6. The work done in pushing a 40 kg chair from the kitchen table to 10 meters down the
hall would be about_
,neglecting friction.
A. 40J
B. 4000J
C. OJ
D. 0.25J

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

Answer:

the interation blood veins

Explanation:

Answer:

a) 14.76 psi

b) 15.59 psi

c) 15.68 psi

d) The solution method is reasonable

Explanation:

The formula for maximum pressure is given as using Bernoulli's Equation :

Pmax = p + 1/2ρV²

Where ρ = Density = 0.002376slug per cubic foot

p = Atmospheric pressure in pounds per cubic foot = 14.6959 pounds per square inch

Converting pounds per square inch to pounds per square foot

= 1 pounds per square inch = 144 pounds per square foot

14.6959 pounds per square inch =

14.6959 pounds per square inch × 144 pounds per square foot

= 2116.2096 pounds per square foot

V = Velocity of the flow = Speed limit.

(a) For safety, the pit lane speed limit is 60 mph. At this speed, what is the maximum pressure on his hand?

Our speed limit is 60 mph

We convert to ft/s

1 mph = 1.46667 ft/s

60 mph =

60 mph × 1.46667 ft/s = 88 ft/s

Pmax = p + 1/2ρV²

Pmax = 2116.2096 + (0.5 × 0.002376 × 88²)

Pmax = = 2125.409472 Ib/ft² =

Converting to psi.

= 2125.409472/144

= 14.759788 psi

≈ 14.76 psi

(b) Back on the race track, what is the maximum pressure when he is driving his IndyCar at 225 mph?

Our speed limit is 225 mph

We convert to ft/s

1 mph = 1.46667 ft/s

225 mph =

225 mph × 1.46667 ft/s = 330 ft/s

Pmax = p + 1/2ρV²

Pmax = 2116.2096 + (0.5 × 0.002376 × 330²)

Pmax = 2245.5828 Ib/ft² =

Converting to psi.

= 2245.5828/144

= 15.594325 psi

≈ 15.59 psi

(c) On the straightaways, the IndyCar reaches speeds in excess of 235 mph.

Our speed limit is 235 mph

We convert to ft/s

1 mph = 1.46667 ft/s

235 mph =

235 mph × 1.46667 ft/s = 344.667 ft/s

Pmax = p + 1/2ρV²

Pmax = 2116.2096 + (0.5 × 0.002376 × 344.667²)

Pmax = = 2257.338465 Ib/ft² =

Converting to psi.

= 2257.3384654/144

= 15.675961562 psi

≈ 15.68 psi

d) For this speed, is your solution method for parts (a and (b) reasonable? Explain.

It is important to note that: the value of 1 atmosphere = 14.696 psi

If we look at the solution above, we can see that the maximum pressure of the speeds in question a, b, c which are: 14.76 psi, 15.59 psi, 15.68 psi respectfully are just a little bit outside the range of 1 atmosphere.

Hence, this is not significant enough to cause damage or harm the hands of Tony Kanaan therefore, my solution method for parts (a and (b) reasonable is reasonable.

Answer: 0.25 seconds.

Explanation:

The yo-yo does 240 revolutions in one minute, and we know that one minute has 60 seconds, then the revolutions per second can be calculated as:

240 rev/60s = 4 rev/s, this will be the frequency of the yo-yo

The frequency is actually written as: f = 4 Hz = 4 s^-1

We want to find the period of this yo-yo.

The period is the duration of one cycle, and we have the relation:

f = 1/T

Where f is the frequency and T is the period, then:

T = 1/f

And we know the value of f, it is f = 4 s^-1

Then the period will be:

T = 1/(4 s^-1) = (1/4) s

Then the period of the yo-yo is 1/4 seconds = 0.25 seconds.

The mechanical energy of the baseball when it is at a height of 9.0m is 39.7 N.

The mechanical energy of the bat is in the form of potential energy.

At a height of 9.0m, the potential energy of the ball = 0.45 * 9.81 *

Potential energy = 39.7 N

In conclusion, the mechanical energy of the baseball bat is the potential energy at that height.

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The coefficient of static friction between the block of wood and the table is 0.449.

The weight of the block of wood is Mg = 4.0 kg × 9.81 m/s^2 = 39.24 N.

The coefficient of static friction μs is given by the equation μ_s = fs/N, where N is the normal force from the table.

Since the block is not accelerating vertically, we know that N = Mg, so we have:

μs = fs/N = 17.64 N / 39.24 N = 0.449

Therefore, the coefficient of static friction between the block of wood and the table is 0.449.

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The maximum height to which the ball attain before falling back down is 1147.96 m

The following data were obtained from the question:

The maximum height reached by the ball can be obtained as illustrated below:

v² = u² – 2gh (since the ball is going against gravity)

0² = 150² – (2 × 9.8 × h)

0 = 22500 – 19.6h

Collect like terms

0 – 22500 = –19.6h

–22500 = –19.6h

Divide both side by –19.6

h = –22500 / –19.6

h = 1147.96 m

Thus, the maximum height reached by the ball is 1147.96 m

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The air pressure that will produce a force of the given magnitude is 135 times the pressure transmitted by the liquid. The value of P2, the pressure transmitted by the liquid, is not given in the problem, so we cannot determine the exact value of P1.

The planet's gravitational pull on the gases above its surface produces atmospheric pressure, which depends on the planet's mass, the radius of its surface, the quantity, makeup, and vertical distribution of the gases in the atmosphere.

The following equations describe the force that compressed air exerts on a tiny piston:

F1 = P1 * A1

The larger piston, which has a larger area A2, receives the power via the liquid. The larger piston's power is determined by:

F2 = P2 * A2

Pascal's rule states that the larger piston receives the same amount of pressure P1 as the smaller piston, so we have:

P1 = P2

Since the forces F1 and F2 are equal, we have:

F1 = F2

Therefore:

P1 * A1 = P2 * A2

P1 * (pi * (5.00 cm)²) = P2 * (pi * (15.0 cm)²)

Simplifying and solving for P1, we get:

P1 = (P2 * A2 * (5.00 cm)²)/ (A1 * (15.0 cm)²)

Substituting A1 = pi * (5.00 cm)² and A2 = pi * (15.0 cm)², we get:

P1 = (P2 * 15.0²) / 5.00²

P1 = 135 * P2.

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Two forces acting on the rocket immediately after leaving the launching pad are the gravitational force and the thrust force.

1. Gravitational Force: The gravitational force is the force exerted by the Earth on the rocket due to their mutual gravitational attraction. It acts downward and is responsible for the rocket's weight.

This force can be represented by the equation Fg = mg, where Fg is the gravitational force, m is the mass of the rocket, and g is the acceleration due to gravity. The gravitational force acts to pull the rocket downward, opposing its upward motion.

2. Thrust Force: The thrust force is the force generated by the rocket's engines as they expel exhaust gases in the opposite direction. It acts upward and propels the rocket forward.

The magnitude of the thrust force depends on factors such as the design of the rocket engines, the amount of fuel burned, and the rate of exhaust gas expulsion. The thrust force must be greater than or equal to the gravitational force for the rocket to overcome Earth's gravity and achieve upward acceleration.

Initially, when the rocket is launched, the thrust force is at its maximum while the gravitational force remains constant. As the rocket gains altitude, the gravitational force decreases slightly due to the increasing distance from the Earth's center.

However, the thrust force continues to be the dominant force propelling the rocket upward.

It's important to note that other forces such as air resistance and wind may also act on the rocket, but immediately after leaving the launching pad, these forces are typically negligible compared to the gravitational force and thrust force.

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Given:

m∠XOB = 90 degrees

Where AOB forms a line segment.

The figure below represents this situation.

From the figure above, we can see that:

m∠XOB = m∠AOX

m∠XOB + m∠AOX = 90 + 90 = 180 degrees

The linear pair theorem states that if two angles form a linear pair, then they are supplementary angles and supplementary angles are angles that sum up to 180 degrees.

Hence, ∠XOB and ∠AOX are supplementary angles by applyng the linear pair theorem.

Also, by applying the substitution property of equality, 2(m∠XOB = 180 degrees).

ANSWER:

• Linear pair theorem

• Substitution property of equality.

The true statement about the electric potential for the equipotential surface is  \(V_A = V_B = V_C\)

A surface with an equipotential potential is one where all points on the surface have the same electric potential. .

That is an equipotential surface is that surface at every point of which, the electric potential is the same.

The formula for the potential across every point on the surface is given as;

V = F/Q x R

V = ER

where;

Since the surface is equipotential with uniform electric across the surface, the electric potential at any point across the surface will be the same.

So \(V_A = V_B = V_C\)

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The orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s. The correct answer is option C

The speed of an object travelling around a circle depends on two quantities namely;

Given that  an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2)

The given parameters are:

Let us first calculate the gravitational field strength on the Saturn.

g = GM/r²

Substitute all the necessary parameters and convert km to m

g = (6.67 × \(10^{-11}\) × 5.68 × \(10^{26}\)) ÷ (300000 × 1000)²

g = 3.79 × \(10^{16}\) ÷ 9 × \(10^{16}\)

g = 0.421 m/s²

The  orbital speed will be

V² = gr

V² = 0.4211 × 300000 × 1000

V² = 126333333.3

V = √126333333.3

V = 11239.8 m/s

Convert it to Km/s by dividing the answer by 1000

V = 11239.8/1000

V = 11.2 Km/s

Therefore, the orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s

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Answer:

1.05×108NC−1,1.17×108NC−1, zero

Explanation:

A uniformly charged sphere has a total charge of 300muC and radius of 8 cm. find the electric field (i) at a point 16 cm from the centre of the sphere (ii) at a point on the surface of the sphere (iii) at a point inside the sphere.

CARRY ON LEARNING

Galileo Galilei was an Italian physicist, mathematician, astronomer, and philosopher who made significant contributions to the scientific revolution during the Renaissance. He is often referred to as the "father of modern observational astronomy" and the "father of modern science."

Galileo made a number of important discoveries and contributions to science. Some of his most significant contributions include:

1- The law of falling bodies: Galileo is credited with developing the concept of free-fall and the mathematical relationship between distance and time for objects in free-fall. He conducted a series of experiments in which he dropped objects of different masses from the Leaning Tower of Pisa to demonstrate that all objects fall at the same rate in a vacuum, regardless of their mass.

2- The telescope: Galileo is credited with building the first practical telescope, which he used to observe the heavens and make a number of important discoveries. He observed the phases of Venus, the lunar surface, and the Galilean moons of Jupiter, among other things.

3- The laws of motion: Galileo is credited with developing the concept of inertia and the laws of motion that later formed the basis of classical mechanics. He also developed the concept of momentum and introduced the idea of a mathematical relationship between force, mass, and acceleration.

4- The scientific method: Galileo is credited with pioneering the scientific method, which involves making observations, developing hypotheses, testing hypotheses through experiments, and drawing conclusions based on the results. This approach to science is still used today and is fundamental to the scientific process.

Your f(x) value is a little ambiguous, so I am assuming the value of f(x)=2x-1

Answer:

(f-g)(x) = 2x-x²+6

Explanation:

f(x)=2x-1

g(x)=x²-7

(f-g)(x)=f(x)-g(x)

          = (2x-1)-(x²-7)

          = 2x-1-x²+7

          = 2x-x²+6

Therefore,

(f-g)(x) = 2x-x²+6

Answer:

The time taken by the wave to travel 8 m is 0.19 s .

Explanation:

frequency, f = 70 Hz

Amplitude, A = 5 mm

Wavelength = 0.6 m

The wave speed is given by

wave speed, v = frequency x wavelength

v = 70 x 0.6

v = 42 m/s

Distance, d = 8 m

Let the time taken is t.

So, \(t =\frac{d}{v}\\\\t =\frac{8}{42}\\\\t = 0.19 s\)

Answer:

I think the object would accelerate.

Explanation:

When the unbalanced force hits the object, it transfers some of its force to the object, making it accelerate

Answer:

5 newtons

Explanation:

Just divide them

The coefficeint of friction given that the object is pulled by a force of 3 N is 0.15

The coefficient of friction is related to force of friction according to the following formula:

Frictional force (N) = coefficient of friction (μ) × normal reaction (N)

F = μN

With the above formula, we can obtain the coefficient of friction as follow:

F = μN

3 = μ × 20

Divide both sides by 20

μ = 3 / 20

μ = 0.15

Thus, the coefficient of friction obtained is 0.15

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The phenomenon that occurs when one wave overlaps and combines with another is Interference.

Wave optics is the branch of physics which deals with the study of optical phenomena like polarization, refraction, diffraction, interference, etc. Study of waves and wave characteristics.

Here,

Interference is the phenomenon of combining of waves when two or more waves superpose or overlaps to form a resultant which can have a higher, lower or the same amplitude as the combining waves.

Hence,

The phenomenon occurs when one wave overlaps and combines with another is Interference.

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Answer:

126

Explanation:

If the coefficient of kinetic friction between Josh's sled and the snow is 0.08, he slides 6.97 meter from the base of the hill.

To find how far from the base of the hill Josh's sled ends up, we need to first find the speed of the sled at the bottom of the hill using the conservation of energy principle,

mgh = (1/2)mv², plugging in the values given in the problem, we get,

m(9.81 m/s²)(3.5 m) = (1/2)mv²

Simplifying and solving for v, we get,

v = √(2gh)

v = √(2(9.81 m/s²)(3.5 m))

v = 8.29 m/s

Now we can use the kinematic equation,

d = vt - (1/2)at, to find how far the sled slides on the horizontal patch of snow before coming to a stop, where d is the distance traveled, v is the initial velocity (8.29 m/s), a is the acceleration due to friction (-μg), and t is the time it takes to come to a stop (which we can find by setting v = 0 and solving for t),

0 = 8.29 m/s - μg*t

t = 8.29 m/s / μg

Substituting this value of t back into the kinematic equation, we get,

d = (8.29)(8.29/μg) - (1/2)μg(8.29/μg)²

d = 6.97 m

Therefore, Josh's sled ends up 6.97 meters from the base of the hill.

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To calculate the electric force between two charges, we can use Coulomb's law:

F = k * |q1 * q2| / r^2

where F is the electric force, k is the electrostatic constant (k ≈ 8.99 × 10^9 N m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.

In this case, q1 = 0.0042 C, q2 = -0.0050 C, and r = 0.0030 m.

Substituting these values into the equation:

F = (8.99 × 10^9 N m^2/C^2) * |0.0042 C * (-0.0050 C)| / (0.0030 m)^2

F = (8.99 × 10^9 N m^2/C^2) * 0.000021 C^2 / 0.000009 m^2

F ≈ 1977.78 N

Therefore, the electric force between the two charges is approximately 1977.78 Newtons.

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Answer:

18 kg * m/s

Explanation:

The equation for momentum is:

momentum = mass * velocity

And although the problem already gave velocity, you must calculate the mass from the graviational force.

Fg = 3.4N = mg = 9.8m

mass = 3.4 N / 9.8 m/s^2 = 0.3469 kg

Momentum = 52m/s * 0.3469 kg - 18.041 kg * m/s = 18

Answer:

A

Explanation:

One of the main benefits of informational interviewing is that it allows the person conducting the interviews to gain insights and information about a particular career or industry.

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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The flux through the large cube is four times that through the small cube.

Electric flux is the rate at which the electric field flows through a given area. The electric flux is directly proportional to the number of electric field lines going through the virtual surface.

i.e. Flux is directly proportional to Area.

Let A1 = Area of gaussian surface with length L.

     A2= Area of gaussian surface with length 2L.

Since this is a cube, area of cube = \(6L^{2}\) , where L = length of side

So, A1 = \(6L^{2}\) and A2 = \(24L^{2}\)

On dividing these two, we get A1/A2 = 1/4

i.e. A2 = 4 A1

Hence the flux through the large cube is four times that through the small cube.

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