3) In measuring the volume of the cylinders, which dimension you should be more accurate about, the length or the diameter. Explain. 4) Why was the micrometer used instead of the vernier caliper to measure the diameter of the wire. 5) According to Legend, Archimedes, who was a famous Greek Mathematician, was given a crown, which was supposed to be made of pure gold but contained some silver alloy, by King Hieron II of Sicily. He was asked by the king to prove or disprove his suspicion. (The crown indeed did contain silver). If you were Archimedes, how would have determined experimentally whether or not the crown was pure gold?

The connection that requires transformers with two secondary windings providing equal voltages is called a center-tapped transformer configuration.

Center-tapped transformers have a primary winding and two secondary windings with a common center tap, which divides the secondary windings into two equal halves, this configuration is commonly used in various electronic and electrical applications. Center-tapped transformers offer several benefits, such as providing balanced voltages for applications like audio amplifiers and power supplies. They can also be used to generate two different voltage levels, allowing for greater flexibility in electronic circuits.

Additionally, center-tapped transformers enable the creation of a virtual ground or a reference point, which is essential in certain applications like push-pull amplifiers. In summary, center-tapped transformers with two secondary windings that provide equal voltages are essential for specific electronic and electrical applications, offering advantages like balanced voltage output, flexibility in voltage levels, and the creation of a virtual ground.

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Answer:

The backbone, spine or vertebral column is made up of 26 small bones called the vertebrae.

The characteristics of bones include:

1. They are strong and rigid

2. They are composed of bone cells called osteocytes.

3. They are lightweight

4. They have a honeycomb-like matrix internally, which helps to give them rigidity.

5. They exist in various types and shapes.

6. They have the ability to grow and repair when damaged

7. They contain inorganic minerals such as calcium and phosphate

The two types of joints are the movable and immovable joints.

Ligaments are bands of tough elastic fibrous tissue around that found around the joints whose function is to link bone to bone, give support to joints as well as limit their movement.

Explanation:

The backbone, spine or vertebral column is made up of 26 small bones called the vertebrae. The 26 small bones include 24 separate vertebrae interspaced with cartilage, and then additionally the sacrum and coccyx. The vertebral column is divided into five regions: cervical, thoracic, lumbar, sacral and coccygeal regions.

A bone is a rigid tissue that is part of the skeleton in vertebrate animals. The characteristics of bones include:

1. They are strong and rigid

2. They are composed of bone cells called osteocytes.

3. They are lightweight

4. They have a honeycomb-like matrix internally, which helps to give them rigidity.

5. They exist in various types and shapes.

6. They have the ability to grow and repair when damaged

7. They contain inorganic minerals such as calcium and phosphate

Joints are the junctions where two bones meet. They serve various functions which include allowing for movement of the body and binding the skeleton together.

The two types of joints are the movable and immovable joints.

Ligaments are bands of tough elastic fibrous tissue around that found around the joints whose function is to link bone to bone, give support to joints as well as limit their movement.

Answer:

5. Vertebrae

Explanation:

A back bone made up of 26 small bones is called a vertebrae.

Answer: Energy is released to the environment.

Explanation:

The student turns in all directions with a compass and the needle always points north is the best evidence would best support the student's claim that earth has a magnetic field. Hence option 'B' is correct.

The area where the force of the magnetism works around the magnetic material or even a flowing electric charge is known as the magnetic field. a diagram that shows the magnetic field and how the magnetic force can be spread inside and outside of a magnetic material.

Electric ions in motion are what generate magnetism. The smallest building blocks of matter are termed atoms. There are electrons in every atom, which are charged entities. The electrons that make up an atom's nucleus, or centre, spin like tops.

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For weightless object, gravity is equal to centripetal acceleration. The radius of the loop is calculated as 8 km.

The property of the motion of an object traversing a circular path is known as centripetal acceleration. Any object that is moving in circle and has an acceleration vector pointed towards center of that circle is Centripetal acceleration.

As Centripetal Acceleration formula is;

a = v²/r

Given, V-  velocity =  280 m/s

And we know that for weightless object,

Gravity =  centripetal acceleration

So, a =  g

given, g =9.8 m/s²

So,9.8 = 280²/r

r= 8000 m

Radius of the loop = 8 km

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Answer:

2.2467

Explanation:

Divide the value of time by a thousand

Rotation curves of galaxies imply the existence of dark matter because they show unexpected and anomalous behavior in the distribution of mass within galaxies.

The rotation curve of a galaxy describes the rotational velocity of stars or gas clouds at various distances from the galactic center. According to Newtonian physics, the rotational velocity should decrease with increasing distance from the center, as the gravitational pull weakens. However, observations have revealed that the rotational velocities remain constant or even increase with distance from the center, indicating the presence of additional mass beyond what is accounted for by visible matter. This discrepancy between the predicted and observed rotational velocities suggests the existence of unseen matter, commonly referred to as dark matter.

Dark matter does not emit or interact with light, making it invisible and difficult to detect directly. However, its gravitational effects can be observed through its influence on the motion of visible matter. The presence of dark matter provides the additional gravitational pull required to explain the observed high rotational velocities of stars and gas clouds in galaxies. Various astrophysical and cosmological studies, such as gravitational lensing and the cosmic microwave background radiation, further support the existence of dark matter.

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Answer:

The correct answer is 24.

Explanation:

An airplane moves 214 m/s as it travels around a vertical circular loop which has a radius of 1.8 km. The magnitude of the normal force on the pilot at the bottom of the loop is 4700 N.

To find the magnitude of the normal force on the pilot at the bottom of the loop, we need to consider the forces acting on the pilot. At the bottom of the loop, there are two main forces acting on the pilot: the gravitational force and the normal force.

The gravitational force is given by the formula F_gravity = m * g, where m is the mass of the pilot and g is the acceleration due to gravity (approximately 9.8 m/s^2).

The normal force is the force exerted by the surface (in this case, the seat) to support the weight of the pilot. At the bottom of the loop, the normal force will be directed upwards to counteract the gravitational force.

In this scenario, the pilot experiences an additional force due to the circular motion. This force is the centripetal force and is provided by the normal force. The centripetal force is given by the formula F_centripetal = m * a_c, where m is the mass of the pilot and a_c is the centripetal acceleration, which is v^2 / r, where v is the velocity of the airplane and r is the radius of the loop.

To find the normal force, we need to calculate the net force acting on the pilot in the vertical direction. At the bottom of the loop, the net force is the sum of the gravitational force and the centripetal force:

Net force = F_gravity + F_centripetal

The normal force is equal in magnitude but opposite in direction to the net force. So, the magnitude of the normal force at the bottom of the loop is:

Magnitude of normal force = |Net force| = |F_gravity + F_centripetal|

Substituting the given values, we have: m = 48 kg v = 214 m/s r = 1.8 km = 1800 m g = 9.8 m/s^2

F_gravity = m * g F_centripetal = m * (v^2 / r)

Net force = F_gravity + F_centripetal Magnitude of normal force = |Net force|

Plugging in the values and performing the calculations, we find that the magnitude of the normal force on the pilot at the bottom of the loop is 4700 N.

An airplane moves 214 m/s as it travels around a vertical circular loop which has a radius of 1.8 km The magnitude of the normal force on the 48 kg pilot at the bottom of the loop is 4700 N. This normal force is required to provide the necessary centripetal force for the pilot to move in a circular path.

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The magnitude of the normal force on the pilot at the bottom of the loop is 5275.2 N.

To determine the magnitude of the normal force on the pilot at the bottom of the loop, we need to consider the forces acting on the pilot. At the bottom of the loop, the pilot experiences two forces: the force of gravity (mg) and the normal force (N).

The force of gravity is given by the equation:

F_gravity = mg,

where m is the mass of the pilot and g is the acceleration due to gravity (approximately 9.8 m/s²).

The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, it is the force exerted by the seat of the airplane on the pilot. At the bottom of the loop, the normal force will be directed upward and must be large enough to balance the downward force of gravity.

To determine the magnitude of the normal force, we need to consider the net force acting on the pilot at the bottom of the loop. The net force is the vector sum of the gravitational force and the centripetal force.

The centripetal force is provided by the normal force, given by the equation:

F_centripetal = m * v² / r,

where v is the velocity of the airplane and r is the radius of the loop.

At the bottom of the loop, the centripetal force must be equal to the gravitational force plus the normal force:

F_centripetal = F_gravity + N.

Plugging in the values, we have:

m * v² / r = mg + N.

Rearranging the equation to solve for N, we get:

N = m * v² / r - mg.

Now we can substitute the given values:

m = 48 kg (mass of the pilot),

v = 214 m/s (velocity of the airplane),

r = 1.8 km = 1800 m (radius of the loop),

g = 9.8 m/s² (acceleration due to gravity).

N = 48 kg * (214 m/s)² / 1800 m - 48 kg * 9.8 m/s².

Calculating this expression, we find:

N ≈ 5275.2 N.

The magnitude of the normal force on the 48 kg pilot at the bottom of the loop is approximately 5275.2 N

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Answer:

7.45 Ω

Explanation:

From the question given above, the following data were obtained:

Resistor 1 (R₁) = 2.50 Ω

Resistor 2 (R₂) = 4.95 Ω

Voltage (V) = 12 V

Equivalent Resistance (Rₑq) =?

Since the resistors are in series arrangement, the equivalent resistance can be obtained as follow:

Rₑq = R₁ + R₂

Rₑq = 2.5 + 4.95

Rₑq = 7.45 Ω

Therefore, the equivalent resistance is 7.45 Ω

The current through the 2Ω resistor is 9.5A

The terminal voltage is 10.8 V

a) The voltage V across 8 Ω resistor is V = I*R = 8*0.5 = 4V

the current through 16Ω resistor is then I = V/R = 4/16 = 0.25 A

the current through 20Ω resistor is then I = current through 8Ω resistor + current through 16Ω resistor = 0.75 A

voltage across 20Ω is V = I*R = 0.75*20 = 15 V

the source voltage is Vs = V8 + V20 = 4+15 = 19 V

therefore the current through 2Ω resistor is

I = V/R = 19/2 = 9.5 A

b) The terminal voltage is

Vterminal = VR = I*R = 0.450*24 = 10.8 V

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Answer:

the ball ofc

Explanation:

the ball have a greater mass then the feather and it have the same speed as the feather

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance.

Of the following observations made of an unknown substance in a laboratory, the physical property is:

The substance has a melting point of 100 degrees Celsius.

The melting point is a physical property because it can be observed and measured without changing the identity of the substance. Other examples of physical properties include color, density, boiling point, conductivity, and solubility.

On the other hand, chemical properties describe the ability of a substance to undergo a chemical change or reaction, and can only be observed by changing the identity of the substance. Examples of chemical properties include flammability, reactivity, and acidity.

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If the resistance remains constant and the voltage doubles, the power will increase by a factor of 4 (option E)

The following data were obtained from the question:

P = V² / R

Resistance is constant, we have

V₁² / P₁ = V₂² / P₂

V² / P = (2V)² / P₂

V² / P = 4V² / P₂

Cross multiply

V² × P₂ = P × 4V²

Divide both side by V²

P₂ = P × 4V² / V²

P₂ = P × 4

From the above, we can conclude that the power will increase by a factor of 4 (option E)

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Answer:

72 km

Explanation:

The formula for Distance = Speed × Time

Speed = 10 m/s

1 metre per second = 3.6 kilometres per hour

10 metre per second =

10 metre per second = × 3.6 kilometres per hour/1 metre per second

= 36km/hr

How far he has travelled = Distance =

Speed × Time

= 36km/hr × 2 hrs

= 72 km

Answer:

La magnitud de la masa del peso es 78.447 libras-masa.

Explanation:

La tensión es una fuerza de reacción de la cuerda causada por la acción de una fuerza externa. En este caso, esa fuerza externa es el peso que cuelga en el centro de la cuerda. Abajo hemos adjuntado una representación simplificada del enunciado.

Por las leyes de Newton, tenemos la siguiente ecuación de equilibrio conformada por tres fuerzas:

\(\vec T_{1} + \vec T_{2} + \vec W = (0, 0)\, [N]\) (1)

Donde:

\(\vec T_{1}\), \(\vec T_{2}\) - Tensiones a cada lado de la cuerda, en newtons.

\(\vec W\)- Peso, en newtons.

Si sabemos que \(\vec T_{1} = T\cdot (\cos \alpha, \sin \alpha)\), \(\vec T_{2} = T\cdot (-\cos \alpha, \sin \alpha)\) y \(\vec W = W\cdot (0, -1)\), entonces tenemos la siguiente ecuación vectorial:

\(T\cdot (\cos \alpha, \sin \alpha) + T\cdot (-\cos\alpha, \sin \alpha) + W\cdot (0, -1) = (0,0)\)

\(T\cdot (0, 2\cdot \sin \alpha) = W\cdot (0, 1)\)

Esto permite reducir la anterior expresión a una fórmula escalar:

\(2\cdot T\cdot \sin \alpha = W\)

Donde \(\alpha\) es el ángulo de inclinación de la cuerda, medido en grados sexagesimales.

El ángulo de inclinación de la cuerda se determina mediante la siguiente fórmula trigonométrica inversa es:

\(\alpha = \tan^{-1} \left(\frac{2\,ft}{10\,ft}\right)\)

\(\alpha \approx 11.310^{\circ}\)

Si conocemos que \(\alpha \approx 11.310^{\circ}\) y \(T = 200\,lbf\), entonces la magnitud del peso es:

\(W = 2\cdot (200\,lb)\cdot \sin 11.310^{\circ}\)

\(W \approx 78.447\,lbf\)

En el Sistema Imperial, las fuerzas son medidas en forma gravitacional, entonces la magnitud de la fuerza gravitacional del peso equivale a la magnitud de su masa. En síntesis, la magnitud de la masa es \(78.447\,lbm\).

La magnitud de la masa del peso es 78.447 libras-masa.

Answer:

6.25 second

Explanation:

we know that

s= (u+v)/2*T

125=20t

t=6.25 second

plz mark as brainalist

The position of the particle at t = 10 seconds is approximately 〈1.491, 30〉 meters after all velocity and acceleration calculations.

There is a particle moving in the xy-plane, whose position can be represented as 〈x(t),y(t)〉=〈sin(2t),t^2−t〉 for 0 ≤ t ≤ 8 seconds. We can find its velocity and acceleration vectors using this position vector.

At t = 8 seconds, the particle starts moving in a straight line with the same velocity vector as it had at that time. Therefore, for t ≥ 8 seconds, we can find the position vector of the particle.

To find the position of the particle at t = 10 seconds, we need to substitute t = 10 in the equation of position vector for t ≥ 8 seconds. The position of the particle at t = 10 seconds is approximately 〈1.491, 30〉 meters.

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The function p(t) for the decay rate is an exponential decay curve. It satisfies the normalization condition, with the integral of p(t) over its domain equal to 1. The mean value of the decay time t is T, which is the mean lifetime. The expected standard deviation about the mean lifetime is also T.

a) I can describe the shape of the function p(t) for you. The function p(t) is an exponential decay function. It starts at a maximum value at t = 0 and decreases exponentially as t increases. The rate of decrease is determined by the mean lifetime T, where a smaller T corresponds to a faster decay rate.

b) To prove that the function satisfies the normalization condition, we need to show that the integral of p(t) over its entire domain is equal to 1. We integrate p(t) from 0 to infinity:

∫[0,∞] p(t) dt = ∫[0,∞] (1/T)\(e^(-t/T)\) dt

This integral evaluates to 1 when computed. Therefore, the function p(t) satisfies the normalization condition.

c) To prove that the mean value of the decay time t is T, we need to calculate the expected value of t, denoted as E[t]. We integrate tp(t) over the entire domain and divide by the normalization constant:

E[t] = ∫[0,∞] t(1/T)\(e^(-t/T)\) dt / ∫[0,∞] (1/T)e^(-t/T) dt

After performing the integration, we find that E[t] = T. Hence, the mean value of the decay time t is indeed T.

d) To prove that the expected standard deviation about the mean lifetime is also T, we need to calculate the expected value of\((t-T)^2\) and then take the square root. This will give us the standard deviation. Using a similar approach as in part (c), we perform the integration:

Standard Deviation = sqrt(∫[0,∞] \((t-T)^2 (1/T)e^(-t/T) dt / ∫[0,∞] (1/T)e^(-t/T) dt)\)

After evaluating the integral and simplifying, we find that the expected standard deviation is also equal to T.

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Answer:

KE=800,000

Explanation:

The formula for kinetic energy is KE=1/2mv^2 or Kinetic Energy= 0.5*mass*velocity^2

so 1000 is the mass and 40 is the velocity

KE=0.5*1000*40^2

KE=0.5*1,000*1,600

KE=800,000 Joules

Answer:

Acceleration occurs when an object changes its VELOCITY or DIRECTION or both

Explanation:

The final speed of the car after the first 4.00 s of acceleration is 13.9 m/s. Therefore, option (b) is correct.

The given problem involves determining the final speed after the first 4 seconds of acceleration. Thus, it is safe to assume that the car accelerated uniformly from rest.

The initial velocity of the car, u = 0 km/hr = 0 m/s

Final velocity of the car, v = 100 km/hr = 27.8 m/s

Time, t = 8.00 s

Acceleration, a = ?

We know that the distance traveled by the car (S) during uniform acceleration can be calculated using the following equation:

S = ut + 1/2 at² ……………….(1)

where u = initial velocity, a = acceleration, t = time, and S = distance traveled.

Substituting the values in the above equation, we get:

100,000 = 0 + 1/2 a (8.00)²a

              = 3.47 m/s²

Now, to determine the final speed of the car after 4 seconds of acceleration, we use the following equation:

v = u + at ……………….(2)

where v = final velocity, u = initial velocity, a = acceleration, and t = time.

Substituting the values in equation (2), we get:

v = 0 + 3.47 m/s² (4.00 s)v

  = 13.9 m/s

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Answer:

86.5 m

Explanation:

\(s = ut + \frac{1}{2} at {}^{2} \\ s = (0)(4.2) + \frac{1}{2} (9.81)(4.2) {}^{2} \\ s = 86.5m \)

Answer:

86.5 m

Explanation:

Law of attraction and Law of radius does not come in Kelper's law.

In astronomy, Kepler's legal guidelines of planetary movement, published via Johannes Kepler between 1609 and 1619, describe the orbits of planets across the solar. The laws changed the heliocentric theory of Nicolaus Copernicus, changing its circular orbits and epicycles with elliptical trajectories, and explaining how planetary velocities vary.

The elliptical orbits of planets were indicated through calculations of the orbit of Mars. From this, Kepler inferred that different our bodies within the solar device, including those farther far from the sun, additionally have elliptical orbits, the 2nd one law allows to set up that when a planet is toward the solar, it travels faster. The 3rd law expresses that the farther a planet is from the sun, the slower its orbital pace, and vice versa.

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Answer:

C. Talk test

Explanation:

The talk test would be readily available to me at the the least cost.

The talk test is about the easiest way that one can monitor intensity as they exercise. Because the only thing needed here is the ability to talk and to breathe.

The intensity lies on if one can talk and breathe at the same time. The harder one exercises, the more breathless they become and they find it difficult to talk.

Answer:

c

Explanation:

Explanation:

s = ut + 1/2at²

= 0(10) + 1/2×6.6×(10)²

= 3.3 × 100

= 330 m

The main answer to the given question is that the current in the 50.0-mH inductor is given by the equation i = 3.00t^2 - 7.00t, where i is in amperes and t is in seconds.

An explanation for this is that the current in an inductor is proportional to the rate of change of the magnetic field through the inductor. In this case, the magnetic field is changing with time as t increases. The equation given for the current is a polynomial function with a squared term and a linear term. This means that the rate of change of the magnetic field is increasing as time increases. At t=0, the current is -7.00A, and it increases with time. This can be seen by taking the derivative of the given equation, which gives the rate of change of the current with respect to time. Overall, the equation for the current in the inductor provides a mathematical description of the changing magnetic field and the resulting current in the circuit.

Your question is about finding the induced voltage across a 50.0-mH inductor when the current changes with time as i = 3.00t^2 - 7.00t, where i is in amperes and t is in seconds. To find the induced voltage (V) across the inductor, we will use the formula V = L * (di/dt), where L is the inductance and di/dt is the derivative of the current with respect to time.
Step 1: Identify the given values:
Inductance, L = 50.0 mH = 0.050 H
Current function, i(t) = 3.00t^2 - 7.00t
Step 2: Find the derivative of the current with respect to time:
di/dt = d(3.00t^2 - 7.00t) / dt = 6.00t - 7.00
Step 3: Use the formula V = L * (di/dt) to find the induced voltage:
V(t) = 0.050 * (6.00t - 7.00)
Step 4: Simplify the expression:
V(t) = 0.3t - 0.35So, the induced voltage across the 50.0-mH inductor is V(t) = 0.3t - 0.35 volts, where t is in seconds.

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Answer:

V = IR

Explanation:

I = 15 A

R = 8.0

V = 15 × 8

= 120V

The work required to make the satellite escape the Earth at point pp would be approximately 31.6 million joules.

To make the satellite escape the Earth, you would need to do work equal to its gravitational potential energy at that point (pp), which is given by the formula:

PE = (-GMm)/r

Where G is the gravitational constant, M is the mass of the Earth, m is the mass of the satellite, and r is the distance between the Earth's center and the satellite.

At point pp, the distance between the Earth's center and the satellite would be the same as the radius of the Earth (since the satellite is on the surface), which is approximately 6,371 kilometers.

Assuming a satellite mass of 1,000 kg, the work required to escape the Earth would be:

PE = -3.16 x 10⁷ J

So the work required to make the satellite escape the Earth at point pp would be approximately 31.6 million joules.

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