36472 is a __% increase compared to 14921

Answer:

(-4, 1)

Step-by-step explanation:

x - 5(x + 5) = -9

x - 5x - 25 = -9

-4x - 25 = -9

-4x = 16

x = -4

y = -4 + 5

y = 1

Answer:

(-2, -6, -6)

Step-by-step explanation:

The center of the sphere, O, and point A, are located on the same diameter of the sphere, AB. Thus, the line segment joining these two points is the radius of the sphere. Therefore, the length of the line segment, OA = OB = r, where r is the radius of the sphere.

We can find the length of the line segment, OA, using the distance formula:

√((5 - 2)^2 + (1 + 3)^2 + (1 - 5)^2) = √(3^2 + 4^2 + (-4)^2) = √49 = 7

Since OA = OB = 7, the coordinates of B can be found by subtracting the radius, 7, from the x, y, and z-coordinates of point A:

B = (5 - 7, 1 - 7, 1 - 7) = (-2, -6, -6)Therefore, the coordinates of B are (-2, -6, -6).

Answer:

7

Step-by-step explanation:

Answer:

A few examples of regular polygons are a triangle, quadrilateral, pentagon, hexagon, heptagon, and a decagon.

Step-by-step explanation:

Hope it is helpful....

Answer:

RANGE: 120 - 160

Step-by-step explanation:

15*8 = 120

20*8 = 160

RANGE: 120 - 160

Part (c) is the correct option i.e. The total dealer's cost is $16588.36.

What is Percentage ?

Percentage, which is a relative figure used to denote hundredths of any quantity. Since one percent (symbolised as 1%) is equal to one hundredth of something, 100 percent stands for everything, and 200 percent refers to twice the amount specified.

Given, Cost paid for car's options = 82 % $3,098 = $2540.36

           Cost paid for base price = 85 % $15,480 = $13158.

           Destination charge = $890

∴ The total dealer's cost will be :

 = Cost paid for car's options +  Cost paid for base price +  Destination charge

=  $2540.36 + $13158 + $890

= $16588.36.

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The unit rate in teaspoons per pound would be 1/2 teaspoons per pound.

What is the unit rate?

A unit rate means a rate for one or something. We write this as a ratio with a denominator of one. For example, if you ran 70 yards in 10 seconds, you ran on average 7 yards in 1 second. Both of the ratios, 70 yards in 10 seconds and 7 yards in 1 second, are rates, but the 7 yards in 1 second is a unit rate.

The number of teaspoons:

                                      \(=1\frac{3}{4}\\\\=\frac{4+3}{4}\\\\=\frac{7}{4}\)

Amount of pasta:

                              \(=3\frac{1}{2}\\\\=\frac{6+1}{2}\\\\=\frac{7}{2}\)

Now the unit rate = number of teaspoons/ amount of pasta

                             \(=\frac{7/4}{7/2}\\\\=\frac{1}{2}\\\)

Hence, the unit rate in teaspoons per pound would be 1/2 teaspoons per pound.

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Answer:

Step-by-step explanation:

1/2

Answer:

C

Step-by-step explanation:

C

Answer:

x=17

Step-by-step explanation:

It is a right angle

so if we do

90-39=51

then we do 51/3

which will give us the answer of 17

3(17)= 51

39+51=90

Answer:

6.912 students did NOT choose a taco type out of the 72 students.

Step-by-step explanation:

I got the number of kids for 54.4% of 72 and 36%, and added them, then subtracted that from 72 to get the total amount

750 - 750 * 0.544 - 750 * 0.36 = 72.

3\(x^4\) + 1 is equivalent to \(x^{(4/2)}\) in terms of asymptotic growth rate. The value of 3\(x^4\) + 1 is O(\(x^{(4/2)}\)) and \(x^{(4/2)}\) is O(3\(x^4\) + 1).

To show that 3\(x^4\) + 1 is O(\(x^{(4/2)}\)), we need to find a constant C and a value of x such that:

|3\(x^4\) + 1| <= C|\(x^{(4/2)}\)|

For x >= 1, we can say that:

3\(x^4\) + 1 <= 4\(x^4\)

Taking the square root of both sides, we get:

sqrt(3\(x^4\) + 1) <= 2x²

Thus, we can choose C = 2 and x0 = 1, and we have:

|3\(x^4\) + 1| <= 2|\(x^{(4/2)}\)| for all x >= 1

Therefore, 3\(x^4\) + 1 is O(\(x^{(4/2)}\)).

To show that \(x^{(4/2)}\) is O(3\(x^4\) + 1), we need to find a constant C and a value of x such that:

|\(x^{(4/2)}\)| <= C|3\(x^4\) + 1|

For x >= 1, we can say that:

\(x^{(4/2)}\) <= x²

Thus, we can choose C = 1 and x0 = 1, and we have:

|\(x^{(4/2)}\)| <= |3\(x^4\) + 1| for all x >= 1

Therefore, \(x^{(4/2)}\) is O(3\(x^4\) + 1).

Since both 3\(x^4\) + 1 is O(\(x^{(4/2)}\)) and \(x^{(4/2)}\) is O(3\(x^4\) + 1).

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Answer:

(6,-2)

Step-by-step explanation:

The volume of water in the bowl when the ball is not completely submerged is 35984π - 4188.79π = 31795.21π cm³. and when the ball is completely submerged is 35984π cm³.

Case 1: The ball is not completely submerged:

To find the volume of water in the bowl when the ball is not completely submerged, we need to calculate the volume of the hemisphere and subtract the volume of the ball.

The radius of the hemisphere is half the diameter, so it is 52/2 = 26 cm. The volume of a hemisphere is given by (2/3)πr^3. Substituting the radius, we get (2/3)π(26^3) = 35984π cm³.

The radius of the ball is half the diameter, so it is 20/2 = 10 cm. The volume of a sphere is given by (4/3)πr^3. Substituting the radius, we get (4/3)π(10^3) = 4188.79π cm³.

Case 2: The ball is completely submerged:

When the ball is completely submerged, the volume of water in the bowl is equal to the volume of the hemisphere. Therefore, the volume of water in the bowl when the ball is completely submerged is 35984π cm³.

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The triangle that has the coordinates as A(0,-4) B(0,-9) C(-2,-5) is; A scalene Triangle

The formula for the distance between two coordinates is;

D = √[(y₂ - y₁)² + (x₂ - x₁)²]

Thus;

Distance AB = √[(-9 + 4)² + (0 - 0)²]

Distance AB = √25

Distance AB = 5

Distance BC = √[(-5 + 9)² + (-2 - 0)²]

Distance BC = √20

Distance CA = √[(-4 + 5)² + (-2 - 0)²]

Distance CA = √5

Since the three sides all have different lengths, then they the triangle is said to be a scalene triangle.

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Answer:

7 - 2m can be translated to "7 minus two times m" or "the difference between 7 and twice m".

3(m + 2) = 15 can be translated to "three times the sum of m and 2 is equal to 15" or "the product of 3 and the sum of m and 2 is 15".

To solve the equation, we can start by distributing the 3 on the left side:

3(m + 2) = 15

3m + 6 = 15

Then, we can subtract 6 from both sides:

3m + 6 - 6 = 15 - 6

3m = 9

Finally, we can divide both sides by 3:

3m/3 = 9/3

m = 3

Therefore, the solution to the equation 3(m + 2) = 15 is m = 3.

5m - m(2 - m) can be translated to "5m minus the product of m and the difference between 2 and m" or "the difference between 5m and m times the quantity 2 minus m".

To simplify the expression, we can use the distributive property to expand the second term:

5m - m(2 - m) = 5m - 2m + m^2 = m^2 + 3m

Therefore, the simplified expression is m^2 + 3m.

The total number of different paths which we can have as calculated from the given data is 6.

To know the number of different three-step paths along the edges of a cube are there that take us from vertex a  to vertex b.

For the first path no of different ways = 3

For the second path no of different ways = 2

For the third path no of different ways = 1

Therefore , the total number of ways

= 3 x 2 x 1

= 6

The solid three-dimensional shape also known as a cube has six square faces, eight vertices, and twelve edges. A cube is also known as a hexahedron.

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For 40 minutes you will pay P^(20).00. For 3 hours you will pay P^(30).00. and for 150 minuted you will pay P^(30).00.

The computer shop has a two-part pricing structure. For the first two hours or fraction of an hour, they charge a fixed rate of P^(20).00. This means that even if you use the computer for less than two hours, you would still be charged for two hours.

After the initial two hours, they charge an additional rate of P^(10).00 per hour or fraction of an hour. This additional charge applies to each succeeding hour beyond the first two hours.

In case (a), where you used the computer for only 40 minutes, you fall within the initial two-hour bracket, so you are charged for the full two hours at a rate of P^(20).00.

In case (b), where you used the computer for 3 hours, you are charged for the first two hours at a rate of P^(20).00 per hour and then an additional hour at a rate of P^(10).00 per hour. This adds up to a total charge of P^(30).00.

In case (c), where you used the computer for 150 minutes (2 hours and 30 minutes), you are charged for the first two hours at a rate of P^(20).00 per hour and then an additional 30 minutes at a rate of P^(10).00 per hour. This also adds up to a total charge of P^(30).00.

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Answer:

Step-by-step explanation:

Find the sketch of the triangle attached.

Area of the triangle = \(\frac{1}{2}|PQ| |PR| sinQPR\)

Given PQ = 20, PR = 12 and ∠QPR = 68°

Area of the triangle = 1/2 * 20 * 12 * sin68°

Area of the triangle = 120sin68°

Area of the triangle = 112.26 square units

Area of the triangle ≈ 112.3 square units (to the nearest tenth of a square unit)

Answer:

111.3

Step-by-step explanation:

Answer:

\(\huge\boxed{\sf AB = 8.86 \ cm}\)

Step-by-step explanation:

θ = 41°

Hypotenuse = BC = 13.5 cm

opposite = AB = ?

We will use the trigonometric ratio of sin.

\(\displaystyle sin \ \theta = \frac{opposite }{hypotenuse} \\\\sin \ 41=\frac{AB}{13.5} \\\\0.656 = \frac{AB}{13.5} \\\\0.656 \times 13.5 = AB\\\\8.86 \ cm = AB\\\\\boxed{ AB = 8.86 \ cm}\\\\\rule[225]{225}{2}\)

Answer:

sheeeeeeeeeeeeeeeeeeesh

Step-by-step explanation:

He walks 5/6 of a mile each day.

Multiply the distance each day by the number of days:

5/6 x 5

When multiplying a fraction by a whole number, multiply the numerator ( top number) by the whole number and leave the denominator ( bottom number as is)

5/6 x 5 = (5 x5)/6 = 25/6 now rewrite as a proper fraction:

25/6 = 4 1/6 total miles.

Answer:

4 1/6 miles over the course of 5 days

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Answer:

ok, here is your answer

Step-by-step explanation:

As the question and information provided do not have a specific part (a), (b), and (c) to be answered, I will provide a general approach to solving this problem.

Let's define the objective function and constraints of the given problem.

Objective function: To minimize the cost of producing Super and Regular gasoline

Cost = (price of High-Quality Fuel * amount purchased from High-Quality Fuel) + (price of Junk Petroleum * amount purchased from Junk Petroleum) + (cost of blending Super gasoline) + (cost of blending Regular gasoline)

Constraints:

- The total amount of Super gasoline produced should be less than or equal to the total amount of gasoline purchased

- The total amount of Regular gasoline produced should be less than or equal to the total amount of gasoline purchased

- The amount of High-Quality Fuel used to produce Super gasoline should be less than or equal to the total amount of High-Quality Fuel purchased

- The amount of Junk Petroleum used to produce Super gasoline should be less than or equal to the total amount of Junk Petroleum purchased

- The amount of High-Quality Fuel used to produce Regular gasoline should be less than or equal to the total amount of High-Quality Fuel purchased

- The amount of Junk Petroleum used to produce Regular gasoline should be less than or equal to the total amount of Junk Petroleum purchased

- The octane rating of Super gasoline should be greater than or equal to 96

- The octane rating of Regular gasoline should be greater than or equal to 87

- The lead content of Super gasoline should be less than or equal to 0.5 grams per litre

- The lead content of Regular gasoline should be less than or equal to 0.15 grams per litre

Now, we can set up the linear programming model for this problem and use software like Excel Solver or MATLAB to solve it and find the optimal values of the decision variables (H, J, S, R, HS, HR, JS, JR). The optimal solution will give us the minimum cost of producing Super and Regular gasoline while satisfying all the constraints.

The volume of this triangular prism is 270cm^3.

The volume of a triangular prism is given by the formula V = (1/2) * b * h * l, where b is the length of the base of the triangle, h is the height of the triangle, and l is the length of the prism.

In this case, we are given that the length of the base of the triangle is 10cm, the height of the triangle is 3cm, and the length of the prism is 18cm. Plugging these values into the formula, we get:

V = (1/2) * 10cm * 3cm * 18cm

V = (1/2) * 30cm * 18cm

V = 15cm * 18cm

V = 270cm^3

Therefore, the volume of this triangular prism is 270cm^3.

Note: The question is incomplete. The complete question probably is: What is the volume of this triangular prism where the length of the base of the triangle is 10cm, the height of the triangle is 3cm, and length is prism is 18cm.

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A)The probability of exactly four buses arriving in the next 2 hours is\($P(X=4)=e^{\wedge}(-2)\left(2^{\wedge} 4 / 4 !\right)=0.090$\) ≈ 0.090.

B) The probability of at least two buses arriving in the next 2 hours is =0.865

C)  The probability of no buses arriving in the next 2 hours is =0.135

d) The probability that it will be between 30 and 90 minutes before the next bus arrives is ,0.185

a) Let \($X$\) be the number of buses that arrive in a 2-hour period. Since the time between arrivals of buses follows an exponential distribution with a mean of 60 minutes, the arrival rate λ is given by\($\lambda=1 / 60$\) 0 buses per minute.

Therefore, the number of buses that arrive in a 2-hour period is a Poisson distribution with parameter \(\mu=\lambda t=(1 / 60) \times 120=2$.\). Thus, X has a Poisson distribution with parameter μ = 2.

The probability of exactly four buses arriving in the next 2 hours is\($P(X=4)=e^{\wedge}(-2)\left(2^{\wedge} 4 / 4 !\right)=0.090$\) ≈ 0.090.

b) The probability of at least two buses arriving in the next 2 hours is

\($P(X \geq 2)=1-P(X=0)-P(X=1)=1-e^{\wedge}(-2)\left(2^{\wedge} 0 / 0 !\right)-e^{\wedge}(-2)\left(2^{\wedge} 1 / 1 !\right)=0.865$.\)

c) The probability of no buses arriving in the next 2 hours is

\(P(X=0)=$ $e^{\wedge}(-2)\left(2^{\wedge} 0 / 0 !\right)=0.135$\)

d) Let Y be the time between the first and second bus arrivals. Then Y follows an exponential distribution with a mean of 60 minutes. We want to find the probability that \($30 \leq Y \leq 90$\).

This is equivalent to finding \(P(Y \leq$ $90)-P(Y \leq 30)$,\), which is equal to F(90) - F(30), where F is the cumulative distribution function of the exponential distribution with \($\lambda=1 / 60$\)

Therefore, the probability that it will be between 30 and 90 minutes before the next bus arrives is\(F(90)-F(30)=\left(1-e^{\wedge}(-90 / 60)\right)-(1$ $\left.e^{\wedge}(-30 / 60)\right)=e^{\wedge}(-1.5)-e^{\wedge}(-0.5)=0.185$\)

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Answer:

\(\huge\boxed{\sf A \approx 483.8 \ m^2}\)

Step-by-step explanation:

Radius = r = 14 m

Angle = θ = 283°

π = 3.14

Area of sector = A = ?

\(\displaystyle A = \frac{\theta}{360} \times \pi r^2\)

Put the given data in the above formula.

Finding area of sector:

\(\displaystyle A = \frac{283}{360} \times (3.14)(14)^2\\\\A = 0.786 \times 3.14 \times 196 \\\\A \approx 483.8 \ m^2\\\\\rule[225]{225}{2}\)

Answer:

1. 1/25 cm^2

2. 9/49 u^2

3. 121/64 in^2

4. 0.01 m^2

5. 12.25 cm^2

Step-by-step explanation:

Take each of the values and square them

EXAMPLE:

(1/5)^2 = 1^2/5^2=1/25

Also, INCLUDE UNITS