4 (02.08 MC)Ler f(x) = 4x+x+ 1 and g(x) = x2- 2. Find a{f(x)). Show each step of your work

Answer:

20/45

6/45

Step-by-step explanation:

A bag contains 1 green, 4 red, and 5 yellow balls. Two balls are selected at random. Find P( 1 red and 1 yellow) and P(2 red).

--------------------

# of red/yellow pairs: 4*5 = 20

# of random pairs: 10C2 = 45

P(1red & 1yellow) = 20/45

# of red pairs: 4C2 = 6

# of random pairs = 45

P(2 red) = 6/45

well, the numeric difference will be 136 - 80 = 56, now, if we take 80 (original price) to be the 100%, what is 56 (the increase) in percentage off of it?

\(\begin{array}{ccll} amount&\%\\ \cline{1-2} 80&100\\ 56&x \end{array}\implies \cfrac{80}{56}=\cfrac{100}{x}\implies \cfrac{10}{7}=\cfrac{100}{x} \\\\\\ 10x=700\implies x = \cfrac{700}{10}\implies x = \stackrel{\%}{70}\)

Answer:

g(x)=x-2/x^2-9

If there is more than one value, separate them with commas.

Step-by-step explanation:

Answer:111.94

Step-by-step explanation:

'Percent (%)' means 'out of one hundred':

p% = p 'out of one hundred',

p% is read p 'percent',

p% = p/100 = p ÷ 100.

25% = 25/100 = 25 ÷ 100 = 0.25.

100% = 100/100 = 100 ÷ 100 = 1.

New value =

149.25 - Percentage decrease =

149.25 - (25% × 149.25) =

149.25 - 25% × 149.25 =

(1 - 25%) × 149.25 =

(100% - 25%) × 149.25 =

75% × 149.25 =

75 ÷ 100 × 149.25 =

75 × 149.25 ÷ 100 =

11,193.75 ÷ 100 =

111.9375 ≈

111.94

a. Category with the greatest frequency is 20 - 24

b. 14 students

c. The percentage is 7%

Frequency is simply described as the number of times an event or observation happened in a given study or experiment that is carried out.

From the information given, we have that;

a. The category with the greatest frequency is the one with most words spelt, we have;

20 - 24

b. The number of students that spelt 35 - 39 words is traceable to

14 students

c. If the total number of students is 200

Then, the percent of students in the 35 - 39 category is;

14/200 × 100/1

Multiply the values

7%

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Step-by-step explanation:

Improper fractions have a numerator that is larger than the denominator

1 = 6/6

 so  1  1/6  = 7/6

PART A: Linda has $4.41 more than Enrique after one year.

PART B: Enrique has $12.10 more than Linda after the second year.

PART A: After one year, we can calculate the amount of money each person has in their respective accounts.

For Linda's account:

Principal amount = $610

Interest rate = 1.2%

\(Interest $ earned = Principal $ amount \times (Interest rate/100) = $610 \times (1.2/100) = $7.32\)

\(Total $ amount after one year = Principal amount + Interest earned = $610 + $7.32 = $617.32\)

For Enrique's account:

Principal amount = $590

Interest rate = 3.9%

\(Interest $ earned = Principal amount \times (Interest rate/100) = $590 \times (3.9/100) = $22.91\)

Total amount after one year = Principal amount + Interest earned = $590 + $22.91 = $612.91

Comparing the two amounts, after one year Linda has more money.

The difference in the amount is:

$617.32 - $612.91 = $4.41

Therefore, Linda has $4.41 more than Enrique after one year.

PART B: After a second year, we need to calculate the amounts again.

For Linda's account:

Principal amount = $617.32

Interest rate = 1.2%

\(Interest earned = Principal amount \times (Interest rate/100) = $617.32 \times (1.2/100) = $7.41\)

Total amount after the second year = Principal amount + Interest earned = $617.32 + $7.41 = $624.73

For Enrique's account:

Principal amount = $612.91

Interest rate = 3.9%

\(Interest earned = Principal amount \times (Interest rate/100) = $612.91 \times (3.9/100) = $23.92\)

Total amount after the second year = Principal amount + Interest earned = $612.91 + $23.92 = $636.83

Comparing the two amounts, after the second year Enrique has more money.

The difference in the amount is:

$636.83 - $624.73 = $12.10

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Given statement solution is :- The present value of R13,000 per year invested for 8 years at 10% compound interest is approximately R69,776.60.

To calculate the present value of an investment with compound interest, we can use the formula for the present value of an annuity:

PV = A *\((1 - (1 + r)^(-n)) / r\)

Where:

PV = Present value

A = Annual payment or cash flow

r = Interest rate per period

n = Number of periods

In this case, the annual payment (A) is R13,000, the interest rate (r) is 10% per year, and the investment is made for 8 years (n).

Using the formula and substituting the given values, we can calculate the present value:

PV = \(13000 * (1 - (1 + 0.10)^(-8)) / 0.10\)

Calculating this expression:

PV = \(13000 * (1 - 1.10^(-8)) / 0.10\)

= 13000 * (1 - 0.46318) / 0.10

= 13000 * 0.53682 / 0.10

= 6977.66 / 0.10

= 69776.6

Therefore, the present value of R13,000 per year invested for 8 years at 10% compound interest is approximately R69,776.60.

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Answer:

81.86%

Step-by-step explanation:

We are given that the mean GPA of students in a course at UC Davis is 3.2 with a standard deviation of 0.3.

Assuming that the data follows normal distribution.

Let X = GPA of students in a course at UC Davis

So, X ~ Normal()

The z score probability distribution for normal distribution is given by;

                              Z  =   ~ N(0,1)

where,  = population mean GPA = 3.2

           = standard deviation = 0.3

Now, the probability that the students in the course have a GPA between 2.9 and 3.8 is given by = P(2.9 < X < 3.8)

       P(2.9 < X < 3.8) = P(X < 3.8) - P(X  2.9)

       P(X < 3.8) = P(  <  ) = P(Z < 2) = 0.97725

       P(X  2.9) = P(    ) = P(Z  -1) = 1 - P(Z < 1)

                                                        = 1 - 0.84134 = 0.15866

The above probability is calculated by looking at the value of x = 2 and x = 1 in the z table which has an area of 0.97725 and 0.84134 respectively.

Therefore, P(2.9 < X < 3.8) = 0.97725 - 0.15866 = 0.8186

Hence, 81.86% of students in the course have a GPA between 2.9 and 3.8.

9514 1404 393

Answer:

  an = 4×34^(n-1)

Step-by-step explanation:

If your recursive definition is ...

  \(\begin{cases}a_1=4\\a_{n}=34a_{n-1}\end{cases}\)

this defines a geometric sequence with a first term a1 = 4 and a common ratio of r = 34. The general form of the explicit function is ...

  \(a_n=a_1\times r^{n-1}\)

For the values shown here, the explicit definition of the sequence is ...

  \(\boxed{a_n=4\times 34^{n-1}}\)

The the vertices of reflected square, Q'R'S'T are Q' = (3, 1), R' = (-8, -2), S' = (-7, -7) and T' = (-2, -6)

A reflection is a mirror image of the shape. An image will reflect through a line, known as the line of reflection. A figure is said to reflect the other figure, and then every point in a figure is equidistant from each corresponding point in another figure.

Given that, a square QRST with vertices Q(-3, 1), R(8, -2), S(7, -7) and T(2, -6)

is reflected across y-axis, to form Q'R'S'T we need to find the vertices of reflected square.

We know that, rule of reflection over y-axis,

(x, y) → (-x, y)

Q' = (3, 1)

R' = (-8, -2)

S' = (-7, -7)

T' = (-2, -6)

Hence, the the vertices of reflected square, Q'R'S'T are Q' = (3, 1), R' = (-8, -2), S' = (-7, -7) and T' = (-2, -6)

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Answer:

Step-by-step explanation:

The distance between two points can be found by using the formula

\(d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\\)

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

Q (2,4) and R (-3,9)

The distance between them is

\( |QR| = \sqrt{ ({2 + 3})^{2} + ( {4 - 9})^{2} } \\ = \sqrt{ {5}^{2} + ( { - 5})^{2} } \\ = \sqrt{25 + 25} \\ = \sqrt{50} \\ = 5 \sqrt{2} \\ = 7.0710678...\)

We have the final answer as

Hope this helps you

The value of angle x in the triangle is 15°

Given: the triangle ABC with equal sides of 9 units.

Since the triangle has equal sides, it will also have equal angles (i.e. it is an equilateral triangle).

Thus, <A = <B = < C =  4x°

Since the sum of angles in a triangle is 180°. We have:

<A + <B + < C = 180°

4x + 4x + 4x = 180°

12x = 180

x = 180/12

x = 15°

Therefore, the value of x is 15°

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Answer: The sum of the numbers from 1 to 400 that are divisible by 11 is equal to $11 \cdot 666 = 7326$.

Step-by-step explanation:

To find the sum of all the natural numbers from 1 to 400 that are not divisible by 11, we can first find the sum of all the natural numbers from 1 to 400, and then subtract the sum of all the natural numbers from 1 to 400 that are divisible by 11.

The sum of the natural numbers from 1 to 400 is equal to $\frac{400 \cdot 401}{2} = 80150$.

There are 400/11 = 36 numbers that are divisible by 11 between 1 and 400, inclusive. The sum of these numbers is equal to $11 + 22 + 33 + \dots + 396 = 11(1 + 2 + 3 + \dots + 36)$. The sum of the first 36 natural numbers is equal to $\frac{36 \cdot 37}{2} = 666$. Therefore, the sum of the numbers from 1 to 400 that are divisible by 11 is equal to $11 \cdot 666 = 7326$.

Subtracting the sum of the numbers that are divisible by 11 from the sum of all the numbers from 1 to 400 gives us a final answer of $80150 - 7326 = 72824$. This is not equal to 35840, as stated in the problem.

Answer:

--------------------------------

Use the sum of the first n terms formula for an AP:

The sum of all natural numbers from 1 to 400:

The greatest natural number less than 400 but divisible by 11:

Sum of the numbers divisible by 11:

Sum of the numbers not divisible by 11:

Answer:

  (a)  $479.50

Step-by-step explanation:

You want to know how much the friend with the smaller bedroom will pay for rent if they split the $975 cost based on the square footage of each bedroom. The two bedrooms in the 1225 square foot property are 130 and 150 square feet.

Apparently, the cost of the non-bedroom area is to be split evenly. That common area is ...

  1225 ft² -(150 +130) ft² = 945 ft²

Then the proportion due from the occupant of the smaller bedroom is ...

  (945/2 +130)/1225 = 241/490 ≈ 0.49184

That fraction of the rent is ...

  0.49184 · $975 = $479.54

The nearest answer choice is $479.50.

__

Additional comment

If we were to assume the split is based only on bedroom size, then the rent paid for the 130 ft² space would be (13/28)($975) ≈ $452.68. This would be equivalent to splitting the rent for the common area in the same proportion as for the bedrooms.

We note that half the rent is $487.50, a number less than either of the last two answer choices. Those can be rejected for that reason. (The smaller bedroom is expected to pay less than half of the rent.)

Mean - this is the average. Add up the numbers and divide by the count of the numbers in the data set.

11+13+14+16+17+18+20+20+21+24+25+29 = 228

There are 12 numbers, so divide by 12.

228/12 = 19. The mean is 19.

Median - - - this is the MIDDLE number. Your data is already in numerical order (hooray!) so there are 12 numbers. Since it's even, we'll take the average of the 2 middle numbers. The 6th number is 18 and the 7th number is 20. The average of these is 19. So the median is 19.

(Side note: yes, median and mean can be the same.)

Mode - - - this is repeat/most common numbers! 20 repeats. 20 is the mode.

Range - - - biggest number is 29, littlest is 11. The range is 29-11 = 18.

Answers:

L = 64

W= 62

Explanation:

Answer:

The number of books sold were:

Math textbooks: 426
Sociology textbooks = 46

Step-by-step explanation:

Let us use the variable \(m\)  to represent the number of math books sold

Let us use the variable \(s\)  to represent the number of math books sold

Combined total of 426 math and sociology books were sold is represented by the equation:
\(m + s = 426\quad\quad\quad(1)\)

Number of math books sold was 46 more than the number  of sociology textbooks sold is given by
\(m - s = 46\quad\quad\quad(2)\)

Adding the equations (1) + (2):
\((m + s) + (m - s) = 426 + 46\\\\2m = 472\\\\m = \dfrac{472}{2}\\\\m = 236\\\\\)

Using Equation (1): \(m + s = 426\)  we get

\(236 + s = 426\\\\s = 426 - 236\\\\s = 190\)

Answer:

Step-by-step explanation:

divide length by 100

The maximum temperature during summer in that year was 34°C.

It's not possible for the maximum temperature in Gulmarg, Kashmir to rise by 44°C during the summer.

A temperature rise of that magnitude would be extremely unusual and potentially dangerous.

However, assuming that the question meant to ask about the difference between the minimum temperature in January and the maximum temperature in summer, we can proceed with the calculation.

The minimum temperature in January was -10°C, and if we add 44°C to it, we get:

-10°C + 44°C = 34°C

Therefore, the maximum temperature during summer in that year was 34°C.

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Answer:

Step-by-step explanation:

Exchange rates are the rates at which one currency can be exchanged for another currency. They represent the value of one currency relative to another currency.

Answer: Im pretty sure part A is 133$

Step-by-step explanation:

Answer:

a). slope = 0 so it is zero slope

b). slope = -3/2 , it is negative

c). slope is undefined

d). slope = 1/3 , it is positive

Step-by-step explanation:

The slope formula is slope = (y2-y1)/(x2-x1) keeping this in mind we will begin with a):

a): (-3,2) and (4,2)

2-2/4-(-3) = 0/7 = 0 -> this is your slope for a) and it is simply zero slope

b): (-1,3) and (1,0)

0-3/1-(-1) = -3/2 -> this is your slope for b) and it is negative

c): (1,2) and (1,4)

4-2/1-1 = 2/0 = undefined. this simply can not happen. if it was flipped it would be 0. (for example. 0/2 = 0 but 2/0 = undefined.) so your slope for c) -> undefined

d): (4,4) and (1,3)

3-4/1-4 = -1/-3 = 1/3 -> this is your slope for d) and it is positive because the negatives " - " cancels out.

Answer:

Divide both sides by the numeric factor on the left side, then solve.

Exact Form:

x=−7/2

Decimal Form:

x=−3.5

Mixed Number Form:

x=−3 1/2

Step-by-step explanation:

Answer:

- 3.5

Step-by-step explanation:

hope this helps :)

Then you can state that angle DEF is congruent to angle GHJ.

The postulate or theorem that allows you to state that angle DEF is congruent to angle GHJ is the Angle-Angle (AA) Postulate.

This postulate states that if two angles of one triangle are congruent to two angles of another triangle, then the third pair of angles must also be congruent.

In this case, if you have two triangles, one with angles DEF and the other with angles GHJ, and

you know that angle D is congruent to angle G and angle E is congruent to angle H, then by the AA Postulate, you can conclude that angle F is congruent to angle J.

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False.  No, extraneous variables should not be included as independent variables in the context of dependent sample designs.

In the context of dependent sample designs, extraneous variables should be controlled or accounted for in the study, but they should not be included as independent variables. This is because these extraneous variables are likely to be correlated with the dependent variable and including them would create an issue of multicollinearity that would affect the statistical analysis and interpretation of the results.

For example, when studying the effect of a new treatment on a group of patients, age, gender, and pre-existing health conditions may be considered as extraneous variables that should be controlled for, but not included as independent variables in the study. In this example, the formula for the regression analysis would be Y = β0 + β1X1 + β2X2 + e, where Y is the dependent variable, X1 and X2 are the independent variables, β0, β1, and β2 are coefficients, and e is the error term.

No, extraneous variables should not be included as independent variables in the context of dependent sample designs.

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Answer:

(2,4)

Step-by-step explanation:

I painfully counted every square to find that a 1 by 1 square is divided into an 8 by 8 square.

K is one square above 1/2, for the second coordinate is 4.

K is also 2 to the left of 0, so the first coordinate is 2.

Therefore, the coordinates of K are (2,4).