2/x = 10/15 it's 2 / x = 10 / 15 find the unknown number in the proportion. Round the answer to the nearest hundredth when necessary ​ Will mark brainly

If b=3, then 3^-2=1/9, and 3^4=81. 1/9÷81= 1/729, which is 3^-6.

You can use any other example you want (I would recommend a calculator)

Answer:

\(2p^2\)

Step-by-step explanation:

Step 1: Apply the exponentiation property:

\((8p^6)^\frac{1}{3} = 8^\frac{1}{3} * (p^6)^\frac{1}{3}\)

Step 2: Simplify the cube root of 8:

The cube root of 8 is 2:

\(8^\frac{1}{3} =2\)

Step 3: Simplify the cube root of \((p^6)\):

The cube root of \((p^6)\) is \(p^\frac{6}{3} =p^2\)

Step 4: Combine the simplified terms:

\(2 * p^2\)

So, the simplified expression is \(2p^2\).

Answer:

Less

Step-by-step explanation:

Look at the hundreds number in set L the numbers are greater in Set L than Set K.

Answer:

  14

Step-by-step explanation:

The triangle inequality is usually expressed as ...

  a +b > c

for any permutation of a, b, c.

Here, that would mean ...

  1 + 14 > c

  c < 15

The largest whole-number value that the third side (c) can have is 14.

_____

Additional comments

Some authors write the triangle inequality as ...

  a +b ≥ c

If you use that version, the longest side could be 15. Such a "triangle" would look like a line segment, and have zero area.

__

We can also check the shortest length:

  c +1 > 14

  c > 13

The smallest whole-number value for the shortest side is also 14. That is, the only triangle with whole-number side lengths of 1 and 14 will be an isosceles triangle with two sides of length 14.

Answer: Rebate applied AFTER the discount

Step-by-step explanation:

Because the rebate value stays the same no matter what, but the discount doesn't.

The empirical rule, also known as the 68-95-99.7 rule, is a statistical rule that applies to data that is approximately normally distributed. It states that:
Approximately 68% of the data falls within one standard deviation of the mean.

Approximately 95% of the data falls within two standard deviations of the mean. Approximately 99.7% of the data falls within three standard deviations of the mean

In the context of your question, where the mean IQ is 100 and the standard deviation is 15, we can use the empirical rule to answer certain questions.
Approximately 68% of individuals would have an IQ between 85 and 115, since this range falls within one standard deviation of the mean.

Approximately 95% of individuals would have an IQ between 70 and 130, since this range falls within two standard deviations of the mean. Approximately 99.7% of individuals would have an IQ between 55 and 145, since this range falls within three standard deviations of the mean.

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Approximately 99.7% of the IQ scores will fall between 55 and 145. The empirical rule, also known as the 68-95-99.7 rule, is a statistical principle that applies to data that follows a normal distribution. It states that:

1. Approximately 68% of the data falls within one standard deviation of the mean.
2. Approximately 95% of the data falls within two standard deviations of the mean.
3. Approximately 99.7% of the data falls within three standard deviations of the mean.

In this case, the standardized test of intelligence has a mean IQ of 100 and a standard deviation of 15.

1. To determine the range of IQ scores within one standard deviation of the mean, we can use the empirical rule. Since 68% of the data falls within one standard deviation of the mean, we can calculate the range as follows:
  - Lower bound: Mean - Standard deviation = 100 - 15 = 85
  - Upper bound: Mean + Standard deviation = 100 + 15 = 115
  Therefore, approximately 68% of the IQ scores will fall between 85 and 115.

2. To determine the range of IQ scores within two standard deviations of the mean, we can use the empirical rule. Since 95% of the data falls within two standard deviations of the mean, we can calculate the range as follows:
 \(- Lower bound: Mean - (2 \times Standard deviation) = 100 - (2 \times 15) = 70\\- Upper bound: Mean + (2 \times Standard deviation) = 100 + (2 \times 15) = 130\)
  Therefore, approximately 95% of the IQ scores will fall between 70 and 130.

3. To determine the range of IQ scores within three standard deviations of the mean, we can use the empirical rule. Since 99.7% of the data falls within three standard deviations of the mean, we can calculate the range as follows:
 \(- Lower bound: Mean - (3 \times Standard deviation) = 100 - (3 \times 15) = 55\\ -Upper bound: Mean + (3 \times Standard deviation) = 100 + (3 \times 15) = 145\)
  Therefore, approximately 99.7% of the IQ scores will fall between 55 and 145.

These ranges give us an idea of where the majority of IQ scores are likely to fall based on the standard deviation from the mean.

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Answer:

945678

Step-by-step explanation:

i took the test

This is the expression for ∂z/∂u using the Chain Rule.

To find ∂z/∂u using the Chain Rule, we first need to find the partial derivative of z with respect to r and θ.
∂z/∂r = e^(r cos θ) cos θ
∂z/∂θ = -e^(r cos θ) r sin θ
Next, we can use the Chain Rule to find ∂z/∂u:
∂z/∂u = (∂z/∂r) * (∂r/∂u) + (∂z/∂θ) * (∂θ/∂u)
We know that r= 6 uv and θ = √(u^2+v^2 ), so we can substitute those values in:
∂z/∂u = (e^(r cos θ) cos θ) * (6v) + (-e^(r cos θ) r sin θ) * (u/√(u^2+v^2 ))
Simplifying this expression, we get:
∂z/∂u = 6ve^(6uv cos(√(u^2+v^2 )))cos(√(u^2+v^2 )) - (u/√(u^2+v^2 ))e^(6uv cos(√(u^2+v^2 )))r sin(√(u^2+v^2 ))
We have z = e^(r cos θ), r = 6uv, and θ = √(u^2 + v^2). We need to find ∂z/∂u.
Using the Chain Rule, we get:
∂z/∂u = (∂z/∂r)(∂r/∂u) + (∂z/∂θ)(∂θ/∂u)
First, let's find the partial derivatives of z:
∂z/∂r = e^(r cos θ) cos θ
∂z/∂θ = -e^(r cos θ) r sin θ
Now, find the partial derivatives of r and θ with respect to u:
∂r/∂u = 6v
∂θ/∂u = u / √(u^2 + v^2)
Now, substitute these partial derivatives back into the Chain Rule formula:
∂z/∂u = (e^(r cos θ) cos θ)(6v) + (-e^(r cos θ) r sin θ)(u / √(u^2 + v^2))
This is the expression for ∂z/∂u using the Chain Rule.

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The client with hypotension weighing 60 kg is prescribed nitroprusside at a rate of 3 mcg/kg/min. The solution concentration is 100 mg in 250 ml of D5W.

To calculate the infusion rate in ml/hr, we need to convert the dose from mcg/kg/min to mg/hr.

First, we calculate the total dose per minute by multiplying the weight of the client (60 kg) by the prescribed dose (3 mcg/kg/min):

Total dose per minute = 60 kg * 3 mcg/kg/min = 180 mcg/min.

Next, we convert the total dose from mcg to mg by dividing by 1,000:

Total dose per minute = 180 mcg/min / 1,000 = 0.18 mg/min.

To calculate the ml/hr, we need to find the total volume of the solution infused per hour. Given that the solution concentration is 100 mg in 250 ml of D5W, we can set up a proportion:

0.18 mg/min / X ml/hr = 100 mg / 250 ml.

Solving for X, we have:

X = (0.18 mg/min * 250 ml) / 100 mg ≈ 0.45 ml/hr.

Therefore, for a client weighing 60 kg using a solution concentration of 100 mg in 250 ml of D5W.

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The probability that more than 6 out of 9 packages arrive on time can be calculated using the binomial distribution.

In this case, we have a success probability of 70% (0.7) and we want to find the probability of getting more than 6 successes out of 9 trials.

Using the binomial probability formula, we can calculate the probability as follows: P(X > 6) = 1 - P(X ≤ 6)

To calculate P(X ≤ 6), we can sum the probabilities of getting 0, 1, 2, 3, 4, 5, and 6 successes.

The calculation involves evaluating individual probabilities and summing them up. The final result will determine the probability that more than 6 out of 9 packages arrive on time.

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The required answer is: the probability of getting a club and then a club on your first and then second draw is 0.0625

A standard deck of cards has 52 cards with: 4 suits (hearts, diamonds, spades and clubs).

13 cards in each suit (ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen and king). If you are dealing with replacement, the probability of getting a club and then a club on your first and then second draw can be calculated as follows:

Probability of getting a club on the first draw:

P(club on first draw) = Number of clubs in the deck / Total number of cards in the deck

P(club on first draw) = 13/52

P(club on first draw) = 1/4

Probability of getting a club on the second draw:

P(club on second draw) = Number of clubs in the deck / Total number of cards in the deck

P(club on second draw) = 13/52

P(club on second draw) = 1/4

Now, the probability of getting a club and then a club on your first and then second draw can be calculated by multiplying the probability of getting a club on the first draw by the probability of getting a club on the second draw.

P(club and then club) = P(club on first draw) × P(club on second draw)

P(club and then club) = (1/4) × (1/4)

P(club and then club) = 1/16

P(club and then club) = 0.0625 or 6.25%

Therefore, the probability of getting a club and then a club on your first and then second draw is 0.0625 or 6.25% (rounded to 4 decimal places).

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The domain of the function \(f(x) = \sqrt{\frac{1}{3}x + 2\) is (d) x  ≥ -6

From the question, we have the following parameters that can be used in our computation:

\(f(x) = \sqrt{\frac{1}{3}x + 2\)

Set the radicand greater than or equal to 0

So, we have

1/3x + 2 ≥ 0

Next, we have

1/3x  ≥ -2

So, we have

x  ≥ -6

Hence, the domain of the function is (d) x  ≥ -6

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Answer:

88 \(in^2\)

Step-by-step explanation:

2(2 x 6 + 4 x 6 + 4 x 2)

\(2\)\((wl+hl+hw)\)

The probability that Imelda selects two mysteries is 2/87.

The Probability in mathematics is the possibility of an event in time. In simple words how many times that incident is happening in any given time interval.

Given:

The table shows the books of several different genres available to read on Imelda's bookshelf.

Imelda selects two different books.

The probability that Imelda selects two mysteries is,

= 5/30 x 4/29

= 2/87

Hence, the probability is 2/87.

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Answer:

A.  Similar triangles must have the same shape, so the measures of the corresponding angles must be equal to each other.

The triangles ABC and DEF are similar triangles, but DEF is twice as big as ABC.

What does it signify when two triangles are similar?

Congruent triangles are triangles that share similarity in shape but not necessarily in size. All equilateral triangles and squares of any side length serve as illustrations of related objects.

                        Or to put it another way, the corresponding angles and sides of two triangles that are similar to one another will be congruent and proportionate, respectively.

How do the sizes of the circles compare?

Given the triangles ABC and DEF

From the figure, we have

AB = 1

DE = 2

This means that the triangle DEF is twice the size of the triangle ABC

Are triangles ABC and DEF similar?

Yes, the triangles ABC and DEF are similar triangles

This is because the corresponding sides of  DEF is twice the corresponding sides of triangle ABC

How can you use the coordinates of A to find the coordinates of D?

Multipliying the coordinates of A by 2 gives coordinates of D.

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do your own bro its your paper sheet

Answer:

Y=3 is a horizontal line. So, a line perpendicular to y=3 must be vertical. The only vertical line among the choices is x=-3, so C must be the answer.

Step-by-step explanation:

\(\begin{gathered} \bf \implies3 \frac{81}{100} \\ \end{gathered} \)

Step 1) Add number separately and decimal seperately

Step 2) See the decimal digit and multiply with it and convert it into simplest form

\(\frac{0.81}{1} \times \frac{100}{100} = \frac{81}{100}\)

Step 3) Add number and (simplest form [Find above]

\(3 + \frac{81}{100} = 3 \frac{81}{100}\)

Step 4) We have convert it into mixed fraction and we have get the answer

\(\begin{gathered} \bf \implies3 \frac{81}{100} \\ \end{gathered} \)

The number the teacher gave Ross is 5127

From the question, we are to determine the number that the teacher gave Ross

From the given information,

Mr. David gave Ross a number and asked him to divide it by 15.

Let the number be x

That is,

x/15

The quotient and remainder obtained by ross are 341 and 12 respectively

That is,

x/15 = 341 + 12/15

Now, we will solve the equation for x

x/15 = 341 + 12/15

Multiply through by 15

x = 15×341 + 12

x = 5115 + 12

x = 5127

Hence, the number the teacher gave Ross is 5127

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The amount of money in the account after 6 years is $68,847.56

To solve this problem, you can use the formula for compound interest,

where V is the final value of the account, P is the initial principal, r is the annual interest rate (expressed as a decimal), and t is the number of years the money is invested.

The formula for compound interest, V = Pe^(rt) is used to calculate the future value of an investment. It takes into account the effect of compounding, which means that interest is earned not only on the initial investment but also on the accumulated interest over time.

Plugging in the given values, we have

V = 51200e^(0.0546) = 51200e^0.324. e^0.324 is approximately 1.38, so the final value of the account is 512001.38 = $68,847.56

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Answer:

Area ABCDE = 82 cm²

Step-by-step explanation:

ABCDE = ΔEAD + ΔDAC + ΔCAB

ABCDE = (12×5)/2 + (12×6)/2 + (8×4)/2 = 30+36+16 = 82

The value of the coefficient B will be 9.

2(x+By)(x-2y)

=2(x^2 -2xy +Bxy -2By^2)

=2x^2 -4xy + 2Bxy - 4By^2

The original form is  \(\d2x^{2} +14x-36y^{2}\)

\(2(x+By)(x-2y)\\\ =2(x^2 -2xy +Bxy -2By^2)\\\\ =2x^2 -4xy + 2Bxy - 4By^2\\\\2x^2 + 14xy - 36y^2\\\\ -36y^2 = -4By^2B= 9\\\\ -4xy +2Bxy= 14xy\\\\xy(-4 +2B)= 14xy\\\\ -4 + 2B = 14\\\\ 2B = 18\\\ B=9\)

hence the value of B=9

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Answer:

b=9

Step-by-step explanation:

The minimum distance the annihilation event could have occurred from the center of the machine is approximately 98.94 nanometers.

To determine the minimum distance the annihilation event could have occurred from the center of the machine, we can use the speed of light as a constant and the time difference between the collisions of the gamma rays.

The speed of light in a vacuum is approximately 299,792,458 meters per second (m/s).

Since the time difference between the collisions of the gamma rays is given as 0.33 nanoseconds, we need to convert this time to seconds. One nanosecond is equal to 1 × 10⁻⁹seconds.

0.33 nanoseconds is equal to 0.33 × 10⁻⁹ seconds.

Now, we can calculate the minimum distance using the equation:

Distance = Speed of light × Time

Distance = 299,792,458 m/s × 0.33 × 10⁻⁹ seconds

Distance ≈ 98.94 nanometers

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Answer:

Since Q is a center of gravity, we can apply these formulas

Therefore, the MLE of θ is θ = -(1/n) ∑ln(x_i). Therefore, θ is an unbiased estimator of θ.

(a) To find the maximum likelihood estimator (MLE) of θ, we first write the likelihood function as follows:

L(θ|x_1, x_2, ..., x_n) = ∏(i=1 to n) f(x_i; θ)

= ∏(i=1 to n) [(1/θ)x_i(1-θ)/θ]

= (1/θ^n) ∏(i=1 to n) x_i(1-θ)

Taking the natural logarithm of L(θ|x_1, x_2, ..., x_n), we have:

ln(L(θ|x_1, x_2, ..., x_n)) = -n ln(θ) + (1-θ) ∑ln(x_i)

To find the MLE of θ, we differentiate ln(L(θ|x_1, x_2, ..., x_n)) with respect to θ and set the derivative to zero:

d/dθ ln(L(θ|x_1, x_2, ..., x_n)) = -n/θ + ∑ln(x_i) = 0

Solving for θ, we get:

θ = -(1/n) ∑ln(x_i)

(b) To show that θ is an unbiased estimator of θ, we need to find its expected value:

E(θ) = E[-(1/n) ∑ln(x_i)]

= -(1/n) ∑E[ln(x_i)]

= -(1/n) ∑[∫0^1 ln(x_i) (1/θ)x_i(1-θ)/θ dx_i]

= -(1/n) ∑[∫0^1 (1/θ)ln(x_i)x_i(1-θ) d(x_i)]

= -(1/n) ∑[θ(-1/(θ^2))(1/2)ln(x_i)^2|0^1 + (1/θ)(1/2)x_i^2(1-θ)|0^1]

= -(1/n) ∑[(1/2θ)ln(x_i)^2 - (1/2θ)x_i^2(θ-1)]

= -(1/n) [(1/2θ)∑ln(x_i)^2 - (1/2θ)(θ-1)∑x_i^2]

Note that ∑ln(x_i)^2 and ∑x_i^2 are constants with respect to θ. Therefore, we have:

E(θ) = -(1/n) [(1/2θ)∑ln(x_i)^2 - (1/2θ)(θ-1)∑x_i^2]

= (1/2) - (1/2nθ)

Since E(θ) = θ, we have:

θ = (1/2) - (1/2nθ)

Solving for θ, we get:

θ = 1/(n+2)

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Answer:

6.7222222222

Step-by-step explanation:

This Maths Is Easy, Y Did You Post It?

Answer:

=6.7222222222

Step-by-step explanation:

Easy peesy lemon squezy!

The lighter pumpkin weighs 3.12 kg, and the heavier pumpkin weighs 6.24 kg.

To solve this, we'll use the given information to set up an equation and then solve for the weight of each pumpkin.
Let the weight of the lighter pumpkin be x kg.

Since the heavier pumpkin is twice the weight of the lighter one, its weight would be 2x kg.
The combined weight of both pumpkins is 9.36 kg, so we can write an equation as follows:
x + 2x = 9.36
Now, we'll solve for x:
3x = 9.36
x = 9.36 / 3
x = 3.12 kg
Now that we have the weight of the lighter pumpkin (x = 3.12 kg), we can find the weight of the heavier pumpkin:
2x = 2(3.12) = 6.24 kg.

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