!!45 points!! True or false;

A quadratic graph cannot show more than one translation, reflection, stretch or shrink at a time, from the graph of the parent function.

Thus, the test for homogeneity follows the same procedures as the test for independence because the assumptions for performing the chi-square test for independence and chi-square test for homogeneity are the same.

The procedures for the chi-square test of homogeneity are the same as for the chi-square test of independence. The data is different for both tests. Tests of independence are used to determine whether there is a significant relationship between two categorical variables from the same population. One population is segmented based on the value of two variables. So there will be a column variable and a row variable.

The chi-square test of homogeneity of proportions can be used to compare population proportions from two or more independent samples, determining whether the frequency counts are distributed identically among different populations.

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Answer:

answer is [(-5)+6]+6]+(-3)=4

Replace x and y’all with the point and solve the equations

1. 2(0.5)+ 4(-6.75) = 1 + -27 = -26

This is true so is an answer.

2. Y = 0.5-7.5 = -7, -7 is not -6.75 so this is not true.

3. 2(-6.75) = 0.5 + 13

13.5 = 13.5

This is true so is also an answer.

4. -6.75 = 0.5(0.5) -7

-6.75 = 0.25-7

This is true so also an answer.

Answers are 1, 3 and 4

Answer:

Equation 1 and 4

Step-by-step explanation:

Point = (x,y) = (0.5,-6.75)

Hence,

x = 0.5 , y = -6.75

Equation 1:

2(0.5) + 4(-6.75) = -26

1 - 27 = -26

-26 = -26

This equation is true for the given point.

Equation 2:

-6.75 = 0.5 - 7.5

-6.75 ≠ -7

The equation is not true for the given point.

Equation 3:

2 (-6.75) = 0.5 + 13

-13.5 ≠ 13.5

The equation is not true for the given point.

Equation 4:

-6.75 = 0.5(0.5) - 7

-6.75 = 0.25 - 7

-6.75 = -6.75

This equation is true for the given point.

\(\rule[225]{225}{2}\)

Hope this helped!

The equation of the line is y = 7x - 36

Equation of the line,

For the given slope and the point the equation of the line is written as,

(y - y1) = m (x - x1)

Given,

The slope is 7, and it passes through ( 8, 6).

Here we need to find the equation of the line.

While we looking into the give equation, we have identified the following,

slope = 7

point = (8,6)

When we apply the values on the formula of equation of the line, then we get,

=> (y - 6) = 7 (x - 6)

When we simplify this one then we get,

=> y - 6 = 7x - 42

Then it can be rewritten as,

=> y = 7x - 36

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Answer:

Just divide the total cost of 21.75 by the number of friends, 3 which is 7.25

Step-by-step explanation:

Graph A: Non-linear function

Graph B: Not a function

Graph C: Linear function

Graph A and Graph B are not functions and Graph C is a linear function. The graph will be non-linear if it has a degree greater than or equal to two. If the graph is a line that goes through all the points, it is a linear function.

Graph A and Graph B cannot be a function because they do not pass the vertical line test, which means there are multiple y-values for some of the x-values.

Graph C is a straight line passing through all the points, thus it is a linear function.

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Step-by-step explanation:

There are FOUR queens in a deck of 52 cards

4/52 chance of selecting a queen =  1/13  chance  = .07692 chance

The formula for the machine value V (in thousands of dollars) at time t ≥ 0 after purchase is given as follows: V (t) = Ct - rt, where C is the initial cost of the machine in thousands of dollars, r is the depreciation rate per year, and t is the time in years since the machine was purchased. V(t) = 710 - 13.7925t Answer: V(t) = 710 - 13.7925t

The value of an industrial milling machine after two years of purchase is $710,000 and after five years, the value is $180,000. Let us find the depreciation rate of the machine.

Linear Depreciation Method: Linear depreciation method is one of the methods used to calculate depreciation in accounting. It is also called straight-line depreciation. Under this method, the depreciation expense of an asset is the same for each year of its useful life.

The formula to calculate the depreciation expense using the straight-line depreciation method is:Depreciation Expense = (Cost of Asset - Salvage Value)/Useful Life Let,

The cost of the industrial milling machine = C = 710The value of the industrial milling machine after five years = S = 180The useful life of the machine in years = LWe have to find a formula for the machine value V (in thousands of dollars) at time t ≥ 0 after purchase.

To find the useful life of the machine, use the following formula:Cost of Asset = Depreciation Expense x Useful Life + Salvage Value710 = (710 - 180)/L * L + 180

Simplifying the above equation, we get:710 = 530/L + 180Multiplying both sides of the equation by L and then subtracting 180 from both sides, we get:530L = 530L = 530 - 180L = 350/53.

Therefore, useful life, L = 350/53 yearsThe depreciation rate of the industrial milling machine is the difference between its cost and salvage value divided by its useful life.

Using the given information, the cost of the machine and the value of the machine after five years, we get: Depreciation Rate = (Cost of Machine - Salvage Value) / Useful LifeDepreciation Rate = (710 - 180) / (350/53)Depreciation Rate = 13.7925

Hence, the formula for the machine value V (in thousands of dollars) at time t ≥ 0 after purchase is given as follows:V (t) = Ct - rt, where C is the initial cost of the machine in thousands of dollars, r is the depreciation rate per year, and t is the time in years since the machine was purchased. V(t) = 710 - 13.7925t Answer: V(t) = 710 - 13.7925t

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Answer:

i believe the answer for #2 is F but i could be wrong

Answer:

F

Step-by-step explanation:

Answer:

if im not wrong im pretty sure its c but I would get a second opinion

Answer:

[0,pi/2)  and (pi/2, pi]  

Step-by-step explanation:

The arc sec is valid in the range 0° ≤ y < 90° or 90° < y ≤ 180°

Converting to radians

[0,pi/2)  and (pi/2, pi]  

It is not valid at pi/2 since there is an asymptote.

The unknown number x = (6.1 ± sqrt(6.

Let's call the two numbers x and y.

We are given:

AM (Arithmetic Mean) between x and y exceeds their GM (Geometric Mean) by 2:

(x + y)/2 - sqrt(xy) = 2

GM between x and y exceeds their HM (Harmonic Mean) by 1.8:

sqrt(xy) - 2xy/(x+y) = 1.8

We can solve for one variable in terms of the other from the second equation and substitute into the first equation to solve for the remaining variable. Let's solve for y in terms of x from the second equation:

sqrt(xy) - 2xy/(x+y) = 1.8

sqrt(xy)(x+y) - 2xy = 1.8(x+y)

sqrt(xy)x + sqrt(xy)y - 2xy = 1.8x + 1.8y

sqrt(xy)(x+y-1.8) = 0.2x + 0.8y

x+y-1.8 = (0.2/0.8)sqrt(xy)(x+y-1.8)

x+y-1.8 = 0.25sqrt(xy)(x+y-1.8)

4x + 4y - 7.2 = sqrt(xy)(x+y)

Now we can substitute this expression for sqrt(xy)(x+y) into the first equation and solve for x:

(x + y)/2 - sqrt(xy) = 2

(x + y)/2 - (4x + 4y - 7.2)/4 = 2

2(x + y) - (4x + 4y - 7.2) = 8

12.2 = 2x + 2y

6.1 = x + y

Now we can substitute x + y = 6.1 into the expression we derived for sqrt(xy)(x+y) to solve for sqrt(xy):

4x + 4y - 7.2 = sqrt(xy)(x+y)

4x + 4y - 7.2 = sqrt(xy)(6.1)

sqrt(xy) = (4x + 4y - 7.2)/6.1

Finally, we can substitute both x + y = 6.1 and sqrt(xy) = (4x + 4y - 7.2)/6.1 into the equation sqrt(xy) - 2xy/(x+y) = 1.8 and solve for y:

sqrt(xy) - 2xy/(x+y) = 1.8

(4x + 4y - 7.2)/6.1 - 2xy/6.1 = 1.8

4x + 4y - 7.2 - 12.2xy = 11.38

4x + 4y - 11.38 = 12.2xy

4x + 4(6.1 - x) - 11.38 = 12.2xy (substituting x + y = 6.1)

xy = 4.08

Now we know that xy = 4.08, and we can use this to solve for x and y:

y = 6.1 - x

xy = 4.08

x(6.1 - x) = 4.08

6.1x - x^2 = 4.08

x^2 - 6.1x + 4.08 = 0

We can solve for x using the quadratic formula:

x = (6.1 ± sqrt(6.

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The probability that a randomly chosen light bulb lasts more than 10,500 hours is 0.0668 (rounded to four decimal places).

The probability that a randomly chosen light bulb lasts more than 10,500 hours is 0.0668(rounded to four decimal places).Here's how to calculate it:Given data mean μ = 9,000 and standard deviation σ = 1,000.To calculate the probability that a random light bulb lasts more than 10,500 hours, convert the problem to a standard normal distribution.

z = (10,500 - μ)/σ = (10,500 - 9,000)/1000 = 1.50

Here's the standard normal distribution curve with the shaded area representing the probability required: Standard normal distribution curve with the shaded area

Now, the area under the curve to the right of z = 1.5 is the probability that a randomly chosen light bulb will last more than 10,500 hours.

Using the Z table, we can look up the value corresponding to a z-score of 1.5. The table gives us a value of 0.9332.Now, the area to the left of z = 1.5 is 1 - 0.9332 = 0.0668, which is the probability that a randomly chosen light bulb lasts more than 10,500 hours, rounded to four decimal places.

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The statement "Every connected undirected graph having degree sequence 2, 2, 4, 4, 6 has a Hamilton cycle" is false.

The statement "Every connected undirected graph having degree sequence 2, 2, 4, 4, 6 has a Hamilton cycle" is false.

To determine if a graph has a Hamilton cycle, we need to analyze the given degree sequence and the connectivity of the graph.

In this case, the degree sequence 2, 2, 4, 4, 6 implies that there are five vertices in the graph, each having a specific number of edges connected to them.

However, the degree sequence alone does not guarantee the existence of a Hamilton cycle.

To disprove the statement, we can provide a counterexample by constructing a connected undirected graph with the given degree sequence (2, 2, 4, 4, 6) that does not have a Hamilton cycle.

By carefully arranging the edges between the vertices, it is possible to create a graph where a Hamilton cycle cannot be formed.

Therefore, the statement claiming that every connected undirected graph with degree sequence 2, 2, 4, 4, 6 has a Hamilton cycle is false.

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Answer:

Inequality:

29.2x + 501.60 ≤ 560

Answer:

She may buy up to 2 reflectors.

Step-by-step explanation:

She can spend up to $560, so the total expense has to be less than or equal to $560.

total expense ≤ 560

All items she buys have a price and a number of items except for the outfits which have a price but an unknown number.

Let x = number of outfits.

total expense = $425.05 + 4 × $15.19 + $15.79 + x × $29.20

total expense = 29.2x + 501.60

Inequality:

29.2x + 501.60 ≤ 560

29.2x ≤ 58.4

x ≤ 2

She may buy up to 2 reflectors.

Considering the images (a),(b),(c),(d),(e),(f) the oriented path is

(a) Negative

(b) Positive

(c) Positive

(d) Zero

(e) Zero

(f) Zero

calculating each quadrant's line integral and symmetry.

In calculus, a line integral is an integral where the function being evaluated is along a curve. A line integral is also known as a route integral, curve integral, or curvilinear integral.

What does a Line integral mean?

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Probability that the drug will be ineffective in more than two cases is 0,68.

Drug is effective in 9 cases out of 10, so the drug:

If the drug is tested on 12 patients, then there are 13 possibilities, namely:

In the problem, asked to find the probability of the drug being ineffective in more than 2 patients, there are 10 possibilities, namely

The way to find out the possibility of a drug being effective in 0-9 patients is:

P(effective ≤ 9) = P(effective 9) + P(effective 8) + ... + P(effective 0)

However, quite a lot is calculated if you use the formula above, less will be calculated if you use the method below:

P(effective ≤ 9) = 1 - ( P(effective 10) + P(effective 11) + P(effective 12) )

Let's try to start by calculating P(effective 10). P(effective 10) means the probability of being effective for 10 people and ineffective for 2 people. Then the effective probability is raised to the power of 10 and multiplied by the ineffective probability raised to the power of 2.

P(effective 10) = \((\frac{9}{10})^{10} .(\frac{1}{10} )^2\)

P(effective 10) = \(\frac{9^{10} }{10^{12} }\)

P(effective 10) = \(\frac{3486784401}{1000000000000}\)

So does P(effective 11) and P(effective 12)

P(effective 11) = \((\frac{9}{10} )^{11}.(\frac{1}{10})^{1}\)

P(effective 11) = \(\frac{9^{11} }{10^{12} }\)

P(effective 11) = \(\frac{3486784401}{1000000000000}\)

P(effective 12) = \((\frac{9}{10}) ^{12} .( \frac{1}{10} )^0\)

P(effective 12) = \(\frac{9^{12}}{10^{12}}\)

P(effective 12) = \(\frac{282429536481}{1000000000000}\)

So:

P(effective ≤ 9) = 1 - ( P(effective 10) + P(effective 11) + P(effective 12) )

P(effective ≤ 9) = 1 - ( \(\frac{3486784401}{1000000000000}\)+ \(\frac{3486784401}{1000000000000}\)+ \(\frac{282429536481}{1000000000000}\))

P(effective ≤ 9) = 1 - \(\frac{317297380491}{1000000000000}\)

P(effective ≤ 9) = 1 - 0,317297380491

P(effective ≤ 9) = 0,682702619509 ≈ 0,68

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Answer:

\(\huge\boxed{\sf \$54.81}\)

Step-by-step explanation:

The cost of pet carrier = $21.89

The cost of 1 bag of cat food = $16.46

The cost of 2 bags of cat food = $16.46 × 2

= $32.92

Total cost:

= $21.89 + $32.92

= $54.81

\(\rule[225]{225}{2}\)

\( \text{Cost of one pet carrier =}\)$21.89

\( \text{Cost of one cat food bag =}\)$16.46

\( \therefore \text{Cost of two cat food bag = }\)$16.46×2= $32.92

\( \therefore\bold{\underline{Total\:cost}}\text{\:of each items = }\)

$21.89 + $32.92 =\( \boxed{\sf \$ \red{54.81}}\)

Answer: The price after 3 years is £6904.15

Step-by-step explanation:

After 1 year,  8500*0.9= 7650

7650*0.95=7267.5

7267.5*0.95=6904.125

The price after 3 years is £6904.15

(1) Total variation: The total variation is the sum of squares of the differences between the observed values of the dependent variable (y) and the mean of the dependent variable (ȳ).

Total variation = SS Total = 464,130,862.6855

Explained variation: The explained variation is the sum of squares of the differences between the predicted values of the dependent variable (ŷ) and the mean of the dependent variable (ȳ).

Explained variation = SS Regression = 462,192,435.0183

Unexplained variation: The unexplained variation is the sum of squares of the differences between the observed values of the dependent variable (y) and the predicted values of the dependent variable (ŷ). Unexplained variation = SS Residual = 1,938,427.6672

(2) R² and R-bar squared:

R² (Coefficient of determination) = 0.9958

R-bar squared (Adjusted coefficient of determination) = 0.9948

(3) SSE (Sum of Squares of Errors): SSE is the sum of the squared differences between the observed values of the dependent variable (y) and the predicted values of the dependent variable (ŷ).

SSE = 1,938,427.6672

s² (Mean squared error): s² is the mean squared error, which is obtained by dividing SSE by the degrees of freedom.

s² = SSE / (n - p - 1) = 161,535.6389

s (Standard error): The standard error is the square root of s².

s = √s² = √161,535.6389 = 401.9150

(4) F(model) statistic:

The F(model) statistic is calculated by dividing the explained variation (SS Regression) by the unexplained variation (SS Residual) divided by its degrees of freedom.

F(model) = (SS Regression / df Regression) / (SS Residual / df Residual)

         = (154,064,145.0061 / 3) / (161,535.6389 / 12)

         = 953.7471

(5) To test the significance of the linear regression model, we compare the F(model) statistic with the critical F-value at a given significance level (α = 0.05). The critical F-value is obtained from the F-distribution table or software.

(6) The p-value related to F(model) can be found in the ANOVA table. The p-value indicates the probability of observing an F-statistic as extreme as the one calculated, assuming the null hypothesis (no relationship between the predictors and the response) is true. By comparing the p-value to a chosen significance level (α), we can determine the significance of the linear regression model.

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Distributive property of multiplication over subtraction

where a, b, and c are some numbers.

Substituting with a = 5, b = 4, and c = 2, we get:

Answer:

m=10

Step-by-step explanation:

divide 6m by 6 and 60 by 6 and you get m=10

Answer:

10

Step-by-step explanation:

divide both sides

6m÷6=60÷6

m=60÷6

m=10

Answer:

A and B

Step-by-step explanation:

Because they have a combined total of 30 years old so that eliminates C and D.

And for the ones that ask how old they are you could put their both 15.

The  values of x will f(x) > 0 for x < 0, and f(x) < 0 for -6 < x < 0 and x > -6.

To determine the values of x for which f(x) > 0, we need to find the intervals where the function is positive. Let's analyze the function f(x) = x*-x³-6x².

First, let's factor out an x from the expression to simplify it: f(x) = x(-x² - 6x).

Now, we can observe that if x = 0, the entire expression becomes 0, so f(x) = 0.

Next, we analyze the signs of the factors:

1. For x < 0, both x and (-x² - 6x) are negative, resulting in a positive product. Hence, f(x) > 0 in this range.

2. For -6 < x < 0, x is negative, but (-x² - 6x) is positive, resulting in a negative product. Therefore, f(x) < 0 in this range.

3. For x > -6, both x and (-x² - 6x) are positive, resulting in a negative product. Thus, f(x) < 0 in this range.  

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David can best improve his investigation by including a control group. A control group is a group that does not receive any treatment or intervention and is used as a benchmark to compare the results of the experimental group. In this case, the control group would be a third young elm tree that is planted near the other two but does not receive any water or fertilizer. David can measure the height and trunk girth of the control tree every week for a year as well.

In scientific research, it is important to include a control group to ensure that the results of the experimental group are due to the treatment or intervention and not due to other factors. In this case, David is investigating the factors that affect plant growth, and he is manipulating the amount of water and fertilizer that the two elm trees receive. However, there could be other factors that affect plant growth, such as soil quality, sunlight exposure, temperature, and pests. If David only measures the height and trunk girth of the two elm trees that receive water and fertilizer, he cannot be sure if any changes in their growth are due to the treatment or due to other factors.

To improve his investigation, David can plant a third young elm tree near the other two and not give it any water or fertilizer. This third tree will serve as the control group, and David can measure its height and trunk girth every week for a year as well. By comparing the growth of the experimental group (the two elm trees that receive water and fertilizer) to the growth of the control group (the third elm tree that receives nothing), David can be more confident that any changes in the growth of the experimental group are due to the treatment and not due to other factors.

David can best improve his investigation by including a control group, which will serve as a benchmark to compare the results of the experimental group. The control group should be a third young elm tree that is planted near the other two but does not receive any water or fertilizer. David can measure the height and trunk girth of the control tree every week for a year as well. By comparing the growth of the experimental group (the two elm trees that receive water and fertilizer) to the growth of the control group (the third elm tree that receives nothing), David can be more confident that any changes in the growth of the experimental group are due to the treatment and not due to other factors.

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Answer:

In the photo

Step-by-step explanation:

Simply multiply the numbers out of the brackets to the numbers in them, adhering to algebraic rules.

Answer:

the one above me is right expet for 2 of them purple and orange

Step-by-step explanation:

it was right on edge

The solution of the equation 3z minus 2 is equal to 46 is 16.

The given equation '3z minus 2 is equal to 46' can be written as

    3z - 2  =   46

Now solving for z because the value of z will give the required solution of the given equation. So now finding the z from the equation:

   3z = 46  + 2

   3z =  48

   z = 48/3

   z = 16

The value of the z is 16 which represents the solution of the given equation i.e 3z minus 2 is equal to 46.

Therefore it is concluded that the solution of the equation 3z minus 2 is equal to 46 is 16.

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The first law of thermodynamics is a fundamental principle in physics that states energy cannot be created or destroyed, only converted from one form to another. It can be expressed in terms of heat and work through the equation:

ΔU = q - w

where ΔU represents the change in internal energy of a system, q represents the heat added to the system, and w represents the work done on or by the system.

Now, let's address when the quantities q and w would be negative numbers.

1) When q is negative: This occurs when heat is removed from the system, indicating an energy loss. For example, when a substance is cooled, heat is extracted from it, resulting in a negative value for q.

2) When w is negative: This occurs when work is done on the system, decreasing its energy. For instance, when compressing a gas, work is done on it, leading to a negative value for w.

In both cases, the negative sign indicates a reduction in energy or the transfer of energy from the system to its surroundings.

In summary, the first law of thermodynamics can be expressed as ΔU = q - w, and q and w can be negative numbers when energy is lost from the system through the removal of heat or when work is done on the system.

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Answer:

7/3

Step-by-step explanation:

2-1/3-2/+1 in its simplest fraction is equal to 7/3.