301017 Advanced Waste Management Week 1 Tutorial Questions Question 1 . The composition of solid waste from a residential community is as follows: Estimate (a) the moisture content, (b) the dens

Since the provided equation is inconsistent, it cannot intersect.

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two equations 3x + 5 and 14, which are separated by the 'equal' sign. A mathematical statement known as an equation is made up of two expressions joined together by the equal sign. A formula would be 3x - 5 = 16, for instance. When this equation is solved, we discover that the value of the variable x is 7.

Here,

we can see that the second set of equation,

4x+2y=12

20x+10y=30

4/20=2/10≠12/30

1/5=1/5≠2/5

The given equation is inconsistent so it does not intersect.

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Answer:

t = 6 km/hour

And, J would be 4 km per hour

Step-by-step explanation:

Let us assume the speed of Tom be T

And, the Speed of Jim  be J

Given that  

T - J = 2 km /hr ...........(i)

After 3 hours distance between them  = 30 km

As they are walking in the opposite direction

Thus,  

Net speed =T + J

L ÷ (T+J) = 3

30 ÷ (T+J) = 3

T +J =10 ..............(2)

After solving these two equations

2T = 12

t = 6 km/hour

And, J would be 4 km per hour

In this triangle, the product of tan A and tan C is `(BC)^2/(AB)^2`.

The given triangle ABC has angle A measuring 45 degrees, angle B measuring 90 degrees, and angle C measuring 45 degrees , Answer: `(BC)^2/(AB)^2`.

We have to find the product of tan A and tan C.

In triangle ABC, tan A and tan C are equal as the opposite and adjacent sides of angles A and C are the same.

So, we have, tan A = tan C

Therefore, the product of tan A and tan C will be equal to (tan A)^2 or (tan C)^2.

Using the formula of tan: tan A = opposite/adjacent=BC/A Band, tan C = opposite/adjacent=AB/BC.

Thus, tan A = BC/AB tan C = AB/BC Taking the ratio of these two equations, we have: tan A/tan C = BC/AB ÷ AB/BC Tan A * tan C = BC^2/AB^2So, the product of tan A and tan C is equal to `(BC)^2/(AB)^2`.

Answer: `(BC)^2/(AB)^2`.

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Answer:

10 apples

Step-by-step explanation:

1 apple = 5 pieces

2 apples = 10 pieces

Answer:

describing the data.

Step-by-step explanation:

It is required to find the third part of the process of investigating a question using data.

Answer: D

Step-by-step explanation: because if you divide the points (15 divided by 8=1.875), (17 divided by 10= 1.8) they will not have the same quotient. So they do not have the same ratios of coins to stamps

Answer:

The equation in slope-intercept form that represents the situation is y=0.25*x + 84 where y represents the temperature in ° F and x the number of chirps per minute.

Step-by-step explanation:

A linear equation can be expressed in the form y=m*x + b. In this equation, x and y are coordinates of a point, m is the slope and b is the y coordinate of the y-intercept. Since this equation describes a line in terms of its slope and its y-intercept, this equation is said to be in its slope-intercept form.

When there are two points of a line (x1, y1) and (x2, y2), the slope is determined by the quotient between the difference of the ordinate of these two points and the difference of the abscissa of the same points. This is:

\(m=\frac{y2-y1}{x2-x1}\)

Having a point on the line, you can substitute the values ​​of m, x and y in the equation y = mx + b and thus find b.

In this case:

So:

\(m=\frac{113-107}{116-92}\)

m= 0.25

substituting the values ​​of m, x1 and y1 in the equation y = mx + b you have:

107= 0.25*92 + b

107 - 0.25*92= b

84=b

The equation in slope-intercept form that represents the situation is y=0.25*x + 84 where y represents the temperature in ° F and x the number of chirps per minute.

A numeric variable is used with the VAR statement.

Given statement,

What type of variable is analyzed using a PROC TTEST? That is, what type of variable do we use with the VAR statement,

Here, we use;

→ Numeric Variable

Hence, a Numeric Variable type of variable is analyzed using a PROC TTEST.

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Component 3 must be started on day 197 to meet the delivery date of day 200.

To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.

(a) Backward schedule:

Operation    |  Work Center  |  Time (hours)  |  Start Day

--------------------------------------------------------

Final Assembly |   Work Center 1  |        1       |     200

Sub-assembly 1 |   Work Center 2  |        2       |     199

Component 4     |   Work Center 3  |        3       |     197

Component 2     |   Work Center 4  |        4       |     196

Component 3     |   Work Center 5  |        3       |     ????

(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.

From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.

Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.

Hence, component 3 must be started on day 197 to meet the delivery date of day 200.

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Answer:

The answer is y = 3x + 3.

Step-by-step explanation:

Hope it helped!

Answer:

276.67

Step-by-step explanation

\(\frac{830}{3} \)= 276\(\frac{2}{3} \)

or 276.67

Answer:

276.67

Step-by-step explanation:

830/3 = 276.7

The values of c for which y = C is a constant solution of y' = y² + 5y - 6 are 1 and -6.

Option d is the correct answer.

To find out the constant solutions of the equation (1), we need to first solve it. Let's solve equation (1) using separation of variables.

Separating variables in equation (1), we get:

dy / dx = y² + 5y - 6Now, multiplying both sides by dx, we get:

dy = (y² + 5y - 6) dxIntegrating both sides, we get:

∫ dy = ∫ (y² + 5y - 6) dxy = (y³ / 3) + (5y² / 2) - 6y + C1... (2)

where C1 is the constant of integration.

We can see that equation (2) is not in the form of y = f(x), which means we can't use it to find the values of c for which y = c is a constant solution of equation (1).

To convert equation (2) into the required form, we need to first simplify it.

Let's do that.Simplifying equation (2), we get:

y (y² + 5y - 12 / 3) + C1y (y² + 5y - 12) / 3 + C1

Now, for y = c to be a constant solution of equation (1), we have:

y (y² + 5y - 12) / 3 + C1 = c

Multiplying both sides by 3, we get:

y (y² + 5y - 12) + 3C1 = 3c

Rearranging, we get:y³ + 5y² - 12y - 3c + 3C1 = 0

Now, if y = c is a constant solution of equation (1), it means that equation (1) should be equal to 0.

So, we have:

y' = 0

On substituting y = c in equation (1), we get:(dy / dx) = c² + 5c - 6= 0

Solving the above equation, we get:

c = 1 and -6

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Answer:

8b + 7m + 4n = -10

Step-by-step explanation:

(8b + 8) + (7m – 2) + (4n + 4)

First thing to do is to try to open the brackets, so we have

8b + 8 + 7m - 2 + 4n + 4 =

Next, we collect like terms, so that we have

8b + 7m + 4n + 8 - 2 + 4 =

8b + 7m + 4n + 10 =

And rearranging, we have that

8b + 7m + 4n = -10

Answer:

3 pairs of shoes cost 189

Step-by-step explanation:

Oh yes it's quite simple but sort of difficult to explain, I'll try the best I can though!

in "C(x)" what ever is in the ( ) is the x value, so where they give you "C(3)" that means x=3. And since in this x represents number of shoes, that means the cost of three shoes is $189.

Hope this helps! If you have any questions about my answer feel free to ask. Stay safe!

Mean = 3.5

Median = 3

Distribution is negatively skewed.

What is skew in the distribution?

The distribution has no skewness if the mean and median are equal.

The median exceeds the mean in a favorably skewed distribution.

The distribution is also negatively skewed if the median is lower than the mean.

Given,

Data set : 1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 8

Mean = \(\frac{1+1+2+2+2+3+3+3+3+4+4+4+5+5+6+8}{16}\)

Mean = \(\frac{56}{16}\)

Mean = \(3.5\)

Median = mid value of the data set when the values are arranged in   ascending order

Here,

the two mid values = \(3, 3\)

Median = \(\frac{3+3}{2}\)

Median = \(\frac{6}{2}\)

Median = \(3\)

Now, as the mean is larger than the median therefore the distribution will be skewed negatively.

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The data in the distribution is positively skewed (skewed to the right). If the writer writes for two more days and creates 5 and 7 comic strips, respectively, the difference between the mean and the median for the new data set is 0.28.

ヾ(•ω•`)o

Answer:

This graph is NOT a function.

Step-by-step explanation:

A graph is a function only if there is exactly one y-value for every x-value. In this case, there are many x-values that have two y-values, making this graph not a function.

Let me know if this helps!

Answer:

\(a_{66}\) = 653

Explanation:

General formula: \(a_{n}\) = (\(a_{1}\) + ((term) - 1) · (common difference)

\(a_{66}\) = 3 + (66 - 1) · (10)

\(a_{66}\) = 653

Answer:

A. & E.

Step-by-step explanation:

A.) 4-4=0

B.) 4+4=8

C.) 1-2=-1

D.) 25-10=15

E.) 16+8=24

9514 1404 393

Answer:

  2/15

Step-by-step explanation:

The given expression for θ can be rewritten to ...

  5sin(θ + arctan(-3/4)) = 0

This will have solutions ...

  θ +arctan(-3/4) = nπ

  θ = nπ - arctan(-3/4) = nπ + arctan(3/4)

__

The corresponding values of sine and cosine will be ...

  sin(arctan(3/4)) = 3/5

  cos(arctan(3/4) = 4/5

or both values may be negative. Either sign will give the same result in the expression we're to find.

  (2sin(θ) -cos(θ))/(sin(θ) +3cos(θ)) = (2(3/5) -(4/5))/(3/5 +3(4/5))

  = ((6 -4)/5)/((3+12)/5) = 2/15

  \(\boxed{\dfrac{2\sin\theta-\cos\theta}{\sin\theta+3\cos\theta}=\dfrac{2}{15}}\)

The correct options for the values of a and b in the equation are a = 2 and b = -3/4

We shall use the negative sign before the bracket at the left hand side of the equation to open bracket as follows;

-(-2 + 3/3) = (- × -2) + (- × 3/4)

-(-2 + 3/3) = (+2) +(-3/4)

so the equation becomes;

7/8 -(-2 + 3/3) = (+2) +(-3/4) + 7/8.

Therefore, the correct options for the values of a and b in the equation are a = 2 and b = -3/4

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Thus he can cut it into six pieces

Answer:

its a commutative property becaus its just changing the order

Answer:

.15¢

Step-by-step explanation:

1.20$ total divided by 8 and its .15¢

Answer:

Step-by-step explanation:

Perimeter means the distance around the outside of your shape. So you need to add up all the sides.

The radical sides might look scary but when you are adding or subtracting you can basically treat them like variables. See image.

rad(8) + 3rad(8) + 5rad(8)

=9rad(8)

This is an answer. But you always have to simplify. And rad8 is not completely simplified. see image.

rad8 = rad4×rad2

The square root of 4 is 2.

rad8 = 2rad2

See image.

The original question answer is 9rad8

=9×2rad2

=18rad2

Given:

From the above expression,

The virtual condition for the .376² MMC pin with a perpendicularity tolerance of .008² diameter at MMC is approximately .001131.

To determine the virtual condition for a .376² MMC (Maximum Material Condition) pin with a perpendicularity tolerance of .008² diameter at MMC, we need to calculate the tolerance zone.

The perpendicularity tolerance specifies the allowable deviation of the pin from a perfect perpendicular orientation. The tolerance zone is defined as a cylindrical volume around the pin, with a diameter equal to the perpendicularity tolerance.

In this case, the perpendicularity tolerance is given as .008² diameter at MMC. Since the diameter at MMC is .376², we can calculate the tolerance zone as follows:

Tolerance zone = .008² * .376²

Simplifying the calculation:

Tolerance zone = .008 * (.376 * .376)

Tolerance zone = .008 * .141376

Tolerance zone = .001131

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Answer:

give me 2 minutes and I will

The predicted average test score for a classroom with 20 students is 432.28. The predicted change in the classroom average test score when going from 17 to 21 students is -24.91. The sample average test score is 414.22. The total sum of squares is 15405.

Let's go through each question and calculate the answers step by step

(a) To find the prediction for a classroom with 20 students, we substitute CS = 20 into the regression equation:

Test score = 556.828 - 6.2274 × 20

Test score = 432.28 (rounded to two decimal places)

(b) To find the prediction for the change in the classroom average test score when going from 17 students to 21 students, we subtract the predicted scores for each case:

Change in test score = (-6.2274 × 21) - (-6.2274 × 17)

Change in test score = -24.91 (rounded to two decimal places)

(c) The sample average class size is given as 22.90. To find the sample average of test scores, we substitute the average class size into the regression equation:

Test score = 556.828 - 6.2274 × 22.90

Test score = 414.22 (rounded to two decimal places)

(d) The total sum of squares (TSS) can be calculated using the formula TSS = n SER², where n is the number of observations and SER is the standard error of the regression. Since the number of observations is 103 and SER is given as 12.3, we have:

TSS = 103 × (12.3²)

TSS = 15405 (rounded to the nearest whole number)

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--The given question is incomplete, the complete question is given below " Suppose that a researcher, using data on class sizestudent submitted image, transcription available below(CS)and average test scores from 103 third-grade classes, estimates the OLS regression

Test scor = 556.828 - 6.2274CS, R^2 = .09, SER = 12.3

(a) A classroom has 20 students. The regression's prediction for that classroom's average test score is__ . (Round your response to two decimal places.)

(b) Last year a classroom had 17 students, and this year it has 21 students. The regression's prediction for the change in the classroom average test score is__ . (Round your response to two decimal places.)

(c) The sample average class size across the 103 classrooms is 22.90.The sample average of the test scores across the 103 classrooms is ___. (Hint: Review the formulas for the OLS estimators.) (Round your response to two decimal places.)

(d) The total sum of squares is ___ . (Hint: Review the formulas for thestudent submitted image, transcription available belowR2 andstudent submitted image, transcription available belowSER.) (Round your response to the nearest whole number.)"--