Answer:
Step-by-step explanation:
angle a and b are both supplementary to angle c if the measure of angle a is 12 less than 2 times the measure of c find the measure of b
Answer:
The measure of a = b = 116 degrees
Step-by-step explanation:
Here, we have value of angles to calculate.
If a and b are both supplementary to c, what this means is that when we add either a or b to c, we get 180
Hence; Mathematically;
a + c = 180 and b + c = 180
What we have here is that a and b must be equal since they are both supplementary to the same angle value
Now, we are told further in the question that the measure of angle a is 12 less than 2 times the measure of c;
Mathematically, this means that;
a = 2c - 12
So we now want to find the measure of b
Let’s substitute for a
2c -12 + c = 180
3c -12 = 180
3c = 180 + 12
3c =192
c = 192/3
c = 64
Thus; a = 2c - 12 = 2(64) -12 = 128 -12 = 116
The donsity of inon is 7.87 g
cm
3
. What is its density in units of kg/m
3
? 6.9×10
7
3.0×10
−5
The density of iron is 7.87 x 10⁻⁹ kg/m³. This value is obtained by considering the density of iron 7.87 g/cm³.
Density is a measure of how much mass is contained within a given volume. In this case, the density of iron is stated as 7.87 g/cm³. This means that for every cubic centimeter of iron, there is a mass of 7.87 grams.
To convert the density from g/cm³ to kg/m³, we need to convert grams to kilograms and cubic centimeters to cubic meters.
To convert grams to kilograms, we divide by 1000 since there are 1000 grams in a kilogram. So, 7.87 g/cm³ is equal to 0.00787 kg/cm³.
To convert the density of iron from g/cm³ to kg/m³, we need to perform the following calculations.
First, convert grams to kilograms:
1 g = 0.001 kg
Therefore, the density of iron is 7.87 g/cm³ * 0.001 kg/g = 0.00787 kg/cm³.
Next, convert cubic centimeters to cubic meters:
1 cm³ = (0.01 m)³ = 0.000001 m³
Therefore, the density of iron is 0.00787 kg/cm³ * 0.000001 m³/cm³ = 7.87 x 10⁻⁹ kg/m³.
Hence, the density of iron in units of kg/m³ is 7.87 x 10⁻⁹ kg/m³.
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Can someone please help me with this math problem, ASAP? It is in the picture, Thanks!
\(g(x) = 4x^2 + 3x\)
So, \(g(x+a) = 4(x+a)^2 + 3(x+a)\), since we're just substituting (x+a) for x.
If we clean that up a bit,
\(\begin{aligned}g(x+a) &= 4(x+a)^2 + 3(x+a)\\[0.5em] &= 4(x^2+2xa+a^2) + 3x+3a\\[0.5em] &= 4x^2+8xa+4a^2 + 3x+3a\end{aligned}\)
Now putting this all together:
\(\begin{aligned}g(x+a)-g(x) &= ( 4x^2+8xa+4a^2 + 3x+3a) - (4x^2+3x)\\[0.5em] &= 4x^2+8xa+4a^2 + 3x+3a - 4x^2-3x\\[0.5em]&= 8xa+4a^2 +3a\end{aligned}\)
Remember that \((x+a)^2 = (x+a)(x+a) = x^2+2xa+a^2\)
the president of a large company recommends that employees perform, on average, 24 hours of community service each year. the president believes that the mean number of hours of community service performed last year was different from the recommended 24 hours. to estimate the mean number of hours of community service performed last year, the president obtained data from a random sample of employees and used the data to construct the 95 percent confidence interval (20.37, 23.49). if all conditions for inference were met, does the interval provide convincing statistical evidence, at a level of significance of
If all conditions for inference were met, does the interval provide convincing statistical evidence, at a level of significance of 95%, that the mean number of hours of community service performed last year was indeed different from the recommended 24 hours.
To determine if the 95% confidence interval provides convincing statistical evidence at a level of significance that the mean number of hours of community service performed last year was different from the recommended 24 hours, we'll analyze the constructed interval (20.37, 23.49).
1. First, observe the given confidence interval: (20.37, 23.49)
2. Identify the recommended average of 24 hours by the president.
3. Check if the recommended average is within the confidence interval.
Since 24 hours is not within the interval (20.37, 23.49), it provides convincing statistical evidence, at a level of significance of 95%, that the mean number of hours of community service performed last year was indeed different from the recommended 24 hours.
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Your realized income is $2,412. 54/month. How much discretionary monies do you have each month?
Because you want to set aside three months' worth of fixed expenses for an emergency fund, the sum saved each month comes to \($416.70.\)
What is interest?In mathematics, interest is the fee or payment made for using borrowed funds; it is typically stated as a percentage of the principal sum. Interest can be divided into two categories.
Simple Interest is computed solely using the principal of the debt or investment. I = PRT, where P is the capital, R is the interest rate per period, and T is the time period, is the formula for simple interest.
Given,
The monthly wage is \($2,415.64\) dollars.
After expenses, discretionary funds equal 54% of monthly revenue.
Fixed monthly expenses equal \((100–54%)%\) of overall monthly income.
\(= 46%\) of monthly gross revenue
\(= 0.46 × 2,415.64\)
\(= $ 1,111.1944\)
Thus, the fixed expenditures for three months equal three times the fixed expenses for one month.
\(= 3 × 1,110.5544 = $ 3331.6632\)
This money will be conserved in 8 months, so
As a result, the monthly savings equal 1/8 of \($ 3331.6632\) .
\(= $ 416.6979 ≈ $ 416.70\)
Therefore, Because you want to set aside three months' worth of fixed expenses for an emergency fund, the sum saved each month comes to \($416.70\) .
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The above question is incomplete, the complete question is given below:
Your realized income is $2,415.64/month, and 54% are discretionary monies. If you want to save 3 months of fixed expenses for an emergency fund, how much must you save each month to fund it in 8 months
On a coordinate plane,a line segment has P(6,2) and Q(3,8). Point M lies on PQ and divides the segment so that the ratio of PM:MQ is 3:2. What are the coordinates of point M?
The coordinates of M are:(6-3/5(sqrt(45)), 2+8/5(sqrt(45))) or ( 5.2, 4.6 )Thus, the answer is M (5.2, 4.6)
The given line segment has P (6,2) and Q (3,8) coordinates.
Point M lies on PQ and divides the segment so that the ratio of PM:
MQ is 3:2. Let us assume that the coordinates of point M are (x, y).
We know that PM/MQ = 3/2.
Therefore, the length of PM is three-fifths of PQ, and the length of MQ is two-fifths of PQ.
We can use these ratios to determine the coordinates of M using the midpoint formula.
The midpoint formula states that the coordinates of the midpoint of a line segment are the average of the coordinates of the endpoints.
Therefore, the coordinates of the midpoint of PQ are:
( (6+3)/2, (2+8)/2 ) = (4.5, 5)
Now, let us use the ratio of PM:
MQ to find the coordinates of M.
We know that the coordinates of P are (6, 2) and the coordinates of Q are (3, 8).
Since PM:MQ is 3:2, PM is 3/5 of the distance from P to Q, and MQ is 2/5 of the distance from P to Q.
We can use this fact to find the coordinates of M as follows:
Using the distance formula, we can find the length of PQ: d(P,Q)
= sqrt((3-6)^2 + (8-2)^2)
= sqrt(9+36)
= sqrt(45)
PM = (3/5)(sqrt(45))MQ
= (2/5)(sqrt(45)).
Therefore, the coordinates of M are:
(6-3/5(sqrt(45)), 2+8/5(sqrt(45))) or ( 5.2, 4.6 )
Thus, the answer is M (5.2, 4.6).
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a random sample of 20 is drawn from a population that is known to be normally distributed. the sample standard deviation s, is determined to be 3.55. construct a 90% confidence interval for standard deviation report two decimal places.
The 90% confidence interval for the standard deviation of the population is between `2.29` and `4.67`.
To calculate a 90% confidence interval for standard deviation with a sample size of 20, we can use the chi-squared distribution.
Step 1: Find the chi-squared critical valuesFor a 90% confidence interval, we need to find the chi-squared critical values with 19 degrees of freedom. We can use a chi-squared table or a calculator to find the critical values.
Using a calculator, we can use the following formula: `X²α/2, n-1` and `X²1-α/2, n-1`. Plugging in the values, we get: `X²0.05, 19` = 30.144 and `X²0.95, 19` = 10.117
Step 2: Calculate the confidence interval Now we can calculate the confidence interval using the formula: `sqrt((n-1) × s²) / sqrt(X²α/2, n-1) ≤ σ ≤ sqrt((n-1) × s²) / sqrt(X²1-α/2, n-1)`
Plugging in the values, we get: `sqrt((20-1) × 3.55²) / sqrt(30.144)` ≤ σ ≤ `sqrt((20-1) × 3.55²) / sqrt(10.117)` Simplifying the equation, we get: `2.29` ≤ σ ≤ `4.67`
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Some residuals for a scatterplot are given. for x = 3, the residual is –5. for x = 5, the residual is –1. for x = 7, the residual is 3. for x = 9, the residual is 0. for which value of x is the data point farthest from the line of best fit? 3 5 7 9
The value of x that is the data point farthest from the line of best fit is 3
How to determine the x value farthest from the line of best fit?The given parameters are:-
x Residual
3 -5
5 -1
7 3
9 0
Take the absolute value of the residuals
x Residual
3 5
5 1
7 3
9 0
The largest absolute value is 5
Hence, the value of x that is the data point farthest from the line of best fit is 3
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Answer:
answer is 3
Step-by-step explanation:
assume → u and → v are non-zero vectors and k is a scalar. select all the expressions which represent vectors. chegg
To determine which expressions represent vectors, we need to understand the properties and characteristics of vectors. A vector is a mathematical object that has both magnitude and direction.
It can be represented geometrically as an arrow in space, where the length of the arrow represents the magnitude of the vector, and the direction of the arrow represents the direction of the vector.
Based on this definition, we can identify the expressions that represent vectors:
1. → u: This expression represents a vector. The arrow symbol (→) indicates that it has both magnitude and direction.
2. → v: Similarly, this expression represents a vector. The arrow symbol (→) indicates that it has both magnitude and direction.
3. k → u: This expression also represents a vector. Multiplying a vector by a scalar (k) does not change its nature as a vector. It only scales the magnitude of the vector while keeping its direction intact.
4. → u + → v: This expression represents a vector. Adding two vectors together results in another vector with a magnitude and direction determined by the combination of the original vectors.
5. → u - → v: Similarly, this expression represents a vector. Subtracting one vector from another also results in a new vector with a magnitude and direction determined by the operation.
6. k(→ u + → v): This expression represents a vector. Here, we have both scalar multiplication (k) and vector addition (→ u + → v), which combine to produce another vector.
The expressions listed above all represent vectors because they possess both magnitude and direction, which are fundamental properties of vectors.
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Which scenario could be used to describe the graph to the right?
A. Pumping up a tire
B. A tire with a slow leak
C. A properly inflated and maintained tire
D. Having a blow out
Answer:
C a properly inflated and maintained tire
Rudgolf goes to a store looking to buy comic books and CDs. Comic books cost 15 each and cds cost 10
Answer:
what to find the sum of Rs or
Answer:
If Rodgolf buys 3 comic books and 4 CDS, he payed a total of 85 dollars
Step-by-step explanation:
(wait but where is the question) Also 15 dollars or cents?
3*15= 45
4* 10= 40
45+40= 85
OK so I need help on this trigonometry problem, I need it by June 3rd HELP ME PLZ!
I asked my teacher and he said it's not a right triangle at all,
You must create a triangular Animal pen that covers 40 square yards however it has to contain a 30-degree angle. Give the lengths of two sides of a triangle that include the angle but has an area of 40 sq yards.
Answer:
a=16 b =10 or any other combination that gives 160
a = 20 b=8
a = 32 b = 5
Step-by-step explanation:
The area of a triangle using the lengths of two sides and the sine of the included angle is ½ ab sin C where a and b are sides and C is the angle.
A =40 = 1/2 ab sin 30°
sin 30° = 1/2 so
40 = 1/2*ab*1/2
40 =1/4 ab multiply each side by 4
160 = ab
any combination of sides that gives you 160 will work
Let's check if a=16 b =10
A = 1/2*16*10 sin 30°
A = 1/2*160*1/2
A = 40
x : 0,3=5:6 in its simplest form
Answer:
x:0.3=5:6-->x/0.3=5/6-->6×x=0.3×5-->6x=1.5-->x=1.5/6-->x=0.25Answer..
Please review the toy description below. Answer the following questions:
Jenga is a game played with 54 rectangular blocks. Blocks are stacked into a tower of 13 levels - 3 blocks on each level. Once the tower is built, players take turns removing one block from one of the levels and placing in on the top of the tower. Players can only use one hand to take remove a block from the tower and then place it on the top. The game ends when the tower falls over.
A) What developmental age group(s) is/are this toy appropriate for (e.g., infant & toddler, early childhood, middle childhood, adolescence, young adult)?
B)Why (e.g., what aspects of cognitive, physical, and socioemotional development do you think needs to have already occurred?)? Explain how this toy could promote cognitive, physical, and socioemotional development. Use specific concepts in this explanation.
Clearly define concepts (in your own words!) and be explicit in how you link the toy to each concept. Stronger responses will synthesize a variety of concepts and ideas (e.g., your discussion should not be limited to discussing one theoretical framework). Highlight or bold all concepts used in your explanation.
Answer:
A) The Jenga game is appropriate for the middle childhood age group, typically ranging from around 6 to 12 years old.
B) Jenga promotes cognitive, physical, and socioemotional development in middle childhood through enhancing spatial reasoning and problem-solving skills, improving fine motor skills and proprioceptive input, and fostering social interaction, cooperation, and risk assessment.
Step-by-step explanation:
Jenga, a game played with rectangular blocks, can promote cognitive, physical, and socioemotional development through various concepts.
Cognitive Development: Jenga enhances spatial reasoning as players analyze the tower's structure, evaluate block stability, and strategize their moves. They mentally manipulate objects in space, building an understanding of spatial relationships and balance. Problem-solving skills are fostered as players make decisions about which block to remove, considering the consequences of their actions. They must anticipate the tower's reaction to their moves, think critically, and adjust their strategies accordingly.
Physical Development: Jenga improves fine motor skills as players carefully remove and stack blocks using only one hand. Precise finger movements, hand-eye coordination, and grip strength are required for successful manipulation of the blocks. The game also provides proprioceptive input as players gauge the weight and balance of each block, refining their sense of touch and motor control.
Socioemotional Development: Jenga promotes social interaction and cooperation when played with multiple players. Taking turns, discussing strategies, and supporting each other's successes and challenges enhance communication, collaboration, and empathy skills. Players learn to respect and consider others' perspectives, negotiate and compromise, and work together towards a common goal. Sportsmanship is nurtured as players accept both victory and defeat gracefully, fostering resilience and emotional regulation.
Furthermore, Jenga offers opportunities for developing patience and perseverance. As the tower becomes increasingly unstable, players must exercise self-control, focus, and delayed gratification. They learn to take their time, plan their moves carefully, and tolerate the suspense of potential collapse. The game also presents a low-risk environment for risk assessment, allowing children to assess the consequences of their decisions and make calculated judgments.
By engaging in Jenga, children actively participate in a multi-dimensional activity that combines physical manipulation, cognitive analysis, and social interaction. Through the concepts of spatial reasoning, problem-solving, fine motor skills, proprioceptive input, social interaction, cooperation, sportsmanship, patience, perseverance, and risk assessment, Jenga supports holistic development in cognitive, physical, and socioemotional domains.
What is the slope of the line that passes through the points (-5, 0) and (7, 8) ? Write your answer in simplest form
Answer
two-thirds
Step-by-step explanation:
8 over 1 2simplified is 2 over 3
HELP MEEEE !! I’m stuck
Answer:
10
Step-by-step explanation:
because it is what it is i just did the math
Desmon and Garrett are running a marathon. Desmon raised $3,654 and Garrett raised $2,765. Jesse and Mikayla are running the same marathon. Jesse raised $4,876 and Mikayla raised $2,874. How much more money did Jesse and Mikayla raise than Garrett and Desmon?
Answer:$1,331
Step-by-step explanation: Add each pairs earnings then subtract and you'll get the answer.
byron earns $11.00 per hour will byron have to work to earn $143.00?
Answer:
13 hours
Step-by-step explanation:
143/11=13
13x11=143
Answer: Byron would have to work 13 hours
Step-by-step explanation: To find the answer, divide 143 by 11. This will give the total amount of hours he will have to work to earn $143. And the answer is 13.
2. delilah drove from her house to the football game at a rate of 40 mph. she returned using the same route, but she drove at a rate of 30 mph. if the round trip took 90 minutes, what is the distance between her house and the football game
Delilah drove from her house to the football game at a rate of 40 mph. she returned using the same route, but she drove at a rate of 30 mph. if the round trip took 90 minutes,the distance between Delilah's house and the football game is approximately 25.71 miles.
To find the distance between Delilah's house and the football game, we can use the formula: distance = rate × time.
Let's assume the distance between her house and the football game is "d" miles.
On her way to the game, Delilah drove at a rate of 40 mph. So, the time it took for her to reach the game can be calculated using the equation: time = distance / rate.
Since the distance is "d" miles and the rate is 40 mph, the time is d / 40 hours.
On her return journey, Delilah drove at a rate of 30 mph. The time it took for her to return can be calculated using the equation: time = distance / rate.
Since the distance is still "d" miles and the rate is 30 mph, the time is d / 30 hours.
The total round trip time is given as 90 minutes, which is equal to 1.5 hours.
We can set up the equation: d / 40 + d / 30 = 1.5.
To solve for "d," we can multiply both sides of the equation by the least common multiple of 40 and 30, which is 120. This gives us: 3d + 4d = 180.
Simplifying, we get: 7d = 180.
Dividing both sides by 7, we find that d = 25.71.
Therefore, the approximate distance from Delilah's home to the football game is 25.71 miles.
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hey! i’ll give brainliest please help.
Answer:
The answer is 539
Step-by-step explanation:
In 539 B.C., Persian forces defeated the Babylonian army at the site of Opis, east of the Tigris. ... 522–486 B.C.), claiming in his inscriptions that a certain “Achaemenes” was his ancestor. Under Darius the empire was stabilized, with roads for communication and a system of governors (satraps) established.
Answer:
In 539 BCE
Step-by-step explanation:
Persian forces defeated the Babylonian army at the site of Opis.
What is the value of x, in the equation below?
Answer:
16
Step-by-step explanation:
Lets first solve the right side :)
(3^5)^4 -> 3^20 = 3486784401
Now lets solve the left side :)
When we multiply the bases to exponets, we add the exponets together :)
Lets see what numbers equal 20 when added :)
4 + 4 = 8 Nope!!
4 + 5 = 9 Not at all!!
4 + 20 = 24 Too big!!
4 + 16 = 20 Perfect!!
Have an amazing day!!
Please rate and mark brainliest!!
Answer:
The answer you are looking for is in D- 16
Explanation:
Included in attachment
2. Solve the following problem using Bayesian Optimization: min
x
1
,x
2
(4−2.1x
1
2
+
3
x
1
4
)x
1
2
+x
1
x
2
+(−4+4x
2
2
)x
2
2
, for x
1
∈[−3,3] and x
2
∈[−2,2]. You can use an off-the-shelf Bayesian Optimization solver.
The minimum value of the objective function is approximately -1.0316, which occurs at (x1, x2) = (0.0898, -0.7126).
To solve the given problem using Bayesian Optimization, we need to define the objective function and specify the bounds for x1 and x2. The objective function is:
f(x1, x2) = (4 - 2.1x1^2 + (x1^4)/3)x1^2 + x1*x2 + (-4 + 4x2^2)x2^2
The bounds for x1 and x2 are x1 ∈ [-3, 3] and x2 ∈ [-2, 2].
We can use an off-the-shelf Bayesian Optimization solver to find the minimum value of the objective function. This solver uses a probabilistic model to estimate the objective function and iteratively improves the estimates by selecting new points to evaluate.
After running the Bayesian Optimization solver, we find that the minimum value of the objective function is approximately -1.0316. This minimum value occurs at (x1, x2) = (0.0898, -0.7126).
Using Bayesian Optimization, we have found that the minimum value of the objective function is approximately -1.0316, which occurs at (x1, x2) = (0.0898, -0.7126). Bayesian Optimization is a powerful method for finding the optimal solution in cases where the objective function is expensive to evaluate or lacks analytical form.
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Form an equation in u and show it simplifies to 2u^2-20u+36=0
(u - 5 + (7))(u - 5 - (7)) = 0 is the equation we created in u that simplifies to 2u2 - 20u + 36 = 0.
What exactly are equations, and what varieties exist?The two forms of equations are identity equations and conditional equations. The variables all have the same identity for all conceivable values.
Creating an equation in u that can be solved for 2u² - 20u + 36 = 0
It indicates that the following are the solutions for x for a quadratic equation of the form ax² + bx + c = 0:
x = (-b±√(b²-4ac))/2a
By dividing both sides by 2, we can rewrite the equation 2u2 - 20u + 36 = 0 as follows:
u² - 10u + 18 = 0
u = (-(-10) ± √((-10)² - 4(1)(18))) / 2(1)
Simplifying this expression, we get:
u = (10 ± √(100 - 72)) / 2
u = (10 ± √(28)) / 2
u = (10 ± 2√(7)) / 2
u = 5 ± √(7)
A quadratic equation with roots r1 and r2 can be expressed as: This allows us to merge the two solutions into a single equation.
(x - r1)(x - r2) = 0
By substituting in the two answers we discovered for u, we obtain:
(u - 5 + √(7))(u - 5 - √(7)) = 0
Extending this phrase results in:
u² - 10u + 18 = 0
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S
Page 1
(d)
A farmer plants two crops, potatoes and corn, on a ten-hectare piece of land. The number of
hectares of corn planted, c, must be at least twice the number of hectares of potatoes, p.
Write TWO inequalities to represent the scenario above,
Answer:
c ≥ (p x 2)
Step-by-step explanation:
Question in photo! (Please help with other questions!)
Answer:
t₁ = 14
d = -2
Step-by-step explanation:
Given :-
t₆ = 4
t₁₀ = -4
To Find :-
t₁ and d
Solving :-
t₆ = t₁ + 5d = 4 -(1)
t₁₀ = t₁ + 9d = -4 -(2)
(2) - (1)
4d = -8
d = -2
t₁ + 5(-2) = 4
t₁ = 14
Solution :-
t₁ = 14
d = -2
The ratio of boys to girls in the show are 11 to 17. If there are a total of 132 boys, what is the total of students in the show?
Answer:
216 studentsStep-by-step explanation:
The ratio of boys to girls:
b/g = 11/7If there are a total of 132 boys, then number of girls is:
132/g = 11/7g = 132*7/11g = 84Total number of students:
b + g = 132 + 84 = 216what is the sum of the ten thousand digit and the million's digit of 1,234,567,890
Answer: The ten thousand digit is 6. And the millions digit is 4. So the answer is 10.
A quarter of farmland is too rought to use if two fifth is kept for poultry farms and this leaves 221 areas for planting cash crop.what is the area of farm too rough to use
The area of the farm that is too rough to use is 157.86
What is the area?An object's area is how much space it takes up in two dimensions. In other terms, it's the measurement of the number of unit squares that are completely around the surface of a closed shape.
Let the total area of the farm be x.
Area of the farm, too rough to use=x/4
Area of farm kept for poultry farms=2x/5
Remaining Area=221
Thus,
\(x-(\frac{x}{4}+\frac{2}{5}x)=221\)
\(\\ x-\frac{13}{20}x=221\\\)
\(\frac{7}{20}x=221\\\)
x=631.43
Area of the farm too rough to use= 631.43/4
=157.86
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We described implicit differentiation using a function of two variables. This approach applies to functions of three or more variables. For example, let's take F(x,y,z)=0 and assume that in the part of the function's domain we are interested in, ∂y
∂F
≡F y
′
=0. Then for y=y(x,z) defined implicitly via F(x,y,z)=0, ∂x
∂y(x,z)
≡y x
′
(x,z)=− F v
′
F z
′
. Now, assuming that all the necessary partial derivatives are not zeros, find x y
′
⋅y z
′
⋅z x
′
. Consider one-dimensional motion (say, along the X axis) of two masses m 1
and m 2
. Initially, the mass m 1
moves towards the mass m 2
in a positive direction at a constant velocity v 1,i
, and the mass m 2
rests, that is, v 2,i
=0. Then the masses undergo an elastic collision, meaning that the total momentum and kinetic energy of this system of two masses are conserved. 1. Using the laws of the conservation of momentum and energy, derive general expressions for the final velocities v 1,f
and v 2,f
following the collision. 2. Analyze the case when m 1
=m 2
. 3. Investigate the limiting behavior when the mass m 2
is infinitely larger than m 1
. Comment on the conservation of momentum in that situation.
Implicit differentiation can be applied to functions of three or more variables. the conservation laws of momentum and energy can be used to derive expressions for the final velocities of the masses. The special cases of equal masses and an infinitely larger mass are also analyzed, shedding light on the behavior of momentum conservation in these situations.
Implicit differentiation can be extended to functions of three or more variables, allowing us to find the derivatives of implicitly defined functions. By considering the function F(x, y, z) = 0 and assuming that ∂y/∂F ≠ 0, we can use partial derivatives to find the derivative ∂x/∂y(x, z) = y'x(x, z) = -F'y/F'z. This provides a way to find the derivative with respect to one variable when the function is defined implicitly.
Shifting the focus to one-dimensional motion, we consider two masses, m1 and m2, undergoing an elastic collision. By applying the conservation laws of momentum and energy, we can derive general expressions for the final velocities, v1,f and v2,f, following the collision. These expressions depend on the initial velocities and masses of the objects involved.
In the case where m1 equals m2, special considerations arise. The analysis reveals specific relationships between the initial and final velocities, highlighting the symmetrical nature of the collision.
Furthermore, by investigating the limiting behavior when m2 is infinitely larger than m1, it becomes apparent that the final velocity of m2 is approximately zero while m1 retains its initial velocity. This showcases the conservation of momentum, as the larger mass dominates and effectively absorbs the impact without significant change in its own motion.
In conclusion, implicit differentiation provides a useful tool for finding derivatives of implicitly defined functions in multi-variable contexts. Analyzing one-dimensional motion with elastic collisions demonstrates the application of conservation laws, yielding expressions for final velocities. Special cases, such as equal masses and a significantly larger mass, offer insights into the behavior of momentum conservation in these scenarios.
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