5x555x666x7777x88888

Given the price the stickers can be sold for, and the cost in total of the stickers, you can make profit.

The total revenue that can be made on the sale of the 600 stickers that you got, would be:

= ( Number of stickers in total / Number of stockers per pack ) x Price per sticker pack

= 600 / 10 x 2

= 60 x 2

= $ 120

Your profit would be:

= Total revenue from stickers - total cost

= 120 - 26. 97

= $ 93. 03

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The function f(x,y) = x^2/2 + 5y^3 + 6y^2 − 7x has a global maximum at (7,-4/5) and no global minimum.

To determine if the function has a global maximum or minimum, we need to check its critical points and boundary points.

Taking partial derivatives with respect to x and y and setting them equal to 0, we have:

∂f/∂x = x - 7 = 0

∂f/∂y = 15y^2 + 12y = 0

From the first equation, we get x = 7. Substituting this into the second equation, we get:

15y^2 + 12y = 0

3y(5y + 4) = 0

This gives us two critical points: (7, 0) and (7, -4/5).

To check if these critical points are local maxima or minima, we need to use the second partial derivative test. Taking second partial derivatives, we have:

∂^2f/∂x^2 = 1, ∂^2f/∂y^2 = 30y + 12

∂^2f/∂x∂y = 0 = ∂^2f/∂y∂x

At (7,0), we have ∂^2f/∂x^2 = 1 and ∂^2f/∂y^2 = 0, which indicates a saddle point.

At (7,-4/5), we have ∂^2f/∂x^2 = 1 and ∂^2f/∂y^2 = -12, which indicates a local maximum.

To check for global extrema, we also need to consider the boundary of the domain. However, the function is defined for all values of x and y, so there is no boundary to consider.

Therefore, the function has a global maximum at (7,-4/5) and no global minimum.

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Therefore, When ratios have the same units, we call that ratio a unit ratio.

When ratios have the same units, we call that ratio a unit ratio. An explanation of what is meant by the term ratio would be helpful. A ratio compares the relative sizes of two or more quantities. If the numbers being compared have the same units, then it is called a unit ratio. Unit ratios are ratios that relate to each other in terms of the same measurement unit. They are also sometimes known as unit rates or unit fractions. They are frequently used to compare the relative size of one quantity to another when they are measured in the same units. For example, when we say that there are two apples for every five oranges, we are expressing a ratio between apples and oranges. However, when we say that there are two apples per five oranges, we are using a unit ratio.

Therefore, When ratios have the same units, we call that ratio a unit ratio.

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Answer:

5000

Step-by-step explanation:

50000 / 10= 5000

Cost of the furniture of 50000 rupees with 10% discount is 45000 rupees

A deduction from the usual cost of something

Here Cost of the furniture = 50000 rupees

Discount = 10%

Then the discount price is = total cost × 10%

\(50000(\frac{10}{100})=5000\) rupees

Then the purchased amount = Total price - Discount

\(50000-5000=45000\) rupees

Hence, the purchased price is 45000 rupees

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The probability of waiting longer than one hour for a taxi is approximately 0.5488

Let X be the time between arrivals of taxis at the intersection. Then, X follows an exponential distribution with a mean of 10 minutes, i.e., E(X) = 10.

We want to find the probability of waiting longer than one hour (i.e., 60 minutes) for a taxi. Let Y be the waiting time for a taxi. Then, Y = kX, where k is a constant.

We can find k as follows

E(Y) = E(kX) = kE(X) = 10k

Since the mean waiting time is one hour (i.e., 60 minutes), we have

E(Y) = 60 minutes = 1 hour

Therefore, we get

10k = 1

k = 1/10

Now we can find the probability of waiting longer than one hour for a taxi as follows

P(Y > 60) = P(kX > 60) = P(X > 6) [since k = 1/10]

where the last step follows from the fact that X follows an exponential distribution with mean 10, so P(X > x) = e^(-x/10) for any x > 0.

Therefore, we get

P(Y > 60) = P(X > 6) = e^(-6/10) = e^(-0.6) ≈ 0.5488

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The given question is incomplete, the complete question is:

The time between arrivals of taxis at a busy intersection is exponentially distributed with a mean of 10 minutes. (a) What is the probability that you wait longer than one hour for a taxi?

She  should plant 118 trees per acre to maximize her harvest area. This will yield 96 bushels per tree.

95 trees per acre x 80 bushels per tree = 7600 bushels

96 trees per acre x 77 bushels per tree = 7392 bushels

97 trees per acre x 74 bushels per tree = 7158 bushels

98 trees per acre x 71 bushels per tree = 6938 bushels

99 trees per acre x 68 bushels per tree = 6732 bushels

100 trees per acre x 65 bushels per tree = 6500 bushels

101 trees per acre x 62 bushels per tree = 6262 bushels

102 trees per acre x 59 bushels per tree = 6038 bushels

103 trees per acre x 56 bushels per tree = 5828 bushels

104 trees per acre x 53 bushels per tree = 5532 bushels

105 trees per acre x 50 bushels per tree = 5250 bushels

106 trees per acre x 47 bushels per tree = 4978 bushels

107 trees per acre x 44 bushels per tree = 4716 bushels

108 trees per acre x 41 bushels per tree = 4452 bushels

109 trees per acre x 38 bushels per tree = 4188 bushels

110 trees per acre x 35 bushels per tree = 3925 bushels

111 trees per acre x 32 bushels per tree = 3663 bushels

112 trees per acre x 29 bushels per tree = 3407 bushels

113 trees per acre x 26 bushels per tree = 3151 bushels

114 trees per acre x 23 bushels per tree = 2895 bushels

115 trees per acre x 20 bushels per tree = 2300 bushels

116 trees per acre x 17 bushels per tree = 1972 bushels

117 trees per acre x 14 bushels per tree = 1638 bushels

118 trees per acre x 11 bushels per tree = 1306 bushels

Therefore, 118 trees per acre will yield the highest harvest of 1306 bushels.

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Answer:

y= 3/5x + 1

Step-by-step explanation:

Slope intercept form is modeled by the equation y=mx+b.

M = slope, while B = y-intercept.

The y-intercept in this scenario equals (0, 1) or just simply 1.

The slope equals 3/5. This can be found with rise/run or y/x.

Answer:

n = -1 , 3.5

Step-by-step explanation:

Move the terms to the left side and set equal to zero. Then set each factor equal to 0

The substitution that has been applied to B(x, y) is dt B(x, y) = √(1+t) (1+t)x+y tx-1.

The substitution that has been applied to B(x, y) is t = tan² 0

The substitution for x and y using the trigonometric identities is given by,

x = sin² 0 / cos² 0 = tan² 0   …(1)

y = sin² 0   …(2)

Differentiating both sides of equation (1) with respect to θ, we get

dx / dθ = 2tan 0 sec² 0

Putting the values of x and y in B(x, y), we get

B(x, y) = I 25 (sin 0)² (sin² 0 / cos² 0)-1 (cos 0)² (sin² 0)-1 dθ

= I 25 (sin 0)² / cos² 0 * cos² 0 / sin² 0 dθ

= I 25 tan² 0 dθ

= 25

∫ t dt √1+t

Now, we need to find the value of dt B(x, y) in terms of t.

To find dt B(x, y), we use the chain rule of differentiation and get

dt B(x, y) = ∂B/∂x dx/dt + ∂B/∂y dy/dt

= 25(2 sin 0 cos 0 sin² 0 / cos³ 0) * 2 sin 0 cos 0 sin 0 cos 0 dθ

= 100 (sin 0)³ (cos 0)³ / cos⁴ 0 dθ

= 100 (sin 0)³ / cos 0 dθ

Now, putting the values of x, y, and t, we get

dt B(x, y) = 100 sin³ 0 / cos 0 dθ

= 100 sin³ θ / cos θ dθ

Using the identity 1+t = sec² 0 or cos² 0 = 1 / (1+t), we can rewrite the above integral as

∫ 100 sin³ θ / cos θ dθ

= ∫ (1+t) (1+t)½ dt

Substituting the limits, we get

∫ 100 sin³ θ / cos θ dθ

= ∫ √(1+t) (1+t)x+y tx-1 dt

Answer: dt B(x, y) = √(1+t) (1+t)x+y tx-1.

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The probability that the mean run time for the 40 runners is between 141 and 143 is 0.1059.

To calculate the probability, we need to assume that the run times for the runners are normally distributed. Let's also assume that the population standard deviation is known to be 5 minutes.

The distribution of the sample mean can be approximated by a normal distribution, with the mean of the sample mean being equal to the population mean, and the standard deviation of the sample mean being equal to the population standard deviation divided by the square root of the sample size (i.e., 5 / sqrt(40)).

Now we can calculate the z-scores for the lower and upper bounds of the desired interval. The z-score formula is given by z = (x - μ) / (σ / sqrt(n)), where x is the value we want to find the probability for, μ is the population mean, σ is the population standard deviation, and n is the sample size.

For the lower bound:

z_lower = (141 - 140) / (5 / sqrt(40)) ≈ 0.8944

For the upper bound:

z_upper = (143 - 140) / (5 / sqrt(40)) ≈ 1.7889

Using a standard normal distribution table or a calculator, we can find the area under the curve between these two z-scores. The probability is equal to the area under the curve between the z-scores.

P(0.8944 < z < 1.7889) ≈ 0.1059

The probability that the mean run time for the 40 runners is between 141 and 143 minutes is approximately 0.1059, or 10.59%. This implies that there is a relatively high likelihood that the sample mean falls within this range.

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Answer:

.....................

Answer:

The value of R is -0.5212

This is a moderate negative correlation, which means there is a tendency for high X variable scores to go with low Y variable scores (and vice versa).

Step-by-step explanation:

Answer:

0.09 or 9%

Step-by-step explanation:

I = Prt

Given:

I = 1890

P = 7000

t = 3

Work:

I = Prt

r = I/(Pt)

r = 1890/(7000 x 3)

r = 1890/21000

r = 0.09

Tom is 12 and Jan is 17

Answer: Tom is 6 y/o

Part a) The final image formed by the second lens will be located on the opposite side of the lens as the object.

To determine the image distance from the second lens, we can use the lens formula:

1/f = 1/v - 1/u,

where f is the focal length of the lens, v is the image distance, and u is the object distance. Given that the object distance is 35.0 cm and the focal length of the lens is 22.0 cm, we can substitute these values into the lens formula to solve for v. The lens formula can be rearranged to:

v = 1/(1/f + 1/u).

Substituting the values, we have:

v = 1/(1/22 + 1/35) = 1/(0.0455 + 0.0286) ≈ 1/0.0741 ≈ 13.5 cm.

Therefore, the image distance from the second lens is approximately 13.5 cm.

Part b) The total magnification of the system is given by the product of the individual magnifications of each lens. The magnification of a lens can be calculated using the formula:

magnification = -v/u,

where v is the image distance and u is the object distance. For the first lens, the object distance is 35.0 cm and the image distance is the distance between the lenses, which is 16.5 cm. Therefore, the magnification of the first lens is:

magnification_1 = -16.5/35.0.

For the second lens, the object distance is the distance between the lenses, which is 16.5 cm, and the image distance is 13.5 cm (as calculated in part a). Therefore, the magnification of the second lens is:

magnification_2 = -13.5/16.5.

The total magnification is the product of these two magnifications:

total magnification = magnification_1 * magnification_2.

Substituting the values, we have:

total magnification = (-16.5/35.0) * (-13.5/16.5) ≈ 0.706.

Therefore, the total magnification is approximately 0.706.

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The equation that can be used to determine the number of hours that Anoop provided legal services is h = $612 / $72 .

Division is the mathematical process used in grouping a number into equal parts using another number. The result of the division process is known as the quotient. The sign used to denote division is ÷. Division is one of the basic mathematical operations.

In order to determine the number of hours that Anoop provides legal services, divide the total amount that he charges the client by the charge per hour.

Number of hours that Anoop worked = total amount he charges the client / charge per hour

h = $612 / $72

h = 8.5 hours

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Answer:

D 20

Step-by-step explanation:

By use of LCM

the LCM of 4 and 5 is 2 x 2 x 5=20

therefore their common denominator is 20

Answer:

mABC=130°

mEBD=130°

mABE=50°

Step-by-step explanation:

The average distance that the transmitter and receiver should attain before working is 16 feet.

The best range or distance within which a receiver can get optimum signals from a wireless transmitter is 16 feet. For radios, the average distance is 50 km.

To obtain the accurate distance, we multiply the time taken to transmit 1 bit by the average speed of transmission. When the minimal distance is close enough, the rate of interference will be limited.

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Quotient of 2 and x is   2/x

nine more than 2/x is = 9+ (2/x)

so therefore, we have 9 + 2/x

hope this helps :)

Answer:

b

Step-by-step explanation:

im pretty sure

Answer:x=4 y=6.66666666667

Step-by-step explanation:

Answer: 10

Step-by-step explanation:

tbh its too long to explain i gtg now but plz just trust me

Answer:

If the product of any two numbers is zero,then one or both of the numbers is zero.That is,if ab=0, then a=0 or b=0 (which includes the possibility that a=b=0).

Answer:

K would be 8

Step-by-step explanation:

8-2 = 6

6/3 = 2

Work Shown:

I'm assuming you meant to write 4p^3+8p^2+3p+6

If so, then we would have these steps

4p^3+8p^2+3p+6

(4p^3+8p^2)+(3p+6)

4p^2(p+2)+3(p+2)

(4p^2+3)(p+2)

Answer:

Step-by-step explanation:

Thde y-intercept is the value oy y when x = 0.  The data table tells us the value of y when x=0 is 4.  The ordered pair is (0,4)