2/3 (6a+9)

plsss i need it asap

Answer:

Step 1: Simplify both sides of the equation.

−7+3(8n−8)=8(7+3n)

−7+(3)(8n)+(3)(−8)=(8)(7)+(8)(3n)(Distribute)

−7+24n+−24=56+24n

(24n)+(−7+−24)=24n+56(Combine Like Terms)

24n+−31=24n+56

24n−31=24n+56

Step 2: Subtract 24n from both sides.

24n−31−24n=24n+56−24n

−31=56

Step 3: Add 31 to both sides.

−31+31=56+31

0=87

Answer:

There are no solutions.

Step-by-step explanation:

The inequality that represents the bid for the artwork is A. b ≥ 25,000.

Inequalities are created through the connection of two expressions. It should be noted that the expressions in an inequality aren't always equal. Inequalities implies that the expressions are not equal. They are denoted by the symbols ≥ < > ≤.

In this case, the famous piece of artwork was up for bid at a museum auction and the minimum bid was $25,000.

Let the minimum bid be b. This will be b ≥ 25,000.

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Answer:

I zont know i need points

Step-by-step explanation:

Yea im srry

Answer:

B) 43.758

Step-by-step explanation:

Starting from the right side of the decimal point, the places are:

tenths

hundredths

thousands

Each time, you add a zero to the previous number (10 to 100 to 1000, etc), therefore the third decimal would be the thousandths place. If the next figure is a 5 or above, you round up, to the next decimal.

The angle θ that will maximize the area of the triangle formed by sides 4 and 12 is π/2 radians.

To maximize the area of the triangle formed by sides of length 4 and 12, we can use the formula for the area of a triangle, A = (1/2)ab * sin(θ), where a and b are the sides and θ is the angle between them.

A = (1/2)(4)(12) * sin(θ)
A = 24 * sin(θ)

To maximize the area, we need to maximize the value of sin(θ). The maximum value of sin(θ) is 1 when θ = π/2 radians.

So, the angle θ that will maximize the area of the triangle formed by sides 4 and 12 is π/2 radians.

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Answer:

Step-by-step explanation:

Given

Points: (0,3) and (-4,-1)

Formula

x = 0 to find the y intercept

m = (y2 - y1)/(x2 - x1)

Solution

y2 = 3

y1 = - 1

x2 = 0

x1 = - 4

m = (3 - -1)/(0 - - 4)

m = 4/4

m = 1

You have y = mx + b so m = 1

the general equation becomes y = x + b

Use point (0,-4)

y = x + b

- 4 = 0 + b

b = - 4

y = x - 4

Answer:

Step-by-step explanation:

Answer:

21x+4

Step-by-step explanation:

X’s: 21x

#’s: 4

So it will be 21x+4

Answer:

I think it might be a constant

The value of variable c in block d is 2.

In the given code, there are multiple nested blocks with variables a, b, c, and d. The variable c appears in two different scopes: one within block b and another within block c.

When the code reaches the  innermost block c, a new variable c is declared with a value of 3. This innermost c variable shadows the outer c variable, which has a value of 2 in block b.

Inside the innermost block c, the value of d is assigned as the concatenation of variables a, b, and c, which are all in the current scope and have values 1, 2, and 3 respectively. Therefore, the value of d is 1 2 3.

In block d, another variable e is declared and assigned the concatenation of variables a, b, and c, which are still in the current scope and have the same values. Hence, the value of e is also 1 2 3.

In summary, the value of variable c in block d is 2, not 3.

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As per the probability, an accurate statement regarding these two distributions is option (a) Distribution A has a higher variance

Looking at the given probabilities for each value in Distribution A and Distribution B, we can calculate their respective means and variances. For Distribution A, the mean is 2.2 and the variance is approximately 1.76. For Distribution B, the mean is 1.02 and the variance is approximately 1.416.

Based on these calculations, we can see that Distribution A has a higher variance than Distribution B.

This means that the values in Distribution A are more spread out from the mean than the values in Distribution B.

Therefore, the accurate statement regarding these two distributions is that Distribution A has a higher variance than Distribution B.

Hence the option (a) is correct.

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Answer:

Phone 1 will allow Ellie to talk the longest

Step-by-step explanation:

Phone 1:

     (0.10x) + 6 = y

(0.10x) + 6 - 6 = 22 - 6

     0.10/0.10x = 16/0.10

                    x = 160 minutes

Phone 2:

      (0.25x) + 5 = y

(0.25x) + 5 - 5  = 22 - 5

     0.25/0.25x = 17/0.25

                      x = 68 minutes

Jacinta needs to order 3 cases of 216 mm x 279 mm x 270 mm printer paper to have the 7,000 sheets needed

information from the question

500 sheets of printer paper 216 mm x 279 mm x 45 mm

packaged in cases 216 mm x 279 mm x 270 mm

Jacinta needs to order 7,000 sheets

Jacinta can only order full cases

Analyzing the size of the printer paper it can be seen that the thickness of 500 sheets is 45 m. The thickness of the cases is 270mm

The amount of packages in a case is solved by

= 270 / 45

= 6

Therefore one case contains

= number of packages in a case * number of sheets per package

= 6 * 500

= 3000 sheets

But Jacinta wants 7000 sheets hence  the number of cases

= 7000 / 3000

= 2.333

Jacinta can only buy full case hence she buys 3 cases. This is because 2 cases will be short of 0.333. To take care of the extra she order full package making it three

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Answer:

50 black, 40 blue, and 20 red.

The interquartile range of the given dataset is 12.5. This measure represents the spread of the middle 50% of the data, providing a robust measure of variability that is not affected by extreme values or outliers.

To find the interquartile range (IQR) of a dataset, we first need to determine the values of the first quartile (Q1) and the third quartile (Q3). The IQR is then calculated as the difference between Q3 and Q1.

Arrange the data in ascending order:

43, 46, 47, 51, 51, 52, 54, 54, 55, 56, 60, 61, 62, 64, 69, 70.

Determine the position of Q1 and Q3:

Q1 is the median of the lower half of the dataset, and Q3 is the median of the upper half.

The dataset contains 16 observations, so the median (Q2) will be the average of the 8th and 9th values, which are 54 and 55.

Q2 = (54 + 55) / 2 = 54.5

For Q1, we consider the first 8 values: 43, 46, 47, 51, 51, 52, 54, 54. Since there are an even number of values, the median will be the average of the 4th and 5th values, which are 47 and 51.

Q1 = (47 + 51) / 2 = 49.

For Q3, we consider the last 8 values: 55, 56, 60, 61, 62, 64, 69, 70. Again, the median will be the average of the 4th and 5th values, which are 61 and 62.

Q3 = (61 + 62) / 2 = 61.5.

Calculate the IQR:

IQR = Q3 - Q1 = 61.5 - 49 = 12.5.

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Answer:

21/8 yards

Step-by-step explanation:

If Sarah wants to make her own costume she will need 21/8 yards of yarn.

To get this, you multiply 2 by 8 and get 16.

Next, you will add 5 onto 16 and get 21.

Keep your 21 and put is as your numerator.

Now take your 8 and put it as your denominator.

The solution of the expression   12 + [2 - (4 × a²)] ÷ 7 + b with the given values of a and b (using BODMAS) is -1 .

Given,

Equation is :     12 + [2 - (4 × a²)] ÷ 7 + b

Values of a and b are; 5 and 1 respectively

Substitute the values of a and b into the equation

12 + [2 - (4 × 5²)] ÷ 7 + 1

Using BODMAS :

solve the expression that is in the bracket first :

⇒ 12 + [2 - 100] ÷ 7 + 1

⇒ 12 + [-98] ÷ 7 + 1

Solve the division next :

⇒ 12 - 14 + 1

Solve the addition next :

⇒ 13 - 14

Solve the subtraction next :

⇒ -1

Therefore, the solution of the expression with the given values of a and b is - 1

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Answer:

$3.50

Step-by-step explanation:

4 2/3 x 0.75 = $3.50

Answer:$3.5

Step-by-step explanation:

The graph of a tangent function in the form y = atan(bx − c) + d has a period of pi/|b|. When b = 1/2, the period is pi. This means that the graph will repeat itself every pi units on the x-axis. The correct option is the second graph.

The graph of the tangent function in the first option has a period of 2pi. This is not consistent with the period of a tangent function with b = 1/2.

The graph of the tangent function in the second option has a period of pi. This is consistent with the period of a tangent function with b = 1/2.

The graph of the tangent function in the third option does not have a period of pi. This is not consistent with the period of a tangent function with b = 1/2.

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A straight line = 180 degrees.

180 - 114 = 66 degrees

We can shape three circles to represent 6/2.

What is a fraction?

A fraction represents a part of a whole or, more generally, any number of equal parts. When spoken in everyday English, a fraction describes how many parts of a certain size there are, for example, one-half, eight-fifths, or three-quarters.

When using a circular model, also known as a circle diagram or a circle model, to represent a fraction, the fraction is represented by shading a portion of the circle. For example, to represent the fraction 6/2, you would shade three circles because 6/2 can be simplified to 3/1, which represents three whole circles.

Hence, we can shape three circles to represent 6/2.

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To prove that any postage of at least 12 cents can be obtained using 3 cents and 7 cents stamps, we will use mathematical induction.

First, let's check the base case. We need to show that it's possible to obtain a postage of 12 cents using 3 cents and 7 cents stamps. We can do this by using two 3 cents stamps and two 7 cents stamps, for a total of 12 cents.
Now, let's assume that it's possible to obtain any postage of at least 12 cents using 3 cents and 7 cents stamps. We want to prove that this also holds for postage values of n+1.
To do this, we need to show that it's possible to obtain a postage of n+1 cents using 3 cents and 7 cents stamps, assuming that we can already obtain any postage of at least 12 cents.
Let's consider the case where n+1 is an odd number. We can use one 7 cents stamp and (n-6)/2 3 cents stamps to obtain a postage of n+1 cents. This works because if n+1 is odd, then n-6 must be even, so we can divide it by 2 and use that many 3 cents stamps.
Now, let's consider the case where n+1 is an even number. We can use two 3 cents stamps and (n-8)/2 7 cents stamps to obtain a postage of n+1 cents. This works because if n+1 is even, then n-8 must be even, so we can divide it by 2 and use that many 7 cents stamps.
Therefore, we have shown that it's possible to obtain any postage of at least 12 cents using 3 cents and 7 cents stamps, and our proof is complete.

To use mathematical induction to prove that any postage of at least 12 cents can be obtained using 3 cents and 7 cents stamps, follow these steps:
Step 1: Base case
Show that the statement holds true for the smallest value (12 cents).
You can obtain 12 cents using four 3-cent stamps (3+3+3+3). So, the base case is true.
Step 2: Inductive hypothesis
Assume the statement is true for some arbitrary value 'k' (k >= 12) such that k can be obtained using 3 cents and 7 cents stamps.
Step 3: Inductive step
Prove the statement is true for the next value, 'k+1'. We need to show that (k+1) cents can also be obtained using 3 cents and 7 cents stamps.
Case 1: If the 'k' postage contains at least one 3-cent stamp, we can replace that with a 3-cent and a 3-cent stamp to obtain (k+1) cents.
Case 2: If the 'k' postage contains only 7-cent stamps, we have at least two 7-cent stamps since k >= 12. We can replace two 7-cent stamps with five 3-cent stamps (7+7 = 3+3+3+3+3), which adds up to the same postage value. In this case, we can obtain (k+1) cents by adding another 3-cent stamp.
In both cases, (k+1) cents can be obtained using 3 cents and 7 cents stamps. Therefore, by mathematical induction, any postage of at least 12 cents can be obtained using 3 cents and 7 cents stamps.

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The 50th term is 290.

It is a sequence where there is a common difference between each consecutive term.

Example:

12, 14, 16, 18, 20 is an arithmetic sequence.

We have,

-4, 2, 8, 14,

This is an arithmetic sequence.

First term = a = - 4

Common difference.

d = 2 - (-4) = 6

d = 8 - 2 = 6

Now,

The nth term = a + (n -1)d

So,

n = 50

a = -4

d = 6

50th term.

= -4 + (50 - 1) 6

= - 4 + 49 x 6

= - 4 + 294

= 290

Thus,

The 50th term is 290.

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The complete question:

What is the 50th term of the sequence that begins −4, 2, 8, 14, ...?

The SI units of the proportionality constant G is Newton \(Kg^{-2} m^2\)

Gravitational force is given by Newton's law of gravitation which states that every particle of matter in the cosmos is drawn to every other particle by a force of attraction that varies directly with the product of their masses and is inversely proportional to the square of the distance or degree of separation from each other.

F = G \($ \frac{m_1 m_2}{r^2}\)

Upon rearranging the terms we get,

G = \($\frac{F r^2}{m_1 m_2}\)

Where F is the gravitational force, \(m_{1}\) and \(m_{2}\) are masses, and r is the length.

Force has the SI units kg · m/s2

The SI units of the proportionality constant G

SI Unit of G = \($\frac{(\text { Newton })\left(\mathrm{m}^2\right)}{\mathrm{kg} ^2}\)

= Newton \(Kg^{-2} m^2\)

Therefore the units are Newton \(Kg^{-2} m^2\)

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Newton's law of universal gravitation is represented by F = G \($ \frac{m_1 m_2}{r^2}\) where F is the gravitational force, \(m_{1}\) and \(m_{2}\) are masses, and r is a length. force has the SI units kg· m/s2. what are the SI units of the proportionality constant G?

Solution. To graph f, we graph the equation y=f(x).

To this end, we use the techniques outlined in Section 1.2.1. Specifically, we check for intercepts, test for symmetry, and plot additional points as needed. To find the x -intercepts, we set y=0. Since y=f(x), this means f(x)=0.

\($$\begin{aligned}f(x) & =x^2-x-6 \\0 & =x^2-x-6 \\0 & =(x-3)(x+2) \quad \text { factor } \\x-3=0 & \text { or } x+2=0 \\x & =-2,3\end{aligned}$$\)

So we get (-2,0) and (3,0) as x-intercepts. To find the y-intercept, we set x=0. Using function notation, this is the same as finding f(0) and f(0)=0^2-0-6=-6. Thus the y-intercept is (0,-6). As far as symmetry is concerned, we can tell from the intercepts that the graph possesses none of the three symmetries discussed thus far. (You should verify this.) We can make a table analogous to the ones we made in Section 1.2.1, plot the points and connect the dots in a somewhat pleasing fashion to get the graph below on the right.

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Answer:

C is closest to the actual result, $1126.03.

Step-by-step explanation:

Use the Compound Amount formula:  A = P(1 + r/n)^(nt), where:

 P is the original principal; r is the interest rate as a decimal fraction; n is the number of compounding periods per year, and t is the number of years.

Then we have A = $1000(1 + 0.04/4)^(4*3), or

                            = $1000(1.01)^12  =  $1126.03

To find the cost of one bottle of water, we need to divide the total cost of the case by the number of bottles in the case, which is 24.

So,

Cost of one bottle of water = Total cost of case / Number of bottles in case

= $2.99 / 24

= $0.1246

Rounding this to two decimal places, we get:

Cost of one bottle of water = $0.12

Therefore, one bottle of water costs $0.12.

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The unit of measure for roll batt insulation is usually in square feet. On the estimate, you should note the type of insulation being used, the type of coverage being provided, the cost of the insulation, and any installation fees.

Roll batt insulation is a type of insulation that is often used to insulate walls, attics, and other areas of the home. The unit of measure for roll batt insulation is usually in square feet. When getting an estimate for the cost of the insulation, it is important to note the type of insulation being used, the type of coverage being provided, the cost of the insulation, and any installation fees that may be involved. This type of information should be noted on the estimate in order to ensure that you are getting the most accurate estimate for the insulation that you need.

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Answer:

3.5 gallons of punch

Step-by-step explanation:

There are 4 quarts in 1 gallon.

Set up equation to convert 14 quarts to gallons: 14÷4 = 3.5.

Elijah made 3.5 gallons of punch.