7. (07.03) An equation is shown below: 4(2x - 5) + 15 = 11 Write the steps you will use to solve the equation and explain each step. (5 points)​

True. The consumer group could have made a type II error. A type II error occurs when the consumer group fails to reject the null hypothesis, which states that the average score increase is equal to 30 points, even though it is actually false.

In this case, if the study program does increase the average score by a different amount, the consumer group may fail to detect this difference and incorrectly conclude that the average score increase is 30 points. This error is possible because no statistical test is perfect, and there is always some level of uncertainty involved in hypothesis testing.

To minimize the risk of a type II error, the consumer group should use an appropriate sample size and consider conducting a power analysis before conducting the study.

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The number 1.5¯¯¯ belongs to the subset of Rational numbers.

Rational Numbers: A real number that can be written as a simple fraction, i.e, a ratio of two integers is known as a rational number.  For example, 1.5 can be said to be a rational number because it can be written as 3/2; 202 is a rational number because it can be written in fractions as 202/1, or 404/2.

Irrational Numbers: A real number that can’t be written as a simple fraction is known as an Irrational number. For example, pi= 3.14159 cannot be written as a simple fraction and that’s why it is an irrational number.

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Answer:

Step-by-step explanation:

Use triangle similarity and the ratio of corresponding sides to solve below.

#91

#92

#93

#94

Note. Posting as picture as unable to post as text

Answer:

amber should graph the second equation

The solution to the equation below rounded to 2 decimal places is 22.20.

Given the logarithmic expressions

ln x = 3.1

We are to determine the value of "x"

ln x = 3.1

Take the exponent of both sides

e^ln x = e^3.1

The exponent will cancel out the log function to have:

x = e^3.1

x = 22.197

Hence the solution to the equation below rounded to 2 decimal places is 22.20.

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It will take approximately 39.532 days for $9500 to earn $800 at an annual interest rate of 8.25%.

To find the number of days it will take for $9500 to earn $800 at an annual interest rate of 8.25%, we need to use the formula for simple interest:

Interest = Principal * Rate * Time

In this case, we are given the interest ($800), the principal ($9500), and the annual interest rate (8.25%). We need to solve for time.

Let's denote the time in years as "t". Since we're looking for the number of days, we'll convert the time to a fraction of a year by dividing by 365 (assuming a standard 365-day year).

$800 = $9500 * 0.0825 * (t / 365)

Simplifying the equation:

800 = 9500 * 0.0825 * (t / 365)

Divide both sides by (9500 * 0.0825):

800 / (9500 * 0.0825) = t / 365

Simplify the left side:

800 / (9500 * 0.0825) ≈ 0.1083

Now, solve for t by multiplying both sides by 365:

0.1083 * 365 ≈ t

t ≈ 39.532

Therefore, it will take approximately 39.532 days for $9500 to earn $800 at an annual interest rate of 8.25%.

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Answer:

\557

Step-by-step explanation:

Answer:\(m\leq 2\)

Step-by-step explanation:

6≥5m−4

Swap sides so that all variable terms are on the left-hand side. This changes the sign direction.

5m−4≤6

Add 4 to both sides

5m≤6+4

add 6+4 to get 10

5m≤10

next Divide both sides by 5. Since 5 is positive, the inequality direction remains the same.

m ≤ 10/5

now Divide 10 by 5 to get 2.

and your answer is m ≤ 2 Hopes this helps :)

Answer:

23.3%

Step-by-step explanation:

Formula: I=PRT (Interest=Principal*Rate*Time)

I=23400-4500=18900

18900=4500*R*18

18900=81000R

R=18900/81000=0.233... Rounds to 23.3%

The standard deviation of the returns on a portfolio that is invested 37 percent is 1.66 percent

This is further explained below.

Generally,

E. 3.41 percent

E(r)Boom = (0.37 *0.14) + (.0.48* 0.16) = 0.1286

E(r)Normal = (0.37 *0.08) + (0.48 0.11) = 0.0824

E(r)Portfolio = (0.10 *  0.1286) + (0.90 *0.0824) = 0.08702

VarPortfolio = [0.10 (0.1286 - 0.08702)2] + [0.90 (0.0824 - 0.08702)2] = 0.000

Std dev = 0.000274 = 1.66 percent

In conclusion,

Std dev = 0.000274 = 1.66 percent

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CQ

What is the standard deviation of the returns on a portfolio that is invested 37 percent in stock Q and 48 percent in stock R?

state probability return

Q R

boom 10% 14% 16%

normal 90% 8% 11%

Answer:

9

Step-by-step explanation: 3x4= 12  -3=9

Answer:

what's nelly's age

Step-by-step explanation:

4x divided by 3?

The Solution of the given expression is -3/2

In mathematics, a fraction is represented by a number that identifies a portion of a whole. A fraction is a component or segment taken from a whole, which can be any number, a certain amount, or an object.  

In fractions, the upper portion is called Numerator and the lower portion is called the Denominator.      

Here given that

fraction numerator x minus 1 over denominator 2 end fraction equals fraction numerator x minus 4 over denominator 5 end fraction

The above fraction can be written Mathematically as given below

=> \([\frac{x-1}{2}] = [\frac{x-4}{5} ]\)

The given expression can be solved as given below

=> \([\frac{x-1}{2}] = [\frac{x-4}{5} ]\)  

=>  \(5(x-1) = 2(x-4)\)

=>  \(5x- 5 = 2x - 8\)

=>  \(5x- 3x = - 8 + 5\)  

=>  \(2x = - 3\)

=>  \(x = -\frac{3}{2}\)  

Therefore,

The Solution of the given expression is -3/2

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The limit doesn't exist.

The value that a function (or sequence) approaches when the input (or index) gets closer to a particular value is known as a limit. Calculus and mathematical analysis are impossible without limits, which are also required to determine continuity, derivatives, and integrals.

In addition to being closely related to limit and direct limit in category theory, the idea of a limit of a sequence is further generalized to include the concept of a limit of a topological net.

A function's limit is typically expressed in formulas as

\(\lim_{x \to c } F(x) = L\)

It is typically used to assign values to specific functions at locations where none are defined while maintaining consistency with existing values.

\(F(x) = -x+8 ,x\leq 0\)

\(F(x) = 4x+9 , if x > 0\)

\(\lim_{x \to 0^{+} } F(x) = \lim_{n \to 0^{+} } (4x+9) = 9\)

\(\lim_{x \to 0^{-} } F(x) = \lim_{x \to 0^{-} } (-x+8) =8\)

\(\lim_{x \to 0^{+} } F(x) \neq \lim_{x \to 0^{-} } F(x)\)

So limit doesn't exist

For limit to exist

\(\lim_{x \to 0^{+} } F(x) = \lim_{x \to 0^{-} } F(x) = \lim_{x \to 0} f(x)\)

must be satisfied

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The equation of g(x) is 24 (3)ˣ when the graph is stretched vertically by a factor of 3 to form the graph g(x).

What is function?

For the parent function f(x) and a constant k >0,

then, the function given by  

g(x) = kf(x) can be sketched by vertically stretching f(x) by a factor of k if k>1 (or)

if 0 < k < 1 , then it is vertically shrinking f(x) by a factor of k

As per the given statement that the graph of f(x) is stretched vertically by a factor of 3 i.e

k = 3 >1

so, by definition

g(x) = 3 f(x) = 3 . 8(3)ˣ

= 8(3)ˣ⁺¹

= 24 (3)ˣ

Hence, the equation of g(x) is 24 (3)ˣ when the graph is stretched vertically by a factor of 3 to form the graph g(x).

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Let \(n=0\). Then \(0^3 = 0\) but 0 > 0 is a false statement.

The negation of the given statement is ¬(r ∨ w) which is ¬r ∧ ¬w.

Given statement: Mei will run or walk to the gym tomorrow. Propositional logic:

Step 1: r: Mei will run to the gym tomorrow. w: Mei will walk to the gym tomorrow.

Step 2: The given statement can be rewritten in the form: r ∨ w.

Step 3: The negation of the given statement is ¬(r ∨ w). Using De Morgan's Laws, we can write the negation as ¬r ∧ ¬w.

Main Part: ¬(r ∨ w)

Explanation: We know that the negation of a disjunction is the conjunction of the negations of the disjuncts. So, the negation of the given statement r ∨ w is ¬r ∧ ¬w. The negation of the given statement "Mei will run or walk to the gym tomorrow" is "Mei will not run and will not walk to the gym tomorrow."

Conclusion: Therefore, the negation of the given statement is ¬(r ∨ w) which is ¬r ∧ ¬w.

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Answer:

13+26=39

Step-by-step explanation:

the 7th odd number is 13 and 13th even is 26

Answer:

\(\displaystyle 39\)

Step-by-step explanation:

\(\displaystyle 39 = 13 + 26 \Rightarrow 39 = 13 + 2[13]\)

On a hundred chart, you will see that the seventh odd number is \(\displaystyle 13,\)and the thirteenth even number is self-explanatory, so you should know what occurs there.

I am joyous to assist you at any time.

Answer:

252 in

Step-by-step explanation:

For this one we are going to split this big confusing shape into 3 simple shapes.

1.

We are going to use the formula for the area of a rectalngle a=lxw and just plug the numbers in.

On this one the width is 12 and the length is 15, so:

12x15=180

180 is the area of the first shape

2.

For this one the width is 6 and the length is 3, so:

6x3=18

18 is the area of the second shape

3.

The last ones width is 9 and the length is 6, so:

9x6=54

54 is the area of the third shape

Total.

Then just add all the area of all the shapes together for the total area of the shape.

180+18+54=252

The total area of this shape is 252

Answer:

scale factor = 2

Step-by-step explanation:

Determine the ratio of corresponding sides, image to original

scale factor = \(\frac{5}{2.5}\) = 2

Answer:

2

Step-by-step explanation:

If one angle in Polygon A is 2.5

and one angle in polygon b is 5

5/2.5= 2

the answer is 2

Answer:

0.025

Step-by-step explanation:

Thats the answer

its divided exmple: 5÷200= the total is 0.025

Answer:

42

Step-by-step explanation:

18/3 = 6

6*7 =42

As the number of workers increases, the number of days it will take to complete the project decreases. option A.

The product of the two variables is constant. option B

The number of days it takes for a construction project to be completed varies inversely as the number of workers assigned to the project. option B.

Relationship 1

Workers : No. of days = 2 : 42

= 1 : 21

Relationship 2:

Workers : No. of days = 3 : 28

= 1 : 9⅓

Relationship 3:

Workers : No. of days = 6 : 14

= 1 : 2 ⅓

2 × 42 = 84

3 × 28 = 84

6 × 14 = 84

12 × 7 = 84

Hence, the relationship between the two variables are inversely proportional because as one variable increases, another decreases.

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a) U is subspace of R^3.

b) The set {(3, -2, 0), (0, 1/2, 1)} is a basis for U.

c) 2.

a) To show that U is a subspace of R^3, we need to verify the following three conditions:

i) The zero vector (0, 0, 0) is in U.

ii) U is closed under addition.

iii) U is closed under scalar multiplication.

i) The zero vector is in U since 0 + 2(0) - 3(0) = 0.

ii) Let (x1, y1, z1) and (x2, y2, z2) be two vectors in U. Then we have:

x1 + 2y1 - 3z1 = 0 (by definition of U)

x2 + 2y2 - 3z2 = 0 (by definition of U)

Adding these two equations, we get:

(x1 + x2) + 2(y1 + y2) - 3(z1 + z2) = 0

which shows that the sum (x1 + x2, y1 + y2, z1 + z2) is also in U. Therefore, U is closed under addition.

iii) Let (x, y, z) be a vector in U, and let c be a scalar. Then we have:

x + 2y - 3z = 0 (by definition of U)

Multiplying both sides of this equation by c, we get:

cx + 2cy - 3cz = 0

which shows that the vector (cx, cy, cz) is also in U. Therefore, U is closed under scalar multiplication.

Since U satisfies all three conditions, it is a subspace of R^3.

b) To find a basis for U, we can start by setting z = t (where t is an arbitrary parameter), and then solving for x and y in terms of t. From the equation x + 2y - 3z = 0, we have:

x = 3z - 2y

y = (x - 3z)/2

Substituting z = t into these equations, we get:

x = 3t - 2y

y = (x - 3t)/2

Now, we can express any vector in U as a linear combination of two vectors of the form (3, -2, 0) and (0, 1/2, 1), since:

(x, y, z) = x(3, -2, 0) + y(0, 1/2, 1) = (3x, -2x + (1/2)y, y + z)

Therefore, the set {(3, -2, 0), (0, 1/2, 1)} is a basis for U.

c) Since the basis for U has two elements, the dimension of U is 2.

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Answer:

OPTION C

Step-by-step explanation:

\( \frac{1}{2} (x - \frac{3}{4} ) = \frac{5}{12} \)

\((x - \frac{3}{4} ) = \frac{5}{6} \)

\(x = \frac{3}{4} + \frac{5}{6} \)

\(x = \frac{9 + 10}{12} \)

\(x = \frac{19}{12}

\frac{3}{4} y - \frac{3}{2} = \frac{5}{2} \)

\( \frac{3}{4} y = 4\)

\(y = \frac{16}{3} \)

(a) In a ring, the set of units consists of elements that have multiplicative inverses. A multiplicative inverse of an element a in a ring is another element b such that a * b = b * a = 1, where 1 is the multiplicative identity in the ring. To prove that the set of units forms a multiplicative group, we need to show three properties: closure, associativity, and existence of an identity element.

Closure: Let a and b be units in the ring. Then, there exist inverses b' and a', respectively, such that a * a' = a' * a = 1 and b * b' = b' * b = 1. Now, consider the product (a * b) * (b' * a'). Using associativity and the fact that 1 is the identity element, we have (a * b) * (b' * a') = a * (b * b') * a' = a * 1 * a' = a * a' = 1. Thus, the product of units is also a unit, demonstrating closure.

Associativity: The multiplication operation in a ring is associative by definition. Therefore, the multiplication of units in a ring is also associative.

Identity Element: The multiplicative identity element, denoted by 1, exists in the ring and is a unit. This element satisfies the property that for any unit a, a * 1 = 1 * a = a.

Hence, the set of units in a ring satisfies the three properties required to form a multiplicative group.

(b) The ring Z/18Z consists of residue classes modulo 18. The units in this ring are the residue classes that have multiplicative inverses. To find the group of units, we need to identify the residue classes that have inverses modulo 18. In other words, we are looking for residue classes a in the range 0 ≤ a < 18 such that gcd(a, 18) = 1.

By calculating the greatest common divisor (gcd) between each residue class and 18, we find that the residue classes 1, 5, 7, 11, 13, and 17 have a gcd of 1 with 18. Therefore, these are the units in the ring Z/18Z.

The group of units in Z/18Z is {1, 5, 7, 11, 13, 17}.

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The prices which the school would collect $0 revenue are $0 and $ 40 respectively.

Since the revenue R(p) = p(200 - 5p).

The price at which the school earn s $0 revenue from the raffle sales is when R(p) = 0.

So, p(200 - 5p) = 0

p = 0 or 200 - 5p = 0

p = 0 or 200 = 5p

p = 0 or p = 200/5 = 4

So, the prices which the school would collect $0 revenue are $0 and $ 40 respectively.

The two ticket prices that would produce a revenue of $500 are $2.68 and $ 37.32

We need to find the two ticket prices that would result in a revenue of $500. So, R(p) = 500.

So, p(200 - 5p) = 500

200p - 5p² = 500

Re-arranging, we have

5p² - 200p + 500 = 0

Dividing through by 5, we have

p² - 40p + 100 = 0

Using the quadratic formula, we find the value of p.

So,

\(p = \frac{-(-40) +/- \sqrt{(-40)^{2} - 4 X 1 X 100} }{2 X 1} \\p = \frac{40 +/- \sqrt{1600 - 400} }{2} \\p = \frac{40)+/- \sqrt{1200} }{2} \\p = \frac{40 +/- 34.64 }{2} \\p = \frac{40 - 34.64 }{2} or p = \frac{40 + 34.64 }{2} \\p = \frac{5.36}{2} or p = \frac{74.64 }{2} \\p = 2.68 or 37.32\)

So, the two ticket prices that would produce a revenue of $500 are $2.68 and $ 37.32

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The value of x³ 3y²x² is 27y² when x is 3. This is because x³ is equal to 27, and multiplying it by 3y² and x² gives 27y².

The value of x³ 3y²x² when x is 3 can be calculated by first understanding how x³ is equal to 27. This is because when something is cubed, the value is three times itself. For example, if x is 2, then x³ is 2 x 2 x 2, which is 8. If x is 3, then x³ is 3 x 3 x 3, which is 27. Once this is understood, the value of x³ 3y²x² when x is 3 can be calculated by multiplying 27 (the value of x³ when x is 3) by 3y² and x². In this case, x² is also equal to 3, so the equation becomes 27 x 3y² x 3, which is equal to 27y². This means that the value of x³ 3y²x² when x is 3 is 27y².

x³ = 3 x 3 x 3 = 27

x³ 3y²x² = 27 x 3y² x 3 = 27y²

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