3x/8=15......will give brainliest

Step-by-step explanation:

He probably forgot to finish the equation.

he started right: 180° - 55° = 125°

but he should have continued 125° = a + b; a = 90° (right angle) b = 125° - 90° = 35°

The slope of the line is 7

What is the slope of the line ?

In mathematics, a line's slope is defined as the ratio of the change in the y coordinate to the change in the x coordinate.

Both the net change in the y-coordinate and the net change in the x-coordinate are indicated by y and x, respectively.

Consequently, the formula for the change in y-coordinate with respect to the shift in x-coordinate is

m = y/x = y/x = change in y/change in x

where "m" represents a line's inclination.

Additionally, the inclination of the line can be depicted by

tan θ = Δy/Δx

So, the slope of a line is brown.

A line's slope typically indicates the steepness and orientation of the line. Finding the difference between two locations, (x1,y1) and (x2,y2), makes it simple to calculate the slope of a straight line.

Slope of the line joining the points (\(x_{1}, y_{1}\)) and

(\(x_{2} ,y_{2}\)) is given by m= \(\frac{y_{2}-y{1}}{x_2-x_1}\)

The given points are (\(x_{1},y_1\)) =(3,-2) and

 (\(x_{2}, y_2\)) =(4,5)

Then, m= \(\frac{5+2}{4-3}=\frac{7}{1}\) =7                          

Hence, the slope is 7.

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Answer:m=1/3

Step-by-step explanation: Cuz I'm smart

Using Naïve Bayes multinomial with alpha=1, we classify the given messages based on their content. Message 4, "Tokyo Japan Chinese," is classified as spam.

To classify the messages using Naïve Bayes multinomial, we consider the content of the messages and their corresponding classifications. We calculate the probabilities of each message belonging to the "Normal" or "Spam" classes.

3 messages are classified as "Normal."

1 message is classified as "Spam."

We calculate the probabilities as follows:

P(Class = Normal) = 3/4 = 0.75

P(Class = Spam) = 1/4 = 0.25

Next, we analyze the occurrence of words in each class:

For the "Normal" class:

The word "Chinese" appears 5 times.

The word "Beijing" appears 1 time.

The word "Shanghai" appears 1 time.

The word "Macao" appears 1 time.

For the "Spam" class:

The word "Tokyo" appears 1 time.

The word "Japan" appears 1 time.

The word "Chinese" appears 1 time.

Now, we calculate the probabilities of each word given the class using Laplace smoothing (alpha=1):

P(Chinese|Normal) = (5 + 1)/(5 + 4) = 6/9

P(Beijing|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Shanghai|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Macao|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Tokyo|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Japan|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Chinese|Spam) = (1 + 1)/(3 + 4) = 2/7

To classify Message 4, "Tokyo Japan Chinese," we compute the probabilities for each class:

P(Normal|Message 4) = P(Chinese|Normal) * P(Tokyo|Normal) * P(Japan|Normal) * P(Class = Normal)

≈ (6/9) * (0/9) * (0/9) * 0.75

= 0

P(Spam|Message 4) = P(Chinese|Spam) * P(Tokyo|Spam) * P(Japan|Spam) * P(Class = Spam)

≈ (2/7) * (2/7) * (2/7) * 0.25

≈ 0.017

Since P(Spam|Message 4) > P(Normal|Message 4), we classify Message 4 as spam.

In summary, using Naïve Bayes multinomial with alpha=1, we classify Message 4, "Tokyo Japan Chinese," as spam based on its content.

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Using Naïve Bayes multinomial with alpha=1, we classify the given messages based on their content. Message 4, "Tokyo Japan Chinese," is classified as spam.

To classify the messages using Naïve Bayes multinomial, we consider the content of the messages and their corresponding classifications. We calculate the probabilities of each message belonging to the "Normal" or "Spam" classes.

3 messages are classified as "Normal."

1 message is classified as "Spam."

We calculate the probabilities as follows:

P(Class = Normal) = 3/4 = 0.75

P(Class = Spam) = 1/4 = 0.25

Next, we analyze the occurrence of words in each class:

For the "Normal" class:

The word "Chinese" appears 5 times.

The word "Beijing" appears 1 time.

The word "Shanghai" appears 1 time.

The word "Macao" appears 1 time.

For the "Spam" class:

The word "Tokyo" appears 1 time.

The word "Japan" appears 1 time.

The word "Chinese" appears 1 time.

Now, we calculate the probabilities of each word given the class using Laplace smoothing (alpha=1):

P(Chinese|Normal) = (5 + 1)/(5 + 4) = 6/9

P(Beijing|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Shanghai|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Macao|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Tokyo|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Japan|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Chinese|Spam) = (1 + 1)/(3 + 4) = 2/7

To classify Message 4, "Tokyo Japan Chinese," we compute the probabilities for each class:

P(Normal|Message 4) = P(Chinese|Normal) * P(Tokyo|Normal) * P(Japan|Normal) * P(Class = Normal)

≈ (6/9) * (0/9) * (0/9) * 0.75

= 0

P(Spam|Message 4) = P(Chinese|Spam) * P(Tokyo|Spam) * P(Japan|Spam) * P(Class = Spam)

≈ (2/7) * (2/7) * (2/7) * 0.25

≈ 0.017

Since P(Spam|Message 4) > P(Normal|Message 4), we classify Message 4 as spam.

In summary, using Naïve Bayes multinomial with alpha=1, we classify Message 4, "Tokyo Japan Chinese," as spam based on its content.

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The correct length of the missing part of the triangle would be = 10. That is option A.

The length of the smaller triangle = 20

The width of the smaller triangle = 16

The length of the bigger triangle = 20+X

The width of the bigger triangle = 24

But for similar triangles = 16/24 = 20/20+X

16(20+X) = 20×24

320+ 16x = 480

16x = 480-320

16x = 160

X = 160/16

X = 10

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The complete equation of the converted unit is 2.3 kiloliters = 23000 deciliters

From the question, we have the following parameters that can be used in our computation:

2.3 kiloliters = deciliters

Represent the blank with x

So, we have

2.3 kiloliters = x deciliters

By unit of conversion, we have

1 Kilo = 10 000 Deci

Using the above as a guide, we have the following:

x = 2.3 * 10000

Evaluate

x = 23000

Hence, the unit is 23000 deciliters

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Step-by-step explanation:

A

let's bring everything on the right hand side back under the square root :

8² = 64

(x³)² = x⁶

so, we get

sqrt(448x^c) = sqrt(64×7×x⁶×x) = sqrt(448×x⁷)

therefore, c = 7

B

similar to A let's bring everything on the right side under the cubic root :

4³ = 64

(x)³ = x³

cubic root(576x^d) = cubic root(64×9×x³×x²) =

= cubic root(576×x⁵)

therefore, d = 5

Answer:

x < 4

Step-by-step explanation:

Please see attached picture for full solution.

Answer:

i dont speak pig latin jfjdjhr r djsjdnzjjz

Answer:

1. Write a rule for the following rotation. Tell the degree and if it is cw or cow. Κ Β' PK B P' P Rotation is degrees about the origin.​

Step-by-step explanation:

1. Write a rule for the following rotation. Tell the degree and if it is cw or cow. Κ Β' PK B P' P Rotation is degrees about the origin.​

There are 34 integers in the given sequence. The formula for the nth term of an arithmetic sequence is: a_n = a_1 + (n - 1) d. We can use the formula for the number of terms of an arithmetic sequence: n = (a_n - a_1 + d)/d

The formula for the nth term of an arithmetic sequence is: a_n = a_1 + (n - 1) d. Where: a_1 = first term n = number of terms d = common difference a_n = nth term. The formula for the number of terms of an arithmetic sequence is: n = (a_n - a_1 + d)/d. We can use these two formulas to solve the given problem.

The given sequence is in arithmetic progression with common difference d = 6:17, 23, 29, 35, ..., 221Using the formula for the nth term of an arithmetic sequence: a n = a 1 + (n - 1)d Where: a 1 = first term n = number of terms d = common difference a n = 221We need to find n.

Here's the formula for the number of terms of an arithmetic sequence: n = (a n - a 1 + d)/d. Putting the values: n = (221 - 17 + 6)/6n = 204/6n = 34Thus, there are 34 integers in the given sequence.

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Answer:

\(m-4\\\)

Step-by-step explanation:

\(m-4\)

Answer:

  see below

Step-by-step explanation:

When you're doing a bunch of these, it is helpful to make a table with reminders as to how they're calculated. That table is shown below.

__

In the attached, we have used ...

  r² = x² +y²

  √20 = 2√5

  √36 = 6

  √25 = 5

and 1/(2√5) = √5/10. (The division is outside the radical.)

Answer:

its number 3

Step-by-step explanation:

Answer: y = 45x + 345

Step-by-step explanation:

Hope this helps!!! :)

It took 1700 J of work to stretch a spring from its natural length of 2 m to a length of 6 m. The spring constant k will be 212.5 N/m.

The potential energy stored in a spring is given by the formula:

PE = (1/2) kx^2

where k is the spring constant, x is the displacement from the equilibrium position, and PE is the potential energy.

In this problem, the spring is stretched from its natural length of 2 m to a length of 6 m, so the displacement is x = 6 m - 2 m = 4 m.

The work done on the spring is equal to the change in potential energy, so:

Work = PE final - PE initial

1700 J = (1/2) k(4² - (1/2) k(0)²

1700 J = 8k

k = 212.5 N/m

Therefore, the spring constant is 212.5 N/m.

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Answer:

x = -2

Step-by-step explanation:

-11x + 14 = 36

-11x = 36 - 14

-11x = 22

x = 22/-11

x = -2

Answer:

-2

Step-by-step explanation:

1. Subtract 14 from both sides.

2. Simplify 36−14 to 22.

3. Divide both sides by -11.

4. Simplify 22/11 to 2.

Answer: Inequality notation is < or ≥.

Step-by-step explanation:

EQUATION ONE: -5x + 7 > 47, x < -8

EQUATION TWO: -5x + 7 ≤ -43, x ≥ 10

Answer:

tan 45° = 1

Step-by-step explanation:

45° is a Special angle,so tan 45° = 1

or it's like the identity of tan

tan 45= sin45° ÷ cos45°

=√2/2 ÷ √2/2

=1

The yield to maturity on a simple loan for $1,500 that requires a repayment of $7,500 in five years' time is 37.14%.

Yield to maturity (YTM) is the total return anticipated on a bond or other fixed-interest security if the security is held until it matures. Yield to maturity is considered a long-term bond yield, but is expressed as an annual rate. In this problem, the present value (PV) of the simple loan is $1,500, the future value (FV) is $7,500, the time to maturity is five years, and the interest rate is the yield to maturity (YTM).

Now we will calculate the yield to maturity (YTM) using the formula for the future value of a lump sum:

FV = PV(1 + YTM)n,

where,

FV is the future value,

PV is the present value,

YTM is the yield to maturity, and

n is the number of periods.

Plugging in the given values, we get:

$7,500 = $1,500(1 + YTM)5

Simplifying this equation, we get:

5 = (1 + YTM)5/1,500

Multiplying both sides by 1,500 and taking the fifth root, we get:

1 + YTM = (5/1,500)1/5

Adding -1 to both sides, we get:

YTM = (5/1,500)1/5 - 1

Calculating this value, we get:

YTM = 0.3714 or 37.14%

Therefore, the yield to maturity on a simple loan for $1,500 that requires a repayment of $7,500 in five years' time is 37.14%.

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l...................................................

Answer:

p > -0.2222

Step-by-step explanation:

7p + 3(-6p + 2) > 7p + 9 +1

7p + (3*-6p + 3*2) > 7p + 10

7p - 18p + 6 > 7p + 10

-11p - 7p > 10 - 6

-18p > 4

p > 4/-18

p > -0.2222

Answer:

Step-by-step explanation: 23 is the median of the data set because it's the number in the middle.  

Median: 16, 18, 19,23, 24, 31, 32  

Mean: 16+18+19+23+24+31+32= 163 then divide by how many numbers you added by 163 divided by 7 equals 23.28571429. I'll just simplify it to 23.29 or rounding to tenths 23.3.

Answer:

Median = 23

Mean = 163/7 = 23.3 (1 d.p.)

Step-by-step explanation:

Given data set:

19, 18, 23, 24, 31, 32, 16

The middle value when all data values are placed in order of size.

Given data values in size order, from smallest to largest:

\(\sf 16, 18, 19, \boxed{\sf 23}, 24, 31, 32\)

The middle value is 23, so the median of this data set is 23.

The sum of all data values divided by the total number of data values.

\(\begin{aligned}\implies \sf mean & =\sf \dfrac{19+18+23+24+31+32+16}{7}\\& = \sf \dfrac{163}{7}\\ & = \sf 23.28571429...\\ & = \sf 23.3\:(1\:d.p.)\end{aligned}\)

When describing the central tendency for qualitative data, the measure that is commonly used is the mode.

Unlike quantitative data, where measures such as the mean or median can be used to describe central tendency, qualitative data consists of categories or labels rather than numerical values.

Therefore, the mode is the most appropriate measure for central tendency in this context.

The mode can be useful in summarizing qualitative data by identifying the most common category or response. It provides insight into the most prevalent characteristic or attribute among the data, allowing for a better understanding of the distribution and patterns within the dataset.


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Answer:

\(434\frac{6}{23}\)  

I hope this helps!

Answer:                          3 ¾

Step-by-step explanation:

                                                            3 ¾                              

The reason that best supports Statement 5 in the given proof is D. Substitution. Therefore, the correct answer is D. Substitution.

Substitution is a mathematical method used to replace one expression or variable in an equation or formula with another expression or variable that has an equivalent value.

This method involves using the properties of equality to make an equation or formula easier to solve.

For example, consider the equation 2x + 3y = 15. If we know that y = 4, we can substitute 4 for y in the equation and solve for x:

2x + 3y = 15

2x + 3(4) = 15

2x + 12 = 15

2x = 15 - 12

2x = 3

x = 3/2

Now,

Statement 5 is: (3x + 7) + (6x - 16) = 180.

The reason for this statement is that we are substituting the given angle measures of ABD and DBC into the equation for the sum of the measures of angles in a linear pair, which is 180 degrees.

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Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 4:

The line of regression is \(\hat y = a+bx\) where:

\(a=\overline y-b \overline x\)

\(b=\frac{r*s_y}{s_x}\)

We are given that \(\overline y=75\), \(s_y=8\), \(\overline x=280\), \(s_x=30\), and \(r=0.60\), therefore our slope, \(b\), is:

\(b=\frac{r*s_y}{s_x}\)

\(b=\frac{(0.60)(8)}{30}\)

\(b=0.16\)

Therefore, the slope of the regression line is 0.16, which can be used along with the values of \(\overline y\) and \(\overline x\) to find the constant \(a\):

\(a=\overline y-b \overline x\)

\(a=75-(0.16)(280)\)

\(a=30.2\)

This means our final regression line is \(\hat y = 30.2 + 0.16x\)

Problem 5:

The slope, \(b=0.16\), means that for every 1 point earned for a student's pre-exam total, their final exam score will increase by 0.16 points for each point they earned on the pre-exam.

Problem 6:

The y-intercept (or constant), \(a=30.2\), means that if a student's pre-exam total were 0, then they would expect to get a 30.2 on the final exam.

Problem 7:

\(R^{2}=(0.60)^{2}=0.36=36\%\)

Problem 8:

The fraction of variability (aka. coefficient of determination), \(R^2\), means that a certain proportion (or percentage) of the variance in the response variable can be explained by the explanatory variable. In context, this means that 36% of the variance in final exam scores can be explained by the pre-exam scores.

To filter observations that are more than 3 standard deviations from the mean in a given data set, you can use the Python code which calculates the mean and standard deviation and filters the observations accordingly.

To filter observations that are more than 3 standard deviations from the mean in a given data set, you can use the following Python code:

import numpy as np

# Sample data

data = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

# Calculate mean and standard deviation

mean = np.mean(data)

std_dev = np.std(data)

# Filter observations

filtered_data = [x for x in data if abs(x - mean) <= 3 * std_dev]

print(filtered_data)

This code uses the NumPy library to calculate the mean and standard deviation of the data set. It then filters the observations by comparing each value to the mean, excluding those that are more than 3 standard deviations away. The resulting filtered_data list contains the observations within the specified range.

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Answer: 17 times

Step-by-step explanation:

It takes 6 times for the first recipe (.25x6=1.5)

It takes another 11 times for the second recipe (.25x4=2 + .25x3 = 0.75)

You add 6 + 11 and get 17

Answer:

the amount that necessary to fund is $2,671.61

Step-by-step explanation:

The computation of the amount is shown below;

Given that

PMT = $270

NPER = 6 × 2 = 12

RATE = 6.2% ÷ 2 = 3.1%

FV = $0

The formula is shown below:

=-PV(RATE;NPER;PMT;FV;TYPE)

After applying the above formula the present value is $2,671.61

hence, the amount that necessary to fund is $2,671.61