3. 80 mol O2 will produce how many moles of CO2? Include entire unit (mol) and


compound formula, 3 sig figs.

Answer:

a) gold-solvent

silver+ copper-solute

b) solvent- water

solute- sugar

c) solute- CO2

solvent- H2O

Matter is composed of indivisible building blocks. This idea was recorded as early as the fifth century BCE by Leucippus and Democritus. The Greeks called these particles atomos, meaning indivisible, and the modern word “atom” is derived from this term. Democritus proposed that different types and combinations of these particles were responsible for the various forms of matter. However, these ideas were largely ignored at the time, as most philosophers favored the Aristotelian perspective.

When atoms establish or break chemical bonds, chemical processes take place. Reactants are the chemicals that begin a chemical reaction, while products are the compounds that are created as a result of the reaction.

When a volcano erupts, glass, rock, and mineral particles are mixed together to form volcanic ash. Less than 2 millimetres in diameter, the particles are very tiny. They have a low density since they are frequently pitted and have numerous holes. In hydrated Portland cement, CSH is the primary factor in the development of strength, while calcium hydroxide is another hydration agent.

Silica granules generate non-explosive dusts when they are suspended in the atmosphere. To create silicates, silica can interact with other metallic elements and oxides. A silicon atom is covalently joined to two oxygen atoms to form silicon dioxide, a kind of silicon oxide composed of linear triatomic molecules.

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When hydrogen and steam are both present in a gas at the same pressure and temperature, this is the ideal gas condition. This is so because according to the ideal gas law, an ideal gas's pressure, volume, and temperature are all precisely proportional to one another.

This indicates that when the two gases have the same temperature and pressure, the two gases will also have the same volume. As a result, the gases are in their ideal state, having the same volume and pressure but retaining their distinct chemical compositions.

This is perfect because it enables the two gases to interact with one another in a predictable way, allowing for the measurement and prediction of the gases' behaviour.

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A reaction that requires water as a reactant is called a hydrolysis reaction. In hydrolysis reactions, water is used to break down a larger molecule into smaller molecules by breaking chemical bonds.

This process requires the addition of a water molecule, which donates a hydrogen ion (H+) to one molecule and a hydroxide ion (OH-) to the other. Hydrolysis reactions are important in many biological processes, such as the breakdown of complex molecules like proteins, carbohydrates, and nucleic acids into their individual building blocks.

Examples of hydrolysis reactions include the breakdown of sucrose (table sugar) into glucose and fructose by the enzyme sucrase, and the breakdown of proteins into their constituent amino acids by the enzyme protease.

Hydrolysis reactions are commonly used in the breakdown of large, complex molecules into smaller, simpler molecules. This is because many large molecules, such as proteins, carbohydrates, and nucleic acids, are too large and complex to be absorbed or utilized by cells. In order to use these molecules, they must be broken down into their individual building blocks.

For example, proteins are composed of long chains of amino acids. To use the amino acids, the protein molecule must be broken down by hydrolysis. The hydrolysis reaction breaks the peptide bonds that hold the amino acids together in the protein chain, producing individual amino acids that can be absorbed and utilized by cells.

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Answer: C

Explanation:

Reaction 1 starts off with one mole of reactant and produces 2 moles of product. The increase in the number of moles, along with the fact that aqueous compounds are more disordered than solid compounds, increases the disorder and thus entropy.

Reaction 2 starts off with 1 mole of solid and produces 1 mole of solid and one mole of gas. The increase in the number of moles, along with the fact that gases are more free and disordered than solids, increases the disorder and thus entropy.

Answer:The energy of the molecules of the wax decreases.

Explanation:

C25H52 + 38 O2 → 25 CO2 + 26 H2O

Explanation:

Word Equation

Lead Nitrate + Sodium Chloride --> Lead Chloride + Sodium Nitrate

Balanced Chemical Equation

2 NaCl (aq) + Pb(NO3)2 (aq) → PbCl2 (s) + 2 NaNO3 (aq)

Ionic Equation

In an ionic equation, the aqueous species in the reaction are broken up into ions.

2Na⁺ + 2Cl⁻  + Pb²⁺  + 2NO₃⁻  → PbCl2 (s)  + 2Na⁺ +  2NO₃⁻

Answer:

Without the respiratory system your blood would be useless. The circulatory and respiratory systems work together to circulate blood and oxygen throughout the body

Explanation:

Sodium and chlorine are the two reactants and sodium chloride is the product.

Therefore, sodium and chlorine are reactants whereas sodium chloride is the product.

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Answer:

1)True

2)True

3)False

4)False

Explanation:

I tried and I hope u pass

Answer:

Products

Explanation:

The end results of a chemical reaction are called products

-> In chemistry, a product is a substance that is formed as the result of a chemical reaction.

-> Not many other ways to word this as it is a definition

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

Products

General Formulas and Concepts:

Reactions

Reactants and Products in RxNs

Explanation:

The substances used in a chemical reaction is called the reactants, usually located on the left side of the arrow (if pointing right).

The substances produced in a chemical reaction is called the products, usually located on the right side of the arrow (if pointing right).

RxN examples:

Reactant + Reactant → Product + Product

Reactant + Reactant → Product

Reactant → Product + Product

Topic: Honors Chemistry

Answer:

K = 0.167

Explanation:

The equilibrium constant, K of a reaction, is defined as the ratio of the concentrations of products and concentrations of reactants.

For the reactions:

A + B ⇄ C + D

For the definition, K is:

K = [C] [D] / [A] [B]

K = [4.0M] [4.0M] / [9.6M] [10.0M]

Answer:

Im pretty sure it is B. Earths temperature

Explanation:

AnswerDo you have a picture of the chart

Explanation:

Answer: your Answer is D. Increases

Explanation:

i. Ionic bond: bond between an anion and a cation. ii. Polar covalent: bond between atoms of the same element but different electronegativities. iii. Non-polar covalent: weak intramolecular bond. iv. Hydrogen: bond between the hydrogen atom in one molecule and a more electronegative atom in another molecule

Based on their properties, chemical bonds are classified into four major types. These include Ionic bonds, covalent bonds, polar covalent bonds, and hydrogen bonds. Some characteristics of the four types of chemical bonds are as follows:

i. Ionic bond: An ionic bond is formed when electrons are transferred from one atom to another atom. The resulting ions are attracted to each other and form an ionic bond. Ionic bonds are typically between metals and nonmetals.

ii. Polar covalent bond: Polar covalent bonds occur when atoms of the same element but different electronegativities bond. The atoms share the electrons unequally in a polar covalent bond, creating a partial positive charge on the less electronegative atom and a partial negative charge on the more electronegative atom. Polar covalent bonds typically occur between nonmetals.

iii. Non-polar covalent bond: Non-polar covalent bonds occur between two atoms of the same element or between different elements with the same electronegativity. The sharing of electrons between the atoms in a nonpolar covalent bond is equal. As a result, there is no net charge distribution across the molecule, and the bond is nonpolar. Nonpolar covalent bonds typically occur between nonmetals.

iv. Hydrogen bond: Hydrogen bonds are weak intramolecular bonds that occur between the hydrogen atom in one molecule and a more electronegative atom in another molecule. Hydrogen bonds are important in the secondary and tertiary structures of proteins and the structure of water.

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Answer:

204,375 mL.

Explanation:

327 mL - 3.2 M

x mL - 2 M

x= (2 M x 327 mL) /3.2 M

x= 204,375 mL.

Answer:

D

Explanation:

Answer:

D) Bacterium

Explanation:

From the equation we can see that

Moles of Fe=12

Moles of Fe_2O_3:-

\(\\ \sf\longmapsto \dfrac{12}{2}=6mols\)

As per the given balanced chemical equation, one mole of iron oxide gives 2 moles of metallic iron. Therefore, 6 moles of Fe₂O₃ is required to produce 12 moles of iron.

Iron is a transition metal showing variable oxidation states. Iron is highly reactive towards oxygen  and water. Iron reacts with oxygen gives iron oxide Fe₂O₃ which is an important ore of iron.

The reaction of iron oxide with carbon monoxide gives metallic iron and carbon dioxide. As per the given balanced chemical equation of this reaction 1 mole of Fe₂O₃ gives 2 moles of Fe.

Hence, number of moles of Fe₂O₃ required to produce 12 moles of Fe is calculated as follows:

Moles of Fe₂O₃ = 12/2 = 6 moles.

Therefore, 6 moles of Fe₂O₃ is required to produce 12 moles of Fe.

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Answer:

H2C2O2 + 2KOH ----- K2C2O4 + 2H2O

Answer:

Physical Properties of Hafnium Hafnium is a shiny and silvery metal exhibiting ductile features. It is usually resistant to corrosion and exhibits similar chemical properties to that of zirconium.

Atomic Mass: 178.49 g.mol −

1Atomic Number: 72Symbol: Hf

The cell potential for the electrochemical cell is 1.23 V when measured at 25°C and [Cd2+] = 10.00 M and [Ag+] 100 M.

The cell potential for an electrochemical cell can be calculated using the Nernst equation, which is given by:
Ecell = E°cell - (0.0592/n) × log(Q)

Where Ecell is the cell potential, E°cell is the standard cell potential, n is the number of moles of electrons transferred, and Q is the reaction quotient.

In this case, the half reactions for the cd/cd2+ and Ag/Ag+ half cells are:
Cd2+(aq) + 2e- -> Cd(s)  (reduction)
Ag+(aq) + e- -> Ag(s)  (reduction)

To calculate the cell potential, we need to find the standard cell potential (E°cell) and the reaction quotient (Q).

The standard cell potential (E°cell) can be found using the standard reduction potentials for the cd/cd2+ and Ag/Ag+ half cells. The standard reduction potential for the cd/cd2+ half cell is -0.40 V, and for the Ag/Ag+ half cell is +0.80 V.
E°cell = E°reduction (cathode) - E°reduction (anode)
= 0.80 V - (-0.40 V)
= 1.20 V

The reaction quotient (Q) can be calculated using the concentrations of Cd2+ and Ag+ ions.
Q = [Cd2+] / [Ag+]
 = (10.00 m) / (100 m)
 = 0.10

Now we can substitute the values into the Nernst equation to calculate the cell potential.

Ecell = 1.20 V - (0.0592/2) × log(0.10)
Ecell = 1.20 V - (0.0296) × log(0.10)
Ecell = 1.20 V - (0.0296) × (-1)
Ecell = 1.20 V + 0.0296
Ecell = 1.23 V

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Option C) RbOH, HBr cannot be mixed together to form a buffer solution is Correct. A buffer solution is a solution that resists changes in pH when small amounts of acid or base are added to it.

The ability of a solution to resist changes in pH is determined by the concentrations of the weak acids and bases present in the solution, as well as the concentration of the strong acid or base that is added to the solution. The weak acids and bases present in a buffer solution react with the strong acid or base to form a salt and water. The salt and water react to neutralize the strong acid or base, maintaining the pH of the solution.

In the case of RbOH and HBr, the weak base, RbOH, and the weak acid, HBr, cannot react with each other to form a salt and water. Therefore, they cannot form a buffer solution. The other pairs of solutions can form a buffer solution if the concentrations of the weak acids and bases present in the solutions are appropriate and the strong acid or base is added in the appropriate concentration.

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Answer:

The solution has a pH value of 9.3.

Explanation:

To solve this problem, we can first determine the H+ ion concentration and then use this value to calculate the pH. To find the H+ ion concentration from the OH- ion concentration, we should use Kw, which we know has a value of 1 * 10^(-14).

We can then use the following formula to solve for [H+]:

Kw = [H+][OH-]

10^(-14) = (2.02 * 10^(-5)) * [H+]

[H+] = 4.950495 * 10^(-10)

Now, we can find the pH using the formula pH = -log[H+].

pH = - log[H+]

pH = - log(4.950495 * 10^(-10))

pH = 9.3

Therefore, the correct answer is that the pH of the solution is 9.3. Note that an alternative way to solve the problem is to find the pOH from the OH- ion concentration and use the resulting value to determine the pH that way instead.

Hope this helps!

The concentration of NaOH in the diluted solution is 0.16 M (approximately).

To determine the concentration of NaOH in the diluted solution, we will use the formula below;

C1V1 = C2V2

where C1 = Concentration of stock solution

V1 = Volume of stock solution

C2 = Concentration of diluted solution

V2 = Volume of diluted solution

First, let us determine the concentration of NaOH in the stock solution.4.0g NaOH was dissolved in 5 mL of water.

The molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

Number of moles of NaOH = mass / molar mass

= 4.0 g / 40 g/mol

= 0.1 mol

The volume of solution = 5 mL

= 0.005 Litres

Molarity of the stock solution (C1) = number of moles of solute/volume of solution in litres

= 0.1 mol / 0.005 L

= 20 M

Now, we want to calculate the concentration of NaOH in the diluted solution.

4 mL of the stock solution was diluted to 500 mL of solution.

The volume of diluted solution (V2) = 500 mL

= 0.5 L

The volume of stock solution (V1) = 4 mL

= 0.004 L

The concentration of diluted solution (C2) = C1V1 / V2

= 20 M × 0.004 L / 0.5 L

= 0.16 M

Thus, the approximate concentration of NaOH in the diluted solution is 0.16 M. (approximately)

Therefore, the concentration of NaOH in the diluted solution is 0.16 M (approximately).

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Diffusion is the net movement of anything generally from a region of higher concentration to a region of lower concentration. Diffusion is driven by a gradient in Gibbs free energy or chemical potential.

1.  the final concentration of NaOH after adding 125 mL of water to 45.3 mL of 0.71 M NaOH solution is approximately 0.189 M.

2.  the final concentration of KOH after adding 550 mL of water to 125 mL of 3.01 M KOH solution is approximately 0.557 M.

1.) If 125 mL of water is added to 45.3 mL of a 0.71 M NaOH solution, the resulting solution will be a diluted NaOH solution. The addition of water will increase the total volume while reducing the concentration of NaOH. To determine the final concentration of NaOH, we need to consider the conservation of moles.

First, let's calculate the moles of NaOH in the initial solution:

moles of NaOH = volume (in L) × concentration (in M)

moles of NaOH = 0.0453 L × 0.71 M = 0.0321433 moles

After adding 125 mL (0.125 L) of water, the total volume of the solution becomes 0.0453 L + 0.125 L = 0.1703 L.

To find the final concentration, we divide the moles of NaOH by the total volume:

final concentration of NaOH = moles of NaOH / total volume

final concentration of NaOH = 0.0321433 moles / 0.1703 L ≈ 0.189 M

Therefore, the final concentration of NaOH after adding 125 mL of water to 45.3 mL of 0.71 M NaOH solution is approximately 0.189 M.

2.) If 550 mL of water is added to 125 mL of a 3.01 M KOH solution, the resulting solution will also be a diluted solution. Again, we will apply the conservation of moles to determine the final concentration of KOH.

First, calculate the moles of KOH in the initial solution:

moles of KOH = volume (in L) × concentration (in M)

moles of KOH = 0.125 L × 3.01 M = 0.37625 moles

After adding 550 mL (0.55 L) of water, the total volume of the solution becomes 0.125 L + 0.55 L = 0.675 L.

To find the final concentration, divide the moles of KOH by the total volume:

final concentration of KOH = moles of KOH / total volume

final concentration of KOH = 0.37625 moles / 0.675 L ≈ 0.557 M

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Answer:

the first statement is correct...

it only supports the main idea of the law of conservation of mass...

hope I can help you...