5/8 subtracted by 3/4

Answer:

1, and that is 27

Step-by-step explanation:

4(x-5)=3x+7

4x-20=3x+7

4x-3x-20-7=0

x-27=0

x=27

a and c are directly proportional to each other when a and b are directly proportional and b and c are directly proportional.

If a and b are directly proportional and b and c are directly proportional, it means that their ratios are equal. Direct proportionality implies that as one variable increases, the other also increases in proportion and as one variable decreases, the other also decreases in proportion.

Mathematically, this can be written as

a = kb and b = mc, where k and m are constants of proportionality.

Multiplying these two equations gives: a = kbm

Substituting the value of b from the second equation in the first equation, we get: a = kmc

Therefore, a and c are also directly proportional to each other with a constant of proportionality km.

Thus, if a increases by a certain factor, c will also increase by the same factor.

If a and b are directly proportional and b and c are directly proportional, then it can be concluded that a and c are directly proportional as well.

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Two tiny parallel horizontal lines serve as the "equality sign" connecting 1 kilogramme of NaCl to 27 ml of a solvent.

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The approximate length of the radius, r is 4.51 cm. SO the option 1 is correct.

In the given question we have to find the approximate length of the radius, r.

As given, circle O has a circumference of approximately 28.3 cm.

The calculation of the circle's boundary is referred as the perimeter or circumference of the circle. Although the circumference of the circle determines the space it occupies.

The circumference of a circle is its length when it's actually opened and represented as a single direction. Units like cm or unit m are typically used to measure it.

As we know that the formula of circumference of circle = 2πr

As circumference of circle = 28.3 cm

So 2πr = 28.3 cm

Divide by 2π on both side, we get

r = 14.15/π

π = 3.14

So r = 14.15/3.14

r = 4.51 cm

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The complete question is:

Circle O has a circumference of approximately 28.3 cm.

What is the approximate length of the radius, r?

a. 4.5 cm

b. 9.0 cm

c. 14.2 cm

d. 28.3 cm

The approximate length of the radius, r, is 4.5 cm.

The formula for calculating the radius, r, of a circle is r = C/2π, where C is the circumference of the circle. In order to calculate the approximate length of the radius, we must first calculate the circumference.

Let's assume that the circumference of the circle is 28.3 cm. To calculate the circumference, we can use the formula C = 2πr. We know the circumference and want to solve for the radius, so we can rearrange the formula to solve for r: r = C/2π.

Plugging in our values, we can calculate the approximate length of the radius: r = 28.3 cm/2π = 4.5 cm. Therefore, the approximate length of the radius, r, is 4.5 cm.

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Answer:

Step-by-step explanation:

(D)

Answer:

8.

Step-by-step explanation:

5 and 5 1/2 are the only fractions between 4 and 6. There are 4 dots above each, and 4 x 2 = 8. (I know the amount of dots because I had this question.)

There are two baskets that weigh more than 4 but less than 6.

The weights of fruit baskets are:

4, 1, 2, 5, 5(1/2), 6

Weight is the quantity of matter in a physical body.

We can see that fruit baskets that weigh more than 4 pounds but less than 6 pounds are ones with weights of 5 pounds and 5(1/2) pounds.

So, there are two baskets that weigh more than 4 but less than 6.

Thus, there are two baskets that weigh more than 4 but less than 6.

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The number of sacks of trash that Jorge's brother picked up is given as follows:

3.75 sacks.

The number of sacks of trash that Jorge's brother picked up is obtained applying the proportions in the context of the problem.

Jorge picks up 2 1/2 sacks of trash, which is a mixed number, hence the decimal number that represents this amount is given as follows:

2 + 1/2 = 2 + 0.5 = 2.5 sacks.

His brother picks up 1 1/2 times as much as Jorge, which is 1 + 1/2 = 1.5 times the amount picked by Jorge, hence the number of sacks of trash that Jorge's brother picked up is obtained as follows:

2.5 x 1.5 = 3.75 sacks.

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The formulas for the transformations mentioned in the problem are:

• Reflection over the x-axis: f(x) → g(x) = -f(x),

• Shift down by a units (a > 0): f(x) → g(x) = f(x) - a,

• Shift left by b units (b > 0): f(x) → g(x) = f(x + b),

• Vertical stretch by a factor k: f(x) → g(x) = k f(x).

In this problem, we have the transformation:

Comparing this expression with the transformations above, we identify:

• a ,reflection over the x-axis, due to the minus sign in front of 5,

• a ,shift down by 8 units,,

• a shift left by 3 units,,

• a ,vertical stretch by a factor of 5,.

We see that the only transformation not made is a shift right by 3 units.

C. Shift right 3 units

Answer:

c

Step-by-step explanation:

Answer:

the correct answer is

B. 3/5 × d = 345

Step-by-step explanation:

steps are in the picture.

Note:If you need to ask question about it ,i can make you understand.thanks

Answer:

26

Step-by-step explanation:

w = 5 so 7w is 7 x 5 = 35 and x = 9 so it’s 35 - 9 which is 26

Given the function:

We will find the y-intercept of the function

The y-intercept is the value of (y) when (x = 0)

so, when x = 0

so, the answer will be option 1)

1) The y-intercept is 2.

The equation of the axis of symmetry is x = 1.

To Avoid Large Errors/Overflow/Underflow :

Part (a) For x=9.8 201 and y=10.2 199,

we have the following expressions:

(i) z= x²+y²

(ii) z=y{(x/y)²+1} = y{(x²/y²)+1}

Comparing (i) and (ii) terms: In terms of power of resisting overflow,

(ii) is better because we do not have large sum of squares of x and y which are almost same order of magnitude

Part (b) With a=c=1 and for 100 values of b over the interval \([10^{7.4},10^{8.5]\) generated by the MATLAB command 'logspace(7.4,8.5,100)', w

e have the following formulas for roots of quadratic equation:

(i) [x1,x2=2a₁{(-b)±sign(b){b²-4ac}¹/²}]

(ii) [x1=2a₁{(-b)-sign(b){b²-4ac}¹/²},x2=x1c/a]

For better resistance to the loss of significance, (ii) is better. As, (ii) is designed to avoid subtracting two nearly equal numbers.

Part (c)For 100 values of x over the interval [\(10^{14},10^{16\)],

we have the following expressions that are mathematically equivalent:

(i) y=2x²+1-1

(ii) y=2x²+1+(1/2x²)

Comparing (i) and (ii) terms: In terms of power of resisting underflow, (ii) is better because it has an additional term of larger order which can counteract the loss of significance at the small x.

Part (d) For 100 values of x over the interval [\(10^{(-9)},10^{(-7.4)\)],

we have the following expressions that are mathematically equivalent:

(i) y=(x+4)-x/ (x+3)

(ii) y=(x+4+x)/2(x+3)

Comparing (i) and (ii) terms: In terms of power of resisting loss of significance, (ii) is better because it has a fraction with 2 instead of a difference, hence reducing the effect of the cancellation.

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Yes, it is possible for a process to pass through the 2nd or 4th quadrant. The 2nd quadrant is characterized by negative values of work done and positive values of heat added.

This could happen in a scenario where a gas is compressed at a constant temperature, which results in negative work done, but heat is added to the gas to maintain its temperature. The 4th quadrant is characterized by negative values of both work done and heat added. This could happen in a scenario where a gas is expanded at a constant temperature, which results in negative work done and no heat is added or removed from the gas.

As for the effect of a negative value of the polytropic index 'n', it indicates that the process is non-adiabatic and not reversible. A negative value of 'n' means that the process is not able to maintain constant heat transfer or constant entropy. This could result in energy losses and a decrease in the efficiency of the process. It could also indicate that the process is not in equilibrium and is being driven by external forces. Overall, a negative value of 'n' can have negative effects on the performance and stability of a process.

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The error represented in this scenario is an inappropriate task allocation or a mismatch between job responsibilities and the assigned task during the interview process.

The primary role of a customer service representative is to interact with customers, address their concerns, and log calls professionally and efficiently. In contrast, performing a detailed analysis of call-in data falls under the domain of data analysis or business intelligence roles.

By asking the candidate to perform a task unrelated to their potential job responsibilities, the company may not accurately assess the candidate's aptitude for customer service tasks. This error could lead to selecting a candidate who may excel in data analysis but may not possess the necessary communication and problem-solving skills required for a customer service representative position.

To avoid this error, the company should focus on evaluating candidates based on their skills, experience, and performance in tasks directly relevant to the customer service role.

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The area of a rectangle with side lengths of 6/8 meter and 4/10 meter is,

Area of rectangle = 6/8 meter × 4/10 meter

                             = 24 / 80 meters²

                             = 6 /20 meters²

                             = 0.3 meters²

Hence, The area of a rectangle with side lengths of 6/8 meter and 4/10 meter is 0.3 meters².

In Trigonometry, it is important that the right triangles (reference triangles) have a consistent orientation. The reference triangle always has a leg perpendicular to the x-axis, the hypotenuse is positive, and θ is the angle adjacent to the x-axis and hypotenuse.

In Trigonometry, the orientation of the right triangles (reference triangles) is important to maintain consistency in the results. A right triangle is considered a reference triangle when one of its angles is used to measure the other two angles in the triangle.

The reference triangle always has one leg perpendicular to the x-axis. This leg is known as the y-axis. The hypotenuse of the right triangle is the line segment connecting the two endpoints of the x and y axes. The theta is the angle adjacent to the x-axis, which is measured from the positive x-axis towards the positive y-axis.

The orientation of the reference triangle is used as a reference when measuring angles in the unit circle. The angles in the unit circle are typically measured in radians and are used to find the values of trigonometric functions such as sine, cosine, and tangent.

In summary, the reference triangle in Trigonometry always has a leg perpendicular to the x-axis, the hypotenuse connecting the endpoints of the x and y axes, and the theta as the angle adjacent to the x-axis. This orientation is important for consistency and accuracy in measuring angles in the unit circle.

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--The given question is incorrect; the correct question is

"In Trigonometry, it is important that the right triangles (reference triangles) have a consistent orientation. The reference triangles always have a leg perpendicular to the ____, the hypotenuse is____, and θ is the angle adjacent to the _______."--

Answer:

\(\textsf{D.}\quad f(x)=\dfrac{(x-1)}{x(x-3)}\)

Step-by-step explanation:

An asymptote is a line that the curve gets infinitely close to, but never touches.

Vertical asymptotes of a rational function occur when the denominator equals zero.

From inspection of the given graph, the vertical asymptotes are:

Therefore, for the denominator to equal zero, it must include the factors:

Since the only answer option that has the factors x and (x - 3) is option D, the graphed rational function is:

\(f(x)=\dfrac{(x-1)}{x(x-3)}\)

Answer: 5, 15

Step-by-step explanation:

Given

Mr. Ramirez purchased 20 concert tickets

The total price of 20 tickets is \(\$225\)

Concert ticket costs \(\$15\) for adults and \(\$10\) for children

suppose there are x adults and y children

\(\therefore x+y=20\quad \ldots (i)\\\\\Rightarrow 15x+10y=225\quad \ldots(ii)\)

Solving (i) and (ii) we get

\(x=5,\ y=15\)

So, there are 5 adults and 15 children

Answer:

(1, 6.71)

Step-by-step explanation:

I'm assuming that you need to solve this by substitution or elimination since you didn't include any context in your question, just the equations.

To solve this by elimination, first, decide on a variable you want to get rid of / cancel out. I chose y. To do this, you need to find the least common multiple (LCM) of 7 and 5, which is 35. Now, multiply the top equation, 21x + 7y = 42, by -5. Multiply the bottom equation, -5x + 5y = 10, by 7. Make sure when you multiply that you either make the 5 or the 7 negative so you can cancel out y. I chose to make 5 negative.

After you multiply by the -5 and the 7, rewrite your new equations:

-105x - 35y = -210

-35x + 35y = 70

Now, add the two equations together. When you do this, the y's cancel out and you're left with -140x = -140. Now, divide both sides by -140, and you're left with x = 1. Plug the value of x into one of your original equations. I chose the bottom equation, -5x + 5y = 10.

-5(1) + 7y = 42   ----->   -5 + 7y = 42.

Add -5 to both sides, which gives you 7y = 47. Divide both sides by 7, which gives you y = 6.71.

The last step is to put the values of x and y into a point: (1, 6.71).

Hope this helps!

i think it is a but i am sorry if it wrong

Step-by-step explanation:

Answer:

Graph

Step-by-step explanation:

If point P has coordinates (x1, y1) and point Q has coordinates (x2, y2), and PQ is reflected across the X-axis, the coordinates of the reflected points P' and Q' can be obtained by flipping the y-coordinates of P and Q and keeping the x-coordinates the same.

Therefore, the coordinates of P' will be (x1, -y1) and the coordinates of Q' will be (x2, -y2).

So, if you want to find the coordinates of the reflected line segment P'Q', you just need to take the coordinates of P' and Q' and connect them with a line. The resulting line segment will have endpoints (x1, -y1) and (x2, -y2).

Note that the length of the reflected line segment P'Q' will be the same as the length of the original line segment PQ, but the orientation of the reflected line segment will be reversed with respect to the X-axis.

Answer:

8 miles

Step-by-step explanation:

Given

Represent the police station with P, Library with L; Fire station with F

The first statement can be represented as:

\(L - P = P - F - 3\)

The second can be represented as:

\(L - P = 5\)

Required

Determine the distance between the police station and the fire station (P - F)

\(L - P = P - F - 3\) --- (1)

\(L - P = 5\) --- (2)

Substitute 5 for L - P in (1)

\(5 = P - F - 3\)

Add 3 to both sides

\(3 +5 = P - F - 3 + 3\)

\(3 +5 = P - F\)

\(8= P - F\)

\(P - F = 8\)

Answer:

12/20=3/5   5/20=1/4 so the answer would be 12/20 + 5/20

Hope this helped you!!

Equivalent fractions for \(\boldsymbol{\frac{3}{5},\frac{1}{4}}\) are \(\boldsymbol{\frac{12}{20},\frac{5}{20}}\) respectively.

A fraction is a portion of another or, more broadly, a set of equal pieces. Equivalent fractions are fractional that have the same value notwithstanding their appearance.

\(\boldsymbol{\frac{3}{5}=\frac{3\times 4}{5\times 4}}\)

  \(=\frac{12}{20}\)

\(\boldsymbol{\frac{1}{4}=\frac{1\times 5}{4\times 5}}\)

  \(=\frac{5}{20}\)

So, equivalent fractions for \(\boldsymbol{\frac{3}{5},\frac{1}{4}}\) are \(\boldsymbol{\frac{12}{20},\frac{5}{20}}\) respectively.

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The sample space of choosing 3 balls at random from a bag containing 3 reds, 5 blues, and 2 greens, without distinguishing between balls of the same color, consists of all possible combinations of the three colors.

To find the sample space, we consider all the possible outcomes of the experiment. Since we are choosing without distinguishing between balls of the same color, we can represent each ball by its color.

The sample space will consist of all possible combinations of the three colors: {RRR, RRB, RRG, RBB, RBG, BBB, BBG, BGG}.

The sample space of choosing a ball from the bag at random, replacing it, and repeating the experiment three times consists of all possible outcomes of the three independent draws.

In this experiment, each draw is independent and the ball is replaced after each draw. Therefore, each draw has the same set of possible outcomes, which is the original set of colored balls in the bag.

Since we repeat the experiment three times, the sample space will consist of all possible combinations of the three draws, where each draw can be any of the three colors: {R, B, G}.

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Answer:

5 more games to be won for the 50% success rate.

Step-by-step explanation:

Total number games played = 500

Number of successful games = 49% of 500

                                                 = 500 × \(\frac{49}{100}\)

                                                 = 245

Number of successful games for the success of 50% = 500 × \(\frac{50}{100}\)

                                                                                        = 250

Therefore, number of game you have to win more = 250 - 245

                                                                                    = 5 games

The number of students in the telescope club by $x$ and the number of students in the math club by $y$.

$y=2x$Now, suppose there are $z$ students who are members of both clubs. Then the total number of students who are in the math club or the telescope club (or both) is given by:$x + y - z$ Substituting $y=2x$ in the above expression, we get:$x + 2x - z=3x - z$ Hence, the expression for the total number of students who are in the math club or the telescope club (or both) is $3x - z$.b)The number of students who are in the math club but not in the telescope club is given by:$y-z$ And the number of students who are in the telescope club but not in the math club is given by:$x-z$ Adding these two expressions, we get the total number of students who are in the math club or the telescope club but not both:$ y-z+x-z $.

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The distance from the earth to venus is an illustration of the sine ratio

The distance from the earth to venus at that time is 1.12 au

See attachment for the diagram that illustrates the complete question.

Start by calculating the angle V using the following sine ratio

SE/sin(V) = VS/sin(E)

This gives

1/sin(V) = 0.723/sin(39.4)

Take the inverse of both sides

sin(V)/1 = sin(39.4)/0.723

Evaluate the quotient

sin(V) = 0.8779

Take the arcsin of both sides

V = 61.4

Calculate the measure of angle S

<S + <V + <E = 180

This gives

<S  = - <V - <E + 180

Substitute known values

<S  = -61.4 - 39.4 + 180

<S  = 79.2

The distance (VE) is then calculated using the following sine ratio

VE/sin(S) = VS/sin(E)

This gives

VE/sin(79.2) = 0.723/sin(39.4)

Multiply bot sides by sin(79.2)

VE = sin(79.2) * 0.723/sin(39.4)

Evaluate the product

VE = 1.12

Hence, the distance from the earth to venus at that time is 1.12 au

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When t = 4, the expression 3⋅2ᵗ evaluates to 48.

Any mathematical statement with variables, numbers, and an arithmetic operation between them is called an expression or an algebraic expression. For instance, the expression 4m + 5 has the terms 4m and 5 as well as the variable m of the given expression, all of which are separated by the arithmetic sign +.

An expression consists of one or more numbers or variables along with one more operation.

When t=4, the expression 3⋅2ᵗ evaluates to:

3⋅2⁴ = 3⋅16 = 48

Hence, when t = 4, the expression 3⋅2ᵗ evaluates to 48.

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The function that describes the equation S = 10S = P x P - 2P + 2 is

\(f(P) = (P^2 - 2P + 2)/9.\)

The given equation S = 10S = P x P - 2P + 2 can be simplified by combining like terms and dividing both sides by 9:

\(9S = P^2 - 2P + 2\)

We can rearrange this equation to solve for S in terms of P:

\(f(P) = (P^2 - 2P + 2)/9\)

Therefore, the function that describes this equation is:

\(f(P) = (P^2 - 2P + 2)/9\)

This function takes an input value of P and outputs the corresponding value of S that satisfies the original equation. The domain of this function is all real numbers since any value of P can be plugged into the equation. However, the range of this function is limited to non-negative values, since S represents a sum of numbers and cannot be negative.

In summary, the function that describes the equation

S = 10S = P x P - 2P + 2 is

\(f(P) = (P^2 - 2P + 2)/9.\)

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