3. Do distilled water conduct electricity? What will happen if we add sugar to it and
then salt to it? Explain.

The density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

To determine the density of ammonia gas (NH3) in a 6.0 L container at a pressure of 820 mm Hg, we need to use the ideal gas law equation, which relates pressure, volume, number of moles, and temperature for a given gas.

The ideal gas law equation is:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we are given the pressure (820 mm Hg), volume (6.0 L), and assuming standard temperature and pressure (STP), we can use the values for R (0.0821 L·atm/(mol·K)) and convert the pressure to atm by dividing by 760 (1 atm = 760 mm Hg).

820 mm Hg / 760 mm Hg/atm = 1.08 atm

Now we can rearrange the ideal gas law equation to solve for density (d):

d = (P * M) / (RT)

Where M is the molar mass of ammonia (NH3), which is approximately 17.03 g/mol.

Substituting the values, we have:

d = (1.08 atm * 17.03 g/mol) / (0.0821 L·atm/(mol·K) * 298 K)

Simplifying the equation, we find:

d ≈ 0.805 g/L

Therefore, the density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

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Faults and problems in three routes of compound Br(bromide) synthesis, and the most feasible route, addressing competition, compatibility, and timing.

The main course includes a nucleophilic replacement of A with MeOH within the sight of HCl, trailed by parchedness with CS₂/Mel/heat. The fundamental issue with this course is the opposition between the replacement and end responses, which could prompt low yields of the ideal item.

The subsequent course includes a comparative nucleophilic replacement of A with MeOH within the sight of TsOH, trailed by a decrease with LiAlH₄. The fundamental issue with this course is the similarity between the acidic TsOH and the diminishing specialist, which could bring about the development of undesirable side items.

The third course includes an immediate buildup of A with ethyl oxalate within the sight of K₂CO₃, trailed by a decarboxylation with H₂SO₄. The fundamental issue with this course is the planning of the decarboxylation step, which could prompt the arrangement of undesirable side items because of overcompensation.

Generally speaking, the most possible course is by all accounts the first, with cautious advancement of the response conditions to limit the opposition among replacement and disposal responses.

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Answer:

Br-Ag-Br

Explanation:

The math expression for time taken = [(0.40) / (2.998 × 10⁸)] s

The speed of light = 2.998 × 10⁸ m/s

Distance travelled by light = 40 cm = 0.40 m

Time taken by the light to travel 0.40 m can be calculated as follows-

Speed of light = (Distance traveled by light) / (time taken)

So,

Time = (Distance traveled by light) / (speed of light) = (0.40 m) / (2.998 × 10⁸ m/s) = 1.334 × 10⁻⁹ s.

The speed of light in vacuum, ordinarily signified c, is a widespread actual steady that is significant in numerous areas of physical science. The speed of light c is precisely equivalent to 299,792,458 meters each second.

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The equilibrium will move to the left as the volume increases, favoring the reactants. The equilibrium will move toward the side of the reaction where there are fewer moles when the volume is reduced.

For reference:

According to Le Chatlier's Principle, a system in equilibrium will adjust to a change in temperature, volume, or the number of moles in a reactant or product in order to maintain equilibrium.

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Answer:

Maximum expected yield = 87.2%

Explanation:

Equations of reactions:

Main reaction: N₂O₄(l) + 2N₂H₄(l) ---> 3N₂(g) + 4H₂O(g)

Side reaction:  2N₂O₄(l) + N₂H₄(l) ----> 6NO(g) + 2H₂O(g)

Molar mass of N₂O₄ = 92 g/mol; molar mass of N₂H₄ = 32 g/mol; molar mass of N₂ = 28 g/mol; molar mass of of NO = 30 g/mol; molar mass of water = 18 g/mol

In the main reaction, 92 g of N₂O₄ reacts with 2 * 32 g of N₂H₄ to produce 3 * 14 g of N₂.

101.1 g of N₂O₄ will react with 2 * 32 * 101.1 / 92 g of N₂H₄ = 70.33 g of N₂H₄

N₂O₄ is the limiting reactant

101.1 g of N₂O₄ will react to produce 3 * 14 * 101.1 / 92 g of N₂ =  46.15 g of  N₂

In the side reaction, (6 * 30 g) of NO  is produced  from (2 * 92 g) of N₂O₄ and 32 g of N₂H₄

12.7 g of N₂O₄ will be produced from ( 2 * 92 * 12.7/180 g) of N₂O₄ and (32 * 12.7/180) g of N₂H₄ to produce

mass of N₂O₄ used = 12.98 g

mass of N₂H₄ used = 2.26 g

mass of N₂O₄ left for main reaction = 101.1 - 12.98 = 88.12 g

mass of N₂H₄ left for main reaction = 101.1 - 2.26 = 98.84 g

In the main reaction, 92 g of N₂O₄ reacts with 2 * 32 g of N₂H₄ to produce 3 * 14 g of N₂

88.12 g of N₂O₄ will react with 2 * 32 * 88.12 / 92 g of N₂H₄ = 61.30 g of N₂H₄

N₂O₄ is the limiting reactant.

88.12 g of N₂O₄ will to react produce 3 * 14 * 88.12 / 92 g of N₂ =  40.23 g of  N₂

Percentage yield = (theoretical yield/actual yield) * 100%

Percentage yield = (40.23/46.15) * 100% = 87.2%

Therefore, maximum expected yield = 87.2%

Answer: B. 430 K

Explanation:

According to Gibb's equation:

\(\Delta G=\Delta H-T\Delta S\)

\(\Delta G\) = Gibbs free energy  

\(\Delta H\) = enthalpy change  = +62.4 kJ/mol

\(\Delta S\) = entropy change  = +0.145 kJ/molK

T = temperature in Kelvin

\(\Delta G\)  = +ve, reaction is non spontaneous

\(\Delta G\)  = -ve, reaction is spontaneous

\(\Delta G\)  = 0, reaction is in equilibrium

\(\Delta H-T\Delta S=0\) for reaction to be spontaneous

\(T=\frac{\Delta H}{\Delta S}\)

\(T=\frac{62.4kJ/mol}{0.145kJ/molK}=430K\)

Thus the Reaction is spontaneous when temperature is 430 K.

Answer:

430 K

Explanation:

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Answer:

Sebacic acid is a naturally occurring dicarboxylic acid with the formula (CH2)8(CO2H)2. It is a white flake or powdered solid. Sebaceus is Latin for tallow candle, sebum is Latin for tallow, and refers to its use in the manufacture of candles.

Explanation:

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Molecules are in constant motion due to their thermal energy, which is related to their temperature.

As the molecules move faster, they are more likely to overcome the intermolecular forces that hold them together, causing them to break apart and become less cohesive. This can cause a solid to melt into a liquid, or a liquid to evaporate into a gas.

In summary, heating a substance increases the kinetic energy of its molecules, causing them to move faster, collide with one another with greater force, and spread apart from each other, resulting in an increase in volume and thermal expansion.

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The mass of the water that could be brought to the boiling point is equal to 4481.35 g. Therefore, option (C) is correct.

The specific heat capacity of a substance is defined as the quantity of heat required to increase the temperature in one unit of substance by one-degree Celcius.

Whenever the energy is lost or absorbed the temperature of the substance will be changed:

Q = mCΔT

Given, the amount of energy transferred, Q = 1500 Kj

The change in the temperature = 100 -20 = 80°C

The specific heat capacity of the water, C = 4.184 J/g°C

The mass of the water for the given change in temperatures can be calculated as:

1500 KJ = m × (4.184 J/g°C) × 80°C

m = 4481.35 g

Therefore, the mass of the water is 4481/35 grams.

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ANSWER

The mass of glucose in grams is 230 grams

EXPLANATION

Given information

The total volume of the solution = 1.5L

Follow the steps below to find the mass of glucose

Step 1: Convert the volume of the solution from L to mL

According to the standard conversion, 1L is equivalent to 1000mL

Let x represents the volume of the solution in mL

Hence, the volume of the solution in mL is 1500mL

Step 2: Find the mass of the glucose in grams

Hence, the mass of glucose in grams is 229.5 grams

The mass of the sodium sulfide required to remove the heavy metal is 1.3 * 10^-4 g.

We know that we have to first convert the concentration of the chromium (VI)ion to molarity and we have to use the formula;

Molarity = ppb * 1* 10^6/Molar mass

This would give us;

Molarity = 29.8 *  1* 10^-6/52 g/mol

= 5.73 * 10^-7 M

Number of moles of the chromium ion = 5.73 * 10^-7 M * 1 L

= 5.73 * 10^-7 moles

Since the reaction is 1:3

1 mole of chromium VI is required to react with 3 moles of sodium sulfide

5.73 * 10^-7 moles reacts with;

5.73 * 10^-7 moles *  3 moles/ 1 mole

= 1.72 * 10^-6 moles

Mass of sodium sulfide required = 1.72 * 10^-6 moles * 78 g/mol

=1.3 * 10^-4 g

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At low temperature and high pressure Ethane gas doesn't not behave like Ideal gas because of its larger molecular size.

Ideal gas is a theoretical gas composed of many randomly moving particles. Ideal gases are called as hypothetical gases which do not exist in nature. Gases exhibit ideal behavior at certain conditions. Ideal gases are assumed to have no interactions among the molecules. The volume of the gases is negligible with respect to the total volume. At low temperature and high pressures the molecules of a gas are very close at each other such that the volume of the gas molecules become significant. The interactions between the atoms become strong enough to affect their properties.

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Answer:

2 - Butyne

Explanation:

The name of the molecule with a carbon atoms arranged in a straight chain with a triple bond between the second and third carbons is 2 - Butyne.

2- Butyne is an alkyne with structural formula given below. Some of the properties of Butyne include it is a produced artificially, it is volatile and colorless in nature.

Hence, the given molecules described is 2 - Butyne.

they both refract white light.

Answer:

They both reflect white light.

Explanation:

How raindrops and prism are similar?

Raindrops and prisms are similar because they both cause light to bend when it enters a prism or raindrop. When light enters a raindrop it causes the light to bend (refract) and separates the white lights into different wavelengths, allowing us to see the individual colors of the rainbow.

Answer:

A. CODIS

Explanation:

The Combined DNA Index System (CODIS), administered by the FBI, maintains DNA profiles obtained through federal, state, and local DNA sample collection programs, and makes this information available to law enforcement agencies across the country for law enforcement identification purposes.

An example of heterogeneous equilibrium is:

Heterogeneous equilibrium refers to an equilibrium state in a chemical reaction where the reactants and products exist in different physical states or phases. It occurs when substances in different phases, such as solids, liquids, and gases, are involved in a chemical reaction.

Considering the given equations:

The equation I: FeO(s) + CO(g) ⇌ Fe(s) + CO₂(g) represents a heterogeneous equilibrium.

This is because the reactants and products involve different phases (solid and gas). FeO is a solid (s), CO is a gas (g), Fe is a solid (s), and CO₂ is a gas (g). The reaction involves the conversion of a solid and a gas to another solid and a gas, and the equilibrium is established between these different phases.

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The acid in the reaction would donate a proton and that would be HNO2.

An acid in a chemical reaction can be identified by the presence of hydrogen ions (H+): Acids are compounds that produce hydrogen ions when dissolved in water. In a chemical reaction, an acid may donate a hydrogen ion to another compound or accept a pair of electrons from a base.

When we look at the reaction, we can see that the specie that has given out the replaceable hydrogen ion is HNO2 thus it is the acid in the reaction.

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Scaling a life-size crime scene onto a sketch paper involves reducing the dimensions of the scene while maintaining accurate proportions.

Here's an example of how to do it:

Measure the dimensions of the crime scene (e.g., length and width) using a tape measure.

Determine the desired scale for the sketch (e.g., 1 inch represents 1 foot).

Calculate the reduction factor by dividing the length of the crime scene by the length on the sketch paper. For example, if the crime scene length is 30 feet and the sketch length is 10 inches (120 inches), the reduction factor would be 30/120 = 0.25.

Multiply all measurements of the crime scene (length, width, objects, distances) by the reduction factor to obtain the corresponding measurements for the sketch.

Transfer the scaled measurements onto the sketch paper using a ruler and appropriate drawing tools.

Citation: The procedure described above is a commonly used method for scaling objects or scenes in forensic science investigations. It is based on principles of measurement and proportion commonly employed in the field. No specific citation is provided since this is a widely used technique in forensic science practice.

Therefore, scaling a life-size crime scene onto a sketch paper involves reducing the dimensions of the scene while maintaining accurate proportions.

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The rate of a reaction refers to how fast or slow a reaction progresses over time. Option B is correct.

It is a measure of the change in concentration of reactants or products per unit of time. The rate of a reaction can be expressed in different units, such as moles per liter per second or grams per second. Factors that can affect the rate of a reaction include the concentrations of the reactants, the temperature, the presence of a catalyst, and the surface area of the reactants.

The rate law equation, which expresses the dependence of the reaction rate on the concentrations of the reactants, can also be used to determine the rate of a reaction under different conditions. The rate of a reaction is important for many applications, such as designing chemical reactions for industrial processes, optimizing reaction conditions in laboratories, and understanding biological processes that involve chemical reactions. Option B is correct.

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Answer: .819 Moles of Air

Explanation: To solve this problem, we will use the Ideal Gas Law which states that PV=nRT. P represents pressure or internal pressure, V is volume, T is temperature, n is moles of a gas, and R is the Universal Gas Constant. For the ideal gas law, R is .08206. R is 8.314 for any other calculation. We are solving for the moles of gas. The gas in this case is air which is a mixture of gases but that isn't important.

Our givens are P = 7.3 atm, V = 2.67 L and T = 17.0°C. We convert T to Kelvin because the Ideal Gas Law requires that. We simply add 273 to the value in Celcius to convert it to Kelvin. Our T is now 290 K. We also know R is our Universal Gas Constant. We can now plug into the law.

(7.3 atm)(2.67 L) = n(.08206)(290 K)

n = ((7.3 atm)(2.67 L))/(.08206)(290 K)

n = .819 moles of air

Hope this helps!

The balanced chemical equation for the reaction of sodium with water is  

2 Na + 2 H₂O  \(\rightarrow\) 2 NaOH +H₂

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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2.65g/ml is the density of a piece of granite whose volume is 20 mL and mass is 53grams. Density is the mass of a specific material per unit volume.

Density is the mass of a specific material per unit volume. Density is defined as d = M/V, in which d represents density, M is weight, as well as V is volume. Density is generally expressed in grams every cubic centimetre. Water, for example, has a density of 1 gram per square centimeter, but Earth has a density of 5.51 kilograms per cubic centimetre.

Density is sometimes measured in kilos per cubic centimeter (in metre-kilogram-second or SI units). The density of air, for example, is 1.2 kilos per cubic metre. 

density = mass / volume

            =53/ 20

            =2.65g/ml

Therefore, 2.65g/ml is the density of a piece of granite whose volume is 20 mL and mass is 53grams.

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Answer:

False; An oxidation-reduction is any chemical process that involves any chemical process in which elements undergo changes in oxidation number. hope that helps love!

The reaction becomes spontaneous at approximately 2667 Kelvin.

To determine the temperature at which a nonspontaneous reaction becomes spontaneous, we can use the equation ΔG = ΔH - TΔS, where ΔG is the change in Gibbs free energy, ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy.

In this case, we are given ΔH = 144 kJ/mol and ΔS = 54 J/K mol. To convert ΔH to J/mol, we multiply by 1000, giving us ΔH = 144,000 J/mol.

To find the temperature at which the reaction becomes spontaneous, we set ΔG to zero, as this is the condition for equilibrium. Thus, we have 0 = ΔH - TΔS.

Rearranging the equation, we have TΔS = ΔH, and substituting the given values, we get T * 54 J/K mol = 144,000 J/mol.

Dividing both sides by 54 J/K mol, we find that T = 144,000 J/mol / 54 J/K mol = 2667 K.

Therefore, the reaction becomes spontaneous at approximately 2667 Kelvin.

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