given

\(\angle{B}=90^{\circ}\)

\(\angle{ADB}=58^{\circ}\)

\(AD=CD\)

\(\angle{ACD}=\angle{CAD}\) which also equals x in your picture.

We need to use the Exterior Angle Property to evaluate x.

This property states that the exterior angle equals sum of two interior opposite angles.

\(\angle{ACD}+\angle{CAD}=58^{\circ}\)

Substitute x for \(\angle{ACD}\) and \(\angle{CAD}\).

\(x+x=58^{\circ}\)

Add x and x.

\(2x=58^{\circ}\)

\(x=29^{\circ}\)

Answer:

The angle is 32

Step-by-step explanation:

The formula for the sum of interior angles is \((n-2)180\)

We have a triangle inside a triangle.

A triangle has 3 sides.

\((n-2)180\\(3-2)180\\1(180)\\180\)

The picture shows us an angle of 90 and 58.

All 3 angles must add up to 180.

\(180-90-58\)

\(x=32\)

Answer:

The population of the town will be 1771.44663 in 6 years.

Here is the calculation:

1400 * (1.04)^6 = 1771.44663

The formula for calculating the population of a town after a certain number of years is:

Population after n years = Initial population * (1 + growth rate)^n

In this case, the initial population is 1400, the growth rate is 4%, and the number of years is 6.

Plugging these values into the formula, we get:

Population after 6 years = 1400 * (1 + 0.04)^6 = 1771.44663

Step-by-step explanation:

Answer:

$25500

Step-by-step explanation:

tv =30000

15% discount= 30000×15÷100

= 4500

selling price = 30000-4500

=25500

The customer will to pay $2,970 in 12 days.

What does 3/10 mean?

3/10 is cash discount term which means that a discount of 3% would be given to the customer if payment for the goods purchased is made within 10 days of purchase.

In this  case, 3% is not applicable since the payment was made after 12 days.

What does 1/20 mean?

1/20 is cash discount term which means that a discount of 1% would be given to the customer if payment for the goods purchased is made within 20 days of purchase, the payment is within this range, hence, a 1% discount would be applied to invoice price so as to determine the cash payable

cash payable=$3,000*(1-1%)

cash payable=$3,000*0.99

cash payable=$2,970

What does n/30 mean?

It means a payment is expected latest after 30 days which does not entitle the customer no discount.

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we have shown that \($(a^m)^n = a^{mn}$\) for all \($a \in G$\) and \($m, n \in \mathbb{Z}$\).

To prove that in a group G, \($(a^m)^n = a^{mn}$\) for all \($a \in G$\) and \($m, n \in \mathbb{Z}$\), we need to show that both sides of the equation are equal.

We start by simplifying the left-hand side:

\($(a^m)^n = a^{mn}$\)

This is because raising a to the power of m and then to the power of n is the same as raising a to the power of mn. This property is known as the associative property of exponents.

Next, we need to show that the right-hand side of the equation is also equal to \($a^{mn}$\):

\($a^{mn} = a^{nm}$\)

This is because multiplication is commutative in \($\mathbb{Z}$\), which means that \($mn = nm$\)

Therefore, we have shown that \($(a^m)^n = a^{mn}$\) for all \($a \in G$\) and \($m, n \in \mathbb{Z}$\).

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In order to factor your quadratic polynomials, the box method, as its name suggests, uses a box. You can divide your quadratic into its factors by using the box, which is essentially a square divided into four equal parts.

Employing the Box Method

For our first quadratic, 6x2 - x - 12, let's utilize the box approach to solve it.

The first step is to create a two by two grid, as shown here:

using a box

Following that, we place the first term in the upper left box and the last term in the lower right box.

The Complete Question.

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Answer:

none is a solution...the solution.is -3

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

                                 \(f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}\).

This definition of the absolute function can be explained geometrically to be similar to the straight line   \(\textbf{\textit{y}} \ = \ \textbf{\textit{x}}\)  , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line  \(\textbf{\textit{y}} \ = \ \textbf{\textit{x}}\)  where \(\textbf{\textit{x}} \ < \ 0\) (shown as the orange dotted line), the segment of the line is reflected across the x-axis.

First, we simplify the expression.

                                             \(3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3\).

We, now, can simply visualise the straight line,  \(y \ = \ x \ + \ 1\) , as a line having its y-intercept at the point  \((0, \ 1)\) and its x-intercept at the point \((-1, \ 0)\). Then, imagine that the segment of the line where \(x \ < \ 0\) to be reflected along the x-axis, and you get the graph of the absolute function \(y \ = \ \left|x \ + \ 1 \right|\).

Consider the inequality

                                                    \(\left|x \ + \ 1 \right| \ < \ 3\),

this statement can actually be conceptualise as the question

            \(``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}"\).

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

                                                \(x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2\)

                                            \(-(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4\)

           *remember to flip the inequality sign when multiplying or dividing by

            negative numbers on both sides of the statement.

Therefore, the values of x that satisfy this inequality lie within the interval

                                                     \(-4 \ < \ x \ < \ 2\).

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.