4. Over the span of a month, a school tracks student choices at lunch. They 1 point
find that 56% of all students buy milk with lunch and 32% buy a piece of
fruit. If 22% of all students buy both milk and fruit, which of the following
represents the percent of students who buy neither?

A. 0.28
B. 0.34
C. 0.42
D. 0.46

Step-by-step explanation:

Flip f(x) about the x-axis by multiplying it by -1

  - f(x)

  the squish it skinnier by multiplying it by 4

g(x) = - 4 f(x)   = -4 x^2

Answer:

0.3²+3

=3.27

Step-by-step explanation:

please mark me as brainliest

Answer:

C. y + 3 = ¼(x + 4)

Step-by-step explanation:

✔️First, find the slope of the given line on the graph that it is perpendicular to:

Slope (m) = ∆y/∆x = -4/1 = -4

Thus, the slope of the line that is perpendicular to the given line would be the negative reciprocal of -4.

The negative reciprocal of -4 = ¼

✔️Find the equation in point-slope form, y - b = m(x - a) using slope and a point on the line:

Substitute m = ¼, (a, b) = (-4, -3) into y - b = m(x - a):

y - (-3) = ¼(x - (-4))

y + 3 = ¼(x + 4)

Answer:

There is sufficient evidence at the 0.10 level of significance that the percentage is not 21 %.

Step-by-step explanation:

In this question we are told that A newsletter publisher believes that 21 % of their readers own a Rolls Royce. A testing firm believes this is inaccurate and performs a test to dispute the publisher's claim.

Thus;

Null hypothesis; H0: μ = 21%

Alternative hypothesis; Ha: μ ≠ 21%

Usually in hypothesis testing, we reject the null hypothesis when the p-value is less than the significance level.

Now, we are told that after performing a test at the 0.10 level of significance, the testing firm decides to reject the null hypothesis.

Thus, we can conclude that There is sufficient evidence at the 0.10 level of significance that the percentage is not 21 %.

So we can conclude that

The correct sequence of transformations that proves AMNO and APQR are congruent is: OAMNO was dilated by a factor of 3 about the origin, then reflected across the y-axis to form APQR.

The correct sequence of transformations that proves AMNO and APQR are congruent is:

OAMNO was dilated by a factor of 3 about the origin, then reflected across the y-axis to form APQR.

To see why, let's examine the properties of the two triangles:

Triangle MNO has vertices at (-2,-1), (-2,4), and (3,1).

Triangle PQR has vertices at (-6,-3), (-6,12), and (9,3).

If we dilate triangle MNO by a factor of 3 about the origin, we get a new triangle with vertices at (-6,-3), (-6,12), and (9,3). This is because each coordinate of MNO is multiplied by 3:

(-2,-1) -> (-6,-3)

(-2,4) -> (-6,12)

(3,1) -> (9,3)

If we reflect this new triangle across the y-axis, we get a new triangle with vertices at (6,-3), (6,12), and (-9,3). This is because the x-coordinates of each point are negated:

(-6,-3) -> (6,-3)

(-6,12) -> (6,12)

(9,3) -> (-9,3)

This final triangle, with vertices at (6,-3), (6,12), and (-9,3), is congruent to triangle PQR. Therefore, we have shown that AMNO and APQR are congruent.

This theorem relates to theorems previously studied in the sense that it involves transformations of geometric shapes, which is a fundamental concept in geometry. In real-world applications, these transformations can be used in computer graphics, architecture, and engineering, among other fields, to manipulate and analyze shapes and structures.

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Answer:

5 dolla footlong

Step-by-step explanation:

Answer:

15.25 is the better.

Step-by-step explanation:

you don't ounces divided by money.

Answer:

Answer:

8/4 + 4/4

Step-by-step explanation:

Try it im not good at math :( but hope it helps :(:

Answer:

40

Step-by-step explanation:

The 4 in 45 is 40 because it is in the tens place, 4 times 10= 40.  The 5 is 5 becasue it's in the ones place.  :)

It's just place value:

Answer:

The first digit i.e. 4 is called the tens' place. Here, there are 4 tens. The last or right digit i.e. 5 is called the ones' place. Therefore, in the number 45 = 4 tens plus 5 ones = 40 + 5 = 45

Answer:

333234

Step-by-step explanation:

333234$ for the next 4 years and the ecvation is 69$+-2$

The sketch of the front elevation and the side elevation of the prism are added as an attachment

From the question, we have the following parameters that can be used in our computation:

The prism

Using the figure as a guide, we understand that:

The front elevation is a rectangle of 2m by 0.5m

While the side elevation is a rectangle merged with a trapezoid

Next, we draw the elevations (see attachment)

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\(\begin{cases} f(x)=x^2-2x-15\\\\ f(x)=-x-9 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{they're equal to each other when}}{x^2-2x-15~~ = ~~-x-9}\implies x^2-x-6=0 \\\\\\ (x-3)(x+2)=0\implies x= \begin{cases} 3\\ -2 \end{cases} \\\\[-0.35em] ~\dotfill\)

\(\stackrel{\textit{substituting on the 1st equation}}{x=3\hspace{5em} f(3)=(3)^2-2(3)-15}\implies f(3)=-12 \\\\\\ \stackrel{\textit{substituting on the 1st equation}}{x=-2\hspace{5em} f(-2)=(-2)^2-2(-2)-15}\implies f(-2)=-7 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill {\Large \begin{array}{llll} (3~~,~-12)\hspace{5em}(-2~~,~-7) \end{array}}~\hfill\)

0.17 I hope this helps you:)

The standard deviation of the sampling distribution is approximately 0.3292.

The behaviour of the sampling distribution of the mean is described by the central limit theorem, a key conclusion in statistics. It asserts that regardless of how the population distribution is shaped, if a random sample of size n is taken from a population with mean and standard deviation, the distribution of sample means will tend towards a normal distribution as n increases.

Because it enables us to utilise the normal distribution to draw conclusions about the population mean based on sample means, the central limit theorem has significant practical ramifications. Additionally, it offers a foundation for confidence interval estimation and statistical hypothesis testing.

The standard deviation is given by the formula:

SD = σ/√(n)

Now, substituting the value of σ = 40, n = 147,400 we have:

SD = σ/√(n) = 40/√(147400) ≈ 0.3292

Hence, the standard deviation of the sampling distribution is approximately 0.3292.

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Answer:

3 months

a quarter is a period of three months

Step-by-step explanation:

Answer:

\(3\)

Step-by-step explanation:

\(\mathrm{Let\ the\ age\ of\ Sophia\ be\ }x\mathrm{\ and\ age\ of\ Mohal\ be\ }x+2.\\\mathrm{Given,}\\\mathrm{Product\ of\ their\ ages = 15}\\\mathrm{or,\ }x(x+2)=15\\\mathrm{or,\ }x^2+2x=15\\\mathrm{or,\ }x^2+2x-15=0\\\mathrm{or,\ }x^2+5x-3x-15=0\\\mathrm{or,\ }x(x+5)-3(x+5)=0\\\mathrm{or,\ }(x+5)(x-3)=0\\\mathrm{i.e.}\ x=-5\ \mathrm{or}\ 3.\)

\(x=-5\ \mathrm{is\ disgarded\ because\ age\ cannot\ be\ negative.}\\\mathrm{So\ the\ age\ of\ Shopia,\ }x=3\)

Answer:

The price of the shirt is $24.63.

Step-by-step explanation:

Let's assume the price of the shirt is x. Then the price of the wallet will be x - 15. We know that the total cost before tax is 34.26, so we can set up the equation:

x + (x - 15) = 34.26

Simplifying, we get:

2x - 15 = 34.26

Adding 15 on both sides:

2x = 49.26

Dividing by 2:

x = 24.63

Therefore, the price of the shirt is $24.63.

Answer:

area = 6 units²

perimeter = 10.06 units

Step-by-step explanation:

area = 1/2bh

area = 1/2(4)(3) = 6 units²

perimeter = 4.123 + 2.236 + 4.243 = 10.06 units

Answer:

The linear equation satisfying the given condition is,

\(x=t+15\)

where x is Ravi's age and t is the number of years

(after 10 years (t=10) his age becomes 25)

Step-by-step explanation:

Let x be Ravi's age

Now, his  current age is unknown, but if you add 10 to it, then it becomes 25, so

x + 10 =25

so, his current age is x = 25 =10

x = 15

Now, we find the linear equation satisfying the given condition,

Let t be the number of years that have passed since the present time

so, if 0 years have passed, his age will be 15 years

after 1 year, his age will be 16 years

after 10 years, his age will be 25 years and so on

so

\(x = t + 15\)

this satisfies the given condition, since if we add ten years i.e t = 10,

then we get 25

The equation is:

Work/explanation:

Here's the linear equation for Ravi's age.

Ravi's age is x.

If you add 10 to x you get x + 10.

That gives 25.

So the linear equation is x + 10 = 25.

x is 146 degrees

This is because angle y and angle x are supplementary, which means their measures add up to 180 degrees

180 - 34 = 146

Answer: x = 146°

Step-by-step explanation:

Given that y = 35°, Using linear pair

x+y = 180

x+35=180(Substitute value of y)
x=180-35(Transposition Method)

x=145°

To describe the center of the data, we can use either the mean or the median.

To describe the variation of the data, we can use either the range or the interquartile range (IQR).

Looking at the dot plot, it seems that the data is somewhat skewed to the right, with a few high-priced outliers. In this case, the median and the IQR may be more appropriate measures of the center and variation, respectively, as they are less sensitive to outliers.

To find the median and IQR:

Arrange the data in order from smallest to largest.

Find the median, which is the middle value. If there are an even number of values, take the average of the two middle values.

Find the first quartile, which is the median of the lower half of the data.

Find the third quartile, which is the median of the upper half of the data.

Calculate the IQR as the difference between the third quartile and the first quartile.

Here are the steps applied to the dot plot:

We can see that the smallest value is about 20 and the largest value is about 120, giving a range of 100 dollars.

The median is approximately 60 dollars, as it is the middle value between the 11th and 12th data points when the data is arranged in order.

The first quartile is approximately 40 dollars, as it isthe median of the lower half of the data points, which are found below the median.

The third quartile is approximately 80 dollars, as it is the median of the upper half of the data points, which are found above the median.

The IQR can be calculated as the difference between the third quartile and the first quartile, which is approximately 40 dollars.

Therefore, the most appropriate measures to describe the center and the variation for this data set are the median and the interquartile range (IQR), respectively. The median is approximately 60 dollars, and the IQR is approximately 40 dollars.

Answer:

A

Step-by-step explanation:

X can only have 1 input buy Y can have many

Answer:

0.1, 4/25, 35%, 36/100, 0.85, 2.6

Step-by-step explanation:

Answer:

209.25

Step-by-step explanation:

Calculate the areas of the triangle, rectangle, and half circle, then add them together:

triangle = 1/2bh = 1/2(6)(10) = 30

rectangle = bh = (14)(10) = 140

half circle = 1/2πr² = 1/2(3.14)(5)² = 39.25

radius = r = D/2 = 10/2 = 5

Total area = 30 + 140 + 39.25 = 209.25

Answer:

209.25 ft²

Step-by-step explanation:

To find the total area of the figure you have to add the areas of the triangle, rectangle and the semi circle.

Area of the triangle.

\( \sf \: A = \frac{1}{2} \times base \times height \\ \sf \: A = \frac{1}{2} \times 6 \: ft \times10 \: ft \\ \sf \: A = \frac{1}{2} \times 60 \: {ft}^{2} \\ \sf \: A =30 \: {ft}^{2} \)

Area of the rectangle.

\(\sf \: A =length \times width \\ \sf \: A =14 \: ft \times 10 \: ft \\ \sf A =140 \: {ft}^{2} \)

Area of the semi circle.

\( \sf \: A = \frac{1}{2} \pi {r}^{2} \\ \sf \: A = \frac{1}{2} \times \pi \times ( \frac{10}{2}) ^{2} \\ \sf \: A = \frac{1}{2} \times \pi \times {5}^{2} \\ \sf \: A = \frac{1}{2} \times \pi \times 25 \\ \sf \: A = \frac{1}{2} \times 3.14 \times 25 \\ \sf \: A = \frac{1}{2} \times 78.5 \\ \sf \: A = 39.25 {ft}^{2} \)

Add up all the areas to find the total area.

\( \sf \: Total \: Area = 30 {ft}^{2} + 140 {ft}^{2} + 39.25 {ft}^{2} \\ = 209.25 {ft}^{2} \)

Given that 16 families went on a trip and the cost of the trip was Rs. 2,16,352.The amount paid by each family is to be determined by unitary method Hence each family paid Rs.13522

Now, let's solve this by using the method of unitary method. To find the cost of 1 family trip, we will divide the total cost of the trip by the number of families.2,16,352 / 16 = 13,522 So, the cost of the trip per family is Rs. 13,522.Hence, each family paid Rs. 13,522 for the trip.

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Answer:

Step-by-step explanation

1. The total cost of the trip for all 16 families is Rs 2,16,352.
2. To find out how much each family paid, we need to divide the total cost by the number of families: Rs 2,16,352 ÷ 16.
3. When we do the division, we get the result: Rs 13,522.

Now let's check if this result is correct:

1. If each family paid Rs 13,522 for the trip, then the total cost for all 16 families would be: 16 × Rs 13,522 = Rs 2,16,352.
2. This is exactly the same as the total cost given in the problem statement.

So we have shown that each family paid **Rs 13,522** for the trip

Answer:

1:False

2:True

3:True

4:True

Answer:

(a) The average rate of change from 0 to 2 is 6

(b) The average rate of change from 3 to 5 is 24

(c) The average rate of change from -3 to 0 is -9

Step-by-step explanation:

The formula for the average rate of change (AROC) is given by:

\(AROC=\frac{f(b)-f(a)}{b-a}\)

(a):

Finding the AROC from 0 to 2

To find the average rate of change from 0 to 2, we use f(2) and f(0), while we plug in 2 for b and 0 for a:

\(\frac{f(2)-f(0)}{(2-0)}\\ \\\frac{((3(2)^2+4)-(3(0)^2+4))}{(2-0)} \\\\\frac{(16-4)}{(2)}\\ \\\frac{12}{2}\\ \\6\)

Thus, the average rate of change from 0 to 2 is 6.

(b):

Finding the AROC from 3 to 5:

To find the average rate of change from 3 to 5, we use f(5) and f(3), while we plug in 5 for b and 3 for a:

\(\frac{f(5)-f(3)}{(5-3)}\\ \\\frac{((3(5)^2+4)-(3(3)^2+4))}{(2-0)} \\\\\frac{(79-31)}{(2)}\\ \\\frac{48}{2}\\ \\24\)

Thus, the average rate of change from 5 to 3 is 24.

(c):

To find the average rate of change from -3 to 0, we use f(0) and f(-3), while we plug in 0 for b and -3 for a:

\(\frac{f(0)-f(-3)}{(0-(-3))}\\ \\\frac{((3(0)^2+4)-(3(-3)^2+4))}{(0+3)} \\\\\frac{(4-31)}{(3)}\\ \\\frac{-27}{3}\\ \\-9\)

Thus, the average rate of change from -3 to 0 is -9.

The area of the required shaded portion is 123 ft²

Given is figure having some shaded portion we need to find the area of the same,

So, the shaded portion is two right isosceles triangles with equal side measuring 14 ft and 7 ft,

So, to find the same, we will calculate the area of the triangles and add them,

Area of a triangle = 1/2 x base x height

Area of the shaded portion = 1/2 x 7 x 7 + 1/2 x 14 x 14

= 122.5 ft²

≈ 123 ft²

Hence the area of the required shaded portion is 123 ft²

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