7. A scale which reads 0 in the vacuum of space is placed on the surface of planet Physica. On the
planet's surface, the scale indicates a force of 10,000 Newtons. Calculate the surface area of the scale,
given that atmospheric pressure on the surface of Physica is 80,000 Pascals.
Known Variables:
Equation:
Solution:
P =
F=
A =

Answer:

B. energy

Explanation:

A vector has direction.

Energy does not have a direction.

Answer:

f

Explanation:

a. The potential energy and its kinetic energy at the instant it is dropped will be 1126.25 J and 0 J respectively.

b. The potential energy and its kinetic energy at the time it is 15m high will be 735.75 J and 390.25 J respectively.

c. The velocity when it is 15m high will be 156.1 m/sec.

d. The height when velocity is 12 m/s will be 15.62 m

e. The potential energy and its kinetic energy at the time it strikes the ground will be 0 J and 1126.25 J respectively

f. The velocity with which it hits the ground will be 21.22 m/sec.

The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.

According to the law of conservation of energy, the total energy is defined as the sum of kinetic energy and potential energy.

Total energy = kinetic energy+potential energy

Also, the energy can not be created nor be destroyed can be transferred from one form to another form.

Kinetic energy is due to the position.While the kinetic energy is due to the velocity.

a)The potential energy and its kinetic energy at the instant it is dropped.

\(\rm PE_{drop}=mgh \\\\\ PE_{drop}=5 \times 9.81 \times 25 \\\\ PE_{drop}=1126.25 \ J\)

\(\rm KE_{drop}=\frac{1}{2} mv^2 \\\\ v= 0 \\\\ KE_{drop}=0 \ J\)

TE= 1126.25+0

TE= 1126.25+0

b. Potential energy and its kinetic energy at the time it is 15m high.

\(\rm PE_{15}=mgh \\\\ \rm PE_{15}= 5 \times 9.81 \times 15 \\\\ PE_{15}=735.75 \ J\)

TE=KE+PE

1126.25=KE+735.75

KE=390.25

c) Velocity when it is 15m high

\(\rm KE=390.25\\\\ 390.25=\frac{1}{2} \times 5 \times v_{15}^2 \\\\ v_{15}=156.1\ m/sec\)

d. Height when velocity is 12 m/s.

\(\rm KE = \frac{1}{2}mv^2 \\\\\ KE =\frac{1}{2} \times 5 \times (12)^2 \\\\ KE=360\ J\)

TE=KE+PE

1126.25=360+PE

PE=766.25

PE=766.25

mgh=766.25

5 ×9.81 ×h=766.25

h=15.62 m

E. Potential energy and its Kinetic energy at the time it strikes the ground.

\(\rm PE_{ground}=0 \ J\)

TE=KE+PE

TE=KE+0

TE=KE

TE= 1126.25

KE=1126.25 J

f. Velocity with which it hits the ground.

\(\rm KE_{ground}=1126.25 J \\\\ \frac{1}{2} mv^2=1126.25\\\\ v^2 = 450 \\\\ v= 21.22 \ m/sec\)

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Answer:

Part A:

Distance=864000 m=864 km

Part B:

Energy Used=ΔE=8638000 Joules

Part C:

\(\frac{\triangle m}{m}=0.004998=0.49985\%\)

Explanation:

Given Data:

v=20m/s

Time =t=12 hours

In Secs:

Time=12*60*60=43200 secs

Solution:

Part A:

Distance = Speed**Time

Distance=v*t

Distance= 20*43200

Distance=864000 m=864 km

Part B:

Energy Used=ΔE= Energy Required-Kinetic Energy of swans

Energy Required to move= Power Required*time

Energy Required to move=200*43200=8640000 Joules

Kinetic Energy=\(\frac{1}{2}mv^2\)

\(K.E\ of\ Swans=\frac{1}{2} *10*(20)^2=2000\ Joules\)

Energy Used=ΔE=8640000 -2000

Energy Used=ΔE=8638000 Joules

Part C:

Fraction of Mass used=Δm/m

For This first calculate fraction of energy used:

Fraction of energy=ΔE/Energy required to move

ΔE is calculated in part B

Fraction of energy=8638000/8640000

Fraction of energy=0.99977

Kinetic Energy=\(\frac{1}{2}mv^2\)

Now, the relation between energies ratio and masses is:

\(\frac{\triangle E}{E}=\frac{\triangle m}{2m}v^2\)

\(\frac{\triangle m}{m}=\frac{2}{v^2} *\frac{\triangle E}{E}\\\frac{\triangle m}{m}=\frac{2}{20^2} *0.99977\)

\(\frac{\triangle m}{m}=0.004998=0.49985\%\)

The work done by the gaseous system if the volume is increased to 0.12 cubic meters is given as 21,600 joules

To find the work done by the gas, we can use the formula:

W = PΔV

where W is the work done, P is the pressure of the gas, and ΔV is the change in volume.

At the initial state, the pressure is P = 2.7 × 10^5 Pa and the volume is V1 = 0.04 m^3. At the final state, the volume is V2 = 0.12 m^3.

The change in volume is ΔV = V2 - V1 = 0.12 m^3 - 0.04 m^3 = 0.08 m^3.

Substituting these values into the formula, we get:

W = PΔV = (2.7 × 10^5 Pa) × (0.08 m^3) = 21,600 J

Therefore, the work done by the gaseous system is 21,600 joules (J).

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Answer:

4.6x10^4 joules

Explanation:

Answer:

triangle if q1 = 4.1 μC , q2 = 3.4 μC , q3 = -3.5 μC ?

Answer:

R_total = 14.57 Ω ,  V_C = 1.176 V

Explanation:

To solve this circuit we are going to find the equivalent resistance of each branch, let's remember

* Serial resistance  

         \(R_{eq}\) = ∑ \(R_{i}\)

* For resistance in parallel

        1 / R_{eq} = ∑ 1/R_{i}

We solve the two branches of the wheatstone bridge

Series resistors

Branch B

         R_B = Rb + R4

         R_B = 2 + 18

         R_B = 20 Ω

Branch C

         R_C5 = Rc + R5

         R_C5 = 3 + 12

         R_C5 = 15 Ω

Resistance in parallel R_B and R_C5

         1 / R_BC = 1 / R_B + 1 / R_C5

          1 / R_BC = 1/20 + 1/15 = 0.116666

          R_BC = 8.57 Ω

Now we have a single branch, we solve the series resistance

          R_total = R_A + R_BC

          R_total = 6 + 8.57

          R_total = 14.57 Ω

b) they ask us for the voltage in the resistance R_C

Let's remember that the voltage in a series circuit is the sum of the voltages

           10 = V_a + V_BC

           10 = i R_a + i R_BC = i (R_a + R_BC)

           i = 10 / (R_a + R_BC)

           i = 10 / (14.57)

           i = 0.6863 A

The current in the series circuit is constant

          V_BC = i R_BC

          V_BC = 0.6863 8.57

          V_BC = 5.8819 V

This voltage is divided in the bridge, for the two branches in parallel it is the same, but the resistance is different in each branch.

     Branch C

             V_BC = i R_C5

             i = V_BC / R_C5

             i = 5.8819 / 15

             i = 0.39213 A

In this branch we have two resistors in series, let's remember that the current in a series circuit is constant

             V_C = i R_C

              V_C = 0.39213 3

              V_C = 1.176 V

Answer:

F₁ = 4 F₀

Explanation:

The force applied on the string by the ball attached to it, while in circular motion will be equal to the centripetal force. Therefore, at time t₀, the force on ball F₀ is given as:

F₀ = mv₀²/r   --------------- equation (1)

where,

F₀ = Force on string at t₀

m = mass of ball

v₀ = speed of ball at t₀

r = radius of circular path

Now, at time t₁:

v₁ = 2v₀

F₁ = mv₁²/r

F₁ = m(2v₀)²/r

F₁ = 4 mv₀²/r

using equation (1):

F₁ = 4 F₀

Answer:

1. High Illiteracy Rate in a Nation has a Negative Impact on the Conducting of Census

2.Corruption Interferes with Census

3.Traditional and Religious Beliefs can Interfere with the Census Exercise

4.insufficient and Ineffective Census Educational Campaign

5.Insufficient Census Experts

Explanation:

The radius of the sphere decreases by 11 mm when the pressure on its surface is increased by 200 MPa.

To determine the decrease in radius of the spherical volume of water when the pressure on its surface is increased, we can use the equation relating pressure to the radius of a sphere:

ΔP = K/R

Where ΔP is the change in pressure, K is a constant, and R is the radius of the sphere.

In this case, we're given that ΔP (change in pressure) is 200 MPa and the initial radius R is 20.0 cm. We need to find the change in radius ΔR.

We can rearrange the equation to solve for ΔR:

ΔR = K/ΔP

Now, we need to determine the value of the constant K. The constant K depends on the bulk modulus of the material, which is a measure of its resistance to compression. For water, the bulk modulus is approximately 2.2 GPa (gigapascals).

Substituting the values into the equation, we have:

ΔR = (2.2 GPa) / (200 MPa)

To simplify the calculation, we need to convert the units so that they are consistent. Let's convert GPa to MPa:

ΔR = (2.2 GPa * 1000 MPa/GPa) / (200 MPa)

ΔR = 11 mm

Therefore, the radius of the sphere decreases by 11 mm when the pressure on its surface is increased by 200 MPa.

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According to the zeroth law of thermodynamics, no heat is transferred between the two objects if both the objects are at the same temperature.

Thus, no heat transfer between the water, pot, and air occurs according to the zeroth law of thermodynamics.

Hence, the zeroth law of thermodynamics is the correct answer.

Answer:

deception

Explanation:

Answer:

Reservoir.

Explanation:

Answer:

precipitation is the answer..

Explanation:

precipitation is any product of the condensation of atmospheric water vapor that falls under gravitational pull from clouds. The main forms of precipitation include drizzling, rain, sleet, snow, ice pellets, graupel and hail.

Answer:

\(d=1200\ lb/ft^3\)

Explanation:

Given that,

The weight of the statue, m = 96 lb

The volume of the statue = 0.08 ft³

We need to find the statue’s weight density. We know that the density of an object is the mass of an object divided by its volume. So,

\(d=\dfrac{m}{V}\\\\d=\dfrac{96\ lb}{0.08\ ft^3}\\\\d=1200\ lb/ft^3\)

So, the density of the statue is equal to \(1200\ lb/ft^3\).

Answer:

The moment of inertia of disc about own axis is 1 kg-m².

Explanation:

Given that,

Mass of ring m= 1 kg

Moment of inertia of ring at diameter \((I_{r})_{d}=1\ kg\ m^{2}\)

The radius of metallic ring and uniform disc both are equal.

So, \(R_{r}=R_{d}\)

We need to calculate the value of radius of ring and disc

Using theorem of perpendicular axes

\((I_{r})_{c}=2\times (I_{r})_{d}\)

Put the value into the formula

\((I_{r})_{c}=2\times1\)

\((I_{r})_{c}=2\ kg\ m^2\)

Put the value of moment of inertia

\(MR_{r}^2=2\)

\(R_{r}^2=\dfrac{2}{M}\)

Put the value of M

\(R_{r}^2=\dfrac{2}{1}\)

So, \(R_{r}^2=R_{d}^2=2\ m\)

We need to calculate the moment of inertia of disc about own axis

Using formula of moment of inertia

\(I_{d}=\dfrac{1}{2}MR_{d}^2\)

Put the value into the formula

\(I_{d}=\dfrac{1}{2}\times1\times2\)

\(I_{d}=1\ kg\ m^2\)

Hence, The moment of inertia of disc about own axis is 1 kg-m².

Answer: Condensation of liquid sweat on the skin

Explanation:

The part that insulates the reaction chamber from the transfer of heat to or from the surrounding environment is (C).

It should be noted that the cup of water plugged by a brown cork is insulated by a second styrofoam cup.

In this case, the black rod and a thermometer are inserted through the cork into the water.

This part that contains a known amount of water, which is placed there before the experiment starts is (B).

This part is where the metal is placed at the beginning of the experiment is (B).

This part that is used for measuring the initial and final temperatures of the water is (A).

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Answer:

Explanation:

C

B

B

A

Edge 2022

The stretch of the spring is proportional to the weight of the mass hung from it. Since the spring stretches by 5.9 cm when a 1.6 kg mass is hung from it, we can use this information to find the stretch when a 2.1 kg mass is hung from it.

The stretch of the spring is given by:

stretch = (mass x gravity x length) / (spring constant)

where mass is the mass hung from the spring, gravity is the acceleration due to gravity (9.81 m/s^2), length is the stretch of the spring, and the spring constant is a measure of the stiffness of the spring (measured in N/m).

We can rearrange this equation to solve for the stretch of the spring:

stretch = (mass x gravity x length) / (spring constant)

length = (spring constant x stretch) / (mass x gravity)

Substituting the given values, we get:

length = (spring constant x 0.059 m) / (1.6 kg x 9.81 m/s^2)

Simplifying, we get:

length = 0.236 m

Therefore, the stretch of the spring when a 2.1 kg mass is hung from it is 0.236 m.

Answer:

Pros of DNA phenotyping:

-Phenotypical characteristics can be predicted such as eye color, hair color, skin pigmentation, and many more.

-predict ancestry of an organism

-Use to find criminals

Cons of DNA phenotyping:

-Some phenotypical traits could not be predicted

- Invading privacy

This technology will surely help forensics, law enforcement as it helps track down unknown perpetrators of crime.

3 arguments for it:

- accurate in narrow down researches

- finding biological ancestry

3 arguments against it

It violates the privacy policy of an individual

Racial discrimination is done of public

Equality policies are not followed by it.

Answer:

The displacement is 6.4m

Explanation:

Step one:

given

we are told that Lucy runs 4 meters to the east,

then 5 meters south.

let the distance east be the displacement in the x-direction, and south be the y-direction

Step two:

The resultant of the x and y displacement is the magnitude of the total displacement z

applying Pythagoras theorem we have

z=√x^2+y^2

z=√4^2+5^2

z=√16+25

z=√41

z=6.4m

Answer: wheres the picture and it could be where they move the fastest

Explanation:

Answer:

Less than A

Explanation:

An orbit sweeps equal areas in equal times during all phases of the orbit.

Kepler's Second law

As 40 days is less than 45 days, less area will be swept in 40 days.

1. false

2. true

I hope this helps ^-^

The resultant force on the positive charge  is mathematically given as

X=40N

Question Parameters:

Three-point charges, two positive and one negative, each having a magnitude of 20

Generally, the -ve charge   is mathematically given as

\(Q+=\sqrt{x^2+x^2+2x.xcos120}\\\\Q+=\sqrt{2x^2+2x*(1/2)}\)

Q+=X

Therefore

\(x=\frac{Kq1q2}{r2}\\\\x=\frac{9*10^9*20*10^{-6}*20*10^{-6}}{(30*10^-2)^2}\)

X=40N

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Answer:

1225kg

Explanation:

Given parameters:

Velocity  = 20m/s

Momentum  = 24500kgm/s

Unknown:

Mass of the car  = ?

Solution:

Momentum is the quantity of motion a body possess;

 Momentum  = mass x velocity

   Mass = \(\frac{24500}{20}\)    = 1225kg

1.47  is the coefficient of static friction between a mass of 0.75kg and a horizontal surface

m=0.75 KG

g=9.8 M/S^2

N=5 N

F=µN

µ=F/N

µ=mg/N

µ=0.75×9.8÷5

µ=1.47

We are physically surrounded with friction. An object moving along a path is resisted by a force known as static friction. Lastly, use an easy example to comprehend it. Think about the activity we perform frequently called walking. We are constantly in contact with the floor while we work. Motion presses against the ground as we move it backward, and we then advance our feet.

One key concept to be aware of in order to minimize friction is the fact that it operates in the opposite direction from relative motion. This phenomena may be useful for reducing the speed of the action until it eventually comes to a stop.

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Answer:

Workdone = 25500Nm

Explanation:

Given the following data

Force = 425N

Distance = 60m

To find the workdone

Workdone = force *distance

Substituting into the equation, we have

Workdone = 425*60

Workdone = 25500Nm

Answer:

1- t^3

2- t^2

3- t1

Explanation:

The acceleration produced in a body, while travelling in a circular motion, due to change in direction of motion is called centripetal acceleration. The formula of the centripetal acceleration is as follows:

ac = v²/r

where,

ac = centripetal acceleration

v = speed

r = radius

for a constant radius the centripetal acceleration will be directly proportional to the speed of object. The speed of pendulum will be lowest at t1 due to zero speed initially. Then the speed will increase gradually having greater speed at t^2 and the highest speed and centripetal acceleration at t^3. Therefore, the three instants in tie can be written in following order from greatest centripetal acceleration to lowest:

1- t^3

2- t^2

3- t1

Answer: \(f=3.125 Hz\)

Explanation:

frequency = 1 / period

\(f=\frac{1}{T}\)

\(f=\frac{1}{0.32}=3.125Hz\)

Therefore, the frequency of the wave is 3.125 Hz.