55) A typical arteriole has a diameter of 0.080 mm and carries blood at the rate of 9.6×10^−5 cm3/s. (a) What is the speed of the blood in an arteriole? (b) Suppose an arteriole branches into 8800 capillaries, each with a diameter of 6.0×10^−6 m. What is the blood speed in the capillaries? (The low speed in capillaries is beneficial; it promotes the diffusion of materials to and from the blood.)

The work done by a 20-newton force applied at an angle of 45.0° is 565.69 J.

Calculation:-

Force = 20 N

distance = 40 meters

angle = cos 45°

Work done = F.d cosθ

                 = 20×40 × 1/√2

                 = 800 / √2

                =  565.69 J

Force is a push or pulls upon an item because of the object's interaction with some other object. pressure is a power that can exchange the motion of an object. A force can reason an object with mass to alternate its speed, i.e., to boost up. pressure also can be described intuitively as a push or a pull. A force has each significance and course, making it a vector amount.

The phrase 'Force' has a unique meaning. At this degree, it is absolutely appropriate to describe a force as a push or a pull. A force is not something that an object consists of or 'has in it. A force is exerted on one object through another. The concept of a force isn't always restricted to living matters or non-living matters.

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Given,

The distance covered, d=30 m

The time interval, t=8 s

As there is no initial velocity is given, we assume that the initial velocity is u=0 m/s

Acceleration of the can be calculated from one of the equations of motion,

Where a is the acceleration of the body.

On substituting the known values ,

Thus the acceleration of the body is 0.94 m/s²

The radius of the wheel with a tangential velocity of 4.3 m/s and centripetal acceleration of 72 m/s² is 0.25 meter.

The acceleration of an object ,moving through a  circular path is called the centripetal acceleration. It is related to the velocity and radius of curvature of the circular path as follows:

a = v²/r.

The tangential velocity or angular velocity is the rotational analogue of the linear velocity.

given that, tangential velocity v = 4.3 m/s

centripetal acceleration a = 72  m/s²

Then, radius of the wheel is calculated as follows:

r = v²/a

r = (4.3 m/s × 4.3 m/s)72 m/s²

 = 0.25 meter.

Therefore, the radius of the rotating wheel is 0.25 meter.

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Explanation:

23 km/hr x 1.5 hrs = 34.5 km

34.5 km = 34500 meters

Answer: A velocity-time graph shows how velocity changes over time

Explanation:

Answer:velocity

Explanation:

The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.

To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.

Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).

According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.

The total momentum before the interaction is given by:

Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)

Mass of the dog (m1) = 24.4 kg

Velocity of the dog (v1) = 2.14 m/s

Mass of the cat (m2) = 5.53 kg

Velocity of the cat (v2) = 3.56 m/s

Mass of the owner (m3) = 78.5 kg

Velocity of the owner (v) = unknown

Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)

The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.

Total momentum after = 0

Equating the two expressions:

(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0

Simplifying the equation:

(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0

71.8648 kg·m/s + (78.5 kg * v) = 0

Solving for v:

78.5 kg * v = -71.8648 kg·m/s

v = -71.8648 kg·m/s / 78.5 kg

v ≈ -0.916 m/s

Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.

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Answer:

Photography is the art, application, and practice of creating durable images by recording light, either electronically by means of an image sensor, or chemically by means of a light-sensitive material such as photographic film.

Explanation:

In the definition of photography:

the art or process of producing images by the action of radiant energy and especially light on a sensitive surface (such as film or an optical sensor)

Purpose of photography:

To communicate and document moments in time.

Explanation:

When you take a photograph and share it with others, you're showing a moment that was frozen through a picture. This moment can tell someone many things, from the environment to what people are doing.

Hope this helps you.

Answer:

It's an art or an application of clicking photos .

Assuming standard atmospheric conditions, the air pressure at sea level is approximately 1013.25 hectopascals (hPa) or 1 atmosphere (atm). The air pressure decreases with altitude following the barometric formula, which states that pressure decreases by about 1 hPa for every 8 meters of ascent.

Using this formula, we can estimate the air pressure at 1200 meters above sea level as follows:

1200 m / 8 m per hPa = 150 hPa

Therefore, the hiker on a mountain ridge 1200 meters above sea level would experience an air pressure of approximately 863.25 hPa (1013.25 hPa - 150 hPa) or about 0.85 atm.

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

The number of cycles (or full oscillations) that take place in a particular amount of time makes up a wave's frequency.

The wave frequency is the quantity of waves that pass a certain location in a predetermined amount of time. The SI unit for wave frequency is the hertz (Hz), and 1 hertz is equal to 1 wave passing through a fixed point in 1 second.

The number of cycles a wave can complete in a period of time—typically one second—is its frequency. A wave's frequency can be calculated by dividing its wavelength by velocity.

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Let's write the expressions for the electric field strength due to several charges in terms of the following:

• Volume charge density

• Area charge density

• Linear Charge density

The electric field strength can be said to be expression which shows the intensity of an electric field at a given location.

Now, we have the following expressions:

• Electric field strength due to several charges in terms of volume.

We have the expression:

Where V is the volume, r is the distance between charges.

• Electric field strength in terms of area charge density:

We have the expression:

Where A is the area and r is the distance between the charges.

• Electric field strength in terms of linear charge density:

ANSWER:

• In terms of Volume charge density:

• In terms of area charge density:

• In terms of linear charge density:

Answer:

Explanation:

5.6. 1: Electric Field of a Line Segment. Find the electric field a distance z above the midpoint of a straight line segment of length L that carries a uniform line charge density λ. dq=λdl.

Answer:

a protractor

Explanation:

because protractors measure angles

To keep the crate moving with a constant velocity, the force you need to exert on it is the force of kinetic friction, which in this case is 90 N. This is the minimum force required to overcome the force of sliding friction and maintain a constant velocity.

When an object is moving across a surface, there is a force of friction that opposes its motion. This is known as the force of kinetic friction. In the case of the wooden crate being pushed across the floor, the force of sliding friction is 90 N.

In order to keep the crate moving at a constant velocity, the force being applied to it must be equal and opposite to the force of sliding friction. This is because if the applied force is less than the force of sliding friction, the crate will slow down and eventually come to a stop. If the applied force is greater than the force of sliding friction, the crate will accelerate.

The force you need to exert on the crate is:

Force = Force of kinetic friction = 90 N

Note that the mass of the crate is not needed to calculate the force you need to exert, only the force of sliding friction acting on it.

Therefore, the force you must apply to the crate in order to maintain its constant velocity is the force of kinetic friction, which in this instance is 90 N. This is the bare minimum force necessary to overcome sliding friction and preserve constant speed.

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Answer:

8760 N

Explanation:

think this is the right answer :)

Explanation:

It is given that,

The separation between two parallel wires, r = 5.6 cm = 0.056 m

Current in both the wires is 2.65 A

(a) We need to find the magnitude of the force per unit length between the wires. It can be given by :

\(\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi r}\\\\\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 2.65\times 2.65}{2\pi \times 0.056}\\\\\dfrac{F}{l}=2.5\times 10^{-5}\ N/m\)

(b) As the current is in same direction, the wires will attract each other.

Answer:

D. 2.5 x 10^4

Explanation:

10 to the power of 4 is 10,000.

10,000 x 2.5 = 25,000

D. 2.5 x 10⁴ is the scientific notation of Ellie records.

Scientific Notation is the expression of a number n in the form a∗10ᵇ. where a is an integer such that 1≤|a|<10. and b is an integer too. It is a way of writing very large or very small numbers. A number is written in scientific notation when a number between 1 and 10 is multiplied by a power of 10.

According to the question,

The given number is 25,000 m

i.e.

25 x 10³

Since we have to put the decimal  between 2 and 5

It becomes,

2.5  x 10⁴

or

10 to the power of 4 is 10,000.

10,000 x 2.5  = 25,000

Therefore,

The answer is 2.25 x 10⁻⁶ M

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ANSWER

EXPLANATION

Parameters given:

Length of the rod, r = 15 m

Angular speed, ω = 8.0 rev/min = 8.0 * 0.105 rad/s = 0.84 rad/s

Weight of the cart, W = 1900 N

To find the tension on the bar, we have to apply the formula for tension:

where m = mass of the cart = 1900/ 9.8 = 193.88 kg

Therefore, the tension on the bar is:

That is the tension on the bar.

Answer:

0.5A

Explanation:

The current can be calculated using the following equation:

Where P is the power and V is the voltage. Replacing P = 60W and V = 120V, we get:

Therefore, the current is 0.5A

Answer:

Assumption: there is no object between this point charge and the observer.

Explanation:

The electric field of a point charge is inversely proportional to the square of the distance from that point charge.

Let \(k\) denote Coulomb's constant (\(k \approx 8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-1}\).) Let the magnitude of that point charge be \(q\). At a distance of \(r\) from this charge, the electric field due to this charge would be:

\(\displaystyle E = \frac{k \cdot q}{r^{2}}\).

Convert the magnitude of the point charge in this question to standard units:

\(q = 1\; \rm nC = 10^{-9}\; \rm C\).

Apply that equation to find the magnitude of the electric field due to this point charge:

\(r = 1\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(1\; \rm m)^{2}} \\ &\approx 9.0\; \rm N \cdot C^{-1}\end{aligned}\).

\(r = 2\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(2\; \rm m)^{2}} \\ &\approx 2.2\; \rm N \cdot C^{-1}\end{aligned}\).

\(r = 3\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(3\; \rm m)^{2}} \\ &\approx 1.0\; \rm N \cdot C^{-1}\end{aligned}\).

The direction of the electric field at a point is the same as the direction of a force from this field onto a positive point charge at this point.

Because the \((+1\; \rm nC)\) point charge here is positive, the electric field of this charge would repel other positive point charges. Hence, the electric field around this \((+1\; \rm nC)\!\) point charge at any point in the field would point away from this charge.

Answer:

1: 51 m

2: some energy was transformed to other forms

3: 3.24

4: 45j

5: 1020

Explanation:

The required height of hill is 51 m. Hence, option (C) is correct.

Given data:

The mass of person is, m = 80 kg.

The energy expended during climbing is, E = 40,000 J.

The energy possessed by the body by virtue of height is known as potential energy. In the given case, the energy expended by the person will be stored in the form of potential energy. Then,

E = U

E = mgh

here, h is the height of hill and g is the gravitational acceleration.

Solving as,

40000 = 80(9.8) h

h ≈ 51 m

Thus, we can conclude that the required height of hill is 51 m. Hence, option (C) is correct.

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Answer:

The speed stays constant after the force stops pushing.

Explanation:

Speed always stays constant when the force stops pushing it.

The current in the circuit when the voltage across the resistor is equal to the voltage across the inductor is given by:

i(t) = [V_B / R] (1 - e^(-Rt/L)) where t is the time after the switch is closed.

The series circuit in the figure contains an ideal battery with a constant terminal voltage V_B=52 V, an ideal inductor L=42 H, a R=20-ohm resistor, and a switch S. Initially, the switch is open, and there is no current in the inductor. At time t=0 s, the switch is suddenly closed. What is the current in the circuit when the voltage across the resistor is equal to the voltage across the inductor-If the voltage across the resistor and the voltage across the inductor are equal, then the voltage across the inductor is V = IR, where I is the current in the circuit.

According to Kirchhoff's law, the voltage across the resistor is equal to the voltage of the battery minus the voltage across the inductor, i.e., V = V_B - L (di / dt), where di/dt is the rate of change of current, and L is the inductance of the inductor. Equating these two expressions for V, we have: IR = V_B - L (di / dt). Rearranging this equation gives us the following differential equation:di / dt + (R/L) i = (V_B / L)The solution of this differential equation is given by: i(t) = [V_B / R] (1 - e^(-Rt/L)).

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Answer:

S = Vy t + 1/2 g t^2 = 1/2 g t^2    vertical speed with zero initial speed

t = (2 S / g)^1/2      with g = 32 ft/sec^2

t = (900 / 32)^1/2 = 5.30 sec    time to reach ground

V = a t = 32 ft/s^2 * 5.30 s = 170 ft/sec

170 ft/sec / (88 ft/sec / 60 mph) = 116 mph           since 88 ft/sec = 60 mph

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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i think

Answer:

physics. The ______ is a systematic way to observe, experiment, and analyze the world. scientific method. The valid digits in a measurement are called the. significant digits.

Explanation:

truth'

Answer:

Radio waves have frequencies as high as 300 gigahertz(GHz)to as low as 30 hertz(Hz).At 300 GHz the corresponding wavelength is 1mm and at 30Hz is 10,000 km

The average wavelength of radio waves ​ranges from roughly two millimeters to more than 150 kilometers. The wavelengths of radio waves are the longest in the electromagnetic spectrum

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

It is the total length of the wave for which it completes one cycle.

The wavelength is inversely proportional to the frequency of the wave as from the following relation.

C = νλ

They also have the lowest frequencies, ranging from around 4,000 cycles per second, or 3 kilohertz, to roughly 280 billion hertz, or 280 gigahertz.

The wavelengths of radio waves are the longest in the electromagnetic spectrum, ranging from roughly two millimeters to more than 150 kilometers.

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