5. Which statement is not true about a distance-versus-time graph?
O Time is plotted on the horizontal x-axis.
The slope of the line represents the speed of the object.
A point on the line represents the speed of the object.

The correct sequence of energy transfer during electricity generation is from the primary source of energy (such as coal, natural gas, nuclear fuel, or renewable sources like wind or solar) to mechanical energy, then to electrical energy.

The process of electricity generation involves the conversion of one form of energy into another. The primary source of energy, such as coal, natural gas, nuclear fuel, or renewable sources like wind or solar, is used to generate heat, which in turn is used to produce mechanical energy. This mechanical energy is then converted into electrical energy using generators, which use the principles of electromagnetic induction to produce a flow of electrons. The electrical energy is then transmitted through power lines to homes, businesses, and other consumers.

For example, in a coal-fired power plant, the coal is burned to produce heat, which is used to generate steam. The steam then drives a turbine, which produces mechanical energy that is used to spin a generator, producing electrical energy. This electrical energy is then transmitted through power lines to consumers. In the case of renewable sources such as wind or solar power, the primary source of energy is directly converted into electrical energy using turbines or photovoltaic cells, respectively.

Therefore, the correct sequence of energy transfer during electricity generation is from the primary source of energy to mechanical energy, then to electrical energy.

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The diffraction grating affects the light from a hydrogen lamp as it produces the separation of the colors of the white light. The spectrum can be viewed through the grating,

Answer:

I. Speed = 20m/s

II. Velocity = 20m/s due North.

Explanation:

Given the following data;

Distance = 40m

Time = 2secs

To find the speed;

Mathematically, speed is given by the formula;

\(Speed = \frac{distance}{time}\)

Substituting into the equation, we have;

\(Speed = \frac{40}{2}\)

Speed = 20m/s.

In physics, we use the same formula for calculating speed and velocity. The only difference is that speed is a scalar quantity and as such has magnitude but no direction while velocity is a vector quantity and as such it has both magnitude and direction.

\(Velocity = \frac{distance}{time}\)

Therefore, the velocity is 20m/s due North.

It takes our Solar system 230 million years to complete one orbit around the milky way galaxy; option E.

The solar system refers to the system of the Sun and the planets that orbit it.

The Sun is the star of our solar system. The planets in our system include:

Our solar system is a part of the Milky Way Galaxy.

It takes about 230 million years for our Solar system to complete one orbit around the Milky Way Galaxy.

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The given equation,F = (9/5)C + 32gives the Fahrenheit temperature corresponding to the Celsius. To find the Fahrenheit temperature equivalent to 25 Celsius, we will substitute the given value of Celsius into the above equation.

So, F = (9/5)(25) + 32F = 45 + 32F = 77Hence, the Fahrenheit temperature equivalent to 25 Celsius is 77 degrees Fahrenheit.

To find the Fahrenheit temperature equivalent to a given Celsius temperature, we use the equation

F = (9/5)C + 32, whereF is the Fahrenheit temperature andC is the Celsius temperature.

The equation is derived from the relationship between the Celsius and Fahrenheit temperature scales.In this equation, 9/5 is a conversion factor used to convert the Celsius temperature to Fahrenheit.

The constant 32 is added to the product of the conversion factor and the Celsius temperature to get the Fahrenheit temperature.The question asks us to find the Fahrenheit temperature equivalent to 25 Celsius. To do this, we substitute the given value of Celsius into the equation.

So, we haveF = (9/5)(25) + 32Simplifying the right-hand side, we getF = 45 + 32Evaluating the expression,

we getF = 77Therefore, the Fahrenheit temperature equivalent to 25 Celsius is 77 degrees Fahrenheit.

Thus, we can conclude that the Fahrenheit temperature equivalent to 25 Celsius is 77 degrees Fahrenheit, which we found using the equation F = (9/5)C + 32.

This equation is used to convert Celsius temperatures to Fahrenheit temperatures. The conversion factor 9/5 is multiplied by the Celsius temperature, and 32 is added to the result to get the Fahrenheit temperature.

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It is not possible to simply "live in one of the galaxies near our cosmological horizon" and have a clear view of the expanding universe. This statement is false.

Firstly, galaxies themselves are not static objects but are also in motion and expanding along with the universe.

Secondly, the "black void" that the statement refers to is likely the misconception that the universe is expanding into some sort of empty space. However, this is not the case as the universe is not expanding into anything. Rather, it is the space itself that is expanding, and all matter and energy in the universe is simply carried along with this expansion.

Therefore, it is not possible to live in a way that would allow one to see the expansion of the universe in the way described in the statement.

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Answer:

No 1000mm equal 0.001km

1000 millimeters = 0.001 kilometer

Formula: divide the value in millimeters by 1000000 because 1 kilometer equals 1000000 millimeters.

So, 1000 millimeters = 1000/1000000

= 0.001 kilometer.

How do you convert 1000 millimeters into kilometers?

To transform 1000 millimeters into kilometer, you just need to multiply the quantity in millimeters by the conversion factor, 1000.

So, 1000 millimeters in kilometers = 1000 times 1000 = 0.001 kilometer, exactly. See details on the formula below on this page.

Answer:

  85.2 N

Explanation:

You want to know your weight if the Earth were 3 times as massive and had 5 times the present radius. Your weight is 710 N.

Your weight is proportional to the mass of the Earth and the square of the radius between your mass and the center of the Earth. The revised dimensions of the earth would multiply your weight by ...

  W = k(M/r²) = 710 N

  W' = k((3M)/(5r)²) = k(M/r²)(3/25) = (710 N)(3/25) = 82.5 N

Your weight would be 82.5 N.

Answer:

\(559\).

Explanation:

Integrate \(a(t)\) with respect to time \(t\) to find an expression for velocity:

\(\begin{aligned} v(t) &= \int a(t)\, d t \\ &= \int (6\, t + 8)\, d t && (\text{power rule}) \\ &= 3\, t^{2} + 8\, t + C_{v} \end{aligned}\).

Note that since this integral is indefinite, the expression for \(v(t)\) includes a constant \(C_{v}\).

Find the value of \(C_{v}\) using the fact that \(v(0) = 2\). Specifically, substitute \(t = 0\) into the expression \(v(t) = 3\, t^{2} + 8\, t + C_{v}\) and solve for \(C_{v}\!\):

\(v(0) = 3\, (0)^{2} + 8\, (0) + C_{v} = C_{v}\).

\(v(0) = 2\).

\(C_{v} = 2\).

In other words, \(v(t) = 3\, t^{2} + 8\, t + 2\).

Similarly, integrate \(v(t)\) with respect to \(t\) to find an expression for position:

\(\begin{aligned} s(t) &= \int v(t)\, d t \\ &= \int (3\, t^{2} + 8\, t + 2)\, d t\\ &= t^{3} + 4\, t^{2} + 2\, t + C_{s} \end{aligned}\).

Similarly, find the value of constant \(C_{s}\) using the fact that \(s(0) = 6\):

\(s(0) = (0)^{3} + 4\, (0)^{2} + 2\, (0) + C_{s} = C_{s}\).

\(s(0) = 6\).

\(C_{s} = 6\).

In other words, \(s(t) = t^{3} + 4\, t^{2} + 2\, t + 6\). Substitute in \(t = 7\) and evaluate to find the position of the particle at that moment:

\(s(7) = 7^{3} + 4\, (7)^{2} + 2\, (7) + 6 = 559\).

The pοsitiοn of the particle at time t = 7 is 559 units.

Tο find the pοsitiοn at time t = 7, we need tο integrate the given acceleratiοn functiοn tο οbtain the velοcity functiοn and then integrate the velοcity functiοn tο οbtain the pοsitiοn functiοn.

Given:

Acceleratiοn functiοn: a(t) = 6t + 8

Initial pοsitiοn: s(0) = 6

Initial velοcity: v(0) = 2

First, let's integrate the acceleratiοn functiοn tο οbtain the velοcity functiοn:

v(t) = ∫(a(t)) dt

= ∫(6t + 8) dt

= 3t^2 + 8t + C

Tο find the cοnstant οf integratiοn (C), we can use the initial velοcity v(0) = 2:

2 = 3(0)² + 8(0) + C

C = 2

Sο, the velοcity functiοn becοmes:

v(t) = 3t² + 8t + 2

Next, let's integrate the velοcity functiοn tο οbtain the pοsitiοn functiοn:

s(t) = ∫(v(t)) dt

= ∫(3t² + 8t + 2) dt

= t³ + 4t² + 2t + C'

Tο find the cοnstant οf integratiοn (C'), we can use the initial pοsitiοn s(0) = 6:

6 = (0)³ + 4(0)² + 2(0) + C'

C' = 6

Sο, the pοsitiοn functiοn becοmes:

s(t) = t³ + 4t² + 2t + 6

Finally, we can find the pοsitiοn at time t = 7:

s(7) = (7)³+ 4(7)² + 2(7) + 6

= 343 + 196 + 14 + 6

= 559

Therefοre, the pοsitiοn at time t = 7 is 559 units.

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Answer:

a) 6498.84 kW

b) 0.51

c) 0.379

Explanation:

See the attached picture below for the solution

Given-

Temperature at state 1 \(T_{1}\) is 40 degree cel. This is equal to the 313 K.

Temperature at state 1 \(T_{2}\) is 650 degree cel. This is equal to the 923 K.

To know the mass flow rate use the idol gas equation. Idol gas equation for a substance can be given as,

\(PV=nRT\)

Rewrite this equation for \(n\),

\(n=\dfrac{PV}{RT}\)

Put the value of known variable from the question,

\(n=\dfrac{100\times\dfrac{850}{60} }{0.287\times 313}\)

\(n=15.77\)

Thus the value of n is 15.77 kg/sec.

Temperature at state 2 is,

In Bryon cycle we know that the processes 1-2 and 3-4 are isotropic. Hence,

\(T_{2} =T_{1}\left (1+ \dfrac{r_{p}^{\dfrac{\gamma-1}{\gamma}-1} }{c_{v} } \right )\)

\(T_{2} =313\left (1+ \dfrac{16^{\dfrac{1.35-1}{1.35}-1} }{0.821 } \right )\)

\(T_{2} =700\)

Temperature at state 3 is,

\(T_{3} =\dfrac{T_4}{1+c_p(r_p^{\dfrac{\gamma-1}{\gamma}-1}-1)}\)

Put the value in above equation we get,

\(T_3=1682\)

\(W=mc_p(T_i{n}-T_{out})\)

\(W=mc_p(T_3-T_2-T_4+T_{1})\)

\(W=15.77\times1.109(1682-700-923+313)\)

\(W=65\)

Thus the net power output is 70 watt.

\(r_b=\dfrac{T_2-T_1}{T_3-T_4}\)

\(r_b=\dfrac{700-313}{1682-923}\)

\(r_b=0.51\)

Hence the back work ratio is 0.51.

\(\eta=\dfrac{W}{Q_{in}}\)

\(\eta=\dfrac{65}{mc_p(T_3-T_2)}\)

\(\eta=0.379\)

Hence, for the given problem the net power output is 70 watt,the back work ration is 0.51, and the thermal efficiency is 0.379.

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When an engineering team reaches the stage of iterating to improve the solution in the engineering design process, there are various activities that the team might be doing. One of the most crucial activities at this stage of the design process is testing. Here are a few things that an engineering team might do to test and improve the solution:

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7718.04 J joules are required to convert 16. 5 g of ice at 0.0°C to liquid water at 32. 0°C

Specific heat, the quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree. The units of specific heat are usually calories or joules per gram per Celsius degree.

Latent heat of fusion, also known as enthalpy of fusion, is the amount of energy that must be supplied to a solid substance (typically in the form of heat) in order to trigger a change in its physical state and convert it into a liquid (when the pressure of the environment is kept constant).

heat require to convert 16.5 g of ice at 0°C to water at 0°C

Q1 =  \(mH_{f}\) = 16.5 * 334 = 5511 J

heat require to convert 0°C of water to water at 32. 0°C

Q2 = mcΔT = 16.5 * 4.18 *(32-0) = 2207.04 J

Total heat = Q1 + Q2

                 = 5511 J + 2207.04 J = 7718.04 J

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In science, a hypothesis is a tentative explanation of an observation, while a scientific theory is a broader, well-tested explanation for a natural phenomenon backed by multiple lines of evidence.

In the scientific method, a hypothesis is an initial explanation or proposed solution to a specific observation or problem. It is often based on limited evidence or previous knowledge and serves as a starting point for further investigation. A hypothesis is testable and can be supported or refuted through experimentation or further observations. It represents a possible explanation that requires empirical evidence to validate or invalidate its validity.

On the other hand, a scientific theory is a well-established and comprehensive explanation for a natural phenomenon that has been extensively tested and supported by multiple lines of evidence. Unlike a hypothesis, a scientific theory goes beyond a single observation or experiment. It encompasses a broad range of observations, experimental results, and logical reasoning. A scientific theory provides a framework that can explain and predict various related phenomena. It is subject to ongoing scrutiny and refinement, but its validity and acceptance are based on its consistency with empirical evidence and its ability to make accurate predictions.

In summary, while a hypothesis is a tentative explanation of an observation, a scientific theory is a broader and well-tested explanation that is supported by multiple lines of evidence and can account for a range of related phenomena.

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None of the answer choices provided are relevant to the security needs of an information system. The security needs of an information system are determined based on factors such as risk assessment, threat analysis, and organizational requirements. They are not determined by changes in air pressure or velocity of air molecules.

The systems development life cycle is a methodical approach to creating an information system that includes stages of initiation, development, and deployment. In the component design phase, designers build the components of the information system, which would include both hardware and software components. The designers establish how components interact with each other and determine the system's security needs during this stage of development.

They also consider how data will flow throughout the system and identify potential security risks and vulnerabilities in the system. Once the components are built, they move on to the next stage of the systems development life cycle, where they integrate the components into the system and test the entire system as a whole. Hence, none of the given answers is correct.

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The acceleration of a particle is a= (-1.6 v1/2) m/s². The initial velocity of the particle is u = 8 m/s.

Now, let's use the formula: 2as = v² - u², where a = (-1.6v^(1/2)) m/s², u = 8 m/s, and v = 0 m/s 2 × (-1.6v^(1/2)) × s = 0 - 8²s = 64 / (2 × 1.6v^(1/2)) = 20v^(1/2)/4 = 5v^(1/2) meters.

This is the distance travelled by the particle before it stops.

We know that the final velocity of the particle is 0 m/s. The initial velocity of the particle is 8 m/s.

The acceleration of the particle is a = (-1.6v^(1/2)) m/s².

Let's use the formula to calculate the time it takes to stop the particle. It is:v = u + at 0 = 8 + (-1.6v^(1/2)) × t t = 8 / (1.6v^(1/2)) t = 5 / v^(1/2) seconds.

This is the time taken by the particle to come to rest.

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The particle travels approximately 12.5 meters before it comes to a stop. It takes approximately 5 seconds for the particle to reach zero velocity.

To determine the distance traveled before the particle comes to a stop, we need to integrate the velocity function over time. The given deceleration is expressed as a = -1.6√v , where v is the velocity in m/s. Since the initial velocity is 8 m/s, we can write the deceleration as a = -1.6√8. Integrating the acceleration with respect to velocity gives us the equation: ∫dv/(-1.6√v ) = ∫dt. Simplifying the integral and solving for t gives us t = 5 seconds.

To find the distance traveled, we integrate the velocity function with respect to time. The velocity function is given by dv/dt = -1.6√v. Separating variables and integrating, we get ∫dv/√v  = ∫-1.6dt. Evaluating the integral and substituting the limits (from v = 8 m/s to v = 0), we find √v = -1.6t + C. Applying the initial condition v(0) = 8, we can solve for C and obtain C = √8. Plugging in the values for t and C, we get √v = -1.6t + √8. Squaring both sides and solving for v, we find v = \((1.6t - \sqrt{8} )^{2}\). Integrating the velocity function again with respect to time, we get ∫\((1.6t - \sqrt{8} )^{2}\) dt = ∫ds. Evaluating the integral and substituting the limits, we find s = 12.5 meters.

Therefore, the particle travels approximately 12.5 meters before coming to a stop.

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In a fire piston, the temperature of the gas inside the piston increases due to adiabatic compression.

In physics, pressure is a measure of the force per unit area that a fluid (liquid or gas) exerts on its surroundings. It is defined as the force F acting perpendicular to a surface divided by the area A over which the force is distributed: pressure = F/A. The SI unit of pressure is the Pascal (Pa), which is defined as one Newton per square meter (N/m²). Other common units of pressure include pounds per square inch (psi), atmospheres (atm), and bar (bar). Pressure is an important concept in many areas of physics, including fluid mechanics, thermodynamics, and atmospheric science. It describes the behavior of fluids in pipes and channels, the operation of hydraulic systems, and the behavior of gases in sealed containers. The pressure of a fluid is related to its density and temperature, and can be influenced by factors such as gravity, elevation, and the motion of the fluid itself.

Here,

When the piston is rapidly pushed down into the cylinder, it compresses the gas inside the cylinder. This rapid compression causes the gas molecules to collide with each other more frequently and with greater force, which in turn increases the temperature of the gas.

Because the compression is adiabatic (i.e., no heat is allowed to enter or leave the system), the increase in temperature is due solely to the work done on the gas by the piston. This increase in temperature is known as adiabatic heating.

The fire piston is a simple but effective tool for starting a fire in the wilderness, and it demonstrates the principles of adiabatic compression and the relationship between pressure, volume, and temperature in a gas.

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Astronomers measure sunspots and their magnetic polarity using a technique called spectropolarimetry. This method analyzes the interaction between the sun's magnetic field and its emitted light. To view the sun's magnetic field, scientists use instruments like magnetographs, which are specialized telescopes that detect and record the sun's magnetic activity.

Sunspots are cooler, darker areas on the sun's surface that possess intense magnetic activity. The Zeeman effect, a phenomenon where the magnetic field splits the spectral lines of light, is crucial in studying the sun's magnetic field. By observing these spectral lines and their shifts, astronomers can determine the strength and direction of the magnetic field in sunspots.

Sunspots typically occur in pairs with opposite magnetic polarities, one being the north pole and the other the south pole. These pairs are aligned in an east-west direction, with the leading sunspot having a magnetic polarity opposite to that of the sun's magnetic field at that particular solar hemisphere.

In summary, astronomers use spectropolarimetry and the Zeeman effect to analyze the sun's magnetic field and identify sunspots' polarities, while magnetographs provide visual representations of the magnetic field distribution.

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Answer:

condensation, the process of changing from a gas to a liquid

Answer:

Approximately \(33\; {\rm m\cdot s^{-2}}\).

Approximately \(55\; {\rm m\cdot s^{-2}}\).

(Assume that the table is level, and that the \(60\; {\rm N}\) force is horizontal.)

Explanation:

Consider all three blocks as one object of mass \(m = (1 + 4 + 6)\; {\rm kg} = 11\; {\rm kg}\). Among all the forces that are in action, the only unbalanced external force on this \(m = 11\; {\rm kg}\) object will be the \(60\; {\rm N}\) force. Hence, the resultant force of this combined object of mass \(m = 11\; {\rm kg}\) will be \(F_{\text{net}} = 60\; {\rm N}\).

Acceleration \(a\) of this combined object will be:
\(\begin{aligned}a &= \frac{F_{\text{net}}}{m} \\ &= \frac{60\; {\rm N}}{11\; {\rm kg}} \\ &= \frac{60}{11}\; {\rm m\cdot s^{-2}}\end{aligned}\).

Since the three crate blocks are moving together, each will have the same acceleration, \(a = (60/11)\; {\rm m\cdot s^{-2}}\).

Resultant force on each of the crate blocks will be:

Assume that the \(60\; {\rm N}\) external force on the \(1\; {\rm kg}\) block points to the right.

When the crates are considered individually, external forces on the \(1\; {\rm kg}\) crate will include:

Since these two forces are in opposite directions, the resultant force on this \(1\; {\rm kg}\) block will be \((60\; {\rm N} - x\; {\rm N})\). However, since the actual resultant force on this block (calculated from acceleration) is \((60 / 11)\; {\rm N}\):

\(\displaystyle 60\; {\rm N} - x\; {\rm N} = \frac{60}{11}\; {\rm N}\).

Therefore, the force that the \(4\; {\rm kg}\) block exerts on the \(1\; {\rm kg}\) block will be

\(\displaystyle 60\; {\rm N} - \frac{60}{11}\; {\rm N} = \frac{600}{11}\; {\rm N} \approx 55\; {\rm N}\).

When considered individually, the only unbalanced external force on the \(m = 6\; {\rm kg}\) block is the normal force from the \(4\; {\rm kg}\) block. Hence, this force will be equal to the resultant force on the \(m = 6\; {\rm kg}\) block, \((360 / 11)\; {\rm N} \approx 33\; {\rm N}\).

Answer:

formula

Explanation:

f0= square root of F/(m/L)/2L= square root of 200/0.010/2.00/2*2.00= 50 Hz. f=f0+deltaf. f=50+5= 55,45 Hz. f=f0= 50Hz.

both ends of the image and vibrates in the most basic manner while under tension. A mode of vibration consists of two unique components: first, a variation in the vibration over time; and, second, a variation in the motion across the structure's space. The oscillation frequency and any accompanying decay or growth rates are defined by the time variation.

The basic mode, also known as the first harmonic, is the simplest normal mode, where the string vibrates in a single loop and is designated by the number n = 1. The second harmonic refers to the second mode (n = 2) in which the string vibrates in two loops.

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The average power delivered to the circuit by the source in an L-R-C series circuit connected to a 120 Hz AC source with Vᵣₘₛ = 87.0 V, a resistance of 79.0 Ω, and an impedance of 100 Ω at this frequency is approximately 7.10 W.

In an AC circuit, the average power delivered can be calculated using the formula:

P = Iᵣₘₛ²R

where P is the average power, Iᵣₘₛ is the RMS current, and R is the resistance.

To find the RMS current, we can use Ohm's law:

Iᵣₘₛ = Vᵣₘₛ / Z

where Vᵣₘₛ is the RMS voltage and Z is the impedance.

In this case, Vᵣₘₛ is given as 87.0 V, and Z is given as 100 Ω.

Substituting the values into the equation, we get:

Iᵣₘₛ = 87.0 V / 100 Ω = 0.87 A

Now we can calculate the average power:

P = (0.87 A)² x 79.0 Ω = 0.87² x 79.0 W ≈ 7.10 W

Therefore, the average power delivered to the circuit by the source is approximately 7.10 W.

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88km/h/129.1km is 0.68h

Explanation:

it will take 0.68h to travel 129.1km of distance

The higher density allows the protogalactic clouds to cool faster and form an elliptical galaxy rather than a spiral galaxy.

In physical cosmology, a protogalaxy or protogalactic cloud , which could also be called a "primeval galaxy", is a cloud of gas which is forming into a galaxy. It is believed that the rate of star formation during this period of galactic evolution will determine whether a galaxy is a spiral or elliptical galaxy; a slower star formation tends to produce a spiral galaxy. The smaller clumps of gas in a protogalaxy form into stars.

Composition

Since there had been no previous star formation to create other elements, protogalaxies would have been made up almost entirely of hydrogen and helium. The hydrogen would bond to form H2 molecules, with some exceptions. This would change as star formation began and produced more elements through the process of nuclear fusion.

Mechanics

Once a protogalaxy begins to form, all particles bound by its gravity begin to free fall towards it. The time taken for this free-fall to conclude can be approximated using the free-fall equations. Most galaxies have completed this free-fall stage to become stable elliptical or disk galaxies, the disks taking longer to fully form. The formation of galaxy clusters takes much longer and is still in progress now.

This stage is also where galaxies acquire most of their angular momentum. A protogalaxy acquires this due to gravitational influence from neighbouring dense clumps in the early universe, and the further the gas is away from the centre, the more spin it gets.

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The Second Law of Thermodynamics states that the total entropy of an isolated system can only increase over time.

Thermodynamics is the branch of physics that deals with the relationships between heat, work, temperature and energy. It is the study of how energy is converted from one form to another and how it is used to do work. Thermodynamics is concerned with the transfer of energy from one object or system to another and how that energy can be transformed or converted into different forms. It also explores the relationships between entropy, temperature, and energy. Thermodynamics can also be used to predict how systems will behave when exposed to a given amount of energy. Thermodynamics is a powerful tool used to understand the behavior of natural systems and to develop efficient technologies.

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The local group of galaxies which the Milky Way belong to is the Virgo Supercluster. C

The Virgo Supercluster as known as the Local Supercluster is a mass concentration of galaxies that contains the Virgo Cluster and Local Group which in turn contains the Milky Way and Andromeda galaxies, as a host as others galaxies.

Therefore, the local group of galaxies which the Milky Way belong to is the Virgo Supercluster.

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Answer: 15 m/\(s^{2}\)

Acceleration (a) = \(\frac{V{f} - V{i} }{t}\)

Here

\(V_{f}\) = final velocity

\(V_{i}\) = initial velocity

t = time period

a = \(\frac{100 - 70}{2}\)  = 15 m/\(s^{2}\)

the car's acceleration =  15 m/\(s^{2}\)

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Answer:

Explanation:

Assuming the machine is a simple machine, such as a lever or pulley, the machine will not do any more work than is put into it. However, it can change the magnitude or direction (or both) of the input force required to achieve a particular output force.

Because the machine does not increase the work done, if the output force is greater, the output distance must be less.

The applicable observations are ...