Answers
Answer:
Step-by-step explanation:
Simplifying
6(2x + -6) = -7(-2x + 4)
Reorder the terms:
6(-6 + 2x) = -7(-2x + 4)
(-6 * 6 + 2x * 6) = -7(-2x + 4)
(-36 + 12x) = -7(-2x + 4)
Reorder the terms:
-36 + 12x = -7(4 + -2x)
-36 + 12x = (4 * -7 + -2x * -7)
-36 + 12x = (-28 + 14x)
Solving
-36 + 12x = -28 + 14x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-14x' to each side of the equation.
-36 + 12x + -14x = -28 + 14x + -14x
Combine like terms: 12x + -14x = -2x
-36 + -2x = -28 + 14x + -14x
Combine like terms: 14x + -14x = 0
-36 + -2x = -28 + 0
-36 + -2x = -28
Add '36' to each side of the equation.
-36 + 36 + -2x = -28 + 36
Combine like terms: -36 + 36 = 0
0 + -2x = -28 + 36
-2x = -28 + 36
Combine like terms: -28 + 36 = 8
-2x = 8
Divide each side by '-2'.
x = -4
Simplifying
x = -4
Answer: i would say D no solution
Related Questions
Which of the following are solutions to the quadratic equation below?\( {x}^{2} + 8x = 9\)Check all that apply.
![Which of the following are solutions to the quadratic equation below?[tex] {x}^{2} + 8x = 9[/tex]Check](https://i5t5.c14.e2-1.dev/h-images-qa/contents/attachments/JxDnsIDg3BoMiMgwI5sDBo56Xiuol3rn.png)
Answers
Given:
There are given the equation:
\(x^2+8x=9\)
Explanation:
According to the question:
We need to find the solution to the given quadratic.
Then,
To find the solution, we will use the quadratic equation formula.
\(x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)Then,
From the equation:
\(x^2+8x-9=0\)Where,
\(a=1,b=8,c=-9\)Then,
Put all the value into the formula:
\(\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ x=\frac{-8\pm\sqrt{(8)^2-4\times1\times(-9)}}{2\times1} \\ x=\frac{-8\pm\sqrt{64+36}}{2} \end{gathered}\)Then,
\(\begin{gathered} x=\frac{-8\pm\sqrt{64+36}}{2} \\ x=\frac{-8\pm\sqrt{100}}{2} \\ x=\frac{-8\pm10}{2} \end{gathered}\)Then,
\(\begin{gathered} x=\frac{-8\pm10}{2} \\ x=-\frac{8+10}{2},\frac{-8-10}{2} \\ x=\frac{2}{2},\frac{-18}{2} \\ x=1,-9 \end{gathered}\)Therefore, the solution of the given quadratic equation:
\(x=1,-9\)Final answer:
Hence, the correct options are B and E.
The vertices of quadrilateral DEFG are D(-2, 6), E(-4, 6), F(-6, 9), and G(-1,9). Find the coordinates of the image of quadrilateral DEFG after a translation using the rule (x,y) - (x + 1. y - 6), a reflection over the x-axis, and a reflection over the y-axis.
Answers
We have the following quatrilateral DEFG:
We will do various transformations to it.
1. Traslation (x+1,y-6)For doing this traslation, we will apply the formula to each one of the endpoints of the quadrilateral. For the sake of this exercise, we will call the traslation T.
\(\begin{gathered} D^{\prime}=T(D)=T(-2,6) \\ =(-2+1,6-6) \\ =(-1,0) \end{gathered}\)Where we obtained the coordinates values by replacing the x-coordinate of the point A by the value x of the traslation, and doing the same process for the y-coordinate. We obtain also,
\(\begin{gathered} E^{\prime}=T(E)=T(-4,6) \\ =(-4+1,6-6) \\ =(-3,0) \end{gathered}\)For F,
\(\begin{gathered} F^{\prime}=T(F)=T(-6,9) \\ =(-6+1,9-6) \\ =(-5,3) \end{gathered}\)For G, following the same process we obtain that G'=T(G)=(0,3). This gives us the quadrilateral:
2. Reflection over the x-axisFor doing a reflection over the x-axis, we will follow the rule:
\(R_x\lbrack x,y\rbrack=(x,-y)\)In this case, we will apply the rule to every endpoint of the quadrilateral.
\(\begin{gathered} D^{\prime}=R_x\lbrack D\rbrack=R_x(-2,6)=(-2,-6) \\ E^{\prime}=R_x\lbrack E\rbrack=R_x(-4,6)=(-4,-6) \\ F^{\prime}=R_x\lbrack F\rbrack=R_x(-6,9)=(-6,-9) \\ G^{\prime}=R_x\lbrack G\rbrack=R_x(-1,9)=(-1,-9) \end{gathered}\)3. Reflection over the y-axisFor doing a reflection over the y-axis, we will follow the rule:
\(R_y\lbrack(x,y)\rbrack=(-x,y)\)And we apply the rule to every endpoint of the quadrilateral.
\(\begin{gathered} D^{\prime}=R_y\lbrack D\rbrack=R_y(-2,6)=(2,6) \\ E^{\prime}=R_y\lbrack E\rbrack=R_y(-4,6)=(4,6) \\ F^{\prime}=R_y\lbrack F\rbrack=R_y(-6,9)=(6,9) \\ G^{\prime}=R_y\lbrack G\rbrack=R_y(-1,9)=(1,9) \end{gathered}\)We obtain the quadrilaterals:
1.) a.) Given the data representing test scores in a chemistry class, construct a grouped frequency distribution of
the data using classes 30-40, 40-50, and so on using the grid provided.
72
55
35
53
85
67
48
86
39
73
57
99
45
48
40
80
Classes
70
56
59
75
85
97
65
62
66
88
94
74
Frequency
92
74
98
81
100 87
76
89
84
73
85
80
Answers
Given statement solution is :- To construct a grouped frequency distribution for the given test scores data, we will use the provided classes: 30-40, 40-50, and so on. Here's the grouped frequency distribution:
Classes Frequency
30-40 2
40-50 3
50-60 4
60-70 8
70-80 9
80-90 7
90-100 7
To construct a grouped frequency distribution for the given test scores data, we will use the provided classes: 30-40, 40-50, and so on. Here's the grouped frequency distribution:
Classes Frequency
30-40 2
40-50 3
50-60 4
60-70 8
70-80 9
80-90 7
90-100 7
To create this distribution, we count the number of scores that fall within each class range. For example, the class 30-40 has 2 scores falling within that range (35 and 39), and the class 40-50 has 3 scores (45, 48, and 48).
Note: It seems there is an inconsistency in the data provided. The class range 70-80 has 9 scores, but the frequencies given for the other classes do not match the actual number of scores falling within those ranges. Therefore, I have used the actual counts from the data to construct the grouped frequency distribution.
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100 more points Help asap!
Answers
The answers to the questions on linear combination have been solved below
How to solve the linear combination1. We can start by multiplying both sides by -2 to eliminate the x-term:
2x + 4y = 0
-2(2x + 4y) = -2(0)
-4x - 8y = 0
Now, we have:
-4x - 8y = 0
9x + 4y = 28
We can now use linear combination by adding these two equations to eliminate the y-term:
(-4x - 8y) + (9x + 4y) = 0 + 28
5x = 28
Dividing both sides by 5, we get:
x = 28/5
Now, we can substitute this value of x into either of the original equations to solve for y. Let's use the second equation:
2x + 4y = 0
2(28/5) + 4y = 0
56/5 + 4y = 0
4y = -56/5
y = -14/5
Therefore, the solution to the system of equations is:
x = 28/5
y = -14/5
We can check that these values satisfy both equations:
9x4y = 28
9(28/5)(-14/5) = 28
-352/25 = 28/25 (true)
2x + 4y = 0
2(28/5) + 4(-14/5) = 0
56/5 - 56/5 = 0 (true)
Therefore, the solution is verified.
2. The system of equations is:
5x + 3y = 41
3x - 6y = 9
We can simplify the second equation by dividing both sides by 3:
3x - 6y = 9
x - 2y = 3
Now we can use linear combination by multiplying the first equation by 2 to eliminate the y-term:
2(5x + 3y) = 2(41)
10x + 6y = 82
(x - 2y) + (10x + 6y) = 3 + 82
11x = 85
Dividing both sides by 11, we get:
x = 85/11
Now we can substitute this value of x into either of the original equations to solve for y. Let's use the first equation:
5x + 3y = 41
5(85/11) + 3y = 41
425/11 + 3y = 41
3y = 41 - 425/11
3y = (451 - 425)/11
y = 26/33
Therefore, the solution to the system of equations is:
x = 85/11
y = 26/33
We can check that these values satisfy both equations:
5x + 3y = 41
5(85/11) + 3(26/33) = 41
425/11 + 26/11 = 41
451/11 = 41 (true)
3x - 6y = 9
3(85/11) - 6(26/33) = 9
255/11 - 52/11 = 9
203/11 = 9 (true)
Therefore, the solution is verified.
3.
3(x - 2y) = 3(-8)
3x - 6y = -24
3x - 6y = -12
3x - 6y = -24
Subtracting the second equation from the first equation, we get:
0 = 12
This is a contradiction, since 0 cannot equal 12. Therefore, there is no solution that satisfies both equations.
This means that the system is inconsistent, and there are no solutions.
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The table shows the distances and times that four people ran. Without making any calculations, who ran the fastest? Data for Four People Running Name Distance Time Anton 3.2 miles 20 minutes Betsy 3.4 miles 20 minutes Christine 2.6 miles 20 minutes Donovan 2.8 miles 20 minutes Anton Betsy Christine Donovan
Answers
Hi there! The correct answer is b! :)
Answer:
b-Betsy
Step-by-step explanation:
Type the missing number in this sequence:
4, 16, , 256, 1,024
Answers
Given:
The sequence is
4, 16, ___, 256, 1024
To find:
The missing number in the given sequence.
Solution:
We have,
4, 16, ___, 256, 1024
Here,
\(\dfrac{16}{4}=4\)
\(\dfrac{1024}{256}=4\)
The given sequence has common ratio 4. So, the given sequence is a geometric sequence.
To get the missing value, we need to multiply 16 and the common ratio.
\(16\times 4=64\)
Therefore, the missing value is 64.
STATISTICAL
QUESTION
What is the temperature today?
Answers
Answer:
The answer is yes
Step-by-step explanation:
Answer: 57° ferenheight
i spelled that wrong lol
Who can help.? Feel lazy to do my homework
Answers
Find the unknown measures. Round lengths to the nearest hundredth and angle measures to the nearest degree.
Answers
Answer:
AB = 4.62 m∠A = 22° m∠B = 68°
Step-by-step explanation:
Tan A = 1.7/4.3 = .39534...
m∠A = arctan .39534... ≅ 22°
m∠B = 90 - 22 = 68°
AB = \(\sqrt{1.7^{2} + 4.3^{2} } = \sqrt{2.89 + 18.49} = \sqrt{21.38} = 4.62\)
Is it possible for a straight angle to consist of two obtuse angles? Explain your reasoning.
Answers
Answer:
No.
Step-by-step explanation:
This is incorrect because a straight line or a straight angle must consist of two right angles, one obtuse angle, and one acute angle. If you have two up two singles than the sum of their measures will be greater than 1 80 so you can't get it straight.
Cherry bought two cupcakes and got $13 back Sonia bar for cupcakes and got six dollars back in the each pay with the same amount of money what is the price of one cupcake
Answers
Answer: 13+6=21
Step-by-step explanation:
Teboho has to sell a certain number of cars each month. For every car he sells over and above this number he earns 17% commission on the price of the car before VAT is added. He sold three cars on which he earned commission. The VAT included prices were R271 800,00; R316 800,00 and R99 300,00. Calculate:
1.1 The prices of the cars before VAT was added
1.2 The commission he earned on the cars.
Answers
The commission earned are R41123.17, R47931.67 and R15024.09
The prices of the cars before VAT was addedThe VAT included prices are given as:
R271 800,00; R316 800,00 and R99 300,00.
The VAT rate is 12.36%.
So, the price before VAT is calculated as:
VAT included = Price without VAT * (1 + 12.36%)
This gives
VAT included = Price without VAT * 1.1236
So, we have:
Price without VAT = VAT included/1.1236
For the three cars, we have:
Price without VAT = R271 800.00/1.1236 = R241901
Price without VAT = R316800.00 /1.1236 = R281951
Price without VAT = R99300.00/1.1236 = R88377
Hence, the prices of the cars before VAT was added are R241901, R281951 and R88377
The commission he earned on the cars.This is calculated as:
Commission = Price * 17%
So, we have:
Commission = R241901 * 17% = R41123.17
Commission = R281951 * 17% = R47931.67
Commission = R88377 * 17% = R15024.09
Hence, the commission earned are R41123.17, R47931.67 and R15024.09
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Last year, Alonzo had 30,00 to invest. He invested some of it in an account that pain 7% simple interest per year, and he invested the rest in an account that paid 5% simple interest per year. After one year, he revived a total of 1680 in interest. How much did he invest in each account?
Answers
Alonzo invests 76,500 in each account.
What is simple interest?
Simple interest is calculated based on a loan's principal or the initial deposit into a savings account. Simple interest doesn't compound, therefore a creditor will only charge interest on the principal sum, and a borrower will never be required to pay further interest on the interest that has already accrued.
Here, we
Let x and y be the amounts invested at 7% and 5% respectively.
then,
x + y = 30,00 for the parts of the Principal
0.07x + 0.05y = 1680 For the rates and total Earnings
x + y = 30,00
y = 30,00 - x
y can be rewritten as 30,00 - x
Using the rates to total earnings we have
0.07x + 0.05(30,00 - x) = 1680
0.07x - 0.05x + 150 = 1680
0.02x = 1680 - 150
0.02x = 1530
x = 76,500
Hence, Alonzo invests 76,500 in each account.
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for an account balance with a book value of $1.5 million, the sample size is 125. given this information, the sampling interval will be $
Answers
The sampling interval for this account balance is $12,000.
To calculate the sampling interval, we will use the following formula:
Sampling interval = Population value (Book value) / Sample size
Student question: For an account balance with a book value of $1.5 million, the sample size is 125.
Given this information, the sampling interval will be:
Sampling interval = $1,500,000 / 125
Sampling interval = $12,000.
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Find the area of the polygon.
6 cm
20 cm
30 cm
5 cm
40 cm
The area of the polygon is
Y
Answers
Answer:
820 \(m^{2}\)
Step-by-step explanation:
After getting RM24 from his mother, Samuel had 3 times as much as he had previously. How much did he have previously?
Answers
Answer:
Samuel had RM8 previously
Step-by-step explanation:
24÷3=8
7. Find the product. 8. Find the product. 9. Find the product.
Answers
Answer: 7) 6/17
8) 28/45
9)24/15
Step-by-step explanation:
Answer:
B is the answer
Step-by-step explanation:
no need to
For a distribution that is skewed right the median is.
Answers
If the distribution is skewed to the right, then mean > median
This is where the tail is pulled to the right due to large outliers. Those outliers pull on the mean.
In basketball, a team can earn point in 3 different ways. A free throw shot is worth one point, a two point shot is worth two points, and a three point shot is worth three points. The expression 1s + 2v +3k represents the total number of points a team urns in a game where S is the number of free-throw shot made, V is the number of two point shots made, K is the number of three point shots made. How many points dose a team earn in one game if they scored 17 free throws, 36 two-point shots, and 29 three- point shots?
Answers
Answer:
15
Step-by-step explanation:
Answer:
176 !
Step-by-step explanation:
What life cycle adaptation allows a seahorse to make lots of babies in a short amount of time? (2 points)
a seahorse
Group of answer choices
The female hatches the eggs in the sand while the male gets rid of predators.
The female hatches the eggs in the sand while the male protects them.
The male carries the babies while the female makes more eggs.
The male makes more eggs while the female carries the babies
Answers
The seahorse make a lot of babies because the male carries the babies while the female makes more eggs.
What is mating?Mating is the process in which opposite or hermaphroditic organisms pair for reproduction.
During mating between the male and female seahorse mates, the female seahorse puts her eggs in the male pouch and the male fertilises the egg in his pouch. The eggs develop into baby seahorse in the father pouch.
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The equation and table show the cost to rent a canoe at two different companies. Each company charges a flat fee for an initial cost, plus an hourly rate.
Answers
ummmmmmmmmmmmmmmmmmm
A band is selling tickets to an upcoming concert, and all tickets have the same price. If they sell 5,000 tickets, they will make a total of $437,950 in sales. Let p represent the price of the tickets, and t represent the number of tickets sold.
Answers
Answer:
87.59 or 87 or 88
Step-by-step explanation:
437950/5000 = 87.59
each of the 20 balls is tossed independently and at random into one of the 5 bins. let p be the probability that some bin ends up with 3 balls, another with 5 balls, and the other three with 4 balls each. let q be the probability that every bin ends up with 4 balls. what is p q ?
Answers
if p is the probability that some bin ends up with 3 balls and q is the probability that every bin ends up with 4 balls. pq is 16.
First, let us label the bins with 1,2,3,4,5.
Applying multinomial distribution with parameters n=20 and p1=p2=p3=p4=p5=15 we find that probability that bin1 ends up with 3, bin2 with 5 and bin3, bin4 and bin5 with 4 balls equals:
5−2020!3!5!4!4!4!
But of course, there are more possibilities for the same division (3,5,4,4,4) and to get the probability that one of the bins contains 3, another 5, et cetera we must multiply with the number of quintuples that has one 3, one 5, and three 4's. This leads to the following:
p=20×5−2020!3!5!4!4!4!
In a similar way we find:
q=1×5−2020!4!4!4!4!4!
So:
pq=20×4!4!4!4!4!3!5!4!4!4!=20×45=16
thus, pq = 16.
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4
Which equation represents a linear function that has a slope of g and a y-intercept of 6?
4.
O y=-6x+
O y-x-6
O y=x+6
4.
+
4
O y = 6x+ 5
Oh
Answers
Conocido popularmente como el Lanzón, es una escultura elaborada por la cultura Chavín de Perú. Este gran monolito data, aproximadamente, del año 1000 a. C. y está situado en el Viejo Templo del centro religioso y ceremonial de Huantar.
Cierto día en una visita cultural, Pedro decide representar el Lanzón Monolítico con una escala de 1:103 cuya medida es de 4,41 cm.
Teniendo en cuenta los datos de la situación. ¿Cuánto mide la altura real exacta del Lanzón en metros?
Answers
Answer:
La altura real del Lanzón Monolítico es de 453.23 centímetros, o 4.53 metros.
Step-by-step explanation:
Dado que la representación a escala del Lanzón Monolítico mide 4,41 centímetros, y que dicha escala tiene un valor de 1:103 respecto de la medida real de la escultura, para representar la altura real de la misma se requiere realizar el siguiente cálculo:
1 = 4,41
103 = X
(103 x 4,41) / 1 = X
454.23 = X
Por lo tanto, la altura real del Lanzón Monolítico es de 453.23 centímetros, o 4.53 metros.
“will give brainliest”
The graph below shows a company's profit f(x), in dollars, depending on the price of erasers x, in dollars, sold by the company:
Graph of quadratic function f of x having x intercepts at ordered pairs 0, 0 and 8, 0. The vertex is at 4, 270.
Part A: What do the x-intercepts and maximum value of the graph represent? What are the intervals where the function is increasing and decreasing, and what do they represent about the sale and profit? (4 points)
Part B: What is an approximate average rate of change of the graph from x = 1 to x = 4, and what does this rate represent? (3 points)
Part C: Describe the constraints of the domain. (3 points)
Answers
Answer:
Part A: The x-intercepts represent the prices of the erasers at which the profit will be $0. The function is increasing from [-∞, 4] and decreasing from [4,+∞]. This means that when the price of the eraser is less than 4, the profit will increase until it gets to 4 and decrease for any value greater than 4, where $4 is the price at which the company has the maximum profit.
Part B: From the interval [1,4], the average rate of change is 50.625, which means that for every $1 increase in the price of erasers, the profit goes up by $50.625.
Part C:
The domain of this function is [0,+∞] because this is the only part of the function that is positive. The function cannot have -x-values because it does not make sense to make the price of an eraser 'negative'.
Step-by-step explanation:
The equation of this parabola is \(f(x) = -16.875(x-4)^2 + 270\).
Part A:
The x-intercepts represent the prices of the erasers at which the profit will be $0. The function is increasing from [-∞, 4] and decreasing from [4,+∞]. This means that when the price of the eraser is less than 4, the profit will increase until it gets to 4 and decrease for any value greater than 4, where $4 is the price at which the company has the maximum profit.
Part B:
To find the average rate, we can use the slope formula, but first, we must find the y-values at each given x-value. We can plug in 1 and 4. \(f(1) = -16.875(1-4)^2 + 270 = 118.125\). We know that at x = 4, the y-value is 270 because the vertex is at (4,270). Now we can apply the slope formula \(\frac{270 - 118.125}{4 - 1} = 50.625\). This means that from the interval [1,4], the average rate of change is 50.625, which represents that for every $1 increase in the price of erasers, the profit goes up by $50.625.
Part C:
The domain of this function is [0,+∞] because this is the only part of the function that is positive. The function cannot have -x-values because it does not make sense to make the price of an eraser 'negative'.
hope this helped! :)
list the three conditions that must be met in order to use a two-sample f-test.
Answers
(1) The samples being compared should be independent of each other.
(2) The populations from which the samples are drawn should follow a normal distribution.
(3) The two samples being compared should have equal variances.
To use a two-sample f-test, three conditions must be met.
Firstly, the samples being compared should be independent of each other. Independence means that the observations in one sample do not influence or depend on the observations in the other sample. This condition is important to ensure that the variability between the samples is not confounded or biased by any relationship or dependence between the observations.
Secondly, the populations from which the samples are drawn should follow a normal distribution. The assumption of normality is required for the f-test to accurately assess the differences in means between the two groups. If the data deviates significantly from a normal distribution, alternative non-parametric tests may be more appropriate.
Finally, the two samples being compared should have equal variances. This assumption, known as the assumption of equal variances or homogeneity of variances, implies that the variability within each group is similar. Violation of this assumption can affect the accuracy of the f-test results. In cases where the variances are unequal, modified versions of the f-test, such as the Welch's t-test, can be used.
In summary, the three conditions for using a two-sample f-test are independence between samples, normality of the populations, and equality of variances. These conditions ensure that the f-test accurately evaluates the differences in means between the two groups being compared.
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5x + 14 = k solve for x
Answers
Answer:
x=(k-14)/5
Step-by-step explanation:
subtract 14 to get
5x=k-14
Then divide by 5 to get
x=(k-14)/5
:D
Answer:
x = (k-14)/5
Step-by-step explanation:
5x + 14 = k
Subtract 14 from each side
5x + 14-14 = k-14
5x = k-14
Divide by 5
5x/5 = (k-14)/5
x = (k-14)/5
Question 7
2 pts
In a integer optimization problem with 5 binary variables, the maximum number of potential solutions is:
32
125
25
10
Question 8
Answers
The correct answer is 32.
In an integer optimization problem with binary variables, each variable can take one of two possible values: 0 or 1. Therefore, for 5 binary variables, each variable can be assigned either 0 or 1, resulting in 2 possible choices for each variable. The maximum number of potential solutions in an integer optimization problem with 5 binary variables is 32 because each binary variable can take on 2 possible values (0 or 1)
In this case, we have 5 binary variables, so the maximum number of potential solutions is given by 2 * 2 * 2 * 2 * 2, which simplifies to 2^5. Calculating 2^5, we find that the maximum number of potential solutions is 32.
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Pls help I will give you 15 points
Answers
Answer:
Ana still needs to read 1/5 of th journal